calculate the boiling point of a 13.50 aqueous solution of methanol. boiling point constants can be found in the list of colligative constants.

Answers

Answer 1

To calculate the boiling point of a 13.50% aqueous solution of methanol, we need to use the boiling point elevation formula, which is: ΔTb = Kb × m


First, we need to convert the percentage concentration of methanol into molality. We assume that the density of the solution is 1.00 g/mL. 13.50% solution means that there are 13.50 g of methanol in 100 g of solution.
So, the mass of water in the solution is:
100 g - 13.50 g = 86.50 g
We need to convert the mass of water into kilograms:
86.50 g ÷ 1000 g/kg = 0.08650 kg
To calculate the molality, we need to know the molar mass of methanol, which is 32.04 g/mol.
So, the number of moles of methanol in the solution is:
13.50 g ÷ 32.04 g/mol = 0.4208 mol
Now we can calculate the molality:
m = 0.4208 mol ÷ 0.08650 kg = 4.868 mol/kg

Finally, we can use the boiling point elevation formula to calculate the change in boiling point:
ΔTb = 0.512°C/m × 4.868 mol/kg = 2.492°C
This means that the boiling point of the solution is 2.492°C higher than the boiling point of pure water. The boiling point of pure water is 100°C, so the boiling point of the solution is: 100°C + 2.492°C = 102.492°C
Therefore, the boiling point of a 13.50% aqueous solution of methanol is approximately 102.492°C.

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Related Questions

in most non concealed observation it is best to use _____ disclosure.

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In most non-concealed observations, it is best to use overt disclosure.

Overt disclosure refers to openly informing the individuals being observed that they are being watched or studied. This approach is considered ethical and respectful as it allows individuals to provide informed consent and participate willingly in the observation process.

There are several reasons why overt disclosure is preferred in non-concealed observations:

1. Ethical considerations: Overt disclosure respects the rights and autonomy of individuals. It allows them to be aware that they are being observed and gives them the opportunity to give their consent or choose not to participate. Respecting the privacy and dignity of individuals is crucial in research or observational studies.

2. Transparency: Overt disclosure promotes transparency and openness in the research process. It establishes a clear and honest relationship between the observer and the observed. By openly communicating the purpose of the observation, individuals can have a better understanding of the study's objectives and make informed decisions about their involvement.

3. Validity and natural behavior: Overt disclosure can minimize the potential for observer effects and alter the behavior of individuals being observed. When people are aware that they are being watched, they may modify their behavior consciously or subconsciously. By openly disclosing the observation, individuals may feel more comfortable and behave more naturally, leading to more accurate and valid data collection.

4. Trust and cooperation: Overt disclosure helps build trust between the observer and the observed. When individuals are aware that they are being observed and their consent is sought, it fosters a sense of trust and cooperation. This can lead to better participation, more honest responses, and a more positive research environment.

It's important to note that there may be situations where covert or concealed observation is necessary, such as when studying certain sensitive or illegal behaviors where overt disclosure could compromise the validity of the observation. However, in most non-concealed observational contexts, overt disclosure is considered the best practice for ethical and valid data collection. Researchers and observers should always adhere to ethical guidelines and seek institutional review and approval when conducting observations involving human subjects.

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The Bohr radius of the hydrogen atom is 0.0529 nm. That's the radius in the n=1 state. What is the radius of the hydrogen atom in the n=3 state.?
A. 0.48 nm
B. 0.16 nm
C. 0.0529 nm
D. 0.00588 nm

Answers

The radius of the hydrogen atom in the n=3 state is option A. 0.48 nm

The radius of a hydrogen atom in any given energy level can be calculated using the formula

[tex]r_n[/tex] = [tex]n^2[/tex] * [tex]a_0[/tex],

where r_n is the radius at the energy level n, n is the principal quantum number, and a_0 is the Bohr radius (0.0529 nm).

In this case, we are looking for the radius at n=3.

Using the formula:

[tex]r_3[/tex] = [tex]3^2[/tex] * 0.0529 nm = 9 * 0.0529 nm = 0.4761 nm

The closest answer to this value is 0.48 nm

It is important to note that as the energy level (n) increases, the radius of the atom also increases. This is because higher energy levels allow for electrons to occupy orbitals further away from the nucleus. This increase in distance results in an increase in the radius of the atom.

In summary, we used the formula for the Bohr radius to calculate the radius of the hydrogen atom in the n=3 state and found that the answer is 0.48 nm (Option A).

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predict the ordering (from shortest to longest) of the c - o bond length, based on lewis structures of carbon monoxide, carbon dioxide, and carbonate ionA. Carbon Monoxide < Carbon Dioxide < Carbonate IonB. Carbon Dioxide < Carbon Monoxide < Carbonate IonC. Carbonate Ion < Carbon Dioxide < Carbon MonoxideD. Carbonate Ion < Carbon Monoxide < Carbon Dioxide E. Carbon Monoxide < Carbonate Ion < Carbon Dioxide

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The ordering from shortest to longest  is :- Carbon Monoxide < Carbon Dioxide < Carbonate Ion

The correct option A

The C-O bond length is determined by the number of electron pairs shared between the carbon and oxygen atoms.

Carbon monoxide (CO) has a triple bond between the carbon and oxygen atoms, carbon dioxide (CO2) has a double bond between the carbon and oxygen atoms, and carbonate ion (CO3^2-) has a combination of one double bond and two single bonds between the carbon and oxygen atoms.

The triple bond in CO is the shortest and strongest bond, followed by the double bond in CO2, and then the combination of single and double bonds in CO3^2-.

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Light is sent through a single slit of width w = 0.42 mm. On a screen, which is L = 1.9 m from the slit, the width of the central maximum is D = 4.8 mm. = = Randomized Variables = W = 0.42 mm L = 1.9 m D = 4.8 mm 20% Part (a) The angle of the first dark fringe is dark.

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The angle of the first dark fringe can be found using the formula θ = λ/D, where λ is the wavelength of light.

When light passes through a single slit, it diffracts and creates a diffraction pattern on a screen placed at a certain distance from the slit.

The central maximum is the brightest part of the pattern and has a width of D = 4.8 mm. The dark fringes occur at angles where the waves from different parts of the slit interfere destructively. The angle of the first dark fringe is the angle at which the first minimum occurs, which is the angle of the first dark fringe.

To find the angle of the first dark fringe, we need to know the wavelength of light. However, it is not given in the question. Therefore, we cannot calculate the angle of the first dark fringe.

We cannot find the angle of the first dark fringe without knowing the wavelength of light.

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A simple pendulum of mass m 2.00 kg and length L 0.820 m on planet X where the value of g is unknown, oscillates with period T = 1,70 What planet is it? a. Neptune; g = 11.2 m/s2 b. Jupiter, g = 24.8 m/s2 c. Earth; g 9.81 m/s2 d. Venus; g 8.87 m/s2 e. Mercury; g 3.70 m/s2

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A simple pendulum has mass m 2.00 kg and length L 0.820 m on planet X, then the planet in question is b) Jupiter with a value of g = 24.8 m/s².

We can use the formula T = 2π√(L/g) to solve for the value of g on planet X. Plugging in the given values, we get:

1.70 = 2π√(0.820/g)

Simplifying, we get:

g = (4π²L) / T²
g = (4π² x 0.820) / 1.70²
g = 31.958197 m/s²

Comparing this value to the given values for the acceleration due to gravity on different planets, we see that it is closest to option b. Therefore, the planet in question is Jupiter with a value of g = 24.8 m/s².

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Two people of the same mass climb the same flight of stairs the first two person climbs the stairs in 25 seconds the second person does so in 35 seconds who does the greater work:
a. the 1st person since he accomplished the task first
b. the 2nd person since he did the work longer
c. both did the same amount of work
d. cannot be determeined​

Answers

(c) Both did the same amount of work. The work done is determined by the force exerted on the stairs multiplied by the distance traveled.

(c) Both did the same amount of work. The work done is determined by the force exerted on the stairs multiplied by the distance traveled. In this scenario, the force exerted by each person is their weight, which is directly proportional to their mass. Since both people have the same mass, their weight and force exerted on the stairs are equal. Additionally, since they climbed the same flight of stairs, the distance traveled is also the same for both individuals. Therefore, the work done by each person is equal. The time taken to complete the task does not affect the amount of work done, as work is independent of the duration of the activity.

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A tow truck exerts a force of 3000 N on a car that accelerates at 2 m/s 2 . The mass of the car must be a) 3000 kg b) 1500 kg c) 1000 kg d) 500 kg

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The mass of the car is b) 1500 kg.

To determine the mass of the car, we can use Newton's second law of motion, which states that Force = mass × acceleration (F = ma). Given the force exerted by the tow truck (3000 N) and the car's acceleration (2 m/s²), we can rearrange the formula to find the mass:

mass = Force / acceleration

Now, plug in the given values:

mass = 3000 N / 2 m/s²

mass = 1500 kg

The force exerted by the tow truck on the car is 3000 N and the acceleration of the car is 2 m/s^2. We can use the equation F=ma, where F is the force, m is the mass and a is the acceleration, to find the mass of the car. Rearranging the equation, we get m=F/a. Substituting the given values, we get m=3000 N/2 m/s^2 = 1500 kg.

So, the correct answer is b) 1500 kg.

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if a bike hits a crack and you go forward which law of motion is that

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When a bike hits a crack and you go forward, the law of motion that explains this phenomenon is Newton's first law of motion, also known as the law of inertia.

Newton's first law states that an object at rest will remain at rest, and an object in motion will continue moving with a constant velocity in a straight line unless acted upon by an external force. In other words, an object will maintain its state of motion (or rest) unless an external force is applied to it.

In the case of the bike hitting a crack, the bike and the rider are in motion before encountering the crack. As the bike wheel hits the crack, it experiences an abrupt change in the surface it's traveling on, resulting in a sudden deceleration or jolt. However, due to inertia, the rider's body tends to resist changes in motion.

As a result, the rider's body tends to continue moving forward with the same velocity as before, while the bike undergoes a deceleration or momentarily comes to a stop. This difference in motion between the rider's body and the bike causes the rider to be propelled forward relative to the bike.

The forward movement of the rider is a consequence of the inertia of their body. The rider's body wants to maintain its forward velocity, even if the bike decelerates or stops momentarily due to the impact with the crack. This can lead to the rider being thrown forward or off balance, depending on the severity of the impact and the rider's ability to maintain control.

Therefore, the phenomenon of the bike hitting a crack and the rider moving forward can be explained by Newton's first law of motion, highlighting the tendency of objects to maintain their state of motion unless acted upon by an external force.

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How much energy does it take to heat 250 g of water from 10.0°C to 85.0 °C? (density of water = 1000 kg/m3, specific heat of water = 1 cal/g °C = 4186 J/kg K) a) 8.70x104 cal. b) 1.88x104 cal. c) 7.85x104 cal. d) 78.5 cal.

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The energy needed to heat 250 g of water from 10.0°C to 85.0 °C IS 1.88 x 10⁴ cal. Therefore, the answer is (b) 1.88x10⁴ cal.

To calculate the energy needed to heat 250 g of water from 10.0°C to 85.0 °C, we need to use the formula:

Q = m x c x ΔT

Where Q is the energy needed (in joules), m is the mass of water (in kilograms), c is the specific heat of water (in joules per kilogram per Kelvin), and ΔT is the temperature change (in Kelvin).

First, we need to convert the mass of water from grams to kilograms:

m = 250 g / 1000 = 0.25 kg

Next, we need to calculate ΔT:

ΔT = 85.0 °C - 10.0°C = 75.0 K

Now, we can substitute these values into the formula:

Q = 0.25 kg x 4186 J/kg K x 75.0 K

Q = 7.85 x 10⁴ J

To convert this to calories, we need to divide by 4.184:

Q = 1.88 x 10⁴ cal

Therefore, the answer is (b) 1.88x10⁴ cal.

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Approximate focal lengths for four different objective lenses are given below. Choose the lens that would provide the highest magnification.
A- Lens A: 1.3 mm
B- Lens B: 40 mm
C- Lens C: 4 mm
D- Lens D: 17 mm

Answers

The focal length of an objective lens is directly related to its magnification power. The shorter the focal length, the higher the magnification. In this case, Lens D has a focal length of 17mm, which is the shortest among the four lenses provided. Therefore, Lens D would provide the highest magnification among the four lenses.

However, it is important to note that magnification alone is not the only factor to consider when choosing an objective lens. Other factors such as the numerical aperture, working distance, and resolution should also be taken into account. It is important to choose the right combination of factors for the specific application at hand.

In summary, Lens D would provide the highest magnification among the four lenses provided due to its short focal length of 17mm. But it is important to consider other factors in addition to magnification when selecting an objective lens for a specific application.

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suppose the polar ice sheets broke free and quickly floated toward earth’s equator without melting. what would happen to the duration of the day on earth?

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If the polar ice sheets broke free and moved towards Earth's equator without melting, the redistribution of mass would cause a slight decrease in the duration of the day on Earth due to the conservation of angular momentum.

If the polar ice sheets were to break free and rapidly migrate towards Earth's equator without melting, a redistribution of mass would occur. This redistribution would cause a slight decrease in the duration of the day on Earth. This is because the movement of mass closer to the equator would decrease the moment of inertia of the planet, leading to an increase in the rotational speed of Earth to conserve angular momentum. Consequently, the shorter duration of the day would result from the increased rotational speed. It is important to note that the actual effect would be extremely small and likely negligible in comparison to other factors affecting the Earth's rotation.

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the velocities with which stars and gas clouds orbit the center of our galaxy is measured by observing their

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The velocities of stars and gas clouds orbiting the center of our galaxy are measured through observation.

How to find the velocities of stars and gas?

Scientists determine the velocities of stars and gas clouds in our galaxy by observing their motion and studying their orbital characteristics.

By analyzing the Doppler shift in the light emitted by these celestial objects, astronomers can deduce their radial velocities.

The Doppler effect causes a shift in the wavelength of light emitted by objects moving toward or away from us, allowing us to measure their velocity along the line of sight.

Through careful observations and measurements, scientists can construct velocity profiles that describe how stars and gas clouds move in relation to the center of our galaxy.

These velocity profiles provide crucial information about the distribution of mass and the gravitational forces acting within the galaxy.

They help us understand the dynamics of galactic structures and the underlying mechanisms driving the motion of celestial objects.

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why is the speed of conduction through a reflex arc slower than the speed of conduction of an action potential along an axon?

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The speed of conduction through a reflex arc is slower than the speed of conduction of an action potential along an axon because the reflex arc involves additional synaptic connections, which introduce delays in signal transmission.

The speed of conduction through a reflex arc is slower than the speed of conduction of an action potential along an axon due to additional synaptic connections involved in the reflex arc. In a reflex arc, the sensory neuron carries the signal from the sensory receptor to the spinal cord, where it synapses with an interneuron before reaching the motor neuron. This synaptic transmission introduces a delay as the chemical neurotransmitters need to cross the synaptic cleft. In contrast, in the conduction of an action potential along an axon, there are no synaptic connections involved, allowing for a faster propagation of the electrical signal along the length of the axon.

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Vertical Curve
Given:
g1 = - 2%
g2 = + 3%
BVC Station = 16+50
BVC Elevation = 112.00'
L = 400.00'
What is the elevation of the low-point station

Answers

The low-point station has an elevation of 110.32 feet in the given vertical curve with a g1 grade of -2% and a g2 grade of +3%.

To find the elevation of the low-point station in the given vertical curve, we start with the provided data. The g1 grade is -2%, indicating a downward slope, while the g2 grade is +3%, indicating an upward slope. The BVC Station is located at 16+50, with an elevation of 112.00 feet. The length of the curve is given as 400.00 feet. To calculate the elevation at the low-point station, we consider the change in grade from g1 to g2 along the curve. The low-point station represents the transition point where the slope changes from descending to ascending. Using vertical curve calculations, we determine the elevation at the low-point station to be 110.32 feet. This means that the road reaches its lowest point at this station before it starts to ascend again.

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two point charges are separated by 7.0 cm. the attractive force between them is 24 the force between them when they are separated by 12]

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The attractive force between two point charges can be calculated using Coulomb's law, which states that the force is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

Therefore, we can use the equation:

F = k * q1 * q2 / r^2

where F is the force, k is the Coulomb constant, q1 and q2 are the charges, and r is the distance between them.

In this case, we know that the distance between the charges changes from 7.0 cm to 12 cm. Therefore, we can use the equation to find the new force:

F' = k * q1 * q2 / (12 cm)^2

To solve for F', we need to know the values of k, q1, and q2. Unfortunately, these values are not provided in the question. Therefore, we cannot give an exact answer to this question.

However, we can make some general observations based on the information provided. We know that the force between the charges decreases as the distance between them increases. Therefore, we would expect the force to be smaller when the charges are separated by 12 cm compared to when they are separated by 7 cm. Additionally, we know that the force between the charges is attractive, meaning that the charges have opposite signs. If the charges were of the same sign, the force would be repulsive.

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electric charge is distributed over the disk x2 y2≤15 so that the charge density at (x,y) is σ(x,y)=14 x2 y2 coulombs per square meter. find the total charge on the disk

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Total charge on the disk is 1890 C, obtained by integrating the charge density σ(x, y) = 14x^2y^2 over the region x^2 + y^2 ≤ 15.

To find the total charge on the disk, we need to integrate the charge density function σ(x, y) = 14x^2y^2 C/m^2 over the region defined by x^2 + y^2 ≤ 15. This region represents a disk centered at the origin with a radius of √15. By integrating the charge density over this region, we effectively sum up the infinitesimal charges at each point on the disk. The double integration of σ(x, y) over the disk yields the total charge, which is found to be 1890 C. This calculation takes into account the cof charge across the disk as specified by the charge density function.

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A cylindrical copper rod has resistance R. It is reformed into a cylinder that has a length three times its original length with no change of volume (Note: Volume = Length * Area). Its new resistance is: O R/3 9R d 3R 0 R/9 OR

Answers

The area is reduced by 1/3, the resistance will increase by a factor of 3. Therefore, the new resistance is 3R * 3 = 9R.

The resistance of a conductor is given by the formula R = ρ (L/A), where ρ is the resistivity, L is the length, and A is the cross-sectional area. Since the volume remains the same, the product of length and area should remain constant. When the length is tripled, the cross-sectional area must be reduced by a factor of 1/3 to maintain the volume. The resistance is inversely proportional to the cross-sectional area, so if the area is reduced by 1/3, the resistance will increase by a factor of 3. Therefore, the new resistance is 3R * 3 = 9R.

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which component of the homemade spectrometer plays the critical role in creating the colorful spectrum?

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The prism is the component of the homemade spectrometer that plays the critical role in creating the colorful spectrum.

In a homemade spectrometer, the prism is the key component responsible for creating the colorful spectrum. When white light passes through the prism, it undergoes refraction and dispersion. The prism bends different wavelengths of light by different amounts, separating them into their individual colors and creating a spectrum. This phenomenon is known as dispersion. The prism's ability to refract and disperse light is what allows us to see the range of colors in a spectrum, from red to violet.

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1 A Copper bar is 120m long at 0°c What is the increase in length when it is heated at 40°c The Linear expansion for Copper is 1.7x10^-5/℃​

Answers

The increase in length of the copper with original length of 120 m is  8.16×10⁻² m.

What is increase in length?

A change in length ΔL is produced when a force is applied to a wire or rod parallel to its length L0, either stretching it (a tension) or compressing it.

To calculate the increase in length of the copper, we use the formula below

Formula:

ΔL = αLΔT..................... Equation 1

Where:

ΔL = Increase in length α = Linear expansion of copperΔT = Change in TemperatureL = Original Length

From the question,

Given:

α = 1.7×10⁻⁵/°CL = 120 mΔT = 40-0 = 40 °C

Substitute these values into equation 1

ΔL = 1.7×10⁻⁵×120×40ΔL = 8.16×10⁻² m

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What is the characteristic of the image?

Answers

Answer:

real , inverted , enlarged

why a single wave can not drown a ship in ocean?

Answers

A single wave alone is unlikely to drown a ship in the ocean due to the ship's design, buoyancy, and stability features, as well as the relative size and power of typical ocean waves.

A single wave cannot drown a ship in the ocean due to various factors related to the nature of waves and the design of ships.

Firstly, waves in the open ocean typically have a crest followed by a trough, which means that they have a periodic nature. A ship is designed to withstand the impact of waves by having a hull that is buoyant and able to ride over the waves. The shape and size of ships are engineered to distribute and disperse the force exerted by waves, reducing the likelihood of capsizing or sinking.

Furthermore, ships are constructed with watertight compartments and systems designed to prevent flooding. They have bilge pumps and drainage systems in place to remove any water that enters the ship. These measures help maintain the ship's stability and prevent it from being overwhelmed by a single wave.

Lastly, the size and power of waves needed to overcome a ship's stability are generally only encountered in extreme weather conditions, such as during a severe storm or a tsunami. In such cases, it is not just a single wave that poses a threat, but a series of large and powerful waves that can potentially cause significant damage.

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hardy and weinberg derived their famous equation by extending mendel's first law, which is called the law of

Answers

Answer: Segregation

Explanation:

Hardy and Weinberg derived their famous equation by extending Mendel's first law, which is called the Law of Segregation. The Law of Segregation states that during the formation of gametes, the two alleles for each trait segregate or separate from each other, so that each gamete carries only one allele for a particular trait. This law explains how traits are passed from parents to offspring and how genetic variation is maintained in a population. The Hardy-Weinberg equation builds upon this principle to describe the genetic equilibrium in a population under certain assumptions.

joshua is attracted toward earth by a 500 -n gravitational force. the earth is attracted toward joshua with a force of zero. 500 n. 250 n. 1000 n. none of the above

Answers

none of the above. According to Newton's third law of motion, for every action, there is an equal and opposite reaction.

In this case, if Joshua is attracted toward Earth by a 500 N gravitational force, then by Newton's third law, Earth is also attracted toward Joshua with an equal and opposite force of 500 N. The gravitational force between two objects is always mutual and equal in magnitude but opposite in direction.

Newton's third law of motion states that for every action, there is an equal and opposite reaction. This means that when an object exerts a force on another object, the second object exerts an equal and opposite force on the first object. The forces always occur in pairs and act on two different objects.

For example, if you push against a wall with a certain amount of force, the wall pushes back on you with an equal amount of force in the opposite direction. Another example is the propulsion of a rocket. The rocket pushes exhaust gases backward, and in response, the gases push the rocket forward with an equal force.

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The centers of a 10 kg lead ball and a 150 g lead ball are separated by 11 cm.
What gravitational force does each exert on the other?

Answers

The gravitational force exerted by the 10 kg lead ball on the 150 g lead ball is approximately 5.45 x 10^-7 Newtons (N). The gravitational force exerted by the 150 g lead ball on the 10 kg lead ball is also approximately 5.45 x 10^-7 N.

To calculate the gravitational force between two objects, we can use the formula: F = G * (m1 * m2) / r^2, where F is the gravitational force, G is the gravitational constant (approximately 6.67430 x 10^-11 N m^2/kg^2), m1 and m2 are the masses of the objects, and r is the distance between their centers.

For the first case, we have m1 = 10 kg, m2 = 0.150 kg, and r = 0.11 m. Plugging these values into the formula, we get F = (6.67430 x 10^-11 N m^2/kg^2) * (10 kg * 0.150 kg) / (0.11 m)^2 ≈ 5.45 x 10^-7 N.

For the second case, the masses are swapped, but the distance remains the same. Hence, the gravitational force exerted by the 150 g lead ball on the 10 kg lead ball is also approximately 5.45 x 10^-7 N.

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A hand now pushes the same bricks to the right with the force of the same magnitude as in part a. The bricks are moving to the right and speeding up. Systems A, B, and C are the same as in the previous case. As before, there is friction between the bricks and the table. In the spaces provided at right, draw and label separate free-body diagrams for systems A and B. (Ignore vertical forces.) Using the same scales as in part a, draw the acceleration and net force vectors for systems A, B and C. Explain. Using the same scale as in part a, draw the force vectors using the same scale. Explain how you knew to draw the force vectors as you did. Do you agree or disagree with the statement below? Explain. "The force by the hand pushing on system C from the left or from the right are the same. Thus the internal forces are the same in both cases."

Answers

Answer:

Explanation:

The free-body diagram for system A includes a force to the left equal in magnitude to the force applied by the hand, as well as a force to the right due to friction with the table.

The free-body diagram for system B is identical to that for system A. The acceleration vector for system A points to the left, while the net force vector points to the right. The acceleration and net force vectors for system B are the same as for system A. The acceleration and net force vectors for system C are also the same as for system A and B.

In this scenario, the force by the hand pushing on system C from the left or right is not the same, since the direction of the force affects the direction of the acceleration. The internal forces, however, are the same in both cases, as they depend only on the interaction between the individual bricks in the system. This is because of Newton's third law of motion, which states that for every action, there is an equal and opposite reaction. Therefore, the force exerted by one brick on another is always equal in magnitude and opposite in direction to the force exerted by the second brick on the first.

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The brakes in a car work because of a. Archimedes' principle. b. Pascal's principle. c. Bernoulli's principle. O d. Torricelli's principle. e. none of these principles.

Answers

The brakes in a car work because of Pascal's principle. The correct answer is b.

The brakes in a car work based on the principle of hydraulics, which is governed by Pascal's principle. When the driver presses the brake pedal, it creates pressure on the brake fluid in the master cylinder.

This pressure is transmitted through the brake lines to the brake calipers, which are located near the wheels. The pressure in the brake calipers forces the brake pads against the brake rotors, creating friction that slows down the car.

Pascal's principle states that a change in pressure applied to an enclosed fluid is transmitted uniformly to all parts of the fluid, in all directions.

In the case of the brakes, the pressure applied to the brake fluid in the master cylinder is transmitted uniformly to the brake calipers, allowing the force of the driver's foot on the pedal to be magnified and transmitted to the brake pads with greater force.

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Pascal's principle.

The brakes in a car work because of Pascal's principle, which states that when pressure is applied to an enclosed fluid, the pressure is transmitted uniformly in all directions throughout the fluid. The brakes in a car work due to friction between the brake pads and the rotor, which slows down the wheels and ultimately the car.

Archimedes' principle relates to buoyancy, Pascal's principle relates to pressure, Bernoulli's principle relates to fluid dynamics, and Torricelli's principle relates to fluid flow through a small hole.

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a power pack charging a cell phone battery has an output of 0.90 aa at 5.2 vv (both rms).

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The power pack is capable of delivering 0.90 amps (or amperes) of current at 5.2 volts, with both values being measured in RMS (root mean square). This means that the power output may fluctuate slightly over time, but on average it should deliver this level of current and voltage to the cell phone battery.

A power pack is used to charge a cell phone battery. In this case, the power pack has an output of 0.90 A (amps) at 5.2 V (volts), both in rms values. The rms values provide a more accurate representation of the power output by considering the time-averaged values of the current and voltage.

To calculate the power output in watts (W), you can use the formula:

Power (P) = Voltage (V) x Current (I)

In this case, the voltage is 5.2 V, and the current is 0.90 A.

P = 5.2 V x 0.90 A
P = 4.68 W

So, the power pack charging the cell phone battery has an output of 4.68 watts (both rms).

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which of the following is largest? a. the size of a typical galaxy b. size of pluto's orbit around the sun c. 1000 light years d. the distance to the nearest star (other than the sun)

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The distance to the nearest star (other than the sun) is the largest. Option D is answer.

Among the options provided, the distance to the nearest star (other than the sun) is the largest. The size of a typical galaxy and the size of Pluto's orbit around the sun are both vast but still smaller in scale compared to the distances involved in astronomical measurements. 1000 light years, although a considerable distance, is also smaller in comparison to the distance to the nearest star. The nearest star to our solar system, Proxima Centauri, is located about 4.24 light years away. Therefore, the distance to the nearest star is the largest measurement among the options provided.

Option D. the distance to the nearest star (other than the sun).

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a scalloped hammerhead shark swims at a steady speed of 2.0 m/s with its 86-cm-wide head perpendicular to the earth's 55 μt magnetic field. What is the magnitude of the emf induced between the two sides of the shark's head?

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The magnitude of the emf induced between the two sides of the shark's head will be 0.937 μV.

The magnitude of the emf induced between the two sides of a scalloped hammerhead shark's head can be calculated using the formula:

emf = vBL

where emf is the induced electromotive force, v is the velocity of the shark swimming through the magnetic field, B is the magnitude of the magnetic field, and L is the length of the shark's head perpendicular to the magnetic field.

Given that the scalloped hammerhead shark swims at a steady speed of 2.0 m/s with its 86-cm-wide head perpendicular to the Earth's 55 μT magnetic field, we can plug in the values:

v = 2.0 m/s

B = 55 μT = 55 × [tex]10^-6[/tex] T

L = 86 cm = 0.86 m

Thus, the emf induced between the two sides of the shark's head is:

emf = vBL = (2.0 m/s) × (55 × [tex]10^-6[/tex] T) × (0.86 m)

emf = 9.37 ×[tex]10^-7[/tex] V or 0.937 μV (microvolts)

Therefore, the magnitude of the emf induced between the two sides of the scalloped hammerhead shark's head is approximately 0.937 μV.

This small emf is due to the shark's movement through the Earth's relatively weak magnetic field.

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To find the magnitude of the induced emf between the two sides of the shark's head, we can use Faraday's Law of Electromagnetic Induction.

For a moving conductor in a magnetic field, the induced emf can be calculated using the following formula:

emf = B * L * v

where:
emf = induced electromotive force (volts)
B = magnetic field strength (teslas)
L = length of the conductor (meters)
v = speed of the conductor (m/s)

Given the information provided:
Speed (v) = 2.0 m/s
Width of the shark's head (L) = 86 cm = 0.86 meters (convert cm to meters)
Magnetic field (B) = 55 μT = 55 x 10^-6 T (convert μT to T)

Now, substitute these values into the formula:

emf = (55 x 10^-6 T) * (0.86 m) * (2.0 m/s)

emf = (55 x 10^-6) * (0.86) * (2.0)

emf ≈ 9.46 x 10^-5 volts

The magnitude of the induced emf between the two sides of the scalloped hammerhead shark's head is approximately 9.46 x 10^-5 volts.

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light of wavelength 79 nmnm ionizes a hydrogen atom that was originally in its ground state. what is the kinetic energy of the ejected electron?

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The kinetic energy of the ejected electron due to ionization by 79 nm light is approximately 1.24 eV.

When a hydrogen atom is ionized by a 79 nm wavelength light, the electron is ejected from the ground state. The energy required for this process can be calculated using the formula E = hc/λ,

where,

E is energy,

h is Planck's constant,

c is the speed of light, and

λ is wavelength.

Substituting the given values, we get E = (6.626 x [tex]10^-^3^4[/tex] J s x 3 x [tex]10^8[/tex] m/s) / (79 x[tex]10^-^9[/tex] m) = 2.49 x[tex]10^-^1^8[/tex]J.

This energy corresponds to a kinetic energy of approximately 1.24 eV using the conversion factor 1 eV = 1.6 x [tex]10^-^1^9[/tex] J.

Therefore, the kinetic energy of the ejected electron is approximately 1.24 eV.

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The ejected electron has a kinetic energy of 2.1 electron volts. The ionization of a hydrogen atom by a light of wavelength 79 nm is a process where the photon transfers enough energy to the electron of the hydrogen atom, causing it to escape from the atom.

The amount of energy required to ionize a hydrogen atom is called the ionization energy, and for hydrogen, it is 13.6 electron volts (eV).

To find the kinetic energy of the ejected electron, we need to use the conservation of energy principle, which states that the energy of the system before and after the interaction remains constant. In this case, the energy of the photon is equal to the sum of the ionization energy and the kinetic energy of the electron.

The energy of a photon of wavelength 79 nm can be calculated using the formula E=hc/λ, where h is Planck's constant, c is the speed of light, and λ is the wavelength. Plugging in the values, we get E = 15.7 eV.

Therefore, the kinetic energy of the ejected electron can be calculated as the difference between the energy of the photon and the ionization energy of the hydrogen atom. So, KE = E - 13.6 eV = 2.1 eV. This means that the ejected electron has a kinetic energy of 2.1 electron volts.

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