Calculate the change of entropy a) of a bath containing water, initially at 20C, when it is placed in thermal contact with a very large heat reservoir at 80C, b) of the reservoir, c) of the bath and reservoir if the bath is brought to 80C via Carnot engine operating between them. The bath and its contents have total heat capacity 10^4 J/K.

Answers

Answer 1

a) The change of entropy of the bath containing water is 5.8 J/K.

b) The change of entropy of large heat reservoir is 28.3 J/K.

c) The change of entropy of the bath and reservoir, if the bath is brought to 80C via the Carnot engine operating between them, is 0 J/K.

The change of entropy for a) the bath containing water when placed in contact with a heat reservoir at 80C is calculated as follows: ΔS = Q/T = (10^4 J/K)(1/Tbath - 1/Treservoir) = (10^4 J/K)(1/293 K - 1/353 K) = 5.8 J/K.

For b) the large heat reservoir, the change of entropy is ΔS = Q/T = (Q added to reservoir)/(Treservoir) = (10^4 J)/(353 K) = 28.3 J/K.

For c) the bath and reservoir brought to 80C via a Carnot engine operating between them, the entropy change of the bath is ΔSbath = Qh/Th - Qc/Tc = (10^4 J)(1/353 K - 1/293 K) = -5.8 J/K, where Qh is the heat added to the bath and Qc is the heat removed from the reservoir. The entropy change of the reservoir is ΔSreservoir = -Qh/Th + Qc/Tc = -(10^4 J)(1/353 K) + (10^4 J)(1/293 K) = 5.8 J/K. The total entropy change for the system is ΔStotal = ΔSbath + ΔSreservoir = 0 J/K.

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Related Questions

Hypotheses: H0 : μ1 = μ2 vs Ha : μ1 ≠ μ2. In addition, in each case for which the results are significant, state which group (1 or 2) has the larger mean.
(a) 95% confidence interval for μ1 − μ2 : 0.12 to 0.54
(b) 99% confidence interval for μ1 − μ2 : −2.1 to 5.4
(c) 90% confidence interval for μ1 − μ2 : − 10.8 to −3.7

Answers

It cannot be determined which group (1 or 2) has the larger mean, as there is no significant difference observed between the means of the two groups.

Based on the given hypotheses (H0: μ1 = μ2 vs Ha: μ1 ≠ μ2), it can be inferred that a two-sample t-test was conducted to compare the means of two independent groups. In this case, the null hypothesis suggests that there is no significant difference between the means of the two groups, while the alternative hypothesis suggests that there is a significant difference.

The given confidence intervals show that the difference in means between the two groups could range from -2.1 to 5.4 with 99% confidence and from -10.8 to -3.7 with 90% confidence. Since both confidence intervals include 0, it suggests that there is no significant difference between the means of the two groups at a significance level of 1% or 10%.

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It cannot be determined which group (1 or 2) has the larger mean, as there is no significant difference observed between the means of the two groups.

Based on the given hypotheses (H0: μ1 = μ2 vs Ha: μ1 ≠ μ2), it can be inferred that a two-sample t-test was conducted to compare the means of two independent groups. In this case, the null hypothesis suggests that there is no significant difference between the means of the two groups, while the alternative hypothesis suggests that there is a significant difference.

The given confidence intervals show that the difference in means between the two groups could range from -2.1 to 5.4 with 99% confidence and from -10.8 to -3.7 with 90% confidence. Since both confidence intervals include 0, it suggests that there is no significant difference between the means of the two groups at a significance level of 1% or 10%.

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A toy duck is floating on the water. The average density of the duck is rhod = 860 kg/m3, while the density of water is rho = 1.0 x 103 kg/m3. The volume of the duck is Vd = 0.000105 m3. Express the weight of the duck, W, in terms of rhod and Vd. Calculate the numerical value of W in Newtons. Express the magnitude of the buoyant force, F, in terms of rho and the volume of water that the duck displaces, Vw.

Answers

The weight of the duck is 0.886 N and the buoyant force is 1.03 N.

We can calculate the  weight of the duck using the formula:

W=m*g; where 'm' is the mass of the duck and 'g' is the acceleration due to gravity.

And the mass of the duck can be calculated by the formula:

[tex]m= rho_d * V_d[/tex]

where [tex]rho_d[/tex] is the density of the duck and [tex]V_d[/tex] is the volume of the duck.

Now after substituting the values into the formula, we get:

[tex]m= (860 kg/m^3) * (0.000105 m^3)[/tex]

m= 0.0903 kg.

Similarly, the weight of the duck will be:

W=m*g

[tex]W=(0.0903 kg) * (9.81 m/s^2)[/tex]

W = 0.886 N

Now the buoyant force (F) can be calculated using the formula:

F = rho*V*g; where 'rho' is the density of the water, 'V' is the volume of the water displaced by the duck, and 'g' is the acceleration due to gravity.

We can say that the volume of the water that is displaced by the duck is equal to its own volume so

[tex]V_d = 0.000105 m^3[/tex]

Substituting the values, we get:

[tex]F = (1.0 * 103 kg/m^3) * (0.000105 m^3) * (9.81 m/s^2)[/tex]

F = 1.03 N

Therefore, the weight of the duck is 0.886 N and the buoyant force is 1.03 N.

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A nearsighted person has near and far points of 11.1 and 19.0 cm , respectively. If she puts on contact lenses with power P = -3.00 D , what are her new near and far points?

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Her new near and far points are 17.0 cm and 34.5 cm respectively.

The formula for calculating the new near and far points is:

1/f = 1/di + 1/do

where f is the focal length of the contact lenses, di is the distance between the contact lenses and the eye (which we can assume is negligible), and do is the distance of the object from the contact lenses.

The near and far points of the nearsighted person are:

dnear = 11.1 cm

dfar = 19.0 cm

To find the new near point, we plug in the values:

1/-3.00 = 1/dnear + 1/25.0

Solving for dnear, we get:

dnear = 17.0 cm

Therefore, the new near point with contact lenses is 17.0 cm.

To find the new far point, we plug in the values:

1/-3.00 = 1/dfar + 1/25.0

Solving for dfar, we get:

dfar = 34.5 cm

Therefore, the new far point with contact lenses is 34.5 cm.

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To find the new near and far points of the nearsighted person with contact lenses of power P = -3.00 D, we can use the following formula:

1/f = 1/di + 1/do

where f is the focal length of the lenses, di is the distance between the lenses and the eye, and do is the distance between the lenses and the object being viewed.

First, we need to find the focal length of the lenses:

P = 1/f

-3.00 D = 1/f

f = -1/3.00 m = -0.33 m

Now we can use the formula to find the new near and far points:

For the near point:

1/-0.33 = 1/0.111 + 1/do

-3.03 m = 9.01 m + 1/do

-12.04 m = 1/do

do = -0.083 m = -8.3 cm

Therefore, the new near point with contact lenses is 8.3 cm.

For the far point:

1/-0.33 = 1/0.190 + 1/do

-3.03 m = 5.26 m + 1/do

-8.29 m = 1/do

do = -0.121 m = -12.1 cm

Therefore, the new far point with contact lenses is 12.1 cm.

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What is the name of the method for determining egg quality by viewing eggs against a light?

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The method for determining egg quality by viewing eggs against a light is called candling.

Candling involves shining a bright light through an egg in a darkened room to examine the interior of the egg. The technique is used to check the quality of the egg and the development of the embryo, and to detect any defects, such as cracks, blood spots, or abnormalities. Candling can also be used to determine the age of an egg by examining the air cell size, which increases as the egg gets older.

Candling is commonly used in the egg industry to sort eggs by quality, size, and weight. It can also be used by hobbyists who keep backyard chickens or other poultry to monitor egg production and ensure the health of their birds.

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A water wave is called a deep-water wave if the water's depth is greater than or equal to one-quarter of the wavelength. The speed of a deep-water wave depends on its wavelength: v=(g1/(28(1/2) Longer wavelengths travel faster. Consider a diving pool that is 6.0 m deep and 12.0 m wide. Standing water waves can set up across the width of the pool. a) Draw the first three standing wave modes for water in the pool. (Hint: What are the boundary conditions at x = 0 and x =L? Can water slosh up and down at the side of the pool?) b) What are the wavelengths for each of these waves? Do they satisfy the condition for being deep-water waves? c) What are the wave speeds for each of these waves? d) Derive a general expression for the frequencies of the possible standing waves. Your expression should be in terms of m,g and L. e) What are the oscillation periods of the first three standing wave modes?

Answers

The boundary conditions at x = 0 and x = L are that the wave amplitude must be zero, since water cannot slosh up and down at the sides of the pool.

a) The first three standing wave modes for water in the pool are:

Mode 1: A single antinode at the center of the pool, with two nodes at the ends.

Mode 2: Two antinodes with one node at the center of the pool.

Mode 3: Three antinodes with two nodes in the pool.

The boundary conditions at x = 0 and x = L are that the wave amplitude must be zero, since water cannot slosh up and down at the sides of the pool.

b) The wavelengths for each of these waves are:

Mode 1: λ = 2L

Mode 2: λ = L

Mode 3: λ = (2/3)L

To check if they satisfy the condition for being deep-water waves, we calculate d = 6.0 m / 4 = 1.5 m for each wavelength:

Mode 1: d = 3.0 m > 1.5 m, so it's a deep-water wave.

Mode 2: d = 1.5 m = 1.5 m, so it's a marginal case.

Mode 3: d = 1.0 m < 1.5 m, so it's not a deep-water wave.

c) The wave speeds for each of these waves can be calculated using the given formula:

v = (gλ/28^(1/2))

where g is the acceleration due to gravity (9.81 m/s^2).

Mode 1: v = (9.81 m/s^2 * 2(12.0 m))/28^(1/2) = 5.03 m/s

Mode 2: v = (9.81 m/s^2 * 12.0 m)/28^(1/2) = 3.52 m/s

Mode 3: v = (9.81 m/s^2 * 2/3(12.0 m))/28^(1/2) = 2.56 m/s

d) The general expression for the frequencies of the possible standing waves can be derived from the wave speed formula:

v = λf

where f is the frequency of the wave.

Rearranging the formula, we get:

f = v/λ = g/(28^(1/2)λ)

The frequency depends on m, which is the number of antinodes in the wave, and L, which is the width of the pool. Since the wavelength is related to the width of the pool and the number of antinodes, we can write:

λ = 2L/m

Substituting this into the frequency formula, we get:

f = (g/28^(1/2))(m/2L)

e)The oscillation periods of the first three standing wave modes are:

Mode 1: T = 4.77 seconds

Mode 2: T = 1.70 seconds

Mode 3: T = 2.95 seconds

These values were calculated using the formula T = 1/f, where f is the frequency of the wave. The frequencies were derived from the wave speed formula and the wavelength formula, and they depend on the number of antinodes and the width of the pool. The oscillation period is the time it takes for the wave to complete one cycle of oscillation.

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a proton moves with a speed of 0.855c. (a) calculate its rest energy. mev (b) calculate its total energy. gev (c) calculate its kinetic energy. gev

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(a) Rest energy of the proton is approximately 938 MeV.

(b) Total energy of the proton is approximately 1.86 GeV.

(c) Kinetic energy of the proton is approximately 0.92 GeV.

To calculate the rest energy of the proton, we use the equation E=mc^2, where E is the energy, m is the mass, and c is the speed of light. The rest mass of a proton is approximately 938 MeV/c^2, so its rest energy is approximately 938 MeV.

To calculate the total energy of the proton, we use the equation E=sqrt((pc)^2+(mc^2)^2), where p is the momentum of the proton. Since we know the speed of the proton, we can calculate its momentum using the equation p=mv/(sqrt(1-(v/c)^2)), where m is the rest mass of the proton. Substituting the values, we get the total energy of the proton to be approximately 1.86 GeV.

To calculate the kinetic energy of the proton, we simply subtract its rest energy from its total energy, which gives us approximately 0.92 GeV.

In summary, the rest energy of the proton is approximately 938 MeV, its total energy is approximately 1.86 GeV, and its kinetic energy is approximately 0.92 GeV.

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A man runs 180. M North, then turns and runs 65m South. The run takes 245s. What is the


man's average velocity?


help

Answers

The man's average velocity is 0.41 m/s, calculated by dividing the total displacement (115 m) by the total time (245 s).

To calculate the average velocity, we need to find the total displacement and divide it by the total time. The man initially runs 180 m north, which we consider as positive displacement. Then he turns and runs 65 m south, which we consider as negative displacement. The total displacement is the sum of these displacements, which is 180 m - 65 m = 115 m. The total time taken is 245 s. Dividing the total displacement (115 m) by the total time (245 s), we get the average velocity of 0.41 m/s. The negative sign indicates that the man's final position is in the opposite direction of his initial position.

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A low-pass filter consists of a 116 μf capacitor in series with a 159 resistor. the circuit is driven by an ac source with a peak voltage of 4.40 v
What is VC when f=12fc?
What is VC when f=fc?
What is VC when f=2fc?

Answers

VC = 0.707Vpeak when f = 12fc, VC = 0.5Vpeak when f = fc, and VC = 0.293Vpeak when f = 2fc.

The impedance of a capacitor (ZC) in an AC circuit is given by ZC = 1/(jwC), where j is the imaginary unit, w is the angular frequency, and C is the capacitance. The impedance of a resistor (ZR) is given by ZR = R. The total impedance of a series RC circuit is Z = ZR + ZC = R + 1/(jwC). The voltage across the capacitor (VC) is given by VC = Vpeak × ZC/(ZC + ZR) = Vpeak/(1 + jwRC), where Vpeak is the peak voltage of the AC source.

When f = 12fc, w = 24pi, and

VC = Vpeak/√(1 + (24pi159116e-6)²) = 0.707Vpeak.

When f = fc, w = 2pi, and

VC = Vpeak/√(1 + (2pi159116e-6)²) = 0.5Vpeak.

When f = 2fc, w = 4pi, and

VC = Vpeak/√(1 + (4pi159116e-6)²) = 0.293Vpeak.

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The circuit you are describing is a simple RC series circuit, which acts as a low-pass filter. The voltage across the capacitor, VC, is given by the following equation:

VC = Vpeak / √(1 + (2πfRC)^2)

where V peak is the peak voltage of the AC source, f is the frequency of the AC source, R is the resistance of the resistor, and C is the capacitance of the capacitor.

For this circuit, we have C = 116 μF and R = 159 Ω.

Part A: When f = 12fc

Here, fc is the cutoff frequency of the filter, which is given by:

fc = 1 / (2πRC)

Substituting the given values, we get:

fc = 1 / (2π x 159 Ω x 116 μF) ≈ 91 Hz

Therefore, 12fc = 1,092 Hz.

Substituting these values into the equation for VC, we get:

VC = 4.40 V / √(1 + (2π x 1,092 Hz x 159 Ω x 116 μF)^2) ≈ 0.163 V

Thus, when the frequency is 12 times the cutoff frequency, VC is approximately 0.163 V.

Part B: When f = fc

Substituting fc = 91 Hz into the equation for VC, we get:

VC = 4.40 V / √(1 + (2π x 91 Hz x 159 Ω x 116 μF)^2) ≈ 0.689 V

Thus, when the frequency is equal to the cutoff frequency, VC is approximately 0.689 V.

Part C: When f = 2fc

Substituting 2fc = 182 Hz into the equation for VC, we get:

VC = 4.40 V / √(1 + (2π x 182 Hz x 159 Ω x 116 μF)^2) ≈ 1.15 V

Thus, when the frequency is twice the cutoff frequency, VC is approximately 1.15 V.

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a pitot tube measures a dynamic pressure of 540 pa. find the corresponding velocity of air in m/s, V=__m/s

Answers

A pitot tube measures a dynamic pressure of 540 so the corresponding velocity of air in m/s, V=23.5 m/s.

To determine the corresponding velocity of air in m/s, we can use the Bernoulli's equation which relates the dynamic pressure to the velocity of the fluid.

The equation is expressed as: P + 0.5ρ[tex]V^2[/tex] = constant, where P is the static pressure, ρ is the density of the fluid, and V is the velocity.

We assume that the static pressure is equal to atmospheric pressure, which is approximately 101,325 Pa.

Solving for V, we get V = [tex]\sqrt{(2*(540))/1.225)}[/tex] = 23.5 m/s. Therefore, the velocity of air in m/s is approximately 23.5 m/s.

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To find the corresponding velocity of air (V) in m/s, we can use the formula for dynamic pressure:

Dynamic pressure (q) = 0.5 * air density (ρ) * air velocity (V)²

We are given the dynamic pressure (q) as 540 Pa. For air at standard conditions, we can use an approximate air density (ρ) of 1.225 kg/m³. We need to solve for air velocity (V).

Rearrange the formula to solve for V:

V² = (2 * q) / ρ
V = √((2 * q) / ρ)

Now, plug in the given values:

V = √((2 * 540 Pa) / 1.225 kg/m³)
V = √(1080 / 1.225)
V ≈ 30.06 m/s

The corresponding air velocity (V) is approximately 30.06 m/s.

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explain why the distillate collected from the steam distillation of cinnamon is cloudy.

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The distillate collected from the steam distillation of cinnamon is often cloudy due to the presence of essential oils and other compounds that are not completely soluble in water.

Steam distillation is a popular process for extracting essential oils and other volatile compounds from natural sources like plants and spices. Steam is fed through the cinnamon bark during steam distillation, causing the volatile chemicals to vaporise and carry over into the condenser, where they are cooled and condensed.

The condensed distillate is a mixture of water and volatile chemicals that are insoluble in water.

The distillate frequently appears hazy when collected due to the presence of minute droplets or particles of essential oils and other compounds that have not entirely dissolved in the water. Because these droplets and particles scatter light, the distillate appears cloudy.

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The distillate collected from the steam distillation of cinnamon appears cloudy due to the presence of essential oil compounds and water-soluble components in the mixture. Steam distillation is a technique used to separate and purify volatile compounds, like essential oils, from plant materials by heating and passing steam through the substance.

This process causes the volatile compounds to vaporize and mix with the steam, which then condenses back into a liquid form upon cooling.

In the case of cinnamon, the distillate obtained contains both essential oils, rich in aromatic compounds like cinnamaldehyde, and water from the steam. These two components have different polarities, with the essential oils being mostly non-polar and the water being polar. As a result, they do not mix well and form an emulsion with tiny droplets of the essential oil dispersed in the water, leading to a cloudy appearance.

To obtain a clear distillate, further separation techniques, such as using a separating funnel, can be employed to separate the essential oils from the water. This allows for the collection of a more concentrated and purified form of the cinnamon essential oil, which can then be utilized in various applications like perfumery, flavoring, and therapeutic uses.

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A Carnot engine operating between hot and cold reservoirs at 250 K and 450 K produces a power output of 900 W. Find the rate of heat input, the rate of heat output, and the thermal efficiency?

Answers

The Carnot engine operating between 250 K and 450 K with a power output of 900 W has a heat input rate of 2,000 W, a heat output rate of 1,100 W, and a thermal efficiency of 55%.

Explanation: The rate of heat input, denoted by [tex]$Q_{\text{in}}$[/tex], can be calculated using the formula:

[tex]Q_{\text{in}}[/tex] = Power Output/Thermal efficiency

[tex]Q_{in} = \frac{{900 \, \text{W}}}{{0.55}} = 1,636.36 \, \text{W}[/tex]

The rate of heat output, denoted by [tex]$Q_{\text{out}}$[/tex], can be determined by subtracting the rate of heat input from the power output:

[tex]$Q_{\text{out}}$[/tex]=Powe output[tex]-Q_{in}[/tex]

[tex]Q_{out}=900W-1,636.36W=-736.36W[/tex]

Note that the negative sign indicates that heat is being expelled from the system. Finally, the thermal efficiency, denoted by [tex]$\eta$[/tex], is given by the ratio of the difference in temperatures between the hot and cold reservoirs [tex]($\Delta T$)[/tex] and the temperature of the hot reservoir [tex]($T_{\text{hot}}$)[/tex]:

[tex]\[\eta = 1 - \frac{{T_{\text{cold}}}}{{T_{\text{hot}}}} = 1 - \frac{{250 \, \text{K}}}{{450 \, \text{K}}} = 0.44\][/tex]

Converting the thermal efficiency to a percentage, we find that the Carnot engine has a thermal efficiency of 44%.

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if the ma’s of each stage are 4, 6, and 9, and the carrier plate rotates at 22 rpm, what is the slip of the 2-pole generator?

Answers

To calculate the slip of a generator, we need to know the synchronous speed and the actual speed of the generator. The synchronous speed of a generator can be calculated using the formula:

Synchronous speed = (120 x frequency) / number of poles

where frequency is in hertz and the number of poles is the number of magnetic poles in the generator.

For a 2-pole generator, the synchronous speed can be calculated as:

Synchronous speed = (120 x 60) / 2 = 3600 rpm

The actual speed of the generator can be calculated using the formula:

Actual speed = synchronous speed - slip x synchronous speed

where slip is the ratio of the difference between synchronous speed and actual speed to synchronous speed.

Let N be the actual speed of the generator in rpm. Then we have:

N = (1 - slip) x synchronous speed = (1 - slip) x 3600

The slip can be calculated using the formula:

Slip = (synchronous speed - actual speed) / synchronous speed

Now, we need to calculate the actual speed of the generator. The carrier plate rotates at 22 rpm, so the actual speed of the generator is the product of the carrier plate speed and the gear ratio of the generator. Let the gear ratio be G. Then we have:

N = 22 x G

Substituting this value of N in the equation above, we get:

22 x G = (1 - slip) x 3600

Solving for slip, we get:

slip = 1 - (22 x G) / 3600

We are given that the multiplication factors (MA) of each stage are 4, 6, and 9. The overall gear ratio G is the product of the individual gear ratios. Therefore, we have:

G = MA1 x MA2 x MA3 = 4 x 6 x 9 = 216

Substituting this value in the equation for slip, we get:

slip = 1 - (22 x 216) / 3600 ≈ 0.87

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A 475 nm light source illuminates a pair of slits with a 2.0μm2.0μm slit width and a 12μmμm slit separation. The pattern is displayed on a screen, and the intensity at the center of the pattern is 1.0mW/cm21. what is the intensity, in milliwatts per square centimeter, of the double-slit interference maximum next to the center maximum?

Answers

The intensity of the first-order maximum next to the center maximum is 0.08 milliwatts per square centimeter.

To calculate the intensity of the double-slit interference maximum next to the center maximum, we need to use the formula for the intensity of the interference pattern, which is given by I = I_0 cos^2(πd sinθ/λ)(sin(πa sinθ/λ))^2, where I_0 is the maximum intensity at the center, d is the slit separation, a is the slit width, λ is the wavelength of the light, and θ is the angle between the line connecting the center of the two slits and the line connecting the center of the pattern and the point on the screen where the intensity is being measured.
In this case, we are given the values of d, a, λ, and I_0, so we just need to find the value of θ for the double-slit interference maximum next to the center maximum. Since the center maximum corresponds to θ = 0, we can use the equation for the position of the interference maxima, which is given by sinθ_m = mλ/d, where m is an integer representing the order of the maximum.
For the first-order maximum next to the center maximum, we have m = 1 and sinθ_1 = λ/d = 475 nm/12 μm = 0.0396. Substituting this value of sinθ_1 into the equation for the intensity, we get:
I_1 = I_0 cos^2(πd sinθ_1/λ)(sin(πa sinθ_1/λ))^2
   = 1.0 mW/cm^2 cos^2(π(12 μm)(0.0396)/475 nm)(sin(π(2.0 μm)(0.0396)/475 nm))^2
   = 0.08 mW/cm^2
Therefore, the intensity of the first-order maximum next to the center maximum is 0.08 milliwatts per square centimeter.

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what is the relationship between the speed distribution of a gas and the mass of the particles? how does this help to explain the relative ease with which hydrogen escapes from its containers?

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The speed distribution of gas particles is related to their mass. Lighter particles, such as hydrogen, have higher average speeds compared to heavier particles.

This is because lighter particles have less mass, so they are more easily accelerated by collisions with other particles in the gas.

The relative ease with which hydrogen escapes from its containers can be explained by its high speed and low mass.

Due to its high speed, hydrogen particles are more likely to collide with the walls of a container and bounce off.

These factors combine to make hydrogen more likely to escape from its container compared to heavier gases with lower speeds.

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what are the first three overtones of a double reed instrument that has a fundamental frequency of 118 hz? it is open at both ends.

Answers

The first three overtones of a double reed instrument with a fundamental frequency of 118 Hz that is open at both ends are 236 Hz, 354 Hz, and 472 Hz.

The frequency of the first overtone is two times the frequency of the fundamental, which gives us 236 Hz 118 Hz x 2 = 236 Hz The frequency of the second overtone is three times the frequency of the fundamental, which gives us 354 Hz 118 Hz x 3 = 354 Hz. The frequency of the third overtone is four times the frequency of the fundamental, which gives us 472 Hz 118 Hz x 4 = 472 Hz.

The first three overtones of this double reed instrument are 236 Hz, 354 Hz, and 472 Hz. Explanation: An open-ended instrument has its overtones at integer multiples of the fundamental frequency. Determine the fundamental frequency: 118 Hz. Calculate the first overtone by multiplying the fundamental frequency by 2: 118 Hz x 2 = 236 Hz. Calculate the second overtone by multiplying the fundamental frequency by 3: 118 Hz x 3 = 354 Hz Calculate the third overtone by multiplying the fundamental frequency by 4: 118 Hz x 4 = 472 Hz.

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A snowboarder on a slope starts from rest and reaches a speed of 3.3 m/s after 7.7 s.a. What is the magnitude of the snowboarder's average acceleration?b How far does the snowboarder travel in this time?

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The magnitude of the snowboarder's average acceleration is approximately 0.43 m/s². The snowboarder travels approximately 12.2 meters in this time.

a) The magnitude of the snowboarder's average acceleration, we can use the following equation:

average acceleration = (final velocity - initial velocity) / time

final velocity = 3.3 m/s (the speed reached by the snowboarder)

initial velocity = 0 m/s (since the snowboarder starts from rest)

time = 7.7 s

Plugging in these values, we get:

average acceleration = (3.3 m/s - 0 m/s) / 7.7 s ≈ 0.43 m/s²

So the magnitude of the snowboarder's average acceleration is approximately 0.43 m/s².

b) We can use the following kinematic equation , to find how far the snowboarder travels in this time .

distance = initial velocity x time + (1/2) x acceleration x time²

initial velocity = 0 m/s (since the snowboarder starts from rest)

time = 7.7 s

acceleration = 0.43 m/s² (the average acceleration calculated in part a)

Plugging in these values, we get:

distance = 0 m/s x 7.7 s + (1/2) x 0.43 m/s² x (7.7 s)² ≈ 12.2 m

So the snowboarder travels approximately 12.2 meters in this time.

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look around you, find an appliance, and look for its power rating. what is the power in watts? what current does this appliance "draw" if the voltage applied to it is 120V?

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The power rating of an electrical appliance is the amount of electrical energy that it consumes per unit time. It is usually measured in watts (W) or kilowatts (kW), and represents the rate at which the appliance converts electrical energy into other forms, such as heat, light, or mechanical work.

The current draw of an appliance depends on its power rating and the voltage applied to it. According to Ohm's Law, the current (I) drawn by an appliance is equal to the power (P) divided by the voltage (V), or I = P/V. For example, if an appliance has a power rating of 1000 watts and is connected to a voltage of 120 volts, the current it draws is 8.33 amperes (A).

It is important to note that the current draw of an appliance can affect the performance of the electrical system it is connected to. Large appliances with high power ratings, such as air conditioners, refrigerators, and electric water heaters, can cause voltage drops and other problems if they are not properly sized and installed.

In general, it is a good practice to check the power rating and current draw of an electrical appliance before using it, and to ensure that it is compatible with the electrical system it will be connected to. This can help prevent safety hazards and improve the efficiency and reliability of the system.

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consider a 250-m2 black roof on a night when the roof’s temperature is 31.5°c and the surrounding temperature is 14°c. the emissivity of the roof is 0.900.

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The Stefan-Boltzmann rule, which states that the energy radiated by an object is proportional to the fourth power of its temperature and emissivity, can be used to determine how quickly the black roof radiates heat into its surroundings. Consequently, the following is the formula for the power the roof radiates:

P = εσA(T^4 - T_0^4)

where P is the power radiated, E is the emissivity (in this case, 0.900), S is the Stefan-Boltzmann constant (5.67 x 10-8 W/m2K), A is the roof's surface area (250 m2), T is the roof's temperature in Kelvin (31.5 + 273 = 304.5 K), and T_0 is the temperature outside in K (14 + 273 = 287 K).

When we enter the values, we obtain:

P is equal to 0.900 x 5.67 x 10-8 x 250 x (304.54 - 287.4) = 10747 W.

As a result, the black roof is dispersing 10747 W of heat onto the area around it. This is an estimate of the radiation-related energy loss from the roof.

Using a white or reflective roof surface would reflect more of the incoming solar radiation and lessen the amount of heat that the roof absorbs as a way to mitigate this energy loss. Insulating the roof is another choice that would lessen the amount of heat transfer from the roof to the building below.

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To calculate the radiative heat transfer between the black roof and its surroundings, we can use the Stefan-Boltzmann law:

Q = σεA(Tᴿ⁴ - Tₛ⁴)

Where:

Q is the rate of radiative heat transfer (in watts)

σ is the Stefan-Boltzmann constant (5.67 x 10⁻⁸ W/m²K⁴)

ε is the emissivity of the black roof

A is the surface area of the roof (250 m²)

Tᴿ is the temperature of the black roof in Kelvin (315°C + 273.15 = 588.15 K)

Tₛ is the temperature of the surroundings in Kelvin (14°C + 273.15 = 287.15 K)

Substituting these values into the equation, we get:

Q = 5.67 x 10⁻⁸ x 0.900 x 250 x (588.15⁴ - 287.15⁴)

Q = 5.12 x 10⁴ W

Therefore, the rate of radiative heat transfer from the black roof to the surroundings is 5.12 x 10⁴ watts.

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a copper kettle contains water at 24 8c. when the water is heated to its boiling point of 100.0 8c, the volume of the kettle expands by 1.2 3 1025 m3 . determine the volume of the kettle at 24 8c

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A copper kettle contains water at 24 8c. When the water is heated to its boiling point of 100.0 8c, the volume of the kettle expands by 1.2 x 10^25 m³. The volume of the kettle at 24°C is approximately 1.1998 x 10^25 m³.

To determine the volume of the kettle at 24°C, we can use the formula for volume expansion:
ΔV = βV₀ΔT
Where ΔV is the change in volume, β is the coefficient of volume expansion for copper, V₀ is the initial volume at 24°C, and ΔT is the change in temperature.
Given that the kettle expands by 1.2 x 10^25 m³ when heated from 24°C to 100°C, we can find the initial volume (V₀) as follows:
1.2 x 10^25 = βV₀(100 - 24)
Assuming β for copper is 5.0 x 10^-5 K^-1:
1.2 x 10^25 = (5.0 x 10^-5)(V₀)(76)
Solving for V₀:
V₀ ≈ 1.1998 x 10^25 m³
So, the volume of the kettle at 24°C is approximately 1.1998 x 10^25 m³.

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An atomic nucleus suddenly bursts apart (fissions) into two pieces. Piece A, of mass mA, travels off to the left with speed vA. Piece B, of mass mB, travels off to the right with speed vB.(a) Use conservation of momentum to solve for vB in terms of mA, mB, and vA.vB =(b) Use the results of part (a) to show thatKA/KB = mB/mA,

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(a) The velocity of piece B (vB) after the fission can be solved in terms of the velocity of piece A (vA), and the masses of the two pieces (mA and mB) using conservation of momentum: vB = (mA/mB) * vA

Conservation of momentum states that the total momentum of a system is conserved if no external forces act on it. In this case, the initial momentum of the system is zero, since the nucleus was at rest before the fission. Therefore, the total momentum of the two pieces after the fission must also be zero.

We can write the total momentum of the system after the fission as:

p = mA * vA - mB * vB

Since the total momentum is zero, we have:

0 = mA * vA - mB * vB

Solving for vB, we get:

vB = (mA/mB) * vA

(b) Using the expression for vB derived in part (a), we can show that the ratio of the kinetic energies of the two pieces after the fission (KA/KB) is equal to the ratio of their masses (mB/mA):

KA/KB = mB * vB² / (mA * vA²)

Substituting the expression for vB from part (a), we get:

KA/KB = mB/mA

The kinetic energy of an object is given by the formula:

K = (1/2) * m * v²

where m is the mass of the object and v is its velocity. Using this formula, we can write the kinetic energy of piece A and piece B after the fission as:

KA = (1/2) * mA * vA²

KB = (1/2) * mB * vB²

Substituting the expression for vB from part (a), we get:

KA/KB = (mA * vA²) / (mB * vB²)

KA/KB = (mA * vA²) / (mB * [(mA/mB) * vA]²)

KA/KB = mB/mA

Therefore, we have shown that the ratio of the kinetic energies of the two pieces after the fission is equal to the ratio of their masses.

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You are given the following consumption function C = 50 + .80YD. What is the amount of autonomous consumption expenditures?
75
100
5
50

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The amount of autonomous consumption expenditures is 50. Your answer is: 50.

The amount of autonomous consumption expenditures is 50. This is because autonomous consumption expenditures are the amount of spending that occurs regardless of income. In this consumption function, the constant term of 50 represents the autonomous consumption expenditures.
                                          the amount of autonomous consumption expenditures in the consumption function C = 50 + .80YD, you need to identify the constant term, which is the part of the equation not dependent on YD (disposable income).

In this consumption function, the constant term is 50. Therefore, the amount of autonomous consumption expenditures is 50. Your answer is: 50.

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if m(t) is frequency modulated with kf = 4hz/v, then determine the expression for the instantaneous frequency and phase deviation as a function of time in each of the time intervals

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The expression for the instantaneous frequency and phase deviation as a function of time in each of the time intervals can be determined using the formula: Instantaneous frequency = fc + kf * m(t)

Frequency modulation (FM) is a type of modulation where the frequency of the carrier signal is varied in accordance with the message signal. The amount of frequency deviation is proportional to the amplitude of the message signal. The rate of change of frequency with respect to the amplitude of the message signal is called the frequency sensitivity or modulation index, denoted by kf. Instantaneous frequency = fc + 4 * m(t) The instantaneous frequency is the frequency of the carrier signal at any given instant of time. It varies with the amplitude of the message signal, and its expression is given by the above formula.

The phase deviation is the change in the phase of the carrier signal due to the frequency modulation. It is proportional to the integral of the message signal and is given by the above formula. The phase deviation is important because it determines the amount of phase shift between the modulated signal and the carrier signal. This phase shift can affect the demodulation process and, therefore, needs to be considered in the design of FM systems. stantaneous frequency is the sum of the carrier frequency (fc) and the product of the modulation index (kf) and the modulating signal (m(t)).

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You put a 51.7 gram mass on a spring, set it in motion with a small amplitude, and count 21 cycles. Those 21 cycles took 3.42 seconds What is kHM Answer

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The spring constant for a mass of 51.7 grams on a spring that undergoes 21 cycles with a small amplitude in 3.42 seconds is 76.8 N/m.

The value of k for a mass on a spring can be determined using the formula T=2π√(m/k), where T is the period of oscillation, m is the mass, and k is the spring constant. In this problem, we know that the mass is 51.7 grams and that 21 cycles took 3.42 seconds, which means that the period of oscillation is T=3.42/21=0.163 seconds. Since the amplitude is small, we can assume that the motion is simple harmonic, which means that T=2π√(m/k) can be used. Rearranging this formula gives k=m(2π/T)^2, which gives k=51.7(2π/0.163)^2=76.8 N/m.

This value was calculated using the formula k=m(2π/T)^2, where m is the mass and T is the period of oscillation.

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a balloon has a volume of 4.0 liters at 24.0°c. the balloon is heated to 48.0°c. calculate the new volume of the balloon (in liters).

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The new volume of the balloon at 48.0°C is approximately 4.83 liters.

To calculate the new volume of the balloon, we can use the ideal gas law: PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature in Kelvin.

Since the amount of gas and the pressure are constant in this problem, we can use the simplified version of the ideal gas law: V1/T1 = V2/T2, where V1 is the initial volume, T1 is the initial temperature, V2 is the final volume (what we're trying to find), and T2 is the final temperature.

Converting the temperatures to Kelvin by adding 273.15, we get: V1/T1 = V2/T2, 4.0 L / (24.0 + 273.15) K = V2 / (48.0 + 273.15) K. Solving for V2, we get: V2 = (4.0 L * (48.0 + 273.15) K) / (24.0 + 273.15) K, V2 ≈ 4.83 L

Therefore, the new volume of the balloon at 48.0°C is approximately 4.83 liters.

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Suppose a spaceship heading straight towards the Earth at 0.85c can shoot a canister at 0.25c relative to the ship. If the canister is shot directly at Earth, what is the ratio of its velocity, as measured on Earth, to the speed of light? What about if it is shot directly away from the Earth (again, relative to c)?

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A spaceship heading straight towards the Earth at 0.85c can shoot a canister at 0.25c relative to the ship. If the canister is shot directly at Earth, the ratio of the canister's velocity, as measured on Earth, to the speed of light is 0.931. If it is shot directly away from the Earth then the ratio of the canister's velocity, as measured on Earth, to the speed of light is 0.387.

We can use the relativistic velocity addition formula to calculate the velocity of the canister relative to the Earth in both cases

If the canister is shot directly at Earth

Let vship = 0.85c be the velocity of the spaceship relative to Earth, and vcanister = 0.25c be the velocity of the canister relative to the spaceship. Then, the velocity of the canister relative to Earth is

vearth = (vship + vcanister) / (1 + vship*vcanister/[tex]c^{2}[/tex])

Plugging in the values gives

vearth = (0.85c + 0.25c) / (1 + 0.85c*0.25c/[tex]c^{2}[/tex]) = 0.931c

So the ratio of the canister's velocity, as measured on Earth, to the speed of light is 0.931.

If the canister is shot directly away from Earth

In this case, the relative velocity between the spaceship and the canister is vcanister' = -0.25c (note the negative sign), since the canister is moving in the opposite direction. The velocity of the canister relative to Earth is then

vearth' = (vship + vcanister') / (1 - vship*vcanister'/[tex]c^{2}[/tex])

Plugging in the values gives

vearth' = (0.85c - 0.25c) / (1 - 0.85c*(-0.25c)/[tex]c^{2}[/tex]) = 0.387c

So the ratio of the canister's velocity, as measured on Earth, to the speed of light is 0.387.

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. the fifth root of fifteen is equal to ________. 15 raised to the power of 15 one fifth of 15 15 raised to the power of 1/5 one fifteenth of 15

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The fifth root of fifteen is equal to c. 15 raised to the power of 1/5.

This means that if we take the number 15 and raise it to the power of 1/5, we will get the fifth root of fifteen, to understand this better, let's first look at what a root is. A root is the inverse of a power, for example, if we have 2^3 = 8, the inverse of this operation would be taking the cube root of 8, which gives us 2 as the answer.

In this case, the fifth root of fifteen means we are looking for the number that, when raised to the power of 5, equals 15. So, if we take 15 and raise it to the power of 1/5, we are essentially finding the number that, when multiplied by itself 5 times, equals 15.  Mathematically, we can express this as: (15)^(1/5) = x, where x is the fifth root of fifteen.  Therefore, the answer to the question is: the fifth root of fifteen is equal to c. 15 raised to the power of 1/5.

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The system in Problem 9.6 was placed under a closed-loop PI control. Determine if the system will have an overshoot for a step input:
a. Kp = 2 and Ki = 1
b. Kp = 1 and Ki = 3

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The overshoot in a closed-loop PI control system depends on the values of Kp and Ki, as well as the system dynamics.

To determine if the system will have an overshoot for a step input, we need to first calculate the closed-loop transfer function using the PI controller. The transfer function for the given system is:
G(s) = 1 / (s² + 3s + 2)
Using the PI controller, the closed-loop transfer function is given by:
Gc(s) = Kp + Ki/s
The overall closed-loop transfer function is then:
Gcl(s) = G(s) * Gc(s) / (1 + G(s) * Gc(s))
Substituting the values of Kp and Ki for each case, we get:                          a. Kp = 2 and Ki = 1

In this case, the proportional gain is relatively high, which could potentially result in an overshoot. However, the integral gain is low, which can help reduce the overshoot. It is not possible to determine the exact overshoot without more information about the system itself.

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What is proof that at least some IR waves penetrate Earth's atmosphere and reach the surface? o We do not have mutant powers. O Cell phones have a signal even on cloudy days. O People get a sunburn on their skin. We can see the stars at night. O We feel the warmth of the Sun.

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The proof that some IR waves penetrate Earth's atmosphere and reach the surface is that we feel the warmth of the Sun .

]There are multiple pieces of evidence that suggest that at least some IR waves penetrate Earth's atmosphere and reach the surface. First, cell phones are able to receive signals even on cloudy days, which indicates that some form of electromagnetic radiation is able to pass through the atmosphere.

Additionally, people are able to get sunburns on their skin, which is caused by exposure to UV radiation from the Sun. This further supports the idea that some wavelengths of radiation are able to penetrate the atmosphere. Another piece of evidence is that we are able to see stars at night, which indicates that some light is able to travel through the atmosphere and reach our eyes.

Finally, we are able to feel the warmth of the Sun, which is caused by infrared radiation reaching the surface of the Earth. All of these observations suggest that at least some types of electromagnetic radiation are able to penetrate Earth's atmosphere and reach the surface.

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A study of car accidents and drivers who use cellular phones provided the following sample data. Cellular phone user Not cellular phone user Had accident 25 48 . Had no accident 280 412 a) What is the size of the table? (2) b) At a 0.01, test the claim that the occurrence of accidents is independent of the use of cellular phones. (15)

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The size of the table is 4 cells. At a 0.01 significance level, we cannot reject the null hypothesis that the occurrence of accidents is independent of cellular phone use.

Step 1: Determine the size of the table. There are 2 rows (accident, no accident) and 2 columns (cell phone user, non-user), making a 2x2 table with 4 cells.
Step 2: Calculate the expected frequencies. The row and column totals are used to find the expected frequencies for each cell. For example, for cell phone users who had accidents, the expected frequency would be (25+280)*(25+48)/(25+48+280+412).
Step 3: Conduct a Chi-Square Test. Calculate the Chi-Square test statistic by comparing the observed and expected frequencies. Then, compare the test statistic to the critical value at a 0.01 significance level.
Step 4: Conclusion. Since the test statistic is less than the critical value, we fail to reject the null hypothesis, meaning the occurrence of accidents seems to be independent of cellular phone use.

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q7 - light travels with the slowest speed when moving through group of answer choices a) glass. b) water. c) air. d) none of the other choices is correct because the speed of light is constant and doesn't change

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The correct answer is b) water. Light travels slower in water compared to air or vacuum. This is because water molecules are more tightly packed together than air molecules, which slows down the speed of light as it interacts with these molecules.

However, it should be noted that the speed of light is constant in a vacuum and does not change.

The speed of light varies depending on the medium it is traveling through. Among the given options, light travels slowest when moving through:

This is because glass has a higher refractive index compared to water and air, which causes light to slow down as it passes through the material.

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