Calculate the conjunctive normal form of the following logic expression (A ^ B v C) ^ (B v ¬ C)

Answer:

The range is the difference between the largest and smallest values in a set of data. In this case, the heights of the 11 plants are listed as:

14, 15, 15, 16, 16, 16, 17, 17, 18, 19, 20

The smallest height is 14 inches and the largest height is 20 inches, so the range is 20 - 14 = 6 inches.

If another plant with a height of 17 inches is added to the data, the smallest and largest values do not change, so the range would still be 6 inches.

Answer:

Answer to the question posted: The range would stay the same value of 6 inches.

Answer to the question in the comments: The mean would decrease in value to about 16.8 inches.

Step-by-step explanation:

Answer to the question posted:

First, to figure out if the range increases, decreases, or stays the same, we need to find the range. The range is siply the difference between the largest ans smallest number. In this problem, the smallest plant height is 14 while the largest plant height is 20. Since the difference between the smallest and largest plant is 20-14, or 6, inches, the range is 6 inches.

Now, let's figure out what would happen if we added a plant with a height of 17 inches. Well, since our smallest plant height and largest plant height would not be changed, the range would stay the same value of 6 inches.

Answer to the question in the comments:

The first step is to find the mean of the plant heights. To find mean, you need to add up all the plant heights and divide it by the number of plants. Since 13+14+15+15+16+16+16+17+17+18+19+20+22+23=241 and there are 14 plants, we can divide 241 by 14 to find the original mean of the plant heights. When we solve 241/14, we get 17.2142857143.

Now, let's figure out what would happen to the mean if we added a plant with a height of 11 inches. Again, we would need to total up all the plant heights, and it should be 11 inches larger than last time, as we are adding 11 inches to the total plant height. Since our original total height was 241, or new total height, adding in the 11 inch plant, would be 252 inches. Now that we have our total plant height including the 11 inch plant, we need to figure out how many total plants we have. If we started with 14 plants and add another plant into the data set, then the total number of plants, including the 11 inch plant, must be 15. Now that we know the new total plant height and new amount of plants, we can find the new mean, The new mean is 252/15, or 16.8.

So, if our mean went from 17.2142857143 to 16.8 when we added the 11 inch plant, the mean would decrease in value to about 16.8 inches.

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Yes, there always exists a perfect match with no weak instability.

For part (a), an example of a set of men and women with preference lists for which every perfect matching has a strong instability would be if all members of one gender ranked all members of the opposite gender equally.

This would mean that no matter which pairing was chosen, one member of the pairing would prefer to be with another member.

As for part (b), an example of a set of men and women with preference lists for which every perfect matching has a weak instability would be if some members of one gender ranked all members of the opposite gender equally, while others had a strict preference.

In this case, the members with strict preferences would always have an alternative that was preferred by one or both members of the pairing, leading to weak instability.

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Answer:

D

Step-by-step explanation:

You just multiplied it times 4 ....it is four times taller

Answer:

69 ways.

Step-by-step explanation:

The solution to the algebraic expression (ab²)³/b⁵ using laws of exponents is; ab

The algebraic expression we are trying to solve is;

(ab²)³/b⁵

Now, according to laws of exponents, we have that;

1) Product Law of exponents: To multiply two expressions with the same base, add the exponents while keeping the base the same

2) Quotient Law of Exponents: To divide two expressions with the same base, subtract the exponents while keeping the base same

3) Zero Law of exponents: Any number (other than 0) raised to 0 is 1

4) Power of a power law of exponents: It states that when we have a single base with two exponents, just multiply the exponents.

We will first apply the power of a power law to get;

(ab²)³/b⁵ = ab⁶/b⁵

= ab

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Answer:

56cm

Step-by-step explanation:

Ratio = 3 : 5 : 7

Perimeter = 120 cm

Process

# of parts = 3 + 5 +7 = 15

Divide 120 by 15 = 120 / 15

Number of parts  = 8

First side = 3 x 8 = 24 cm

Second side = 5 x 8 = 40 cm

Third side = 7 x 8 = 56 cm

Perimeter = 24 + 40 + 56 = 120 cm

The probability of a single value greater than 134 is given as follows:

P(X > 134) = 0.6844 = 68.44%.

The probability of the sample mean greater than 134 is given as follows:

P(M > 134) = 0.9641 = 96.41%.

The z-score of a measure X of a variable that has mean symbolized by [tex]\mu[/tex] and standard deviation symbolized by [tex]\sigma[/tex] is obtained by the rule presented as follows:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The mean and the standard deviation for this problem are given as follows:

[tex]\mu = 155, \sigma = 43.7[/tex]

The probability of a single value above 134 is one subtracted by the p-value of Z when X = 134, hence:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

Z = (134 - 155)/43.7

Z = -0.48

Z = -0.48 has a p-value of 0.3156.

Hence:

1 - 0.3156 = 0.6844 = 68.44%.

For the sample of 14, the standard error is given as follows:

[tex]s = \frac{43.7}{\sqrt{14}} = 11.68[/tex]

Hence:

Z = (134 - 155)/11.68

Z = -1.8

Z = -1.8 has a p-value of 0.0359.

Hence:

1 - 0.0359 = 0.9641 = 96.41%.

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As a range of values that are bound above and below the statistic's mean, a confidence interval is likely to contain an unidentified population parameter. So the statement is true.

The mean of your estimate plus and minus the range of that estimate constitutes a confidence interval. Within a specific level of confidence, this is the range of values you anticipate your estimate to fall within if you repeat the test.

In statistics, confidence is another word for probability. For many different statistical estimates, such as proportions, population means, differences between population means or proportions, and estimates of variation among groups, confidence intervals can be calculated.

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Answer:

y = 2 [tex](3)^{x}[/tex]

Step-by-step explanation:

the standard form of an exponential function is

y = a [tex]b^{x}[/tex]

to find a and b use ordered pairs from the table

using (1, 6 )

6 = a[tex]b^{1}[/tex] , that is

6 = ab → (1)

using (3, 54 )

54 = ab³ → (2)

divide (2) by (1) on both sides

[tex]\frac{54}{6}[/tex] = [tex]\frac{ab^3}{ab}[/tex] , that is

b² = 9 ( take square root of both sides )

b = [tex]\sqrt{9}[/tex] = 3

substitute b = 3 into (1) and solve for a

6 = 3a ( divide both sides b 3 )

2 = a

then the exponential function for the table is

y = 2 [tex](3)^{x}[/tex]

To the inverse, use the formula A−1=1/ad−bc[d  −b]

                                                                          [ −c    a]

when the system (ii) By applying the inverse, that is, by calculating A-1 B where B represents the right-hand side (i.e. B = ),  the solutions to the two systems-:

−3

1

for system (a) and B =

2

3

for system (b)).

and B =

2

3

for system (b)).

The coefficient matrix is

[4−2

1   5]

To find the inverse, use the formula

A−1=1/ad−bc[d  −b

                   −c    a]

The solutions can then be obtained by multiplying this inverse matrix by the vectors. (For example, use writing to solve the equation Ax=b.

x=A⁻¹b)

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The full question

Consider the following two systems.

(a)

4x−2yx+5y==−31

(b)

4x−2yx+5y==23

(i) Find the inverse of the (common) coefficient matrix of the two systems.

(ii) Find the solutions to the two systems by using the inverse, i.e. by evaluating A^{-1} B where B represents the right-hand side (i.e.

B =−31

For exponential function g(x)=10ˣ, the table is given below.

An exponential function is a Mathematical function in the form f (x) = aˣ, where “x” is a variable and “a” is a constant which is called the base of the function and it should be greater than 0. The most commonly used exponential function base is the transcendental number e, which is approximately equal to 2.71828.

Exponential Growth

In Exponential Growth, the quantity increases very slowly at first, and then rapidly. The rate of change increases over time. The rate of growth becomes faster as time passes. The rapid growth is meant to be an “exponential increase”. The formula to define the exponential growth is:

y = a ( 1+ r )ˣ

Where r is the growth percentage.

Exponential Decay

In Exponential Decay, the quantity decreases very rapidly at first, and then slowly. The rate of change decreases over time. The rate of change becomes slower as time passes. The rapid growth meant to be an “exponential decrease”. The formula to define the exponential growth is:

y = a ( 1- r )ˣ

Where r is the decay percentage.

Now given function

g(x)=10ˣ

then function g(x-1)=10^(x-1)ˣ⁻¹

So, g(x)/g(x-1)=10*10ˣ⁻¹=10ˣ⁻¹=10

Therefore, the table will be as

 x             g(x)              g(x)/g(x-1)

 2             100                 10

 3               1000              10

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Answer:

wassup my mf jsbhdhdbsidhdbududbdbdishdbjdudhdbd

The journal entry for the transaction will be:

Debit Cash $617,500

Credit Preferred stock   $475,000

Credit Paid up Capital in excess of Par  142,500

(Issued Preferred Stock in Cash)

A journal entry is the act of recording any transaction, whether one that is economic or not. An accounting diary that displays the debit and credit balances of a corporation lists transactions.

4,750 Preferred Stock issued at 100 Par Value at $ 130

Means $ 30($ 130-$ 100) Paid up Capital in excess of Par

Total amount Received :

Preferred Stock Par Value           = 4,750 Shares at 100       = $475,000

Paid up Capital in excess of Par  = 4,750 Shares at 30    = $ 142,500

Total Received = $ 617,500

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Answer:

The large box contains 18.5 kg of fruit.

The small box contains 6.75 kg of fruit.

Step-by-step explanation:

We know that 3L + 2S = 69 and 5L + 6S = 133.

In order to solve for one variable, we can multiply the first equation by 3 so we can eliminate S.

The new equations are 9L + 6S = 207 and 5L + 6S = 133.

Now, we can subtract the equations from each other to solve for one variable, L.

We now get 4L = 74, and when we divide 4 from both sides, we get L = 18.5. This means that a large box has 18.5 kg of fruit.

Now that we know what the large box contains, we can plug the answer into one of the original equations to solve for S.

We now get 3(18.5) + 2S = 69, which we can solve by distributing to get 55.5 + 2S = 69, subtracting 55.5 from both sides to get 2S = 13.5, and then dividing 2 from both sides to get S = 6.75.

We now know both boxes, with the large containing 18.5 kg and the small containing 6.75 kg.

Answer:

12q=1200

12q/12=1200/12

q=100

1 quintal has 100 kg. The equation above was to show how to solve it with a variable. Hope this helps!

Step-by-step explanation:

In a Isosceles triangle, DEF , ∆DFB is congruent to ∆DEC by SAS Congruence criteria, i.e., ∆DFB ≅ ∆DEC.

SAS congruance Criteria : If two sides and the angle between these two sides of one triangle are congruent to the corresponding sides and angle of another triangle, then the two triangles are congruent. We have a triangle DFE with base FE, see in above figure. The EC congruent to FB, i.e., FB ≅ EC. We have to prove ∆DFB ≅ ∆DEC.

Proof : It is known that ∆DEF is isocles triangle with base FE. So, two sides of triangle are equal.

In ∆DFB and ∆DEC,

=> DF = D E ( by definition of Isoceles triangle)

Also, base FB≅ EC ( since, we have)

Now, ∠DFE = ∠DEF => ∠DFB = ∠DEC ( because DE = DF in ∆DEF , corresponding angles of equal sides are equal) .

So, Two sides and the angle between the sides of one triangle, ∆DFB is congruent to the corresponding sides and angle of another triangle, ∆DEC. Therefore, by SAS Congruence criteria, Triangle DFB is congruent to triangle DEC, i.e., ∆DFB≅ ∆DEC. Hence proved..

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Complete question:

Given: ΔDFE is isosceles with base FE; FB ≅ EC. Prove: ∆DFB ≅ ∆DEC.Complete the missing parts of the paragraph proof. We know that triangle DFE is isosceles with base FE and that segment FB is congruent to segment EC because . Segment DF is congruent segment by the definition of isosceles triangle. Since these segments are congruent, the base angles, angles , are congruent by the isosceles triangle theorem. Therefore, triangles are congruent by SAS

Answer:

15 - 3 ?

Step-by-step explanation:

We will start by doing the equation on the left:

5(x-3)

Since we will substitute X for 6 the updated equation will be:

5(6-3)

We will now solve it using bodmas so it will be 6-3 which is 3. Then 3 multiplied by 5 is 15.

We will start by doing the equation on the right:

x + 13

Since we will substitute X for 6 the updated equation will be:

6 + 13

So now to simplify it all it will be:

15x = 6 + 13

On solving the provided question we can say that The coordinates are = ( 9 , - 6 ); the slope intercept will be y + 6 = 9xm - m

In mathematics, the intersection point is the place on the y-axis where the slope of the line crosses. a place where the y-axis crosses on a line or curve. Y = mx+c, where m stands for the slope and c for the y-intercept, is used as the equation for the straight line to show this. The slope (m) of the line and its y-intercept (b) are emphasised in the equation's intercept form. When an equation has the intercept form (y=mx+b), the slope is m and the y-intercept is b. Some equations can also be rewritten such that they seem to be slope intercepts. If y=x is rewritten as y=1x+0, for instance, the slope and y-intercept are both changed to 1.

The coordinates are = ( 9 , - 6 )

the slope intercept will be y + 6 = 9xm - m

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Answer:
the answer should be A

Step-by-step explanation:

Answer:

below

Step-by-step explanation:

First find the area ( pi r^2) of the endcaps...then multiply by the height

pi r^2 h =  3.14 (5^2)(5) = 392.50 cm^3

Answer:

$490.36

Step-by-step explanation:

We can start solving the problem by using the formula for compound interest:

A = [tex]P(1+\frac{R}{n})^{nt}[/tex]

Where A is the final amount, P is the initial principal, R is the interest rate, n is the number of times the interest is compounded in a year, and t is the number of years.

First, we need to calculate the outstanding amount after 60 payments. Since the interest is 12.5% convertible semi-annually, we can use the following formula:

A = [tex]P(1+\frac{R}{2})^{2t}[/tex]

Where P = $50,000 (initial principal), R = 12.5/100 = 0.125, n = 2 (convertible semi-annually), t = 60/12 = 5 years.

A =$ [tex]$50,000(1+\frac{0.125}{2*5})[/tex]

= $ [tex]$50,000(1.0625)^{10}[/tex]

= $50,000(1.7440312)

= $87,201.56

So, the outstanding amount after 60 payments is $87,201.56

Next, we need to calculate the remaining balance after paying $10,000 as a lump sum, which is $87,201.56 - $10,000 = $77,201.56

Now, we need to calculate the monthly payments for 10 years at 11% interest convertible semi-annually. Using the formula above:

A =[tex]P(1+\frac{R}{n})^{nt}[/tex]

Where P = $77,201.56, R = 11/100 = 0.11, n = 2 (convertible semi-annually), t = 10 years.

To find the value of x, we can set up the equation:

$77,201.56 = [tex]x*(1+\frac{0.11}{2})^{2*120}[/tex] - $10,000

Solving for x gives:

x ≈ $490.36 is the monthly instalment for 10 years at 11% interest convertible semi-annually.

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After using the deductive reasoning the procedure always produces the number 8.

Procedure:

Let the number be x.

We have to add 5 to the number x.

So the expression is x + 5.

We have to multiply the sum by 3.

Now the expression is 3(x + 5).

Now we have to subtract 7.

Now the expression is 3(x + 5) - 7.

Then we have to decrease this difference by the triple of the original number.

The triple of original number is 3x.

Now the expression is {3(x + 5) - 7} - 3x.

Now solving this expression

= {3(x + 5) - 7} - 3x.

First simplify the bracket

= 3x + 15 - 7 - 3x.

= 8

Now we can se that the after following the whole procedure the answer is 8.

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To solve for the value of x that would make KM ∥ JN, we can use the converse of the side-splitter theorem.

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The function's value is f(x). The line's slope is m.When x is equal to 0, the function's value is equal to b, which is also the coordinate at where the line in the coordinate plane crosses the y-axis.

The function's value is f(x). The line's slope is m.

When x is equal to 0, the function's value is equal to b, which is also the coordinate at where the line in the coordinate plane crosses the y-axis.

The x-value coordinate's is given by x.

Graph Rules for Derivatives

The graph of f'(x) will be below the x-axis if f(x) has a negative slope.

The graph of f'(x) will be above the x-axis if f(x) has a positive slope.

The x-intercepts of f' will be all relative extrema of f(x) (x).

Given that ;

f(x)= x³

f(x)-4 = x³- 4

See attached graph using the graph tool

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Length of the curve is 1

Arc length or length of a curve is the distance travelled by a point it follows the graph of a function along a some particular interval.

Given,

[tex]y=\int\limits^0_x {\sqrt{cost2t} } \, dt[/tex]

Let find the derivative of the function,

[tex]\frac{dy}{dt} =\frac{d}{dt} (\int\limits^0_x {\sqrt{cost2t} } \, dt)[/tex]

[tex]\frac{dy}{dt} = \sqrt{cos2t}[/tex]

Now using arc length formula,

[tex]L= \int\limits^0_\frac{\pi }{4} {\sqrt{1+(\sqrt{cos2t})^{2} } } \, dt[/tex]

[tex]L= \int\limits^0_\frac{\pi }{4} {\sqrt{1+cos2t} } \, dt[/tex]

Using trigonometric identities, [tex]cos^{2} t+sin^{2} =1[/tex] and[tex]cos2t = cos^{2}t-sin^{2} t[/tex][tex]L= \int\limits^0_\frac{\pi }{4} {\sqrt{cos^{2} t+sin^{2} + cos^{2}t-sin^{2} t } } \, dt[/tex][tex]L= \int\limits^0_\frac{\pi }{4} {\sqrt{2cos^{2} t} } \, dt[/tex]

[tex]L= \sqrt{2} \int\limits^0_\frac{\pi }{4} cos t} } \, dt = \sqrt{2} sint[/tex]

Apply limits we get,  L=1.

Hence, length of the curve , L=1.

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The factor by which g(x) grows over the interval from 14 to 16 is 64/56 = 1.1429.

An interval is a specific range of values within a set of data. It is the difference between the maximum and minimum values of the data set, and is used to measure the spread of the data. Intervals can be used in a variety of ways, from measuring the distribution of data over time to help identify trends in the data. Intervals can also be used to find outliers or unusually high or low values in a data set. Interval data is often used in statistics to measure the variability of data.

The factor by which g(x) grows over the interval from 14 to 16 can be determined by dividing the value of g(16) by the value of g(14).
The value of g(14) is 56, and the value of g(16) is 64.
Therefore, the factor by which g(x) grows over the interval from 14 to 16 is 64/56 = 1.1429.

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The equation, 2(x + 8) = 2x + 8 has no solution because 16 = 8.

To solve an equation, you find the value of the variable that makes the equation true. This can involve using inverse operations (such as addition and subtraction, multiplication and division, or exponentiation and logarithms) to isolate the variable on one side of the equation, and then using properties of equality to simplify the equation.

Given the following, 2(x + 8) = 2x + 8:

Step 1: Distribute 2(x + 8) = 2x + 8 to get 2x + 16 = 2x + 8

Step 2: Subtract 2x from both sides to get 16 = 8

2x + 16 = 2x + 8

2x + 16 - 2x = 2x + 8 - 2x

16 = 8

There is no solution.

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