calculate the freezing point for 0.48 molmol ethylene glycol and 0.17 mol kbrmol kbr in 166 gg h2oh2o .

The balanced chemical equation for the reaction between hydrogen gas and nitrogen gas to produce ammonia is:

3H2 + N2 -> 2NH3
According to the equation, it takes 3 moles of hydrogen gas and 1 mole of nitrogen gas to produce 2 moles of ammonia.

At STP (Standard Temperature and Pressure), one mole of any gas occupies 22.4 litres of volume. Therefore, 2 litres of hydrogen gas and 2 litres of nitrogen gas represent:
2 L H2 x (1 mol H2 / 22.4 L) = 0.089 mol H2
2 L N2 x (1 mol N2 / 22.4 L) = 0.089 mol N2

Since the reaction requires 3 moles of hydrogen gas and 1 mole of nitrogen gas, we have to find the limiting reactant in this case. It is the nitrogen gas since we have only 0.089 mol of it, which is less than the 0.267 mol required to react with the 0.089 mol of hydrogen gas.

Therefore, the amount of ammonia produced will be based on the amount of nitrogen gas used. From the equation, 1 mole of nitrogen gas produces 2 moles of ammonia.

Therefore, the 0.089 mol of nitrogen gas will produce:
0.089 mol N2 x (2 mol NH3 / 1 mol N2) = 0.178 mol NH3

Using the molar volume of a gas at STP, we can calculate the volume of ammonia produced:
0.178 mol NH3 x (22.4 L / 1 mol NH3) = 3.99 L NH3

Therefore, 2 litres of hydrogen gas and 2 litres of nitrogen gas at STP can produce 3.99 litres of ammonia.

Learn more about hydrogen gas, here:

brainly.com/question/24433860

#SPJ11

The frequency of UV light with a wavelength of 2.54 x 10^-7m is 1.18 x 10^15 Hz.

The frequency of UV light with a wavelength of 2.54 x 10-7m can be calculated using the formula:

frequency = speed of light / wavelength

The speed of light is a constant value of approximately 3.00 x 10^8 m/s.

Therefore, frequency = 3.00 x 10^8 m/s / 2.54 x 10^-7m = 1.18 x 10^15 Hz.

To learn more about UV light, visit:

https://brainly.com/question/20733713

#SPJ11

The percent yield of the Diels-Alder reaction between 0.302 g of anthracene and 0.158 g of maleic anhydride to produce 0.249 g of the product is 89.9%.

To calculate the percent yield of the Diels-Alder reaction, you need to use the following formula:

Percent yield = (actual yield / theoretical yield) x 100%

To determine the theoretical yield, you need to first calculate the limiting reagent. In this case, the limiting reagent is the reactant that is completely consumed in the reaction, which can be found by comparing the mole ratio of the reactants to the balanced equation of the Diels-Alder reaction.

The balanced equation for the Diels-Alder reaction between anthracene and maleic anhydride is:

Anthracene + Maleic anhydride → endo-7,8-dihydroxy-4,5-epoxy-3-methoxy-10-methyl-1,2,3,4,4a,5,6,7-octahydrophenanthrene-2,3-dicarboxylic acid anhydride

The mole ratio of anthracene to maleic anhydride is 2:1, which means that for every 2 moles of anthracene, 1 mole of maleic anhydride is required. Therefore, the theoretical yield can be calculated based on the amount of limiting reagent, which in this case is the maleic anhydride.

To determine the moles of maleic anhydride used in the reaction, you need to convert the mass given to moles using its molar mass. The molar mass of maleic anhydride is 98.06 g/mol.

0.158 g / 98.06 g/mol = 0.00161 mol

Since maleic anhydride is in a 2:1 ratio with anthracene, the moles of anthracene used in the reaction can be calculated as follows:

0.00161 mol / 2 = 0.000805 mol

Now that you have the amount of limiting reagent (maleic anhydride) used in the reaction, you can calculate the theoretical yield based on the balanced equation. The balanced equation shows that 1 mole of maleic anhydride reacts with 1 mole of anthracene to produce 1 mole of the product. Therefore, the theoretical yield can be calculated as follows:

0.000805 mol x (344.34 g/mol) = 0.277 g

Now you can calculate the percent yield using the formula mentioned earlier:

Percent yield = (actual yield / theoretical yield) x 100%
Percent yield = (0.249 g / 0.277 g) x 100%
Percent yield = 89.9%

Therefore, the percent yield of the Diels-Alder reaction between 0.302 g of anthracene and 0.158 g of maleic anhydride to produce 0.249 g of the product is 89.9%.

Learn more about  Diels-Alder reaction here

https://brainly.com/question/30751490

#SPJ11

Intermolecular bonding that occurs between carboxylic acids is hydrogen-bonding.

Carboxylic acids are polar molecules that have carbonyl group (C=O) and  hydroxyl group (-OH) attached to same carbon atom. They form intermolecular hydrogen bonds due to the presence of hydrogen-bonding site ( hydroxyl group) and hydrogen-bonding acceptor site (carbonyl group).

The carbonyl oxygen atom is partially negative, and hydroxyl hydrogen atom is partially positive, which allows the formation of hydrogen bond between neighboring carboxylic acid molecules. These hydrogen bonds are relatively strong and can result in formation of dimers or other aggregates of carboxylic acid molecules in liquid or solid state.

To know more about intermolecular bonding, refer

https://brainly.com/question/2193457

#SPJ1

The value of Ka for nitrous acid (HNO2) at 25°C is 4.5×10^−4.So, the chemical equation for the equilibrium that corresponds to Ka for nitrous acid is: HNO2 (aq) + H2O (l)  ⇌ H3O+(aq) + NO2- (aq)

Part A: To write the chemical equation for the equilibrium that corresponds to Ka for nitrous acid, follow these steps:
1. Write the chemical formula for nitrous acid:

HNO2
2. Break down nitrous acid into its ions:

H+ and NO2-
3. Write the chemical equation for the dissociation of nitrous acid in water:

HNO2 (aq) + H2O (l)  ⇌ H3O+(aq) + NO2- (aq) ,where H3O+ represents the hydronium ion and NO2- represents the nitrite ion.

Learn more about nitrous acid (HNO2) : https://brainly.com/question/28166496

#SPJ11

The reaction that illustrates ΔH∘f for NaHCO3 is the one that represents the formation of one mole of NaHCO3 from its constituent elements in their standard states hence the correct reaction is: (b) Na(s) + H2(g) + C(s) + O2(g) → NaHCO3(s)

This reaction shows the formation of NaHCO3 from its constituent elements (Na, H, C, and O) in their standard states (solid, gas, solid, and gas, respectively). ΔH∘f is the enthalpy change when one mole of a compound is formed from its constituent elements in their standard states.

More on reaction equations: https://brainly.com/question/15368283

#SPJ11

The rate constant (k) in the given rate law has units of mol l-1s-1, as it is the ratio of the rate of the reaction to the concentrations of the reactants ([d] and [x]) raised to their respective powers in the rate law equation.

The units of the rate law equation are determined by the orders of the reactants in the reaction, which are given by the exponents in the rate law equation. Thus, the units of the rate constant (k) must be such that the units of the rate (mol l-1s-1) are obtained when the concentrations of the reactants are multiplied by the rate constant (mol l-1s-1 x mol x mol). Therefore, the correct answer is (a) mol l-1s-1.

To learn more about "rate constant", visit: https://brainly.com/question/24749252

#SPJ11

The causes of incomplete combustion are insufficient time, insufficient oxygen, insufficient mixing, and dissociation.This statement is true.

The causes of incomplete combustion are insufficient time, insufficient oxygen, insufficient mixing, and dissociation. Incomplete combustion occurs when there is not enough oxygen to react with the fuel, or due to insufficient time combustion will be partial or insufficient mixing of reactant; which  prevents the combustion process from being completed. This can lead to the production of harmful byproducts such as carbon monoxide.

Incomplete combustion is a chemical reaction that involves the partial oxidation of a fuel. The incomplete combustion occurs where there is an insufficient amount of oxygen. Here, the fuel is incompletely oxidized. Hence, the incomplete combustion forms a number of byproducts.

To learn more about combustion https://brainly.com/question/10458605

#SPJ11

2.35 x 10²⁰ atoms are present in a 27.2 mg sample of Gallium.

The total atomic mass of all the atoms that make up a molecule is calculated using a scale where the atomic masses of hydrogen, carbon, nitrogen, and oxygen are 1, 12, 14, and 16, respectively. For instance, the molecular mass of water, which consists of two hydrogen atoms and one oxygen atom, is 18 (2 + 16).

moles of Gallium = mass of sample / molar mass of Gallium

moles of Gallium = 27.2 mg / 69.72 g/mol

moles of Gallium = 0.0003906 mol

The number of atoms can be determined using Avogadro's number:

number of atoms = moles of Ga x Avogadro's number

number of atoms = 0.0003906 mol x 6.022 x 10²³ atoms/mol

number of atoms = 2.35 x 10²⁰ atoms

To know more about atoms visit:-

https://brainly.com/question/30898688

#SPJ1

There are 6 electrons in a ground-state As atom in the gas phase with quantum numbers n = 3 and l = 1. Therefore, the correct option is option (D) 6.

The quantum number n represents the principal quantum number, which specifies the energy level of an electron. The quantum number l represents the azimuthal quantum number, which specifies the shape of an electron's orbital.

For an As atom in the ground state, the electron configuration is 1s2 2s2 2p6 3s2 3p3. This means there are 5 valence electrons in the 3rd energy level (n = 3).

For an electron with quantum numbers n = 3 and l = 1, we know that it is in a p orbital. There are three p orbitals in the 3rd energy level, each of which can hold up to 2 electrons (with opposite spins). Therefore, there are a total of 6 electrons in the 3rd energy level with l = 1.

Know more about quantum number here:

https://brainly.com/question/2292596

#SPJ11

When examining the potential maps for LiH, HF, and H2:

a. HF and H2 are polar compounds because their potential maps show regions of positive and negative charge separated by a distance, indicating an uneven distribution of electron density. LiH is a nonpolar compound because its potential map shows a uniform distribution of electron density between the two atoms.

b. LiH has the largest hydrogen because its bond length is the shortest of the three compounds. A shorter bond length indicates a stronger bond, which requires more energy to break.

c. HF has the hydrogen that would be most apt to attract a negatively charged molecule because its potential map shows the greatest concentration of electron density near the hydrogen atom. This indicates that the hydrogen atom has a high partial negative charge and is therefore more likely to attract a negatively charged molecule.

To know more about compound here

https://brainly.com/question/634206

#SPJ4

Dislocations do not exist in ionic solids due to their unique structure and bonding properties.

Ionic solids are composed of positively charged cations and negatively charged anions, arranged in a regular repeating lattice. This crystalline structure results in strong electrostatic forces between the oppositely charged ions.

In ionic solids, each ion is surrounded by multiple ions of the opposite charge, which helps to create a strong, stable structure.

The electrostatic attraction between the ions makes it difficult for dislocations to form, as it would require significant energy to move the ions out of their stable positions.

Dislocations are lattice defects that allow for the movement of atoms or ions within the crystal structure.

They play a critical role in the plastic deformation of materials, as they allow for the material to change its shape without fracturing.

However, in ionic solids, the strong ionic bonds and rigid lattice structure make it very difficult for dislocations to form or move.

Furthermore, if a dislocation were to occur in an ionic solid, it would result in closely spaced ions of the same charge being brought together.

This would create an unfavorable high-energy state due to the electrostatic repulsion between the like-charged ions.

The energy required to create and maintain such a dislocation is prohibitively high, making it highly unlikely for dislocations to exist in ionic solids.

In summary, dislocations do not exist in ionic solids due to the strong electrostatic forces between oppositely charged ions, the rigid lattice structure, and the high energy required to overcome electrostatic repulsion between like-charged ions.

To know more about dislocations here

https://brainly.com/question/28444341

#SPJ11

If 20 ml of water is added to 10 ml of a 0.5 m cacl2 solution, what is the new concentration of chloride ions would be 0.334 M.

1. Determine the initial amount of CaCl2:
Initial volume (V1) = 10 ml
Initial concentration (C1) = 0.5 M
Amount of CaCl2 = V1 x C1 = 10 ml x 0.5 M = 5 mmol

2. Calculate the total volume of the new solution:
Initial volume (V1) = 10 ml
Volume of water added = 20 ml
Final volume (V2) = V1 + Volume of water added = 10 ml + 20 ml = 30 ml

3. Determine the new concentration of CaCl2:
Amount of CaCl2 = 5 mmol
Final volume (V2) = 30 ml
New concentration (C2) = Amount of CaCl2 / V2 = 5 mmol / 30 ml = 1/6 M or approximately 0.167 M

4. Calculate the new concentration of chloride ions:
CaCl2 dissociates into 1 Ca²⁺ ion and 2 Cl⁻ ions. So, the concentration of Cl⁻ ions is twice the concentration of CaCl2.
New concentration of Cl⁻ ions = 2 x C2 = 2 x 0.167 M = 0.334 M

So, the new concentration of chloride ions in the solution is 0.334 M.

To know more about concentration calculations here:

https://brainly.com/question/31318951#

#SPJ11

The Solvay method has two main issues, which are:

1. [tex]Ca[/tex] calcium chloride disposal:

2. Limited supplies of raw materials

In the Solvay process, sodium carbonate ([tex]Na_2CO_3[/tex]) is synthesized through a series of chemical reactions involving ammonia, carbon dioxide, and sodium chloride. The main chemical equations for these reactions are:

1. Formation of ammonium chloride:
[tex]NH_3[/tex]+ [tex]HCl[/tex] → [tex]NH_4Cl[/tex]

2. Formation of ammonium bicarbonate:
[tex]NH_3[/tex] + [tex]H_2O + CO_2[/tex] → [tex]NH_4HCO_3[/tex]

3. Formation of sodium bicarbonate (precipitation):
[tex]NH_4HCO_3[/tex] + [tex]NaCl[/tex] → [tex]NaHCO_3[/tex] + [tex]NH_4Cl[/tex]

4. Formation of sodium carbonate (by heating sodium bicarbonate):
[tex]2NaHCO_3[/tex] → [tex]Na_2CO_3[/tex] +[tex]H_2O[/tex] + [tex]CO_2[/tex]

The two major problems with the Solvay process are:

1. Disposal of byproduct calcium chloride: The Solvay process generates a significant amount of calcium chloride  as a byproduct, which requires proper disposal or use. The accumulation and disposal of this waste can lead to environmental concerns.

2. Limited raw material sources: The Solvay process requires high-purity raw materials, specifically sodium chloride and limestone (calcium carbonate). The availability and quality of these raw materials can limit the scalability and efficiency of the process.

Learn more about Solvay here

https://brainly.com/question/1371291

#SPJ11

1) Sodium Hydroxide (NaOH) 2) Sodium Chloride (NaCl)

1. An example of a solution or reagent for which precision is very important is the preparation of a standard solution for titration, such as a sodium hydroxide (NaOH) solution.  Precision is crucial in this case because the accuracy of the titration result depends on the exact concentration of the standard solution. If the concentration is not precise, it can lead to errors in the calculated values and impact the quality of the experimental results.

2. An example of a solution or reagent for which precision is less critical is a sodium chloride (NaCl) solution used for rinsing laboratory glassware. In this case, the exact concentration of the solution is not as important because its primary purpose is to remove contaminants or residual chemicals from the glassware. As long as the solution is able to effectively clean the glassware, minor variations in concentration will not significantly impact the outcome of subsequent experiments using that glassware.

To learn more about sodium hydroxide click here

brainly.com/question/29327783

#SPJ11

A redox reaction would take place if a piece of copper metal was dissolved in a magnesium sulphate solution.

If you place a piece of copper metal in a solution of magnesium sulfate, a redox reaction would occur. The copper metal would oxidize and the magnesium ions in the solution would reduce.

The half-reactions involved are:

Copper oxidation half-reaction:[tex]Cu(s)[/tex] → [tex]Cu^2^+[/tex](aq) + [tex]2e^-[/tex]

Magnesium reduction half-reaction:[tex]Mg^2^+(aq)[/tex] +[tex]2e^-[/tex] → [tex]Mg(s)[/tex]

Overall reaction: [tex]Cu(s) + MgSO_4(aq)[/tex] → [tex]CuSO_4(aq) + Mg(s)[/tex]

In this reaction, the copper metal loses electrons to become [tex]Cu^2^+[/tex] ions, which dissolve in the solution to form copper sulfate. At the same time, the magnesium ions in the solution gain electrons from the copper metal to become magnesium metal.

In summary, if you place a piece of copper metal in a solution of magnesium sulfate, the copper metal will dissolve and copper sulfate will form while magnesium metal will deposit on the surface of the copper metal.

Learn more about redox reaction here

https://brainly.com/question/2671074

#SPJ11

Electron capture transforms 4019K into a nuclide having 18 protons and 22 neutrons. The correct answer is b) 4018Ar.

Electron capture occurs when a proton in the nucleus of an atom captures an electron from an inner electron shell, resulting in the conversion of that proton into a neutron. The process causes a decrease in the atomic number (Z) by one while keeping the mass number (A) the same.

In this case, the initial nuclide is 4019K, with 19 protons and 21 neutrons. When electron capture occurs, one proton is transformed into a neutron, so the resulting nuclide will have 18 protons and 22 neutrons which is option b) 4018Ar.

Learn more about electron capture: https://brainly.com/question/11689871

#SPJ11

The process of electron capture for 4019K results in the transformation of a proton to a neutron within its atom, changing it from potassium (K) to argon (Ar). Therefore, it becomes 4018Ar.

In electron capture, an inner orbital electron is captured by the nucleus of its own atom, usually resulting in the transformation of a proton to a neutron. When a proton in 4019K undergoes electron capture, it changes from potassium (K) to argon (Ar), and its atomic number decreases by one. Therefore, 4019K is transformed into 4018Ar as a result of the electron capture.

https://brainly.com/question/33415187

#SPJ12

When ethyl bromide reacts with potassium cyanide in methanol, the major product formed is CH3CH2CN (ethyl cyanide), while a minor amount of CH3CH2NC (ethyl isocyanide) is also produced.

When ethyl bromide undergoes a reaction with potassium cyanide in methanol, the main product that is formed is ch3ch2cn, which is ethyl cyanide.

However, a smaller amount of ch3ch2nc, which is ethyl isocyanide, is also produced. This reaction is an example of a nucleophilic substitution reaction, in which the cyanide ion acts as a nucleophile and displaces the bromide ion from the ethyl bromide molecule.

The major product, ethyl cyanide, is a useful intermediate in organic synthesis and can be further transformed into a variety of compounds.

Visit here to learn more about  cyanide ion : https://brainly.com/question/29643748
#SPJ11

Answer:

there are two sp2 s p 2 hybridized carbon atoms in allene.

In allene (H2C=C=CH2), there are zero sp2 hybridized carbons. Both carbons involved in the double bonds are sp hybridized.

In allene (H2C=C=CH2), there are two sp2 hybridized carbons present. Hybridization is the process of mixing atomic orbitals to form new hybrid orbitals that have different properties than the original atomic orbitals. Carbon can have three types of hybridization: sp, sp2, and sp3. In sp2 hybridization, one s orbital and two p orbitals of the same energy level combine to form three hybrid orbitals. These hybrid orbitals have a trigonal planar arrangement with bond angles of 120 degrees. In allene, the central carbon atom is sp hybridized and forms two sigma bonds with each adjacent carbon atom. The terminal carbons are sp2 hybridized and form two sigma bonds with each adjacent carbon atom and one pi bond with the central carbon atom. Therefore, there are two sp2 hybridized carbons present in allene.

To learn more about hybridized carbons click here

brainly.com/question/13829121

#SPJ11

The name of this molecule is 2-bromo-3-methylbutan-2-ol.

The chain contains 5 carbon atoms, so the parent chain is a pentane. The alcohol group is attached to the second carbon atom of the chain, so the suffix -ol is added. The bromine atom is attached to the second carbon atom of the chain, so it is indicated by the prefix 2-bromo. The methyl group is attached to the third carbon atom of the chain, so it is indicated by the prefix 3-methyl. 2-bromo-3-methylbutan-2-ol is a chemical compound with the molecular formula C5H11BrO.

It is also known by other names, including 2-bromo-2-methyl-3-butanol, tert-butyl bromoacetate, and tert-butyl 2-bromoacetate.This compound is a colorless liquid with a boiling point of 135-136°C and a density of 1.32 g/mL at 25°C. It is slightly soluble in water but soluble in organic solvents such as ethanol and diethyl ether.

2-bromo-3-methylbutan-2-ol is commonly used as an intermediate in the synthesis of pharmaceuticals and agrochemicals. It can also be used as a starting material for the preparation of other organic compounds.

To learn more about carbon atoms click here

brainly.com/question/30507533

#SPJ11

The Ksp of silver iodate, AgIO3, having a solubility in water of 0.051 g/L, is 3.25 x 10⁻⁸.

The solubility product constant, Ksp, is the product of the concentrations of the ions raised to their stoichiometric coefficients in the balanced equation for the dissolution reaction. For silver iodate, the balanced equation is:

AgIO₃(s) ⇌ Ag⁺(aq) + IO₃⁻(aq)

The Ksp expression for this reaction is:

Ksp = [Ag⁺][IO₃⁻]

To find the value of Ksp, we need to determine the concentrations of Ag⁺ and IO₃⁻. Since the solubility of silver iodate in water is 0.051 g/L, we can use this value to calculate the concentration of AgIO₃ in solution:

AgIO₃(molar mass) = Ag(molar mass) + I(molar mass) + O₃(molar mass)
AgIO₃(282.77 g/mol) = Ag(107.87 g/mol) + I(126.90 g/mol) + O₃(48 g/mol)
[AgIO₃] = 0.051 g/L / 282.77 g/mol = 1.80 x 10⁻⁴ mol/L

Since the stoichiometric coefficients for Ag⁺ and IO₃ ⁻are both 1 in the balanced equation, the concentrations of these ions in solution are also equal to 1.80 x 10⁻⁴ mol/L. Therefore, we can substitute these values into the Ksp expression:

Ksp = [Ag⁺][IO₃⁻] = (1.80 x 10⁻⁴ mol/L)(1.80 x 10⁻⁴ mol/L) = 3.25 x 10⁻⁸

Therefore, the solubility product constant, Ksp, for silver iodate is 3.25 x 10⁻⁸.

Learn more about solubility product constant here: https://brainly.com/question/29350479

#SPJ11

1. The mechanisms of bleaching by the three types of bleaching agents are as follows:

a) Chlorine bleach: Chlorine bleach contains sodium hypochlorite (NaOCl) as the active ingredient. The mechanism of bleaching involves the oxidation of chromophores (color-bearing molecules) in stains or impurities, which breaks the chemical bonds and renders them colorless.

b) Hydantoin and cyanurate bleaches: These bleaches contain active halogen-based compounds like dichloroisocyanurate or bromochlorodimethylhydantoin. The mechanism of bleaching is similar to chlorine bleach, as they release active halogens, which oxidize the chromophores and remove color.

c) Oxygen-releasing bleach: Oxygen-releasing bleaches contain hydrogen peroxide or its precursors like sodium perborate or sodium percarbonate. The mechanism of bleaching involves the release of active oxygen species, which oxidizes the chromophores, breaking their chemical bonds and eliminating color.

Regarding halogen lamps, they have some special features that make them increasingly popular:

- Halogen lamps are more energy-efficient than incandescent lamps, as they produce more light output per watt of electricity.
- They have a longer lifespan compared to incandescent lamps, due to the halogen cycle, which helps prevent the blackening of the glass envelope and redeposit tungsten back onto the filament.
- Halogen lamps produce a whiter, brighter light, which is closer to natural sunlight, making them suitable for various applications like task lighting or highlighting artwork.
- They are available in various sizes and shapes, providing more options for their use in different settings.

I hope this answers your question about the mechanisms of bleaching by different bleaching agents and the special features of halogen lamps.

Learn more about the bleaching agents :

https://brainly.com/question/30883090

#SPJ11

When we talk about the spontaneous process the following is considered true

A spontaneous process refers to the working of a reaction that doesn't require any input from the external environment to facilitate the current system. It is considered an irreversible process and can only be brought back to its prime state using the help of some external agents.

some well-known examples of spontaneous processes are

To learn more about spontaneous processes,

https://brainly.com/question/2855292

#SPJ4

Let's determine which of these compounds can form hydrogen bonds among their own molecules in pure samples of bulk material.

Hydrogen bonding is a strong nonbonding interaction that can occur when a hydrogen atom is bonded to a highly electronegative atom (typically N, O, or F) and is attracted to another highly electronegative atom.

1. [tex]CH^2O[/tex]: This compound does not have a hydrogen atom bonded to N, O, or F. Therefore, it cannot form hydrogen bonds.
2. [tex]CH^3CH^2CH^3[/tex]: This compound does not have a hydrogen atom bonded to N, O, or F. Therefore, it cannot form hydrogen bonds.
3. [tex]CH^2COOH[/tex]: This compound has a hydrogen atom bonded to O (in the COOH group). Therefore, it can form hydrogen bonds.
4. [tex]CH^2OH[/tex]: This compound has a hydrogen atom bonded to O (in the OH group). Therefore, it can form hydrogen bonds.

So, the compounds that can form hydrogen bonds among their own molecules in pure samples of bulk material are [tex]CH^2COOH[/tex] and [tex]CH^2OH[/tex].

To know more about "Hydrogen bond" refer here:

https://brainly.com/question/30402075#

#SPJ11

In the event, that we use exactly 5.62 mL of hot water to dissolve benzoic acid and then try to  cool it in an ice-water bath, we can see a clear  recovery of 372 mg. Therefore, for the given question Option C is the correct answer.

The given expected recovery when 382 mg of benzoic acid is crystallized  can be calculated using the solubility of benzoic acid in water

Considering the Solubility of benzoic acid inside water at

95°C = 6.80 g/100 mL

0°C = 0.18 g/100 mL

The minimum amount of hot water required to dissolve 382 mg of benzoic acid can be calculated using

Let x be the volume of water required in mL

At the solubility of 95°C

 6.80 g/100 mL

= 382 mg / x

Calculating for x

 x = (382  x 100) / (6.80 )

= 5.62 mL

In the event, that we use exactly 5.62 mL of hot water to dissolve benzoic acid and then try to  cool it in an ice-water bath, we can see a clear  recovery of 372 mg. Therefore, for the given question Option C is the correct answer.

To learn more about benzoic acid,

https://brainly.com/question/14282502

#SPJ4

Examples of mechanical energy include contracting, relaxing, and movement.

Mechanical energy is the sum of an object's kinetic and potential energy, which is related to motion and position. In the context of your question, contracting and relaxing represent potential energy changes, while movement represents kinetic energy changes. Chemical energy, on the other hand, is not an example of mechanical energy as it is stored within the bonds of chemical substances.

To know more about the mechanical energy refer here :

https://brainly.com/question/29408366#

#SPJ11

Answer: Brass requires more thermal energy for each degree of temperature change compared to water.

Explanation: Brass requires more thermal energy for each degree of temperature change compared to water. This is because brass has a higher specific heat capacity than water. Specific heat capacity is the amount of thermal energy required to raise the temperature of a given amount of substance by 1 degree Celsius.

The specific heat capacity of brass is 0.38 J/g°C, while that of water is 4.18 J/g°C. This means that it takes 0.38 Joules of energy to raise the temperature of 1 gram of brass by 1 degree Celsius, while it takes 4.18 Joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius.

In practical terms, this means that if a 1-gram piece of brass and a 1-gram volume of water are both initially at 25°C and are heated to 30°C, it would take 0.38 Joules of energy to heat the brass and 4.18 Joules of energy to heat the water to the same temperature. Therefore, more thermal energy is required to heat brass compared to water for each degree of temperature change.

32.0 mL of the 0.300 M LiOH solution is required to neutralize 48.0 mL of the 0.200 M H2SO4 solution.

To solve this problem, we need to use the equation:

M1V1 = M2V2

where M1 is the molarity of the LiOH solution, V1 is the volume of LiOH solution needed, M2 is the molarity of the H2SO4 solution, and V2 is the volume of H2SO4 solution.

We are given:

M2 = 0.200 M
V2 = 48.0 mL

To find M1V1, we need to first convert V2 to liters:

V2 = 48.0 mL x (1 L / 1000 mL) = 0.0480 L

Now we can solve for M1V1:

M1V1 = M2V2
M1V1 = (0.200 M)(0.0480 L)
M1V1 = 0.00960 mol

To find V1, we need to divide both sides by M1:

V1 = (0.00960 mol) / (0.300 M)
V1 = 0.032 L

Finally, we need to convert V1 to milliliters:

V1 = 0.032 L x (1000 mL / 1 L) = 32.0 mL

Therefore, 32.0 mL of the 0.300 M LiOH solution is required to neutralize 48.0 mL of the 0.200 M H2SO4 solution.

Learn more about Neutralize here:-

https://brainly.com/question/30225857

#SPJ11

When benzene is treated with D_2SO_4, a deuterium atom replaces one of the hydrogen atoms through an electrophilic substitution reaction. The mechanism for this reaction involves the formation of a sigma complex, which is an intermediate species that forms when the electrophile, deuterium atom (D_2SO_4) coordinates with the pi electron cloud of benzene.

Explanation-
The first step in the mechanism involves the formation of the sigma complex, where the D_2SO_4 molecule coordinates with the pi electron cloud of benzene. This results in the formation of a cyclic intermediate where the deuterium atom is bound to the carbon atom that originally held the hydrogen atom.

Next, the cyclic intermediate undergoes a proton transfer, where the hydrogen atom is transferred from the adjacent carbon atom to the deuterium atom, resulting in the formation of a new sigma complex. This new sigma complex is then attacked by a nucleophile, which causes the deuterium atom to be replaced with the nucleophile.

Overall, the mechanism for the substitution of a hydrogen atom with a deuterium atom in benzene involves the formation of a sigma complex, followed by a proton transfer and nucleophilic attack.

for more questions on ‘mechanism of formation of sigma complex’: https://brainly.com/question/31328374

#SPJ11

A syringe contains 56.05 ml of gas at 315.1 k. what volume will that gas occupy if the temperature is increased to 380.5 k is 0.076 l or 76 ml.

To answer this question, we can use the ideal gas law equation: PV = nRT, where P is pressure, V is volume, n is the number of moles of gas, R is the ideal gas constant, and T is temperature.
Since we know the initial volume and temperature of the gas in the syringe, we can use this information to calculate the initial pressure and number of moles of gas. We'll assume that the pressure remains constant as the temperature changes.
PV = nRT
n = PV/RT = (1 atm) * (56.05 mL) / (0.0821 L*atm/mol*K * 315.1 K) = 0.0023 moles

Now, we can use the same equation to calculate the new volume of the gas when the temperature increases to 380.5 K.
V = nRT/P = (0.0023 mol) * (0.0821 L*atm/mol*K) * (380.5 K) / (1 atm) = 0.076 L or 76 mL
Therefore, the gas in the syringe will occupy a volume of 76 mL when the temperature increases to 380.5 K.

To know more about the gas volume refer here :

https://brainly.com/question/24189159#

#SPJ11