The horizontal force to be applied on the puck is 2.16 N
The horizontal force to be applied to a puck of given mass and acceleration on a friction-free table
Given:
A 1.2-kg puck is moved on a horizontal friction-free air table with an acceleration equal to that of 1.8 [tex]m/s^2[/tex]
Using Newton’s second law of motion, a body experiencing a force F gets accelerated in the direction of the force and its magnitude a is proportional to magnitude of the applied force. It also holds an inverse relation with the mass of the body m . This can be expressed as,
[tex]F = Ma[/tex]
Here, mass of the puck is 1.2kg. The acceleration is 1.8 [tex]m/s^2[/tex]
F = 1.2 x 1.8
F = 2.16 N
What is Friction ?Friction is a force that prevents the relative movement of solid surfaces, fluid layers and material elements sliding against each other. There are several types of friction:
Dry friction is a force that opposes the relative lateral movement of two solid surfaces in contact. Dry friction is divided into static friction ("stich") between non-moving surfaces and kinetic friction between moving surfaces. In addition to atomic or molecular friction, dry friction usually arises from the interaction of surface features called turgidities. Fluid friction describes friction between layers of viscous fluid moving relative to each other. Lubricating friction is fluid friction where a lubricating fluid separates two solid surfaces. Skin friction is part of the resistance, the force that prevents the movement of fluid on the surface of the body. Internal friction is a force that prevents movement between the components of a solid material during its deformation.To learn more about friction, visit;
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what is the average velocity of a race car that traveled 88km in 20 min
Answer:
73.3333meters per second
Explanation:
average velocity= distance ÷ time
=(88×1000)/(20×60)
=73.3333m/s
what is the moment of inertia of the object starting from rest if it has a final velocity of 5.8 m/s? express the moment of inertia as a multiple of mr2 , where m is the mass of the object and r is its radius.
The moment of inertia of the object as a multiple of MR² is 0.126 MR².
According to the law of conservation of energy he is always conserved at each and every point so going by this,
At the top will be equal to the energy at the bottom.
Because at the top there will be no kinetic energy and add the bottom there will be no potential energy the bottom there will be only kinetic energy and rolling energy.
So we can write,
Mgh = 1/2IW² +1/2MV²
Where,
M is the mass of the body,
G is acceleration due to gravity,
H is the height,
I is the moment of inertia,
W is angular velocity,
V is the linear velocity.
The height of the object is given to be 2.11 m. Final velocity is given to be 5.8m/s.
Now, putting all the values,
M(2.11)(9.8) = 1/2(IV²/R²) + 1/2MV²
I = 0.126MR²
Hence the moment of inertia of the object is 0.126MR².
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Complete question- an object rolls without slipping down a 2.1 m high incline.
What is the moment of inertia of the object starting from rest if it has a final velocity of 5.8m/s stress the moment of inertia as a multiple of MR² object and R is its radius.
Are there any exceptions to the rule that planets rotate with small axis tilts and in the same direction as they orbit the sun?.
Venus and Uranus are exception to these rules.
Venus rotates in the horizontal course when Uranus falls as it circles the solar on its aspect.Venus, like the different stars, at the beginning rotates anticlockwise however it nevertheless does.The exceptions are Venus and Uranus but they've what's called regressive rotation, rotating parallel to the solar's roster.
Uranus is the 7th planet from the sun. Its call is a connection with the Greek god of the sky, Uranus, who, in step with Greek mythology, turned into the exceptional-grandfather of Ares, grandfather of Zeus and father of Cronus. It has the third-largest planetary radius and fourth-largest planetary mass in the solar system.
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a car accelerates from rest to 30m/s while traveling a distance of 20m what was its acceleration
Answer:
22.5 m/s²
Explanation:
The final velocity, initial velocity, distance traveled and acceleration are related by the equation
v² = u² - 2ad [1]
where
v = final velocity
u = initial velocity
a = acceleration
d = displacement
We can manipulate the above equation [1] to solve for a in terms of the other parameters
a = (v² - u²)/2d
Given v = 30 m/s, u = 0 m/s, d = 20 m.
a = (30² - 0²)/(2 x 20)
a = 900/40
a = 22.5 m/s²
How do the Earth's physical factors influence population density? When population growth increases in an area, what is happening to the
birth rate and age structure of that population?
Any region's population density is determined by the physical characteristics of Earth.
Earth:
The only astronomical object known to harbour life is Earth, which is third from the Sun. Despite the vast amounts of water in the Solar System, only Earth has liquid surface water. Around 71% of the surface of the Earth is covered by the seas, dwarfing its lakes, rivers, and polar ice. The remaining 29% of the Earth's surface is made up of land, which includes continents and islands. The interplay between the numerous slowly moving tectonic plates that make up the Earth's surface layer produces mountain ranges, volcanoes, and earthquakes. The planet's liquid outer core generates the magnetic field that creates the magnetosphere and diverts dangerous solar winds.
The population density is greatly influenced by the physical characteristics of the Earth. It is evident that locations with ideal living circumstances have higher population densities. The population density is influenced by the temperature and climate.
An territory's birth rate will rise and its mortality rate will fall as population growth grows in that location. The population consequently starts to increase.
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pleaseee help im struggling a lottt
Answer:
d=s/t
Explanation:
s=d/t
/t /t
s/t=d
Hope this helps
The diagram below shows a wind turbine.
At a particular wind speed, a volume of 2.3 × 10ª m³
of air passes the blades each second.
The density of air is 1.2 kg/m³.
Calculate the mass of air passing the blades per
second.
The mass of air passing the blades per second is 2.76 × [tex]10^{4}[/tex] kg
What is wind energy formula?A kind of solar energy is wind energy. The technique through which wind is utilized to generate power is known as wind energy. The kinetic energy in the wind is converted to mechanical power by wind turbines.
A renewable energy source that harnesses the power of the wind is wind energy. The wind energy formula is given by,
P = 1/2 ρAV³, where P = Power
Given that,
density of air (ρ) = 1.2kg/m³
volume (v) = 2.3×[tex]10^{4}[/tex] m³
Now calculate mass of the air -
mass = density × volume
= 1.2 × (2.3 × [tex]10^{4}[/tex])
= 2.76 × [tex]10^{4}[/tex] kg
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two tugboats pull a disabled supertanker. each tug exerts a constant force of 1.20×106 nn , one at an angle 10.0 ∘∘ west of north, and the other at an angle 10.0 ∘∘ east of north, as they pull the tanker a distance 0.880 kmkm toward the north.
The ideas of vector components and the work done are relevant to this question.
The total work done by the two tugboats on the supertanker is "2.03 x 10⁹ J".
First, we will calculate the force in the direction of the displacement. It will be the sum of the x- vector components of both the forces:
Fx = Fx1 +Fx2
Fx = Fcosθ₁+Fcosθ₂
where,
F = magnitude of forces = 1.2 x 10⁶ N
θ₁ = angle of the first boat with horizontal = 10°
θ₂ = angle of the second boat with horizontal = 10°
Therefore,
Fx=2(1.2 x 10⁶) (cos10)
Fx=2,361,600
Now, we will calculate the work done by the tugboats:
Work done = Fx × d
W = 2,316,600×880
W=2.03 x 10⁹ J
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What is the velocity of a 1-kg ball that is dropped from a 50m height after free-falling
for 1 second?
Answer:
See below
Explanation:
Weight/mass of the object is irrelevant ( not needed)
v = at
= 9.81 m/s^2 * 1 s = 9.8 m/s
If X = 5 and Y = 3, what does Z equal?
Answer:
What is the figure? please provide
A 1520 kg car accelerates at a rate of
1.50 m/s². What is the net force on the car?
Answer:
Your answer is F = 2280 N
Explanation:
The formula for force is [tex]F=ma[/tex]. Given this formula, [tex]1520[/tex] × [tex]1.5[/tex] [tex]= 2280[/tex]
According to the nebular theory of solar system formation, which law best explains why the solar nebula spun faster as it shrank in size?.
The law of conservation of angular momentum.
What is angular momentum?
Angular momentum is the rotational analog of linear momentum in physics. It is a conserved quantity, meaning the total angular momentum of a closed system remains constant. Both the direction and magnitude of angular momentum are conserved.
What is the law of conservation of angular momentum?
The law of conservation of angular momentum asserts that a system's total angular momentum is conserved when there is no external torque present. In other words, the magnitude and direction of the total angular momentum of an isolated system remain constant.
According to the Nebular Theory, the solar system originated as a massive, slowly rotating cloud of gas measuring around one light-year in diameter. As the cloud cooled, its own gravity caused it to collapse. It distorted into a revolving pancake shape due to the conservation of angular momentum, which required it to spin faster as it shrank.
Hence, the law of conservation of angular momentum best explains why the solar nebula spun faster as it shrank in size.
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osteoporosis is a condition that makes bones more
consider a large truck carrying a heavy load, such as steel beams. a significant hazard for the driver is that the load may slide forward, crushing the cab, if the truck stops suddenly in an accident or even in braking. assume, for example, that a 11,000 kg load sits on the flat bed of a 15,000 kg truck moving at 16.0 m/s. assume that the load is not tied down to the truck, but has a coefficient of friction of 0.450 with the flat bed of the truck. (a) calculate the minimum stopping distance for the truck for which the load will not slide forward relative to the truck.
Answer:
WOW are you a cool women?
if you transmitted radio signals to the moon when it is 385,000 km from earth and waited to receive the echo, how long would you wait (in s)?
If you transmitted radio signals to the moon when it is 385,000 km from the earth and waited to receive the echo, then you have to wait 2.57 seconds.
What is Velocity?The total displacement covered by any object per unit of time is known as velocity.
As given in the problem if you transmitted radio signals to the moon when it is 385,000 km from the earth and waited to receive the echo,
The speed of light = 3 × 10⁸ m /s
The distance traveled by the radio waves = 2 × 385,000 × 1000
= 770000000 meters
The time of the echo = 770000000 / 3 × 10⁸
= 2.57 seconds
Thus, you have to wait 2.57 seconds to receive the echo.
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a car traveling at 27 m/s hits a tree. if the front end of the car is 1.2 meters, what is the acceleration rate of the car.
The acceleration rate of the car travelling at 27m/s in 1.2metres is 303.8m/s².
How to calculate acceleration?Acceleration of a body refers to the amount by which a speed or velocity increases. The acceleration of a moving body can be calculated using one of the equation of motion as follows:
v² = u² + 2as
Where;
v = final velocityu = initial velocitya = accelerations = distanceAccording to this question, a car traveling at 27 m/s hits a tree. if the front end of the car is 1.2 meters, the acceleration rate of the car can be calculated as follows:
27² = 0² + 2(a)(1.2)
729 = 2.4a
a = 303.8m/s²
Therefore, 303.8m/s² is the acceleration of the car.
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The gravitational force beyween two objects is 2000 N. The mass of the objects is reduced to one-third of its original mass
AP Physics -An object is thrown downward with an initial speed of 20. m/s on Earth. What is the:
a) acceleration of the object
b) displacement after 4 seconds.
c) time required to reach a speed of 50. m/s.
d) time required to fall 300. M (Hint: factor the quadratic).
e) speed after falling 100. m.
Answer:
Explanation:
Given:
V₀ = 20 m/s
t = 4 s
V = 50 m/s
H₁ = 300 m
H₂ = 100 m
______________
a) Acceleration of the object:
g = 9.8 m/s²
b) Displacement after 4 seconds.
H = V₀*t₁ + g*t²/2 = 20*4 + 9.8*4² / 2 ≈ 160 m
c) Time required to reach a speed of 50 m/s.
t = (V - V₀) / g = (50 - 20) / 9.8 ≈ 3 s
d) Time required to fall 300 m.
H₁ = V₀*t + g*t²/2
300 = 20*t + 9.8*t² / 2
4.9*t² + 20*t - 300 = 0
t ≈ 6 s
e) Speed after falling 100 m.
Н₂ = (V₂² - V₀²) / (2*g)
V₂² = V₀² + 2*g*H
V₂ = √ (V₀² + 2*g*H) = √ (20² + 2*9.8*100) ≈ 49 m/s
HELP! PLEASE Show ALL the work, Thank you!
Jacque's velocity during the race segment is 3 meter/sec.
The direction of a body or object's movement is defined by its velocity. In its basic form, speed is a scalar quantity. In fact, velocity is a vector quantity. It has magnitude and direction both.
We are given that,
The time taken by Jacque = Δt = t₂ - t₁ = 7.0min - 3.5min = 3.5 min
The distance covered in race = Δx = x ₂- x₁ = 1260m - 630m = 630m
To get the velocity of the racer we can calculate by the equation,
V = Δx/ Δt
Here, Δx is the change in distance and Δt is the change in time of the racer. So putting the value in above equation for getting racer velocity,
V = 630m/3.5min
V = 180 m/min
V = 3 m/sec
Therefore , Jacque's velocity during the race would be 3 m/s.
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Which of the following statements about the nucleus of a typical atom (such as a carbon atom in your little finger) is FALSE:
A. the nucleus has an overall positive charge
B. the nucleus takes up a very small amount of space compared to the entire atom
C. the nucleus contains both protons and neutrons
D. the nucleus repels the electrons which move around it
E. the nucleus contains most of the mass of the atom
Answer:
D - False
Explanation:
D the protons and electrons are ATTRACTED to each other
The statement which is false about the nucleus of an atom is that the nucleus repels the electrons which move around it. Hence, option D is correct.
What is an atom?The atom is the smallest particle of matter that may be divided without releasing electrically charged. Additionally, it is the smallest piece of matter with the characteristics of a chemical substance. The atomic is the basic unit of chemistry as a result. The majority of an atom remains in space. A cluster of negative electrons surrounds a positive charge nucleus made up of nucleons, which make up the rest of the structure.
The electrons, the lightest alpha particles in nature, are larger and less dense than the nucleus, which is both small and dense. Electrons are drawn to positive charges by their electric forces, which also bind electrons to a nucleus in an atom.
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what true airspeed and angle of attack should be used to generate the same amount of lift as altitude is increased?
According to the given statement A higher true airspeed for any given angle of attack.
How do you determine angle of attack?The angle between both the wing and the direction of flight is known as the angle of attack. The angles of attack is also the angle between both the wing and the relative wind since the direction of flight is the opposite of the airflow.
What is the best angle of attack?The ideal launch angle is dependent on ball speed, according to physics. The ideal launch angle is around 15 degrees at ball velocities typical of most amateur players. The average launch angle of PGA Tour golfers is just over 11 degrees because to their faster ball speed.
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A ball, thrown upward, initially loses speed due to downward free-fall__________. At the top of it’s trajectory, it momentarily stops, then increases its speed as it descends. Throughout, its acceleration is ___________.
A ball, thrown upward, initially loses speed due to downward free-fall. At the top of it’s trajectory, it momentarily stops, then increases its speed as it descends. Throughout, its acceleration is (g)= 9.8 m/s²
What is acceleration?A particular object has changed its velocity in a particular time. That ratio called the acceleration of the object. Example: A car starts its journey from rest and ends at 25 m/s velocity in 5 second interval. So the acceleration is = 25/5 = 5m/s²
How can we calculate the acceleration of the ball?According to the definition of the acceleration due to gravity, Whenever a particle or a object throw upwards some amount of force attract that object at the center of the earth that is called the gravity. For this gravity that produce a acceleration due to gravity. The value of acceleration due to gravity is 9.8 m/s².
According to the question a ball is thrown upwards, initially loses speed due to downward free-fall. This case happens for the gravity.
At the top of it’s trajectory, it momentarily stops, then increases its speed as it descends. This also happens for the gravity cause the ball always attract the ball at the center of the earth.
For this attraction the acceleration due to gravity generated. So its acceleration throughout the case is same as the acceleration due to gravity, that means = 9.8 m/s².
According to the conversation, we can conclude that, Throughout, its acceleration is (g)= 9.8 m/s²
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2. The potential energy of an object depends on its _______.
Answer:
homboy it Position
Explanation:
Answer: i think position
Explanation:just thinking
What is the wavelength in micrometers of light with a frequency of 3. 2 × 10^12 hz?.
94 mn the wavelength in micrometers of light with a frequency of 3. 2 × 10^12 hz.
What is wavelength?
The wavelength of a periodic wave is the distance over which the wave's shape repeats in physics. It is the distance between two successive corresponding locations of the same phase on the wave, such as two neighbouring crests, troughs, or zero crossings, and it is a feature of both travelling and standing waves, as well as other spatial wave patterns. The spatial frequency is the inverse of the wavelength. The Greek letter lambda (λ) is widely used to represent wavelength.
Because all electromagnetic waves travel at the speed of light, c = v (lambda) where v is frequency and lambda is wavelength and c is the speed of light.
v=c/λ
By putting the values -
3.2 × 10^12 = 3.00*10^8 / λ
λ= 3.0010^8 / 3.2 × 10^12
= 9.375m 1 / 10^
= 94 mn
Therefore the answer to this question is 94 mn.
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Choose the statements that accurately describe the feeding relationships in this food web. Check all that apply.
The otter is a secondary consumer.
The frog is a secondary consumer.
The algae are producers.
The flies are primary consumers.
The snails are primary consumers.
The heron is a secondary consumer.
The algae are producers. The otter is a secondary consumer, frog is a secondary consumer. The flies are primary consumers, snails are primary consumers and heron is a secondary consumer. All statements are correct.
What is a food web?A food web is basically a graphical representation of animals eating each other in an ecological community that is formed by the natural interconnection of food chains.
Sea otters are secondary consumers that hunt sea urchins in the kelp forest. A secondary consumer is the great blue heron. It can be eaten by the food web's tertiary consumer.
Snails are herbivores, which means they only eat plants, and thus fit into the food web as primary consumers.
Herbivores are always the primary consumers, and omnivores can be the primary consumers when eating plants. Rabbits, bears, giraffes, flies, humans, horses, and cows are examples of primary consumers.
Thus, all the given statements are correct.
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)since individual stars can live from millions to billions of years, how can observations taken at the current time tells us about stellar evolution?
A nebula is a cloud of gas and dust that gives rise to stars. The lone star can shine on its own for a very long time. They are not everlasting, despite the fact that they shine for a very long period. These observations allow us to examine the inside of stars of various ages, each of which has a unique interior temperature and set of circumstances.
How do stars develop?In frigid clouds of gas and dust, stars form. Because dust is particularly opaque to optical and ultraviolet light, neither wavelength will get through the star-forming zone. Although less opaque than dust, gas remains opaque nonetheless. (b) Infrared, microwave, and radio wavelengths all easily penetrate dust. Additionally, dust scatters IR wavelengths to UV-optical light, which makes newborn stars and other dusty objects even luminous in the IR. Atomic and molecular gas that is cool (T 50 k) and dense is visible in the IR and also emits line radiation in the submm and radio.
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A circuit with a battery, a 14 Ω resistor, and a 17 Ω resistor, in parallel. The total current is the system is 2.8 A. What is the voltage of the battery?
Given data:
* The total current in the system is I = 2.8 A.
* The resistance of resistors connected in parallel is,
[tex]\begin{gathered} R_1=14\text{ ohm} \\ R_2=17\text{ ohm} \end{gathered}[/tex]Solution:
The equivalent resistance of the system is,
[tex]\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}[/tex]Substituting the known values,
[tex]\begin{gathered} \frac{1}{R_{eq}}=\frac{1}{14}+\frac{1}{17} \\ \frac{1}{R_{eq}}=\frac{17+14}{14\times17} \\ R_{eq}=\frac{14\times17}{17+14} \\ R_{eq}=7.68\text{ ohm} \end{gathered}[/tex]According to Ohm's law, the voltage across the battery in terms of the current and equivalent resistance is,
[tex]\begin{gathered} V=IR_{eq} \\ V=2.8\times7.68 \\ V=21.5\text{ volts} \end{gathered}[/tex]Thus, the voltage across the battery is 21.5 volts.
A car of mass 1,000 kg begins stationary on a road at the top of a mountain, at a height h = 3,000 m. The car then rolls freely down a winding road, travelling a total distance of 5 km, to reach the height h = 2,000 m. Assume g = 9.8 ms-2:
give answer in 3 significant figures, with units.
The amount of energy lost by the car when it descended from a height of 3000 m to 2000 m is 980×10⁴ J
How do I determine the energy lost?We'll begin by obtaining the energy at the top of the mountain (height = 3000 m). This is shown below:
Mass (m) = 1000 KgAcceleration due to gravity (g) = 9.8 m/s²Height (h) = 3000 mEnergy (E) =?E = mgh
E = 1000 × 9.8 × 3000
E = 29400000 J
Next, we shall obtain the energy at height = 2000 m
Mass (m) = 1000 KgAcceleration due to gravity (g) = 9.8 m/s²Height (h) = 2000 mEnergy (E) =?E = mgh
E = 1000 × 9.8 × 2000
E = 19600000 J
Finally, we shall obtain the the energy lost by the car. Details below:
Energy (at height 3000 m) = 29400000 JEnergy (at height 2000 m) = 19600000 JEnergy lost =?Energy lost = Energy (at height 3000 m) - (at height 2000 m)
Energy lost = 29400000 - 19600000
Energy lost = 980×10⁴ J
Thus, we can conclude that the energy lost is 980×10⁴ J
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Complete question:
A car of mass 1,000 kg begins stationary on a road at the top of a mountain, at a height h = 3,000 m. The car then rolls freely down a winding road, travelling a total distance of 5 km, to reach the height h = 2,000 m. Assume g = 9.8 ms-2:
How much energy did the car lose on descent? Give you answer to 3 significant figures, with units.
Energy lost =?
A coin is dropped from a height of 80 m. How fast will it fall, just before it hits the ground? [Take g = 10 m/s2 , Hint: For a falling body, the total PE at the greatest height will be equal to the K.E., just before it touches the ground]
The speed of the coin just before it hits the ground dropped from a height of 80 m will be 40 m / s
The total PE at the greatest height = The K.E just before it touches the ground
PE = m g h
KE = 1 / 2 * mv²
PE = Potential energy
KE = Kinetic energy
m = Mass
g = Acceleration due to gravity
h = Height
v = Final velocity
h = 80 m
g = 10 m / s²
PE = KE
m g h = 1 / 2 * mv²
m * 10 * 80 = 1 / 2 * m * v²
v² = 800 * 2
v = √ 1600
v = 40 m / s
Potential energy is the energy at rest and kinetic energy is the energy in motion. Potential energy is maximum at rest and when the object starts to move, it potential energy drops and it kinetic energy rises.
Therefore, the speed of the coin just before it hits the ground is 40 m / s
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An Atwood machine consists of 40-kg object A and 43-kg object B. Suppose
object A is released from rest. Determine the magnitude of the acceleration for
both objects. Assume the rope and pulley are massless.
Help
The magnitude of the acceleration for both objects is 0.36 m/s².
Acceleration is the name we supply to any system wherein the velocity modifications. for the reason, that velocity is a velocity and a path, there are only methods in order to accelerate: trade your velocity or exchange your path or exchange each.
Acceleration is the fee of alternating of the velocity of an object with recognition to time. Accelerations are vector quantities. The orientation of an object's acceleration is given by means of the orientation of the internet pressure acting on that object.
Uniform acceleration, non-uniform acceleration, and average acceleration are the three varieties of multiplied motions. The term uniform acceleration refers to a motion in which an object travels in an immediate line with an increase in velocity at the same intervals of time.
calculation:-
mass 1 = 43 kg
F₁ = 430 N
mass 2= 40 kg
F₂ = 400 N
Tension = (F₁m₂ + F₂m₁)/ m₁ + m₂
= (430 × 40 + 400 × 43) / 83
=34400 /83
= 414.46 N
a = (F₁ - F₂)/ toatl mass
= 430 N - 400N / 83
= 0.36 m/s²
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