Calculate the kinetic energy of an object of mass 10kg when it is moving with a velocity 2ms

Answers

Answer 1

The kinetic energy of the mass will be 20 Joules.

Given:

mass [tex]m[/tex] = 10 kg

velocity [tex]v[/tex] = 2 m/s

To find:

Kinetic energy KE =?

Solution:

                        KE = [tex]\frac{1}{2}[/tex][tex]mv^{2}[/tex]

                             = [tex]0.5[/tex] x [tex]10[/tex] x [tex]2^{2}[/tex]

                             = [tex]20[/tex] [tex]joules[/tex] [tex]or[/tex] [tex]kg.m/s^{2}[/tex]

For reference:

https://www.geeksforgeeks.org/practice-problems-on-kinetic-energy/

Answer 2

Answer: The answer  is the kinetic energy of the object is 20 joules .

Explanation: we know that ,

               here, mass= 10 kg;

                          velocity = 2m/s

 The kinetic energy of the object = 1/2×mass×(velocity)²

                                                           =  1/2×10kg×(2m/s)²

                                                           =1/2×10 ×4kg(m/s)²

                                                            =5×4 joules

                                                             = 20 joules or

                                                                          0.02 kilo joules


Related Questions

Part A. A block is sliding with constant acceleration down an incline. The block starts from rest at t = 0 and has speed 3.40 m/s after it has traveled a distance 8.90 m from its starting point.
What is the speed of the block when it is a distance of 17.8 m from its t = 0 starting point? Express your answer with the appropriate units.

Answers

The speed of the block when it is a distance of 17.8 m from its starting point is 14.1 m/s.

What is speed?

Speed is a rate at which something is travelling or moving. It can be measured in a variety of ways, such as miles per hour (mph), kilometres per hour (kph), metres per second (m/s), or knots.

The acceleration of the block can be calculated using the equation a = (v-u)/t, where a is the acceleration, v is the final velocity, u is the initial velocity and t is the time. Since the initial velocity of the block is 0 m/s, we can write: a = v/t.
Using the given information, we know that when the block has traveled a distance of 8.90 m from its starting point, its speed is 3.40 m/s. Therefore, we can calculate the acceleration of the block as follows: a = 3.40 m/s / (8.90 m / 3.40 m/s) = 0.38 m/s2.
Now, we can use the equation v2 = u2 + 2ax to calculate the velocity of the block when it is a distance of 17.8 m from its starting point. Substituting the known values, we get: v2 = 0 + 2(0.38 m/s2)(17.8 m) = 14.1 m/s2
Therefore, the speed of the block when it is a distance of 17.8 m from its starting point is 14.1 m/s.

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a hockey puck at rest is equilibrium is it in equilibrium if it slides across ice at constant velocity

Answers

No, the hockey puck is not in equilibrium if it slides across ice at a constant velocity.

What is equilibrium?

Equilibrium is a state of balance in a system where opposing forces are equal and there is no net change. In economics, equilibrium is a situation in which market supply and demand balance each other out and, as a result, prices become stable. When a market is in equilibrium, the amount of goods and services produced by suppliers is equal to the amount of goods and services demanded by consumers. In this state of balance, there is no tendency for prices to change. Equilibrium is an essential concept in economics, as it helps to explain how prices are determined in a market-based economy.

Equilibrium implies a state of balance, where the forces acting upon the object are balanced and the object is not accelerating. Since the hockey puck is moving across the ice surface at a constant velocity, there is an unbalanced force acting on it, causing it to move. Therefore, it is not in equilibrium.

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Which of the following statements are true concerning particles and antiparticles?Check all that apply.a) All particles have antiparticles.b) The antiproton can be described as the antiparticle to the proton.c) Antiparticles have a very long lifetime.d) Some particles serve as their own antiparticles.e) The proton can be described as the antiparticle to the electron.f) Antiparticles are produced in nuclear reactions.

Answers

The true statements concerning particles and antiparticles are:

b) The antiproton can be described as the antiparticle to the proton.

d) Some particles serve as their own antiparticles.

f) Antiparticles are produced in nuclear reactions.

Every charged particle has an antiparticle, which has the same mass and spin as it has but the opposite charge, according to the quantum field theory. All of the available experimental data supports this broad quantum field theory conclusion. The positron is the electron's antiparticle.

Antiparticles are subatomic particles with opposing electric charge and magnetic moment but the same mass as a particle of regular matter. Consequently, the positron (a positively charged electron) is the negatively charged electron's antiparticle.

An antiparticle is a subatomic particle that, by definition, has the same mass as its counterpart in a normal particle but the opposite magnetic moment and electric charge. For instance, the antiparticle of an electron is a positron.

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If you throw a ball straight downward (in the absence of air resistance), after leaving your hand its acceleration isSelect one:a. less than 10 m/s2.b. greater than 10 m/s2.c. 10 m/s2.

Answers

After the ball leaved the hand its acceleration is: 10 m/s2

What is vertical launch?

In physics vertical launch is the motion described by an object that has been launched vertically in which the acceleration is the earth's gravitational force.

In the vertical launch downward movements, the acceleration due to the gravity is always acting downward and its value is 10 m/s2, this is because of attraction that the earth exerts on all bodies pulling them toward its center

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The magnetic structure of figure 1.21 was built with cast steel. As the final flux density is low, the relative magnetic permeability may be taken as 1000.
determine: a. the reluctance of all legs of the structure;

Answers

About Magnetic

Magnets are one of the objects that are widely used in human life today, because of their ability to attract metal so that they can be used in everyday life. Magnets can be used in making electric motors, power plants and so on.

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which one of the following statements concerning the electric field is false? the si unit of the electric field is the newton per meter (n/m). the magnitude of the electric field at a particular location due to a particular charged particle is inversely proportional to the square of the distance of the particle from that location. at a given point, a charged particle will experience a force, if an electric field is present at that location. if a positively charged particle is placed at a location where the electric field is directed due north, it will be accelerated due north. the electric field is a vector quantity.

Answers

The statement that is false is:

"if a positively charged particle is placed at a location where the electric field is directed due north, it will be accelerated due north."

A charged particle will experience a force in the direction of the electric field, but it may not necessarily be accelerated in the same direction. The acceleration of a charged particle depends on other factors such as the mass of the particle, the strength of the electric field, and any other forces acting on the particle. So, a positively charged particle may not be accelerated due north, even if the electric field is directed due north. The electric field is a fundamental concept in physics and is used to describe the force that a charged particle experiences in a given electric field. It is a vector quantity that represents the force per unit charge and is defined as the force that a charged particle would experience if placed at a given point in space.

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Whait is harmonics of recuency?

Answers

A harmonic is a wave or signal whose frequency is an integral (whole number) multiple of the frequency of the same reference signal or wave.

Define  harmonics of  frecuency?

Harmonics is defined as the integer (whole number) multiple of the fundamental frequency. Open cylindrical columns, vibrating strings will vibrate at all the harmonics of the fundamental frequency.

In music, harmonics are used on string instruments and wind instruments as a way of producing sound on the instrument, particularly to play higher notes and, with strings, obtain notes that have a unique sound quality or "tone colour".

The first harmonic is also called the fundamental frequency. It is the lowest possible value of the frequency. In simple words, a wave that has only 2 nodes and an antinode is called the first harmonic.

The harmonic frequencies are integer multiples [2, 3, 4, ...] of the fundamental frequency. For example, the 2nd harmonic on a 60 Hz system is 2*60 or 120 Hz. At 50Hz, the second harmonic is 2* 50 or 100Hz. 300Hz is the 5th harmonic in a 60 Hz system, or the 6th harmonic in a 50 Hz system.

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A 10g bullet moving 70ms-¹ penetrate a block of wood 5cm before stopping determine the kinetic energy of the bullet, the average stopping force​

Answers

Answer:

-490 Newtons

Solution:

The work is attached

Calculate the pressure exerted on the ground by a person weighing 70kg whose two feet cover an area of 400cm square.if the man stands on one foot,what is the new pressure he exerts on the ground?

Answers

Pressure is force per unit area. To calculate the pressure exerted on the ground by a person, we need to know the force the person is exerting and the area of their feet.

The person weighs 70 kg, and the force of gravity acting on them is equal to their weight, so the force exerted on the ground by the person is 70 kg x 9.8 m/s^2 = 686 N (Newtons)

The area of their feet is 400 cm^2, which is equal to 0.04 m^2 (since 1 cm^2 = 0.0001 m^2)

The pressure exerted on the ground by the person is equal to the force exerted divided by the area of the feet:
Pressure = 686 N / 0.04 m^2 = 17150 Pa (Pascals)

If the man stands on one foot, the area of the foot in contact with the ground will be half the original area, so 0.04 m^2/2 = 0.02 m^2
The pressure exerted on the ground will be 686 N/ 0.02 m^2 = 34,300 Pa. So he will exert double the pressure on the ground as he was exerting before.

A car travels at 75 km/h on a level road in the positive direction of an x axis. each tire has a diameter of 69 cm. relative to a woman riding in the car, what are the following values?
(a) the velocity v at the center of each tire
( __ m/s)
(b) the velocity v at the top of each tire
( ___ m/s)
(c) the velocity v at the bottom of each tire
( __m/s)
(d) the magnitude a of the acceleration at the center of each tire
__m/s2
(e) the magnitude a of the acceleration at the top of each tire
__m/s2
(f) the magnitude a of the acceleration at the bottom of each tire
__m/s2
Relative to a hitchhiker sitting next to the road, what are the following values?
(g) the velocity v at the center of each tire
( __ m/s)
(h) the velocity v at the top of each tire
( __m/s)
(i) the velocity v at the bottom of each tire
( __m/s)
(j) the magnitude a of the acceleration at the center of each tire
__m/s2
(k) the magnitude a of the acceleration at the top of each tire
__ m/s2
(l) the magnitude a of the acceleration at the bottom of each tire
__ m/s2

Answers

The conversion factor from km/h to m/s is 1000/3600 m/s/km/h.

So, the velocity of the car relative to the woman riding in the car is 75 km/h x (1000/3600 m/s/km/h) = 20.83 m/s.

(a) The velocity at the center of each tire is the same as the velocity of the car relative to the woman riding in the car, which is 20.83 m/s.

(b) The velocity at the top of each tire is 20.83 m/s + (π x (69/2) cm x 2π radians/s /s) = 20.83 m/s + 27.77 m/s = 48.60 m/s.

(c) The velocity at the bottom of each tire is 20.83 m/s - (π x (69/2) cm x 2π radians/s /s) = 20.83 m/s - 27.77 m/s = -6.94 m/s.

(d) The acceleration at the center of each tire is 0 m/s2.

(e) The acceleration at the top of each tire is (π x (69/2) cm x 2π radians/s^2) = 869.68 m/s^2.

(f) The acceleration at the bottom of each tire is - (π x (69/2) cm x 2π radians/s^2) = -869.68 m/s^2.

Relative to the hitchhiker sitting next to the road, the velocity of the car is negative, i.e., -20.83 m/s.

(g) The velocity at the center of each tire relative to the hitchhiker is -20.83 m/s.

(h) The velocity at the top of each tire relative to the hitchhiker is -20.83 m/s + 27.77 m/s = -6.94 m/s.

(i) The velocity at the bottom of each tire relative to the hitchhiker is -20.83 m/s - 27.77 m/s = -48.60 m/s.

(j) The acceleration at the center of each tire relative to the hitchhiker is 0 m/s2.

(k) The acceleration at the top of each tire relative to the hitchhiker is 869.68 m/s^2.

(l) The acceleration at the bottom of each tire relative to the hitchhiker is -869.68 m/s^2.

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In a race two horses start from rest and each maintains a constant acceleration. In the same elapsed time Silver Bullet runs 1.20 times farther than Shotgun. According to the equations of kinematics, which one of the following is true concerning the accelerations of the horses?
A. aSilver Bullet = 1.44 aShotgun
B. aSilver Bullet = aShotgun
C. aSilver Bullet = 0.72 aShotgun
D. aSilver Bullet = 2.40 aShotgun
E. aSilver Bullet = 1.20 aShotgun

Answers

According to the equations of kinematics, concerning the accelerations of the horses will be E. aSilver Bullet = 1.20 aShotgun.

ABOUT KINEMATICS

Kinematics is a part of physics that deals with motion. Then how can an object be said to move.

The answer is if the object changes position.

If we move position within a certain time we call it velocity. Then our speed changes every time we call it acceleration.

Position, velocity, and acceleration are quantities in physics that have a close relationship with kinematics.

This quantity is a vector quantity which has magnitude and direction. Kinematics itself has several types, namely motion kinematics and particle dynamics.

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For the below figure, the coordinates of the particles are:
Q1 (-2, 0)
Q2 (2m, 0)
Q3 (0,2m)
01-02-1nC
Determine the charge magnitude for Q3 to ensure the net force on Q3 is facing down the Y axis with a net magnitude of 5.9 Micro N
Q3
D
Y axis
08
x axis

Answers

Answer:

To determine the charge magnitude for Q3, we need to use Coulomb's Law, which states that the force between two point charges is proportional to the product of the charges and inversely proportional to the square of the distance between them.

The net force on Q3 is given as F_net = F_12 + F_13 + F_23

The force between Q1 and Q3 is given as F_13 = (1/(4πε)) * (Q1*Q3)/(D^2)

The force between Q2 and Q3 is given as F_23 = (1/(4πε)) * (Q2*Q3)/((2m-D)^2)

The force between Q1 and Q2 is given as F_12 = (1/(4πε)) * (Q1*Q2)/(2m)^2

where ε is the electric constant and D is the distance between Q3 and Q1 along the Y-axis

By equating the net force to the given value of 5.9 Micro N we can solve for Q3.

Explanation:

Above

list at least four devices that are used to control a motor automatically. briefly describe the purpose of each device. select the best answer for each of the following.

Answers

There are four primary types of motor controllers and drives: stepper, servo, DC, and AC.

Which of the following control devices is beneficial in a circuit for a motor?One of the primary motor control devices is one that attaches or detaches the motors or loads from the line. The load is connected to the line by the main control devices, which comprise the motor contactor, starter, and controller.There are four primary types of motor controllers and drives: stepper, servo, DC, and AC. Each has an input power type that has been changed to the desired output function to fit with an application.They are inverse, integral, and derivative functions. Depending on how complex a process is and how much control is needed, these control approaches may be employed alone or in combination to apply automatic control to that process.                  

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While operating around buildings, the remote pilot in command (PIC) should be aware of the creation of wind gusts that:
Change rapidly in direction and speed, creating turbulence

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While operating around buildings, the remote pilot in command (PIC) should be aware of the creation of wind gusts that change rapidly in direction and speed, creating turbulence.

The ATC authorization that is also known as air traffic control authorisation is the mechanism by which an operator is accepted to be able to operate in a controlled airspace. Usually the authorized pilot are aware of the wind gusts that change rapidly in direction and speed, creating turbulence.

Any pilot who is operating within a airspace of high buildings that is a controlled airspace is required to have the ATC authorization weather if the aircraft that he is using is small in size or big.

Usually the air space surface that is present above 10000 feet of the surrounding of the nation is considered to be the class B Airspace where fast wind are are observed.

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students are measuring the relationship between current and voltage in a circuit. the lab instructions say to plot the voltage versus the current. what values go on the x and y axes of the graph

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The x-axis of the graph should be labeled "Current (A)", with the current in amperes (A) being the independent variable.

What is graph?

A graph is a mathematical structure used to model relationships between objects. It is a collection of points, called vertices, and lines connecting them, called edges. Graphs are used to represent networks of communication, data organization, computational devices, the flow of computation, and even abstract concepts. Graphs are useful in a variety of applications, including computer vision, artificial intelligence, graphics, and databases.

The y-axis of the graph should be labeled "Voltage (V)", with the voltage in volts (V) being the dependent variable. The graph should represent the relationship between voltage (y-axis) and current (x-axis).

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A car is traveling at a steady 71 km/h in a 50 km/h zone. A police motorcycle takes off at the instant the car passes it, accelerating at a steady 7.5 m/s2.
a. How much time elapses before the motorcycle is moving as fast as the car?
b. How far is the motorcycle from the car when it reaches this speed?

Answers

(a) The time elapses before the motorcycle is moving as fast as the car is 2.6296 second.

(b) The motorcycle is 25.93 meter far from the car when it reaches this speed.

What is acceleration?

Acceleration is rate of change of velocity with time. Si unit of acceleration is meter/second² (m/s²).

Speed of the car = 71 km/h = 71 ×5/18 m/s = 19.722 m/s.

Acceleration of the  police motorcycle = 7.5 m/s²

Hence, Time taken by the motorcycle  to be  as fast as the car = 19.722 ÷ 7.5 s

= 2.6296 second.

The distance between the motorcycle  and the car

= (19.722×2.6296 - 1/2×7.5 × 2.6296²) meter

= 25.93 meter.

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A particle travels between two parallel vertical walls separated by 23 m. It moves toward the opposing wall at a constant rate of 9.6 m/s. It hits the opposite wall at the same height. a=9.8. What will be its speed when it hits the opposing wall? At what angle with the wall will the particle strike?

Answers

The particle is moving toward the wall and is being deflected at the same time.

What is Vertical walls?

The time to reach the wall will be 18.4/7.2  =2.56 sec. The direction of the acceleration is not specified but since the ask for how high  we will assume it is upward. S=1/2 at^2  t= 2.56.

s = 0.5X 1.7 m/s 2 x 2.56*2.56 = 5.5 meters. Two velocities on x one way  the up velocity  is 1.7*2.56 = 4.3 m/s or the arctan of  4.3/7.2 =30.8 degrees.

Vertical gardens, sometimes known as "green walls," are large-scale plant arrangements that are affixed to wall-mounted structures. They serve as an effective ornamental element while also being quite practical because they improve the indoor air quality and the comfort level of the surrounding area.

Therefore, The particle is moving toward the wall and is being deflected at the same time.

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An object that is initially at rest breaks up into two pieces of unequal masses when a spring-loaded device is released. If you compare the kinetic energy of the larger mass to that of the smaller mass immediately after they separate, which of the following statements is correct?
A) The kinetic energy of the larger mass is greater. B) The kinetic energy of the smaller mass is greater. C) The kinetic energies of the two masses are equal. D) The total kinetic energy is zero J.

Answers

"The kinetic energy of the bigger mass is higher," is the right statement.

Among the below-mentioned statement, the statement given in option (A) is correct.

The initial potential energy of the system is transferred to kinetic energy when a spring-loaded mechanism is released and an item breaks into two pieces of unequal mass. The total beginning potential energy must match the whole final kinetic energy, according to the rule of conservation of energy.

Because both masses' initial kinetic energy is zero, the end kinetic energy will be split in proportion to their masses.

As a result, the bigger mass has more kinetic energy than the smaller mass.

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A voltage drop test can find excessive resistance in a circuit that may not be detected using an ohmmeter.TrueFalse True

Answers

It is accurate to say that a voltage drop test might uncover excessive resistance in a circuit that an ohmmeter could miss.

Does a voltage decrease indicate resistance?Voltage drop in electronics is the decline in electric potential along a current's path as it flows through a circuit. Because some of the energy supplied is lost, voltage drops between conductors, contacts, and connectors are undesired.Voltage drop testing is a straightforward but efficient diagnostic technique to find high-resistance issues in a circuit rapidly. The voltage drop across a load, device, or conductor can be measured using the DC voltage scale on your Digital Volt Ohm Meter (DVOM) or Digital Multi-meter.It is accurate to say that a voltage drop test might uncover excessive resistance in a circuit that an ohmmeter could miss.            

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Determine the resultant internal loadings in the beam at cross sections through points D and E. Point E is just to the right of the 16-kN load.Shear ForceShear force is the total effective force or resultant force vertical to the shaft or beam. Normal force is perpendicular to the shear force. The magnitude of the shear force depends on the vertical load applied to the beam.

Answers

The resultant internal loadings in the beam at cross sections through point D and E are 15.12 kN upwards and 34.88 kN upwards respectively.

To calculate the internal loading at point D and E, first we need to calculate the support reaction at A and C, by taking the moment about reaction A.

R₁ + R₂ = 25×4 + 15 = 115 kN

R₂ × 7 = 15 × 5.5 + 100 × (4×2/3)

R₂ = 349.167/7 = 49.88

R₁ = 115 - 49.88 = 65.12 kN

Internal loading at D = 65.12 - 25×2 = 15.12 kN upwards

Internal loading at E = 49.88 - 15 = 34.88 kN upwards

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--The given question is incomplete, the complete question is:

"Determine the resultant internal loadings in the beam at cross sections through points D and E in the given figure. Point E is just to the right of the 15-kN load."--

you have three charged conducting spheres. the magnitude of these charges are 2c, 3c and 4c. without knowing which charges are positive and which charges are negative, which of the following could represent the charge on a single sphere if the spheres are brought into contact with each other and then separated?a. -10 Cb. 15 Cc. 0.5 Cd. -1 C

Answers

The charge on a single sphere if the spheres are brought into contact with each other and then separated will be -1C

Hence, option (d) is the correct choice.

The net charge within a conductor is equal to zero. If a +q charge is applied to a solid sphere, it will be dispersed evenly throughout its surface. Inside the sphere, there will be no fee.

As a result, the electric fields will be identical to those of a hollow spherical.

If three conducting charged spheres are brought into contact and then separate, then total charges divide equally on each sphere and we can finch charge on a single sphere.

Here given, the magnitude of charges are 2C, 3C, 4C.

Then the charge on a single sphere will be -2C -3C +4C = -1 C

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From a stationary hot-air balloon 500 feet above the ground, two sightings of a lake are made (see the figure). How long is the lake?

Answers

The length of the lake is 839.1 ft, if the height of the hot-air balloon is 500 ft.

Angle of depression of the farthest end, θ₁ = 25°

Angle of depression of the nearest end, θ₂ = 65°

Height of the balloon, h = 500 ft

The distance between the bottom of the balloon and the farthest end of the lake, x = 500/tan25 = 1072.25 ft

The distance between the bottom of the balloon and the nearest end of the lake, y = 500/tan65 = 233.2 ft

The length of the lake, l = 1072.25 - 233.2 = 839.1 ft

--The given question is incomplete, the complete question is:

"From a stationary hot-air balloon 500ft above the ground, two sightings of a lake are made. One at the farthest end of the lake at an angle of depression of 25 degrees and another at the nearest end of the lake at an angle of depression of 65 degrees. How long is the lake?"--

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Find the ratio of the y velocity of the string to the slope of the string calculated in the previous part.
Express your answer as a suitable combination of some of the variables ω, k, and vp.

Answers

The ratio of the y velocity of the string to the slope of the string is given by the expression vy/m = ω/k.

Find the ratio of the y velocity of the string to the slope of the string calculated in the previous part?This ratio is determined by the angular frequency (ω) of the wave, the wave number (k) of the wave, and the phase velocity (vp) of the wave.The angular frequency (ω) is related to the frequency (f) of the wave by the equation ω = 2πf.The wave number (k) is related to the wave length (λ) of the wave by the equation k = 2π/λ.The phase velocity (vp) is related to the wave number (k) and the angular frequency (ω) by the equation vp = ω/k.Therefore, the ratio of the y velocity of the string to the slope of the string is given by the expression vy/m = ω/k = vp.The ratio of the y velocity of the string to the slope of the string is equal to the product of the angular frequency, ω, and the wave velocity, vp. This ratio is expressed as:velocity ratio = ω*vpThe angular frequency is related to the wave number, k, such that:ω = 2πkTherefore, the velocity ratio can be rewritten as:velocity ratio = 2πk*vpThis equation shows that the ratio of the y velocity of the string to the slope of the string is a combination of the angular frequency, wave number, and wave velocity. This ratio is an important factor in understanding the behavior of a wave in a string.

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when a ball thrown straight upwards reaches the very top of its path, its magnitude of acceleration is

Answers

when a ball thrown straight upwards reaches the very top of its path, its magnitude of acceleration is equal to acceleration due to gravity (g).

What is a Freely Falling Body?

A body is considered to be falling freely when it is dropped from a height under the influence of earth's gravity without being given any initial velocity.The body has no starting velocity.The body is subjected to an acceleration that is downward and equal to the earth's gravitational pull.The gravitational attraction of the earth causes the ball to become stationary when it reaches the highest point. When it eventually comes back, the speed is equivalent to the speed of gravity.Free fall causes an item to accelerate by -9.8 m/s². Free fall is any motion of a body in which gravity is the only force acting on it according to Newtonian mechanics. A body in free fall experiences no force according to general relativity, which reduces gravitation to a space-time curvature.

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Three metal cubes with edges 3 cm, 4 cm and 5 cm are melted to form a single cube. Find the area of the side formed in the large cub

Answers

The area of the side formed in the large is 36 cm².

What is cube?

A cube is a three-dimensional solid object in geometry that is surrounded by six square faces, facets, or sides, three of which meet at each vertex. It looks like a hexagon when viewed from a corner, and its net is typically portrayed as a cross.

The total volume of the three cubes = 3³ cm³ + 4³ cm³ + 5³ cm³ = 216 cm³

So, the length of the edges of the new cube = ∛216 cm = 6 cm

Hence,  the area of the side formed in the large cub = 6² cm² = 36 cm².

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1) A bowling ball is rolling down a lane at a bowling alley. How can you know that a force has acted on the bowling ball?
a-by determining a change in the direction of the bowling ball as it rolls down the alley
b-by determining the direction of the bowling ball
c-by timing how long the bowling ball takes to reach the end of the lane
d-by measuring the mass of the bowling ball


2) What is the advantage of using a simple machine to do work?

a-A simple machine reduces the force needed to do the work.
b-A simple machine reduces the time needed to do the work.
c-A simple machine reduces the displacement required to do the work.
d-A simple machine reduces the work that has to be done.


3)Students measure how much work it takes to lift an object two meters. They use an inclined plane that is 3 meters long, an inclined plane that is 4 meters long, and a compound pulley. Which statement is correct?(1 point)

a-The 3-meter plane will require the least amount of work.
b-All three simple machines will require the same amount of work.
c-The compound pulley will require the least amount of work.
d-The 4-meter plane will require the least amount of work.


4) What is the advantage of using an inclined plane to move boxes into a truck?
a-You will use less force.
b-You will need to do less work.
c-You will walk less distance.
d-You will use less energy.


5) How can the mechanical advantage of a lever be calculated?

a-Divide the length of the effort arm by the length of the load arm.
b-Divide the length of the load arm by the length of the effort arm.
c-Divide the input force by the output force.
d-Divide the output distance by the input distance.


6) A student makes a class 1 lever to lift a box, but he finds that he cannot apply enough force to lift the box. How can he modify the lever to reduce the amount of force he needs?

a-He can lengthen the part of the lever he pushes on.
b-He can shorten the part of the lever he pushes on.
c-He can lengthen the part of the lever bearing the load.
d-He can use a taller fulcrum.


7) Using a class 1 lever, students lift a bucket of water 0.3 meters. They push on the lever a distance of 1.8 meters. If they use 312 Newtons of force, how much force would they need to lift the bucket without the lever?(1 point)

1,872 N
52 N
561.6 N
93.6 N


8) Which equation shows the relationship between work and energy?

a-W=Eo/Ei
b-W=Eo×Ei
c-W=ΔE
d-W=Eo+Ei

9) A gardener uses a lever to pry a rock out of the ground. She presses the lever down 0.9 meters and applies 30 Newtons of force. How much work does she do?(1 point)

a-29.1 J
b-27 J
c-270 J
d-30.9 J


10) A robot vacuum cleaner cleans the Potters’ front room. Which is the vacuum cleaner’s useful output energy?

a-electric energy that recharges the robot’s battery
b-thermal energy that warms the robot
c-kinetic energy that moves the robot and its brush
d-sound energy that makes a whirring noise


11) A worker uses a pulley to lift a bale of hay from a truck into a barn. If she expends 390 Joules of energy, and 358 Joules lift the box, what is the pulley’s efficiency?

a-91.8%
b-108.9%
c-0.918
d-8.2%


12) A worker uses a pulley to lift a bale of hay from a truck into a barn. If she expends 390 Joules of energy, and 358 Joules lift the box, what is the pulley’s efficiency?

a-8.2%
b-0.918
c-108.9%
d-91.8%


13) Nadia pushes a box up an inclined plane. She expends 2,000 Joules of energy, but only 1,540 Joules are applied to the box. What happens to the other 460 Joules of energy?

a-They are converted to other forms of energy.
b-They are destroyed.
c-They are transferred to another simple machine.
d-They are transferred back into Nadia.


14) Students invent a game that uses a lever to flip beanbags toward a target. How could they make the lever more efficient?

a-Make the target larger.
b-Use lighter beanbags.
c-Use a fulcrum with a sharper point.
d-Use a taller fulcrum.

Answers

1) by determining a change in the direction of the bowling ball as it rolls down the alley

2) A simple machine reduces the force needed to do the work.

3) The compound pulley will require the least amount of work.

4) You will need to do less work.

5) Divide the input force by the output force.

6) He can lengthen the part of the lever he pushes on.

7) 561.6 N

8) W=ΔE

9) -27 J

10) kinetic energy that moves the robot and its brush

11) 91.8%

12) -91.8%

13) They are converted to other forms of energy.

14) Use a fulcrum with a sharper point.

What is the mechanical advantage?

Mechanical advantage is the ratio of output force to input force in a machine, used to determine its efficiency in doing work.

We know that the essence of the simple machine is that it helps to do more work in a short time.

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a 2.00-kg ball a moves at 3.00 m/s toward the right. it collides elastically with a 4.0-kg ball b that is initially at rest. the velocities of the balls after the collisions are

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The velocity of ball a after the collision is 1.33 m/s and the velocity of ball b after the collision is 1.67 m/s.

The velocity of the balls after the impact may be calculated using the momentum conservation rule.

The system's momentum before the collision equals the system's momentum after the impact.

Each ball's momentum before the contact is determined by its mass and velocity.

Let us refer to the velocity of ball a following the collision as va' and the velocity of ball b following the collision as vb'.

The law of conservation of momentum may thus be stated as follows:

m1 * v1 + m2 * v2 = m1 * v1' + m2 * v2'

where m1 is the mass of ball a, v1 is its velocity before the collision,

m2 is the mass of ball b, and

v2 is its velocity before the collision.

Since ball b was initially at rest, v2 = 0 m/s.

Plugging in the given values, we get:

2.00 kg * 3.00 m/s + 4.00 kg * 0 m/s

= 2.00 kg * va' + 4.00 kg * vb'

Solving for va' and vb', we get:

va' = (4.00 kg * 0 m/s + 2.00 kg * 3.00 m/s) / (2.00 kg + 4.00 kg)

= 1.33 m/s

vb' = (2.00 kg * 3.00 m/s) / (2.00 kg + 4.00 kg)

= 1.67 m/s

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A ball with an initial velocity of 9.6 m/s rolls up a hill without slipping.
a)Treating the ball as a spherical shell, calculate the vertical height it reaches in m. b) Repeat the calculation for the same ball if it slides up the hill without rolling in m.

Answers

(a) The vertical height (the ball with an initial velocity of 9.6 m/s rolls up a hill without slipping) reaches = 7.836 m

(b) The calculation for the same ball if it slides up the hill without rolling in = 4.70 m

As the ball begins to roll up the hill, its kinetic energy begins to change into gravitational potential energy, and by the time it reaches its maximum height on the hill, it has been completely converted into gravitational potential energy. Because the ball is rolling up, it has both translational and angular kinetic energy: As a result of energy conservation, we have:

Potential energy = Kinetic energy trans + Kinetic energy rotation

mgh = ½ mv² + ½ Iw²

Hence,

(a) the vertical height:

h = 5v² / 6g

= 5 (9.6)² / (6 x 9.81)

= 460.8 / 58.8

= 7.836 m

(b) If the ball slide up without rolling, it means the angular velocity is zero.

Hence,

h' = v² / 2g

= (9.6)² / (2 x 9.8)

= 92.16 / 19.6

= 4.70 m

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Matt's book is motionless on a table.

Which force diagram would represent Matt's book? You may neglect the effects of air resistance.
1. Diagram A
2. Diagram B
3. Diagram C
4. Diagram D

Answers

C as balanced forces result in no motion

The fundamental frequency of a pipe that is open at both ends is 544 Hz Part A How long is this pipe? Express your answer with the appropriate units. Part B If one end is now closed, find the wavelength of the new fundamental. Express your answer with the appropriate units. Part C If one end is now closed, find the frequency of the new fundamental. Express your answer with the appropriate units.

Answers

The length of a pipe open at both ends is:

Part A: To find the length of a pipe with a fundamental frequency of 544 Hz, use the equation v = fλ, where v is the speed of sound (343 m/s), f is the frequency, and λ is the wavelength. This gives λ = 343/544 = 0.6297 m.

Part B: If one end of the pipe is closed, the wavelength of the new fundamental will be half of the wavelength of the open pipe, so the wavelength in this case will be 0.3148 m.

Part C: To find the frequency of the new fundamental, use the equation f = v/λ, with v = 343 m/s and λ = 0.3148 m. This gives f = 1094 Hz.

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