The length of the Burgers vector in niobium is 0.2852 nm, in silver it is 0.2897 nm, and in silicon it is 0.9405 nm.
The Burgers vector (b) is the measure of the lattice distortion associated with a dislocation in the crystal. The magnitude of the Burgers vector is equal to the magnitude of the lattice distortion associated with the dislocation. The Burgers vector is usually expressed in terms of the lattice constant (a) of the crystal.
The lattice constant (a) is the distance between adjacent lattice points in a crystal. The value of the lattice constant depends on the crystal structure and the material.
The Burgers vector for a screw dislocation in a BCC crystal is given by:
b = a × (√(3)) / 2
where a is the lattice constant. For niobium, the lattice constant is a = 0.3296 nm, so the Burgers vector is:
b = (0.3296 nm) × (√(3)) / 2 = 0.2852 nm
The Burgers vector for an edge dislocation in an FCC crystal is given by:
b = a × (√(2)) / 2
where a is the lattice constant. For silver, the lattice constant is a = 0.4086 nm, so the Burgers vector is:
b = (0.4086 nm) × (√(2)) / 2 = 0.2897 nm
The Burgers vector for a dislocation in a diamond cubic crystal is given by:
b = a × (√(3))
where a is the lattice constant. For silicon, the lattice constant is a = 0.5431 nm, so the Burgers vector is:
b = (0.5431 nm) × (√(3)) = 0.9405 nm
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How many moles are in 1.5 x 1022 atoms of Cu?
There are 0.0249 moles of Cu in 1.5 x 10²² atoms of Cu.
What is Mole?
A mole is a unit of measurement used in chemistry to express amounts of a chemical substance. It is defined as the amount of a substance that contains the same number of entities (such as atoms, molecules, or ions) as there are in 12 grams of pure carbon-12, which is approximately 6.022 x 10²³ entities.
This number is called Avogadro's number and is used as a conversion factor between the mass of a substance and the number of particles it contains.
To calculate the number of moles, we need to know the atomic mass of Cu, which is 63.55 g/mol.
We can use Avogadro's number, 6.022 x 10²³, to convert the number of atoms to moles:
1.5 x 10²² atoms Cu * (1 mol Cu / 6.022 x 10²³ atoms Cu) = 0.0249 mol Cu
Therefore, there are 0.0249 moles of Cu in 1.5 x 10²² atoms of Cu.
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There are 0.0249 moles of Cu in 1.5 x 10^22 atoms of Cu.
What is Mole?
A mole is a unit of measurement used in chemistry to express amounts of a chemical substance. It is defined as the amount of a substance that contains the same number of entities (such as atoms, molecules, or ions) as there are in 12 grams of pure carbon-12, which is approximately 6.022 x 10^23 entities. This number is called Avogadro's number and is used as a conversion factor between the mass of a substance and the number of particles it contains.
To calculate the number of moles, we need to know the atomic mass of Cu, which is 63.55 g/mol.
We can use Avogadro's number, 6.022 x 10^23, to convert the number of atoms to moles:
1.5 x 10^22 atoms Cu * (1 mol Cu / 6.022 x 10^23 atoms Cu) = 0.0249 mol Cu
Therefore, there are 0.0249 moles of Cu in 1.5 x 10^22 atoms of Cu.
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Iodine-131 has a half-life of 8 days. How many days will it take before 32mg of Iodine-131 has decayed to 1mg?
Answer:40 days
- K = [ ln ( 1/2 ) ] / [ t 1/2 ]
- K = [ln ( 1/2 ) ] / 8 = - 0.08664 ( days )^-1
ln C/ C0 = ( - K ) ( t )
C=1mg and C0= 32mg
t = [ ln (1/32 )] / [ - 0.08664 ] = 40 days
In the 1920s, western powers began to expand their influence in the middle east primarily due to __________. A. The discovery of oil in the regionb. The rising number of terrorist attacks against the westc. European desires to create a jewish homelandd. Rising fundamentalist movements in iran and saudi arabia please select the best answer from the choices provided. Abcd.
In the 1920s, western powers began to expand their influence in the middle east primarily due to A. The discovery of oil in the region.
The Role of Oil in the Expansion of Western Powers in the Middle East during the 1920sIn the 1920s, the Western powers, such as Britain and France, began to expand their influence in the Middle East primarily due to the discovery of oil in the region. The discovery of oil brought enormous economic and strategic importance to the region, and the Western powers sought to secure their access to this valuable resource. The discovery of oil also helped to modernize the region, as the Western powers invested in infrastructure development, such as pipelines, ports, and railways, which facilitated the transportation of oil and other goods. The Western powers also sought to protect their interests in the region by establishing protectorates, such as Kuwait and Bahrain, and by dividing up the former Ottoman Empire into new nation-states that would be more amenable to Western influence. This led to a backlash from some in the region, who saw the Western powers as meddling in their affairs, and who called for greater independence and self-determination. Nonetheless, the discovery of oil in the region had a profound impact on the political and economic development of the Middle East and continues to shape the region's geopolitics today.
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Please select the word from the list that best fits the definition impersonal relationships are due to job specialization.
Answer:
Organic solidarity
Explanation:
its right
The density of cobalt is 8.86 g/cm³. The mass of the average atom of cobalt is 9.786316
x 10-23g. How many atoms of cobalt are contained within 1.00 cm³ of cobalt?
In this question, the density of cobalt is equal to 8.86 g per cubic centimeter. The mass of average atom of cobalt is equal to 9.786 316 times 10. Raise to part minus 23 grand. So this is the mass of average item of cobalt. And we have to calculate the number of atoms of cobalt, when volume is equal to one cc. So in one cc of cobalt we have to calculate the number of atoms of COBOL present. First of all, using the formula that density is equal to mass divided by volume. We can calculate the mass of atoms present in one cc. So the mass would be equal to density, multiplied by volume. From this mass comes out to be density is 8.86 g per centimeter cube and volume is one centimeter tube. So the mass would be equal to 8.86 g. Now we have the mass of atoms present in one cc of COBOL. Now, since mass is 8.86 g and we know that 9.7863 16 times 10 raise to part -23 g is equal and to one atom since it is a mass of average atom of cobalt. So from this we can say that 8.86 g of cobalt would be equal to one divided by 9.7686316 multiply by 8.86 atoms of Cobalt. From this. By solving it, we will get the value which is equal to when we multiply and divide these things. We will get the value 9.5 times 10, raise to part 22 atoms, so 9.5 Multiply by 10 days to part 22 items are present in 8.86 g of cobalt. Or we can say that one cc of cobalt. So our answer is option A.
I hope this helps! o(〃＾▽＾〃)o
Suppose you are measuring the mass of a solid sample on a balance using a weigh boat. You record the data in a
table.
Mass of weigh boat
2.193 g
Mass of weigh boat and sample 5.063 g
What is the mass of the solid sample (in g)?
The mass of the solid sample in grams would be 2.87 grams.
Weighing methodMass of the weighing boat = 2.193 grams
Mass of the weighing boat and the sample = 5.063
In other to determine the mass of the solid sample, the mass of the weighing boat needs to be subtracted from the mass of the weighing boat and the sample.
Mass of sample = Mass of sample+weighing boat - mass of weighing boat.
= 5.063 - 2.193
= 2.87 grams
In other words, the mass of the solid sample is 2.87 grams.
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Triglycerides are the most common lipid found in food and in the body, they consist of a _____ backbone attached to three FA
Triglycerides, also known as triacylglycerols, are composed of a glycerol backbone attached to three fatty acid chains.
The fatty acids are esterified to the three hydroxyl groups of the glycerol backbone, forming a molecule with three fatty acid chains bound to a glycerol molecule. Triglycerides are the main constituents of natural fats and oils and are the most common form of stored energy in animals.
Triglycerides are the main type of fat (lipid) found in the body and in food. They are composed of three fatty acids attached to a glycerol backbone. Triglycerides are an important source of energy for the body and are stored in adipose tissue (body fat) for later use. They can also be found in the bloodstream, where they can contribute to the formation of plaque in the arteries, increasing the risk of heart disease. Triglycerides are commonly found in foods that are high in fat, such as oils, butter, and meats, as well as in some plant-based foods, such as nuts and seeds.
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Osmium is one of the densest elements known. What is its density if 2.72 g has a volume of 0.121c * m ^ 3
Answer:
Density is defined as the mass of a substance per unit volume, so we can use the given mass and volume to calculate the density of osmium.
Density = mass / volume
Substituting the given values, we get:
Density = 2.72 g / 0.121 m^3
Simplifying, we get:
Density = 22.48 g/m^3
Therefore, the density of osmium is 22.48 g/m^3.
Explanation:
Answer:
22,426 g/m³.
Explanation:
Density is defined as mass per unit volume. To calculate the density of osmium, we need to divide its mass by its volume:
Density = Mass / Volume = 2.72 g / (0.121 cm³ * (1 m³ / 10^6 cm³))
= 2.72 g / 0.121 * 10^-6 m³ = 2.72 * 10^6 g / 0.121 m³ = 22,426 g/m³
So, the density of osmium is approximately 22,426 g/m³.
A new element with three naturally occurring isotopes has an average atomic mass determined to be 81.5529
amu. The first two isotopes have relative abundances of 76.12% and 10.27% and masses of 81.6643 amu and
81.1239 amu respectively. What is the mass of the third isotope?
- report your answer in six significant figures
- do not include units
The average atomic mass for the new element is given 81.5529 amu. The percentage abundance for the third isotope is 13.6 %. Then its atomic mass is 83.9 amu.
What are isotopes?Isotopes are atoms of same element with different atomic mass numbers. Almost all elements have two or more isotopes but not all of them are stable in nature.
The average atomic mass can be calculated from the isotopic mass and and percentage abundance as follows:
atomic mass = ∑ (isotopic mass × %abundance /100 )
Apply the isotopic mass and abundance of all isotopes given as follows:
atomic mass of the element = (76.12/100 ×81.6643 amu) + (10.27/100 × 81.1239 amu) + (13.6 /100 × X amu) =81.5529 amu.
Then,
(13.6 /100 × X amu) = 70.41 amu.
X = 83.9 amu.
Therefore, the atomic mass of the third isotope is 83.9 amu.
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Consider a gas cylinder containing 0. 250 moles of an ideal gas in a volume of 6. 00 l with a pressure of 1. 00 atm. The cylinder is surrounded by a constant temperature bath at 292. 0 k. With an external pressure of 3. 00 atm, the cylinder is compressed to 2. 00 l. Calculate the w(gas) for this compression process, in j
The work done on the gas during the compression process is 0.0418 kJ/K.
How did we get the value?The work done on the gas during a compression process can be calculated using the equation:
w = -P * (Vf - Vi)
where P is the external pressure, Vf is the final volume, and Vi is the initial volume. The negative sign indicates that work is done on the gas.
Using the given values, we have:
w = -3.00 atm * (2.00 L - 6.00 L)
The volume units need to be converted to liters:
w = -3.00 atm * (2.00 L - 6.00 L) = -3.00 atm * (-4.00 L) = 12.00 L * atm
Next, the pressure unit must be converted to pascals:
w = 12.00 L * atm * (1.00 atm) = 12.00 L * 1.01325 * 10^5 Pa = 12.16 kJ
Finally, the work done must be divided by the temperature to get the work done per kelvin:
w / T = 12.16 kJ / (292.0 K) = 0.0418 kJ/K
So the work done on the gas during the compression process is 0.0418 kJ/K.
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How many moles of Al2S3 are
equivalent to 605 g Al2S3?
(Al2S3 = 150.17 g/mol)
? 1 mol Al₂S3
The number of moles of Al2S3 that would be equivalent to 605 g of the compound will be 4.03 moles.
Number of moles calculationThe number of moles in a particular mass of a compound is the ratio of the mass of the compound and the molar mass of the compound.
Mole = mass/molar mass
Molar mass of Al2S3 = 150.17
Mole of 605 g Al2S3 = 605/150.17
= 4.03 moles
In other words, the number of moles of 605 g Al2S3 is 4.03 moles.
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Part 6 Computation (12 points) 1. Calculate the average atomic mass of Iron using the chart provided. (6pts) Isotopic symbol 54Fe 56Fe 57 Fe 58Fe Natural Abundance (%) 5.8 91.7 2.2 0.3
Answer:
84.066 amu
Explanation:
The average atomic mass of iron can be calculated using the following formula:
Average atomic mass = (54Fe * 0.058 + 56Fe * 0.917 + 57Fe * 0.022 + 58Fe * 0.003) / (0.058 + 0.917 + 0.022 + 0.003)
Plugging in the numbers, we get:Average atomic mass = (54 * 0.058 + 56 * 0.917 + 57 * 0.022 + 58 * 0.003) / (0.058 + 0.917 + 0.022 + 0.003)
Average atomic mass = (31.12 + 51.592 + 1.254 + 0.174) / (0.058 + 0.917 + 0.022 + 0.003)
Average atomic mass = 84.066 / (0.058 + 0.917 + 0.022 + 0.003)Average atomic mass = 84.066 / 1
Average atomic mass = 84.066So, the average atomic mass of Iron is 84.066 atomic mass units (amu).
Which coefficients correctly balance the equation below
AI+CuSO - -> AI2(SO4)3+Cu
Answer:
Explanation:
In order to balance the equation, the coefficients in front of each element must be equal on both sides of the equation. Here's one way to balance the equation:
2 AI + 3 CuSO4 ---------------> 2 AI2(SO4)3 + 3 Cu
This means that for every 2 atoms of AI and 3 molecules of CuSO4, you'll get 2 molecules of AI2(SO4)3 and 3 atoms of Cu.
In the equation:
2H₂ + O₂ → 2H₂O
How many moles of hydrogen react with 0.37 mol of oxygen
Solving the Question
[tex]2H_2 + O_2\rightarrow 2H_2O[/tex]
From the balanced chemical equation, we know that 2 moles of H2 is required to react with 1 mole of O2:
⇒ [tex]\dfrac{n_{H_2}}{2}=\dfrac{n_{O_2}}{1}[/tex]
We're also given that we have 0.37 moles of O2:
⇒ [tex]\dfrac{n_{H_2}}{2}=\dfrac{0.37}{1}[/tex]
Solve for moles of H2:
⇒ [tex]n_{H_2}=\dfrac{0.37}{1}*2\\\\n_{H_2}=0.74[/tex]
Answer0.74 moles of hydrogen react with 0.37 moles of oxygen.
What is the molarity of a solution containing 2.50 moles in 35 mL of solution?
Answer: 71.43 M.
Explanation: To calculate the molarity of a solution, we divide the number of moles of solute by the volume of the solution in liters. The volume of the solution in this case is given in milliliters, so we need to convert it to liters before we can calculate the molarity.
35 mL = 0.035 L (since 1 mL = 0.001 L)
So, the molarity of the solution can be calculated as follows:
Molarity = moles of solute / volume of solution in liters
Molarity = 2.50 moles / 0.035 L
Molarity = 71.43 M
Therefore, the molarity of the solution is 71.43 M.
When 25 mol of nitrogen reacts with 25 mol of hydrogen according to this reaction:
____ N2 + ____ H2 → ____ NH3
a. What is the limiting reactant?
b. What is the excess reactant?
c. How many moles of NH3 will be produced?
In the reaction N2 (g) + 3H2 (g) 2NH3 (g) Hydrogen will be the limiting reagent if equal amounts of each reactant are utilized since it is required to produce ammonia at a rate of 3 moles of hydrogen for every mole of nitrogen.
What does a limiting agent do?A reactant that is entirely consumed when a chemical reaction is finished is the limiting reagent. Due to the need for this reagent, the amount of product that can be produced is constrained.An ingredient in a chemical reaction known as the limiting reactant or limiting reagent controls how much product is produced. Calculating the theoretical yield of a reaction requires knowing which reactant is the limiting one.For more information on limiting agent kindly visit to
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Type the correct answer in the box. Express your answer to three significant figures.
The half-life of carbon-14 is 5,730 years. Dating organic material by looking for C-14 can't be accurately done after
50,000 years.
Suppose a fossilized tree branch originally contained 4.30 grams of C-14. How much C-14 would be left after 50,000 years?
Use the formula N = No (+)*
A tree branch that originally had 4.3 grams of carbon-14 will have
grams after 50,000 years.
Answer:
0.041 grams of carbon-14 remaining.
Explanation:
The half-life of carbon-14 is the time it takes for half of the original amount of carbon-14 to decay. In this case, the half-life of carbon-14 is 5,730 years. This means that after 5,730 years, half of the original amount of carbon-14 will remain, and half will have decayed.
In this problem, we are given that a fossilized tree branch originally contained 4.30 grams of C-14, and we are asked how much C-14 would be left after 50,000 years. To find this, we need to calculate how many half-lives have occurred over this time period, and then find the resulting amount of C-14.
We can use the formula N = N0 * (1/2)^(t/t1/2) to calculate the amount of C-14 after a given number of half-lives, where N0 is the initial amount of C-14, t is the total time elapsed, and t1/2 is the half-life of the substance.
Plugging in the given values, we get N = 4.30 g * (1/2)^(50000 years / 5730 years/half-life) = 0.041 g.
So, after 50,000 years, the tree branch will have 0.041 grams of carbon-14 remaining.
ALLEN
One of the main terms used in physics to describe the radioactive decay of a specific sample or element over a predetermined amount of time is half-life, also known as half-life period. After 50,000 years, the tree branch will have 0.041 grams of carbon-14 remaining.
What is half-life?A radioactive material's half-life is typically described as the amount of time it takes for one half of its atoms to decay or change into another substance. Ernest Rutherford made the first discovery of the theory in 1907. It is typically denoted by the letters Ug or t1/2.
Understanding half-lives is crucial because they allow you to determine if a sample of radioactive material is safe to handle. A sample is deemed safe when its radioactivity is below detection thresholds. Ten half-lives later, something occurs.
We can use the formula N = N0 * (1/2)^(t/t1/2)
N = 4.30 g * (1/2)^(50000 years / 5730 years/half-life) = 0.041 g.
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See question in the picture below , will give brainliest for correct answer
Answer: I got you, As4S6 + 9O2 -> As4O6 + 6SO2
Explanation:
As4S6 + 9O2 -> As4O6 + 6SO2
4 As 4
6 S 1 6
18 2 O 8 18
Describe some common chemical properties of matter?
Answer:
Some are Oxidation, Reduction, Combustion and electronegativity
Explanation:
When isopropanol (c3h8o) burns in oxygen, carbon dioxide, water, and heat are produced.
Answer: True
Explanation:
This is the standard process for all Carbon based Combustion reactions.
The compound is burned with some quantity of Oxygen, and it reacts to form some amount of water and carbon dioxide.
Please help me I’ve been stuck on this question for 10 minutes
The arrow shows that the bond between the chlorine atom and the fluorine atom is polar covalent. The electrons in the bond are pulled closer to the fluorine atom, and the chlorine atom is slightly negative.
What is a polar covalent atom?A polar covalent bond is a type of chemical bond that occurs when two atoms share electrons unequally. In a polar covalent bond, the electrons are attracted more strongly to one of the atoms than the other, leading to a separation of electric charge.
The electrons in the bond are pulled closer to the fluorine atom, making it slightly negative, and the chlorine atom becomes slightly positive. This is because fluorine is more electronegative than chlorine, meaning that it has a greater attraction for the shared electrons in the bond.
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Electric Current: Mastery Test
Select the correct answer.
What is the symbol for voltage?
OA. P
OB. V
OC. T
OD. V
Reset
Next
The derived unit for voltage inside the International System of Units is called volt. V is the symbol for voltage. Therefore, the correct option is option D.
What is voltage?Voltage seems to be the difference throughout electric potential between two locations, often referred to as electrical pressure, electric tension, as well as (electric) potential difference.
It refers to the labor required per unit of charge that move pure test charge between two places inside a static electric field. The derived unit for voltage inside the International System of Units is called volt. V is the symbol for voltage.
Therefore, the correct option is option D.
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The rate constant for this first‑order reaction is 0.0340 s−1
at 400 ∘C.
A⟶products
After how many seconds will 17.2%
of the reactant remain?
=
Answer:
it will take 100 seconds for 17.2% of the reactant to remain.
Explanation:
This is a first-order reaction, which means the rate of the reaction is proportional to the concentration of the reactant. The half-life (T1/2) of a first-order reaction can be calculated as follows:
T1/2 = ln(2) / k
Where k is the rate constant.
So, the half-life of the reaction at 400 ∘C can be calculated as follows:
T1/2 = ln(2) / 0.0340 s−1 = 20.3 s
To find the time it takes for 17.2% of the reactant to remain, we can use the formula:
[A]t = [A]0 * e^(-kt)
Where [A]t is the concentration of the reactant at time t, [A]0 is the initial concentration of the reactant, k is the rate constant, and t is the time.
We want to find t such that [A]t = 0.172 * [A]0. Taking the natural logarithm of both sides:
ln([A]t / [A]0) = -kt
ln(0.172) = -k * t
t = -ln(0.172) / k = -ln(0.172) / 0.0340 s−1 = 100 s
So, it will take 100 seconds for 17.2% of the reactant to remain.
In a breathalyzer, ethanol is detected through a reaction with the yellow-
orange dichromate ion in which the green chromium(III) ion is produced in
the presence of acid. The following balanced chemical equation
summarizes the reaction:
3 CH3CH₂OH(aq) + 2 Cr₂O72- (aq) + 16 H (aq) → 3 CH3COOH (aq) + 4 Cr³+
(aq)+11 H2O (D)
Which of these processes occurs the fastest?
The fastest process in the reaction described in the balanced chemical equation is the production of the green chromium(III) ion in the presence of acid.
What is involved ethanol reaction?The ethanol reaction involved in a breathalyzer is a chemical reaction between ethanol (CH3CH2OH) and the yellow-orange dichromate ion (Cr2O72-). In the presence of acid, the ethanol reacts with the dichromate ion to produce green chromium(III) ion (Cr³+) and acetic acid (CH3COOH).
The reaction between ethanol and dichromate ion is used in breathalyzers to detect the presence of ethanol in a person's breath. A breathalyzer is a device used to measure the alcohol concentration in a person's breath.
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How does a scientist make two solutions with the same molarity
a. By dissolving the same number of moles of each substance in the
same volume of water
B. By dissolving the maximum amount of each substance in the
same volume of water
C. By dissolving 1 mole of each substance in enough water to make
sure dissolving is complete
D. By dissolving the same number of grams of each substance in
ce in the
same volume of water
The concentration of a solution can be expressed in molarity, molality, mass percent, etc. By dissolving the same number of moles of each substance in the same volume of water a scientist make two solutions with the same molarity. The correct option is A.
What is molarity?The molarity of a solution is defined as the number of moles of the solute present per litre of the solution. It is usually expressed in mol / L. The equation used to calculate the molarity is:
Molarity = Number of moles of the solute / Volume of the solution in litres
The solutions with the same number of moles and volume have equal molarity.
Thus the correct option is A.
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Calculate the volume (in mL) of 0.685 M HCl needed to react completely with 7.47 g of CaCO3 in a gas-forming reaction?
?mL
217.8 mL volume of 0.685 M HCl are required to react completely with 7.47 g of CaCO3.
How to calculate the volume of HCl needed?
The balanced chemical equation for the reaction between HCl and CaCO3 is:
2HCl + CaCO3 → CaCl2 + CO2 + H2O
From the equation, we can see that 2 moles of HCl are required to react with 1 mole of CaCO3. We can use this stoichiometric ratio to calculate the amount of HCl required to react with 7.47 g of CaCO3.
Step 1: Calculate the number of moles of CaCO3.
molar mass of CaCO3 = 40.08 g/mol (Ca) + 12.01 g/mol (C) + 3(16.00 g/mol) (O) = 100.09 g/mol
moles of CaCO3 = mass / molar mass = 7.47 g / 100.09 g/mol = 0.0746 mol
Step 2: Calculate the number of moles of HCl required.
From the balanced equation, we need 2 moles of HCl for every 1 mole of CaCO3.
moles of HCl = 2 x moles of CaCO3 = 2 x 0.0746 mol = 0.1492 mol
Step 3: Calculate the volume of HCl required.
We are given the concentration of HCl as 0.685 M, which means there are 0.685 moles of HCl per liter of solution.
volume of HCl = moles of HCl / concentration of HCl
volume of HCl = 0.1492 mol / 0.685 mol/L = 0.2178 L
To convert the volume to milliliters, we multiply by 1000:
volume of HCl = 0.2178 L x 1000 mL/L = 217.8 mL
Therefore, 217.8 mL volume of 0.685 M HCl are required to react completely with 7.47 g of CaCO3.
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10. What is lost in an atom as a result of radioactive decay? What equation relates this loss to
energy produced? (1 pt)
Mass that is number of protons and neutrons is lost in an atom as a result of radioactive decay.
What is an atom?
An atom is defined as the smallest unit of matter which forms an element. Every form of matter whether solid,liquid , gas consists of atoms . Each atom has a nucleus which is composed of protons and neutrons and shells in which the electrons revolve.
The protons are positively charged and neutrons are neutral and hence the nucleus is positively charged. The electrons which revolve around the nucleus are negatively charged and hence the atom as a whole is neutral and stable due to presence of oppositely charged particles.
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A patient needs exactly 1000. mL of a fluid over a 6-hour period. The drop factor is 15 gtt/mL. What is the drip rate in gtt/min?
According to the question, the drip rate in gtt/min is 25 gtt/min.
What is drip rate?
Drip rate is a medical term referring to the controlled delivery of a liquid, such as an intravenous (IV) infusion, over a specified period of time. It is usually expressed in terms of drops per minute. It is also called drop rate, infusion rate or flow rate.
To calculate this, we need to first determine the total number of drops that need to be administered over the 6-hour period. To do this, we multiply the total volume of fluid (1000 mL) by the drop factor (15 gtt/mL). This gives us a total of 15,000 gtt.
Now we need to determine how many drops are required per minute. To do this, we divide the total number of drops (15,000 gtt) by the total number of minutes in 6 hours (360 minutes). This gives us a result of 41.67 gtt/min.
Finally, we need to round this value up to the nearest whole number. This gives us a drip rate of 42 gtt/min, or 25 gtt/min when rounded down to the nearest whole number.
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PLEASE BROO if the controlled substances, which schedule of drugs is the average person most likely to have in their homes? How are the controlled substances in this group different from those in the other schedule levels?
Answer:
The average person is most likely to have Schedule V controlled substances in their homes. These drugs have a low potential for abuse and limited dependence liability compared to other schedule levels. They are often used for medical purposes and include cough syrups containing codeine, anti-diarrhea medications, and some prescription pain medications.
The drugs in other schedule levels, such as Schedule I, II, III, and IV, have a higher potential for abuse and dependence and are considered to be more dangerous and addictive. These schedules include drugs such as cocaine, methamphetamine, fentanyl, and other highly regulated substances.
Explanation:
Aluminum bromide and chlorine gas react to form aluminum chloride and bromine gas.
The balanced equation is : Aluminum bromide and chlorine gas react to form aluminum chloride and bromine gas.
AlBr₃ + 3Cl ---> AlCl₃ + 3Br
The Aluminum bromide and chlorine gas will react to form the aluminum chloride and the bromine gas
AlBr₃ + Cl ---> AlCl₃ + Br
reactant product
Al 1 1
Br 3 1
Cl 1 3
The chemical equation is said to be the balanced equation if the atoms of the reactants side is equals to the atoms of the product side. Multiplying the 3 in Cl and the 3 in the Br. The equation is as follows :
AlBr₃ + 3Cl ---> AlCl₃ + 3Br
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This question is incomplete, the complete question is :
Balance the chemical equation : Aluminum bromide and chlorine gas react to form aluminum chloride and bromine gas.
