calculate the mass percent of a solution prepared by dissolving 17.2 g of nacl in 149 g of water

An electrochemical cell is made up of two different metal electrodes in an electrolyte and is used to produce an electric current through an oxidation-reduction reaction. Fe2+(aq) + -Fe3+(aq) option(a).

The half-reaction that takes place in the reduction of an electrochemical cell is referred to as the reduction half-reaction. The half-reaction that occurs in the oxidation half-reaction is known as the oxidation half-reaction. In the given electrochemical cell, the reduction half-reaction is Fe3+(aq) + e- ⇌ Fe2+(aq). The first step in identifying the reduction half-reaction is to distinguish between the anode and cathode. The anode is the electrode at which oxidation occurs, while the cathode is the electrode at which reduction occurs. The zinc electrode in the given cell is the anode, and it loses electrons, becoming Zn2+(aq). The iron electrode is the cathode, and it gains electrons, becoming Fe2+(aq). Fe3+(aq) + e- ⇌ Fe2+(aq)Fe3+(aq) undergoes reduction in the electrochemical cell. Therefore, option a is the right answer. The standard reduction potential for a half-reaction can also be used to predict which half-reaction will be reduced in a cell. The reaction with a more positive E° value (standard reduction potential) is reduced, while the reaction with a lower E° value is oxidized.

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The partial pressure of xenon in the container, which contains 30.0 grams of argon and 15.0 grams of xenon in a 120.0 ml volume at 22.0°C, is approximately 22.9 atm.

To calculate the partial pressure of xenon, we need to use the ideal gas law equation:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

First, we need to calculate the number of moles of each gas. We can use the molar mass of argon (39.95 g/mol) and xenon (131.29 g/mol) to convert the given masses into moles:

moles of argon = 30.0 g / 39.95 g/mol

moles of xenon = 15.0 g / 131.29 g/mol

Next, we need to convert the given volume to liters:

V = 120.0 ml / 1000 ml/L = 0.120 L

The temperature T is given as 22.0°C, which we convert to Kelvin:

T = 22.0°C + 273.15 = 295.15 K

Now, we have the values for n, V, and T. The next step is to calculate the total number of moles of gas in the container by summing the moles of argon and xenon.

Finally, we can calculate the partial pressure of xenon using the equation:

P(xenon) = (moles of xenon / total moles of gas) * total pressure

Since the total pressure is not given, we assume it to be 1 atm, as it does not affect the ratio of partial pressures. After substituting the values into the equation and performing the calculations, the partial pressure of xenon is approximately 22.9 atm.

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The window on the left side of the simulation shows the reaction a bc ⇌ ab c. This reaction is different from the reaction by which ammonia is synthesized in several ways. The reaction by which ammonia is synthesized is an exothermic reaction, whereas the reaction shown in the simulation is an endothermic reaction.

In an exothermic reaction, heat is produced as the reaction progresses, while in an endothermic reaction, heat is absorbed from the surroundings.

The synthesis of ammonia is an exothermic reaction that occurs as follows:

N2(g) + 3H2(g) ⇌ 2NH3(g) + Heat

The reaction produces heat as it progresses.

It is a reversible reaction, and it occurs at high temperature and pressure.

In contrast, the reaction shown in the simulation is endothermic.

This means that the reaction requires heat to proceed.

The reaction is reversible and can be written as follows:

a bc ⇌ ab + c

The reaction requires energy in the form of heat to proceed from left to right.

When energy is supplied to the system, the reaction proceeds from left to right, and when energy is removed from the system, the reaction proceeds from right to left.

In conclusion, the reaction shown in the simulation is different from the reaction by which ammonia is synthesized in several ways, including their exothermic and endothermic nature.

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N-ethyl-N-methylaniline has two alkyl substituents in total: an ethyl group and a methyl group.

The compound has two parts: aniline and the alkyl groups. Aniline is a molecule with a special structure called an aromatic ring, and it has an amino group (NH2) attached to it. The alkyl groups are just small chains of carbon and hydrogen atoms.

Aniline has two alkyl groups attached to it. One of the alkyl groups is called ethyl, and the other one is called methyl. The important thing to know is that the alkyl groups are connected to the nitrogen atom in the aniline molecule.

To determine the number of alkyl substituents in N-ethyl-N-methylaniline, let's break down the compound's name. "N-ethyl" suggests the presence of an ethyl group (-CH2CH3) attached to a nitrogen atom (N), and "N-methyl" indicates a methyl group (-CH3) attached to another nitrogen atom (N). Therefore, we have two alkyl substituents: one ethyl group and one methyl group. These alkyl groups are attached to the nitrogen atoms in the aniline molecule, which consists of a benzene ring (C6H5-) with one hydrogen atom replaced by an amino group (-NH2).

The alkyl groups in N-Ethyl-N-methylaniline serve as substituents, which means they replace hydrogen atoms in the parent compound, aniline. The ethyl group consists of two carbon atoms bonded to each other and three hydrogen atoms, while the methyl group consists of one carbon atom and three hydrogen atoms.

Hence, the compound N-ethyl-N-methylaniline has two alkyl substituents.

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The maximum in-plane tensile stress that you would suggest that this plate should carry can be estimated by using the fracture toughness value, which is 40 MPa*m0.5 for the similar plate samples pulled out.

The fracture toughness of a material indicates the resistance of the material to crack propagation, which is a measure of its ability to withstand stress and load. For brittle metals, a critical stress intensity factor (KIC) is used to calculate the fracture toughness.

The maximum in-plane tensile stress, σmax, can be estimated using the following equation:σmax = KIC / (Y * sqrt(a))Where, KIC is the fracture toughness,Y is a geometric factor that depends on the geometry of the sample, and a is the length of the crack that is being analyzed.

However, in this case, it is known that no flaws were detected in the plate by non-destructive testing techniques. Therefore, we can assume that there are no cracks present in the plate. Hence, the maximum in-plane tensile stress that can be applied to the plate can be estimated using the yield strength of the brittle metal.

The yield strength is the maximum stress that a material can withstand before it starts to deform plastically. Therefore, based on the given information, it is suggested to apply a maximum in-plane tensile stress that is lower than the yield strength of the brittle metal.

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The new water level in the graduated cylinder, after adding a 15.0 g piece of iron and a 20.0 g piece of lead, is approximately 151.34 ml.

To calculate the new water level, we need to consider the volumes of iron and lead based on their densities. The density of iron is approximately 7.87 g/ml, and the density of lead is approximately 11.34 g/ml. By dividing the masses of the respective metals by their densities, we can find their volumes.
The volume of iron is approximately 1.90 ml (15.0 g ÷ 7.87 g/ml), and the volume of lead is approximately 1.76 ml (20.0 g ÷ 11.34 g/ml). Subtracting the sum of these volumes from the initial water level of 155 ml gives us the new water level of approximately 151.34 ml.
Therefore, the new water level in the cylinder is approximately 151.34 ml.

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Lower-grade (sub-bituminous) coals in Western countries are being actively mined for environmental reasons because they are more plentiful and accessible than the higher-quality (bituminous) coal in the Appalachian region.

Lower-grade coal or sub-bituminous western is coal that has relatively lower sulfur content compared to other coal grades.

Sulfur emissions from burning coal can contribute to air pollution and the formation of acid rain.

Sub-bituminous coals typically contain lower sulfur content, making them a more environmentally favorable choice in terms of sulfur emissions.

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Complete question:

What is an environmental reason why lower-grade ( sub-bituminous) western coals are now being mined?

The Shine-Dalgarno (SD) sequence is used during the initiation step of protein synthesis in prokaryotes.

During translation, the SD sequence is located on the mRNA molecule and serves as a ribosome-binding site. It interacts with a complementary sequence on the small subunit of the ribosome, facilitating the proper positioning of the ribosome on the mRNA.

The SD sequence plays a crucial role in the recognition and initiation of translation in prokaryotes. It helps in the proper alignment of the ribosome with the start codon on the mRNA, ensuring the accurate initiation of protein synthesis.

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Approximately 1.56% of a cesium-131 sample remains after 60 days.

The decay constant of a radioactive sample determines the proportion of the original atoms that remain in the sample over time. Half-life is a measure of the time it takes for a radioactive sample to decay half of its atoms. Cesium-131, for example, has a half-life of 9.7 days and, after 60 days, we want to know what percentage of the sample remains.In every half-life, the amount of atoms remaining is halved. That is to say, half the number of atoms from the previous half-life remain. Since the half-life of cesium-131 is 9.7 days, the number of half-lives that have occurred in 60 days is 60/9.7 = 6.18.Since every half-life reduces the amount of atoms remaining by half, the number of atoms remaining after six half-lives is 1/2⁶. The amount of cesium-131 remaining after 60 days can be calculated as follows:100% - [(1/2)⁶× 100%] = 1.56%Therefore, approximately 1.56% of a cesium-131 sample remains after 60 days.

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Light travels about 9.46 x 10^15 meters in one calendar year (one light-year).

Light travels at a speed of 299,792,458 meters per second in a vacuum. To find out how long it takes for light to travel 120 yards (the length of a soccer field), we need to convert the yards to meters.1 yard = 0.9144 meters. Therefore, 120 yards = 109.728 meters.

To calculate the time it takes for light to travel this distance, we can use the formula: time = distance/speed time = 109.728/299,792,458 time = 0.000000366 seconds or 3.66 x 10^-7 seconds. To find out how far light travels in one calendar year (also known as a light-year), we need to multiply the speed of light by the number of seconds in a year.1 year = 31,536,000 seconds (approx.) distance = speed x time distance = 299,792,458 x 31,536,000 distance = 9,460,730,472,580,800 meters or approximately 9.46 x 10^15 meters. Therefore, light travels about 9.46 x 10^15 meters in one calendar year (one light-year).

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Explanation:

To find the freezing point of the solution, we can use the freezing point depression equation:

ΔT = Kᵣ x m

Where ΔT is the change in freezing point, Kᵣ is the freezing point depression constant of benzene, and m is the molality of the solution.

Substituting the values from the problem, we get:

ΔT = 5.12 °C/m x 2.8 m

ΔT = 14.34 °C

Since ΔT = Tᵢ - T, where Tᵢ is the freezing point of the solvent (benzene) and T is the freezing point of the solution, we can rearrange the equation to solve for T:

T = Tᵢ - ΔT

T = 5.50 °C - 14.34 °C

T = -8.84 °C

Therefore, the freezing point of the solution is -8.84 °C.

Answer:The freezing point of the solution is -8.84 °C.

Explanation:

The heat of the reaction is determined as 956 J.

The heat of the reaction is calculated by applying the following formula as follows;

Q = mcΔθ

where;

The mass of the water is obtained from its density;

density of water = 1 g/ml

mass of water = density x volume

mass of water = 1 g/ml x 55.7 ml = 55.7 g

The heat of a reaction is calculated as;

Q = 55.7 x 4.186 x 4.1

Q = 956 J

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The compound that is a secondary amine among the following is CH3CH2CH2NHCH3.

Amines are organic compounds that contain nitrogen. They are classified according to the number of alkyl or aryl groups that are bonded to nitrogen. Primary, secondary, and tertiary amines are the three classifications. 1. (CH3)3CNHCH3 is a tertiary amine and not a secondary amine. 2. CH3CH(NH2)CH2CH3 is a primary amine, not a secondary amine. 3. CH3CH2CH2NHCH3 is a secondary amine and falls under the classification of a secondary amine. 4. CH3CH2CH2CH2CH2NH2 is a primary amine, not a secondary amine.Therefore, the compound that is a secondary amine among the following is CH3CH2CH2NHCH3.

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Consider the planet-probe system for each of the two planets, then the first planet has a higher total mechanical energy.

The planet-probe system is a system consisting of a planet and a probe that orbits around it, the energy of such systems can be calculated using the principle of conservation of mechanical energy. The system with the greater total mechanical energy is the one that has a higher potential and kinetic energy at any given point in time.

If the potential energy is higher, the total mechanical energy will also be higher. In the context of classical mechanics, the total mechanical energy of a system is defined as the sum of its kinetic energy and potential energy. In other words, the total mechanical energy is the energy that is available to do work, and it is conserved in a closed system. Therefore, if the mechanical energy of the planet-probe system of a planet is greater than that of another planet, then the first planet has a higher total mechanical energy.

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NaOh or Ca(OH)₂ are not phosphates however, they can react with phosphates.

NaOH is called  sodium hydroxide and Ca(OH)₂ is called  calcium hydroxide.

They can be used to precipitate phosphate ions from solution.

The reaction between NaOH and phosphates or  Ca(OH)₂ and phosphates  is a double displacement reaction, in which the sodium ions in NaOH switch places with the phosphate ions in the phosphate compound. or the calcium ions in Ca(OH)₂ switch places with the phosphate ions in the phosphate compound.

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Dispersion forces are intermolecular forces that exist between the molecules of a substance. They are caused by the fluctuations in electron density, which results in temporary dipoles in a molecule. Dispersion forces are present in all molecules, regardless of their polarity or size.

The following statements are true about dispersion forces except one: All of the following statements concerning dispersion forces are correct EXCEPT: Dispersion forces are present in all molecules. Dispersion forces increase with the increase in molecular size. Dispersion forces are the weakest of all intermolecular forces. Dispersion forces are stronger in polar molecules. The correct answer is D: Dispersion forces are stronger in polar molecules. The statement is not true about dispersion forces because polar molecules have permanent dipole moments due to the uneven distribution of electrons in the molecule. Polar molecules possess dipole-dipole forces, which are stronger than dispersion forces. As a result, dispersion forces are weaker in polar molecules.

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The temperature at which the vapor pressures of the liquid and solid solvents are equal is known as the freezing point.

Thus, The solution vapour pressure will be lower than the pure solvent's when a non-volatile solute is added to a volatile liquid solvent. As a result, the solid and solution will come to equilibrium at a lower temperature than they would with a pure solvent and temperature.

The reasoning based on chemical potential is identical to this justification in terms of vapor pressure since a vapor's chemical potential is inversely proportional to pressure and temperature.

The reduction of the solvent's chemical potential in the presence of a solute is the cause of all the colligative features. This reduction is a result of entropy and freezing point.

Thus, The temperature at which the vapor pressures of the liquid and solid solvents are equal is known as the freezing point.

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The reaction that is associated with the lattice energy of CaS is (c) Ca²⁺(aq) + S²⁻ (aq) → Cas(s)

Lattice energy is defined as the amount of energy required to completely separate one mole of a solid ionic compound into its individual gaseous ions. It is therefore an indicator of the stability of the compound. The higher the lattice energy, the more stable the compound is. This is because the energy required to break the electrostatic attraction between the oppositely charged ions is high. In order to calculate lattice energy, one needs to know the charge of each ion, the distance between them, and Avogadro's number. Lattice energy is always an exothermic process because energy is released when the ions come together to form a solid compound. CaS is an ionic compound, so it has a high lattice energy. The reaction that is associated with the lattice energy of CaS is (c) Ca²⁺(aq) + S²⁻ (aq) → Cas(s). This is because the reaction involves the formation of solid CaS from its individual ions, which requires the release of energy as heat. The other reactions listed do not involve the formation of CaS from its ions, so they are not associated with the lattice energy of CaS.

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The Balanced nuclear equation for nitrogen-18: Nitrogen-18 is a radioactive isotope of nitrogen. The beta decay of Nitrogen-18 can be written as follows; N-18 → 0/-1 e + C-18where the beta particle is symbolized as 0/-1 e and C-18 is the resulting nuclide of nitrogen-18.

Beta decay, also called beta minus decay, is an radioactive decay in which an atomic nucleus emits a beta particle and transforms into a different element. In beta minus decay, a neutron is converted into a proton, an electron, and an antineutrino. The resulting nuclide has an atomic number that is one greater than that of the original nuclide and an atomic mass number that is unchanged.  The process of beta emission changes the atomic number of the element. The atomic number of Nitrogen is 7 and the mass number of Nitrogen-18 is 18. Beta emission will change the atomic number of Nitrogen-18 by -1 since it loses an electron and converts into oxygen. Oxygen is one atomic number greater than Nitrogen, so the element formed after the beta decay of nitrogen-18 is Oxygen-18. The balanced nuclear equation for the beta decay of nitrogen-18 can be written as follows; N-18 → 0/-1 e + O-18Hence, the balanced nuclear equation for the beta decay of Nitrogen-18 is: N-18 → 0/-1 e + O-18.

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The correct statement about silicon is D. All of these.

Silicon (Si) is a chemical element that exhibits properties of a metalloid. A metalloid is an element that has characteristics of both metals and nonmetals. Silicon has a shiny, blue-grey color with a metallic luster, which is characteristic of many metalloid elements.

Additionally, silicon is widely used as a semiconductor material. Semiconductors have electrical conductivity between that of a conductor and an insulator. Silicon's ability to conduct electricity can be modified by adding impurities, a process known as doping. This property makes silicon a fundamental component in the manufacturing of electronic devices such as transistors, integrated circuits, and solar cells.

Therefore, all of the given options are correct. Silicon is a metalloid, it has a blue-grey color with metallic luster, and it is commonly used as a semiconductor in various technological applications.

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pH of the resulting hydrochloric acid solution is 2.74.

To find the pH of a solution, we need to know the concentration of H+ ions in it.

We can use the equation

pH = -log[H+]

to calculate the pH of the solution given the concentration of H+ ions.

Here's how we can solve the problem:

Step 1: Find the moles of HCl in the solution.

The molar mass of HCl is 36.5 g/mol.

Mass of HCl = 0.30 g

Moles of HCl = mass/molar mass= 0.30/36.5= 0.00822 mol

Step 2: Find the concentration of H+ ions in the solution.

HCl is a strong acid, which means that it dissociates completely in water to give H+ and Cl- ions.

HCl → H+ + Cl-

So, the concentration of H+ ions in the solution is equal to the concentration of HCl, which is given by:

C = n/V = 0.00822 mol/4.5 L = 0.00183 mol/L

Step 3: Find the pH of the solution.

pH = -log[H+]

pH = -log(0.00183)

pH = 2.74

Therefore, the pH of the resulting hydrochloric acid solution is 2.74.

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The higher specific volume if both piston-cylinder systems contains 10 kg of air (ideal gas) UA=UB. Therefore, option B is correct.

The internal energy of a gas refers to the total energy associated with the microscopic motion and interactions of its individual particles, such as atoms or molecules. It includes various forms of energy, such as kinetic energy and potential energy.

The internal energy of the ideal gas is given by

3 UA UB ==nRT 2

Temperature is not changing, the number of moles is also the same, so there will be no change in internal energy.

so UA=UB

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Your question is incomplete the complete question is attached to the image.

Explanation:

To solve the problem, we can use the freezing point depression equation:

ΔT = Kf · molality

where ΔT is the change in freezing point, Kf is the freezing point depression constant, and molality is the concentration of the solution in moles of solute per kilogram of solvent.

In this case, we're looking for the freezing point of a solution of C5H4 in benzene, given that the freezing point of pure benzene is 5.50 °C, and the freezing point depression constant is 5.12 °C/m.

First, let's calculate the molality of the solution:

molality = moles of solute / kilograms of solvent

To find the moles of solute, we need to know the molar mass of C5H4. By looking it up in a periodic table, we find:

Molar mass of C5H4 = 64.09 g/mol

The problem doesn't tell us how much solute was added, but it does give us the concentration of the solution as 0.41 m (which means 0.41 moles of C5H4 per kilogram of benzene). Therefore:

molality = 0.41 moles / 0.998 kg ≈ 0.411 mol/kg

Now we can calculate the freezing point depression:

ΔT = Kf · molality

ΔT = 5.12 °C/m · 0.411 mol/kg ≈ 2.10 °C

The freezing point depression tells us how much the freezing point of the solution is lowered compared to the freezing point of pure benzene. Therefore, the freezing point of the solution is:

Freezing point = 5.50 °C - 2.10 °C = 3.40 °C

Therefore, the freezing point of the 0.41 m solution of C5H4 in benzene is 3.40 °C.

The freezing point of the solution, given that the water has a freezing point of 0.00 °C is -5.58 °C

We know that the freezing point of a solution is related to the freezing point of water by the following equation:

Freezing point of solution = Freezing point of water - Freezing point depression

With the above formula, we shall obtain the freezing point of the solution. This is illustrated below:

Freezing point of solution = Freezing point of water - Freezing point depression

Freezing point of solution = 0 - 5.58

Freezing point of solution = -5.58 °C

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The child needs 1,569.25 mg of amoxicillin per day, with 784.63 mg of amoxicillin per dose.

Streptococcus infections are commonly treated with amoxicillin, a broad-spectrum antibiotic.

Amoxicillin is effective against many different types of bacteria, including Streptococcus bacteria.

When a child has a streptococcus infection, amoxicillin may be prescribed at a dosage of 45 mg per kg of body weight per day given b.i.d.

In this case, a 76.8 lb child would be given 1,385.28 mg of amoxicillin per day, divided into two equal doses, for a total of 692.64 mg per dose.

Amoxicillin is a penicillin antibiotic used to treat infections caused by bacteria.

It is effective against many different types of bacteria, including streptococcus bacteria.

The required dosage of amoxicillin for a child is determined by their body weight and the extent of the infection they are experiencing.

In this case, the child weighs 76.8 lbs, which is equivalent to 34.85 kg.

The dosage of amoxicillin is 45 mg per kg of body weight per day, so the child needs 1,569.25 mg of amoxicillin per day.

This dosage is divided into two equal doses, so the child needs 784.63 mg of amoxicillin per dose.

Since amoxicillin is often taken orally, this dosage can be provided in the form of a tablet, suspension, or chewable tablet.

The duration of amoxicillin treatment will depend on the severity of the infection and the response of the child to the treatment. Generally, amoxicillin treatment lasts for 10 to 14 days.

The child should continue taking amoxicillin for the full prescribed course, even if they start feeling better before the treatment is completed.

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K and S²⁻ are isoelectronic ions with 19 number of electron. Therefore, the correct option is option C.

When two atoms, ions, or molecules share an identical electronic structure or valence electron count, they are said to be isoelectronic. "Equal electric" and "equal charge" are the terms used. Chemical species that are isoelectronic often have identical chemical characteristics.

Cu and Zn²⁺

Atomic number of copper = 29

Atomic number of Zinc =30, +2 shows that zinc has two less electron

number of electron of Zinc = 30-2=28

Hence, Cu and Zn²⁺ are not isoelectronic ions

Ti²⁺ and Sc

Atomic number of Sc= 21

number of electron of copper = 22-2=20

Hence, Ti²⁺ and Sc  are not isoelectronic ions

K and S²⁻

Atomic number of K = 19

Number of electron of sulfur = 16+3=19

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The correct equilibrium expression for the reaction C(s) + H2O(g) = CO(g) + H2(g) is K = [CO][H2]/[C][H2O].

The equilibrium expression for a chemical reaction represents the ratio of the concentrations (or partial pressures) of the products to the concentrations (or partial pressures) of the reactants, each raised to the power of their respective stoichiometric coefficients.

In the given reaction:

C(s) + H2O(g) ⇌ CO(g) + H2(g)

The stoichiometric coefficients are 1 for each species involved.

The equilibrium expression can be written as:

K = [CO][H2] / [C][H2O]

Here, the square brackets [] represent the concentrations of the species at equilibrium.

Therefore, the correct equilibrium expression for the given reaction is K = [CO][H2] / [C][H2O].

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The addition of NH₃ (aq) to CuCO₃ (s) will decrease the solubility of CuCO₃ due to the formation of the complex ion [Cu(NH₃)₄]²⁺ (aq).

The addition of NH₃ (aq) to CuCO (s) forms the complex ion [Cu(NH₃)₄]²⁺ (aq).

The formation constant (Kf) for this complex ion is given as 1.07 * 10¹².

The solubility product constant (Ksp) for CuCO₃(s) is given as 2.30 * 10⁻¹⁰.

These constants provide information about the equilibrium between the dissolved species and the solid compound.

In this case, we can write the reaction as:

CuCO₃ (s) ⇌ Cu²⁺ (aq) + CO₃²⁻ (aq)

Upon the addition of NH3(aq), the complex ion [Cu(NH3)4]2+(aq) is formed:

Cu²⁺ (aq) + 4 NH₃(aq) ⇌ [Cu(NH₃)₄]²⁺ (aq)

The Kf value of 1.07 * 10¹² indicates a highly stable complex, meaning that the formation of the complex is favored.

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Hydroxide reacts with protons to make water molecules.

The plausible explanation for the negative entropy of hydration for OH- is that hydroxide ions (OH-) react with protons (H+) present in the solution to form water molecules (H2O). This reaction reduces the number of distinct species in the system, resulting in fewer possible microstates.

The decrease in the number of microstates leads to a decrease in entropy. In contrast, the other species tested in the lab (NH4+, Na+, and NO3-) do not undergo similar reactions that reduce the number of distinct species, hence their hydration entropies may be different.

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The correct chemical formula for hexaaquanickel (II) chloride is: [Ni(H₂O)₆]Cl₂

The name "hexaaquanickel (II) chloride" tells us that the compound contains a nickel ion with a charge of +2 and six water molecules. The formula shows us that the compound contains one nickel ion, two chlorine ions, and six water molecules.

The nickel ion is represented by the symbol Ni. The charge on the nickel ion is indicated by the superscript +2. The water molecules are represented by the symbol H₂O. The subscript 6 indicates that there are six water molecules in the compound.

The chloride ions are represented by the symbol Cl. The subscript 2 indicates that there are two chloride ions in the compound.

The overall formula for hexaaquanickel (II) chloride is therefore [Ni(H₂O)₆]Cl₂.

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