Answer:
2.35 * 10^{-4} moles
Explanation:
T
4. A patient must take 200 milligrams of medication with each meal. If 1 milliliter ofliquid contains 25 milligrams of medication, how many milliliters of medication shouldthe patient take each day? Assume that the patient eats 3 meals per day.
To determine how many milliliters the patient need each meal we can use a rule of three:
[tex]\begin{gathered} 1\text{ mL}\rightarrow25\text{ mg} \\ x\rightarrow200\text{ mg} \end{gathered}[/tex]then:
[tex]x=\frac{200\cdot1}{25}=8[/tex]Hence the patient need 8 mL each meal; since the patient eats three meals per day he needs a total 24 mL per day of the medication.
Which would require the least force to move a box along a floor with a coefficient of friction of 0.30?
Multiple Choice
pull it with a rope at an angle of 30° above the horizontal
push it at an angle of 30° below the horizontal
EITHER pull it with a rope at an angle of 30° above the horizontal OR push it at an angle of 30° below the horizontal
not enough information to solve
The least force to move a box along a floor with a coefficient of friction of 0.30 Pull it with a rope at an angle of 30° above the horizontal.
Coefficient of FrictionThe friction coefficient is the ratio of the normal force pressing two surfaces together to the frictional force preventing motion between them. Typically, it is represented by the Greek letter mu (μ). In terms of math, is equal to F/N, where F stands for frictional force and N for normal force. Since both F and N are measured in units of force, the coefficient of friction is a dimensionalless quantity (such as newtons or pounds). For both static and kinetic friction, the coefficient of friction has a range of values. When an object experiences static friction, the frictional force resists any applied force, causing the object to stay at rest until the static frictional force is removed. The frictional force opposes an object's motion in kinetic friction.To learn more about Coefficient of Friction refer :
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a floor with a 0.30 coefficient of friction requires the least amount of force to move a box along it. At a 30° angle above the horizontal, pull it with a rope.
The correct answer is A.
What exactly is the friction coefficient?The resistive force of friction divided by the normal and perpendicular force (N) pushing the objects together yields the coefficient of friction (fr), which is a numerical value.
What are the two friction coefficients?The static friction coefficient and the kinetic friction coefficient are the two types of friction. Generally speaking, the coefficient of kinetic friction is lower than the coefficient of static friction.
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A hollow sphere of mass 1.4 kg has a radius of 1.5 m and has a linear speed of 5.6 m/s at the edge. what is the angular momentum of the hollow sphere?
We will have the following:
[tex]I=(1.4kg)(1.5m)(5.6m/s)\Rightarrow I=11.76kg\cdot m^2/s[/tex]So, the moment of inertia of the hollow sphere is 11.76 kg*m^2/s.
True or false-Normal reaction is the force
that opposes the force of gravity and acts in
the direction of the force of gravity.
O True
O False
false
normal force always acts perpendicular to the contact force
23. A simple circuit has a voltage of 12V and a current of 1.8A. Find the resistance in thecircuit24. A simple circuit has a resistance of 1101 and a current of 0.9A. What is the voltagesupplied to the circuit?
23.
Given,
Voltage , V=12V
Current, I=1.8 A
To find
The resistance in the circuit
Explanation
We know
By Ohm's law,
[tex]V=RI[/tex]where R is th6e resistance
Putting the values,
[tex]\begin{gathered} 12=R\times1.8 \\ \Rightarrow R=6.67A \end{gathered}[/tex]Conclusion
The resistance is 6.67A
In an electric breakdown in air (a spark), an electron (inertia 9.11 × 10 −31 kg ) experiences an electric force of 4.99 × 10 −13 N .What is the electron's acceleration?
The electron's acceleration is 5.302x10¹⁷m/s²
What is electron's acceleration?
Considered is the acceleration of electrons in a plasma by a strong electromagnetic wave that strikes the surrounding magnetic field at an angle. It is demonstrated that there is a wave amplitude threshold that causes stochasticity. Although significant acceleration is possible below this threshold, it is restricted to a single resonance's trapping breadth. The electrons can accelerate from resonance to resonance above the threshold. It is further demonstrated that the Hamiltonian surfaces defining the interaction between waves and particles are topologically open when the parallel phase velocity of electromagnetic waves is supraluminous. In this situation, electrons acquire a lot of energy. The mechanism is appropriate for use in space applications since it is quite resilient and only slightly sensitive to changes in the wave parameters and the beginning energy of the electron.
Applying Newton's law of motion:
F = ma
⇒a = F/m
⇒a=4.83x10⁻¹³/9.11x10⁻¹³
⇒a=5.302x10¹⁷m/s²
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Two
objects attract each other gravitationally
a force of 50 10 10 N when they are
apart.
If the mass of one object is
2.00 kg, what is the mass of the other
Object?
with
0.20m
M2 = 0.665 kg
The mass of other object is 0.665 kg
Solution:To solve this, we must apply Newton's law of universal gravitation, which states that the force of gravity between two massive bodies 1, 2, is proportional to their masses M1 and M2 and inversely proportional to the square of the distance d between them:
F = (GM1M2) / D²
Here G = 6.67 × 10⁻¹¹ Nm²/kg²
F = 50×10⁻¹⁰N
M1 = 2.00kg
D = .20 m
by substituting values ,
50×10⁻¹⁰N =(( 6.67 × 10⁻¹¹ Nm²/kg²)(2.00kg)M2) / (.20 m)²
50×10⁻¹⁰ = 1.334 × 10⁻¹⁰ M2 /( .20)²
(50×10⁻¹⁰) (.20)² = 1.334 × 10⁻¹⁰ M2
2 ×10⁻¹⁰ = 1.334 × 10⁻¹⁰ M2
M2 = 1.334 × 10⁻¹⁰ / 2 ×10⁻¹⁰
M2 = 0.665 kg
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What is the pH and pOH of number 4 a-d
The pH and pOH of [H+] are 4 and 10 respectively.
a. [H+] = 1.0 × 10⁻⁴ M = 4
b. [H+] = 7.9 × 10⁻⁶ M = 6 - log 7.9 = 5.1
c. [OH⁻] = 1.0 × 10⁻² M = 14 - 2 = 12
d. [OH⁻] = 2.3 × 10⁻⁸ M = 14 - 8 - log 2.3 = 6.36
PH, traditionally denoting "ability of hydrogen", is a scale used to specify the acidity or basicity of an aqueous solution. Acidic solutions are measured to have decreased pH values than simple or alkaline solutions.
PH is a degree of the way acidic/primary water is. The variety goes from zero - 14, with 7 being neutral. pHs of less than 7 suggest acidity, whereas a pH of greater than 7 indicates a base. pH is virtually a degree of the relative amount of free hydrogen and hydroxyl ions inside the water.
Whilst the pH scale generally runs from 0 to fourteen, it's far truly feasible to calculate a negative pH. A bad pH happens when the molarity of hydrogen ions in a strong acid is more than 1 N (Normality).
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Using a lower frequency of light in a slit diffraction experiment has what effect?Select one:a.There is no difference between frequencies of light.b.fewer bright bandsc.brighter patternsd.more bright bands
Here b option is correct because the frequency affe
Lesson 10
Write an expository essay explaining how force is related to each of the following essential content points.
*gravity
*air resistance
*inertia
*acceleration
*transfer of momentum
Gravity is the force by which a planet or other body draws objects toward its center. The force of gravity keeps all of the planets in orbit around the sun.
Air resistance is a force that is caused by air. The force acts in the opposite direction to an object moving through the air.
Inertia means an object will continue its current motion until some force causes its speed or direction to change.
Acceleration is the rate of change of velocity per unit time. It is vector quantity and its S.I. unit is m/[tex]s^{2}[/tex].
Transfer of momentum is the amount of momentum transferred from one particle to another during particle collision or interaction. This phenomenon can be utilized in various areas of physics and optics including condensed matter physics and diffraction on the atomic scale.
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What is the speed of each ball when they are each 4.10 m above the ground?
ANSWER:
12.3 m/s
STEP-BY-STEP EXPLANATION:
The vertical speed can be calculated by means of the following equation:
[tex]v^2_{^{}y}=u^2_y+2\cdot a\cdot s[/tex]The speed in both cases is the same, since the angle remains the same.
We can calculate the initial speed in y since we know the angle, the value s would be the height, therefore, we substitute and calculate the final speed in y:
[tex]\begin{gathered} v^2_y=(11\cdot\sin 50)^2+2\cdot(-9.8)\cdot(-4.1) \\ v^2_y=151.36 \\ v_y=\sqrt[]{151.36} \\ v_y=12.3\text{ m/s} \end{gathered}[/tex]The speed would be 12.3 m/s in both cases
1. Using the values of acceleration calculate Usain’s greatest and least net forces.Average Acceleration(m/s/s)02.84.861.120.60.510.180.19-0.18-0.180
Given:
mass of the usain is
[tex]m=94\text{ kg}[/tex]Acceleration is given as
[tex]a=0,\text{ 2.8, 4.86, 1.12, 0.6, 0.51, 0.18 0.19, -0.18, 0}[/tex]Required: calculate the greatest and least net forces.
Explanation:
we know the force is given as
[tex]F=ma[/tex]where m is the mass and a is the acceleration
to calculate the greatest force
we need find the greatest acceleration in the given table that is
[tex]a=4.86\text{ m/s}^2[/tex]plugging all the values in the above relation we get:
[tex]\begin{gathered} F=ma \\ F=94\text{ kg}\times4.86\text{ m/s}^2 \\ F=456.84\text{ N} \end{gathered}[/tex]now, to calculate the least force we have the find the least acceleration
that is
[tex]a=0\text{ m/s}^2[/tex]plugging all the values in the above relation, we get:
[tex]\begin{gathered} F=ma \\ F=94\text{ kg}^\times0 \\ F=0 \end{gathered}[/tex]so least force is zero.
we can se another least force when the acceleration is negative that is
[tex]a=-0.18\text{ m/s}^2[/tex]then force is
[tex]\begin{gathered} F=ma \\ F=94\text{ kg}\times-0.18\text{ m/s}^2 \\ F=-16.92\text{ N} \end{gathered}[/tex]Thus. the greatest force is
[tex]\begin{equation*} 456.84\text{ N} \end{equation*}[/tex]and least force is
[tex]-16.92\text{ N}[/tex]A car traveling with a speed of 64.5 mph (mi/h) What is the cars speed in meters per second ( m/s)
We will have the following:
[tex]\begin{gathered} 64.5\frac{mi}{h}\ast\frac{1609.34m}{1mi}\ast\frac{1h}{3600s}=28.83400833...m/s \\ \\ \approx28.8m/s \end{gathered}[/tex]So, the velocity given is approximately 28.8 m/s.
A small box is held in place against a rough vertical wall by someone pushing on it with a force directed upward at 27 ∘ above the horizontal. The coefficients of static and kinetic friction between the box and wall are 0.40 and 0.30, respectively. The box slides down unless the applied force has magnitude 23 N .
The box slides down the wall unless an external force of magnitude 23 N is applied on it. The object is directed upward with an angle of 27° above the horizontal surface. Therefore, the mass of block is 1.90 kg
What is friction?
A friction is a kind of force which resists the sliding or rolling of objects over the surface of each other.
Applied force, F = 23 N
Coefficient of static friction, μs = 0.40
Coefficient of kinetic friction, μs = 0.30
θ = 27°
Let 'N' be the normal reaction of the wall acting on the block and 'm' be the mass of block.
Resolve the components of force 'F'
As the block is in horizontal equilibrium with the wall.
So,
F Cos27° = N
N = 23 Cos27° = 20.495 N
As the block does not slide so it means that the static friction force acting on the block balances the downwards forces (gravity) acting on the block.
The force of static friction is:
μs x N = 0.4 x 20.495 = 8.19 N .... (1)
The vertically downward force acting on the block is (mg - F Sin27°)
mg - 23 Sin 27° = mg - 10.441 ... (2)
Now by equating the forces from equation (1) and (2), we get
mg - 10.441 = 8.19
mg = 18.631
m x 9.8 = 18.631
m = 1.90 kg
Thus, the mass of block is 1.90 kg.
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Your question is incomplete, most probably the complete question is:
A small box is held in place against a rough vertical wall by someone pushing on it with a force directed upward at 27 ∘ above the horizontal. The coefficients of static and kinetic friction between the box and wall are 0.40 and 0.30, respectively. The box slides down unless the applied force has magnitude 23 N. What is the mass of the box in kilograms?
You're pulling a suitcase through the airport on its wheels. The suitcase handle is at an angle of 62.4 to the horizontal. The pulling force you apply to the handle is 10.4 N. How much work (in Joules) are you doing on the suitcase if you pull it a distance of 25.9 m through the airport?
The work is given by:
[tex]W=Fd\cos \theta[/tex]where F is the foce acting on the object, d is the distance traveled and theta is the angle between the force and the distance. Then in this case we have:
[tex]\begin{gathered} W=(10.4)(25.9)\cos 62.4 \\ W=124.79 \end{gathered}[/tex]Therefore you are doing 124.79 J
The elevator and passengers have a mass of 5500 kg. After a stop at the fifth floor, the elevator accelerates upward uniformly at 1.0 m/s2 until it is rising at 2.0 m/s. What is the magnitude of the net force acting on the elevator as it accelerates?
The net force acting on the elevator is 5940.0N
We are given that,
The acceleration of elevator upward = a =1.5m/s²
The total mass of the elevator and passenger = 5500 kg
The velocity of the elevator = v = 2.0 m/s
Therefore , the elevator accelerating upward then the net exerted force F is acting on the elevator can be calculated by the Newton's second law of motion i.e.
F = ma
Thus, the acceleration due to gravity (g) of the elevator would be taken as 9.8 m/s² then the above equation may be written as,
F = m (g + a)
If putting the values in above equation then we get the total exerted force of the elevator,
F = 5500kg ( 9.8 m/s² + 1.0m/s² )
F = 5940.0 N
Therefore, the net force acting on the elevator would be 5940.0N
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Compute the wavelength in air of ultrasound with a frequency of 38 kHz if the speed of sound is 344 m/s.answer in:____ m
λ = 0.0091 m
Explanation:The frequency, f = 38 kHz
f = 38000 Hz
The speed, v = 344 m/s
The wavelength is calculated using the formula:
λ = v/f
Substitute f = 38000 Hz and v = 344 m/s into the formula and solve for λ
λ = 344/38000
λ = 0.0091 m
Poor electrical conductors have low resistance.TrueFalse
ANSWER
False
EXPLANATION
The resistance of a material is the ability of the material to oppose the flow of electrical current through it.
A conductor is a material that allows the flow of electricity through it. This implies that if a material is a poor conductor, then, it does not allow the free flow of electrical current through it. In other words, the material opposes the flow of current and can be said to have resistance.
Therefore, if a material is a poor conductor, it means that it has a high resistance.
The correct answer is false.
A. 0.2 m/s
B. 9.875 m/s
C. 6.2 m/s
D. 6.125 m/s
(i would like to know how to do it)
Answer:
C. 6.2 m/s
Explanation:
The magnitude of the distances are
East direction
| d1 | = 80 m
West direction
| d2 | =75m
Total magnitude of distance = 80 + 75 = 155
Total time taken = 5 + 20 = 25 s
Magnitude of speed = 155/25 = 6.2 m/s
10. An athlete swims from the north end to the south end of a 60.0m pool in
20.0s and makes the return trip to the starting position in 22.0s.
a. What is the average velocity for the first half of the swim?
b. What is the average speed for the entire trip?
c. What is the average velocity for the round trip?
a) 3 meter per second is the average velocity for the first half of the swim.
b) 2.72 meter per second is the average speed for the entire trip.
c) 2.85 meter per second is the average velocity for the round trip.
What is velocity and example?Velocity can be defined as the rate that something moves in a specific direction. as the speed of a vehicle speeding north on a highway or the pace at which a rocket lifts off. Because the velocity vector is scalar, its absolute value magnitude will always equal the motion's velocity.
Briefing:The formula to find average velocity is given by :-
Average velocity =total distance/total time taken
a) The average velocity for the first half of the swim = 60/20 =3 ms⁻¹
b) The average velocity for the entire trip of the swim=60/22=2.72 ms⁻¹
c) The average velocity for the roundtrip= 60+60/20+22 = 120/42 =2.85 ms⁻¹
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Question 1
Thallium-208 has a half-life of 3.00 minutes. How much of 80.0 g sample of Thallium-208 has decayed (no longer radioactive) after 12 minutes?
75,0 g
5.0 g
10.0 g
40,0 g
Answer:
Explanation:
Given:
T = 3.00 min
t = 12 min
m₀ = 80.0 g
____________
m - ?
The Law of radioactive decay:
m = m₀·2^(-t/T)
n = (t/T) = 12 / 3.00 = 4
m = m₀ / 2ⁿ
m = 80 / 2⁴ = 80 / 16 = 5 g
Quick physics problem BIG POINTS, need asap
Answer:
Explanation:
Given:
L = 68 km
V₁ = 88.2 km/h
V₂ = 97.4 km/h
_____________
t -?
Time to complete the distance for each skier:
t₁ = L / V₁ = 68 / 88.2 ≈ 0.77 h
t₂ = L / V₂ = 68 / 97.4 ≈ 0.70 h
Waiting time:
t = t₁ - t₂ = 0.77 - 0.70 = 0.07 h
or
t = 60·0.07 = 4.2 min
Which term describes the adaptation of cells, organs, or organ systems for a specific function?
The organ system is made to connect with the organ and it does the job for the organ by the connection.
What is organ system?
An organ is a group of tissues that work together for the overall function of the organ, and an organ i hain system is a group of organs are that work together to the perform a specific function. The human organism of consists of eleven organ system.
An organ system is a group of the organs that work together in the body to perform a complex function, such as the pumping blood or the processing and utilizing the nutrients. There are 11 of major organ systems in the human body: The circulatory system. The lymphatic system. In The respiratory system.
Cell can adapt themselves by undergoing 5 different condition
-hyperplasia
-hypertrophy
-atrophy
-metaplsia
-dysplasia
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The gap between thundering and flashing of light is found to be 10 seconds.How high may the clouds be in the sky?
Answer:
Lightning and thunder are produced simultaneously, but the thunder is heard a few seconds after the lightning is seen. This is because the speed of light in air is more than the speed of sound in air.
The speed of light is given as 3×10
8
m/s. The speed of sound is 340 m/s. Thus, the entire time of 10 seconds (as mentioned in the question) between seeing the light and hearing the thunderstorm is taken by the sound to travel to the observer. Hence, the distance traveled by the thunder is given as follows.
s=vt; where,
s is the distance traveled, v is the velocity of sound and t is the time taken.
That is, 330m/s×10s=3400m=3.4km.
Thus, the distance traveled by the thunder is 3.4km.
Explanation:
Answer:
Explanation:
Given:
V = 340 m/s - Sound speed
t = 10 c
______________
S - ?
S = V·t = 340·10 = 3 400 m
A 2.4 kg block slides freely across a rough horizontal surface such that the block slows down with an acceleration of -0.8 m/s^2. What is the coefficient of kinetic friction between the block and the surface? (Use g= 10 m/s^2) *
Given:
Mass of block = 2.4 kg
Acceleration = -0.8 m/s^2
Let's ifnd the coefficient of kinetic friction,
To find the coefficient of kinteic friction, apply the formula:
[tex]\mu=\frac{F}{N}[/tex]Where:
F is frictional force
N is the normal force.
Hence, we have:
[tex]\begin{gathered} \mu=\frac{ma}{mg} \\ \\ \mu=\frac{2.4\times(0.8)}{2.4\times10} \\ \\ \mu=\frac{1.92}{24} \\ \\ \mu=0.08 \end{gathered}[/tex]Therefore, the coefficient of friction between the block and the surface is 0.08
ANSWER:
0.08
A metal rod 80cm long lengthens by 0.090cm when its temperature rises by 93.6 C. What is the linear expansivity of the metal?
The linear expansion of the metal is 0.000012 K⁻¹
The linear expansion of the metal rod is given by
ΔL = L₀αΔT
where,
ΔL = 0.090 cm is the linear expansion
L₀ = 80 cm is the initial length of the rod
α is the linear expansivity
ΔT = 93.6°C is the increase in temperature
By re-arranging the equation, we find the linear expansivity:
α = ΔL÷L₀ΔT = 0.090cm ÷ 80cm ×93.6K = 0.000012 K⁻¹
Temperature is the measure of hotness or coldness expressed in terms of any of several scales, together with Fahrenheit and Celsius. Temperature suggests the course in which warmness energy will spontaneously go with the flow—i.e., from a warmer body (one at a better temperature) to a less warm frame (one at a decrease temperature).
Body temperature is an early caution signal of contamination. Fever is one of the frame's first reactions to infection and is a commonplace symptom in lots of illnesses. Tracking your body temperature, can help locate disorder or contamination early.
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AWNSER!!!!!!!!!!!!!!!!!!!!!!! HELP HELP HELP HELP HELP HELP! Determine the gravitational potential energy of a 7.5-N object ready to fall from a height of 5 m. Show your work.
Answer: 7.5x5 =37.5
Answer:
7.5×3.5=37.5
Explanation:
Gravitational potential energy= mgh (mass × gravitational field strength × height)
So the formula mg gives you weight so we can write it as weight × height)
weight and force is same thing so both units are Newton. Please note that gravitational field strength is constant and its value is 10
Answer:
The correct answer would be :
7.5×3.5=37.5
Explanation:
This is because the gravitational potential energy= mgh
So this formula of mg gives us the weight so we can then write this as
(weight × height)
weight and force is same thing so both units are Newton. Please note that gravitational field strength is constant and its value is 10
Explanation:
Have a great day/week.
999Can you tell me if the answer I have gotten is correct
In order to calculate the horizontal distance the ball will travel after falling off the table, first let's calculate the time the ball will be falling, using the formula below and considering the vertical movement:
[tex]\begin{gathered} \Delta S=V_0\cdot t+a\cdot\frac{t^2}{2} \\ 1=0+9.81\cdot\frac{t^2}{2} \\ 1=4.905t^2 \\ t^2=\frac{1}{4.905} \\ t=0.45 \end{gathered}[/tex]So the ball was falling for 0.45 seconds. Let's use this time to calculate the horizontal displacement when the ball started falling:
[tex]\begin{gathered} \Delta S=V\cdot t \\ \Delta S=1.4\cdot0.45 \\ \Delta S=0.63\text{ meters} \end{gathered}[/tex]So the distance is 0.63 meters.
What would be my independent,dependent variable also my control group. In the experiment the distance of the walk and run were the same 10 meters throughout
According to the data, the independent variable is distance, control group is time and dependent variables are velocity and acceleration.
A roller coaster has 658J of energy at the bottom of a loop. How much energy does the roller coaster have at the top of the loop, assuming no friction
The energy of the roller coaster at the bottom of the loop is given as
E = 658 J.
This is the kinetic energy of the roller coaster.
Due to this kinetic energy, the roller coaster starts moving upwards.
With the increasing height of the roller coaster, potential energy increases and kinetic energy decreases.
Thus, at the top of the loop, the roller coaster has only potential energy.
According to the conservation of energy,
[tex]\begin{gathered} \text{Energy at the bottom of the loop = Energy at the top of the loop} \\ E=\text{ 658 J} \end{gathered}[/tex]Thus, the answer is 658 J.
