Calculate the pH of a buffer that is 0.040 M HF and 0.080 M NaF. The Ka for HF is 3.5 × 10^-4.
A) 2.06
B) 4.86
C) 3.16
D) 3.46
E) 3.76

To name a compound that has multiple double/triple bonds, you will need to follow these steps:

1. Identify the longest carbon chain containing the multiple bonds (double or triple).
2. Number the carbon atoms in the chain, starting from the end closest to the first multiple bond.
3. For each multiple bond (double/triple), indicate its position in the chain using the corresponding carbon number.
4. Use the prefixes "di-" or "tri-" for two or three multiple bonds of the same type, respectively. If there are different types of multiple bonds, use the prefixes "en" for double bonds and "yn" for triple bonds.
5. Combine the position numbers, prefixes, and the base name of the hydrocarbon (alkane, alkene, or alkyne).

For example, if you have a compound with two double bonds on the second and fourth carbons, the name would be 2,4-diene.

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To find the percent of Sodium in Sodium Carbonate, follow these steps:

1. Determine the molecular formula of Sodium Carbonate: Na2CO3

2. Calculate the molar mass of Sodium Carbonate:
  - Sodium (Na) has a molar mass of 22.99 g/mol.
  - Carbon (C) has a molar mass of 12.01 g/mol.
  - Oxygen (O) has a molar mass of 16.00 g/mol.

3. Calculate the total molar mass of Sodium Carbonate:
  - (2 × 22.99 g/mol for Na) + (1 × 12.01 g/mol for C) + (3 × 16.00 g/mol for O) = 105.98 g/mol.

4. Calculate the mass contribution of Sodium:
  - 2 × 22.99 g/mol = 45.98 g/mol.

5. Calculate the percent of Sodium in Sodium Carbonate:
  - (Mass of Sodium / Total molar mass of Sodium Carbonate) × 100%
  - (45.98 g/mol / 105.98 g/mol) × 100% ≈ 43.4%

The percent of Sodium in Sodium Carbonate is approximately 43.4%.

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The substances are most likely to the form the solution when it is placed in the water is  Sodium Iodide, the Propanol,  Potassium Fluoride.

The solubility of the solute in the solvent will be depends on the solute-solvent interaction. The interaction in between the solute and the solvent will be increases, the solubility will increases.

The Propanol will be dissolve in the water as the is the polar covalent. The Pentane and the benzene are the nonpolar hydrocarbons, and it will not dissolve as in the polar solvent, water. The Sodium Iodide, the Propanol, and the Potassium Fluoride are correct options.

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This question is incomplete, the complete question is :

five different substances are given to you to be dissolved in water. which substances are most likely to form a solution when placed in water?

Sodium Iodide,  Propanol,  Potassium Fluoride, pentene, benzene.

True. SN2 reactions typically result in a product that has the same relative configuration as the starting material.

The SN2 reactions same relative configuration is  because the nucleophile attacks the carbon from the opposite side of the leaving group, leading to inversion of the stereochemistry.

A nucleophilic substitute in which the rate demanding step involve 2 components.

for example; oH cL

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When the plunger of the syringe was pulled upward, the balloon expanded or inflated.

When the plunger of the syringe was pushed, the balloon compressed or deflated.

For Activity B, after being submerged in warm water, the balloon expanded or inflated.

The expansion of the balloon can be explained by the gas laws and the kinetic molecular theory (KMT). The gas laws state that when the temperature of a gas increases, its volume also increases, assuming that pressure remains constant. KMT explains that gas particles have kinetic energy and move randomly and rapidly, colliding with each other and the container they are in.

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The answer choice that determines whether or not an action potential is triggered in the postsynaptic neuron is C. the overall net change in membrane potential caused by the combined EPSPs and IPSPs.

This is because the postsynaptic neuron integrates both the depolarizing effects of excitatory postsynaptic potentials (EPSPs) and the hyperpolarizing effects of inhibitory postsynaptic potentials (IPSPs) to determine if the action potential threshold is reached. If the net effect of these combined potentials surpasses the threshold, an action potential will be generated in the postsynaptic neuron.

Conversely, if the combined potentials do not meet the threshold, an action potential will not be triggered. Therefore, it is the overall net change in membrane potential caused by the simultaneous presence of both EPSPs and IPSPs that ultimately decides whether an action potential will be initiated in the postsynaptic neuron. The answer choice that determines whether or not an action potential is triggered in the postsynaptic neuron is C. the overall net change in membrane potential caused by the combined EPSPs and IPSPs.

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The four quantum numbers, their symbols, descriptions, organizational levels, and possible values are as follows:

1. Principal quantum number (n): This quantum number describes the energy level and size of an electron's orbital. Its organizational level is the electron shell. Possible values are positive integers (n = 1, 2, 3, ...).

2. Angular momentum quantum number (l): This quantum number describes the shape of an electron's orbital. Its organizational level is the subshell. Possible values are integers ranging from 0 to (n - 1) (l = 0, 1, 2, ..., n - 1).

3. Magnetic quantum number (m_l): This quantum number describes the orientation of an electron's orbital in space. Its organizational level is the orbital. Possible values are integers ranging from -l to +l (m_l = -l, -(l-1), ..., 0, ..., +(l-1), +l).

4. Spin quantum number (m_s): This quantum number describes the intrinsic angular momentum (or "spin") of an electron. Its organizational level is the individual electron. Possible values are +1/2 and -1/2 (m_s = +1/2, -1/2).

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To find the mole fraction of NH3 in the solution, we need to first calculate the total mass of the solution:

Total mass = mass of NH3 + mass of water
Total mass = 15.0 g + 250.0 g
Total mass = 265.0 g

Next, we can calculate the volume of the solution using the density:

Density = mass/volume
Volume = mass/density
Volume = 265.0 g/0.974 g/mL
Volume = 271.82 mL

Now, we can use the volume and concentration of NH3 to calculate the amount of moles of NH3 in the solution:

Concentration = mass/volume
Concentration of NH3 = 15.0 g/271.82 mL
Concentration of NH3 = 0.055 mol/mL

To find the mole fraction of NH3 in the solution, we need to divide the moles of NH3 by the total moles of the solution:

Mole fraction of NH3 = moles of NH3 / total moles
Total moles = (mass of NH3/molar mass of NH3) + (mass of water/molar mass of water)
Total moles = (15.0 g/17.03 g/mol) + (250.0 g/18.02 g/mol)
Total moles = 0.881 mol + 13.871 mol
Total moles = 14.752 mol

Mole fraction of NH3 = 0.055 mol/mL / 14.752 mol
Mole fraction of NH3 = 0.003729

Therefore, the mole fraction of NH3 in the solution is 0.003729.

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The information about muscles and bones and acid and alkalis are given below.

Your body needs oxygen (O2) and carbon dioxide (CO2) gases for different processes. Oxygen is necessary for cellular respiration, which is the process by which your body creates energy from glucose. Carbon dioxide, on the other hand, is a waste product of cellular respiration and must be removed from the body. It is transported to the lungs and exhaled.

Breathing rate and pulse rate are controlled by the autonomic nervous system, which responds to changes in the body's need for oxygen and removal of carbon dioxide. During physical activity or exercise, the body's need for oxygen increases, and so the breathing rate and pulse rate increase to deliver more oxygen to the muscles. When at rest, the body requires less oxygen, so the breathing rate and pulse rate decrease.

A drug is a substance that affects the way the body functions. Drugs can be used for medicinal purposes, such as to treat diseases or alleviate symptoms, or for recreational purposes. Some drugs are legal and can be obtained with a prescription, while others are illegal.

The human arm consists of three main parts: the upper arm, the forearm, and the hand. The upper arm bone is called the humerus, and the two bones in the forearm are called the radius and ulna. The hand consists of the wrist, palm, fingers, and thumb. Muscles that help to move the arm include the biceps brachii, triceps brachii, deltoid, and rotator cuff muscles.

Capillaries are small, thin-walled blood vessels that connect arteries and veins. They have a single layer of cells that allows for the exchange of gases, nutrients, and waste products between the blood and the tissues. Oxygen (O2) and carbon dioxide (CO2) are stored and carried by hemoglobin, a protein found in red blood cells. In the lungs, hemoglobin binds to oxygen, and in the tissues, it releases oxygen and binds to carbon dioxide for transport back to the lungs.

An acid is a chemical substance that donates protons (hydrogen ions) to a solution. Acids have a pH less than 7 and can be corrosive or sour. Some common examples of acids include hydrochloric acid, sulfuric acid, and citric acid.

An alkali is a chemical substance that accepts protons (hydrogen ions) from a solution. Alkalis have a pH greater than 7 and can be caustic or bitter. Some common examples of alkalis include sodium hydroxide and potassium hydroxide.

A neutral substance is a chemical substance that has a pH of 7, which is neither acidic nor alkaline. Water is a good example of a neutral substance.

Litmus is a type of dye that changes color in response to pH changes. It turns red in acidic solutions (pH less than 7) and blue in alkaline solutions (pH greater than 7).

A variable is a factor or condition that can be changed or manipulated in an experiment or study. It can be either an independent variable (the variable that is being manipulated) or a dependent variable (the variable that is being measured).

The name of the reaction between an acid and an alkali is a neutralization reaction.

Some common word equations involving acids and alkalis include:

Hydrochloric acid + sodium hydroxide → sodium chloride + water

Sulfuric acid + potassium hydroxide → potassium sulfate + water

Nitric acid + calcium hydroxide → calcium nitrate + water

In a chemical reaction, reactants are the starting materials or substances that undergo a chemical change, while products are the substances that are formed as a result of the chemical change. For example, in the reaction between hydrochloric acid and sodium hydroxide, the reactants are hydrochloric acid and sodium hydroxide, and the products are sodium chloride and water. The chemical equation for this reaction is:

HCl + NaOH → NaCl + H2O

Here, HCl and NaOH are the reactants, while NaCl and H2O are the products.

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Let's start by setting up the initial conditions:

We have a balloon with a known volume (3.2 L) and the pressure inside the balloon is at atmospheric pressure (760 mm Hg). When submerging in water, the pressure increases to 783 mmHg.

Next, we need to use the ideal gas law (P1 * V1 = P2 * V2) to solve for the new volume of the balloon underwater:

760 * 3.2 = 783 * V2

Now, we can solve for the new volume of the balloon:

V2 = (783 / 760) * 3.2

V2 = 3.39 L

So, the new volume of the balloon is 3.39 L, which is a slight increase in volume due to the increase in pressure underwater.

We can use the given formula (P1 * V1 = P2 * V2) to solve for the volume change in any situation where there is a change in pressure and volume. This is a very common and important equation in chemistry and physics, and it's important to be able to understand and use it effectively.

Option 2- 6.63ml of ethanol is required to produce 10g of CO₂.

The chemical equation is not provided in the question. However, we can determine the amount of ethanol needed to produce 10.0 g of CO2 using stoichiometry.

The balanced chemical equation is:

C₂H₅OH + 3O₂ → 2CO2 + 3H₂O

From the equation, we can see that 1 mol of ethanol (C₂H₅OH) produces 2 mol of CO₂. The molar mass of ethanol is 46.07 g/mol, which means that 1 mL of ethanol has a mass of 0.789 g.

To determine the volume of ethanol needed, we first need to calculate the number of moles of CO₂ produced:

10.0 g CO₂× (1 mol CO2/44.01 g CO₂) = 0.227 mol CO₂

Since 1 mol of ethanol produces 2 mol of CO₂, we need half as many moles of ethanol:

0.227 mol CO₂ × (1 mol C₂H₅OH/2 mol CO₂) = 0.114 mol C₂H₅OH

Finally, we can use the density of ethanol to calculate the volume needed:

0.114 mol C₂H₅OH × (46.07 g/mol) ÷ (0.789 g/mL) = 6.63 mL

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The described process is the six-electron reduction of Cr3+ ions to solid chromium (Cr) and solid selenium (Se). We can determine the accuracy of the following claims using the information provided:

G > 0: Under normal circumstances, the reaction is not spontaneous because it entails reducing Cr3+ ions to Cr, which requires energy input. G is hence positive.

S > 0: Without extra system knowledge, it is challenging to discern the sign of S. The total change in entropy (S) may, however, be little or even negative because the reaction results in the production of two solid products from two watery reactants.

Since G is positive, the reaction is reactant-favored and not product-favored. The claim that "The reaction is reactant-favored" is thus true.

Since the reaction involves the transfer of six electrons from Cr3+ to Se, the statement "n = 6 mol electrons" is accurate.

G > 0: Since the reaction is not spontaneous under normal circumstances, G is higher than zero.

The appropriate answers are thus:

The reaction is reactant-favored.

n = 6 mol electrons.

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A formula unit is the smallest repeating unit of a compound in ionic form, and it represents one molecule or ion. The formula weight, on the other hand, is the sum of the atomic weights of all the atoms in a compound's formula, including both the empirical formula and the molecular formula.

The unit used for molecular weight and formula weight is atomic mass units (amu) or grams per mole (g/mol). The difference between these two weights is that the molecular weight is the weight of a molecule in its simplest form, while the formula weight is the weight of the empirical formula of a compound.

To find the molecular weight of a compound, you add up the atomic weights of all the atoms in the molecule. To find the formula weight, you add up the atomic weights of all the atoms in the empirical formula. For example, the molecular weight of water is

18.015 g/mol (2 x 1.008 amu for hydrogen + 1 x 15.999 amu for oxygen),

while the formula weight is 18.015 g/mol as well (1 x 1.008 amu for hydrogen + 1 x 15.999 amu for oxygen).

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When 12.73 g sample of water is injected into a closed evacuated flask of volume 5L  at 65 c. By 6.377% percent  of the water will be vapor when equilibrium is reached.

The ideal gas law can be demonstrated as the equation of the state of a perfect gas. The product of the pressure and volume of a one-mole ideal gas is equal to the product of the absolute temperature (T) and universal gas constant (R).

Mathematically the ideal gas equation can be described as follows:

PV = nRT

Where n is the moles of a substance,  R is the gas constant., T is the temperature, P is the pressure, and V is the volume of the gas.

Given, the volume of water, V = 5 L

The temperature of the water, T = 65°C = 65 + 273 = 338 K

The pressure of the water, P = 187.5 mmHg =  0.25 atm

Substituting the values V, R, P, and temperature in the ideal gas equation, we get:

The number of moles of water vapor, n = PV/RT

n = 0.25 ×5/(0.082 × 338)

n = 0.0451 mol

The mass of the water vapor = 0.0451 × 18 = 0.812 g

The percent of water vaporized = (0.812/12.73) × 100 = 6.377%

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The complete question is

1 2.73 g sample of water is injected into a closed evacuated flask of volume 5L at 65 c. what percent (by mass) of the water will be vapor when equilibrium is reached? the vapor pressure of water at 65°C is 187.5 mmHg

Delta E represents the energy difference between reactants and products in a chemical reaction.

The contrast between the possible energy of the items and the likely energy of the reactants is known as the adjustment of expected energy or ΔE. In a synthetic response, this energy contrast addresses how much energy that is either delivered or consumed during the response.

Assuming the potential energy of the items is lower than that of the reactants, then the response discharges energy as intensity, light, or sound. This is known as an exothermic response. On the other hand, assuming the expected energy of the items is higher than that of the reactants, then, at that point, the response assimilates energy from its environmental elements. This is known as an endothermic response.

The size of ΔE relies upon a few variables, including the compound bond qualities and the temperature and tension of the response. Understanding the adjustment of potential energy is significant in fields like science and thermodynamics, as it permits researchers to anticipate and control the energy changes that happen during synthetic responses.

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The complete question is:

In a reaction, the potential energy of the reactants is 40 kJ/mol, the potential energy of the products is 10 kJ/mol and the potential energy of the activated complex is 55 kJ/mol. What is the activation energy for the reverse reaction?(answer: 45 kJ/mol)

The correct answer is True. The percent by mass of each element in a compound is known as the percent composition of a compound.

can you give me a brilliant mark?

When a quinone is oxidized, it forms a hydroquinone.

This is because the oxidation reaction involves the addition of two hydrogen atoms to the quinone, which results in the formation of a hydroquinone molecule. The process of oxidizing a quinone to form a hydroquinone is an important chemical reaction in many biological processes, including cellular respiration and photosynthesis.

what is oxidation reaction ?

Redox is a type of chemical reaction in which the oxidation states of atoms are changed. Redox reactions are characterized by the actual or formal transfer of electrons between chemical species, most often with one species undergoing oxidation while another species undergoes reduction.

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Answer:

72,540 meters

Explanation:

distance is equals to speed x time

first will change the time in minutes to sec ad Multiply

For every mole of NaN3 that is broken down, one mole of N2(g) is produced. Using the molar mass of NaN3, which is 68.99 g/mol, we can determine how many moles of NaN3 are present given that we have 50.0 g of the substance.

We get 0.724 mol of NaN3 by dividing 50.0 g by 68.99 g/mol. We can determine that 0.724 mol of NaN3 will result in 0.724 mol of N2(g) since 1 mole of NaN3 yields 1 mole of N2(g). We may use the molar mass of N2(g), which is 28.02 g/mol, to determine the mass of N2(g) produced.

0.724 mol is multiplied by 28.02 g/mol to yield 20.3 g of N2(g). Therefore, 20.3 g of N2(g) will be created from 50.0 g of NaN3.

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Liquid water in the earth's air is an example of a D. liquid in a gas.

Air enveloping the Earth holds a striking type of solution: liquid water suspended in gas. This phenomenon, known as a gas-liquid solution, or a method by which a non-gas solute is dissolved in a gas solvent, pervades the atmosphere.

Visible neither to the eye nor with aid of a microscope, vaporized droplets immerse themselves within air's interstices and remain invisible to sight. Other illustrative examples of this process include carbon dioxide laced throughout bubbly soda, oxygen permeating red vernal blood.

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You can determine the R/S configuration of a chiral center in a Fischer projection when the lowest priority group is not initially on a vertical line.

To determine the R/S configuration of a chiral center in a Fischer projection when the lowest priority group is not on a vertical line, you can follow these steps:

1. Identify the chiral center and assign priority to the four groups attached to it based on the Cahn-Ingold-Prelog rules (the higher the atomic number, the higher the priority).

2. Rotate the Fischer projection in such a way that the lowest priority group (group 4) is placed on a vertical line. You can achieve this by mentally exchanging two groups at a time until the desired orientation is obtained. Remember, every exchange reverses the configuration (from R to S or vice versa).

3. Once the lowest priority group is on a vertical line, determine the R/S configuration by observing the clockwise or counterclockwise direction of the priority order (1-2-3). If the order is clockwise, it is R; if counterclockwise, it is S.

4. If you made an odd number of exchanges in step 2, the configuration remains the same. If you made an even number of exchanges, the configuration is reversed (R to S or vice versa).

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So, 30 g of the solid substance absorbed 79.5 J of heat during the phase change.

The heat of fusion is the amount of heat energy required to melt one gram of a substance at its melting point. Therefore, to calculate the amount of heat absorbed during the phase change of 30 g of the solid substance with a heat of fusion of 2.65 J/g, we can use the following formula:

Q = m * ΔHf

here Q is the amount of heat absorbed (in joules), m is the mass of the substance (in grams), and ΔHf is the heat of fusion (in joules per gram).

Q = 30 g * 2.65 J/g

= 79.5 J

Therefore, 30 g of the solid substance absorbed 79.5 J of heat during the phase change.

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Answer:

2Na + Cl2 -------> 2 NaCl ... only add at sodium and

product 2 coficient

N2 + 3H2 --------> 2NH3 ...... only add at Hydrogen molecule and it's product 2 and 3 respectively.

The equations can be balanced as -

2Na + Cl₂ = 2 NaCl

2N₂ + 3H₂ = 2 NH₃

A balanced chemical equation is an equation where the number of atoms of each type in the reaction is the same on both reactants and product sides.

An unbalaced chemical equation is not an accurate representation of a chemical equation and thus requires balancing.

The law of conservation of mass is the governing law for balancing a chemical equation.

The law states that ‘mass can neither be created nor be destroyed in a chemical reaction’

Hence, the total mass of substances before the reaction should be equal to the mass after the reaction is complete.

Therefore, The equations can be balanced as -

2Na + Cl₂ = 2 NaCl

2N₂ + 3H₂ = 2 NH₃

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General corrosion occurs when most or all of the atoms on the same metal surface are oxidized, damaging the entire surface. Most metals are easily oxidized: they tend to lose electrons to oxygen (and other substances) in the air or in water. As oxygen is reduced (gains electrons), it forms an oxide with the metal

The given statement, The value of Kw is 10¹⁴ M² at 25°C is False.

The value of Kw, otherwise known as the ionic product of water, is not 10¹⁴ M² at 25°C. Kw is the product of the activity of the hydrogen and hydroxide ions of a given solution at a certain temperature. The value of Kw depends on temperature and is an equilibrium constant for the dissociation of water into hydrogen and hydroxide ions.

At 25°C, the value of Kw is approximately 10⁻¹⁴ M², which is significantly lower than 10¹⁴ M². This is because water molecules are relatively stable at 25°C, so they do not easily dissociate into hydrogen and hydroxide ions. As temperature increases, so does the value of Kw, because the increased energy causes more water molecules to dissociate into ions, thus increasing the ionic product of water.

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The properties of the element and its compounds are not the same. In the case of fluorine, we know that this is a volatile and reactive element but fluorides are stable and less harmful elements that can serve beneficial purposes.

Fluorine is a chemical element that is known for its ability to combine easily with oxygen and other elements. It is a highly reactive substance but this is not the case with fluorides. The fluorides have already undergone a reaction so they are no longer as volatile as fluorine in the ordinary state.

They are used in toothpaste formulations to strengthen the gums but this cannot be said of fluorine which should not be tasted in the raw state.

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If the pH of the resulting solution is 2.65, The Ka for the acid is 3.21 x 10⁻⁶.

To calculate the Ka for the acid, we need to use the relationship between Ka, the concentration of the acid in solution, and the pH of the solution:

Ka = [H+][A-]/[HA]

where [H+] is the concentration of hydrogen ions in solution, [A-] is the concentration of the conjugate base of the acid in solution, and [HA] is the concentration of the acid in solution.

Given that the pH of the solution is 2.64, we can calculate the concentration of hydrogen ions in solution:

pH = -log[H+]

2.64 = -log[H+]

[H+] = 2.24 x 10⁻³M

Since the acid is monoprotic, the concentration of the conjugate base [A-] is equal to the concentration of the acid [HA]:

[HA] = 1.56 M

Now we can use the formula for Ka:

Ka = [H+][A-]/[HA]

Ka = (2.24 x 10⁻³)² / 1.56

Ka = 3.21 x 10⁻⁶

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The solution is going to have a pH of 12.7.

The pH uses a logarithmic scale with 7 as neutral, where lower values are more acidic and higher ones are more alkaline, to represent the acidity or alkalinity of a solution. The hydrogen ion concentration (c), expressed in moles per litre, determines the pH, which is equal to log10(c).

Now we know that;

pOH = - log(0.05M)

pOH = 1.3

pH = 14 - 1.3

= 12.7

We know that the above can be justified if we remember that pH +
pOH = 14

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