Calculate the pH of a buffer that is 0.200 M H3BO3 and 0.122 M KH2BO3. The Ka for H3BO3 is 5.8 × 10^-10.
A) 8.93
B) 9.02
C) 10.77
D) 9.46
E) 3.52

a. For the first  response A B--> 2C, the value of ∆ H2 will be equal in magnitude but  contrary in sign to ∆ H1, because the rear  response.

2C--> A B, is just the original  response reversed. So, ∆ H2 = - ∆ H1.  

b. For the first  response A1/2 B--> C, the value of ∆ H2 will also be equal in magnitude but  contrary in sign to ∆ H1, because the rear  response, C--> A1/2 B, is just the original  response reversed. So, ∆ H2 = - ∆ H1.  

c. For the first  response A--> B 2C, the value of ∆ H2 will be equal in magnitude but  contrary in sign to ∆ H1/ 2, because the rear  response, 1/ 2B C-->1/2 A, is just the original  response reversed and halved. So, ∆ H2 = - ∆ H1/ 2.

For the first  general  response, A B--> 2C and 2C--> A B, the value of ∆ H2 will be equal in magnitude but  contrary in sign to ∆ H1, because the rear  response, 2C--> A B, is just the original  response reversed. So, ∆ H2 = - ∆ H1.   This means that the enthalpy change for the rear  response is equal in magnitude but  contrary in sign to the enthalpy change for the forward  response.  

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The types of alkyl halides that are capable of forming a carbocation include:

1. Primary alkyl halides (1°): These have the halogen atom bonded to a carbon that is bonded to only one other carbon atom.
2. Secondary alkyl halides (2°): These have the halogen atom bonded to a carbon that is bonded to two other carbon atoms.
3. Tertiary alkyl halides (3°): These have the halogen atom bonded to a carbon that is bonded to three other carbon atoms.

Tertiary alkyl halides are the most capable of forming carbocations due to their greater stability, followed by secondary and primary alkyl halides.

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Al(OH)3 has a molar solubility of about 2.2 1010 M in pure water, which is answer option (B).

Its solubility is the maximum amount of solute that may dissolve in a known volume of solvent at a specific temperature.

The solubility product expression for Al(OH)₃ is:

Ksp = [Al3+][OH-]³

Assuming that x is the molar solubility of Al(OH)₃ in pure water, then the equilibrium concentrations of Al³⁺ and OH⁻ in the solution are both equal to x. Therefore, we can write:

Ksp = x * (3x)³ = 27x⁴

Substituting the value of Ksp = 1.3 × 10⁻³³, we get:

27x^4 = 1.3 × 10⁻³³

Solving for x, we get:

x = (1.3 × 10⁻³³ / 27)[tex]^{(1/4)[/tex] ≈ 2.2 × 10⁻¹⁰ M

Therefore, the molar solubility of Al(OH)₃ in pure water is approximately 2.2 × 10⁻¹⁰ M, which corresponds to answer choice (B).

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Al(OH)3 has a molar solubility of about 2.2 1010 M in pure water, which is answer option (B).

Its solubility is the maximum amount of solute that may dissolve in a known volume of solvent at a specific temperature.

The solubility product expression for Al(OH)₃ is:

Ksp = [Al3+][OH-]³

Assuming that x is the molar solubility of Al(OH)₃ in pure water, then the equilibrium concentrations of Al³⁺ and OH⁻ in the solution are both equal to x. Therefore, we can write:

Ksp = x * (3x)³ = 27x⁴

Substituting the value of Ksp = 1.3 × 10⁻³³, we get:

27x^4 = 1.3 × 10⁻³³

Solving for x, we get:

x = (1.3 × 10⁻³³ / 27) ≈ 2.2 × 10⁻¹⁰ M

Therefore, the molar solubility of Al(OH)₃ in pure water is approximately 2.2 × 10⁻¹⁰ M, which corresponds to answer choice (B).

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7.45 atm is the initial pressure of a gas in balloon that has a volume of 14. 0 L and a temperature of 36 C when it was moved into a location with pressure of 5. 0 atm, 6. 0 L and 18. 0 C.

The ideal gas law, which links a gas's pressure, volume, temperature, and number of moles (n), can be used to address this issue:

PV = nRT

where R is the constant of an ideal gas.

We must use the initial circumstances existing before the balloon was relocated in order to determine the gas's initial pressure. The volume (V) and temperature (T) are known, but we still need to determine the amount of gas per mole (n).

n = PV/RT

By considering the starting conditions, we may determine n:

n = (P₁V₁)/(R*T₁)

where P1, V1, and T1 are the starting pressure, volume, and temperature, respectively.

n is calculated as (P114.0 L)/(0.0821L atm/mol*K * (36+273) K).

Now we may utilize the last circumstances to get the gas's final pressure:

P₂V₂ = nRT₂

where T₂ is the final temperature and V₂ the final volume.

P₂ = (nRT₂)/V₂

(P₁V₁T₂) (V₂*T₁)

P₂ is equal to (P114.0 L(18+273 K)/(6.0 L*(36+273 K)).

P₂ = 3.22 atm

The ideal gas law can also be used to determine the initial pressure:

P₁ = nRT₁/V₁

P₁ = (nRT₁)/V₁

P₁ = (14.0 L * 0.0821 L atm/molK * (36+273) K) / (3.22 atm * 6.0 L * (36+273) K).

P₁ = 7.45 atm

As a result, the balloon's gas had a 7.45 atm beginning pressure.

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The oxygen atom of the carbonyl group bears a significant amount of partial negative charge. This is because oxygen is more electronegative than the carbon it is bonded to, which causes it to attract the shared electrons more strongly, resulting in a partial negative charge on the oxygen atom and a partial positive charge on the carbon atom.

The oxygen atom of the carbonyl group bears a significant amount of c. partial negative charge, due to the electronegativity of the oxygen atom causing it to attract electrons more strongly than the carbon atom.

                 This results in an uneven distribution of electron density, with the oxygen atom having a greater share of the electrons and a partial negative charge, while the carbon atom has a partial positive charge.
                       

Therefore,  The oxygen atom of the carbonyl group bears a significant amount of c. partial negative charge.

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The number of moles of the unknown quantity of gas is 3.74 mol.

The Ideal gas law states that "the pressure multiplied by volume is equal to moles multiply by the universal gas constant multiply by temperature.

It is expressed as;

PV = nRT

Where P is pressure, V is volume, n is the amount of substance, T is temperature and R is the ideal gas constant ( 0.08206 Latm/molK )

Given that:

Plug the values into the above formula and solve for n.

PV = nRT

n = PV / RT

n = ( 2.3 × 50L ) / ( 0.08206 Latm/molK × 375K )

n = 115 Latm / 30.7725 Latm/mol

n = 3.74 moles.

Therefore, the amount of gas is approximately 3.74 mol.

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The one which is not necessary for the filtration is thermometer. The correct option is A.

The filtration, the process in which the solid particles present in the liquid or the gaseous fluid will be removed by the use of the filter medium which will the permits and the fluid to pass the through it but it will be retains the solid particles.

The most common example of the filtration is the making tea. When we are preparing the tea, the filter or the sieve which is used when we separate the tea leaves from the water and through the sieve pores, the water will be pass. The correct option is A.

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To find the molarity of the final solution, we can use the formula:

M1V1 = M2V2

where M1 is the initial molarity, V1 is the initial volume, M2 is the final molarity, and V2 is the final volume.

In this problem, we know that:

M1 = 1.5 M
V1 = 60.0 mL = 0.060 L
V2 = 2.0 L

We want to find M2, the final molarity. Plugging in the values we know, we get:

(1.5 M)(0.060 L) = M2(2.0 L)

Solving for M2, we get:

M2 = (1.5 M)(0.060 L)/(2.0 L)
M2 = 0.045 M

Therefore, the molarity of the final solution is 0.045 M.

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The radius of a barium atom in units of picometers is 225.77 pm.

The radius of a barium atom can be calculated using the density and the unit cell of barium. The density of barium is 3.59 g/cm3 and it has a body-centered cubic unit cell. Using the density and the volume of the unit cell, we can calculate the molar mass of barium which is 137.327 g/mol.

The molar mass is then divided by the Avogadro constant to calculate the atomic mass of barium. Then, the atomic radius of barium can be calculated using the mass and the density of barium. The atomic radius of barium is calculated to be 225.77 pm.

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Keto-enol tautomerism is a chemical equilibrium between an organic chemistry enol (alcohol) and a keto form (a ketone or an aldehyde). There are said to be tautomers between the keto and enol forms.

The image of the keto tautomeric form of the compound (2Z) But-2-en-2-ol is attached below.

In comparison to aldehydes, ketones tend to be more stable and are therefore less likely to produce the enol tautomer because they have two alky groups that donate electron density into the carbonyl carbon.

III>II>I is the order of tautomeric compound stability. The tautomer III has the maximum stability because to the conjugated C=C and C=O double bonds, which leads to delocalization and hydrogen bonding. Additionally, tautomer I is less stable than tautomer II because the enol group is less stable than the keto group.

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The complete question is:

Draw the keto tautomeric form of the following compound: (2Z) But-2-en-2-ol

Interactive 3D display mode Draw the molecule on the canvas by choosing buttons from the Tools (for bonds), Atoms, and Advanced Template toolbars. The single bond is active by default.

The rate law relates the rate of a chemical reaction to the concentrations of its reactants, and its orders must be experimentally determined by measuring the rate changes as reactant concentrations vary, as stoichiometric coefficients cannot be used to determine the reaction orders.

The rate law is a mathematical expression that relates the rate of a chemical reaction to the concentrations of its reactants. It is usually written in the form: rate = k[A]^m[B]^n, where k is the rate constant, [A] and [B] are the concentrations of the reactants, and m and n are the orders of the reaction with respect to A and B, respectively. The overall order of a reaction is the sum of the individual orders of each reactant, so it can be determined by adding up the values of m and n.

Stoichiometric coefficients cannot be used to determine the orders of a reaction because they only indicate the ratio in which the reactants are consumed, not the rate at which they are consumed. The orders of a reaction must be experimentally determined by measuring how the rate of the reaction changes as the concentration of each reactant is varied. This can be done by performing a series of experiments in which one reactant concentration is varied while keeping the others constant and measuring the rate of the reaction. By analyzing the data, the orders of the reaction can be determined.

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The percentage of O₂ that will react to form NO at 1700 °C is approximately 98.3%.

This can be calculated by using the equilibrium constant and the initial molar ratios of the reactants. By using the equilibrium equation, we can set the initial molar ratio of N₂ and O₂ to Kc.

In this case, Kc = 4.10 × 10⁻⁴ and the initial molar ratio of N₂ and O₂ is 1:1 (as both have 0.459 mole). The equation can then be rearranged to solve for the percentage of O₂ that will react to form NO. This yields a value of approximately 98.3%.

This value can be used to determine the equilibrium concentration of NO in the container. As the initial molar ratio of N₂ and O₂ is 1:1, the equilibrium molar ratio of NO would also be 1:1. Therefore, the equilibrium concentration of NO in the 0.665-L container would be 0.459 mol/L.

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Sex cells, also known as gametes, transmit genetic information for determining traits to their offspring through a process called meiosis.

During meiosis, the diploid parent cell undergoes two rounds of cell division, resulting in four haploid daughter cells, each containing half the genetic information of the parent cell.

In humans, the male sex cell, or sperm cell, and the female sex cell, or egg cell, each contains 23 chromosomes, which combine during fertilization to form a diploid zygote with 46 chromosomes. The genetic information carried by these chromosomes determines various traits such as eye color, height, and susceptibility to certain diseases.

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Normality is a measure of the concentration of a solution, which takes into account the number of active particles (ions or molecules) in the solution. It is defined as the number of equivalents of solute per liter of solution.

The equation used to find normality when given molarity depends on the nature of the solute and the reaction in question. In general, the relationship between molarity (M) and normality (N) is given by the formula:
N = M x n

where n is the number of equivalents of solute per mole. For example, if you have a solution of hydrochloric acid (HCl) with a molarity of 1 M, and you want to find its normality, you need to know that HCl is a strong acid that dissociates completely in water, producing one hydrogen ion (H+) and one chloride ion (Cl-) per molecule of HCl. Therefore, the number of equivalents of HCl is 1, and n = 1.

Using the formula above, we get:
N = M x n = 1 M x 1 equiv/mole = 1 N
So the normality of the 1 M HCl solution is 1 N.

In summary, normality is a concentration unit that takes into account the number of active particles in a solution, and the equation to find it from molarity depends on the nature of the solute and the reaction involved.

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The chemical law, which states that equal volumes of all ideal gases at the same temperature and pressure contain the same number of molecules, was first proposed by the Italian chemist Amedeo Avogadro. This principle is typically named after him as Avogadro's Law.

What is Amedeo Avogadro ?

In 1811, Avogadro published an article in a scientific journal, where he distinguished between molecules and atoms. He argued (contrary to what was thought) that in the case of water, the hydrogen and oxygen "atoms" were actually "molecules." One molecule of oxygen would react with two molecules of hydrogen (H2O).

Thus he proclaimed his famous hypothesis: "Equal volumes of any gases contain the same number of molecules when measured under the same conditions of temperature and pressure."

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To calculate the concentration of H3O⁺ in a solution containing 5.5 × 10^-5 M OH⁻ at 25°C, we will use the ion product of water (Kw) formula. At 25°C, Kw = [H3O⁺][OH⁻] = 1.0 × 10^-14.

Step 1: Write down the given values.
[OH⁻] = 5.5 × 10^-5 M
Kw = 1.0 × 10^-14

Step 2: Use the formula to find [H3O⁺].
[H3O⁺] = Kw / [OH⁻]

Step 3: Substitute the given values into the formula.
[H3O⁺] = (1.0 × 10^-14) / (5.5 × 10^-5)

Step 4: Calculate the result.
[H3O⁺] = 1.818 × 10^-10 M (approximately)

Now, we need to identify if the solution is acidic, basic, or neutral. Since [H3O⁺] < [OH⁻], the solution is considered basic.

So the correct answer is:
A) 1.8 × 10^-10 M, basic

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Based on the information, we can infer that the point of view of the creator of the cleats is "It is worth investing in quality cleats" (option D):

To identify the sentence that refers to the point of view of the advertiser we must read the ad and the options. Once we have done this procedure we can establish what would be the statement that would express the opinion of the advertiser.

In this case, we can infer that the statement that expresses the advertiser's opinion is "It is worth investing in quality cleats" because it highlights that the value of this product is high, but likewise its quality is superior to that of other products from this type.

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Answer: The volume of nitrogen evolved at STP when 63 g of ammonium dichromate is heated is approximately 5.6 L.

Explanation:

To find the volume of nitrogen evolved, we'll first need to determine the moles of ammonium dichromate used, and then use the stoichiometry of the balanced equation to find the moles of nitrogen produced. Finally, we'll convert the moles of nitrogen to volume at STP.

The balanced equation is:

(NH4)2Cr2O7 -> Cr2O3 + 4H2O + N2

Calculate the molar mass of ammonium dichromate, (NH4)2Cr2O7:

2 * (14.01 [N] + 4 * 1.01 [H]) + 2 * 51.99 [Cr] + 7 * 16.00 [O] =

2 * (14.01 + 4.04) + 103.98 + 112.00 = 252.06 g/mol

Calculate the moles of ammonium dichromate:

63 g / 252.06 g/mol ≈ 0.25 mol

Use stoichiometry to find moles of nitrogen produced:

1 mol (NH4)2Cr2O7 produces 1 mol N2, so 0.25 mol (NH4)2Cr2O7 produces 0.25 mol N2.

Convert moles of nitrogen to volume at STP (standard temperature and pressure):

At STP (0°C and 1 atm), 1 mole of any gas occupies 22.4 L. Therefore, 0.25 mol N2 occupies:

0.25 mol × 22.4 L/mol ≈ 5.6 L

So, the volume of nitrogen evolved at STP when 63 g of ammonium dichromate is heated is approximately 5.6 L.

The Ksp is (C) 5.33 × 10⁻³⁷.

Its solubility is the maximum amount of solute that may dissolve in a known volume of solvent at a specific temperature.

The balanced chemical equation for the dissolution of Ba₃(PO₄)₂ is:

Ba₃(PO₄)₂(s) ⇌ 3Ba²⁺(aq) + 2PO₄³⁻(aq)

The expression for the solubility product constant (Ksp) of Ba₃(PO₄)₂ is:

Ksp = [Ba²⁺]³ [PO₄³⁻]²

Given that the molar solubility of Ba₃(PO₄)₂ is 8.89 × 10⁻⁹ M, we can assume that the initial concentration of Ba²⁺ and PO₄³⁻ ions is also 8.89 × 10⁻⁹ M. Substituting this value into the Ksp expression, we get:

Ksp = (8.89 × 10⁻⁹)³ (8.89 × 10⁻⁹)² = 5.33 × 10⁻³⁷

Therefore, the answer is (C) 5.33 × 10⁻³⁷.

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Answer:

Phenol

Explanation:

A phenol is a compound that has an alcohol functional group (-OH) attached to a benzene ring.

The compound formed when an alcohol is attached to an aromatic ring is called a phenol. Phenols are a type of organic compound that contain a hydroxyl group (-OH) attached to an aromatic hydrocarbon group. The hydroxyl group in phenols is directly attached to the carbon atom of the aromatic ring, and this makes phenols distinct from alcohols, which have a hydroxyl group attached to an alkyl group.

Phenols can be prepared by a variety of methods, including the reaction of an aryl halide with a metal hydroxide, such as sodium hydroxide (NaOH), or the reaction of an arene oxide with a proton source, such as an acid. One common method for preparing phenols is called the Dowd-Beckwith reaction, which involves the oxidation of an aromatic hydrocarbon using a peroxyacid, such as m-chloroperoxybenzoic acid (MCPBA).

Phenols have a wide range of applications in industry and in organic chemistry. They are used as disinfectants and antiseptics, as well as in the production of plastics, resins, and other chemicals. Phenols are also used in the synthesis of pharmaceuticals, dyes, and flavors.

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We need to mix 0.7 liters of ethanol with 0.3 liters of water to make a total of 1 liter of solution.

We need to dilute the stock solution by adding a certain amount of water.

Using formula:

Volume of ethanol = (desired concentration/stock concentration) x total volume of solution

Desired concentration is 70%, the stock concentration is 100%, and the total volume of solution can be any desired amount.

For example, to make 1 liter of 70% ethanol solution:

Volume of ethanol = (70 / 100) x 1 liter = 0.7 liters of ethanol

The remaining volume of the solution will be filled with water, which is:

Volume of water = 1 liter - 0.7 liters = 0.3 liters of water

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The amide produced from pentanoic acid and ammonia is pentanamide. To form this amide, pentanoic acid reacts with ammonia in a process called amidation.

Here's a step-by-step explanation:

1. Pentanoic acid (C4H9COOH) has a carboxyl group (-COOH) at one end.

2. Ammonia (NH3) has a lone pair of electrons on the nitrogen atom, making it a nucleophile.

3. The nitrogen atom in ammonia attacks the carbonyl carbon atom in pentanoic acid, forming a tetrahedral intermediate.

4. The intermediate collapses, expelling a hydroxyl group (-OH) from the carboxyl group and forming a new bond between the nitrogen and carbonyl carbon atoms.

5. The product is pentanamide (C4H9CONH2), an amide formed from pentanoic acid and ammonia.

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The partial pressure exerted by the neon gas is 1.6 atm.

1. Determine the total moles of gas present in the system.
Total moles = moles of CO2 + moles of Ar + moles of N2 + moles of Ne
Total moles = 7.0 + 7.0 + 7.0 + 4.0 = 25.0 moles

2. Calculate the mole fraction of Ne.
Mole fraction of Ne = moles of Ne / total moles
Mole fraction of Ne = 4.0 / 25.0 = 0.16

3. Determine the partial pressure of Ne.
Partial pressure of Ne = mole fraction of Ne × total pressure
Partial pressure of Ne = 0.16 × 10.0 atm = 1.6 atm

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To find the pH of the orange juice with a hydronium concentration of [tex]1.78 * 10^{-3}[/tex] M at 25°C, follow these steps:

1. Recall the pH formula: [tex]pH = -log10[H+][/tex], where [H+] represents the hydronium concentration.
2. Substitute the given hydronium concentration into the formula: [tex]pH = -log10(1.78 × 10^{-3} )[/tex]
3. Calculate the pH using a calculator or logarithm table.

The calculated pH is approximately 2.75. Therefore, the correct answer is:
C) 2.75

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A swimmer is moving at a speed of 2.0 meters/second, it will take the swimmer 50 seconds to go 100 meters. So, correct answer is: 50 seconds.

Speed is a measure of how fast an object is moving and can be defined as the distance traveled per unit of time. Standard unit of speed is meters per second (m/s) in International System of Units (SI).

To solve this, we can use the formula time = distance/speed.
In this case, the distance is 100 meters and the speed is 2.0 meters/second.

Step 1: Plug in the values into the formula: time = 100 meters / 2.0 meters/second
Step 2: Calculate the time: time = 50 seconds

So, it will take the swimmer 50 seconds to go 100 meters.

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The liquefaction of noble gases is possible due to the presence of Van der Waals forces, specifically London dispersion forces, which become more significant as the noble gases are cooled and compressed.

The forces that make the liquefaction of noble gases possible are:

1. Van der Waals forces: These are weak intermolecular forces that arise from temporary fluctuations in electron distribution, resulting in temporary dipoles. Noble gases have low boiling points due to their weak intermolecular forces, and by cooling and compressing them, these forces become significant enough to cause the gases to condense into a liquid.

2. London dispersion forces: These are a specific type of Van der Waals forces that exist between all molecules, including noble gases. They result from the temporary dipoles induced by the movement of electrons around the atoms. As noble gases are cooled and compressed, these forces become more pronounced, leading to their liquefaction.

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The international association of artists you're referring to is known as CoBrA, which was active in the mid-20th century.

The group's name was derived from the first letters of the cities Copenhagen, Brussels, and Amsterdam. Coincidentally, this name also refers to a specific type of venomous reptile, the cobra. CoBrA artists focused on organic experimentation and free expression of the unconscious in their art.

Following World War II, the pioneering artists that made up the CoBrA international art movement revolutionized modern art. It was the first really global avant-garde art movement to emerge after World War II. Its participants looked for fresh ways to express themselves that were based on spontaneity and experimentation for modern society.

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The Algol binary star system consists of a 3.7 solar mass main sequence star and a 0.8 solar mass red giant due to their different rates of evolution.

The reason for this is that the Algol system is a binary star system, which means that it consists of two stars that orbit around their common center of mass. The main sequence star in the Algol system has a mass of 3.7 solar masses, which is significantly larger than the 0.8 solar mass red giant. The more massive star evolved faster and exhausted its hydrogen fuel, leading to the end of its main-sequence lifetime, while the less massive star is still in the process of fusing hydrogen in its core.

The more massive star evolved into a red giant, while the less massive star is still on the main sequence. The difference in the stars' mass and evolution led to the current configuration of the Algol system.

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(a.) Higher temperatures give a faster rate of reaction. We've seen before that when reactions are carried out at a higher temperature, they have a faster rate of reaction. In the Haber process, a higher temperature would allow the reaction to occur more quickly.

(b)  If the pressure is increased, the equilibrium position moves to the right, so the yield of ammonia increases. The rate of reaction also increases because the gas molecules are closer together, so successful collisions are more frequent.