Calculate the pH of a solution formed by mixing 250.0 mL of 0.15 M NH 4Cl with 200.0 mL of 0.12 M NH 3. The K b for NH 3 is 1.8 × 10 -5.
4.74
9.26
9.45
4.55
9.06

HBr and KCH3COOH would generate a salt derived from a weak acid and a weak base.

Salt is a mineral composed primarily of sodium chloride (NaCl), a chemical compound belonging to the larger class of salts; salt in its natural form as a crystalline mineral is known as rock salt or halite. Salt is present in vast quantities in seawater, where it is the main mineral constituent. Salt is essential for life in general, and saltiness is one of the basic human tastes. The tissues of animals contain larger quantities of salt than do plant tissues. Salt is one of the oldest and most ubiquitous food seasonings, and salting is an important method of food preservation.

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NaCl > NaBr > NaF The higher the charge and size of the ions that make up an ionic compound, the higher the melting point.

Electrostatic forces are forces of attraction or repulsion that act between objects that have static electric charges. These forces are created when electrons are either transferred or shared between two objects. Electrostatic forces can be very strong, even though the charges involved are typically very small.

NaCl has the highest charge and size, so it will have the highest melting point. NaBr has a slightly lower charge and size than NaCl, so it will have a lower melting point. Finally, NaF has the lowest charge and size of the three, so it will have the lowest melting point.

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To make a 0.197 m nitric acid solution from a stock solution of 6.00 m nitric acid, you need to dilute the stock solution with water. The amount of concentrated acid needed can be calculated using the formula: C1V1 = C2V2

where C1 is the initial concentration of the stock solution, V1 is the volume of the stock solution needed, C2 is the final concentration of the dilute solution, and V2 is the total volume of the dilute solution.

In this case, we can plug in the values we have:

C1 = 6.00 m
C2 = 0.197 m
V2 = 75.0 ml

Solving for V1, we get:

V1 = (C2V2) / C1
V1 = (0.197 m * 75.0 ml) / 6.00 m
V1 = 2.47 ml

Therefore, you need to add 2.47 ml of concentrated nitric acid to 72.53 ml of water to obtain a total volume of 75.0 ml of the dilute solution.

To make a 0.197 M nitric acid solution with a total volume of 75.0 mL from a 6.00 M stock solution, you can use the dilution equation:

M1V1 = M2V2

Where M1 is the initial molarity (6.00 M), V1 is the volume of concentrated acid needed, M2 is the final molarity (0.197 M), and V2 is the final volume (75.0 mL). To find the volume of concentrated acid needed (V1), rearrange the equation:

V1 = (M2V2) / M1

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The pH of a 0.308 M ascorbic acid solution is 3.35, which is closest to option d) 3.425.

To calculate the pH of a 0.308 M ascorbic acid solution, we need to determine the concentration of H+ ions in solution.

First, we need to determine which acid dissociation constant (Ka) to use. Ascorbic acid has two ionizable hydrogens, so we need to use Ka1 and Ka2 to determine the concentration of H+ ions.

Ka1 = 7.9 x 10^-5
Ka2 = 1.6 x 10^-12

We can use the following equation to calculate the concentration of H+ ions:

Ka = [H+][A-]/[HA]

Where [H+] is the concentration of H+ ions, [A-] is the concentration of the conjugate base, and [HA] is the concentration of the acid.

For the first dissociation, we have:

7.9 x 10^-5 = [H+][C6H6O6^-]/[H2C6H6O6]

We know the concentration of ascorbic acid is 0.308 M, so we can substitute:

7.9 x 10^-5 = [H+][C6H6O6^-]/0.308

Solving for [H+]:

[H+] = (7.9 x 10^-5)(0.308)/[C6H6O6^-]

Now, we need to determine the concentration of C6H6O6^-. We can assume that all of the ascorbic acid dissociates into H+ and C6H6O6^-.

So, [C6H6O6^-] = [H+]

Substituting into the previous equation:

[H+] = (7.9 x 10^-5)(0.308)/[H+]

Simplifying:

[H+]^2 = (7.9 x 10^-5)(0.308)

[H+] = 0.000450 M

Now, we need to determine the pH of the solution:

pH = -log[H+]

pH = -log(0.000450)

pH = 3.35

Therefore, the pH of a 0.308 M ascorbic acid solution is 3.35, which is closest to option d) 3.425.

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1680 kJ energy is required to decompose 765 g of PCl3, according to 4PCl3(g) → P4(s) + 6Cl2(g) ΔH = 1207 kJ

The molar mass of PCl3 is 137.33 g/mol, so 765 g corresponds to:

n = m/M = 765 g / 137.33 g/mol = 5.572 mol PCl3

According to the balanced equation, 4 moles of PCl3 decompose to release 1207 kJ of energy. Therefore, the amount of energy required to decompose 5.572 mol of PCl3 is:

(5.572 mol PCl3) x (1207 kJ / 4 mol PCl3) = 1682.2 kJ

Rounding to three significant figures, the answer is 1680 kJ (option a).

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15.2 g of KCl are produced when 25.0 g of KClO₃ decompose.

The balanced chemical equation is:

2KClO₃ → 2KCl + 3O₂

The molar mass of KClO₃ is 122.55 g/mol, and the molar mass of KCl is 74.55 g/mol.

To find the amount of KCl produced, we need to first determine the number of moles of KClO₃ decomposed.

Number of moles of KClO₃ = mass / molar mass = 25.0 g / 122.55 g/mol = 0.204 moles

From the balanced chemical equation, 2 moles of KClO₃ produce 2 moles of KCl.

Therefore, 0.204 moles of KClO₃ produce (2/2) × 0.204 moles of KCl = 0.204 moles of KCl.

The mass of KCl produced is given by:

Mass of KCl = number of moles × molar mass = 0.204 moles × 74.55 g/mol = 15.2 g

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The effect that co2 has on the atmosphere is CO2, or carbon dioxide, is a greenhouse gas that contributes to the warming of the Earth's atmosphere. This increase in temperature can cause a range of negative impacts.

CO2, or carbon dioxide, is a greenhouse gas that contributes to the warming of the Earth's atmosphere. When there is an increase in CO2 in the atmosphere, it can trap more heat, leading to a rise in global temperatures. This increase in temperature can cause a range of negative impacts, such as melting ice caps, rising sea levels, and more extreme weather events. This is why an increase in CO2 in the atmosphere is a cause for concern. It is important to reduce our emissions of CO2 and other greenhouse gases to mitigate the impacts of climate change.

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The mole fraction of gas b is 0.33, the total pressure in kPa is 76 kPa, and the partial pressure of gas c is 17.3 kPa.

To find the mole fraction of gas b, we first need to calculate the total number of moles of all gases present in the mixture. From the diagram, we can see that the total number of moles is 2 + 3 + 4 = 9 moles. To find the mole fraction of gas b, we divide the number of moles of gas b by the total number of moles:

Mole fraction of gas b = Number of moles of gas b / Total number of moles
Mole fraction of gas b = 3 / 9
Mole fraction of gas b = 0.33 (rounded to two decimal places)

To find the total pressure in kPa, we add up the partial pressures of all gases:

Total pressure = Partial pressure of gas a + Partial pressure of gas b + Partial pressure of gas c
Total pressure = 12.4 kPa + 46.3 kPa + 17.3 kPa
Total pressure = 76 kPa

Finally, to find the partial pressure of gas c, we simply look at the diagram and see that it is 17.3 kPa.

Therefore, the mole fraction of gas b is 0.33, the total pressure in kPa is 76 kPa, and the partial pressure of gas c is 17.3 kPa.

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The gas that would behave most ideally among Ne, N2, Xe, and CH4 at the same temperature and pressure is Neon.

This is because Ne is a noble gas with the least intermolecular forces and minimal electron interactions, which are key factors for a gas to exhibit ideal behavior.

The ideal gas law states that at the same temperature and pressure, all gases should behave similarly. However, in reality, most gases deviate from ideal behavior to some extent. This is because ideal gas behavior assumes that there are no intermolecular forces between gas molecules, which is not the case in real gases.

Noble gases, such as neon and argon, have a completely filled valence shell and are therefore considered to be non-polar. This means that they have weaker intermolecular forces than other gases, such as CH4 or N2, which are polar. Therefore, noble gases are more likely to behave ideally than other gases under the same conditions.

In summary, while all gases should behave similarly at the same temperature and pressure according to the ideal gas law, noble gases like neon and argon would behave most ideally due to their weaker intermolecular forces.

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The carbon dioxide (CO2) can stimulate ventilation by binding both peripheral and central chemoreceptors. When CO2 levels rise in the body, it can cross the blood-brain barrier and stimulate the central chemoreceptors located in the brainstem, as well as the peripheral chemoreceptors located in the carotid bodies.

This results in an increase in ventilation, as the body attempts to eliminate excess CO2 and maintain normal pH levels in the blood.
Peripheral chemoreceptors are located in the carotid and aortic bodies, which are sensitive to changes in arterial blood gases.

They are responsible for detecting changes in oxygen (O2), CO2, and pH levels in the blood. Central chemoreceptors, on the other hand, are located in the brainstem and are mainly responsive to changes in CO2 levels.

When CO2 levels increase in the body, it can stimulate both peripheral and central chemoreceptors, leading to an increase in ventilation.
CO2 is a chemical that can stimulate ventilation by binding both peripheral and central chemoreceptors. This mechanism helps the body maintain normal pH levels in the blood and prevent respiratory acidosis.

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So, the partial pressure of gas B is 1.18 atm.

To find the partial pressure of gas B, we will use Dalton's Law of Partial Pressures. The formula is:
Total pressure = Pressure of gas A + Pressure of gas B
We are given the total pressure (1.88 atm) and the pressure of gas A (0.70 atm). Now, we can solve for the pressure of gas B:
1.88 atm (total pressure) = 0.70 atm (pressure of gas A) + Pressure of gas B
Step 1: Subtract the pressure of gas A from both sides of the equation:
1.88 atm - 0.70 atm = Pressure of gas B
Step 2: Calculate the pressure of gas B:
1.18 atm = Pressure of gas B
So, the partial pressure of gas B is 1.18 atm.

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The correct answer is (b) NH3(g) → 1/2N2(g) + 3/2H2(g). The heat of reaction for this equation is equal to the average bond energy for the N-H bond in NH3.

The heat of reaction (ΔH) for a chemical reaction is the difference in enthalpy between the products and reactants. In the case of a reaction involving the breaking of a bond, the ΔH can be related to the bond energy of that bond. The average bond energy for the N-H bond in NH3 is approximately 391 kJ/mol.

In equation (b), one N-H bond is broken in NH3 to form 1/2 N2 and 3/2 H2. The ΔH for this reaction is equal to the bond energy of the N-H bond, which is 391 kJ/mol. Therefore, the correct answer is (b).

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Before the reaction, boron is using sp² hybrid orbitals, with a tetrahedral geometry. Nitrogen is using sp³ hybrid orbitals as well, with a tetrahedral geometry.

Nitrogen is a colorless, odorless, and tasteless gas that makes up 78.09% of the Earth's atmosphere. It is an essential element in all living organisms, as it is involved in the production of proteins, DNA and RNA. Nitrogen is found in the form of ammonia and nitrates and is used in the production of fertilizers, explosives, and other nitrogen-based compounds. It is also used in the manufacture of steel and other industrial products.

Before the reaction, Boron (B) is using three sp² hybrid orbitals, and Nitrogen (N) is using three sp³ hybrid orbitals. The geometry of Boron is trigonal planar and the geometry of Nitrogen is tetrahedral.

After the reaction, Boron (B) is still using three sp² hybrid orbitals, and Nitrogen (N) is now using three sp³d hybrid orbitals. The geometry of Boron is still trigonal planar, and the geometry of Nitrogen has changed to trigonal pyramidal.

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The mass of the water will be produced when the amount reacts with the LiOH is 360 g.

The chemical reaction in between the CO₂ and the LiOH is expressed as the chemical equation is as :

2LiOH + CO₂  --->  Li₂CO₃  +  H₂O

The moles of the CO₂ = 20 mol

The 1 mol of the CO₂ will produce the 1 mol of the  H₂O

The molar ratio are 1 : 1

The moles of the  H₂O = 20 mol

The mass of the  H₂O = moles × molar mass

The mass of the H₂O = 20 × 18

The mass of the  H₂O = 360 g

The mass of the water that is  H₂O is the 360 g.

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The balanced equation for the reaction is:

2Sr(s) + O2(g) → 2SrO(s)

The molar mass of Sr is 87.62 g/mol.

The given amount of Sr is 15.4 g.

We can use the stoichiometry of the balanced equation to find the number of moles of SrO that will be produced when 15.4 g of Sr is completely consumed. According to the balanced equation, 2 moles of Sr produces 2 moles of SrO. Therefore, 1 mole of Sr produces 1 mole of SrO.

Moles of Sr = mass/molar mass = 15.4 g/87.62 g/mol = 0.1759 mol

From the stoichiometry of the balanced equation, we can see that 1 mole of Sr produces 1 mole of SrO. Therefore, 0.1759 moles of Sr will produce 0.1759 moles of SrO.

The molar mass of SrO is 103.62 g/mol. Therefore, the mass of SrO produced is:

mass of SrO = moles of SrO × molar mass of SrO

mass of SrO = 0.1759 mol × 103.62 g/mol

mass of SrO = 18.2 g

Therefore, 18.2 g of SrO will be produced when 15.4 g of Sr is completely consumed.

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The number of moles of iron (III) sulfide are produced from the reaction of 449 grams of iron (III) bromide is 0.76 moles

Mass of FeBr₃ = 449g

Molar mass of FeBr₃ = 56 + (80x3) = 296g/mol

Mole of FeBr₃ =?

Mole = Mass /Molar Mass

Mole of FeBr₃ = 449/296

Mole of FeBr₃ = 1.52 moles

Step 2:

  The balanced equation for the reaction.

              2FeBr₃ + 3Na₂S —> 6 NaBr + Fe₂S₃

Step 3: Assurance of the quantity of mole of Fe2S3 created from the response of 449g ( i.e 1.52 moles) of FeBr3. The following illustrates this:

2 moles of FeBr₃ reacted to produce 1 mole of Fe₂S₃.

1.52 moles of FeBr₃  = (1.52 x 1)/2 = 0.76 mole of Fe₂S₃.

0.76 mole of Fe₂S₃ is produced from the reaction.

The International System of Units' substance quantity unit is the mole. A measure of the number of elementary entities present in an object or sample is the quantity amount of substance.

Any chemistry calculation based on experimental results relies heavily on the mole idea. The mole is the way we relate the tiny iotas and particles that make something up to the quantifiable properties, for example, mass which we might see in a lab setting

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Diamines are bifunctional molecules that contain two amino (-NH₂) groups. They are commonly used in the synthesis of nylons, which are a type of synthetic polymer that has good mechanical strength, chemical resistance, and elasticity.

The diamine molecules react with dicarboxylic acid molecules to form polyamide chains, which then form the backbone of the nylon polymer. Dialcohols are bifunctional molecules that contain two hydroxyls (-OH) groups. They are used in the synthesis of polyesters, which are a type of synthetic polymer that has good mechanical strength, chemical resistance, and heat resistance. The dialcohol molecules react with dicarboxylic acid molecules to form polyester chains, which then form the backbone of the polyester polymer.

Diamine: used in the synthesis of nylons

Dialcohol: used in the synthesis of polyesters

Dinitro: neither

Diether: neither

Diacid: used in the synthesis of polyesters and nylons

Diester: used in the synthesis of polyesters

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There is a trend in the products of reactions as you go from left to right across a period. Generally, the trend is that the products become more acidic as you move from left to right.

This is due to the increasing electronegativity of the elements, which causes them to form more polar covalent bonds with oxygen.
For example, when metals react with oxygen to form metal oxides, the products become more acidic as you move from left to right. Sodium oxide (Na2O) and magnesium oxide (MgO) are basic, while aluminum oxide (Al2O3) is amphoteric (meaning it can act as both an acid and a base) and silicon dioxide (SiO2) is acidic.
The trend in the products of reactions as you go from left to right across a period is that they become more acidic due to increasing electronegativity of the elements. This is demonstrated by the metal oxide reaction producing an acidic solution as you move from left to right.

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The molecular structure of [tex]BrF_6^+[/tex] is octahedral. [tex]BrF_6^+[/tex]  is a cationic compound that is formed by the combination of a bromine atom and six fluorine atoms. Option C .

The Br atom has seven valence electrons, and each F atom has seven valence electrons. Therefore, the total number of valence electrons in the [tex]BrF_6^+[/tex] ion is 42.

To determine the molecular structure of the ion, we need to first draw its Lewis structure, which shows the arrangement of the atoms and the bonding electrons. In the Lewis structure of [tex]BrF_6^+[/tex], the Br atom is surrounded by six F atoms, and each F atom is bonded to the Br atom via a single covalent bond. The Br atom also has a positive charge, indicating that it has lost one electron.

The octahedral molecular structure of [tex]BrF_6^+[/tex] arises from the fact that there are six bonding pairs of electrons and no lone pairs of electrons around the Br atom. The six F atoms are arranged symmetrically around the Br atom, forming an octahedral shape. Therefore, the correct answer is C, octahedral.

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18 s of current to be allowed to run to deposit this much silver.

The number of moles of silver can be calculated as shown below.

40 mg / (108 g/mol) = 0.3704 mmol

Since each silver ion carries one unit of charge, the total charge required can be calculated by multiplying the number of moles by the Faraday constant (F):

Q = 0.3704 mmol * (1 mol/equiv) * (96485 C/equiv) = 35.74 C

Now that we know the required charge, we can use the equation

Q = I*t to solve for the time required:

t = Q / I = 35.74 C / 2.0 A = 17.87 s.

Therefore, the correct answer is (b) 18 s.

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In an electroplating process, it is desired to deposit 40 mg of silver on a metal part by using a current of 2.0 A. How long must the current be allowed to run to deposit this much silver? (The silver ions are singly charged, and the atomic weight of silver is 108.)

Answers:

a) 16 s

b) 18 s

c) 20 s

d) 22 s

Xenon can be the central atom of a molecule by expanding beyond an octet of electrons

Define lectrons.

A negatively charged subatomic particle known as an electron can be free (not bound) or bound to an atom. One of the three main types of particles within an atom is an electron that is bonded to it; the other two are protons and neutrons. The nucleus of an atom is made up of electrons, protons, and neutrons together.

The valence shell electrons in a molecule are depicted in an extremely simplified manner by a Lewis Structure. It is used to demonstrate how the electrons in a molecule are positioned around particular atoms. Electrons are shown as "dots" or, in the case of a bond, as a line connecting the two atoms.

Lewis Structure of XeF2 is linear(in attachment)

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To calculate the concentration of the diluted solution, we can use the dilution formula C1V1 = C2V2 where C1 is the concentration of the stock solution, V1 is the volume of the stock solution used, C2 is the concentration of the diluted solution, and V2 is the final volume of the diluted solution.

Substituting the values given in the problem, we have (11.7 M)(25.0 mL) = C2(0.500 L) Simplifying this equation, C2 = (11.7 M)(25.0 mL) / (0.500 L) C2 = 585 M / L Therefore, the concentration of the diluted solution is 0.585 M (option b).

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The correct answer is -2430 kJ/mol rxn. To solve this problem, we need to use the balanced chemical equation and the molar mass of SiH4 to calculate the moles of SiH4 that reacted.

Then we can use the amount of heat given off to calculate the enthalpy change of the reaction.
First, we need to balance the chemical equation:
SiH4(g) + 2O2(g) → SiO2(s) + 2H2O(l)
Next, we need to calculate the moles of SiH4 that reacted:
moles of SiH4 = mass/molar mass = 80.3 g / 32.1 g/mol = 2.50 mol
Now we can use the amount of heat given off to calculate the enthalpy change of the reaction:
ΔH = q/n = -3790 kJ / 2.50 mol = -1516 kJ/mol

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To calculate the pH, the equation which represents an acid-base or a buffer solution is represented below is used.

pH = pKₐ + log([A⁻]/[HA])

One way to determine the pH of a buffer is by using the Henderson–Hasselbalch equation, which is

pH = pKₐ + log([A⁻]/[HA])

In the above equation, [HA] and [A⁻] refer to the equilibrium concentrations of the conjugate acid–base pair used to create the buffer solution. For the titration of a weak acid with a strong base, the pH curve is initially acidic and has a basic equivalence point (pH > 7). The section of curve between the initial point and the equivalence point is known as the buffer region.

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The salt that produces a basic solution when dissolved in water is NaF (sodium fluoride).

Here's a step-by-step explanation:

1. Identify the ions in the salt: NaF consists of Na+ (sodium ion) and F- (fluoride ion).
2. Determine the acidity or basicity of the ions:
  - Na+ is the cation of a strong base (NaOH, sodium hydroxide), so it does not affect the pH.
  - F- is the anion of a weak acid (HF, hydrofluoric acid), so it tends to accept a proton (H+) and increase the pH.
3. Combine the ions' effects: Since Na+ does not affect the pH and F- increases the pH, NaF dissolved in water will produce a basic solution.

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By using the information provided in the table and the amount of sugar packets added to 100 ml of solution, we can determine the concentration of sugar standards in g/100 ml.

To determine the concentration of the sugar standards in g/100 ml of solution, we can use the information provided in the table. The sugar standards are solutions with varying amounts of sugar dissolved in 100 ml of solution. The sugar concentration is expressed as g sugar/100 ml or % w/v.

According to the table, the first two sugar standards have been done for us. The first standard has 0 g sugar/100 ml, which means no sugar was added to the solution. The second standard has 3.5 g sugar/100 ml, which means one sugar packet was dissolved in the solution.

To determine the concentration of the third sugar standard, we need to know how many sugar packets were dissolved in 100 ml of solution. Since the second standard has 3.5 g sugar/100 ml, we can assume that one sugar packet was used. Therefore, to make the third standard, we need to add two sugar packets to 100 ml of solution, which gives us a concentration of 7 g sugar/100 ml.

Similarly, to determine the concentration of the fourth sugar standard, we need to add three sugar packets to 100 ml of solution, which gives us a concentration of 10.5 g sugar/100 ml.

Therefore, the concentrations of the sugar standards in g/100 ml of solution are:

- Standard 1: 0 g sugar/100 ml
- Standard 2: 3.5 g sugar/100 ml
- Standard 3: 7 g sugar/100 ml
- Standard 4: 10.5 g sugar/100 ml

In summary, by using the information provided in the table and the amount of sugar packets added to 100 ml of solution, we can determine the concentration of sugar standards in g/100 ml.

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The stickiness of eating an orange is due to the presence of natural sugars, specifically fructose, in the fruit. These sugars are hydrophilic, which means they are attracted to water molecules.

When water is applied to hands that have come in contact with an orange, the water molecules surround and dissolve the sugar molecules, making them easy to wash away .On the other hand, the greasiness of eating French fries is due to the presence of oils or fats, which are hydrophobic, meaning they repel water molecules. Because soap contains molecules that are both hydrophobic and hydrophilic, it can effectively break up and dissolve the oil and grease on hands when combined with water. The hydrophobic part of the soap molecule attaches to the grease, while the hydrophilic part attaches to the water, allowing the grease to be washed away.

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The anion present in the aqueous solution of [tex]Cu(C_2H_3O_2)_2[/tex] is [tex]C_2H_3O^{2-[/tex].

Anion is an atom or group of atoms that has gained one or more electrons, giving it a net negative charge. Anions are formed when an atom gains electrons due to an imbalance in the atom’s outermost electron shell. By gaining electrons, the atom becomes more stable and is able to bond with other atoms. These bonds form molecules and compounds.

This is because the compound [tex]Cu(C_2H3O_2)_2[/tex] is a salt composed of positively charged Cu²⁺ ions and negatively charged [tex]C_2H_3O^{2-[/tex] ions. Since the compound dissolves in water, the ions separate from each other and the [tex]C_2H_3O^{2-[/tex] anion remains in the aqueous solution.

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When the temperature of a strip of iron is increased, the length of the strip actually decreases. This phenomenon is known as thermal expansion, where the metal expands when heated and contracts when cooled.

The increase in temperature causes the atoms in the metal to vibrate more, increasing the distance between them and causing the metal to expand in all directions. This expansion is most noticeable in the length of the strip, as it is the longest dimension.

However, the width and thickness of the strip may also increase to a smaller extent. This effect is important to consider in various applications, such as building bridges and pipelines, where changes in temperature can affect the structure's integrity.
When the temperature of a strip of iron is increased, the length of the strip also increases. This occurs due to thermal expansion, a property of most materials, including iron. As the temperature rises, the atoms within the iron strip vibrate more vigorously and the overall dimensions of the strip expand. In this case, the length of the strip increases as the temperature increases. The width may also be affected, but the primary focus of your question is on the length. So, the correct option is that the length of the strip of iron also increases when its temperature is increased.

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The mole fraction of [tex]O_{2}[/tex] is 0.50 and its partial pressure is 0.70 atm.

D is the correct answer.

Partial Pressure can be calculated as:

= Total pressure × % of [tex]O_{2}[/tex]/100

= 1.40 = 50/100

= 0.70

The mole fraction is defined as the number of molecules of a specific component in a mixture divided by the total number of moles in the mixture. It's a way of indicating how concentrated a solution is.

By dividing the total number of moles of all the components of a solution by the number of moles of one component of a solution, the mole fraction can be computed. It should be noted that the mole fractions of all the components in the solution should add up to 1.

It is a measurement of concentration that is equal to the product of the moles of a component and the moles of the entire solution. Mole fraction is a unitless expression because it represents a ratio.

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