Answer:4.5
Step-by-step explanation:4.5
To win trivia game ,Nevan must score 90 points.each correct answers is worth 1 3/4 points, and each incorrect answer is worth "-1/4" points.if he gets 58 questions correct and 22 questions incorrect, does nevan win?how many points does he score?
Answer:
Yes, Nevin scored 96 points.
Step-by-step explanation:
[tex](58 \times 1.75) - (22 \times .25)[/tex]
[tex]101.5 - 5.5 = 96[/tex]
how do you do this question
As x and 68° are alternate interior angles, so, x = 68°.
We are given a set of parallel lines and a transversal.
We can see that:
The type of angle pairs is alternate interior angles.
( as it forms an inverted F-shape)
Now, these angles are 68° and x°.
So, we know that, the alternate interior angles are equal to each other.
So, we get that:
x = 68°
Therefore, as x and 68° are alternate interior angles, so, x = 68°.
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1. Chandra recorded her quarterly sales in a bargraph. Chandra will get a bors of $5.000her average quarterly sales for the year reach$70,000. What must her sales be for the fourthquarter in order for Chandra to earn the bonus?A $45,000B. $50,000C. 865,000D.60,000
Given:
Chandra get a bonus if average quarterly sales for an year exceeds $70000.
From the bar diagram, we can find the sales for each quarter.
The height of each bar gives the sales for each quarter.
Since the data in the vertical column is given in thousands of dollars, multiply the height of the bar by 1000 to get the correct sales value.
The sales for the first quarter is $40000.
The sales for the second quarter is $100000.
The sales for the third quarter is $80000.
Let x be the sales for the fourth quarter.
Now, the average of the quarterly sales is,
[tex]\begin{gathered} A=\frac{Sum\text{ of all quarterly sales}}{\text{Number of quarters}} \\ A=\frac{40000+100000+80000+x}{4} \end{gathered}[/tex]Put A=70000 and solve the equation for x to obtain the sales for the fourth quarter so that Chandra gets bonus.
[tex]\begin{gathered} 70000=\frac{220000+x}{4} \\ 70000\times4=22000+x \\ 280000-220000=x \\ 60000=x \end{gathered}[/tex]So, the sales of the fourth quarter must be $60000 in order for Chandra to earn the bonus.
Hence, option D is correct.
If AFGH - AQRS, m_F = x + 26, m R = 3x, and m Q = 5x - 12, find the value of x.
Explanation
Step 1
as the triangles are similar
[tex]\begin{gathered} \measuredangle F=\measuredangle Q \\ x+26=5x-12 \\ \end{gathered}[/tex]Step 2
solve for x
[tex]\begin{gathered} x+26=5x-12 \\ \text{subtract x in both sides} \\ x+26-x=5x-12-x \\ 26=4x-12 \\ \text{add 12 in both sides} \\ 26+12=4x-12+12 \\ 38=4x \\ \text{divide both sides by 4} \\ \frac{38}{4}=\frac{4x}{4} \\ 9.5=x \end{gathered}[/tex]so, the anwer
Solve for u: u^3u^-9. I need this without negative exponents.
EXPLANATION
Given the equation u^3u^9
In this case, we have a product of powers with the same base, so by the properties of the powers, we should add both exponents.
In this case, the adittion is as follows:
3 + (-9) = 3 - 9 = -6
So the power now has a negative exponent, so we need to reverse the fraction in order to get a positive exponent
[tex]u^{-6}[/tex]Reversing the expression:
[tex]\frac{1}{u^6}[/tex]o find the quotient of 8 divided by one-third, multiply 8 by
One-eighth.
One-third.
3.
8.
The quotient of 8 divided by one-third, multiply 8 by 3. Option C
What are fractions?Fractions are simply defined as part of a whole element, set or quantity.
The different types of fractions are;
Simple fractionsComplex fractionsProper fractionsImproper fractionsMixed fractionsExamples of simple fractions include; 1/2, 1/5
Examples of proper fractions include; 2/3 . 4/6
Examples of mixed fractions include; 2 1/4, 3 6/7
Examples of improper fractions include;5/4, 6/54
From the information given, we have;
8 ÷ 1/3
Take inverse of the divisor and multiply
8 × 3/1
24
Then, multiplying 8 by 3 is 24
Hence, the value is 3
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29. pls help need to answer this question
Answer:
x and y coefficients, are the same, equal, are
If 45.78 ÷ 1.7 is written in long division form as long division set up where 17 is on the outside of the division symbol and 45780 is on the inside so that the divisor is written as a whole number, where should the decimal point be placed in the dividend?
Answer:
the answer is 27.5
Step-by-step explanation:
the decimal point should be placed in the ones place...I think
Help me please giving brainlyest
Answer:
The answer is A
Step-by-step explanation:
y=-0.5x + 225
This is because every month 50 cents which can be written as 0.5 is taken off the account so it would be negative. Since X = the number of months, you would multiply it by 0.5, hence -0.5x. Since 225 is the orginial balance you would add that.
Please do mark Brainliest!
Find the tangent line to the following function at the given value. y = (3x^2 + x - 4)(2x^3+ 3x + 1) at x = 1
Answer:
The tangent line using limits/ derivatives is y=42x-42
Step-by-step explanation:
Answer:
f(x) = (3·x^2 + x - 4)·(2·x^3 + 3·x + 1)
f(x) = 3·x^2·2·x^3 + 3·x^2·3·x + 3·x^2·1 + x·2·x^3 + x·3·x + x·1 - 4·2·x^3 - 4·3·x - 4·1
f(x) = 6·x^5 + 9·x^3 + 3·x^2 + 2·x^4 + 3·x^2 + x - 8·x^3 - 12·x - 4
f(x) = 6·x^5 + 2·x^4 + x^3 + 6·x^2 - 11·x - 4
f'(x) = 30·x^4 + 8·x^3 + 3·x^2 + 12·x - 11
tangent at x = 1
f(1) = 6·1^5 + 2·1^4 + 1^3 + 6·1^2 - 11·1 - 4 = 0
f'(1) = 30·1^4 + 8·1^3 + 3·1^2 + 12·1 - 11 = 42
t(x) = f'(1)·(x - 1) + f(1)
t(x) = 42·(x - 1) + 0
t(x) = 42·x - 42 + 0
t(x) = 42·x - 42
The function f(x)=3^x is often referred to as a tripling function because f(x) triples whenever x changes by 1 But this is not the only example of a tripling function. Give two more distinct examples of tripling functions (functions whose values triple whenever the independent variable changes by 1).f(x)=3x^2g(x)= h(x)=
Answer:
Explanation:
Given the function, g(x) below:
[tex]g(x)=2(3^x)[/tex]We evaluate g(x) for x=1,2 and 3:
[tex]\begin{gathered} g(1)=2(3^1)=6 \\ g(2)=2(3^2)=18 \\ g(3)=2(3^3)=54 \end{gathered}[/tex]We see that whenever x increases by 1, the value of g(x) triples.
After a concert for a 1000 and 200 people only nine people said they would not go to see the band again. What percent of the people who went to the concert said they would not go to see the band again.
Answer:
Out of the 1,200 people who attended the concert in question, 0.75% would not see the band again.
Step-by-step explanation:
There were 1,200 people in total at the concert and out of these, 9 people said that they would not see the band again.
In percentage terms, this is expressed as:
= Number of people who would not see band again / Total number of people who attended x 100%
= 9 / 1,200 x 100%
= 0.75 %
In conclusion, 0.75% of people who attended would not see the band again.
so I have this problem in my workbook for math and it says to circle the whole numbers and explain my reasoning, here are the numbers : 9, 4/4, and 1.00000 which ones do I choose and what do I say
EXPLANATION.
The whole numbers are the same natural numbers that start from zero to infinity, they are positive and negative, for example in the number line we can see them from zero to positive infinity, and from zero to negative infinity.
Whole numbers express a complete unit, this means that they do not have an integer part and a decimal part.
Now according to what has already been mentioned, we can see in the exercise that the integers are 9 and 1.00000, which we must enclose in a circle.
C
Finding Angles Measures
61⁰
A
E
61°
B
D
LL
Find the following angle measures.
m/EAD=
m/CAB=
✓ Done
The measure of angle ∠EAD is 29° and ∠CAB is 119°.
What are angles?In Euclidean geometry, an angle is a shape created by two rays that share an endpoint and are referred to as the angle's sides and vertex, respectively. The plane that contains the rays contains the angles created by two rays.Depending on the measurement, there are various angles in geometry. Basic angles are identified by their names: acute, obtuse, right, straight, reflex, and full rotation.So, according to the image ∠CAF is 180°.
And, ∠CAF = ∠CAE + ∠EAD + ∠DAFObtain, ∠EAD as follows:
∠CAF = ∠CAE + ∠EAD + ∠DAF180 = 61 + ∠EAD + 90180 = 151 + ∠EAD180 - 151 = ∠EAD∠EAD = 29°Similarly, ∠CAF = ∠CAB + ∠BAF
Obtain, ∠CAB as follows:
∠CAF = ∠CAB + ∠BAF180 = ∠CAB + 61180 - 61 = ∠CAB∠CAB = 119°Therefore, the measure of angle ∠EAD is 29° and ∠CAB is 119°.
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The correct question is given below:
Find the following angle measures.
mEAD =
mCAB =
A city has a population of 350,000. The
population has decreased by 30% in the past
ten years. What was the population of the city
ten years ago?
Answer:
the population was 455,000
Step-by-step explanation:
350,000 × 0.3 = 105,000
105,000 + 350,000 = 455,000
Please answer all questions and show you Find the mean of each of the following data sets. 1,2,2,3,3,3,4,4,4 and 4
============================================================
Explanation:
Add up the values
1 + 2 + 2 + 3 + 3 + 3 + 4 + 4 + 4 + 4 = 30
Then divide by the sample size n = 10 since there are 10 items in this list
30/10 = 3
The mean is 3.
---------------
An example in real life
Imagine that the numbers given represent the number of cookies that 10 people have. Person A has 1 cookie, person B has 2 cookies, person C has 2 cookies, person D has 3 cookies, and so on.
Adding up all the cookies gets us 30 total. Imagine all the cookies are placed on a plate somewhere.
To split the cookies evenly among the 10 people, we divide by 10 to get 30/10 = 3. This means each person gets 3 cookies, which is exactly the arithmetic mean.
a hunter is practicing his aim using a practice target. he takes 5 shots. all 5 shots hit the target, but they do not hit or surround the bullseye. in addition, all 5 shots are very spread apart on the target. classify the hunter's accuracy and precision.
The answer is low accuracy and low precision.
Given:
A hunter is practicing his aim using a practice target. he takes 5 shots. all 5 shots hit the target, but they do not hit or surround the bullseye. in addition, all 5 shots are very spread apart on the target.
From the given statements :
All 5 shots hit the target, but they do not hit or surround the bullseye here no shots hit or surround the bullseye means there is no closeness to true value,Hence low accuracy.
All 5 shots are very spread apart on the target here all shots are very spread apart means there is no closeness between the shots,Hence low precision.
Therefore the answer is low accuracy and low precision.
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janis is 3 years older than her sister. thirty years from now the sum of their ages will be 111. find the current ages of the sisters.
The current ages of the sisters are:
Janis = 27 years oldJanis's sister = 24 years oldInformation about the problem:
Janis = Sister + 3(30+Janis) + (30+Sister) = 111Janis = JSister = STo solve this problem we must establish the equations according to the given data and solve the operations:
J = S + 3 (1)
(30+J) + (30+S) = 111 (2)
We have two equations with two unknowns, substituting the value (J) in the second equation, we have:
30+J+30+S = 111
60 + J + S = 111
J+S = 111-60
J+S = 51
(S+3) + S = 51
2S + 3 = 51
2S = 51-3
2S = 48
S = 48/2
S = 24
Substituting (S) into one of the equations (J) we have:
J = S + 3
J = 24+3
J = 27
What is an equation?An equation is the equality between two algebraic expressions, which have at least one unknown or variable.
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Natasha and Jorge were asked to find the quotient to the decimal division problem 18.8÷1.6. Natasha says her answer is 11.75. Jorge says his answer is 1.175.
a. Who is correct? Natasha or Jorge?
b. Explain how you know who is correct. Include in your explanation at least one possible error the student who was incorrect made. Giving 90 points away
a. Natasha says her answer is 11.75. Therefore, she is correct.
b. The possible error that was made was that Jorge shifted the decimal backward.
How to illustrate the information?A quotient is a quantity created by the division of two numbers in mathematics. The quotient is widely used in mathematics and is also known as the integer component of a division, a fraction, or a ratio. A decimal is a number with a whole and a fractional part. Decimal numbers are between integers and represent a numerical value for a whole plus some fraction of a whole.
From the information, it should be noted that Natasha and Jorge were asked to find the quotient to the decimal division problem 18.8÷1.6.
a. It should be noted that the division of the decimals will be:
= 18.8 ÷ 1.6
= 11.75
This can easily be done with a calculator.
b. One can easily know who is correct through the use of a calculator or mentally. The fact that Jorge got 1.175 is incorrect.
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given t : v ---- w as in exercise 47, and given a subspace z of w , jet u be the set of all x in v such that t (x) is in z . show that u is a subspace of v
The proof that "u" is a subspace of "v" is given below.
Suppose that t:v->w is a linear transformation where "v" and "w" are vector spaces.
Let "z" be the subspace of "w".
Since "t" is a linear transformation, the zero vector of "w" is in "z".
Let x, y ∈ U.
Then t(x), t(y) ∈ z.
Since, "z" is a subspace of "w".
So, "z" is closed under vector addition.
Thus, t(x) + t(y) ∈ z.
Now, t(x) + t(y) = t(x + y), since, t is a linear transformation.
Therefore, t(x + y) ∈ z.
Thus, x + y ∈ u.
Therefore, "u" is closed under vector addition.
Hence proved.
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2. Calculate the height of a triangle with base length 5,2 cm and area equal to 26,58 cm². (Round off the answer to 2 decimal places.)
[tex]\textit{area of a triangle}\\\\ A=\cfrac{1}{2}bh ~~ \begin{cases} b=base\\ h=height\\[-0.5em] \hrulefill\\ b=5.2\\ A=26.58 \end{cases}\implies 26.58=\cfrac{1}{2}(5.2)h \\\\\\ 26.58=2.6h\implies \cfrac{26.58}{2.6}=h\implies 10.22\approx h[/tex]
helpppppppppppppppppppppppppppppppppppppppppppppp
I need help finding surface area of a figure
The surface area will be the surface area of the rectangular prism, plus the surface area of the triangular prism, minus the area of the base of the triangular prism, so:
For the rectangular prism:
[tex]\begin{gathered} SA_{rp}=2(lw+lh+wh) \\ where \\ l=length=4ft \\ w=width=16ft \\ h=height=6ft \\ SA_{rp}=2(4\cdot16+4\cdot6+16\cdot6) \\ SA_{rp}=2(184) \\ SA_{rp}=368ft^2 \end{gathered}[/tex]For the triangular prism:
[tex]\begin{gathered} SA_{tp}=2ls+bh+lb \\ where \\ l=length=4ft \\ h=height=9ft \\ b=base=12ft \\ s=side=11ft \\ SA_{tp}=2\cdot4\cdot11+12\cdot9+4\cdot12 \\ SA_{tp}=244ft^2 \end{gathered}[/tex]The area of the base of the triangular prism is:
[tex]A=12\cdot4=48ft^2[/tex]Therefore:
[tex]\begin{gathered} SA=SA_{rp}+SA_{tp}-A \\ SA=368ft^2+244ft^2-48ft^2 \\ SA=564ft^2 \end{gathered}[/tex]Enter the letters of the points that are on the graph of $y = 6$.
Answer: E
Step-by-step explanation: On the y axis go 6 spaces up and E will be 6 spaces to the right.
how to find scale with area
Answer:
hope this helped
Step-by-step explanation:
Multiply the height of Rectangle by the scale factor. This will give you the height of Rectangle
Multiply the width of Rectangle by the scale factor. This will give you the width of Rectangle
Multiply the height and width of Rectangle to find the area
find the area of this triangle and the values of x and y
First let's find the value of x using the Pythagorean theorem in the left small triangle:
[tex]\begin{gathered} 14^2=6^2+x^2 \\ 196=36+x^2 \\ x^2=196-36 \\ x^2=160 \\ x=\sqrt[]{160}=4\sqrt[]{10}=12.65 \end{gathered}[/tex]Now, finding the value of y with the Pythagorean theorem in the right small triangle, we have:
[tex]\begin{gathered} 16^2=x^2+y^2 \\ 256=160+y^2 \\ y^2=256-160 \\ y^2=96 \\ y=\sqrt[]{96}=4\sqrt[]{6}=9.8 \end{gathered}[/tex]The area of the triangle is calculated with the formula:
[tex]\text{area}=\frac{b\cdot h}{2}[/tex]Where b is the base and h is the height relative to this base. Using b = 6 + y and h = x, we have:
[tex]\begin{gathered} \text{area}=\frac{(6+y)x}{2} \\ \text{area}=\frac{(6+4\sqrt[]{6})4\sqrt[]{10}}{2} \\ \text{area}=(6+4\sqrt[]{6})2\sqrt[]{10} \\ \text{area}=12\sqrt[]{10}+8\sqrt[]{60} \\ \text{area}=12\sqrt[]{10}+16\sqrt[]{15} \\ \text{area}=12\cdot3.162+16\cdot3.873 \\ \text{area}=99.912 \end{gathered}[/tex]Need help
show your solution
1) [tex]2^{5+3}[/tex] = [tex]2^{8}[/tex] (By Product rule of exponents [tex]a^{m} *a^{n} = a^{m+n}[/tex])
2) [tex]m^{5+7}[/tex] = [tex]m^{12}[/tex] (By Product rule of exponents [tex]a^{m} *a^{n} = a^{m+n}[/tex])
3) [tex]b^{4+2} = b^{6}[/tex] (By Product rule of exponents [tex]a^{m} *a^{n} = a^{m+n}[/tex])
4) [tex]x^{2+1}*y^{2} = x^{3}y^{2}[/tex] (By Product rule of exponents [tex]a^{m} *a^{n} = a^{m+n}[/tex])
5) [tex]x^{4+5}*y^{1+1} = x^{9}y^{2}[/tex] (By Product rule of exponents [tex]a^{m} *a^{n} = a^{m+n}[/tex])
6) [tex]2^{4 - 3} = 2^{1} = 2[/tex] ( By Quotient rule of exponents [tex]a^{m} /a^{n} = a^{m-n}[/tex])
7) [tex]c^{8 - 5} = c^{3}[/tex] ( By Quotient rule of exponents [tex]a^{m} /a^{n} = a^{m-n}[/tex])
8) [tex]x^{4 - 4} = x^{0} = 1[/tex] ( By Quotient rule of exponents [tex]a^{m} /a^{n} = a^{m-n}[/tex])
9) [tex]a^{2- 3} = a^{-1}[/tex] ( By Quotient rule of exponents [tex]a^{m} /a^{n} = a^{m-n}[/tex])
10) [tex]m^{5*10} = m^{50}[/tex] (Power of a power rule [tex](a^{m})^{n} = a^{m*n}[/tex])
11) [tex]5^{2*2} = 5^{4}[/tex] (Power of a power rule [tex](a^{m})^{n} = a^{m*n}[/tex])
12) [tex]\frac{x^{2*2} }{y^{3*2} } = \frac{x^{4} }{y^{6} }[/tex] (Power of a quotient rule [tex]( \frac{a}{b} )^{m} = \frac{a^{m} }{b^{m} }[/tex])
13) [tex]a^{1*3} b^{2*3} =a^{3} b^{6}[/tex] (Power of a power rule [tex](a^{m})^{n} = a^{m*n}[/tex])
14) [tex]c^{2*5} d^{3*5} =c^{10} d^{15}[/tex] (Power of a power rule [tex](a^{m})^{n} = a^{m*n}[/tex])
15) [tex](m^{2-2} )^{2} = (m^{0} )^{2} = 1^{2} =1[/tex] (Power of a quotient rule [tex]( \frac{a}{b} )^{m} = \frac{a^{m} }{b^{m} }[/tex] and Zero exponent rule [tex]a^{0} = 1[/tex])
16) [tex]\frac{y^{2*0} }{z^{7*0} } = \frac{y^{0} }{z^{0} } = 1[/tex] (Power of a quotient rule [tex]( \frac{a}{b} )^{m} = \frac{a^{m} }{b^{m} }[/tex] and Zero exponent rule [tex]a^{0} = 1[/tex])
17) [tex]\frac{1}{k^{2} }[/tex] ( Negative Exponent rule [tex]a^{-m} = \frac{1}{a^{m} }[/tex] )
18) [tex]g^{3*-2} h^{3*-2} = g^{-6} h^{-6} = \frac{1}{g^{6}h^{6} }[/tex] ( Negative Exponent rule [tex]a^{-m} = \frac{1}{a^{m} }[/tex] )
19) [tex]( x^{3-2} y^{3-2} )^{5} = (xy)^{5} =x^{5} y^{5}[/tex] (By Quotient rule of exponents [tex]a^{m} /a^{n} = a^{m-n}[/tex] )
20) [tex](m^{2-3} n^{2-2} )^{4} =(m^{-1}n^{0})^{4} = m^{-4} = \frac{1}{m^{4} }[/tex] (Power of a quotient rule [tex]( \frac{a}{b} )^{m} = \frac{a^{m} }{b^{m} }[/tex] and Zero exponent rule [tex]a^{0} = 1[/tex]) ( Negative Exponent rule [tex]a^{-m} = \frac{1}{a^{m} }[/tex] )
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17
Yolanda took a bus to visit her grandmother for a four-day visit.
a. At the bus station she waited for 2 of an hour until it was time to board the bus.
How many minutes did Yolanda wait to board the bus? Show or explain how you got your
answer.
Yolanda brought a CD to listen to on the bus.
The CD is 78 minutes long.
• The bus ride was 2½ hours long.
b. How many minutes longer was the bus ride than the CD? Show or explain how you got
your answer.
c. Yolanda wondered how many minutes are in 4 days. What is the total number of minutes
4 days? Show or explain how you got your answer.
(Not for me it’s for my friend that needs help.)
Answer:
72 minutes
Step-by-step explanation:
150
-78
72
Answer:
Step-by-step explanation:
1) 2hours??
2) 150-78=72mins
3)24x4=96
96x60=5760
determine if the statement below is always, sometimes, or never true. Justify your answer: 2(3+5x)=6+5x
Answer:
Never True
Step-by-step explanation:
The equation is not balanced.
for students who earned a score of 21 or higher on the quiz, the cumulative frequency is and the relative cumulative frequency is .
For students who earned a score of 21 or higher on the quiz
The cumulative frequency = 16
The relative frequency = 32%
The number of times a specific value appears in the data is its frequency (f). A variable's distribution is its frequency pattern, or the collection of all conceivable values and the frequencies corresponding to those values.
To get relative frequency, we will take this cumulative number and divide by the total number of students. number of 21 or more / total number of students = 16 / 50 = 0.32 or 32%.
The cumulative frequency of students who earned a score of 21 or higher on the quiz is =16.
Total frequency is = 4+8+15+7+7+3+4+2=50.
So the relative cumulative frequency is
= 16 / 50
= 0.32 or 32%.
Hence , the relative cumulative frequency when students who earned a score of 21 or more is 0.32.
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