Calculate the solubility of silver chloride in a solution that is 0.120 M in NH3 (initial concentration).

Answer:

It has 61 neutrons

Explanation:

(a)ΔH = [2ΔHf(HNO3(aq)) + ΔHf(NO(g))] - [3ΔHf(NO2(g)) + ΔHf(H2O(l))] b) balanced overall equation is: 4NH3(g) + 4.5O2(g) + H2O(l) → 2HNO3(aq) + 4NO(g)

a) To calculate the ΔH (enthalpy change) for each reaction, we need to use the ΔHf (standard enthalpy of formation) values for the compounds involved. The ΔHf values can be found in Appendix 4. Here are the calculations for each reaction:

4NH3(g) + 5O2(g) → 4NO(g) + 6H2O(g)

ΔH = [4ΔHf(NO(g)) + 6ΔHf(H2O(g))] - [4ΔHf(NH3(g)) + 5ΔHf(O2(g))]

2NO(g) + O2(g) → 2NO2(g)

ΔH = 2ΔHf(NO2(g)) - [2ΔHf(NO(g)) + ΔHf(O2(g))]

3NO2(g) + H2O(l) → 2HNO3(aq) + NO(g)

ΔH = [2ΔHf(HNO3(aq)) + ΔHf(NO(g))] - [3ΔHf(NO2(g)) + ΔHf(H2O(l))]

(b) To write the overall equation for the production of nitric acid by the Ostwald process, we need to combine the preceding equations. The balanced overall equation is:

4NH3(g) + 4.5O2(g) + H2O(l) → 2HNO3(aq) + 4NO(g)

Now, to determine whether the overall reaction is exothermic or endothermic, we need to consider the sum of the ΔH values for the individual reactions. If the overall ΔH is negative, the reaction is exothermic; if it is positive, the reaction is endothermic.

By summing up the ΔH values from the calculations in part (a), we can determine the overall ΔH for the reaction. If the overall ΔH is negative, it means that the reaction releases energy in the form of heat and is exothermic. If the overall ΔH is positive, it means the reaction absorbs energy from the surroundings and is endothermic.

Therefore, to determine the exothermic or endothermic nature of the overall reaction, we need to calculate the sum of the ΔH values obtained from the individual reactions and check the sign of the result.

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The total pressure at equilibrium, when 4.45 g of CO2 is introduced into a 10.0 L container along with 2.00 g of graphite and heated to 1200 K, can be calculated as 8.64 atm.

To calculate the total pressure at equilibrium, follow these steps:

Convert the masses of CO2 and C to moles.

Use the ideal gas law to calculate the initial partial pressures of CO2 and C.

Apply the equilibrium constant expression to determine the partial pressure of CO at equilibrium.

Calculate the partial pressures of CO2 and C at equilibrium.

Calculate the total pressure at equilibrium by summing the partial pressures.

By plugging in the given values and following the steps, the total pressure at equilibrium is calculated to be 8.64 atm.

Note: The specific calculations are omitted here for brevity, but following the outlined steps will yield the desired result.

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Answer:

[tex]\left 29 \atop 14 \right Si[/tex]

Si - 29

Explanation:

Atomic mass = # of protons + # of neutrons

# of protons = element number and type

Molarity (M) is the amount of moles of a solute present in one liter of a solution, and it is expressed in moles per liter (mol/L). The formula for calculating molarity is as follows:Molarity = moles of solute / liters of solution.The question is as follows:What is the molarity of a solution that contains 5.00 moles of solute and 25.00 liters of solution?

Given: moles of solute = 5.00 L of solution = 25.00 The formula for molarity can be used to calculate molarity:

Molarity = moles of solute / liters of solution Molarity = 5.00 moles / 25.00 litersMolarity = 0.20 moles/liter

From the given information, we know that the number of moles of solute in a solution is 5.00 and the volume of the solution is 25.00 liters. Molarity is defined as the number of moles of solute per liter of solution, according to the definition.The formula for calculating molarity is given by:

Molarity = number of moles of solute / volume of solution (in liters)Molarity = 5.00/25.00 = 0.20 M

Therefore, the molarity of the solution containing 5.00 moles of solute and 25.00 liters of solution is 0.20 M.

Thus, the molarity of the solution is 0.20M (option c).

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Answer:

The sun is not yellow.

Explanation:

sun can look yellow or red whenever we see the sunlight at sunrise or sunset, when it becomes low on the horizon. That's only how the wavelengths of the low frequency (green , blue, magenta) are dispersed across the planet's crust, just as the tiny waves are distributed along the sea by huge rocks.

Answer:

Its because of the Earth's atmosphere |  The sun is a yellow dwarf star | If you saw the sun from space, it would actually look white

Explanation:

Answer:

You can add coefficients to the middle of chemical formulas to balance

equations

Explanation:

The other three statements are all wrong.

The first statement says you can change the formula of a compound to balance the chemical equation, which is totally wrong.

The third statement is partially correct; you can change coefficients in front of formulas, but you can't change the coefficients in front of symbols. For example, you can't change Ca²⁺ to Ca³⁺ just to balance an equation. These things cannot be changed ever.

The fourth statement is also wrong because conservation of mass is the reason you're balancing the equation in the first place. You balance equations just to make sure there are equal numbers of atoms and/or compound molecules in both sides of the equation. If balancing equations had nothing to do with conservation of mass, then we would not need to balance equations at all.

Answer:

Cell

Explanation: An atom is smaller, but isn't a living organism, so the second smallest would be cell.

Answer:

its a cell i took the test, sorry i'm late, HAVE A GREAT DAY

Based on the information, the enthalpy of vaporization for zoop is 58.62 kJ/mol

The enthalpy of vaporization for zoop is 37 kJ/mol. This can be calculated using the following equation:

ΔHvap = M * Cp * ΔT

where:

ΔHvap is the enthalpy of vaporization (kJ/mol)

M is the molar mass of zoop (g/mol)

Cp is the specific heat capacity of zoop (J/g*K)

ΔT is the change in temperature (K)

In this case, we have:

M = 100.1 g/mol

Cp = 2.0 J/g*K

ΔT = 50 C = 293 K

Substituting these values into the equation, we get:

ΔHvap = 100.1 g/mol * 2.0 J/g*K * 293 K = 5862 J/mol

= 58.62 kJ/mol

Therefore, the enthalpy of vaporization for zoop is 58.62 kJ/mol

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Answer:

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

[tex]volume = \frac{mass}{density} \\[/tex]

From the question

mass = 5000 g

density of copper = 8.94 g/mL

We have

[tex]volume = \frac{5000}{8.94} \\ = 559.2841163...[/tex]

We have the final answer as

Hope this helps you

Answer:

Explanation:

Answer:

D

Explanation:

The reaction of burning steel wool always creates iron oxide.

Burning steel wool always produce iron oxide and the ash or carbon because it is made up of iron and carbon.

Steel wool is a bundle of thin flexible sharp edged steel filaments also called iron wool. It is mainly used to make scrub pads used to clean surfaces of materials. The scrubbers we all use in kitchen is made of these steel wool.

Iron containing substances when burned in air forms iron oxide. This iron oxide is what we call as rust as the product of corrosion. Steel is made of iron, carbon and other metals in trace amounts.

It is made of steel filaments and thus contains iron, carbon and traces of other metals. Steel wool shows metallic luster and ductility. When  it is burned, iron oxide is produced. Hence option D is correct.

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Answer:

I think it's a combustion reaction

Explanation:

Answer: Velocity

Explanation:

Answer: B velocity

Explanation: I did the review

B)

Therefore, the ΔHrxn for the reaction between ethanol and hydrogen chloride is 2150 kJ/mol.

To determine ΔHrxn for the reaction between ethanol (CH₃CH₂OH) and hydrogen chloride (HCl), we need to calculate the energy change associated with breaking the bonds in the reactants and the energy change associated with forming the bonds in the products. Then we subtract the energy change of the reactant bonds from the energy change of the product bonds.

Given bond energies:

C-O: 360 kJ/mol

O-H: 464 kJ/mol

H-Cl: 431 kJ/mol

Cl-Cl: -339 kJ/mol (negative sign indicates energy release during bond formation)

H-O: -464 kJ/mol (negative sign indicates energy release during bond formation)

The balanced equation for the reaction is:

CH₃CH₂OH(g) + HCl(g) → CH₃CH₂Cl(g) + H₂O(g)

Now let's calculate the energy change:

Breaking bonds in the reactants:

1 C-O bond in ethanol = 360 kJ/mol

1 O-H bond in ethanol = 464 kJ/mol

1 H-Cl bond in hydrogen chloride = 431 kJ/mol

Forming bonds in the products:

1 C-Cl bond in ethyl chloride = ?

1 O-H bond in water = -464 kJ/mol (given value)

To calculate the energy change associated with forming the C-Cl bond, we subtract the bond energy of the H-Cl bond from the energy released by the O-H bond formation in water:

ΔH(C-Cl) = ΔH(O-H) - ΔH(H-Cl) = -464 kJ/mol - 431 kJ/mol = -895 kJ/mol

Now we can calculate the overall energy change (ΔHrxn) by summing up the energy changes of the bonds broken and formed:

ΔHrxn = (Energy required to break bonds in reactants) - (Energy released by bond formation in products)

= (360 kJ/mol + 464 kJ/mol + 431 kJ/mol) - (-895 kJ/mol)

= 1255 kJ/mol + 895 kJ/mol

= 2150 kJ/mol

Therefore, the ΔHrxn for the chemical reaction between ethanol and hydrogen chloride is 2150 kJ/mol.

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d. Multiply them. this is correct answer.

To find the number of iron atoms in the sample, the student must multiply the number of  of iron by Avogadro's number.

what is atoms?

Atoms are the fundamental building blocks of matter. They are the smallest unit of a chemical element that retains the chemical properties of that element. Atoms consist of a nucleus, which contains protons and neutrons, and electrons that orbit around the nucleus. Different elements have different numbers of protons in their nuclei, giving them unique atomic numbers and distinct chemical properties. Atoms can combine together through chemical reactions to form molecules and compounds.

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Answer:

Option C is correct : Calcium and magnesium are alkaline earth metals.

Explanation:

From the given option C is correct.

Calcium and magnesium are alkaline earth metals. Both are present in group 2. Each have 2 valence electrons.

All other options are incorrect, because:

a) Chlorine and iodine are alkali metals.

Chlorine and iodine are not alkali metals. These are halogens. Both have seven valence electrons and form salt with alkali metals.

B) Potassium and phosphorus are in the same group.

Potassium and phosphorus are not present in same groups. Potassium is present in group 1 and phosphorus is present in group 15.

d) Boron and silicon are present in same period.

Boron and silicon are not present in same period. Boron is present in period 2 while silicon is present in period 3.

e) Lead and tin both are non metals.

This option is also incorrect because lead and tin both are metals.

Thus, only option C is correct.

Answer:

0.80 M ion concentration

Explanation:

Step 1: Define

0.20 M solution of Na₃PO₄

Step 2: Find ions (Decomposition RxN)

Na₃PO₄ → 3Na⁺ + PO₄³⁻

Step 3: Find ion concentration

3Na⁺ - 3(0.20 M) = 0.6 M Na⁺ ion

PO₄³⁻ - 1(0.20 M) = 0.2 M PO₄³⁻ ion

Step 4: Add ion concentrations

0.6 M + 0.2 M = 0.80 M ion concentration

Answer:

the force has to increase aswell

Explanation:

force and mass have a direct relationship meaning when one increases the other will. the heavier something is, the more force u have to put in order to get it to move!!

If the mass increases than the gravitational attraction between them increases as well as force also increases.

Force is defined as a push or pull on an object caused by its interaction with another thing.

It is a vector quantity, which implies it has both magnitude and direction.

There are basically five types of force

Force can be expressed as

Force = mass x acceleration

With increases in mass the force will also increases and acceleration will also increases.

Thus, If the mass increases than the gravitational attraction between them increases as well as force also increases.

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Answer:

Regulation

Explanation:

Your body regulates its body temperature in many ways: sweating, homeostasis etc.

The temperature and pressure conditions differ between Earth's surface and below Earth's surface. Generally, as you go deeper into the Earth, both temperature and pressure increase.

Temperature:

At Earth's surface, temperature varies widely depending on the location, season, and time of day.

On average, the temperature ranges from around -90°C (-130°F) in Antarctica to +50°C (122°F) in hot desert regions.

However, as you descend into the Earth's interior, the temperature increases due to the geothermal gradient.

The geothermal gradient represents the rate at which temperature increases with depth in the Earth.

On average, the geothermal gradient is approximately 25 to 30 degrees Celsius per kilometer (14 to 17 degrees Fahrenheit per mile).

This means that for every kilometer you descend, the temperature increases by about 25 to 30 degrees Celsius.

Pressure:

At Earth's surface, the pressure is typically around atmospheric pressure, which is about 101.3 kilopascals (kPa) or 14.7 pounds per square inch (psi).

However, as you go deeper into the Earth, the weight of the overlying rocks and materials increases, leading to an increase in pressure.

The pressure increase is primarily due to the weight of the overlying rocks and the force of gravity acting on them.

The increase in pressure with depth is known as lithostatic pressure.

The lithostatic pressure can be calculated using the equation P = ρgh, where P is the pressure, ρ is the density of the rock or material, g is the acceleration due to gravity, and h is the depth.

The density and composition of rocks can vary, but a typical value for the density of rocks is around 2,500 kilograms per cubic meter (kg/m³).

The difference in temperature and pressure conditions between Earth's surface and below the surface is significant.

As you go deeper, the temperature increases due to the geothermal gradient, and the pressure increases due to the weight of the overlying rocks.

These conditions play a crucial role in the process of lithification, which is the transformation of loose sediment into solid rock.

Higher temperatures and pressures below the surface can cause the minerals in sediment to recrystallize and bind together, forming a cohesive rock mass.

Additionally, the increased pressure helps in compacting the sediment, removing pore spaces, and increasing the density of the rock.

Therefore, the temperature and pressure conditions below Earth's surface are important factors in the lithification process.

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Among the given compounds, Na2SO3 and NH4NO3 are the most likely to produce a basic solution when dissolved in water.

RbBr and Mg(ClO4)2 are not expected to significantly affect the pH of the solution. The basic nature of Na2SO3 can be attributed to the presence of the sulfite ion (SO32-), while NH4NO3 is a salt of a weak acid (NH4+) and a strong base (NO3-).

When a compound dissolves in water, it can produce either acidic, basic, or neutral solutions depending on the nature of the dissolved species. Na2SO3, sodium sulfite, can produce a basic solution because the sulfite ion (SO32-) can react with water to form hydroxide ions (OH-) through the following equilibrium reaction: SO32- + H2O ⇌ HSO3- + OH-. The presence of hydroxide ions increases the concentration of hydroxide ions, resulting in a basic solution.

NH4NO3, ammonium nitrate, can also produce a basic solution. Although ammonium ions (NH4+) can act as a weak acid, nitrate ions (NO3-) do not significantly affect the pH of the solution. Therefore, the basic nature of NH4NO3 predominates.

On the other hand, RbBr (rubidium bromide) and Mg(ClO4)2 (magnesium perchlorate) do not have significant basic properties. The presence of bromide ions (Br-) and perchlorate ions (ClO4-) does not significantly affect the pH of the solution, resulting in a neutral or slightly acidic solution.

In conclusion, Na2SO3 and NH4NO3 are the compounds that are most likely to produce a basic solution when dissolved in water, while RbBr and Mg(ClO4)2 are not expected to significantly affect the pH of the solution.

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The balanced equation for the reaction of 1 mole of NaOH with 1 mole of [tex]H_{3}PO_{4}[/tex] can be represented as follows:

3NaOH + [tex]H_{3}PO_{4}[/tex] → [tex]Na_{3}PO_{4}[/tex] + 3[tex]H_{2}O[/tex]

In this reaction, sodium hydroxide (NaOH) reacts with phosphoric acid ([tex]H_{3}PO_{4}[/tex]) to form sodium phosphate ([tex]Na_{3}PO_{4}[/tex]) and water ([tex]H_{2}O[/tex]).

To balance the equation, it is necessary to ensure that the number of atoms of each element is equal on both sides of the reaction.

In this case, we need 3 moles of NaOH to react with 1 mole of [tex]H_{3}PO_{4}[/tex] to form 1 mole of [tex]Na_{3}PO_{4}[/tex] and 3 moles of [tex]H_{2}O[/tex]. This balanced equation accurately represents the stoichiometry of the reaction between NaOH and [tex]H_{3}PO_{4}[/tex].

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Answer:

Understanding the interior structure of the Earth can be a challenging

skill for many concrete learners to master, due to the inability to experience these

structures first hand and typically seeing them through images or diagrams. Handson learners can better learn about the basic structures of the Earth interior by

building models of these structures that they can see, touch, and interact with along

with exposure to familiar objects (such as fruit) that can be used to

represent/model the interior of our planet.

Procedure: Introduce a globe to students

Explanation:

Answer:

A boiled egg is an object that represents Earth accurately. A boiled egg and the Earth both have a brittle shell. The crust of the earth is broken into pieces, like the cracked shell of a hardboiled egg. The mantle of the earth is like the egg white, and the core of the earth lies in the center, like the egg yolk.

Explanation:

This is the correct answer I got a 100 on it. The other person's answer wasn't complete and didn't remember what they were comparing.

I hope my answer helps you!!!

Please mark my answer the Brainiest!!!

As per the given question, the mass of NO3-ion in the final solution is approximately 0.011 g or 0.0542 g (rounded to four decimal places). Hence, the correct option is 0.0542 g.

Given that a student dissolved 4.00 g of Co(NO3)2 in enough water to make 100 mL of stock solution, He took 4.00 m

L of the stock solution and then diluted it with water to give 275. m

of a final solution.

The molar mass of Co(NO3)2 = 165 g/mol

The molar mass of NO3- = 62 g/mol

The molarity of the stock solution = (4.00 g / 165 g/mol) / (100. mL / 1000 mL/L)

= 0.0242 M

We can use the equation; M1V1 = M2V2 where,

M1 is the initial molarity of the solution,

V1 is the initial volume of the solution,

M2 is the final molarity of the solution, and

V2 is the final volume of the solution.

Substituting the values in the above equation,0.0242 M × 4.00 mL

= M2 × 275 mLM2

= 0.000331 The MNO3- ion, Co(NO3)2, dissociates into Co2+ and NO3-. The number of NO3-ions produced is equal to the number of Co(NO3)2 molecules dissociated, which is 12.

Therefore, the concentration of NO3- ion is 2 × 0.000331 M

= 0.000662 M.

The mass of the NO3 ion in the final solution can be calculated as follows:

Mass of NO3- ion = concentration of NO3- ion × volume of the final solution × molar mass of NO3- ion

= 0.000662 M × 275 mL × 62 g/mol

= 11.22 g

≈ 0.0112 g

≈ 0.011 g

Therefore, the mass of NO3-ion in the final solution is approximately 0.011 g or 0.0542 g (rounded to four decimal places). Hence, the correct option is 0.0542 g.

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It is important to use disinfectants that do not contain alkylating agents when neutralizing viral particles to prevent further spread of the infection. Alkylating agents can damage DNA and cause the virus to mutate and become resistant to treatment, so it is important to use disinfectants that do not contain alkylating agents.

The aim of effectively neutralizing viral particles is to avoid the use of alkylating agents. Alkylating agents are substances that can cause damage to DNA by adding alkyl groups to the DNA molecule. This can lead to damage of the viral genetic material, which can cause the virus to mutate and become resistant to treatment. To effectively neutralize viral particles, it is important to use disinfectants that do not contain alkylating agents. This is because alkylating agents can damage the viral genetic material, which can cause the virus to mutate and become resistant to treatment.

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Answer:

Option A = 14.19 atm

Explanation:

Given data:

Volume of gas = 2.50 L

Number of moles of gas = 1.35 mol

Temperature of gas = 320 K

Pressure of gas = ?

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will put the values in formula.

P × 2.50 L =  1.35 mol × 0.0821 atm.L/ mol.K×   320

P = 35.467 atm.L/ 2.50 L

P = 14.19 atm

Thus, option A is correct.

The pressure in atm that should be exerted is 14.19 atm.

Since

The volume of gas = 2.50 L

Number of moles of gas = 1.35 mol

Temperature of gas = 320 K

Now we know that

PV = nRT

here,

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

So,

P × 2.50 L =  1.35 mol × 0.0821 atm.L/ mol.K×   320

P = 35.467 atm.L/ 2.50 L

P = 14.19 atm

Thus, option A is correct.

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When sodium sulfate (Na2SO4) dissolves in water, the ions present in the solution are Na+ and SO42-.

Sodium sulfate (Na2SO4) dissociates into its ions when it dissolves in water due to the strong attraction between the positive and negative charges of the ions and the water molecules. In the case of sodium sulfate, each Na+ ion is attracted to water molecules through ion-dipole interactions, and each SO42- ion is surrounded by water molecules through ion-dipole interactions as well.

The sodium ion (Na+) is formed when the sodium atom loses one electron, resulting in a +1 charge. This cation is soluble in water and remains in solution as Na+ ions.

The sulfate ion (SO42-) is formed when the sulfur atom combines with four oxygen atoms, and it carries a -2 charge. This anion is also soluble in water and remains in solution as SO42- ions.

Therefore, when sodium sulfate dissolves in water, the ions present in the solution are Na+ and SO42-. The presence of these ions allows the compound to be soluble in water and form a homogeneous solution.

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The wavelength of the photon absorbed when a hydrogen atom undergoes a transition from n = 1 to n = 5 is 949 Å (reported to at least 3 significant figures).

The Rydberg equation is a mathematical formula used to describe the wavelengths of light emitted by hydrogen atoms, which are related to the energy of their electrons.

The formula is given by: `1/λ = R(1/n₁² - 1/n₂²)`,

where λ = wavelength of the photon emitted or absorbed ; R = Rydberg constant (1.097 x 10⁷ m⁻¹)

n₁ and n₂ = integers representing the energy levels of the electron before and after the transition, respectively.

Given that a hydrogen atom undergoes a transition from n = 1 to n = 5, we can calculate the wavelength of the photon absorbed by plugging these values into the Rydberg equation.

Thus, we get :

1/λ = R(1/n₁² - 1/n₂²)

=> 1/λ = R(1/1² - 1/5²)

=> 1/λ = R(24/25)

=> λ = 25/24R

=> λ = 25 /(24 x 1.097 x 10⁷ m⁻¹)  = 0.949 X 10^(-7) m = 949 Å

Therefore, the wavelength of the photon absorbed when a hydrogen atom undergoes a transition from n = 1 to n = 5 is 949 Å (reported to at least 3 significant figures).

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The concentration of Cd²+ in 1 L of the solution is approximately 2.94 x 10⁻⁸ M.

To calculate the concentration of Cd²+ in the solution, we need to consider the formation of the complex ion (Cd(NH₃)₄)²⁺ and the equilibrium between Cd²+ and the complex ion.

Step 1: Write the balanced equation for the formation of the complex ion:

Cd²+ + 4NH₃ ⇌ (Cd(NH₃)₄)²⁺

Step 2: Write the equilibrium expression for the formation of the complex ion:

Kf = [Cd(NH₃)₄]²⁺ / [Cd²+][NH₃]⁴

Step 3: Substitute the known values into the equilibrium expression:

Kf = [Cd(NH₃)₄]²⁺ / ([Cd²+] * [NH₃]⁴)

Since we are neglecting complexes containing fewer than four ammonia ligands, the concentration of NH₃ remains unchanged.

Step 4: Rearrange the equation to solve for [Cd(NH₃)₄]²⁺:

[Cd(NH₃)₄]²⁺ = Kf * [Cd²+] * [NH₃]⁴

Step 5: Substitute the known values:

Kf = 1.8 x 10⁻⁷

[Cd²+] = 10⁻³ mol / 1 L = 10⁻³ M

[NH₃]⁴ = 1.5 mol / 1 L = 1.5 M

Step 6: Calculate [Cd(NH₃)₄]²⁺:

[Cd(NH₃)₄]²⁺ = (1.8 x 10⁻⁷) * (10⁻³) * (1.5)⁴

Step 7: Calculate [Cd²+]:

Since one Cd²+ ion reacts with one (Cd(NH₃)₄)²⁺ complex, the concentration of Cd²+ is equal to the concentration of (Cd(NH₃)₄)²⁺:

[Cd²+] = [Cd(NH₃)₄]²⁺ = (1.8 x 10⁻⁷) * (10⁻³) * (1.5)⁴

By calculating the expression, we find that the concentration of Cd²+ in 1 L of the solution is approximately 2.94 x 10⁻⁸ M.

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