Calculate the volume in mL of 0.600 M NaCl solution that contains 0.00123 moles of NaCl

The solubility product of PbCl₂ is 2.374 x 10⁻⁴.

Copper bromide is more soluble than lead iodide.

The maximum amount of solute that can dissolve in a known quantity of solvent at a certain temperature is its Solubility. This is the property that allows things like sugar molecules to dissolve in a cup of coffee. Water is known as a “universal solvent” because it can dissolve most substances but there are a few exceptions. The solubilty of a substance depends upon its Ksp ( solubility product)  value.

Given,

Solubility in g/L = 10.85

In moles/L = 10.85 ÷ 278

= 0.03901 moles/ L

Ksp = [Pb²⁺] [2Cl⁻]²

      = (0.03901) (2 × 0.03901)²

        =  2.374 x 10⁻⁴

Ksp is a measure of solubility of a  compound in water. The higher the Ksp, the more soluble the compound is. Thus, Ksp of copper bromide is greater than that of lead iodide and therefore, it is more soluble in water.

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Answer:

We know that, Va= 20.45 cm³, Vs= 20 cm³, Ma= 0.04M . But molar mass of Na₂CO₃ = 106. So, concentration (g/dm³) = 0.02045 × 106 = 2.1677 g/dm³. Hence, The percentage purity of the sodium carbonate solid is 21.25%.

The Keq for the reaction will be 0.89.

The concentration of CO2 Will be 1.67M.

The equilibrium constant (Keq) for the reaction formulated as Keq = [H2O]^2 / ([H2]^2 [O2]), can be evaluated using the given concentrations of hydrogen and oxygen.

After applying both their respective quantities, we arrive at a calculated value of 0.89 for Keq. Moving on, to calculate the concentration of CO2 in the equation H2O (1) + CO2 (g) → H2CO3 (aq), where Keq = [H2CO3] / ([H2O] [CO₂]), having been supplied with a value of Keq equal to 0.15 and H2CO3 being at 0.25M, the rearranged expression reveals that [CO2] equals 1.67 M following basic algebraic substitution.

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Q_w = 307.3 J

C_m = .233 J/g•K

%error = 39.95%

For simplicity's sake, I'm relabeling

Q_w as Q1

m_w as m1

C_w as c1

T_eq as T2

T_w as T1

Q_m as Q2

m_m as m2

C_m as c2

experimental value as exp

actual value as actual

Question 1

Q1 = m1•c1•(T2-T1)

Identify what you know

m1 = 124g

c1 = 4.13 J/g • K

T2 = Final temperature = 22.3°C

T1 = Initial temperature = 21.7°C

Convert Celsius to Kelvin (C+273.15=K)

T2 = 295.45 K

T1 = 294.85 K

Plug in

Q1 = 124g•(4.13 J/g•K)•(295.45K - 294.85K)

Solve

Q1 ≈ 307.3 J

Question 2

-Q1 = Q2 = m2•(c2)•(T2-100)

Ignore Q2 for a second, and you're left with

-Q1 = m2•(c2)•(T2-100)

which is the same thing.

Identify what you know

Q1 = 307.3 J

m2 = 17g

T2 = 22.3°C

Plug in

-(307.3J) = 17g • c2 • (22.3°C-100°C)

Solve

-307.3 J = (-1320.9 g•°C) • c2

c2 = .233 J/g•°C or J/g•K (I'll explain later)

Question 3

%err = ((exp - actual)/actual) • 100%

Identify what you know

exp = .233 J/g•K

actual = .388 J/g•K

Plug in

%err = ((.233 J/g•K - .388 J/g•K)/ .388 J/g•K) • 100%

Solve

%err = -39.95 %

Take the absolute value

%err = 39.95%

Referring to earlier change in units:

The reason we can not use the K value of T2 (295.45K) is because the formula provided (T2-100) does not account for T2 being in K. It only accounts for T2 being in °C.

The correct answer is "Particles are more likely to collide with enough energy to form an activated complex," which is the last option, as when the temperature of a reaction increases, the average kinetic energy of the particles increases.

Chemical reactions require a certain amount of energy to occur. This energy is called activation energy. In order for reactant molecules to undergo a chemical reaction, they must overcome the activation energy barrier. This barrier is like a hill that reactants must climb over to reach the product state. One way to provide the energy required to overcome the activation energy barrier is to increase the temperature of the system. This is because temperature is a measure of the average kinetic energy of particles in a system. As the temperature increases, the kinetic energy of the particles also increases. This means that they are moving faster and colliding with greater energy.

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We need more information to solve this problem. Specifically, we need to know the volume (or concentration) of HCl used to react with the Mg. Without that information, we cannot determine how many grams of Mg reacted.

M = 1.183

Molarity is moles/Liter, so setting up some equations gives you

1) 1M = Xmol/0.05L

2) 2.5M = Xmol/0.05L

3) 0.5M = Xmol/0.05L

Solve for each X

1) X = 0.05mol

2) X = 0.125mol

3) X = 0.0025mol

Now add all the moles and Liters (separately)

XM = (0.05+0.125+0.0025)mol/(0.05+0.05+0.05)L

XM = 0.1775mol/0.15L

X = 1.183M

According to the solubility of  of sparingly soluble electrolytes by conductometer and potentiometer.

Solubility is defined as the ability of a substance which is basically solute to form a solution with another substance. There is an extent to which a substance is soluble in a particular solvent. This is generally measured as the concentration of a solute present in a saturated solution.

The solubility mainly depends on the composition of solute and solvent ,its pH and presence of other dissolved substance. It is also dependent on temperature and pressure which is maintained.It can also be determined for electrolytes.

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The shape of a graph that shows the velocity in the x direction (v) versus time when the object is accelerating in the x direction would be a curve with a non-zero slope.

The rate at which an object's displacement changes in relation to a frame of reference is its velocity. The direction of the movement of the body or the object is defined by its velocity.

According to the equation v = s/t, velocity (v) is a vector quantity that quantifies displacement (or change in position, s), over the change in time (t).

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Answer: I expect a horizontal line (slope 0). As time increases, the velocity in the x direction stays about the same.

Explanation: Edmentum sample answer

The rate expression is k [BF₃]²[NH₃], overall order is 3, rate constant k is 1.13 × 10⁻³ mol⁻² dm⁶ s⁻¹.

The rate expression for this reaction can be written as:

Rate = k [BF₃]^m[NH₃]^n

The method of initial rates can be used to calculate the values of m and n. When we compare experiments 1 and 2, notice that halving the concentration of [NH3] reduces the initial rate of reaction. This suggests that the reaction is first order in terms of [NH3], implying that n = 1.

When comparing experiments 1 and 3, notice that increasing the concentration of [BF3] by a factor of 2.5 increases the initial rate of reaction by a factor of 9.39 (i.e., 2.13/0.227). This shows that the reaction is about second order in relation to [BF3], i.e., m 2.

Therefore, the rate expression for the reaction is:

Rate = k [BF₃]²[NH₃]

The overall order of the reaction is m + n = 3.

Using the data from experiment 4, substitute the values and solve for k:

Rate = k [BF₃]²[NH₃]

1.02 × 10-¹ = k (3.00 × 10⁻¹)² (1.00 x 10⁻¹)

k = 1.02 × 10-¹ / (3.00 × 10⁻¹)² (1.00 x 10⁻¹)

k = 1.13 × 10⁻³ mol⁻² dm⁶ s⁻¹

Therefore, the rate constant k is 1.13 × 10⁻³ mol⁻² dm⁶ s⁻¹.

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From the calculation, the pH of the solution can be obtained as 0.39.

We first have to obtain the dissociation constant of the solution;

α = √Ka/C

Ka = Cα^2

Ka = 4.9 * 10^-3 * 6

Ka = 0.0294

Then we have that;

0.0294 = [x]^2/[6 - x]

0.0294 * [6 - x] = x^2

0.1764 - 0.0294 x = x^2

x^2 +  0.0294 x - 0.1764 =0

x = 0.41 M

Thus the pH of the solution is;

pH = -log[0.41]

= 0.39

pH is an important parameter in chemistry, biology, and many other fields, as it can affect the behavior and properties of substances and reactions.

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50 g of As[tex]_2[/tex]O[tex]_3[/tex] are titrated with 38.5 mL of KMnO[tex]_4[/tex] to reach the end point. 0.26M is the concentration of the KMnO[tex]_4[/tex]  solution.

Concentration in chemistry refers to the quantity of a material in a certain area. The ratio of the solute within a solution to the solvent or whole solution is another way to define concentration. In order to express concentration, mass in unit volume is typically used.

The solute concentration can, however, alternatively be stated in moles or volumetric units. Concentration may be expressed as per unit mass rather than volume.

5As[tex]_2[/tex]O[tex]_3[/tex](s)+4MnO[tex]_4[/tex]⁻(aq)+9H[tex]_2[/tex]O(l)+12H⁺(aq)⟶10H[tex]_3[/tex]AsO[tex]_4[/tex](aq)+4Mn[tex]_2[/tex]⁺(aq)

the stoichiometry ratio between As[tex]_2[/tex]O[tex]_3[/tex] and MnO[tex]_4[/tex]⁻ is 5:4

0.0126 moles of  As[tex]_2[/tex]O[tex]_3[/tex] will react with 4/5×0.0126 moles = 0.01008moles

0.01008moles of MnO[tex]_4[/tex]⁻ is present in 38mL

concentration of KMnO[tex]_4[/tex]= moles×volume

                                        = 0.010/38×1000

                                        =0.26M

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2 M solution of a compound can be made by dissolving 2g of compounds in 1 liter of water. Either by diluting the appropriate volume of a more concentrated solution also known as a stock solution to the desired final volume or by dissolving a known mass of solute in a solvent, solutions of known concentration can be prepared.

For example, when we add one part by weight of powder to 19 parts by weight of the solvent is used to make a 5% solution. For 1% solution, the addition of 1gm of NaCl to 100L of water. which is the final volume of the solution.

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Note that the above prompt on Ecology draws it's analysis form a well known story which have been told visually called "The Lion King".

The answers are:

1) Biotic Factors, simply put are living things

2 examples of things from Lion King Introduction are:

3) Abiotic factors are Non -living things.

4) Examples from the introduction are:

5) the symbiotic relationship is called: commensalism.

Long-term biological interactions known as commensalism occur when individuals of one species benefit while those of the other species suffer neither advantages nor harm.

Ecology which is the study of the environment, allows  a person  to comprehend how different types of creatures coexist in various kinds of physical settings.

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Full Question:

Although part of your question is missing, you might be referring to this full question:

1) What is Biotic Factors

2) List three biotic factors from the Lion King introduction

3) What is Abiotic factors?

4) List three Abiotic factors from the Lion King introduction

5) The bird riding on the tusks of the elephant feed on insects the elephant stirs up. What kind of symbiotic relationship exists between the two?

1. The mass (in grams) of FeCl₂ contained in the sample is 14.96 grams

2. The mass (in grams) of KBr present in the solution is 16.66 grams

1. The mass of FeCl₂ contained in the sample can be obtained as shown below:

First, we shall obtain the mole

Mole = molarity × volume

Mole of FeCl₂ = 0.762 × 0.155

Mole of FeCl₂ = 0.118 mole

Finally, we shall determine the mass of FeCl₂ present in the sample. Details below:

Mass = Mole × molar mass

Mass of FeCl₂ = 0.118 × 126.75

Mass of FeCl₂ = 14.96 grams

2. The mass of KBr present in the solution can be obtained as shown below:

First, we shall obtain the mole

Mole = molarity × volume

Mole of KBr = 0.350 × 0.4

Mole of KBr = 0.14 mole

Finally, we shall determine the mass of KBr in the solution. Details below:

Mass = Mole × molar mass

Mass of KBr = 0.14 × 119

Mass of KBr = 16.66 grams

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From the titration curve that have been shown in the image, the equivalence point is 50 mL

At the equivalence point on a titration curve, the amount of titrant added is chemically equivalent to the amount of analyte in the sample being evaluated. As a result of the reaction between the titrant and analyte at this point, the entire analyte has been neutralized by the titrant.

You can locate the equivalence point by plotting the pH or any relevant aspect of the sample under examination as a function of the volume of titrant used.

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Polysaccharides can be differentiated from monosaccharides by enzymatic assays.

When I hear the term aromaticity what comes to my mind is the Huckel rule. In accordance with the Huckel rule, for a compound to be aromatic, then the compound must have to contain 4n + 1 number of pi elecryons of which benzene satisfies by having 6 pi electrons in its molecular orbital.

Peptides, which are chains of amino acids joined together by peptide bonds, are created when amino acids interact with one another through peptide bonds.

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The process of cellular respiration releases energy because the energy that is released when the bonds are formed in CO[tex]_2[/tex] and water is equal to the energy required to break the bonds of sugar and oxygen. Therefore, the correct option is option A.

Cells turn sugars into energy through a process called cellular respiration. Cells need fuel or an electron acceptor to power the chemical process that converts energy into usable forms such as ATP along with additional kinds of energy that can be utilised to power cellular reactions.

All multicellular species, including eukaryotes, as well as certain single-celled organisms, generate energy by aerobic respiration. Utilising oxygen, which is the strongest electron acceptor found in nature, is called aerobic respiration. The process of cellular respiration releases energy because the energy that is released when the bonds are formed in CO[tex]_2[/tex] and water is equal to the energy required to break the bonds of sugar and oxygen.

Therefore, the correct option is option A.

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A muffi n recipe calls for cream of tartar, or potassium hydrogen tartrate. The amount of cream of tartar that is required contains 2.56 ×10²³atoms of carbon. 0.42moles of potassium hydrogen tartrate is required

In the Global System of Units (SI), the mole represents the unit of material quantity. How many fundamental entities of a particular substance are present within an object a sample is determined by the quantity of that material. An elementary entity can be a single atom, a molecular structure, an ion, a charged particle pair, or a particle that is subatomic like a proton depending on the makeup of the substance.

For instance, despite the fact that the two substances have different volumes and masses, 10 moles of water because 10 moles of the chemical element mercury both contain the same quantity of stuff, because the mercury comprises exactly one particle for each molecule of water.

mole = 2.56 ×10²³/ 6.022×10²³

       = 0.42moles

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If you mix 20.0 mL of 0.010 M MgCl[tex]_2[/tex] with 20.0 mL of 0.0020 M Na[tex]_2[/tex]CO[tex]_3[/tex],  magnesium carbonate will not precipitate out from the solution.

The byproduct of the condensing of atmospheric water vapour that falls from clouds as a result of gravitational pull is referred to as precipitation in meteorology. Rain, sleet, slush, ice pellets, graupel, drizzle, and hail are the main types of precipitation.

When a region of the outside world becomes completely saturated with water vapour, the water condenses or "precipitates" or falls. Because the water vapour does not enough condense to precipitate, fog and mist are instead colloids rather than precipitation. magnesium carbonate will not precipitate out from the solution.

Ksp =[Mg²⁺][CO₃²⁻]

[0.010][20] = C₂×40

C₂=0.001M

Q= 0.005×0.001

   = 5×10⁻⁶M

Q<Ksp

precipitation will not occur

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