calculate tje umber of ml of hcl reagent (36.0%, specific gravity - 1.18) that are needed to preapre one liter of .1 m hcl solution

Answers

Answer 1

The amount of HCl reagent (36.0%, specific gravity - 1.18) required to prepare 1 litre of 0.1M HCl solution is [tex]0.3085 ml[/tex].

To prepare 1 litre of 0.1M HCl solution, we need to calculate the amount of HCl reagent (36.0%, Specific gravity - 1.18) required.

HCl has a molecular weight of 36.46 g/mol..

Now, the equation to calculate the amount of HCl required is:

Amount of HCl = [tex]\frac{ (Molarity of solution * Volume of solution * Molecular Weight of HCl) }{(Percentage purity of HCl * Specific Gravity of HCl)}[/tex]

So, the amount of HCl reagent required to prepare 1 litre of 0.1M HCl solution is:

Amount of HCl = [tex]\frac{(0.1 * 1 *36.46) }{(36.0 x 1.18)}= 0.3085 g[/tex]

Now, 1 g of HCl reagent = 1 ml of HCl reagent

Therefore, the amount of HCl reagent (36.0%, specific gravity - 1.18) required to prepare 1 litre of 0.1M HCl solution is[tex]0.3085 ml[/tex].

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Related Questions

a pipet is used to measure out 10 ml of water. if the mass of this volume of water is 9.990 g and the density of water is given as 0.9978 g/ml, what is the actual volume of water measured out?

Answers

the actual volume of water measured out is 10.02 ml, which is slightly higher than the intended volume of 10 ml. This could be due to various factors, such as the presence of air bubbles or human error in reading the pipet

To determine the actual volume of water measured out, we need to use the given information about the mass and density of water.

First, we can use the density formula to calculate the mass of 10 ml of water:

density = mass / volume

Rearranging the formula, we get:

mass = density x volume

Substituting the given values, we get:

mass = 0.9978 g/ml x 10 ml = 9.978 g

This means that the mass of the water measured out is 9.978 g.

However, the question states that the mass of the measured water is 9.990 g. This means that there is an additional mass of water that was inadvertently added or that there is an error in the measurement.

To find the actual volume of water measured out, we can use the following formula:

actual volume = measured mass / density

Substituting the given values, we get:

actual volume = 9.990 g / 0.9978 g/ml = 10.02 ml

Therefore, the actual volume of water measured out is 10.02 ml, which is slightly higher than the intended volume of 10 ml. This could be due to various factors, such as the presence of air bubbles or human error in reading the pipet

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how do i find the answer to What does Newton's first law of motion state?

Answers

Answer: Newton's first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force. This tendency to resist changes in a state of motion is inertia.

Explanation:

Hoped that helped =)

what kind of bonds are responsible for the unique cohesion, surface tension, and adhesion properties of water molecules?

Answers

The unique cohesion, surface tension, and adhesion properties of water molecules are primarily due to the hydrogen bonds between the molecules.

The reaction below would best be described as what type of reaction:
ZnBr₂ + Fe
FeBr₂ + Zn

Answers

Answer:

The reaction ZnBr2 + Fe -> FeBr2 + Zn is a redox reaction, also known as an oxidation-reduction reaction.

Explanation:

9) For the following balanced equation, NH3(g) + HCl(g) → NH4Cl(s)
how many moles of the product could be produced by complete reaction of 1.00g of ammonia?

Answers

For the equation, 0.059 moles of NH₄Cl can be produced to complete the reaction.

How to calculate moles?

In order to determine how many moles of the product, NH₄Cl, can be produced by the complete reaction of 1.00g of ammonia, we can use the balanced chemical equation. According to the equation, 1 mole of NH3 reacts with 1 mole of HCl to produce 1 mole of NH₄Cl.

Thus, if we have 1.00g of NH₃, we can calculate the number of moles by using the molar mass of NH₃:

1.00g NH₃ / 17.0 g/mol = 0.059 moles NH₃

So, if we have 0.059 moles of NH₃, we can produce 0.059 moles of NH₄Cl.

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Please help
What volume, in liters, of 4.0 M LiBr solution can be made using 100.0 g LiBr?
(LiBr; 86.44 g/mol) [?] L

Answers

ANS = 0.288 L can be made.

How can we find the volume?

The first thing that you need to do here is to convert the mass of lithium bromide to moles by using the compound's molar mass.

The number of moles of the solute—in your example, lithium bromide—present per 1.00 L of the solution is simply referred to as the molarity of the solution.

For every 1.00 L of this solution, 4.00 moles of lithium bromide must be present in order to create a 4.00-M solution.

You may calculate how many litres of this solution can be made using the molarity of the solution as a conversion factor because you already know that your sample contains 1.1515 moles of lithium bromide.

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.What is the gram-formula mass of a compound if 5 moles of the compound have a mass
of 100 grams?

Answers

The gram formula mass of a compound if 5 moles of the compound have a mass of 100 grams would be 20 grams/mole.

What is gram-formula mass?

The gram formula mass of a compound is the total weight of all atoms in a molecule or a formula unit of a substance.

It is also the ratio of the mass of a compound and the number of moles present in the mass of the compound.

Gram formula mass = mass/mole

In this case, mass = 100 grams, and mole = 5 moles

Gram formula mass = 100/5

                                 = 20 grams/mole

In other words, the gram formula mass of the compound is 20 grams/mole.

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can you substitute confectioners sugar for granulated sugar.true/false

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The answer is true, confectioners sugar can be substituted for granulated sugar but it may not always be an exact 1:1 substitution.

Confectioners sugar (also known as powdered sugar or icing sugar) can be substituted for granulated sugar in some recipes, but it may not always be an exact 1:1 ratio substitution.

Confectioners sugar is a very fine powder that contains cornstarch, which is added to prevent caking. Due to its fine texture, it can dissolve quickly in recipes and can add a slightly different texture to baked goods. It can also affect the sweetness level of the recipe as it usually contains cornstarch or other additives, which can also influence the texture of the final product.

In general, substituting confectioners sugar for granulated sugar works best in recipes that don't require the sugar to dissolve completely, such as frosting or glazes. For recipes that require the sugar to dissolve, such as in baking or making meringues, it's best to use granulated sugar.

So, the answer is "True", but the substitution may not be appropriate for all recipes.

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what is the minimum concentration of dissolved salts water can have and still be considered salt water?

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Water can be defined as saltwater when it contains enough dissolved salts to alter its physical and chemical properties. The minimum concentration of dissolved salts in water that can still be considered saltwater is generally defined as 3.5% or 35 parts per thousand (ppt) by weight.

This concentration is often referred to as the "salinity" of the water, and it represents the total amount of dissolved salts in the water. Salinity is typically measured using a unit called "practical salinity units" (psu), which is equivalent to ppt.

Water with a salinity level below 3.5% is typically considered freshwater. However, it's important to note that the exact threshold for when water is considered saltwater may vary depending on the context. For example, some sources may define saltwater as any water with a salinity level above 1 ppt, while others may use a higher threshold.

In general, the higher the salinity level of water, the more challenging it can be for organisms to survive in it. This is because high levels of dissolved salts can affect the osmotic balance of cells, making it harder for them to regulate the flow of water and nutrients

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Copper is an element. How do these images of copper illustrate this?

Answers

Copper is an element which comprises of same kind of atoms which can be illustrated by the images.

What is an element?

It is defined as a substance which cannot be broken down further into any other substance. Each element is made up of its own type of atom. Due to this reason all elements are different from one another.

Elements can be classified as metals and non-metals. Metals are shiny and conduct electricity and are all solids at room temperature except mercury. Non-metals do not conduct electricity and are mostly gases at room temperature except carbon and sulfur.

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Your question is incomplete, but most probably your  full question with attached image is:Copper is an element. How do these images of copper illustrate this?

why was it important to ensure that the solute was completely dissolved in the cyclohexane before freezing the solution

Answers

It important to ensure that the solute was completely dissolved in the cyclohexane before freezing the solution because it affects the freezing point of the solution.

When a solute dissolves in a solvent, it reduces the solvent's freezing point, which implies the solution must be chilled to a lower temperature than the pure solvent in order to freeze. This is referred to as freezing point depression.

If the solute is not entirely dissolved in the solvent, the resultant solution may have a non-uniform composition, with greater concentrations of solute in certain places than in others. This might cause the freezing point of the solution to be lower than predicted, as well as the production of crystals or other solid particles, which can interfere with the experiment's accuracy.

Furthermore, if the solute is not entirely dissolved, the resultant solution may not be homogenous, and its characteristics may differ from one section of the sample to the next. This might result in inconsistencies and inaccuracies in the experiment.

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two porous containers are filled with hydrogen and neon respectively. under identical conditions, 2/3 of the hydrogen escape in 6 hours. how long will it take for half the neon to escape?

Answers

Using Grahams law, after calculation it takes about 2 * (1/0.223) = 2.24 times as long for half of the neon to escape, or approximately 13.44 hours.

We can use Graham's Law to solve this problem, as it relates the rate of effusion of a gas to its molar mass. According to Graham's Law, the rate of effusion of a gas is inversely proportional to the square root of its molar mass.

Let's assume that the rate of effusion of hydrogen is 1. We need to find the time it takes for half of the neon to escape, given that 2/3 of the hydrogen has escaped in 6 hours.

From Graham's Law, we know that:

(rate of effusion of hydrogen) / (rate of effusion of neon) = sqrt(molar mass of neon) / sqrt(molar mass of hydrogen)

We can rearrange this equation to solve for the rate of effusion of neon:

(rate of effusion of neon) = (sqrt(molar mass of hydrogen) / sqrt(molar mass of neon)) * (rate of effusion of hydrogen)

Since we know that the rate of effusion of hydrogen is 1, we can simplify the equation to:

(rate of effusion of neon) = (sqrt(molar mass of hydrogen) / sqrt(molar mass of neon))

We can find the ratio of the molar mass of hydrogen to neon from the periodic table. The molar mass of hydrogen is 1 g/mol, and the molar mass of neon is 20.18 g/mol. Therefore:

(sqrt(molar mass of hydrogen) / sqrt(molar mass of neon)) = (sqrt(1 g/mol) / sqrt(20.18 g/mol)) = 0.223

So, the rate of effusion of neon is 0.223 times the rate of effusion of hydrogen. If 2/3 of the hydrogen has escaped in 6 hours, then 1/3 of the hydrogen is still in the container after 6 hours. Since the rate of effusion of neon is 0.223 times the rate of effusion of hydrogen, we can assume that the rate of effusion of neon is constant and also 0.223. Therefore, it will take 1/2 * (1/0.223) = 2.24 times as long for half of the neon to escape, or approximately 13.44 hours.

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In water, a substance that ionizes completely in solution is called a a. weak electrolyte b. nonelectrolyte c. nonconductor d. strong electrolyte

Answers

In water, a substance that is ionizes totally and completely in solution is called strong electrolyte.

Ionization is a process in which a neutral snippet or patch earnings or loses one or further electrons. The performing charged snippet/ patch is called an ion. A appreciatively charged ion is called a cation, while a negatively charged ion is called an anion.

The ionization process is used in a wide variety of outfit, for illustration, spectrometer, radiation remedy, fluorescent lights,etc.

Strong electrolytes are ones that completely ionise or dissociate in their aqueous solution.

These electrolytes have a higher extension of ionisation and a high electrical conductivity.

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a piston confines 0.200 mol ne(g) in 1.20 l at 25 8c. two experiments are performed. (a) the gas is allowed to expand through an additional 1.20 l against a constant pressure of 1.00 atm. (b) the gas is allowed to expand reversibly and isothermally to the same final volume. which process does more work?

Answers

A piston confines 0.200 mol Ne(g) in 1.20 l at 25 °C . Two experiments are performed. The process does more work is the second experiment.

(a) The gas is allowed to expand through the additional 1.20 L against the  constant pressure of the 1.00atm

Irreversible path is as :

W = -Pex × ΔV

Where

Pex = 1.00 atm

ΔV = 1.20 L

W = - (1.00 atm) × 1.20 L

W = -1.20 L. atm  × 101.325 J /1 L.atm

W = -121.59 J

(b)  The gas is allowed to expand the reversibly and the  isothermally to the same final volume is as :

W = - nRT ln (V final / V initial)

Where

n = the number of moles = 0.200

R = gas constant = 8.3145 J/K.mol

T = 298 Kelvin

V final / V initial  = 2.40 / 1.20 = 2

W = - (0.200mol) × 8.3145 J/K.mol × 298K × ln(2.4/1.2)

W = - 343.5 J

Thus the second one does the more work.

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Which mass of Carbon id produced?

Answers

Answer:

(c) 4.4g

Explanation:

Given:

mass of calcium carbonate (mCaCO3) = 10g

MrCaCO3 = 100

To find: mCO2

Solution:

CaCO3 + 2HCl → CaCl 2 + H2O + CO2

Now,

MrCaCO3 = 40 + 12 + 16.3 = 100

Therefore,

Number of moles (n) = m/Mr

nCaCO3 = 10/100 = 0.1

The amount of moles is proportional to the coefficient of the reaction. Since both calcium carbonate (CaCO3) and carbon dioxide (CO2) have the same coefficient.

nCO2 = 0.1

MrCO2 = 12 + 16.2 = 44

mCO2 = 0.1 × 44 = 4.4g

Calculate the volume of oxygen that will be spent on burning 300 liters of ethane containing 5.8% non-combustible impurities

Answers

Answer:

To calculate the volume of oxygen that will be required to burn 300 liters of ethane containing 5.8% non-combustible impurities, we need to determine the amount of pure ethane present.

Since the ethane contains 5.8% non-combustible impurities, 100 - 5.8 = 94.2% of the 300 liters of ethane is pure and can be burned.

The amount of pure ethane is 94.2% * 300 liters = 282.6 liters.

The stoichiometric equation for the complete combustion of ethane is:

C2H6 + 7O2 -> 4H2O + 6CO2

This equation tells us that for every molecule of ethane that is burned, 7 molecules of oxygen are required.

The volume of oxygen required for burning 282.6 liters of ethane is 282.6 liters * 7 = 1989.2 liters.

So, the volume of oxygen that will be required to burn 300 liters of ethane containing 5.8% non-combustible impurities is 1989.2 liters.

Assuming that the non-combustible impurities have no effect on the combustion of ethane, we can calculate the volume of oxygen required to burn 300 liters of ethane as follows:

Write the balanced chemical equation for the combustion of ethane:

C2H6 + 3.5 O2 -> 2 CO2 + 3 H2O

Determine the stoichiometry of the reaction, which tells us the molar ratio of ethane to oxygen required for complete combustion. From the balanced equation, we see that 1 mole of ethane reacts with 3.5 moles of oxygen.

Convert the volume of ethane from liters to moles, using the ideal gas law:

PV = nRT

where P is the pressure of the gas, V is the volume of the gas, n is the number of moles of gas, R is the gas constant, and T is the temperature of the gas. Assuming standard temperature and pressure (STP), which is 1 atm and 0°C, we have:

n = PV/RT = (1 atm * 300 L)/(0.08206 Latm/molK * 273 K) = 12.5 moles of ethane

Calculate the amount of oxygen required for combustion, using the stoichiometry of the reaction:

3.5 moles of O2 are required for 1 mole of ethane, so for 12.5 moles of ethane, we need:

12.5 moles of ethane * 3.5 moles of O2/mole of ethane = 43.75 moles of O2

Convert the moles of oxygen to volume, again using the ideal gas law:

V = nRT/P = (43.75 mol * 0.08206 Latm/molK * 273 K)/1 atm = 994.8 L of O2

Therefore, approximately 994.8 liters of oxygen will be spent on burning 300 liters of ethane containing 5.8% non-combustible impurities.

the mass of a proton is 1.0074 amu, the mass of a neutron is 1.0087 amu, and the mass of an electron is 0.00054858 amu. given this information, what can you predict for the mass of a single atom of 3h (tritium)?

Answers

It will have a mass of 3.025 amu. This is because the mass of a tritium atom is made up of the mass of one proton, two neutrons, and three electrons.

The mass of a single atom of 3H (tritium) can be predicted by adding the mass of the three protons, three neutrons, and three electrons in the atom. Since a single atom of 3H (tritium) contains 3 protons, 3 neutrons, and 3 electrons, the mass of a single atom of 3H (tritium) can be calculated by adding the mass of each of these particles together.

The mass of a single atom of 3H (tritium) can be calculated using the equation:

Mass of 3H (tritium) = [tex](3 * Mass of Proton) + (3 * Mass of Neutron) + (3 * Mass of Electron)[/tex]

Mass of 3H (tritium) =[tex](3 *1.0074 amu) + (3 *1.0087 amu) + (3 * 0.00054858 amu)[/tex]

Mass of 3H (tritium) = [tex]3.0218 amu[/tex]

Therefore ,he mass of a single atom of 3h (tritium) is 3.0218 amu

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complete question:the mass of a proton is 1.0074 amu, the mass of a neutron is 1.0087 amu, and the mass of an electron is 0.00054858 amu. given this information, what can you predict for the mass of a single atom of 3h (tritium)?

it will have a mass of exactly 3 amu

it will have a mass of 1.008 amu

it will have a mass of 3.025 amu

it will have a mass somewhat greater than 3.025 amu

it will have a mass somewhat less than 3.025 amu

You would like to determine if the temperature inside a freezer is lower than 0°C. Using a glass of liquid water, describe how you could estimate the temperature. Could you determine if the freezer has a temperature of −10°C by just using the glass of water?

Answers

Yes, you can determine if the temperature inside a freezer is below 0°C by using a glass of liquid water. Here's how:

Fill a glass with room-temperature water.Place the glass of water inside the freezer and let it sit for a few minutes, until the water has stabilized at the temperature of the freezer.Observe the state of the water. If the water is still liquid, then the temperature inside the freezer is above 0°C. If the water is beginning to freeze, with ice forming on the surface, then the temperature is below 0°C.

However, it is not possible to determine the exact temperature of the freezer by just using a glass of water. The temperature can only be estimated by observing the state of the water and making a rough guess based on the extent of the freezing.

For example, if the water is just starting to freeze, then the temperature could be close to 0°C. If the water has mostly frozen, then the temperature could be closer to -10°C. However, without a thermometer, the exact temperature cannot be determined.

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How the angle b/w AB6 type molecules is 90

Answers

The angle between AB6 molecules is determined by the number of bonds between the atoms. AB6 molecules are molecules that are composed of six atoms in a ring. Each of the atoms is connected to two other atoms.

What is the atoms?

Atoms are the basic building blocks of all matter. They are the smallest particles of an element that still retain their chemical identity. Atoms are composed of a nucleus made of protons and neutrons, surrounded by electrons in shells. The number of protons in an atom determines the element it is, and the number of neutrons can vary to give different isotopes of the same element. Atoms can be combined by chemical bonds to form molecules and other compounds. The properties of an atom are determined by its electron configuration which can be altered by chemical reactions.

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match the following aqueous solutions with the appropriate letter from the column on the right. fill in the blank 1 1. 0.22 m bas a. lowest freezing point fill in the blank 2 2. 0.19 m niso4 b. second lowest freezing point fill in the blank 3 3. 0.20 m nh4br c. third lowest freezing point fill in the blank 4 4. 0.34 m ethylene glycol(nonelectrolyte) d. highest freezing point

Answers

0.22 M BaS -> d. highest freezing point0.19 M NiSO4 -> c. third lowest freezing point0.20 M NH4Br -> b. second lowest freezing point0.34 M Ethylene Glycol (nonelectrolyte) -> a. lowest freezing point

When a solute is added to a solvent, it lowers the freezing point of the solution. The extent to which the freezing point is lowered depends on the concentration of the solute particles in the solution. A higher concentration of solute particles leads to a greater decrease in the freezing point, resulting in a lower freezing point. The freezing point of a solution is directly proportional to the concentration of solute particles. Among the given solutions, the ethylene glycol solution will have the lowest freezing point as it is a nonelectrolyte and will not dissociate into ions in solution. The rest of the solutions contain electrolytes and will dissociate into ions in solution, increasing the concentration of solute particles and decreasing the freezing point. The highest freezing point will be observed in the BaS solution, which has the highest concentration of solute particles, while the NH4Br solution has a lower concentration of solute particles and will have the second lowest freezing point. The NiSO4 solution will have a slightly lower concentration of solute particles and will have the third lowest freezing point.

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C6H6 (l) + Cl2 (g) → C6H5Cl (s) + HCl (g)

If 45.6g of benzene (C6H6) reacts completely with the chlorine gas (Cl2), how many atoms of hydrochloric acid will be produced

Answers

Answer:

45.6g ÷ 78g/mol = 0.58mol (C6H6)

1mol (C6H6) = 1mol (HCl)

HCl = 0.58mol

0.58mol × 6.022×10^23

=......atoms

Explanation:

Find the number of moles (HCl)

Multiply the number of moles produced by the avogadro's number and get the number of atoms produced.

3.51 x 10²³ atoms of hydrochloric acid (HCl) will be produced.

What is Balanced Chemical Equation?

A balanced chemical equation is a representation of a chemical reaction using chemical formulas and coefficients that shows the relative amounts of reactants and products involved in the reaction. The coefficients are used to balance the number of atoms of each element on both the reactant and product sides of the equation, ensuring that the law of conservation of mass is satisfied. A balanced chemical equation also provides information about the stoichiometry of the reaction, including the mole ratios between reactants and products.

The balanced chemical equation is:

C6H6 (l) + Cl2 (g) → C6H5Cl (s) + HCl (g)

From the equation, it is clear that 1 mole of benzene (C6H6) reacts with 1 mole of chlorine gas (Cl2) to produce 1 mole of hydrochloric acid (HCl).

First, we need to calculate the number of moles of benzene (C6H6) in 45.6g:

moles of C6H6 = mass of C6H6 / molar mass of C6H6

moles of C6H6 = 45.6 g / 78.11 g/mol

moles of C6H6 = 0.5839 mol

Since 1 mole of benzene (C6H6) produces 1 mole of hydrochloric acid (HCl), the number of moles of hydrochloric acid (HCl) produced is also 0.5839 mol.

To convert the number of moles of hydrochloric acid (HCl) to the number of atoms of hydrochloric acid (HCl), we need to use Avogadro's number:

number of atoms of HCl = moles of HCl x Avogadro's number

number of atoms of HCl = 0.5839 mol x 6.022 x 10²³/mol

number of atoms of HCl = 3.51 x 10²³ atoms

Therefore, 3.51 x 10²³ atoms of hydrochloric acid (HCl) will be produced.

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pls help thank you very much

Answers

Answer:

a copper is the answer to ur

magnesium po hahahahahaha

what piece of lab equipment would you use to estimate the volume of a drop of water?

Answers

To estimate the volume of a drop of water, you can use a piece of lab equipment called a micropipette.

A micropipette is a precision instrument that is used to measure and transfer small volumes of liquid. It works by suctioning up a known volume of liquid and then dispensing it into a test tube or other vessel. The micropipette is accurate to within 0.1-1% of the total volume, making it ideal for measuring small volumes such as drops of water.

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In the SI system of units, the mole is one of seven base units. It is frequently used in
chemical calculations. However, a mole of something is just a particular quantity of it. It
is not a unit of measure in the way that meters, seconds, and kilograms are.
Calculations performed with the number of moles of a substance could also be
performed with the number of particles of a substance. Based on this information, do
you think that the mole should be considered a base unit in the SI system? Explain why
or why not.

Answers

Answer:

Whyyy

Explanation:

The mole should be considered a base unit in the SI system because it is widely used in chemical calculations as a standard unit for counting the number of particles in a substance. The mole allows for easy and accurate calculation of the amount of substance, which is a crucial aspect in many chemical processes. In addition, the mole is defined as the number of entities in a substance, such as atoms, molecules, or ions, and its definition is based on Avogadro's constant. The mole also has practical applications in fields such as pharmacology and environmental science, where the measurement of a specific quantity of a substance is essential.

In conclusion, the mole is a necessary unit for the SI system of units due to its widespread use in chemical calculations and its important role in accurately measuring the amount of substance in a variety of scientific disciplines.

Which structural fragment would give rise to a characteristic triplet-quartet pattern in the 1H NMR spectrum? A. True or false

Answers

It is True that structural fragment would give rise to a characteristic triplet-quartet pattern in the 1H NMR spectrum.

A characteristic triplet-quartet pattern in the 1H NMR spectrum typically arises from the presence of a proton that is coupled to two neighboring protons. The splitting of the peak into a triplet arises from the coupling to the two neighboring protons, while the quartet arises from the splitting of each of the triplet peaks due to the coupling between the two protons. This pattern is also known as an ABX pattern, where A represents the peak of the proton that is not coupled to the other two protons, B represents the peak of the proton that is coupled to one of the neighboring protons, and X represents the peak of the proton that is coupled to both of the neighboring protons. This type of splitting pattern can be used to identify the presence of certain structural fragments, such as a methylene (-CH2-) group flanked by two different types of protons.

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if the rate of appearance of no2 is equal to 0.560 mol/min at a particular moment, what is the rate of appearance of o2 at that moment?

Answers

the rate of appearance of O2 at that particular moment would be 0.280 mol/min for  no2 is equal to 0.560 mol/min at a particular moment.

The balanced chemical equation for the reaction that produces NO2 and O2 would be helpful to answer this question. Assuming the reaction is:

2 NO → 2 NO2 + O2

The stoichiometry of the reaction tells us that for every 2 moles of NO that disappear, 2 moles of NO2 and 1 mole of O2 are produced. Therefore, the rate of appearance of O2 would be half the rate of appearance of NO2, or:

Rate of appearance of O2 = (0.560 mol/min) / 2 = 0.280 mol/min

So the rate of appearance of O2 at that particular moment would be 0.280 mol/min.

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draw the products formed when the following alkene is treated with o3 followed by zn, h2o. be sure to answer all parts.

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The given alkene can undergo ozonolysis in the presence of ozone (O3) followed by reduction with zinc (Zn) and water (H2O) to yield two products.

The ozonolysis reaction cleaves the double bond in the alkene and generates two carbonyl compounds, which can then be reduced by zinc to form aldehydes or primary alcohols depending on the reaction conditions.

The ozonolysis of the given alkene, 2-methyl-2-pentene, results in the formation of two carbonyl compounds: propanal and 2-methylpropanal. These carbonyl compounds can then undergo reduction with zinc and water to form the corresponding aldehydes or primary alcohols.

The reduction of propanal with zinc and water results in the formation of propan-1-ol, which is a primary alcohol. The reaction involves the addition of hydrogen atoms to the carbonyl group of propanal, followed by the removal of the resulting oxygen atom as water. The reduction of 2-methylpropanal with zinc and water results in the formation of 2-methylpropan-1-ol, which is also a primary alcohol. The reduction mechanism is similar to that of propanal, but with the addition of hydrogen atoms to the carbonyl group of 2-methylpropanal instead.

In summary, the products formed when 2-methyl-2-pentene is treated with ozone followed by zinc and water are propan-1-ol and 2-methylpropan-1-ol. These products are formed by ozonolysis of the alkene to generate carbonyl compounds, followed by reduction of the carbonyl compounds to primary alcohols with zinc and water. This reaction demonstrates the versatility of ozonolysis and reduction reactions in synthesizing aldehydes and primary alcohols from alkenes, which are important building blocks in organic chemistry.

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7) Using the following balanced equation 4 Fe(s) + 302(g) → 2Fe2O3(s)
a) How many moles of product would be produced by complete reaction of 0.15 moles of iron? (Be sure to show
your work including the mole ratio you used)

Answers

Answer:

0.075 moles

Explanation:

Looking at the balanced equation, 4 moles of Fe(s) react with 3 moles of [tex]O_{2}[/tex] to produce 2 moles of [tex]Fe_{2}O_{3}[/tex] (s). In other words, for every 4 moles of Fe(s) used, there are 2 moles of product. The mole ratio is therefore 4:2, or 2:1. In other words, you divide the moles of Fe by two to find the moles of product.

There are 0.15 moles of Fe, so the moles of product should be half of this according to the molar ratio.

0.15 / 2 = 0.075

Your answer is 0.075 moles.

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Which units express specific heat capacity? J/(gi°C), J/(giK), cal/(gi°C), cal/(giK)

Answers

C is the specific heat capacity, q is the amount of heat required, m is the mass of the substance, and T is the change in temperature. Jkg1K1 is the unit of specific heat capacity as a result.

Joules per gram per degree (J/goC) or calories per gram per degree (cal/goC) are two different ways to measure specific heat.Specific heat is expressed in SI units of J/kg•K. (On occasion, you might also find specific heat given in J/g•K.) 903 J/kg•K is the specific heat of aluminum. As a result, to elevate 1 kg of aluminum by 1 K, 903 J are needed. Typically, joules or calories per gram per degree Celsius are used as the units of specific heat.As an illustration, the specific heat of water is 1 calorie (4.186 joules) per gram per degree Celsius.The formula q = mcT, where m is the sample's mass, c is its specific heat, and T is the temperature change, can be used to Identify the heat that a sample (q) gains or loses.

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Draw the structure of cis-jasmone, a natural product isolated from jasmine flowers, formed by treatment of alkyne A with H2, in the presence of the Lindlar catalyst. Click the "draw structure" button to launch the drawing utility.

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The resulting product is cis-jasmone, which has the following structure:

        H

         |

CH3-CH-CH=CH-CH=O

         |

      CHO

The synthesis of cis-jasmone involves the hydrogenation of an alkyne in the presence of a Lindlar catalyst. Specifically, alkyne A is treated with hydrogen gas (H2) and a Lindlar catalyst, which is a type of palladium catalyst that selectively hydrogenates alkynes to cis-alkenes. The reaction conditions prevent complete reduction of the alkyne to an alkane. The molecule has a six-carbon ring with a double bond between carbons 2 and 3 and a carbonyl group (C=O) attached to carbon 6. The two methyl groups attached to carbons 1 and 2 are both on the same side of the ring, giving the molecule a cis configuration.

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