Answers
The first derivative of the given function is :
g'(x) = 24x²-24x-288
The second derivative of the function is:
g''(x) = 48x-24
The value of g''(-3) is:
-168
At x=-3 the graph of g(x) is concave down.
At x=-3 there is local maximum.
Given the function is g(x) = 8x³-12x²-288x
The first derivative of the function is:
g'(x) = 8(3)x³⁻¹ - 12(2)x²⁻¹ - 288(1)x¹⁻¹
g'(x) = 24x₂-24x-288
g'(X) = 24(x²-x-12)
Now, the second derivative of the function is :
g'(x) = 24(x²-x-12)
or x²-x-12 = 0
x²-4x+3x-12=0
x(x-4)+3(x-4) = 0
(x-4)(x+3)
x=4 and x=-3
now, g''(x) =24(2)x²⁻¹ - 24(1)x¹⁻° - 12(0)
g''(x) = 48x-24
Now find the local maximum and local minimum.
for x=4
g''(x) = 48x-24
g''(x) = 48(4)-24
g''(x) =168
Since, g''(x)>0 sox=4 is local minimum.
for x=-3
g''(x) = 48x-24
g''(x) = 48(-3)-24
g''(x) = -168
Since, g''(x)<0,so x=-3 is the local maximum.
Hence at x=-3 the graph of g(x) is concave down.
Hence we get the desired results.
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Related Questions
Order the sides of the triangle from shortest to longest. (HINT: You need to find the missing angle first!) 85 40° X V
Answers
To find the missing angle we use that the sum of the inner angles of a triangle must add up 180º:
[tex]\angle W+\angle V+\angle X=180º[/tex]We know W and V, so we clear X:
[tex]\angle X=180º-\angle W-\angle V=180º-80º-40º=60º[/tex]To order the sides, you don't need the size of them. Let's take a look at the angles:
So, since the angle with vertex on W is the widest, the opposite side to it (the segment XV) will be the longest. Then, the second angle is the one in X, so the second largest side will be it's opposite side (segment WV).
And finally but not last, the shortest side will be the oposite one to the narrowest angle, the one in V.
In summary, the sides ordered from shortest to longest are: c-a-b
A roofer earns $22 per hour for regular hours worked and $30per hour for overtime hours worked. If he puts in 40 hours of regular time during a certain week and he wishes to earn $1050, how many hours of overtime should he work?The roofer should work ___ hours of overtime.(Type an integer, proper fraction, or mixed number.)
Answers
The roofer should work 5 2/3 hours of overtime.
Explanation:Given:
Earnings for regular hours = $22 per hour
Earnings for overtime = $30 per hour
Time spent on regular hours = 40 hours
Total amount to be earned = $1050
To find:
The number of hours worked overtime
let the number of hours worked overtime = h
Earnings for regular hours (number of hours) + Earnings for overtime (number of hours) = 1050
[tex]\begin{gathered} 22(40)\text{ +}30(h)\text{ = 1050} \\ 880\text{ + 30h = 1050} \end{gathered}[/tex][tex]\begin{gathered} collect\text{ like terms:} \\ 30h\text{ = 1050 - 880} \\ 30h\text{ = 170} \\ \\ divide\text{ both sides by 30:} \\ h\text{ = 170/30} \\ h\text{ = 17/3 = 5}\frac{2}{3}\text{ hours} \end{gathered}[/tex]The perimeter of the figure is given. Find the length of the indicated side.?4x - 4Perimeter = 16x + 6The length of the indicated side is
Answers
Width = 4x + 7
Explanation:The perimeter of the rectangle shown = 16x + 6
The width of the rectangle = 4x - 4
Perimeter of a rectangle = 2(Length + Width )
16x + 6 = 2[ (4x - 4) x Width]
(16x + 6)/2 = (4x - 4) x width
8x + 3 = (4x - 4) x width
Width = 8x + 3 - (4x - 4)
Width = 8x - 4x + 3 + 4
Width = 4x + 7
One brand of cereal sells for $3.15 for 10 ounces. What is the unitprice per pound?a. $.31b. $5.04c. $ 3.49d. $50.40
Answers
Answer:
[tex]\begin{gathered} \\ B\colon\text{ \$5.04} \end{gathered}[/tex]Explanation:
Here, we want to get the unit price per pound
From the question, the brand sells for $3.15 per 10 ounces
Mathematically, 1 ounce is 0.0625 pound
Thus $3.15 is the price for 0.625 pounds (10 * 0.0625 pounds)
if $3.15 is for 0.625 pounds
$x will be for 1 pound
Mathematically:
[tex]\begin{gathered} 3.15\times1\text{ = 0.625}\times x \\ x\text{ = }\frac{3.15}{0.625} \\ x\text{ = \$5.04} \end{gathered}[/tex]hi please h3lp I have only 10 min to do this because it's due in 10 minutes and I've been trying to figure this out for a while
Answers
To graph the system
y ≤ 2x + 1
y < -x - 1
first, you have to graph the lines
y = 2x + 1
y = -x - 1
From the y-intercept and the slope, we know that the first line passes through the points:
(0, 1)
(0+1, 1+2) = (1, 3)
From the y-intercept and the slope, we know that the second line passes through the points:
(0, -1)
(0+1, -1-1) = (1, -2)
Next, we have to find if a point satisfies each equation or not, in order to know which region we have to shade. Taking for example the point (0, 0) and replacing it into the first inequality,
0 ≤ 2(0) + 1
0 ≤ 1
which is true, then we have to shade the region below the line y = 2x + 1
Replacing (0, 0) into the second inequality,
0 < -0 - 1
0 < -1
which is false, then we have to shade the region below the dotted line y = -x - 1
The final result is shown in the next picture.
This corresponds to graph X
A house has increased in value by 38% since it was purchased. If the current value is $345,000, what was the value when it was purchased?
Answers
The formula for calculating the percent change over time is:
[tex]\begin{gathered} p=\frac{N-O}{O}\cdot100 \\ \text{ Where} \\ p\text{ is the percent change } \\ N\text{ is the new value } \\ O\text{ is the old value} \end{gathered}[/tex]In this case, we have:
[tex]\begin{gathered} p=38 \\ N=345000 \\ O=x \end{gathered}[/tex][tex]\begin{gathered} p=\frac{N-O}{O}\cdot100 \\ 38=\frac{345000-x}{x}\cdot100 \\ \text{ Multiply by x from both sides} \\ 38x=x\cdot\frac{345000-x}{x}\cdot100 \\ 38x=(345000-x)100 \\ \text{ Divide by 100 from both sides} \\ \frac{38x}{100}=\frac{(345000-x)100}{100} \\ 0.38x=345000-x \\ \text{ Add x from both sides} \\ 0.38x+x=345000-x+x \\ 1.38x=345000 \\ \text{ Divide by 1.38 from both sides} \\ \frac{1.38x}{1.38}=\frac{345000}{1.38} \\ x=250000 \end{gathered}[/tex]AnswerThe value of the house when purchased is 250,000.
Makayla bought 1/4 pound of ham and 5/8 pound of turkey. How much more turkey did she buy
Answers
Solve each equation by using the method of your choice. Find exact solutions.
Answers
Given the quadratic equation:
[tex]16x^2-24x-27=0[/tex]To find the solutions for the given equation you have to apply the quadratic formula:
[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]Where
a is the coefficient of the quadratic term
b is the coefficient of the x-term
c is the constant of the equation
For this equation, a= 16, b= -24, and c= -27, replace the values into the formula:
[tex]\begin{gathered} x=\frac{-(-24)\pm\sqrt[]{(-24)^2-4\cdot16\cdot(-27)}}{2\cdot16} \\ x=\frac{24\pm\sqrt[]{576+1728}}{32} \\ x=\frac{24\pm\sqrt[]{2304}}{32} \\ x=\frac{24\pm48}{32} \end{gathered}[/tex]Solve the addition and subtraction separately to determine both possible values of x:
-Addition:
[tex]\begin{gathered} x=\frac{24+48}{32} \\ x=\frac{72}{32} \\ x=\frac{9}{4} \end{gathered}[/tex]-Subtraction
[tex]\begin{gathered} x=\frac{24-48}{32} \\ x=-\frac{24}{32} \\ x=-\frac{3}{4} \end{gathered}[/tex]The solutions of the quadratic equation are x=9/4 and x=-3/4
Question 2 of 1010 PointsWhich inequality below satisfies the solution set graphed on the following number line?
Answers
ANSWER
C. x² - x ≥ 6
EXPLANATION
Let's analyze the solution set graphed first. We can see that the values -2 and 3 are included in the set, and all values below -2 and above 3. So, the solution set is (-∞, 2] U [3, ∞).
To find which inequality satisfies this solution set we have to solve them. To do so, we will be using the quadratic formula:
[tex]\begin{gathered} ax^2+bx+c=0 \\ \\ x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} \end{gathered}[/tex]A. To solve this one, first, add x to both sides,
[tex]-x^2+x+6\geqslant0[/tex]Now, apply the quadratic formula to find the zeros. For this inequality, a = -1, b = 1, and c = 6
[tex]\begin{gathered} x=\frac{-1\pm\sqrt{1^2-4(-1)6}}{2(-1)}=\frac{-1\pm\sqrt{1+24}}{-2}=\frac{-1\pm\sqrt{25}}{-2} \\ \\ x_1=\frac{-1-5}{-2}=\frac{-6}{-2}=3 \\ \\ x_2=\frac{-1+5}{-2}=\frac{4}{-2}=-2 \end{gathered}[/tex]But in this case, the solution set is [-2, 3] - note that for any value outside this interval the inequality is false.
B. Similarly, apply the quadratic formula for a = -3, b = 3, c = 18,
[tex]\begin{gathered} x=\frac{-3\pm\sqrt{3^2-4(-3)18}}{2(-3)}=\frac{-3\pm\sqrt{9+216}}{2(-3)}=\frac{-3\pm\sqrt{225}}{-6}=\frac{-3\pm15}{-6} \\ \\ x_1=\frac{-3+15}{-6}=\frac{12}{-6}=-2 \\ \\ x_2=\frac{-3-15}{-6}=\frac{-18}{-6}=3 \end{gathered}[/tex]Again, the solution set is [-2, 3] since for any value outside the interval the inequality is not true.
C. Subtract 6 from both sides,
[tex]x^2-x-6\geqslant0[/tex]Apply the quadratic formula, with a = 1, b = -1, and c = -6,
[tex]\begin{gathered} x=\frac{-(-1)\pm\sqrt{(-1)^2-4\cdot1(-6)}}{2\cdot1}=\frac{1\pm\sqrt{1+24}}{2}=\frac{1\pm\sqrt{25}}{2}=\frac{1\pm5}{2} \\ \\ x_1=\frac{1+5}{2}=\frac{6}{2}=3 \\ \\ x_2=\frac{1-5}{2}=\frac{-4}{2}=-2 \end{gathered}[/tex]In this case, if we take any value between -2 and 3, for example 1,
[tex]\begin{gathered} 1^2-1\ge6 \\ \\ 0\ge6 \end{gathered}[/tex]We can see that the inequality is false, while if we take a value greater than 3 or less than -2, for example, -5,
[tex]\begin{gathered} (-5)^2-(-5)\ge6 \\ \\ 25+5\ge6 \\ \\ 30\ge6 \end{gathered}[/tex]We can see that the inequality is true.
Hence, we can conclude that inequality C satisfies the solution set graphed.
Find the area of this figure. Round your answer to the nearest hundredth. Use 3.14 to approximate A = [ ? ] ft.
Answers
The area of the figure = Area of the Triangle + Area of the semi-circle
Area of the Triangle = 1/2 x b x h
Base = 6 feet
Height = 8 feet
Area of the Triangle = 1/2 x 6 x 8 = 48/2 = 24 feet^2
Area of the circle = pi x r ^2 radius = 8/2 = 4 ft
= 3.14 x 4 x 4
= 50.24 feet^2
Total area = 24 + 50.24 = 74. 24 feet ^2
round to nearest tenth 3.5÷2.29
Answers
Given
[tex]3.5\div2.29=1.528[/tex]Round to the nearest tenth, this is:
[tex]1.5[/tex]Answer: 1.5
The regulation height of a basketball hoop is 10 feet. Let the location of thebasket be represented in the coordinate plane by the point (0, 10). Let the ballbe thrown at a 45° angle with the ground.1. Suppose Nancy is standing a horizontal distance of 10 feet from thebasket at the point (-10, 0), and she shoots a basket from 6 feet in theair with an initial velocity of 22 ft/s.a. Write parametric equations that represent the ball's motion throughthe air.b. Graph the parametric equations on your calculator in an appropriatewindow and sketch the results below.
Answers
SOLUTION:
a. The parametric equations that represent the balls motion is;
[tex]\begin{gathered} x(t)=x_0+(v_0cos\theta)t \\ y(t)=y_0+(v_0sin\theta)t+0.5gt^2 \end{gathered}[/tex]Inserting the values;
[tex]\begin{gathered} x(t)=-10+(22cos45)t \\ y(t)=6+(22sin45)t+0.5(-32)t^2 \end{gathered}[/tex]Simplifying, we have;
[tex]\begin{gathered} x(t)=15.56t-10 \\ y(t)=-16t^2+15.56t+6 \end{gathered}[/tex]b. The graph of the parametric equation is given below;
1. Luna and Miles want to start selling baked goods to raise money for their gymnastics team to get new gear. Luna is baking double chocolate brownies with white chocolate chips and is selling them for $4 for each brownie. Miles is making oatmeal raisin cookies because that is his favorite and is selling them for $2 per cookie. Between the two of them they would like to raise $100. Write an equation in standard form and y intercept form to express the scenario. Identify one possible solution and explain what it means.
2.We can model real world situations given an equation, a table, or a graph. Identify a time when it would be better to use a table than a graph and explain why.
Answers
Using a system of equations, it is found that:
1.
Equation in standard form: 4x + 2y = 100.Equation in y-intercept form: y = -2x + 50.One possible solution is x = 10 and y = 30, meaning that she can sell 10 chocolate chips and 30 brownies.2. Tables are good for summarized data, that is, containing a few pairs of input - outputs solutions.
What is a system of equations?A system of equations is when multiple variables are related, and equations are built to find the numeric values of each variable, according to the relations built in the problem.
In the context of this problem, the variables are given as follows:
Variable x: number of chocolate chips sold.Variable y: number of cookies sold.Considering that they want to raise $100, and the prices of $4 for each chocolate chip and of $2 for each brownie, the equation is:
4x + 2y = 100.
In intercept form, the equation is given by:
2y = 100 - 4x
y = -2x + 50.
When x = 10, the solution of the system for y is given as follows:
y = -2(10) + 50 = -20 + 50 = 30.
Hence one possible solution is (x,y) = (10,30), meaning that she can sell 10 chocolate chips and 30 brownies.
In this question, we are given pairs of input-output that satisfy the given condition, hence tables are more appropriate than graphs.
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Answer:
1. 100=4x+2y and y = -2x+50
X=19, and Y=12
2. Graphs are better for showing trends. tables are better for showing precise data.
Step-by-step explanation:
Luna makes $4 per cookie, so her equation for her income is 4x. Miles makes $2 per cookie, so his equation is 2y. Since they want to make $100, that means that 100 = 4x+2y. Then put this in y-inercept form. Or, y=-2x+50
So now I need to find a solution for y = -2x+50, or 100=4x+2y. One way to do this is through substitution. We can use 12 as the y input.
This would mean that miles sold 12 brownies. Then, ---> = 19.
Therefore, a solution is x=19 and y=12. Meaning Luna sold 19 cookies and Miles sold 12 cookies. (19,12)
expand the square of a binomial (9y+2)^2
Answers
We will solve the following:
[tex](9y+2)^2=81y^2+36y+4[/tex]***Explanation***
We will have that in order to expand a polynomial of the form:
[tex](a+b)^2[/tex]We will proceed by using the following rule:
[tex](a+b)^2=a^2+2ab+b^2[/tex]In our case the solution for the given polynomial is [Step by step]:
[tex](9y+2)^2=(9y)^2+2(9y)(2)+(2)^2[/tex][tex]\Rightarrow(9y+2)^2=81y^2+36y+4[/tex]From the given information. Write the recursive and explicit functions for each arithmetic sequence. Use these terms please; recursive f(1) = first term, f(n) = pattern+f(n-1). Explicit: y = pattern*x + 0 term. work backwards to find 0 term
Answers
An arithmetic sequence has the form:
[tex]f(n)=f(1)+d(n-1)[/tex]where d is the common difference.
For this sequence the common difference is 3 and the first term is:
[tex]f(1)=3[/tex]Plugging this values in the general expression we have:
[tex]\begin{gathered} f(n)=3+3(n-1) \\ f(n)=3n-3+3 \\ f(n)=3n \end{gathered}[/tex]Therefore the sequence is:
[tex]f(n)=3n[/tex]Now, from this expression we can determine the value of the zeroth term:
[tex]\begin{gathered} f(0)=3(0) \\ f(0)=0 \end{gathered}[/tex]Hence the zeroth term is:
[tex]f(0)=0[/tex]A die is toss three times let X be the sum of three numbers obtainedDetermine whether the random X has a binomial distribution if so take the number of trails N . If it doesn’t explain why
Answers
The given experiment is a die that is tossed three times.
X is the sum of the three numbers obtained.
You need to determine if the random X variable has a binomial distribution.
First, we need to understand what makes a random variable has a binomial distribution. There are 4 conditions to be met:
1. There are a fixed number of trials N
2. Each trial has only two possible outcomes: success or failure
3. The probability of success is equal in each trial
4. The trials are independent.
In this case, condition 1 is met, but condition 2 is not met, since in each trial we can obtain 6 different numbers, then there are not only two possible outcomes, but 6, then the sum of the three numbers has more than two possible outcomes. So, the random X variable doesn't have a binomial distribution.
It takes you 52 seconds to walk from the first (ground) floor of a building to the third floor. How long will it take you to walk from the first floor to the sixth floor (at the same pace, assuming all floors have the same height)?
Answers
Can you please help me translate the argument into symbolic form?
Answers
Let p be: John goes to the beach
Let q be: He will go surfing.
Then in symbolic form, the argument becomes:
[tex]\begin{gathered} p\Rightarrow q \\ p \\ ----------- \\ \therefore q \end{gathered}[/tex]p ⇒ q
p
---------------------
∴ q
An argument is valid if the conjuction of the premises implies the conclusion.
p | q | p ⇒ q | (p ⇒ q) ∧ p | [(p ⇒ q) ∧ p] ⇒ q
---------------------------------------------------------------------\
F | F | T | F | T
F | T | T | F | T
T | F | F | F | T
T | T | T | T | T
The table above shows that the argument is a tautology.
Hence, the argument is valid
Given: 14-2(x + 8) = 5x - (3x - 34); Prove: x = -9
help pls lol
Answers
The value of x is -9.
Here the equation is :
14 - 2(x + 8) = 5x -( 3x - 34)
We have to prove that x = -9.
From the above-given equation, we have to find the value of x.
So by evaluating the equation we have:
14 -2(x +8) = 5x - (3x - 34)
= 14 - 2x - 16 = 5x - 3x + 34
= -2 -2x = 2x + 34
= 4x = -34 - 2
= 4x = -36
=x = -9
Therefore the value of the above-given equation x = -9.
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The slope of this line and the unit rate are the same.Price of Cookies at Bakery141210Find the unit ratefor the number ofcookies per dollar008Number of Cookies464[?] cookies$[ ]22 4 6 8 10 12 146 8Price ($)
Answers
SOLUTION
We want to find the unit rate for number of cookies per dollar. This can be done using the diagram below
So the unit rate is calculated thus
[tex]\begin{gathered} \text{Unit rate = }\frac{rise\text{ }}{\text{run}} \\ =\frac{14\text{ cookies }}{7\text{ dollars }} \\ =\frac{14}{7} \\ 2\text{ cookies per dollar} \end{gathered}[/tex]Hence the answer is 2
A scientist adds drops of liquid to a test tube. The test tube has marks every 1/5 ml.
Each drop contains 0.14 mL. Between which, two marks on the test tube will the liquid be after the sixth drop is added?
a. 1/5 and 2/5, between 0.2 and 0.4 mL's
b.2/5 and 3/5, between 0.4 and 0.6 ml's
c.3/5 and 4/5, between 0.6 and 0.8 mL's
d. 4/5 and 5/5, between 0.8 and 1 ml
Answers
The marks on the test tube where the liquid will be after the sixth drop is added is d. 4/5 and 5/5, between 0.8 and 1 ml.
How to calculate the value?From the information, the scientist adds drops of liquid to a test tube. The test tube has marks every 1/5 ml while each drop contains 0.14 mL.
In this case, it was stated that each drop is about 0.14mL. Therefore, it's important to note that the value of the 6th drop will be:
= Number of drops × Amount on each drop
= 6 × 0.14
= 0.84
In this case, 0.84 is between 0.8 and 1ml.
Therefore, the correct option is D.
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An aircraft factory manufactures airplane engines. The unit cost C (the cost in dollars to make each airplane engine) depends on the number of engines made. Ifx engines are made, then the unit cost is given by the function C(x) = 0.5x ^ 2 - 150x + 26, 777 . How many engines must be made to minimize the unit cost?Do not round your answer.number of airplane engines________
Answers
EXPLANATION:
We are given the unit cost to produce x number of airplanes as follows;
[tex]C(x)=0.5x^2-150x+26777[/tex]However, to minimize the unit cost, we need to first take the derivative of the cost function and then find its value at zero.
Thuis is shown below;
[tex]C(x)=0.5x^2-150x+26777[/tex][tex]\frac{d}{dx}=2(0.5)x^{2-1}-1(150)x^{1-1}+0[/tex]Note that for a derivative, the constant term is always equal to zero. We can now simplify what we have above;
[tex]\frac{d}{dx}=1x^1-150[/tex][tex]\frac{d}{dx}=x-150[/tex]We now set this equal to zero and simplify;
[tex]x-150=0[/tex]Add 150 to both sides;
[tex]x=150[/tex]ANSWER:
Therefore, to minimize the unit cost, 150 engines must be made.
compare the ratio of 3:5 and 4:7
Answers
Answer:
Step-by-step explanation:
The least common multiple of the denominators 5 and 7 is 35. Make the denominators of the fractions as 35 using multiplication. Compare the numerators. So, 3 : 5 is greater than 4 : 7.
Hope this helps!
What is anequation of the line that passes through the points (-6,5) and (6,-7)?
Answers
The line that passes through the given point may be stated as
y - y1 = m(x - x1)
where (x1, y1) and (x2, y2) = (-6,5) and (6,-7)
m = (y2 - y1)/(x2 - x1)
= (-7 - 5)/(6 - -6)
= -12/12
= -1
Hence the equation of the line that passes through the given points is
(y - 5) = -1(x - -6)
y - 5 = - x - 6
y = -x - 6 + 5
y = -x - 1
6.
A mug is 3/7
full. The mug contains 1/2
of a cup of water. Find
the capacity of the mug. Write the
answer as a fraction or mixed
number in simplest form.
contains
Answers
The capacity of the mug is 7/6 cups.
What is the capacity of the mug?
Given,
A mug is 3/7 full.
The mug contains 1/2 of a cup of water.
Solution:
Let x be the water.
Water the mug has = 3/7 of x
= 3/7x
Since the water in the mug is 1/2 cup,
3/7x = 1/2
x = 1/2 ÷ 3/7
= 1/2 × 7/3
= 7/6
Therefore,
The capacity of the mug is 7/6 cups.
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David buys milk and lemons at the store.
.
. He pays a total of $40.01.
• He pays $2.89 for the milk.
• He buys 8 bags of lemons that each cost the same amount.
.
Which equation could be used to determine b, how much each bag of lemons costs?
Can someone tell
Me the equation could be used yo determine b, how much each bag of lemon cost
Answers
I'm not sure the right equation that we need to used for this problem.
The solution is, :
8x = 40.01 -2.89, is the equation could be used to determine b, how much each bag of lemons costs.
What is equation?An equation is a mathematical statement that is made up of two expressions connected by an equal sign. In its simplest form in algebra, the definition of an equation is a mathematical statement that shows that two mathematical expressions are equal.
here, we have,
given that,
David buys milk and lemons at the store.
. He pays a total of $40.01.
• He pays $2.89 for the milk.
• He buys 8 bags of lemons that each cost the same amount.
Cost of 1 bag of lemons = $ x
Cost of 8 bags of lemons = 8 *x = 8x
Cost of 8 bags of lemons = Total cost - cost of the eggs
8x = $40.01 - $2.89
so, 8x = 40.01 -2.89, is the equation.
Hence, The solution is, :
8x = 40.01 -2.89, is the equation could be used to determine b, how much each bag of lemons costs.
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How many different permutations can be formed using all the letters in the word COLORADO?
Answers
Ok, the number of different permutations are:
8!/3! (Considering the three O's)
A bird flies downward 2 feet per second for 6 seconds. Then the bird flies up 7 feet. Which equation represents the total distance the bird travels
Answers
The equation that represents the total distance the bird travels would be; d = 1/3.
What is an equation?An equation is an expression that shows the relationship between two or more numbers and variables. A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be one degree.
Given that bird flies downward 2 feet per second for 6 seconds. Therefore, the bird flies up 7 feet.
Since, a bird flies 2 feet = 1 second
Thus, for 6 seconds = 6 x 2 = 12 feet.
for 6 seconds = 12 feet.
Similarly, the bird flies up 7 feet = 6/12 x 7
= 42/12 = 3.5
Hence, the equation that represents the total distance the bird travels would be; d = 2/6 = 1/3.
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find the basic feasible solution at this point by setting the non-basic variables equal to 0
Answers
To determine wether a variable is a basic variable or not in a simplex tableu we have to look for the variables which have a one in a column and all the other values are zero, the variables that fullfil this condition are the basic ones.
Looking at the tableu we notice that the basis variables are: x2, s5 and Z. Now that we know that, we look at each row where the number one appear and put all the other variables equal to zero, with this in mind we conclude that:
[tex]\begin{gathered} x_1=0 \\ x_2=17 \\ s_3=0 \\ s_4=0 \\ s_5=29 \\ Z=12 \end{gathered}[/tex]I need help in math can you help me please
Answers
Given that the triangles are corresponding triangles, then ∠B ≅ ∠E, therefore:
m∠B = m∠E
Replacing with data:
3v + 4 = 8v - 6
3v is adding on the left, then it will subtract on the right
6 is subtracting on the right, then it will add on the left
4 + 6 = 8v - 3v
10 = 5v
5 is multiplying on the right, then it will divide on the left
10/5 = v
2 = v
Then, the measure of B is:
m∠B = 3v + 4 = 3(2) + 4 = 10°
The measure of angle B is 10°
