Answers
Answer:
Fluorobenzene
Explanation: Fluorobenzene is an organic compound, which is a derivative of benzene. It has a fluorine atom attached to one of the carbon atoms in the benzene ring. It appears as a colorless liquid and has a slightly sweet odor. Fluorobenzene is used as a solvent and catalyst in various chemical reactions. It is also used in the production of agrochemicals and pharmaceuticals. Due to its high solubility in water, it can contaminate groundwater and pose a risk to human health and the environment.
Related Questions
Assuming that ground water flow does follow the contours of the land, is it possible that there are two sources of contamination? What would you expect to find if all three companies had leaking storage tanks and were actual sources of contamination?o
Answers
If ground water flow follows the contours of the land, it is possible that there are two sources of contamination.
This can occur if there are multiple locations of contamination that are not connected through the flow of groundwater. For example, if two companies had leaking storage tanks on opposite sides of a hill, the contaminants from each site could flow in different directions and not mix with each other.
If all three companies had leaking storage tanks and were actual sources of contamination, we would expect to find that the groundwater near each company contained contaminants associated with that company's stored chemicals. The contaminants may be different for each company, depending on the type of chemicals stored.
However, if the contamination has been ongoing for a long time, the chemicals may have mixed together in the groundwater, making it difficult to identify the specific source of contamination for each chemical. In this case, further investigation would be needed to determine the specific sources and extent of contamination from each company.
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in general, which of the following statements about electron-pair geometries is true? question 14 options: a) they maximize the space between valence electrons to minimize the repulsion between them. b) they maximize the polarity of valence electrons to minimize the attraction between them. c) they maximize the space between
Answers
They maximise the distance between valence electrons to reduce the repulsion between them, which is option an in the correct response. This is so because the idea behind electron-pair geometries is to reduce valence electron repulsion.
By increasing the distance between them, which decreases the repelling power of the interactions between electrons, this is accomplished.
Because they reduce electron repulsion and enable molecules to adopt their most stable form, electron-pair geometries are used to anticipate the structure of molecules.
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A 2.26 gg lead weight, initially at 11.1 ∘C∘C, is submerged in 7.45 gg of water at 52.2 ∘C∘C in an insulated container.
Answers
Answer:
The temperature of the water and lead weight is 31.0°C.
Explanation:
To solve this problem, we can use the formula:
q = mcΔT
where q is the heat transferred, m is the mass, c is the specific heat, and ΔT is the change in temperature.
First, let's calculate the heat transferred from the water to the lead weight:
q1 = mcΔT = (7.45 g)(4.184 J/g°C)(52.2°C - T) where T is the final temperature of the water and lead weight
q2 = mcΔT = (2.26 g)(0.128 J/g°C)(T - 11.1°C)
Since the container is insulated, the heat transferred from the water to the lead weight is equal to the heat transferred from the lead weight to the water:
q1 = q2
(7.45 g)(4.184 J/g°C)(52.2°C - T) = (2.26 g)(0.128 J/g°C)(T - 11.1°C)
Simplifying and solving for T:
T = 31.0°C
Therefore, the final temperature of the water and lead weight is 31.0°C.
how many grams of MgCl2 are contained in 0.50 L kc a 1.5 m solution?
Answers
0.50 L of a 1.5 m solution contains 71.4 grams of MgCl2.
To solve this problemThe equation moles of solute = molarity x volume (in liters) can be used.
When converting to grams, we may use the molar mass of the MgCl2 to determine how many moles there are in the solution.
MgCl2 has a molar mass of roughly 95.21 g/mol.
The volume must first be changed from liters to milliliters:
0.50 L = 500 mL
Next, we may determine how many moles of MgCl2 are present in the solution:
moles of MgCl2 = molarity x volume (in liters)
moles of MgCl2 = 1.5 mol/L x 0.50 L
moles of MgCl2 = 0.75 moles
Finally, we can figure out how much MgCl2 is present in the solution:
mass of MgCl2 = moles of MgCl2 x molar mass
mass of MgCl2 = 0.75 moles x 95.21 g/mol
mass of MgCl2 = 71.4 grams
Therefore, 0.50 L of a 1.5 m solution contains 71.4 grams of MgCl2.
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40n and 53n what is the magnitude of the net force on the crate
Answers
The magnitude of the net force on the crate is 13 N.
Generally, in science, the word 'force' has a very precise meaning. Force is usually described as a push or a pull.
Generally the magnitude of the force is described as the number which is used to represent the strength of the force. Let's consider an example, suppose the force is equal to 10 N towards the east direction and 'towards east' indicates direction while '10' indicates the magnitude of the force. So we can say that basically, Magnitude is the 'value' or 'amount' of any physical quantity.
Here, assuming that the two forces are acting opposite,
Net force = 53 N - 40 N = 13 N
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Calculate the molar solubility, S , of CuS if it has a Ksp value of 6×10−37.
Answers
The molar solubility of CuS is 7.8 x 10⁻¹⁹ M.
The solubility product expression for CuS is:
Ksp = [Cu²⁺][S²⁻]Since CuS dissociates to form one Cu²⁺ ion and one S²⁻ ion, the molar solubility of CuS can be represented as x. Therefore, at equilibrium:
[Cu²⁺] = x[S²⁻] = xSubstituting these values in the Ksp expression:
Ksp = x²Solving for x, we get:
x = √(Ksp) = √(6 x 10⁻³⁷) = 7.8 x 10⁻¹⁹ MTherefore, the molar solubility of CuS is 7.8 x 10⁻¹⁹ M.
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The complete question is:
Calculate the molar solubility, S , of CuS if it has a Ksp value of 6×10⁻³⁷.
The nitrogen pressure at the Venusian surface is 2050 torr and the atmosphere of Venus is 3.0 mole% N2. What is the surface pressure on Venus in atm?
Answers
P = nRT/V
where P is the pressure, n is the number of moles, R is the gas constant, T is the temperature, and V is the volume.
First, we'll find the number of moles of nitrogen in the atmosphere:
n(N2) = 3.0/100 x n(total)
where n(total) is the total number of moles in the atmosphere.
Next, we'll rearrange the ideal gas law to solve for P:
P = nRT/V
We can assume that the volume is 1 mole of gas at STP, which is 22.4 L. The temperature on Venus is around 735 K. The gas constant is 0.08206 L atm/mol K.
Plugging in the values, we get:
P = (0.03)(0.08206)(735)/22.4
P = 0.679 atm
Therefore, the surface pressure on Venus is approximately 0.679 atm.
Numbers placed in front of formulas in an aquation are called
Answers
Why are some Hydro flow rolling pins HFO refrigerants classified as a a2l
Answers
Hydro flow rolling pins HFO refrigerants classified as a A2L because they contain a fluorine.
Some Hydro Fluoro Olefin (HFO) refrigerants are classified as A2L according to the ASHRAE (American Society of Heating, Refrigerating, and Air-Conditioning Engineers) classification system for refrigerants. The "A" in A2L stands for "lower toxicity," and the "2" indicates "lower flammability."
The classification of refrigerants is based on their potential toxicity and flammability. A2L refrigerants are considered to have lower toxicity and lower flammability compared to other types of refrigerants. They have specific thermodynamic properties that make them suitable for use in refrigeration and air conditioning systems.
Fluorine makes HFO refrigerants less flammable than hydrochlorofluorocarbons (HCFCs) and hydrofluorocarbons (HFCs). which are highly flammable. A2L refrigerants have lower global warming potential (GWP) and ozone depletion potential (ODP), which makes them a more sustainable choice for certain applications.
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Hydro flow rolling pins HFO refrigerants are a type of refrigerant used in air conditioning systems. The 'a2L' is a safety classification from ASHRAE that indicates these refrigerants are mildly flammable but have lower flammability. Such classifications are used for safety considerations.
Explanation:The Hydro flow rolling pins HFO refrigerants are designed for use in refrigeration and air conditioning systems. An HFO refrigerant is a hydrofluorolefin refrigerant; they are a new class of refrigerants that have a very low planet-warming potential.
The designation a2L is actually a safety classification set by ASHRAE (American Society of Heating, Refrigerating and Air-Conditioning Engineers) and it means that these refrigerants are mildly flammable but exhibit lower flammability. The '2' indicates that the refrigerant has low flammability and the 'L' means it has a lower burning velocity. These classifications inform technicians and engineers about the safety considerations they need to be aware of when handling and working with these substances.
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Hydrazine, N2H4, reacts with oxygen to form nitrogen gas and water.
N2H4(aq)+O2(g)⟶N2(g)+2H2O(l)
If 3.45 g of N2H4 reacts with excess oxygen and produces 0.650 L of N2, at 295 K
and 1.00 atm, what is the percent yield of the reaction?
Answers
Four peripheral hydrogen atoms and two singly-bonded nitrogen atoms make up the molecule of hydrazine.
Thus, It is a colourless, poisonous irritant and sensitizer in its anhydrous form, which harms the central nervous system and causes symptoms as severe as tumours and convulsions.
In addition to having a strong reducing agent that makes it highly explosive, hydrazine has a strong smell that is similar to that of ammonia.
Given this, it appears odd that over 100,000 metric tonnes of the substance are produced annually throughout the world. But hydrazine does have an impact on our daily activities. It can save our lives, give us food and clothing, keep us warm, and even transport us to the moon. It even has the ability to go back in time.
Thus, Four peripheral hydrogen atoms and two singly-bonded nitrogen atoms make up the molecule of hydrazine.
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What is the numerical value of Kc
for the following reaction if the equilibrium mixture contains 0.032 M
N2O4 and 0.24 M NO2?
N2O4(g)⇌2NO2(g)
Answers
Kc = [NO2]^2 / [N2O4]
Where [NO2] and [N2O4] are the molar concentrations of NO2 and N2O4, respectively, at equilibrium.
Substituting the given equilibrium concentrations into the expression for Kc, we get:
Kc = (0.24 M)^2 / (0.032 M) = 1.8 M
Therefore, the numerical value of Kc for the given reaction, when the equilibrium mixture contains 0.032 M N2O4 and 0.24 M NO2, is 1.8 M.
a reaction between 1.7 moles of zinc iodide and excess sodium
Answers
Answer: I got you fam
Explanation:
The formula is Na2CO3 + ZnI2 → 2NaI + ZnCO3
Or -5.19
What inference can be drawn from the graph? a graph of reactant and product concentration vs. time; a red curve shows the reactant decreasing and a blue curve shows the product concentration increasing over time; the two curves do not intersect; the chemical equation shows A + B reacting to produce C + D A. The reaction between A and B is reactant favored. B. The amount of product is greater than the amount of reactant. C. The reaction uses all its reactants to form products. D. The reaction reaches equilibrium at 1.5 seconds. E. The amount of reactants is highest at equilibrium.
Answers
The reaction between A and B is reactant favored. This inference can be drawn from the graph.
Chemical reactions occur all around us, including in our body's digestion of food and the creation of the sunlight's light. Understanding both chemical and physical alterations is crucial before starting any chemical reactions. The best illustration of a chemical and physical alteration is a burning candle. The reaction between A and B is reactant favored. This inference can be drawn from the graph.
Therefore, the correct option is option A.
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The heat of fusion of water is 79.9 cal/g. If a 7.2 g piece of ice melts in 105 g of water at 34.3 deg C in an insulated bottle, what is the final temperature of the water?
The heat of fusion of water is 79.9 cal/g. If a 7.2 g piece of ice melts in 105 g of water at 34.3 deg C in an insulated bottle, what is the final temperature of the water?
Type your answer...
Answers
The heat of fusion of water is 79.9 cal/g. If a 7.2 g piece of ice melts in 105 g of water at 34.3 deg C in an insulated bottle, 35071.6 °C is the final temperature of the water.
The physical concept of temperature indicates in numerical form how hot or cold something is. A thermometer is used to determine temperature. Thermometers are calibrated using a variety of temperature scales, which historically defined distinct reference points or thermometric substances.
The most popular scales were the Celsius scale, sometimes known as centigrade, with the unit symbol °C, the scale of Fahrenheit (°F), or the Kelvin scale (K), with the latter being mostly used for scientific purposes.
Δ T = T(initial) - T(final)
T(final)= m × c × q - T(initial)
T(final)= 79.9 x 4.184 x 105 - 30.0
T(final)= 35071.6 °C
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How many years passed between the first man on the Moon and the first US woman in space?
Answers
It took 14 years between the first man on the Moon and the first US woman in space.
What is space exploration?The use of astronomy and space technology to explore outer space is known as space exploration. While astronomers use telescopes to explore space, physical exploration is carried out by both uncrewed robotic space probes and human spaceflight.
Understanding gravity, the magnetosphere, the atmosphere, fluid dynamics, and the geological evolution of other planets, for example, has come from studying the solar system.
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2.5 mL of a 0.150 M solution is diluted with 2.5 mL of water. What is the concentration of the new solution?
Answers
The new concentration of the solution can be gotten as 0.075 M.
Dilution formula for solutionsThe formula that we should use is;
C1V1 = C2V2
where:
C1 = initial concentration of the solution (in units of mass/volume, moles/liter, or other concentration units)
V1 = initial volume of the solution
C2 = final concentration of the solution after dilution
V2 = final volume of the solution after dilution
We have to note that;
C1V1= C2V2
Thus we have that;
2.5 * 0.150 = 5 * V
V = 0.075 M
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A soft drink contains 33g of sugar in 349g of H2O. What is the concentration of sugar in the soft drink in mass percent?
.
Answers
A soft drink contains 33g of sugar in 349g of H[tex]_2[/tex]O. 14.3% is the concentration of sugar in the soft drink in mass percent.
One approach to indicate the concentration of any dissolved component in a solution is by mass percentage. Mass percentage is the ratio of the total weight of a compound in a solution to the overall mass of the solution, expressed in percentages.
In order to express the mass percent of a solution, the grammes of solute are divided by the grammes of solution, and the result is multiplied by 100. As long as you use a comparable number for both the component and solute mass.
Mass percent = (mass of solute/mass of solute+ mass of solvent)×100
= ( 33/ 33+ 349)×100
=14.3%
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Does anyone have the Labs: Acid and Bases, lab report. I will give brainliest.
Answers
A variety of lichen was used to create the natural acid-base indicator known as litmus.
Since we can't taste everything to determine if it constitutes an acid or a base, litmus paper is essentially an indicator that is used to differentiate acids from bases. It is also known as an acid-base indicator since it can detect the presence of either a base or an acid in a solution.
Litmus is combined with wood cellulose paper to create a litmus paper. The lichen plants that are used to make the purple dye known as litmus are classified as members of the Thallophyta division. A variety of lichen was used to create the natural acid-base indicator known as litmus. You can determine whether a variety of solutions are bases or acids by testing them with red and blue coloured litmus paper.
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Read the passage and answer the question.
In 2000, when paleontologist Paul Sereno led an expedition into Ténéré desert in Niger looking for the fossils of dinosaurs and ancient crocodiles, the photographer Mike Hettwer wandered away from the group to take pictures of some dunes near the main dig site. The photographer quickly found bones sticking out of the dunes, but they were human bones, not the prehistoric reptile bones the group had been looking for. However, the group was not going to pass up such an amazing discovery.
During the site excavation, the paleontologists found dozens of gravesites. Some of them held skeletal remains and potsherds with wavy lines etched in them. The scientists named this group the Kiffians. The others held skeletal remains that indicated a taller group of people, and their potsherds were decorated with patterns of dots. The scientists named this group the Tenerians. The graves also contained tools and beads made from stones or bones, as well as refuse heaps containing the bones of the animals the people living in the area had consumed. Some of the graves didn't contain any pottery so it was a mystery which group they belonged to. It was also not known when these people lived in the desert or how they survived.
The carbon-14 dating revealed that the Kiffians lived in the area around 9,700 years ago, and then the area was abandoned until the Tenerians lived in the area 7,000 years ago. The scientists want to reconstruct what the land looked like when it was inhabited, as well as understand why there was about a 2,000-year-gap during which nobody lived in the area.
The scientists hypothesize that the two civilizations lived around a lake that dried up during periods of drought and then eventually reformed. The changing lake led people to move, depending on if they had a water source or not.
How can scientists use radiometric dating to reconstruct the geologic history of the area to support or reject their hypothesis of a disappearing and reappearing lake? What is a tool that scientists can use to ensure that their radiometric dating is accurate?
Answers
Answer & Explanation:
Scientists can use radiometric dating to reconstruct the geologic history of the area and support or reject their hypothesis of a disappearing and reappearing lake by analyzing the sediments and other geological features present in the area. Radiometric dating, such as carbon-14 dating, can determine the age of the sediments, fossilized remains, and other materials. By analyzing the age and composition of these materials, scientists can track changes in the environment over time, including periods of drought or increased precipitation that could cause a lake to dry up or reform.
To ensure the accuracy of their radiometric dating, scientists can use calibration methods, such as cross-dating with other dating techniques like dendrochronology (tree-ring dating), or comparing their results with well-dated samples from similar or nearby environments. This can help validate the radiometric dating results and provide more confidence in the reconstructed geologic history and any conclusions drawn from it regarding the presence or absence of a lake in the area at different times.
Given the reaction:
If there are initially 14.2 moles of iron (III) nitrate nonahydrate, how many moles of steam (water vapor) will be produced?
Answer in mol.
Answers
Total, 127.8 moles of the steam (water vapor) will be produced.
Iron(III) nitrate nonahydrate, or Fe(NO₃)₃·9H₂O, is a compound that contains iron (III) cations (Fe³⁺) and nitrate anions (NO₃⁻) combined with nine water molecules (H₂O) per formula unit. The nine water molecules are referred to as "nonahydrate," which indicates that there are nine water molecules associated with each formula unit of Fe(NO₃)₃. This compound is also commonly known as ferric nitrate nonahydrate.
Balanced equation for the given reaction is;
Fe(NO₃)₃·9H₂O(s) → Fe(NO₃)₃(s) + 9H₂O(g)
According to the equation, one mole of Fe(NO₃)₃·9H₂O produces 9 moles of water vapor (H₂O) when it undergoes the reaction. Therefore, if there are initially 14.2 moles of Fe(NO₃)₃·9H₂O, the number of moles of water vapor (H₂O) produced will be;
14.2 moles of Fe(NO₃)₃·9H₂O × 9 moles of H₂O per 1 mole of Fe(NO₃)₃·9H₂O = 127.8 moles of H₂O
Therefore, 127.8 moles of water vapor will be produced.
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the process of dissolved solute particles being surrounded by water molecules in an aqueous solution is called
Answers
The process of dissolved solute particles being surrounded by the water molecules in an aqueous solution is called solvation or hydration.
Solvation occurs when water molecules surround and interact with solute particles, usually ions or polar molecules, forming a stable solution. The water molecules surround the solute particles, with their polar ends facing the solute, creating a layer of water molecules around the solute particles, effectively dispersing and stabilizing them throughout the solution.
Solvation is a key process in many chemical and biological reactions that occur in aqueous solutions, as it helps to facilitate the dissolution of solutes and influences their properties and behavior in solution.
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--The given question is incomplete, the complete question is
"The process of dissolved solute particles being surrounded by water molecules in an aqueous solution is called ----------- ."--
Determine the number of moles in 100,0 g S
Answers
The number of moles in 100g of Sulphur is 3.13 moles.
How to calculate number of moles?The number of moles in a substance can be calculated by dividing the mass of the substance by its molar mass as follows:
moles = mass ÷ molar mass
According to this question, there are 100g of Sulphur. Sulphur has an atomic mass of 32g/mol. The moles of this element can be calculated as follows;
moles = 100g ÷ 32g/mol
moles = 3.13moles
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How to Derive Ideal gas equation?
Answers
Calculate the percent ionization of 0.115 M lactic acid in a solution containing 7.0×10−3 M sodium lactate.
Answers
The percent ionization of 0.115 M lactic acid in a solution containing 7.0×[tex]10^-^3[/tex] M sodium lactate is 1.22% as percent ionization of a weak acid in solution is a measure of how much of the acid has dissociated into its ions.
The chemical equation for the dissociation of lactic acid is:
HC₃H₅O₃ ⇌ H+ + C₃H₅O₃−
The Ka value for lactic acid is 1.4×10^−4 at 25°C.
Initial: [HC₃H₅O₃]] = 0.115 M, [NaC₃H₅O₃] = 7.0×[tex]10^-^3[/tex] M, [H+] = 0 M, [C₃H₅O₃−] = 0 M
Using the Ka expression for lactic acid,
Ka = [H+][C₃H₅O₃−]/[HC₃H₅O₃]]
Substituting the equilibrium concentrations into the equation and solving for x,
1.4×[tex]10^-^4[/tex]= [tex]x^2[/tex]/(0.115−x)
Solving for x using the quadratic formula,
x =1.4×[tex]10^-^3[/tex] M
Now the percent ionization of lactic acid:
% Ionization = [H+]/[HC₃H₅O₃] × 100%
% Ionization = (1.4×[tex]10^-^3[/tex] M)/(0.115 M) × 100%
% Ionization = 1.22%
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If 4.53g Ar are added to 1.12 atm He in a 2.00 L cylinder at 27.0 Celsius degree
What is the total of gaseous mixture?
Answers
The total gaseous mixture is 4.48 g.
The total gaseous mixture can be calculated using the ideal gas law: PV = nRT.
First, we need to convert the temperature to Kelvin: 27.0°C + 273.15 = 300.15 K.
Next, we can use the ideal gas law to calculate the number of moles of each gas:
For He: n = (1.12 atm) (2.00 L) / (0.08206 L·atm/mol·K) (300.15 K) = 0.0906 mol
For Ar: n = (4.53 g) / (39.95 g/mol) = 0.113 mol
The total number of moles of gas in the mixture is then:
n(total) = n(He) + n(Ar) = 0.0906 mol + 0.113 mol = 0.204 mol
Finally, we can calculate the total mass of the mixture:
m(total) = n(total) × M(avg)
where M(avg) is the average molar mass of the mixture, which can be calculated as:
M(avg) = (M(He) + M(Ar)) / 2 = (4.003 g/mol + 39.95 g/mol) / 2 = 21.98 g/mol
Thus,
m(total) = 0.204 mol × 21.98 g/mol = 4.48 g
Therefore, The total weight of the gaseous mixture is 4.48 g.
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Calculate the pH of the three solutions described below. (25 pts)
a) 6.0 x 10-3 M HClO4
b) .0009 M Sr(OH)2
c) The solution made by mixing 25.00 mL of 0.121 M HCl + 30.00 mL of 0.100 M KOH
Answers
a) HClO₄ is a strong acid, and in water, it will dissociate completely into H+ and ClO₄⁻. The concentration of H⁺ in this solution is therefore equal to the concentration of HClO₄:
[H⁺] = 6.0 x 10⁻³ M
Using the definition of pH, we have:
pH = -log[H⁺]
pH = -log(6.0 x 10⁻³)
pH = 2.22
b) Sr(OH)₂ will dissociate completely into Sr²⁺ and 2OH⁻. The concentration of OH⁻ in this solution is therefore twice the concentration of Sr(OH)₂:
[OH-] = 2 x 0.0009 M
[OH-] = 0.0018 M
Using the definition of pH, we have:
pOH = -log[OH-]
pOH = -log(0.0018)
pOH = 2.74
Since pH + pOH = 14, we have:
pH = 14 - pOH
pH = 14 - 2.74
pH = 11.26
c) Solution made by mixing 25.00 mL of 0.121 M HCl and 30.00 mL of 0.100 M KOH
HCl + KOH → H2O + KCl
The moles of HCl in 25.00 mL of 0.121 M HCl are:
moles HCl = concentration x volume
moles HCl = 0.121 mol/L x 0.025 L
moles HCl = 0.003025 mol
The concentration of HCl in the final solution is:
[HCl] = moles HCl / total volume of solution
[HCl] = 0.003025 mol / (25.00 mL + 30.00 mL)
[HCl] = 0.003025 mol / 0.055 L
[HCl] = 0.055 M
Similarly, the moles of KOH in 30.00 mL of 0.100 M KOH is:
moles KOH = concentration x volume
moles KOH = 0.100 mol/L x 0.030 L
moles KOH = 0.003 mol
The concentration of OH⁻ in the final solution is:
[OH⁻] = moles OH⁻ / total volume of solution
[OH⁻] = 0.006 mol / 0.055 L
[OH⁻] = 0.109 M
Using the definition of pH, we have:
pH = 14 - pOH
pH = 14 - (-log[OH⁻])
pH = 14 - (-log(0.109))
pH = 12.06
Thus, the pH of (a) is 2.22, (b) is 11.26, and (c) is 12.06.
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Why does intermolecular force exists between particles
Answers
Hi i need help figuring how many mol… please if you can hurry! Thank you
Answers
The number of moles is 0.001734 moles
The Ideal gas law is the equation of state of a hypothetical ideal gas. It is a good approximation to the behaviour of many gases under many conditions, although it has several limitations. The ideal gas equation can be written as
PV = nRT
where,
P = Pressure
V = Volume
T = Temperature
n = number of moles
Given,
Volume = 3.4L
Pressure = 1.2 atm
Temperature = 283K
PV = nRT
1.2 × 3.4 = n × 8.314 × 283
n = 0.001734 moles
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What mass in grams of oxygen gas are produced when 2.43 x 10-4 g of KCIO,
are completely reacted according to the following chemical equation:
2 KCIO₂ (s) → 2 KCI (s) + 3 0₂(g)
Answers
The balanced chemical equation shows that 2 moles of KCIO4 produce 3 moles of O2. Therefore, we can write a ratio of the moles of KCIO4 to moles of O2 as:
2 moles KCIO4 / 3 moles O2
We can use the molar mass of KCIO4 to convert the given mass of KCIO4 to moles:
2.43 x 10^-4 g KCIO4 x (1 mol KCIO4/ 391.28 g KCIO4) = 6.20 x 10^-7 mol KCIO4
Using the mole ratio, we can calculate the number of moles of O2 produced:
6.20 x 10^-7 mol KCIO4 x (3 moles O2 / 2 moles KCIO4) = 9.30 x 10^-7 mol O2
Finally, we can use the molar mass of O2 to convert the number of moles to mass in grams:
9.30 x 10^-7 mol O2 x (32.00 g O2 / 1 mol O2) = 2.98 x 10^-5 g O2
Therefore, the mass of O2 produced is 2.98 x 10^-5 g.
List at least five terms from the introduction that you can use as key words in your search. edmentum science
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Finding and examining search phrases that people enter through search engines for the purpose to utilise that information is the process of conducting keyword research.
The phrases and words that people employ when using search engines in order to locate what they're searching for are known as keywords. For instance, you may type "mens leather coat" into a search engine to get a new jacket. The phrase is still regarded as a keyword even though it has numerous words.
Keywords are concepts and themes that describe the subject matter of your article. They are the phrases and words that users type into search engines to find information, commonly referred to as "search queries" within SEO. If you scale down the size of all the content on your page, including the images, videos, prose, and so on.
To know more about Keyword research, here:
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Answer:
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Explanation:
