Answer:
Yeah you can change the language
Answer:
yes of course you can do it.
What is standard form of the parabola y - 4 = -(x - 1)^2
Answer:
Given that,
The equation of the parabola is,
[tex]y-4=-(x-1)^2[/tex]To find the standard form of the parabola.
Explanation:
Given equation is,
[tex]y-4=-(x-1)^2[/tex]From the definition we know that, standard form of the parabola is of the form,
[tex]y=a(x-h)^2+k[/tex]The standard form of the parabola is,
[tex]y=-(x-1)^2+4[/tex]Answer is: option B
[tex]y=-(x-1)^2+4[/tex]select functions f and g such that the ratio of function f to function g is equal to the function h.
What is required is that our choice should satisfy the equation:
[tex]f(x)\text{ = g(x) }\times\text{ h(x)}[/tex]By observation and trial, we obtain :
[tex]\begin{gathered} g(x)=x^2\text{ - x -2} \\ h(x)\text{ = x - 4} \end{gathered}[/tex]When we multiply, we have:
[tex]\begin{gathered} (x^2\text{ - x - 2) (x -4)} \\ =x^3-4x^2-x^2\text{ + 4x - 2x + 8} \\ =x^3-5x^2\text{ + 2x + 8} \end{gathered}[/tex]Hence,
[tex]f(x)=x^3-5x^2\text{ + 2x + 8}[/tex]In summary,
[tex]\begin{gathered} f(x)=x^3-5x^2\text{ + 2x + 8} \\ h(x)\text{ = x - 4} \\ g(x)=x^2\text{ - x -2} \end{gathered}[/tex]need help with math paper only one page
Proportional relation
The slope
The blue slope is negative and the green one is positive, if you realize it your slope has to be positive.
To calculate the slope (m)
y = m x +b
m = (y2-y1)/ (x2-x1)
____________________
You can take two points from the graph for example
Points (x, y)
Point 1 (0, 0); x1= 0 ; y1= 0
point 2 (300, 450); x2= 300 ; y2= 450
m = (450 - 0)/ (300 - 0)
m = 45/ 30
m = 3/2
_____________________
The equation that represents the graph
y= 3/2 x
________________________________
Table
Grams of fish (x); the number of calories (y)
y= 3/2 x
x= 300 Grams of fish
y= 3/2 (300)
y= 450
450 calories
______________
x= 1
y= 3/2 (1)
y= 3/2 = 1.5
1.5 calories
_____________
x= 1000
y= 3/2 (1000)
y= 3000/2 = 1500
1500 calories
_______________________
y = 2001 calories
y= 3/2 x
2001 = 3/2 x
x= 2001 *2/3
x= 1334
1334 grams of fish
Which expression describes the distance between point A and point B on the number line?
Answer:
2 -(-3)
Step-by-step explanation:
Diamonds are weighed in carats.
A carat is gram.
5
What is the weight in grams
of the largest diamond in the world,
the 3106-carat Cullinan diamond?
plss help
Answer:
621.2 grams
Step-by-step explanation:
One carat is 0.2 grams
Multiply that by 3106 to get 621.2 grams
What's the answer please and thank you
step 1
Find the slope
we take the points
(5,-30) and (8, -48)
m=(-48+30)/(8-5)
m=-18/3
m=-6
step 2
Find the equation of the line in slope intercept form
y=mx+b
we have
m=-6
point (5,-30)
substitute
-30=-6(5)+b
-30=-30+b
b=0
therefore
y=-6xJackie claims that points with the same x- and y- coordinates must lie in Quadrant l or Quadrant lll. Do you agree or disagree? Explain your answer.
It is known that in the I and III quadrants, the signs of the x- and y- are the same.
Jackie claims that the points with the same x - and y - coordinates must lie in the I or III quadrant.
His claim is true.
The points with the same x - and y - coordinates are of the form (a,a) or (-a,-a). If the point is of the form (a,a), it lies in the quadrant I
If the point is of the form (-a,-a), it lies in quadrant III.
H= {(1, 0), (3, b), (5, b)}
Give the domain and range of H.
Write your answers using set notation.
1.Using geometry vocabulary, describea sequence of transformation that maps p onto figure q.2. write transformation mapping rule for the sequence you describe in part (a)P:(-1,2) (-1,4) (-4,2)(-4,4)Q:(2,-2) (2,-5) (4,-2) (4,-5)
First, we transform the coordinates of the vertices of P 270° anticlockwise.
The 270° anticlockwise transformation rule, T, is defined as:
[tex]T\colon(x,y)\to(y,-x)_{}[/tex]Therefore,
[tex]T(-1,2)=(2,1)[/tex][tex]\begin{gathered} T(-1,4)=(4,1) \\ T(-4,2)=(2,4) \\ T(-4,4)=(4,4) \end{gathered}[/tex]Let the resultant shape be named P'
Hence,
P': (2,1), (4,1) (2,4) (4,4)
Next
We translate the resultant shape downwards by 6 units.
The transformation rule, S, for moving downwards by 6 units is given by:
[tex]S\colon(x,y)\to(x,y-6)_{}[/tex]Therefore,
[tex]S(2,1)=(2,1-6)=(2,-5)[/tex][tex]\begin{gathered} S(4,1)=(4,1-6)=(4,-5) \\ S(2,4)=(2,4-6)=(2,-2) \\ S(4,4)=(4,4-6)=(4,-2) \end{gathered}[/tex]Hence, the image of S on P' is : (2,-2) (2,-5) (4,-2) (4,-5)
This is illustrated by the image below
A car is traveling at 25 mph during rush hour. How far does the car travel in 3 minutes and 45 seconds? Round your answer to the nearest foot
Given:
The speed of car is 25 mph.
Explanation:
Determine the speed of car in foot per second.
[tex]\begin{gathered} 25\text{ mph=25 mph}\cdot\frac{1.46667\text{ fps}}{1\text{ mph}} \\ =36.6675 \end{gathered}[/tex]So car travel 36.6675 feet in 1 second.
Determine the time in seconds.
[tex]\begin{gathered} 3\text{ min 45 sec=3}\cdot60sec+45\text{ sec} \\ =180+45\text{ sec} \\ =225\text{ sec} \end{gathered}[/tex]Determine the distance travelled by car in 3 minutes 45 seconds.
[tex]\begin{gathered} 36.6675\cdot225=8250.1875 \\ \approx8250 \end{gathered}[/tex]So car travell 8250 feet.
Answer: 8250
You're flying from Joint Base Lewis-McChord (JBLM) to an undisclosed location 201 km south and 160 km east. Mt. Rainier is located approximately 56 km east and 40 km south of JBLM. If you are flying at a constant speed of 800 km/hr, how long after you depart JBLM will you be the closest to Mt. Rainier?
The time it would take to get closest to Mt Rainier, t ≈ 8.53 × [tex]10^{-3}[/tex] hours.
What is the separation of a line from a point?The perpendicular distance of a point to a line is the closest distance between them. The length of the perpendicular segment connecting a point to a line is the distance between them.
It would take roughly 5.12 minutes to go to the closest point to Mount Rainier.
The following justifies why the value is accurate:
The given parameters are;
The flight's direction is 201 kilometres south and 160 km east.
Mount Retainer is situated 56 kilometers east and 40 kilometers south of JBLM.
Flight velocity is 800 km/h.
The travel path's slope, in m, is given as follows:
m = -201/160
=1.2
The equation of the path is therefore;
y+201 = -1.2(x-160)
y = -1.2(x-160) - 201
The required slope for the perpendicular distance from the travel path to the Mt Rainier, m', is therefore;
m' = -1/m
Which gives;
m' = 1/1.2
The equation of the line is therefore;
y+ 40 = 1/1.2(x-56)
y = 1/1.2(x-56)-40
The coordinates of the point where the two lines meet is therefore;
-1.2(x-160)-201 = 1/1.2(x-56)-40
solving this we get
x = 22.46
y = -67.83
The magnitude of the distance in km is, d = 71.451
The time it will take to be closest to Mt. Rainier, t, is given as follows;
t = 71.451/800
t = 8.9×[tex]10^{-3}[/tex]
The time it would take to get closest to Mt Rainier, t ≈ 8.53 × [tex]10^{-3}[/tex] hours.
To know more about distance from a line to a point, visit:
https://brainly.com/question/1597347
#SPJ9
Factor the following expression completely:
x² 18x + 80 =
Help please ad thanks!
Answer:
[tex]18 {x}^{3} + 80[/tex]
Step-by-step explanation:
[tex] {x}^{2} \times 18 {x}^{1} + 80 \\ {x}^{2 + 1} x18 + 80 \\ {x}^{3} x18 + 80 \\ 18 {x}^{3} + 80[/tex]
Hello what is the question to both parts and what is the monthly payment
In general, the monthly payment formula is
[tex]M=\frac{P(\frac{r}{12})(1+\frac{r}{12})^n}{(1+\frac{r}{12})^n-1}[/tex]In our case,
[tex]P=19300,r=0.061,n=3\cdot12=36[/tex]Where r=6.1%=0.061 and the number of payments is 12months*3years=36 monthly payments. Thus, the answer is
[tex]\begin{gathered} \Rightarrow M=19300\cdot\frac{\frac{0.061}{12}(1+\frac{0.061}{12})^{36}}{(1+\frac{0.061}{12})^{36}-1} \\ \Rightarrow M=588.0182\ldots \\ \Rightarrow M\approx588.02 \end{gathered}[/tex]The monthly payment is $588.02
Please answer :-Factorize x²+1.
The given expression is
[tex]x^2+1[/tex]We can not factorize this expression bt the normal factorizing ways
Because it is a binomial with + as a middle sign can not be distributed into 2 factors
Then there is no factorizing for the given binomial
If the sign between the two terms is (-), then we can factorize it into two same factors with different middle sign
We can use the complex numbers to factorize it
[tex]\begin{gathered} x^2=(x)(x) \\ 1=(i)(-i) \\ (x)(i)+(x)(-i)=(xi)-(xi)=0 \\ (x+i)(x-i) \end{gathered}[/tex]Then the factors are (x + i) and (x - i)
[tex]x^2+1=(x+i)(x-i)[/tex]Answer:
x^2+1
Step-by-step explanation:
The expression is not factorable with rational numbers.
I need to now the answer for a and b
Knowing that there is a total of 250 6th grade students that participated in the challenge:
a. You can identify that:
-The percentage of students that participated in lifting leights is 8%.
A percent can be written as a decimal number by dividing it by 100:
[tex]\frac{8}{100}=0.08[/tex]Therefore, the number of students that participated in that exercise is:
[tex](250)(0.08)=20[/tex]- The percentage of students that participated in running is 30%.
Therefore, the number of them that participated in this exercise is:
[tex](250)(\frac{30}{100})=75[/tex]- Notice that the percentage of students that participated in swimming is 5%.
Hence, the number of them that participated in this exercise is:
[tex](250)(\frac{5}{100})\approx13[/tex]b. Notice that the number of students who chose walking is:
[tex](250)(\frac{17}{100})\approx43[/tex]Therefore, the total number of students that chose swimming, walking, and lifting weight is:
[tex]13+43+20=76[/tex]Notice that that number is greater than the number of students who chose running.
Hence, the answers are:
a. Lifting Weights:
[tex]20\text{ students}[/tex]Running:
[tex]75\text{ students}[/tex]Swimming:
[tex]13\text{ students}[/tex]b. Joseph is right, because there are 76 students who chose swimming, walking, and lifting weights, and there are 75 students who chose running.
The probability a student at Jamal's school is in the band is 0.20. Jamal wants to estimate the probability that in 3 randomly selected students, at least 2 are in the band.
To do this, he uses a simulation. He lets 1 represent a student who is in the band and 2, 3, 4, or 5 represent a student who is not in the band. He then uses a computer to randomly generate 3 random numbers from 1 to 5 twenty times. The results of these 20 trials are shown in this list.
233, 113, 131, 244, 414,344, 412, 132, 554, 454,334, 235, 125, 412, 254,232, 221, 342, 333, 313
Based on this simulation, what is the estimated probability that at least 2 of 3 randomly selected students are in band?
Enter your answer, as a decimal, in the box.
Answer:
0.45
Step-by-step explanation:
1) the required probability can be calculated as:
P=(number_trials_with_2or3_students_in_band)/(total_number_trials);
according to the formula above:
2) number of trials with 2 or 3 students in the band is:
233, 113, 131, 244, 414,344, 412, 132, 554, 454,334, 235, 125, 412, 254,232, 221, 342, 333, 313 - 9;
3) total number of trials is: 20.
finally, P=9/20=0.45
Answer: its 0.10
Step-by-step explanation:
i took da quiz heres proof
I need help what would be the 20th term in this sequence? 7, 14, 21, 28, 35... NUMBER 7
Cm, this is the solution:
This is the sequence given:
7, 14, 21, 28, 35
d = 7 (Common difference)
An = 7n (Arithmetic sequence)
The 20th term is:
A20 = 7 * 20
A20 = 140
... Rotate the following polygon 90* CCW. List the new image coordinates. Write the general Coordinate 10 -10 The general rule for 90 degrees counter xy) > (30)
The general rule for 90* CCW rotation of a figure about the origin, is:
[tex]\mleft(x,y\mright)\to(-y,x)[/tex]By definition, the original figure is called "Pre-Image" and the new figure is called "Image".
Knowing the coordinates of each point of the figure, you can apply the rule shown. So you get that points of the new image are:
[tex]\begin{gathered} A\mleft(2,3\mright)\rightarrow A^{\prime}(-3,2) \\ B\mleft(5,3\mright)\rightarrow B^{\prime}(-3,5) \\ C\mleft(1,5\mright)\rightarrow C^{\prime}(-5,1) \\ D\mleft(6,5\mright)\rightarrow D^{\prime}(-5,6) \end{gathered}[/tex]Therefore, the answers are:
1. The general rule is:
[tex](x,y)\to(-y,x)[/tex]2. Knowing the points of both figures, you can draw them. The graph is:
3. The new image coordinates are:
And you're fine that on his way to work he waits time for the bus is roughly uniformly distributed between 8 minutes and 17 minutes 1 day he time his weight and writes down a number of minutes ignoring the 2nd run a solution to 3 decimal places
We have the waiting times uniformly distributed between 8 and 17 minutes. As he ignore the seconds, we have a discrete distribution with values 8 to 16.
We have to find what is the probaility that the waiting time is 10 minutes.
We can find this probability knowing that 10 is one class out of 17-8=9 classes with equal probability.
So the probability is:
[tex]P(X=10)=\frac{1}{9}\approx0.111[/tex]We now have to calculate the probability that the waiting time is between equal or higher 11 and less than 13. This include classes 11 and 12 (and not 13), so we include 2 classes out of 9. Then, the probability is:
[tex]P(11\le X\le13)=\frac{2}{9}\approx0.222[/tex]Answer:
P(X=10) = 0.111
P(11<=X<13) = 0.222
Find GH. BC 19 GH 9x - 3 FE 5х + 1 option A: 2 option B: 6 option C: 15. option D: 51
Since FE and BC are given to be parallel, the figure BCEF is a trapezium.
The line GF divides the sides BF and CE equally. Hence, we can say that GH is parallel to side FE and BC.
Hence, the trapeziums BCHG and FEHG are similar.
Hence, the ratio between sides can be expressed as,
[tex]\frac{\text{BC}}{GH}=\frac{GH}{FE}[/tex][tex]\begin{gathered} \frac{19}{9x-3}=\frac{9x-3}{5x+1} \\ 95x+19=(9x-3)^2 \\ 95x+19=81x^2-2\times3\times9x+9 \\ 95x+19=81x^2-54x+9 \end{gathered}[/tex][tex]0=81x^2-149x-10[/tex]Using discriminant method, the equation can be solved as,
[tex]\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ x=\frac{-(-149)\pm\sqrt[]{(-149)^2-4\times81\times(-10)}}{2\times81} \end{gathered}[/tex]The positive solution to the equation is x≈2.
So,
[tex]\begin{gathered} GH=9\times2-3 \\ =15 \end{gathered}[/tex]Hence, GH=15.
simplify this expression 2 (times) x (times) 3 (times) y
The first to answer I will give branliest
The simplified expression of the expression 2 x 3 x y is 6y
How to simplify the expression?From the question, we have the following statement that can be used in our computation: 2 (times) x (times) 3 (times) y
Express as numbers
So, we have
2 x 3 x y
Evaluate the products of the numbers
So, we have the following representation
2 x 3 x y = 6 x y
Evaluate the products of the number and the variable
So, we have the following representation
2 x 3 x y = 6y
The above expression cannot be further simplified
Hence, the expression is 6y
Read more about fractions at
https://brainly.com/question/2929160
#SPJ1
please help me out quickly huge point for grab please let your answer be correct
Answer:
first is T second is F
Step-by-step explanation:
In the 2.5 minutes between innings in a baseball game, a hotdog launcher launches 12 hotdogs into the crowd. Clara, a member of the mascot team, wants to know how long she has to launch each hotdog. What is the unit rate in seconds per hotdog?
The unit rate in seconds per hotdog is 12.5 seconds.
The time between the innings in a baseball game is 2.5 minutes.The hotdog launcher has to launch a total of 12 hotdogs into the crowd within the time between the innings.Clara is a member of the mascot team. She has a limited amount of time to launch each hotdog.Let us convert the time in minutes to seconds.2.5 minutes equals 2.5*60 seconds.The time is 150 seconds.The total number of hotdogs to be launched is 12.The amount of time available for each hotdog is the rate at which she can launch hotdogs into the crowd.The unit rate in seconds per hotdog is 150/12.The unit rate in seconds per hotdog is 12.5 seconds.To learn more about rate, visit :
https://brainly.com/question/14731228
#SPJ1
If there is 1/3 of quantity A for every 4/9 of quantity B, how much of quantity A is there for 2/5 of quantity B?
Answer:
3/10 ths of A
Step-by-step explanation:
Find out how many 4/9 ths there are
2/5 / 4/9 = 2/5 * 9/4 = 18/20
Now multiply the number of 4/9ths ( which is 18/20) by 1/3
1/3 * 18/20 = 6/20 = 3/10ths of A
What is the x and y intercepts of the line 2x-5y=20
The x-intercept and the y-intercept of the original equation of line 2x-5y=20 is (10,0) and (0,-4).
What is defined as the x and y intercepts?An intercept is a y-axis point by which the slope of a line passes. It is the y-coordinate of a point on the y-axis in which a straight line or a curve intersects. This is represented by the equation for a straight line, y = mx+c, where m is the slope as well as c is the y-intercept.The x-intercept occurs where y=0, and the y-intercept occurs where x=0.
2x-5y=20 is the original equation of the line.
1) Substitute 0 for y to obtain 2x - 5(0) = 20, that equals 2x = 20.
Now, find x by dividing all sides by 2, and x = 10, resulting in the x-intercept (10,0)
2) Substitute 0 for x to obtain 2(0) - 5y = 20, which equals -5y = 20.
Now, find y by dividing all sides by 5, and y = -4, implying that the y-intercept is (0,-4).
Thus, the x-intercept and the y-intercept of the original equation 2x-5y=20 is (10,0) and (0,-4).
To know more about x and y intercepts, here
https://brainly.com/question/24609929
#SPJ13
A board game uses a spinner to determine how many spaces a player will move forward on each turn. The probability is 1/2 that the player moves forward 1 space, and moving forward 2 or 3 spaces each have 1/4 probability. What is the expected value for the number of spaces a player moves forward on a turn?
ANSWER
1.75
EXPLANATION
The expected value of an event X is the sum of the products of each value of the event and the probability of the event resulting in that value.
In this case,
[tex]E\lbrack X\rbrack=1\cdot P(1\text{ }forward)+2\cdot P(2\text{ }forward)+3\cdot P(3\text{ }forward)=1\cdot\frac{1}{2}+2\cdot\frac{1}{4}+3\cdot\frac{1}{4}[/tex]Solve,
[tex]E\lbrack X\rbrack=\frac{1}{2}+\frac{1}{2}+\frac{3}{4}=\frac{7}{4}=1.75[/tex]Hence, the expected number of spaces the player moves in a turn is 1.75.
Find the domain and range. Then use the drop down menu to select the correct symbols to indicate your answer in interval notation. If a number is not an integer then round it to the nearest hundredth. To indicate positive infinifty ( \infty ) type the three letters "inf". To indicate negative infinity(-\infty ) type "-inf" with no spaces between characters.positive quadratic with closed end point at (-5,2) and open end point at (3,2) vertex=(-1,0)The domain is:AnswerAnswer,AnswerAnswerThe range is: AnswerAnswer,AnswerAnswer
• For domain { -5 ≤x < 3 } : [ -5 ;3),
( take notice of the square bracket that indicates a closed dot/ circle, and open bracket that indicates open circle/dot)
• For range : { 0≤ y≤ 2} : [0;2]
( take note that our graph extends up to y -value = 2 , our minimum being 0 , we put close brackets because it starts at 0 and end at 2 .)
Jessica owns a sword, a set of wooden nunchucks, a giant wooden club, and a deadly pair of fists. She also owns a wooden shield and a set of medieval knight's armor. If she can only take one weapon and one piece of defensive equipment, what is the probability she will choose something made of metal?
The probability of choosing something made of metal is 0.5.
Let the wooden shield and set of medieval knight's armor be a combination 1.
And the sword, a set of wooden nunchucks, a giant wooden club, and a deadly pair of fists be a combination 2.
Al the wooden piece of combination 2 will come under one category and the metal piece be in another category.
Similarly, in combination 1 wooden piece is in one category, and the metal piece is in another category.
Therefore, the probability of the combination of metal from combination 1 and combination 2 of the metal category would be,
(1 ÷ 2) × ((2 ÷ 4) + (1÷2)) = 0.5
Learn more about probability at
https://brainly.com/question/11234923?referrer=searchResults
#SPJ1
What is the distance between the points (4,3) and (1,-1) on the coordinateplane?
ANSWER
A. 5 units
EXPLANATION
The distance between two points (x₁, y₁) and (x₂, y₂) is given by the Pythagorean Theorem,
[tex]d=\sqrt[]{(x_1-x_2)^2+(y_1-y_2)^2}[/tex]In this case, the points are (4, 3) and (1, -1). The distance between them is,
[tex]d=\sqrt[]{(4-1)^2+(3-(-1))^2}=\sqrt[]{3^2+(3+1)^2}=\sqrt[]{3^2+4^2}=\sqrt[]{9+16}=\sqrt[]{25}=5[/tex]Hence, the distance between the given points is 5 units.
Questions in picture
A:
For the first graph the equation would be y=25x with y being the cost and x being the number of yards. Then put 40 for x so it is y=25(40) and solve.
The answer for graph is 1000
For the second table it costs 490 dollars to move 20 yards and 40 is double of 20 so double the cost.
The answer for table is 980
B:
The rate of change for graph is y=25x and that means for every yard shipped you pay 25 dollars
The rate of change for table is whatever the cost divided by the number of yards is i can't see the numbers
C:
In the first question the graph is 1000$ and the table is 980$ so the table would be cheaper
