can u please help me with number 3 the graph

Step-by-step explanation:

the volume of a sphere is

4/3 × pi × r³

the original sphere had a radius of 3.

now, after a dilation of factor 4 the radius is 3×4 = 12.

the volume of that sphere is then

4/3 × pi × 12³ = 4/3 × pi × 1728 = 2304pi

Answer:

144

Step-by-step explanation:A first add 98 + 46 keyword Sum for interior angles

The testable question can be Which sprouts faster, a moist lima bean or a dry lima bean?

We have,

June laces a lima bean inside a damp paper towel, then places it in a baggie.

June takes another lima bean and places it in a dry paper towel and puts it in a baggie.

The Experiment is related to moisture because one damp and one dry towel is used.

So, the testable question can be

Which sprouts faster, a moist lima bean or a dry lima bean?

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Answer:

2.45ℓ

Step-by-step explanation:

0.33ℓ x 4 = 1.32ℓ (1ℓ 320 ml)

11.12ℓ - 1.32ℓ = 9.8ℓ (total in 4 jugs)

9.8ℓ ÷ 4 = 2.45ℓ (each jug)

hope this helped :)

The spreadsheet formula that will calculate the post-split number of outstanding shares in C3 will be C3*(B2/C2).

Assuming the split ratio has been inputted in cells B2 and C2, one can easily ascertain the post-split number of outstanding shares in cell C3 by simply using the following formula:

=C3 × (B2/C2).

In this case, the equation multiplies the pre-split quantity of outstanding shares by the ratio written down in cells B2/C2 for the determination of resulting post-split number of outstanding shares that are in cell C3.

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Answer:

False. If the revaluation of the asset is higher than the carrying value, the following entries will be made: Debit Asset account and Credit Revaluation reserve account. The revaluation reserve account is a balance sheet account and does not affect the capital accounts of the partners directly. However, the revaluation reserve may indirectly affect the capital accounts of the partners if the revaluation reserve is distributed to the partners or used to offset losses in the future. It is worth noting that the specific accounting treatment may vary depending on the accounting standards being used by the company.

Step-by-step explanation:

The height of this parallelogram include the following: B. 12 cm.

In Mathematics and Geometry, the area of a parallelogram can be calculated by using the following formula:

Area of a parallelogram, A = b × h

Where:

By substituting the given parameters into the formula for the area of a parallelogram, we have the following;

Area of a parallelogram = 10 × 12

Area of a parallelogram = 120 cm².

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

The mode of the number of pizzas ordered for all 189 stores is [tex]66[/tex]. The Option D is correct.

Mode refer he most frequent number, that is, the number that occurs the highest number of times. To find mode, we must determine the value that appears most frequently in the sample.

From the given data: [tex]28, 53, 35, 66, 35, 28, 66, 48, 53, 53, 66, 53, 66, 66, 35[/tex]. We see that the value 66 appears 5 times, which is more than any other value.

Therefore, the number 66 is the mode.

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The numeric ratio of the segment ratio are:

To find the numeric ratios of the given segment ratios, to calculate the distances between the given points.

CD: DB

The distance between C(6,2) and D(4,3) is:

CD = √[(6 - 4)² + (2 - 3)²] = √5

The distance between D(4,3) and B(-4,7) is:

DB = √[(4 + 4)² + (3 - 7)²] = 10

Therefore, the numeric ratio of CD:DB is:

CD:DB = √5:10

CE: CA

The distance between C(6,2) and E(4,2) is:

CE = √[(6 - 4)² + (2 - 2)²] = 2

The distance between A(-4,2) and C(6,2) is:

CA = √[(-4 - 6)² + (2 - 2)²] = 10

Therefore, the numeric ratio of CE:CA is:

CE:CA = 2:10

DE: BA

The distance between D(4,3) and E(4,2) is:

DE = √[(4 - 4)² + (3 - 2)²] = 1

The distance between B(-4,7) and A(-4,2) is:

BA = √[(-4 + 4)² + (7 - 2)²] = 5

Therefore, the numeric ratio of DE:BA is:

DE:BA = 1:5

CD: CB

The distance between C(6,2) and D(4,3) is:

CD = √[(6 - 4)² + (2 - 3)²] = √5

The distance between C(6,2) and B(-4,7) is:

CB = √[(6 + 4)² + (2 - 7)²] = √181

Therefore, the numeric ratio of CD:CB is:

CD:CB = √5:√181

Based on the numeric ratios, determine the type of ratio for each segment ratio:

CD: DB is a part:part ratio

CE: CA is a part:whole ratio

DE: BA is a part:part ratio

CD: CB is a part:whole ratio

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Answer:

A) oblique hexagonal prism

Step-by-step explanation:

Answer:

right hexagonal prism

Step-by-step explanation:

as seen on the Image below the left one is a right hexagonal prism and the right one is a oblique hexagonal prism.

1. The width of the pen must be greater than or equal to the sum of the diameters of the two circular food containers, which is equal to 2x + 2x = 4x:

2. The width of the pen must also be less than or equal to the length of the pen, which is 10 feet:

3. The radii of the gravel bases must be greater than or equal to the radii of the food containers, which is equal to x:

4. The radii of the gravel bases must also be less than or equal to half the width of the pen, which is equal to y/2:

System of inequalities that can be used to determine the width of the pen, y, and the radii of the gravel bases, x, is:

Answer:

Step-by-step explanation:

The sum of the diameters of the gravel bases cannot exceed the width of the pen, so 2⁢x+2⁢x≤y. Rewrite this to get y≥4⁢x as the first inequality in the system.Next, to write the expression for the cost of the fencing, find the perimeter of the rectangle and multiply the perimeter by the cost per foot of fencing. The pen is a rectangle, so the perimeter is 2⁢(10)+2⁢(y), or 20+2⁢y. Multiply the cost ($4.00 per foot) by the perimeter to get 4⁢(20+2⁢y).Now write an expression for the gravel bases for the circular food containers. Because A=π⁢r2 and the cost of the gravel is $2.00 per square foot, multiply the cost of the material by the sum of these areas to get 2⁢(π⁢x2)+2⁢(π⁢x2).The total cost must be less than or equal to $150, so we can say that 4⁢(20+2⁢y)+2⁢(π⁢x2)+2⁢(π⁢x2)≤150. Finally, simplify and solve for y.80+8⁢y+2⁢π⁢x2+2⁢π⁢x2≤15080+8⁢y+4⁢π⁢x2≤1508⁢y≤70−4⁢π⁢x2y≤8.75−0.5⁢π⁢x2So, this is the system.

y≥4⁢x

y≤8.75−0.5⁢π⁢x2

Without additional information about the model house, it is impossible to accurately describe the surface that Molly does not need to paint. It could be any surface that will not be visible when the model house is displayed, such as the underside of a roof, the back of a wall, or the bottom of a floor.

The ratio in simplest form is 1:4, the correct option is C.

We are given that;

The options  A. 2/3 B. 3/4 C. 1/4 D. 4/1

Now,

The letters D and O are used 2 times and 4 times respectively in the words “RATIOS AND PROPORTIONS”. So we can write the ratio as 2:4.

The GCF of 2 and 4 is 2, since 2 is the largest number that can divide both 2 and 4 without leaving a remainder.

To simplify the ratio, we divide both terms by 2:

2:4 = (2/2):(4/2) = 1:2

Therefore, by the ratio the answer will be 1/4.

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Answer:

y=-3

Step-by-step explanation:

Answer:

Y = - 3

Step-by-step explanation:

So lets help you out here.....

First of all you should set up how you have to solve, let do this step by step...

Step 1 : 2y + 3y - 18 = - 33

Step 2 : Combine like terms... (2y + 3y = 5y)

Step 3 : Set up your new equation (5y - 18 = - 33)

Step 4 : Subtract negative 18 by negative 33 (- 18 - 33 = -15)

(PS: In a calculator - 18 - 33 is -51 but the 18 is also a negative so it would be - 15)

Step 5 : Divide (- 15 / 5 = - 3)

And that is how you solve this problem, have a great day!!!!!!

The percentage of the total that women represent, would be 60% of the total.

Given that 60 % of men is equal to 40 % of women, we have :

0. 6 M = 0. 4 W

Solving for women in terms of Men gives:

W = ( 0.6 x M) / 0.4

= 1.5 x M

We can then find the percentage of women to be:

= (W / Total ) x 100

= ((1.5 x M) / (2.5 x M)) x 100

= (1.5 / 2.5) x 100

= 0.6 x 100

= 60%

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Answer:

x = 6 feet

Step-by-step explanation:

using Pythagoras' identity in the right triangle.

the square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

x² + 8² = 10²

x² + 64 = 100 ( subtract 64 from both sides )

x² = 36 ( take square root of both sides )

x = [tex]\sqrt{36}[/tex] = 6 feet

The equation for the gradient on the curve C is y = x³ - 2x² + 5x - 3

Given data ,

Let the gradient of every point on the curve C is given by the equation dy/dx = 3x² - 4x + k

Now , we can integrate this equation with respect to x to obtain the equation for C

∫(dy/dx)dx = ∫(3x² - 4x + k)dx

Integrating the right-hand side with respect to x, we get:

∫(3x² - 4x + k)dx = x^3 - 2x^2 + kx + C1

where C1 is the constant of integration

Now, on simplifying the points P(0, -3) and Q(2, 7) that lie on C to find the values of C1 and k

For point P(0, -3)

when x = 0, y = -3

Plugging these values into the equation x³ - 2x² + kx + C1 = y, we get:

0³ - 2(0)² + k(0) + C1 = -3

C1 = -3

For point Q(2, 7):

when x = 2, y = 7

Plugging these values into the equation x³ - 2x² + kx + C1 = y, we get:

2³ - 2(2)² + k(2) - 3 = 7

k = 5

On substituting the values of C1 and k back into the equation , we get

y = x³ - 2x² + 5x - 3

Hence , the equation is y = x³ - 2x² + 5x - 3

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We would expect 138 groups in the larger zoo to have 5 or more people based on the relative frequency of group sizes in Julia's data.

To determine how many groups of 5 or more people we would expect to see in a larger zoo with 600 groups of visitors in a day, we need to use the relative frequency of each group size in Julia's data.

To calculate the relative frequency of each group size, we need to divide the frequency of each group size by the total number of groups:

Group Size   Frequency   Relative Frequency

1                          9             9/150 = 0.06

2                         52           52/150 = 0.35

3                         27            27/150 = 0.18

4                         38            38/150 = 0.25

5                         16             16/150 = 0.11

6                          6              6/150 = 0.04

7                          5              5/150 = 0.03

8                          7              7/150 = 0.05

We can see that the relative frequency of groups with 5 or more people is 0.11 + 0.04 + 0.03 + 0.05 = 0.23. This means that we would expect 23% of the 600 groups in the larger zoo to have 5 or more people.

To calculate the actual number of groups with 5 or more people, we multiply the total number of groups by the relative frequency:

Number of groups with 5 or more people = 600 x 0.23 = 138

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Answer:

(2,0)

Step-by-step explanation:

Salton City has a lower altitude because -60.96 meters is less than -38.1 meters.

Option C is the correct answer.

We have,

The altitude of Bombay Beach is -60.96 meters.

The altitude of Salton City is -38.1 meters.

Altitude is the height of a location above sea level, and a negative value indicates that the location is below sea level.

Therefore, we can see that Salton City has a higher altitude than Bombay Beach because -38.1 meters is a higher altitude than -60.96 meters.

Thus,

Salton City has a lower altitude because -60.96 meters is less than -38.1 meters.

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The triangles are similar, and the scale factor is given as follows: k = 0.8.

Similar triangles are triangles that share these two features listed as follows:

The sum of the measures of the internal angles of a triangle is of 180º, hence the measure of the missing angle is given as follows:

x + 114 + 24 = 180

x + 138 = 180

x = 42º.

Which is equals to the measure on the second triangle, hence they are similar.

The scale factor is given as follows:

k = 16/20 = 36/45 = 0.8.

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[tex]-37 < -12v+1 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ v=-11\hspace{5em}-37 < -12(-11)+1\implies -37 < 133 ~~ \checkmark \\\\[-0.35em] ~\dotfill\\\\ v=-9\hspace{5em}-37 < -12(-9)+1\implies -37 < 109~~ \checkmark \\\\[-0.35em] ~\dotfill\\\\ v=-5\hspace{5em}-37 < -12(-5)+1\implies -37 < 61~~ \checkmark \\\\[-0.35em] ~\dotfill\\\\ v=6\hspace{5em}-37 < -12(6)+1\implies -37 < -71 ~~ \bigotimes[/tex]

The equation that represents the number of credits the student has earned after t semesters is C(t) = 12t + 15.

Let x be the number of credits the student had before starting college, and let y be the number of credits the student takes each semester. We can use this information to write an equation that represents the number of credits the student has earned after t semesters.

After 2 semesters, the student had 39 credits, which means the student earned 2y + x credits in those two semesters. Similarly, after 5 semesters, the student had 75 credits, which means the student earned 5y + x credits in those five semesters.

Using this information, we can write the following equation:

C(t) = yt + x

where C(t) represents the number of credits the student has earned after t semesters.

We know that C(2) = 2y + x = 39 and C(5) = 5y + x = 75. We can use these two equations to solve for x and y:

2y + x = 39

5y + x = 75

Subtracting the first equation from the second equation gives:

3y = 36

Therefore, y = 12, which means the student takes 12 credits each semester. Substituting y = 12 into either of the two equations above gives x = 15, which means the student had 15 credits before starting college.

Thus, the equation that represents the number of credits the student has earned after t semesters is C(t) = 12t + 15.

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