Can you help me solve this, please?

The expression which shows how the distributive property of the can be used to multiply 8×29 as in the task content is; 8(20 + 9).

It follows from the task content that the given product to be multiplied is; 8×29.

Consequently, it follows from convention that the distributive property of multiplication allows that the multiplication in this case can be rewritten as follows;

8×29 = 8 (20 + 9)

Hence, we have; (8×20) + (8×9).

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The ratio of bananas to fruit is 13 : 21

The given parameters are

Banana = 13

Apple = 8

The total number of fruits is

Fruit = Banana + Apple

Substitute the known values in the above equation

Fruit = 13 + 8

Evaluate the sum

Fruit = 21

The ratio of bananas to fruit is then represented as:

Ratio = Banana : Fruit

Substitute the known values in the above equation

Ratio = 13 : 21

Hence, the ratio of bananas to fruit is 13 : 21

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Answer:

x + 4y = 7

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (- 1, 2 ) and (x₂, y₂ ) = (3, 1 )

m = [tex]\frac{1-2}{3-(-1)}[/tex] = [tex]\frac{-1}{3+1}[/tex] = - [tex]\frac{1}{4}[/tex] , then

y = - [tex]\frac{1}{4}[/tex] x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (- 1, 2 )

2 = [tex]\frac{1}{4}[/tex] + c ⇒ c = 2 - [tex]\frac{1}{4}[/tex] = 1 [tex]\frac{3}{4}[/tex] = [tex]\frac{7}{4}[/tex]

y = - [tex]\frac{1}{4}[/tex]x + [tex]\frac{7}{4}[/tex] ← in slope- intercept form

multiply through by 4 to clear the fractions

4y = - x + 7 ( add x to both sides )

x + 4y = 7 ← equation in standard form

equation of line in two point form is needed here.

Answer:

a)  2x + 4

b)  2x + 5

c)  8

d)  9

Step-by-step explanation:

Given functions:

[tex]\begin{cases}f(x)=x+1\\g(x)=2x+3 \end{cases}[/tex]

Function composition is an operation that takes two or more functions and combines them into a single function.

(f o g)(x) means find g(x) first and then substitute the result into f(x).

(g o f)(x) means find f(x) first and then substitute the result into g(x).

Part (a)

[tex]\begin{aligned}(f \circ g)(x) & = f[g(x)]\\& = g(x)+1\\ & = (2x+3)+1\\& = 2x+4\end{aligned}[/tex]

Part (b)

[tex]\begin{aligned}(g \circ f)(x) & = g[f(x)]\\& = 2[f(x)]+3\\& = 2(x+1)+3\\ & = 2x+2+3\\& = 2x+5\end{aligned}[/tex]

Part (c)

[tex]\begin{aligned}(f \circ g)(2) & = f[g(2)]\\& = g(2)+1\\ & = (2(2)+3)+1\\ & = (4+3)+1\\& = 8\end{aligned}[/tex]

Part (d)

[tex]\begin{aligned}(g \circ f)(2) & = g[f(2)]\\& = 2[f(2)]+3\\& = 2(2+1)+3\\ & = 2(3)+3\\ & = 6+3\\& = 9\end{aligned}[/tex]

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(fog)(x)

(gof)(x)

(fog)(2))

(gof)(2)

The fraction (1/3)⁻⁴ is equal to 81.

Given that:

Fraction: (1/3)⁻⁴

Rewrite the expression by applying the rule that states a negative exponent is equal to the reciprocal of the positive exponent:

(1/3)⁻⁴= 1 / (1/3)⁴

Now, let's simplify (1/3)⁴:

(1/3)⁴ = (1/3) × (1/3) × (1/3) × (1/3)

(1/3)⁴ = 1/81

So, the expression becomes:

1 /(1/3)⁴ = 1 / (1/81)

Now, dividing by a fraction is equivalent to multiplying by its reciprocal:

1 / (1/81) = 1 × 81 = 81

Therefore, the fraction (1/3)⁻⁴ is equal to 81.

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Based on the given parameters, the value of the printer after 9 years is $3304

The given parameters about the exponential function are

Initial value, a = $7000

Depreciation rate, r = 8%

Time, t = 9

Exponential functions are different from linear functions, and they are calculated using the following exponential function

A = a *(1 - r)^t

To calculate the value in nine years, we have:

Substitute the known values in the above equation

A = 7000 * (1 - 8%)^9

Express 8% as decimal

A = 7000 * (1 - 0.08)^9

Evaluate the difference

A = 7000 * (0.92)^9

Evaluate the exponent

A = 7000 * 0.472

Evaluate the product

A = 3304

Hence, the value of the printer after 9 years is $3304

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Answer: 5040

Step-by-step explanation

We need to find how much it will depreciate each year based of of original cost.
8% of 7000
turn the percent into a decimal
.08
multiple .08 by the 7000
.08 * 7000 = 560

The printer depreciates 560 each year , to find the total for 9 years multiply by 9

560*9 =5040

Answer:

This the only one I know for sure right

I think the second one mn/on=qn/pn

I think the last one and the first one too but let me know which was right!

Step-by-step explanation:

Hi what unit of algebra or geometry is this because I did this before, and I can help you.

Equation (A) C= 1.46n shows the relationship between the total cost of gasoline, c, and the number of gallons purchased, n.

To find the right equation:

Therefore, equation (A) C= 1.46n shows the relationship between the total cost of gasoline, c, and the number of gallons purchased, n.

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The complete question is given below:
The total cost of gasoline varies directly with the number of gallons purchased. Kathy pays $23.36 for 16 gallons of gasoline. Which equation

shows the relationship between the total cost of gasoline, c, and the number of gallons purchased, n?

A.C= 1.46n

B. n = 1.46c

C.C = 23.361

D. n = 23.36c

==================================================

Work Shown:

width = w

length = w+9

perimeter = 2*(length + width)

P = 2(w+9+w)

P = 2(2w+9)

P = 4w+18

4w+18 = P

4w+18 = 270

4w = 270 - 18

4w = 252

w = 252/4

w = 63 meters is the width

w+9 = 63+9 = 72 meters is the length

Check:

perimeter = 2*(length + width)

perimeter = 2*(72 + 63)

perimeter = 2*(135)

perimeter = 270

The answer is confirmed.

See attachment for the graph of the reflection of f(x) across the y-axis

The function is given as:

f(x) = 1.5(0.5)^x

The rule of reflection across the y-axis is

(x, y) = (-x, y)

So, we have the following equation

f'(x) = 1.5(0.5)^-x

Rewrite the function as

g(x) = 1.5(0.5)^-x

So, we plot the graph of the function g(x)

See attachment for the graph of the reflection of f(x)

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step 1 :

g(x) = 1.5

step 2 :

g(0): 1.5

step 3 :

plot at (0,1.5)

step 4 :

g(1) = 3

g(-1) = .75

step 5 :

plot (1,3) & (-1,0.75)

step 6:

y=0

The Volume of the Cylinder B is gotten as; 720 cm³

We are given 2 similar cylinders with;

ratio of heights = a : b

Thus;

ratio of areas = a² : b²

We are given that;

Height of A is 5cm.

Height of B is 10cm.

Thus;

Ratio of heights = 5 : 10 = 1 : 2

Therefore;

ratio of areas = 1² : 2² = 1 : 4

The cross sectional area of B is 4 times the cross sectional area of A. Thus;

Cross sectional area of B = 4 × 18 = 72 cm²

Volume of cylinder = cross section area × height

Volume of cylinder B = 72 × 10 = 720 cm³

The complete question is;

A and B are two cylinders that are mathematically similar.

The area of the cross-section of cylinder A is 18cm².

Height of A is 5cm.

Height of B is 10cm.

Work out the volume of cylinder B

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The rate of interest applied on the amount is 15%.

According to the statement

we have given that the sum of money amounts to Rs. 2175 in 3 years and to Rs. 2625 in 5 years.

And we have to find the rate of interest on this money.

So, For this purpose,

The given equation is:

Money in 3 years = 2175

Money in 5 years = 2625

Amount increased in 2 years = 2625-2175

Amount increased in 2 years = 450

And amount increased per year = 450/2

Amount increased per year = 225.

SI in 3 years=450/2 *3=Rs. 675

Principal amount= 2175-675=1500

so again,

R=(I*100)/(P*T)

R=15%

So, The rate of interest applied on the amount is 15%.

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Answer:

its A

Step-by-step explanation:

Answer: The first one (A)

Step-by-step explanation:

Answer:

landline

hshdjdh

dbbdhdhdh

bdbdhdhdhe

Answer:

Router

Step-by-step explanation:

Hope this helps

Answer:

[tex]20a^2-70a[/tex]

Step-by-step explanation:

1) Expand by distributing terms.

[tex]10\times2a+10a\times-7[/tex]

2) Take out the constants.

[tex](10\times2)aa+10a\times-7[/tex]

3) Simplify [tex]10\times2[/tex] to [tex]20.[/tex]

[tex]20aa+10a\times7[/tex]

4) Use Product Rule:[tex]x^ax^b=x^{a+b}[/tex].

[tex]20a^2+10a\times-7[/tex]

5) Simplify [tex]10a\times-7[/tex] to [tex]-70a.[/tex]

[tex]20a^2-70a[/tex]

Thank you,

Eddie

Answer:

20a² - 70a

Step-by-step explanation:

(10a)(2a-7)

= 10a*2a + 10a*-7

= 20a² - 70a

Answer:

SAVE WATER

Step-by-step explanation:

i)

x + 1 = 20

subtract 1 from both sides

x + 1 - 1 = 20 - 1

x = 19

19 = S

ii)

15 = 2x + 13

subtract 13 from both sides

15 - 13 = 2x + 13 - 13

2 = 2x

divide both sides by 2

2/2 = 2x/2

1 = x

1 = A

iii)

2x + 5 = 49

subtract 5 from both sides

2x + 5 - 5 = 49 - 5

2x = 44

divide both sides by 2

2x/2 = 44/2

x = 22

22 = V

iv)

[tex]\frac{3x + 3}{2}[/tex] = 9

multiply both sides by 2

[tex]\frac{3x + 3}{2}[/tex] x 2 = 9 x 2

3x + 3 = 18

subtract 3 from both sides

3x + 3 - 3 = 18 - 3

3x = 15

divide both sides by 3

3x/3 = 15/3

x = 5

5 = E

v)

8(x - 7) = 128

apply the distributive law

8x - 56 = 128

add 56 to both sides

8x - 56 + 56 = 128 + 56

8x = 184

divide both sides by 8

8x/8 = 184/8

x = 23

23 = W

vi)

16 = 2(x + 7)

apply the distributive law

16 = 2x + 14

subtract 14 from both sides

16 - 14 = 2x + 14 - 14

2 = 2x

divide both sides by 2

2/2 = 2x/2

1 = x

1 = A

vii)

[tex]\frac{7y}{7}[/tex] = 20

sevens cancel out

y = 20

20 = T

viii)

2x - 1 = 9

add 1 to both sides

2x - 1 + 1 = 9 + 1

2x = 10

divide both sides by 2

x = 5

5 = E

ix)

2(x - 8) = 20

apply the distributive property

2x - 16 = 20

add 16 to both sides

2x - 16 + 16 = 20 + 16

2x = 36

divide both sides by 2

2x/2 = 36/2

x = 18

18 = R

Code Word/s: SAVE WATER

hope this helps :)

Answer:

Save Water

Step-by-step explanation:

(I’m sorry it took so long, I had to write it out Σ(＝д＝ﾉ)ﾉ

I hope this helps! ヾ(>ꇴ<) xx

Under the assumption of simple harmonic motion, the package will be at x = 4.50 centimeters at a time of 0.805 seconds.

Simple harmonic motion is a kind of periodic motion represented by sinusoidal functions. Physically speaking, it is a good approximation for periodic motion due to small perturbations and with absence of frictions and viscous forces on the system.

The position of an object under simple harmonic motion is described by the following equation:

x (t) = A · cos (2π · t / T + Ф)      (1)

Where:

If we know that T = 5 s, A = 8.50 cm, Ф = 0 rad and x = 4.50 cm, then the time when the package will reach x = 4.50 cm is:

4.50 = 8.50 · cos (2π · t / 5)

9 / 17 = cos (2π · t / 5)

0.322π = 2π · t / 5

t = 0.805 s

Under the assumption of simple harmonic motion, the package will be at x = 4.50 centimeters at a time of 0.805 seconds.

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The value of A is A(1,-15) and the distance between AB is 8 so these are the correct answers.

According to the statement

We have given that the

AB = 8 and B lies at −7, and we have to find the position of the A on the number line.

Let a be a point on number line and b be the second point on number line.

And The distance between two numbers on number line is calculate by subtracting the smaller number from larger number.

Here

AB = 8

B = -7

We have to look at the options one by one.

For A = -1

As A>B

AB = -1-(7) = -1+7 = 6

For A = 1

As A>B so

AB = 1-(-7) = 8

So with A = 1 , AB = 8

This is one of the right answers.

For A=15

As A>B

AB = 15-(-7) = 22

For A=-15

As B>A

AB = -7 -(-15) = 8

As with A=1 and A=-15, the distance between AB is 8 so these are the correct answers.

So, The value of A is A(1,-15) and the distance between AB is 8 so these are the correct answers.

Disclaimer: This question was incomplete. Please find the full content below.

Question:

Suppose A and B are points on the number line. If AB = 8 and B lies at −7, where could A be located?

Select ALL that apply.

A −1

B 1

C 15

D −15

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DPU is the number of defects in a sample divided by the number of opportunities while DPMO is the number of defects divided by the number of units tested within a sample. Option B

Defects per unit (DPU) can be defined as the number of defects divided by the number of opportunities

It is also seen as the universal measure of quality.

For example, if there are 100 defects in 1,000 units produced, then the defects per unit will be 0.01.

Defects per million opportunities can be defined as a mathematical calculation of the estimated quality of a process

From this information, we can conclude that DPU and DPMO are measure of defects in a sample.

Thus, DPU is the number of defects in a sample divided by the number of opportunities while DPMO is the number of defects divided by the number of units tested within a sample. Option B

Complete question is;

________ is the number of defects in a sample divided by the number of opportunities while ________ is the number of defects divided by the number of units tested within a sample.

a. DPMO, DPU

b. DPU, DPMO

c. RTY, FTY

d. FTY, RTY

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Esta estrategia se puede aplicar sumando  15,75 + 0,25, –1,8 + –0,20, 3,5 + 12,5 y 2,62 + 7,38 antes de sumar el tercer número dado en cada caso.

La estrategia propuesta consiste en sumar dos números decimales que den como resultado un número entero antes de sumar el tercer número decima. Por ejemplo si teneos  1,4 + 0,6  + 1,2, se debe sumar primero 1,4 + 0,6 lo que es igual a 2 antes de sumar el 1,2.

Este estrategia es beneficiosa porque facilita sumar números decimales.

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Answer:

C

Step-by-step explanation:

C

Answer:

Step-by-step explanation:

its c

The inequality that describes p, the area of a pizza that is larger than a small pizza 730 < p

From the information given, we have that;

Area of the small pizza = 730 square centimeters

p  = area of the larger pizza

In writing inequality, we have to use the signs

<  less than

> greater than

Since p has greater area, we have

730 < p

Thus, the inequality that describes p, the area of a pizza that is larger than a small pizza 730 < p

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Answer:

the answer is actually p > 730

Step-by-step explanation:

i juts checked on Kahn academy and i got it right..

Option A AY || XV given that A, Y, Z are midpoints of sides XW, VW, XV respectively. This can be obtained by knowing what similar triangles are and finding which sides are proportional.

Similar triangles: If two triangles have proportional sides the are similar.

For example, if ΔABC and ΔDEF are similar then

[tex]\frac{AB}{DE}= \frac{BC}{EF} =\frac{AC}{DF}[/tex]

∠ABC = ∠DEF and ∠ACB = ∠DFE

Then we can write that, ΔABC ~ ΔDEF

Here in this question,

Since A, Y, Z are midpoints of sides XW, VW, XV

XA = AW

WY = VY

XZ = VZ

To consider sides AY and XV we should take triangles ΔWAY and ΔWXV

[tex]\frac{WX}{WA} =\frac{2WA}{WA} = 2[/tex]  (since A is the midpoint of WX)

[tex]\frac{WV}{WY} =\frac{2WY}{WY} = 2[/tex]  (since Y is the midpoint of WV)  

∠AWY = ∠XWV (reflexive property)

Therefore ΔWAY and ΔWXV are similar triangles

[tex]\frac{WX}{WA}= \frac{XV}{AY} =\frac{WV}{WY}[/tex] = 2

∠WAY = ∠WXV and ∠AYW = ∠XVW

Hence,

AY || XV option A AY || XV given that A, Y, Z are midpoints of sides XW, VW, XV respectively.

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Disclaimer: The question was given incomplete on the portal. Here is the complete question.  

Question: Analyze the diagram below and answer the question that follows. If Z, Y and A are midpoints of ΔVWX what is true about AY and XY?

A. AY || XV

B. 1/2 AY = XV

C. AY = XV

D. AY ≅ XV

Answer:

A

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

(x + 15 + 19 + 23 + 41) / 5 = 20

x + 15 + 19 + 23 + 41 = 100

x + 98 = 100

x = 2

Answer: it’s 2 (A)

Step-by-step explanation:

20 * 5 = 100

15 + 19 + 23 + 41 = 98

100-98=2

From the given information, we get the value of ABC = 120°.

Given: In the figure, O exists the center of the circle and OABC exists as a parallelogram.

Now, the radius of the circle exists

OA = OB = OC

Opposite sides of a parallelogram are equal

AB = OC and OA = BC

In ∆OAB,

OA = OB = AB and,

In ∆OCB,

OC = OB = BC

Therefore, ∆OAB and ∆OCB exist in equilateral triangles.

All angles of an equilateral triangle are equivalent to 60°.

Hence, ∠ABC = ∠OBA + ∠OBC

∠ABC = 60° + 60°

∠ABC = 120°

Therefore, the value of ∠ABC = 120°.

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A function, C(x), to model the water used by the car wash on a shorter day will be (B) 3x³ + 4x² - 11x - 8.

To find a function, C(x), to model the water used by the car wash on a shorter day:

Given information -

Now the amount of water is cut from the total water usage so to find out the new model c(x) we need to subtract the decrease in water from the total water usage.

We are trying to find:

Therefore, a function, C(x), to model the water used by the car wash on a shorter day will be (B) 3x³ + 4x² - 11x - 8.

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The correct question is given below:

The water usage at a car wash is modeled by the equation W(x) = 4x3 + 6x2 − 11x + 7, where W is the amount of water in cubic feet and x is the number of hours the car wash is open. The owners of the car wash want to cut back their water usage during a drought and decide to close the car wash early two days a week. The amount of decrease in water used is modeled by D(x) = x3 + 2x2 + 15, where D is the amount of water in cubic feet and x is time in hours.

Write a function, C(x), to model the water used by the car wash on a shorter day

The equivalent angle in the interval [0, 2pi] is 5pi/6.

Remember that for any given angle θ in radians, we define a family coterminal or equivalent angles as:

A = θ + n*(2pi)

Where n is a whole number.

Now we want to find an angle equivalent to 17pi/6 that is on the range between 0 and 2pi.

Then we can write:

A = 17pi/6 + n*(2pi)

If we use n = -1, then we get:

A = 17pi/6 - 2pi = 17pi/6 - 12pi/6 = 5pi/6

This is the equivalent angle in the desired range.

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The measure of centre includes mean median and mode and the measure of variability includes range, interquartile range and mean absolute deviation.

A measure of central tendency (measure of centre) is a value that attempts to describe a set of data by identifying the central position of the data set.

The measure of central tendency includes the mean, median and mode.

The measure of variation describes the amount of variability or spread in a set of data.

The common  measures of variability are the range, the interquartile range (IQR), variance, and standard deviation.

Therefore, the measure of centre includes mean median and mode and the measure of variability includes range, interquartile range and mean absolute deviation.

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