cellular phones use radio waves to transmit information. if your cell phone uses a frequency of 1900 mhz, what is the wavelength of the electromagnetic radiation emitted by your phone?

The number of bright interference fringes in the central diffraction envelope is 3.

To determine the number of bright interference, we need to understand the equation of first minima in the diffraction pattern, and the equation of angular locations of the double slit interference pattern.

For the equation of first minima in the diffraction pattern is:

[tex]W[/tex]·[tex]Sin[/tex]θ = [tex]m_{1}[/tex]·λ

For the equation of angular locations of the double slit interference pattern is:

[tex]d[/tex]·[tex]Sin[/tex]θ = [tex]m_{2}[/tex]·λ..... (1)

Here, W is single slit width while d is slit separation

Next, we need to determine the number of bright interference fringes in the central diffraction envelope.

For the first minima, [tex]m_{1} = 1[/tex], then rewrite the equation (1) as follows.

=[tex]a[/tex]·[tex]Sin[/tex]θ = [tex]m_{1}[/tex]·λ

=[tex]a[/tex]·[tex]Sin[/tex]θ = [tex]1[/tex]·λ

=[tex]a[/tex]·[tex]Sin[/tex]θ = λ..... (2)

Then, from the equations (1) and (2)

[tex]=m_{2}=\frac{d}{w} \\=m_{2}=\frac{2w}{w}\\=m_{2}=2[/tex]

Therefore, there are 3 bright fingers, 1 at the centre and 2 in each side.

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If we keep oscilloscope plates close with potential difference 25 V , the  Charge on each plate will be 4.68 *10^-11 C.

The capacitance of a parallel plate capacitor is given by:

C = ∈₀A / d

where

∈₀ = 8.85 *10^-12 F/m is the vacuum permittivity

A is the area of each plate

d is their separation

For the capacitor in the problem:

A= 0.033m² = 0.0011m²

d = 5.2 mm = 0.0052 m

Substituting,

C = (8.85 *10^-12) (0.0011m)/ 0.0052 = 1.87 *10^-12 F

The capacity is related to the charge on the plate by:

Q=CV

where

V = 25.0 V is the potential difference between the plates

C = 1.87 *10^-12 F

Substituting,

Q = (25.0) (1.87 *10^-12) = 4.68 *10^-11 C

Charge on each plate = 4.68 *10^-11 C

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The tension in the cable is 4248 N.

The force transmitted through a rope, string, or wire when two opposing forces pull on it is known as tension. The tension force pulls energy equally on the bodies at the ends and is applied along the entire length of the wire.

Given parameters:

Weighs of the elevator, M = 300.0 kg.

weighs of Joey, m = 60.0 kg.

Upward acceleration of the elevator, a = 2.0 m/s².

And, acceleration due to gravity, g = 9.8 m/s².

So, net tension in the cable, T = (M + m)g + (M + m)a

= ( 300.0 + 60.0 ) × 9.8 N + (300.0 +60.0 )× 2.0 N

= 4248 N.

Hence, the tension in the cable that pulls the elevator upwards is 4248 N.

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According to the work-energy theorem, twice the speed corresponds to 4 times the energy and 4 times the driving distance.

There are different forms of energy on earth. The sun is considered the elementary form of energy on earth. In physics, energy is considered a quantitative property that can be transferred from an object to do work. Therefore, we can define energy as the force required for any  physical activity. So we can define energy in simple words as follows Energy is the ability to do work  According to the laws of conservation of energy, "energy can neither be created nor destroyed, it can only be changed from one form to another". The SI unit of energy is the joule.

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In both the cases gravitational potential energy is same.

Gravitational potential energy is energy an object possesses because of its position in a gravitational field. The most common use of gravitational potential energy is for an object near the surface of the Earth where the gravitational acceleration can be assumed to be constant at about 9.8 m/s².

Given two cases height of the top is 3 ft so the potential energy is same as potential energy is dependent on height of the ball.

In both the cases gravitational potential energy is same.

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Compared to the orbital speeds of the planets in our solar system, the Milky Way Galaxy's rotation curve is far more flat and steady. While there is less mass as we get farther from the sun in our solar system.

The orbital speed of an astronomical body or object (such as a planet, moon, artificial satellite, spacecraft, or star) in gravitational bound systems is its speed relative to the most massive body's centre of mass, or the barycenter, if one body is significantly more massive than the other bodies in the system put together.

The phrase can be used to describe either the mean orbital speed (i.e., the speed throughout the course of an orbit) or its instantaneous speed at a specific location in the orbit. For objects in closed orbits, the maximum (instantaneous) speed occurs at periapsis (perigee, perihelion, etc.), whereas the smallest speed occurs at apoapsis (apogee, aphelion, etc.). When two-body systems are perfect, things An astronomical body or object (such as a planet, moon, man-made satellite, spacecraft, or star) moves through space at a certain speed called its orbital speed in gravitational bound systems.

When a system closely resembles a two-body system, the object's specific orbital energy, also known as "total energy," and its distance from the central body can be used to calculate the object's instantaneous orbital speed at a specific point in the orbit. Independent of position, the specific orbital energy is constant.

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The magnification of this telescope is 12.

Solution:

F = 1200 mm = 120 cm

f = 32mm, 25mm, 14 mm, 10mm

M = F/f 120/ = 3.75

M = 120/25 =  4.8

M = 120/14 = 8.57

M = 120/10 = 12.

Magnification ratio means that the ratio of subject size on the sensor plane is greater than or equal to the actual size of the subject. This allows macro lenses to capture very sharp close-ups of insects, etc. The magnification produced by a lens is equal to the ratio of image distance to object distance. Total magnification In a compound microscope the total magnification is the product of the objective and ocular lenses.

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The internal resistance of the battery is 5.686ohms.

A battery's internal resistance (IR) is characterized as the resistance to current flow inside the battery. The internal resistance of a battery is primarily affected by two factors: electrical resistance.

The main causes of the increase in internal resistance with lead acid are sulfation and grid corrosion. Temperature has an impact on resistance as well; heat reduces it and cold increases it. An increase in runtime can be achieved by briefly lowering the internal resistance of the battery  

The formula below is used to determine the battery's internal resistance.

(V/R)r = V'

Make r the equation's subject.

r = V'R/V

Given:

V =  68.1  V

R = 20.6 ohms

V' = 18.8 V

r = (18.8×20.6)/68.1

r = 387.28/68.1

r = 5.686ohms.

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The self inductance of a length of such a pair of wires is

[tex]\frac{\mu_0}{\pi} \ln \left(\frac{d-a}{a}\right)[/tex]

Finding the magnetic field's constant current I and variable radius r due to one of the wires using Ampere's law

[tex]$\mu_0 I=\oint \vec{B} \cdot \vec{d} \mathrm{l}$[/tex]

[tex]$\begin{aligned} &=\int_0^{2 \pi} \mathrm{Br} d \theta \\ \mathrm{I} &=\mathrm{B}(2 \pi \mathrm{r}) \\ \mathrm{B} &=\frac{\mu_0 \mathrm{I}}{2 \pi \mathrm{r}} \end{aligned}$[/tex]

Keep in mind that one of the wires will generate the total magnetic flux () twice as much due to the setup's symmetry. The relationship between self inductance and flux is then maintained.

[tex]\begin{aligned}&\phi_{\text {total }}=2 \int_{\mathrm{A}} \overrightarrow{\mathrm{B}} \cdot \overrightarrow{\mathrm{dA}} \\&=2 \int_{\mathrm{a}}^{\mathrm{d}-\mathrm{a}}\left(\frac{\mu_0 \mathrm{I}}{2 \pi \mathrm{r}}\right) 1 \mathrm{dr}\end{aligned}[/tex]

Фtotal = [tex]$\frac{\mu_0 I l}{\pi} \ln \left(\frac{d-a}{a}\right)$[/tex]

Inductance, L=[tex]\frac{\phi_{\text {total }}}{\mathrm{I}}=\frac{\mu_0 1}{\pi} \ln \left(\frac{\mathrm{d}-\mathrm{a}}{\mathrm{a}}\right)[/tex]

Inductance per unit length Фtotal  =[tex]\frac{\mu_0}{\pi} \ln \left(\frac{d-a}{a}\right)[/tex]

Therefore the self-inductance of a length of such a pair of wires is [tex]=\frac{\mu_0}{\pi} \ln \left(\frac{d-a}{a}\right)[/tex]

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To find the equation of a circle using matrices, we need at least 3 data points.

The general equation for a circle is given by:

x² + y² + Cx + Dy + E = 0

There are 3 constants in the above equation, C, D, and E. Hence, we need 3 independent equations in order to get unique solution for C, D, and E.

To get 3 equations, we need minimum 3 data points.

Let the data points be: (x₁, y₁) , (x₂, y₂), and (x₃, y₃)

Substitute each data point into the general equation:

x₁² + y₁² + Cx₁ + Dy₁ + E = 0

x₂² + y₂² + Cx₂ + Dy₂ + E = 0

x₃² + y₃² + Cx₃ + Dy₃ + E = 0

The matrix form can be written as:

| x₁   y₁  1 |  | C |         | x₁² + y₁²  |

| x₁   y₁  1 |  | D | =  -   | x₂² + y₂² |

| x₁   y₁  1 |  | E |          | x₃² + y₃² |

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Tension is defined as the pulling force transmitted axially using a string, a rope, chain, or similar object, or by each end of a rod, truss member, or similar 3-D object; tension might also be expressed as the action-reaction pair of forces acting at each end of said elements.

Maximum tension:

T - mg = mv²/L

By energy conservation:

mgh = ¹/₂ mv²

v² = 2gh

Now the tension force in the vine at this position is given as:

T = mg +  mv²/L

Now substitute the values in the above equation:

T = 688 N + m(2gh)/L

T = 688 + 2×3.2(688)/18

T = 932.6 N

As the force is less than the limit of 950 N so the vine didn't break.

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The Schwarzschild Radius Rs of this black hole is 5.69 x [tex]10^{10}[/tex] m

The Schwarzschild radius or gravitational radius is a physical parameter in the Schwarzschild solution of Einstein's field equations that corresponds to the radius defining the event horizon of a Schwarzschild black hole.

Let's assume that the ring shaped disk is circular and thus, to find the mass of the object at the center of the milky way, we can use the circular orbit equation;

v = √(GM/r)

where;

G is the gravitational constant and has a value of 6.67 x 10^(-11) Nm²/kg²

R is the radius of the orbit,

M is the mass of the larger object

v = velocity = 190km/s = 190000 m/s

Also

1 light year = 9.4605 x 10^(15) m

Thus,7.5 light years = 7.5 x 9.4605 x 10^(15) m

so, M = v²r/G

Putting all the values in the equation,

M = [190000² x 7.5 x 9.4605 x 10^(15)]/6.67 x 10^(-11)

M = 3.84 x 10^(37) kg

Now, mass of the sun generally has a value of 1.9891 x 10^(30) kg

Thus, value of mass of object in solar masses = 3.84 x 10^(37)/1.9891 x 10^(30) = 1.931 x 10^(7) solar masses

The formula for Schwarzschild radius is given as;

Rs = 2GM/c²

Where c is speed of light = 3 x 10^(8) m/s

Thus,

Rs = 2 x 6.67 x 10^(-11) x 3.84 x 10^(37)/(3 x 10^(8))² = 5.69 x [tex]10^{10}[/tex] m

The Schwarzschild radius Rs of this black hole is 5.69 x [tex]10^{10}[/tex] m

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An electron degenerate object is a white dwarf, whereas a neutron star is a neutron degenerate object. A white dwarf is less compact and has a larger radius than a neutron star.

A white dwarf would collapse into a denser entity known as a neutron star if it reached the Chandrasekhar limit and nuclear reactions were to stop. This would happen if nuclear reactions continued to occur.

White dwarf stars are prevented from collapsing by the fact that electrons are fermions, while neutron stars are prevented from collapsing by the fact that electrons are fermions.

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The angle of just resolution light from two stars is greater if the light of the average star is red or if it is blue.

The formula to find the aperture of the telescope

D = 1.22λ/dФ

Limits of resolution:

The limit of resolution is a measure of the ability of the objective lens to separate in the image adjacent details that are present in the object.

There is diffract in the light when it passed through space and gets bent around obstacles. Diffraction grants disperse light according to wavelength, for example, it can be used to produce spectra.

Therefore an astronomical telescope is used to view distant stars. The angle is greater if the light of the average stars is red or if it is blue.

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The GPE that the barbells have at max height is ,

3680.h j=11,000 units

where h= maximum height the barbells were lifted

work done by the championship lifter ,W = 11,000 units

weight of the barbells, N = 3680 N

The gravitational potential energy, P.E., the barbells had at their maximum height of lift is given as follows;

P.E. = m × g × h

Where;

m = The mass of the barbells;

g = The acceleration due to gravity = 9.8 m/s^2

h = The maximum height to which the barbells are lifted

m × g = The weight of the barbells = 3680 N

∴ P.E. = 3680 N × h = 3680·h J

we know the law of conservation of energy, according to this the work done by the weight lifter is equals to the maximum gravitational potential energy gained by the barbell is equal to energy at maximium height i.e P.E

therefore, GPE = 3680.h j = W = 11,000j is your answer.

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The acceleration of the box is 3.4m/s² and if the box starts from rest at constant force for 3 seconds, then the speed of the box will be 10.2m/sec

The frictional force (f) = μN

where μ= coefficient of kinetic friction

N = Normal force = mg

The given value for μ = 0.10

∴ f = 0.10 × 45 × 10

f = 45 N

Hence F net = applied force - frictional force

F net = 200 - 45

F net = 155N

Thus, the acceleration of box (a) will be, F = ma

where m = mass of box =45kg

a = F /m

a = 155/45

a = 3.4 m/s²

a) Hence acceleration of the box pulled horizontally is 3.4m/s²

The speed of the box pulled, if initially the box was at rest and constant force is applied for 3 seconds,

v = u + at

v = 0 + 3.4 × 3

v = 10.2 m/s

b) Hence, the speed of the box at constant force is 10.2m/s

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The energy from the sun can be maximized by the use of a photocell.

We know that energy is the ability to do work. The only source y which energy can be able to enter into the ecosystem is by the energy that comes from the sun. It is the plants that are able to access this energy that comes from the sun and are able to convert it into the form that could be used by living things.

Humans can access the energy that is produced by the sun and then use it to be able to power some devices. This is the origin of the photocells and is a good way to put the solar energy to good use.

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Answer:

relax

Explanation:

your answer is right there in front of you force = weight

area of feet = area

while your pressure = force per unit area i.e

force/area = 600/0.03

= 2 × 10⁵

Two projectiles of mass and are fired at the same speed but in opposite directions from two launch sites separated by a distance, will land at a place x = D/2 [ 1+{ (m₁ - m₂) / m₁ + m₂)}

This is calculated using the conservation of linear momentum in the horizontal direction as ,

(vm₁vₓ₁ - m₂vₓ₁ ) ₓî = (m₁ + m₂) vₓ₂ ₓî

vₓ₂ = {(m₁ - m₂) / m₁ + m₂)} × vₓ₁

vₓ₂ = {(m₁ - m₂) / m₁ + m₂)} × v Cos Θ

t max = vₓ₁ / g

=  v Sin Θ / g

x =(D / 2) + vₓ₂t max

= (D / 2) { {(m₁ - m₂) / m₁ + m₂)} × v² Sin Cos Θ / g } ------ (1)

now,

D = 2 vₓ₁vₓ₂ / g

D / 2 = v² Sin Cos Θ / g

From equation (1) we get,

x = D/2 [ 1+{ (m₁ - m₂) / m₁ + m₂)}

Hence , D/2 [ 1+{ (m₁ - m₂) / m₁ + m₂)} is the place they will land.

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Answer:

1.25 cm³

Explanation:

m = 7.0 g

d = 5.6 g/cm³

v = ?

Using,

[tex] d \: = \frac{m}{v} [/tex]

[tex]v = \frac{m}{d} [/tex]

[tex]v = \frac{7}{5.6} [/tex]

[tex]v = 1.25 \: c {m}^{3} [/tex]

Mass of to object is 3 kg and 2 kg.

What is Gravitational force?

In mechanics, gravity, often known as gravitation, is the universal force of attraction that acts between all matter. It is by far the weakest known natural force and so has no effect on the internal properties of ordinary stuff. Due to its long reach and ubiquitous action, it influences the trajectories of bodies in the solar system and elsewhere in the universe, as well as the architecture and evolution of stars, galaxies, and the entire cosmos. The weight, or downward force of gravity, exerted by the Earth's mass on all bodies on Earth is proportional to their mass. The acceleration that freely falling objects experience is used to calculate gravity.

F =G(m1m2/r2)

m1m2 = [(1.00 X 10-8N)(20*10-2m)2]

/[6.67*10-11Nm2/kg2]

Now

m1-m2 =[(m1+m2)2-4m1m2] =[(5kg)2-4(6kg2)] =(1kg2) = 1kg 2m1 =

(m1+m2)+(m1-m2) = 5kg + 1kg =6kg

m1 = 3kg, m2 = 5kg,

and

m2 = 5kg - 3kg = 2kg

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The car would be moving with a velocity of 21 m/s at the end of the five seconds.

We know that the first equation of motion is ⇒ v = u + at (i)

Here, the car moves with an initial velocity, u =  8.5 m/s (ii)

The car accelerates at a constant rate, a = 2.5 m/s² (iii)

The total time during this process, t = 5 seconds (iv)

Putting the values of the initial velocity, acceleration, and time (ii, iii, and iv) in equation (i), we get ⇒ v = 8.5 + (2.5)(5)

v = 21 m/s

Therefore, the car moves with a final velocity of 21 m/s at the end of the five seconds.

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Answer:

2. The object must have zero average acceleration over the interval.

Explanation:

Notes:

-Velocity can have zero change if it is either at rest or moving at a constant velocity. This also means there is zero acceleration (acceleration is any change in velocity).

-Velocity is also speed and direction, so if it changes direction (for example: moving backward or in a circle) it is not constant even if it has a constant speed. It also means the object is accelerating.

1: Nothing can be determined without additional information.

Incorrect, because it is solvable by the process of elimination.

2: The object must have zero average acceleration over the interval.

Correct, because zero acceleration equals zero change in velocity.

3: The object must be changing position.

Incorrect, because you don't know whether or not the object is accelerating.

4:  The object must have zero average velocity over the interval.

Incorrect, because this implies it is at rest. To have zero change, it can be at rest OR moving at a constant velocity.

5:  The object must have constant velocity over the interval.

Incorrect, because zero change in velocity can mean either be at rest OR moving at a constant velocity.

6: The object must begin and end at the same position.

Incorrect, because to begin and end at the same position implies that it was at rest or it changed direction while moving to end at the same position. (see Notes above for explanation)

7: The object must have constant acceleration over the interval.

Incorrect, because you can't have zero change in velocity if there is acceleration (Acceleration is any change in velocity).

8: The object must be at rest.

Incorrect, because to have zero change, it can be at rest OR moving at a constant velocity.

Answer:

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What is the condition for a force to do work on a body ?

Question

What is the condition for a force to do work on a body ?

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Solution

The condition of force to do some work is that the force should be along the direction of displacement.

work is done when the object moves through a certain distance in a particular direction after the force had been applied on it.

Work Done = Force x Distance x Cos theta

For work to be done, the force must be applied and must not be zero.

The body on which the force is applied must move in one direction or the other and hence the S must not be zero.

The force must not be applied at 90 degrees angle upon the object as Cos 90 equals zero.

The correct answer is 0.41 R. Option A.

Solution:

We have given acceleration due to gravity at any height is new = 4.9m/sec²

The radius of the earth = r

We know that acceleration due to gravity at any height is given by

g¹ = GM/(R + h)²...eqn 1

And acceleration due to gravity at the earth g = GM/R²...eqn2

Dividing eqn 2 by eqn 1

g/g¹ = (r+h)²/r²

9.8/4.9 =  (r+h)²/r²

2r² = (r+h)²

[tex]\sqrt{2r}[/tex] = h+r

h = 0.41r

Gravitational acceleration decreases as one moves deeper into the earth, reaching zero at the center of the earth. Similarly, the gravitational force is said to decrease with distance from the Earth's surface and become zero at infinity.

The projectile's instantaneous velocity at maximum altitude is zero. Gravity gives the ball the same acceleration when it rises as it does when it descends so the time to reach the maximum height is the same as the time to return to the starting position. increase.

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For mass movements, gravity is the primary driving force. A trigger is frequently present in mass-wasting occurrences.

It could be caused by human operations like grading a new road, quake shaking, super volcano, storm waves, or storm-related waves. Mass-wasting is most frequently caused by an increase in water content in the slope. Rapidly dissolving snow or ice, as well as a heavy downpour, can cause the water content to rise. The force of gravity pulls everything towards to the Earth’s centre from every point on its surface. Gravity pulls downward on a level surface that is also parallel to the surface of the Earth. The stability of the consolidated and poorly consolidated earth materials can be compromised by gravity, increasing moisture content, and seismic events. The earth material slides down slope due to the compromised stability, a process known as mass wasting.

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Answer:

false is the answer . in my point of view

The coefficient of kinetic friction among the floor and the field is 0.092.

Friction is a form of touch force. It exists among the surfaces which might be in touch. The frictional pressure depends at the person of the surface in touch. The rougher the ground, the greater the friction is worried. The frictional force is proportional to the pressing pressure, it's the load of the frame. it is independent of the region of the contact.

Calculation:-

mass = 5 kg

distance travelled = 5 m

initial speed = 3 m/s

v² = u² -2as

a = u²/2s

 = 3²/2 × 5

 = 0.9 m/s²

F = μkN

ma = μkmg

5×0.9 = μk 5 ×9.8

μk = 4.5/49

     = 0.092

Friction is the force resisting the relative movement of strong surfaces, fluid layers, and material factors sliding in opposition to every different. There are numerous forms of friction: Dry friction is a strain that opposes the relative lateral motion of two strong surfaces in touch.

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It is possible for a smaller force with a longer time to be stronger than a larger force with a shorter time since impulse equals force x time.

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