Choose the smallest number. 3/18 10/3

Answer:

theta = 44.4 degrees

Step-by-step explanation:

Since this is a right triangle, we can use trig formulas

cos theta = opposite/ hypotenuse

cos theta = 15/21

Take the inverse of each side

cos^ -1 (cos theta) = cos ^-1 (15/21)

theta =44.4153086

theta = 44.4 degrees

Answer:

[tex]{ \tt{ \cos(A) = \frac{ \sqrt{700} }{40} }} \\ { \tt{ \cos(A) = 0.66 }}[/tex]

Step-by-step explanation:

Step 2:

[tex] ({15x}^{2} - 9x) + (5x - 3)[/tex]

Stepc3:

[tex]3x(5x - 3)[/tex]

Answer:

f=x−32

Step-by-step explanation:

Subtract 3232 from both sides.

Answer:

f=32.2m

Step-by-step explanation:

got it right on edge

Answer:

x = 3     y = 5

Step-by-step explanation:

     y=x+2

+    y=-x +8

2y = 10

y = 5

y = -x + 8

5 = -x + 8

x = 3

Answer:

D

Step-by-step explanation:

Answer:

(a) T = 16√x

Step-by-step explanation:

T is directly proportional to √x, so we can say,

T=k√x (where k is a constant)

now, according to the question,

400=k×√625

400=k×25

k=16

so, putting the value of k in the equation, T=16√x

Answered by GAUTHMATH

Step-by-step explanation:

Given that ,

Mathematically we can write it as ,

[tex]\implies T \propto \sqrt{x}[/tex]

Let k be the constant , therefore ,

[tex]\implies T = kx [/tex]

Now when T = 400 and x = 625 , lets find the value of k , as ,

[tex]\implies 400 = k\times 625 \\\\\implies k =\dfrac{400}{625}\\\\\implies k= 0.64 [/tex]

Therefore the required formula will be ,

[tex]\implies \underline{\underline{ T = 0.64x}} [/tex]

4. MIke divided the group into 5 groups. If there were 28 people in each group how big was the original group?

a. What are they asking for?

how big was the original group?

b. identify all the necessary numbers.

28,5

c. write the equation or problem in numeric form.

x=28*5

d. solve the math.

x=140

e.write the answer

. the original group contains 140 people.

5. If he difference is 589 and the subtrahend is 339,what is the minuend?

a. What are they asking for?

what is the minuend?

b. identify all the necessary numbers.

589,339

c. write the equation or problem in numeric form.

x=589-339

d. solve the math.

x=250

e.write the answer.

minuend=250

6. If the quotient is 17 and the dividend 765, what is the divisor?

a. What are they asking for?

what is the divisor?

b. identify all the necessary numbers.

17,765

c. write the equation or problem in numeric form.

x=765/17

d. solve the math.

x=45

e.write the answer.

divisor is 45.

4. Solution

a. How big was the original group?

b. 28 and 5

c. x = 28×5

d. x = 140

e. There are 140 people in original group.

5. Solution

a. What is the minuend?

b. 589 and 339

c. x = 589-339

d. x = 250

e. The minuend is 250.

6. Solution

a. What is the divisor?

b. 17 and 765

c. x = 765/17

d. x = 45

e. Hence, 45 is the divisor.

Answer:

y= ¼x +1

Step-by-step explanation:

Rewriting the equation into the slope-intercept form (y= mx +c, where m is the gradient and c is the y- intercept):

4y -x= -20

4y= x -20 (+x on both sides)

y= ¼x -5 (÷4 throughout)

Thus, slope of given line is ¼.

Parallel lines have the same gradient.

Gradient of line= ¼

y= ¼x +c

To find the value of c, substitute a pair of coordinates into the equation.

When x= 8, y= 3,

3= ¼(8) +c

3= 2 +c

c= 3 -2

c= 1

Hence the equation of the line is y= ¼x +1.

Answer:

The answer is B

Step-by-step explanation:

B

The 22 Australian dollar in USD is 18.33.

Currency is a medium of exchange for goods or services within an economy, usually issued by a government or central bank and generally accepted at its face value.

Given that, we need to determine that there are how many USD in 22 AUD,

So, 1.2 Australian dollars equals 1 US dollar.

Therefore,

22 AUD = 22 x 1 / 1.2 = 18.33

Hence, the 22 Australian dollar in USD is 18.33.

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Given the 22 m. horizontal distance and the angles of elevation of 26°

and 31° gives the height of the building as approximately 2.49 meters.

Horizontal distance from the building = 22 m

Angle of elevation to the top of the roof = 26°

Angle of elevation to the top of the antenna = 31°

Height of his eyes from the ground = 1.53 m

Required:

The height of the antenna.

Solution:

In a right triangle, we have relative to an angle of the triangle, we have;

Opposite side = Adjacent side

Height of the building + Height of antenna = [tex]1.53 + 22 \times tan \left(31^{\circ} \right)[/tex] ≈ 14.75

Which gives;

Height of the building = [tex]1.53 + 22 \times tan \left(26^{\circ} \right)[/tex] ≈ 12.26

Therefore;

Height of the antenna ≈ 14.75 - 12.26 ≈ 2.49

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Answer:

Profit % = 39%

Step-by-step explanation:

Cost price of the article = 9

Price for repairing = 4

Therefore, Total cost of the article = 9 + 4 = 13

Selling price  of the article = 18

Profit = 18 - 13 = 5

Hence,

          [tex]Profit \% = \frac{Profit}{Cost \ price} \times 100\\\\[/tex]

                        [tex]= \frac{5}{13} \times 100\\\\=38.46 \%\\\\=38.5 \%[/tex]

Profit percent (to the nearest %) = 39%

Answer:

[tex]Height = x - 5[/tex] --- one of the dimension

Step-by-step explanation:

Given

[tex]Volume = 4x^3 - 20x^2 + 3x - 15[/tex]

Required

The side dimension

Factorize the given expression

[tex]Volume = 4x^2 (x- 5) + 3(x - 5)[/tex]

Factor out x - 5

[tex]Volume = (4x^2 + 3)(x - 5)[/tex]

Volume is the product of base area and height'

Hence:

[tex]Area = 4x^2 + 3[/tex]

[tex]Height = x - 5[/tex]

Proportional Linear Relationships can be expressed in the following ways:

From a graphical point of view, a relationship is proportional and linear if the line representing the equation goes via the origin. It is to be noted that a relationship must be linear for it to be proportional and vice versa.

Thus, it is correct to state that Proportional Linear Relationships can be expressed in the following ways:

An example of an equation that is proportional and linear is:
y = 6x + 8. Note that this linear equation is proportional because it has a constant component.

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Answer:

quadratic binomial

[tex]{ \boxed{ \bf{a {x}^{2} + bx + c }}} \\ 2 {g}^{2} + 3g - g[/tex]

Evelyn and Meredith were paddling at a rate of [tex]\frac{3+\sqrt{493}}{11}mph[/tex] which is equivalent to 2.29mph approximately.

Step 2: See attached picture

Step 3: In this case we only have different variables, there is the rate at which Evelyn and Meredith were paddling, the rate at which they moved when rowing upstream, the rate at which they moved when rowing downstream, the time it took them to paddle upstream and the time it took them to paddle downstream.

v = rate at which Evelyn and Meredith were paddling.

[tex]v_{up}[/tex]= velocity at which they were moving when paddling upstream.

[tex]v_{down}[/tex]= velocity at which they were moving when paddling downstreamstream.

[tex]t_{up}[/tex]= time it took them paddling upstream.

[tex]t_{down}[/tex]= time it took them paddling downstream

Se attached picture for the table.

Step 4: Building this equation will require us to combine different equations into a single one. Let's start with the equation for the final rate at which they paddled when rowing upstream.

[tex]v-2=v_{up}[/tex]

When rowing upstream, the current will drag the kayak, so we subtract it from the rate at which they were rowing.

Let's find the final rat at which they moved when rowing downstream.

[tex]v+2=v{down}[/tex]

next, the problem tells us it took them 3 hours and 40 minutes to row up and down the channel so we can convert it into just hours like this:

[tex]40min*\frac{1hr}{60min}=\frac{2}{3}hr[/tex]

[tex]3hr+\frac{2}{3}hr=\frac{11}{3}hr[/tex]

so now we can build our equation for time.

[tex]t_{up}+t_{down}=\frac{11}{3}[/tex]

We also know that the rate is built by dividing the distance over the time it took them to travel the distance, so:

[tex]v_{up}=\frac{1}{t_{up}}[/tex]

[tex]v_{down}=\frac{1}{t_{down}}[/tex]

If we solved each of those equations for their respective times, we would end up with the following:

[tex]t_{up}=\frac{1}{v_{up}}[/tex]

[tex]t_{down}=\frac{1}{v_{down}}[/tex]

so we can now combine all the equations together so we get:

[tex]t_{up}+t_{down}=\frac{11}{3}[/tex]

[tex]\frac{1}{v_{up}}+\frac{1}{v_{down}}=\frac{11}{3}[/tex]

[tex]\frac{1}{v-2}+\frac{1}{v+2}=\frac{11}{3}[/tex]

So this equation models the problem.

Step 5: We can solve this equation by multiplying everything by the LCD

In this case the LCD is:

3(v-2)(v+2)

so, when doing the respective multiplications we end up with:

[tex]\frac{3(v-2)(v+2)}{v-2}+\frac{3(v-2)(v+2)}{v+2}=\frac{11(3)(v-2)(v+2)}{3}[/tex]

We can now simplify to get:

3(v+2)+3(v-2)=11(v+2)(v-2)

We can now do the respective multiplications to get:

[tex]3v+6+3v-6=11(v^{2}-4)[/tex]

and we can further simplify:

[tex]6v=11v^{2}-44[/tex]

Step 5: So we can now solve it by using the quadratic formula, first, we need to rewrite the equation in standard form:

[tex]11v^{2}-6v-44=0[/tex]

So we can now use the quadratic formula:

[tex]v=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a}[/tex]

we substitute:

[tex]v=\frac{-(-6) \pm \sqrt{(-6)^{2}-4(11)(-44)}}{2(11)}[/tex]

and simplify:

[tex]v=\frac{6 \pm \sqrt{36+1936}}{22}[/tex]

[tex]v=\frac{6 \pm \sqrt{1972}}{22}[/tex]

[tex]v=\frac{6 \pm \sqrt{4(493)}}{22}[/tex]

[tex]v=\frac{6 \pm 2\sqrt{493}}{22}[/tex]

[tex]v=\frac{3 \pm \sqrt{493}}{11}[/tex]

this gives us two possible results:

[tex]v=\frac{3 + \sqrt{493}}{11}[/tex] and [tex]v=\frac{3 - \sqrt{493}}{11}[/tex]

Step 6: We only pick the first result since it's the positive result. We don't take the second one because a negative result represents the kayak moving in the opposite direction which is not how the situation was modeled.

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Answer:

1000

Step-by-step explanation:

Given data

we have the sequence

25, 10, -5, ...

we want to find the 66th term, let us apply the formula

an = a + (n – 1)d

a= 25

n= 66

d= 15

substitute

a66= 25+(66-1)15

a66= 25+(65)*15

a66= 25+975

a66= 1000

Hence the 66th term is 1000

Answer:

nom nom

Step-by-step explanation:

nom nommy nom nom

Step-by-step explanation:

log 25 + log 8 = log (25 × 8) = log 200

log 200 - log 2 = log (200 ÷ 2) = log 100

logarithm base 10 of 100 is 2.

Answer:

:

Example Question #1:

Step-by-step explanation:

Which of the following is the equation of a line that is parallel to the line 4x – y = 22 and passes through the origin?

Possible Answers:

4x – y = 0

(1/4)x + y = 0

4x + 8y = 0

4x = 8y

y – 4x = 22

Correct answer:

4x – y = 0

Explanation:

We start by rearranging the equation into the form y = mx + b (where m is the slope and b is the y intercept); y = 4x – 22

Now we know the slope is 4 and so the equation we are looking for must have the m = 4 because the lines are parallel. We are also told that the equation must pass through the origin; this means that b = 0.

In 4x – y = 0 we can rearrange to get y = 4x. This fulfills both requirements.

', .

Answer:

Diameter = 14 units

Step-by-step explanation:

Volume ofa cylinder = πr²h

Volume of the cylinder = 245π cubic units

Height = 5 units

Volume of a cylinder = πr²h

245π = π × r² × 5

245π = 5r²π

Divide both sides by π

245π / π = 5r²π / π

245 = 5r²

r² = 245/5

= 49

r² = 49

r = √49

r = 7 units

Diameter = 2 × radius

= 2 × 7 units

= 14 units

Diameter = 14 units

Answer:

The temperature at the start is 35F

The temperature of the room is 74F

Step-by-step explanation:

Given

[tex]T(m) = 74 - 39(0.87)^m[/tex]

Solving (a): The temperature at the start.

To do this, we set: [tex]m = 0[/tex]

So, we have:

[tex]T(0) = 74 - 39(0.87)^0[/tex]

[tex]T(0) = 74 - 39*1[/tex]

[tex]T(0) = 74 - 39[/tex]

[tex]T(0) = 35[/tex]

Hence, the temperature at the start is 35F

Solving (b): The room temperature

We have:

[tex]T(m) = 74 - 39(0.87)^m[/tex]

To get the temperature of the room, we simply remove the exponential function.

So, we have:

[tex]Initial = 74[/tex]

Hence, the temperature of the room is 74F

The initial temperature of the liquid is 35 F and the room temperature is 74 F.

The melting point is the temperature at which the solid starts converting into liquid.

Given here,

[tex]T_m = 74- 39(0.87)^m[/tex]

Leat the [tex]m = 0,[/tex]

So,

[tex]T_0 = 74- 39(0.87)^0\\\\T_0 = 35 \rm \ F[/tex]

Thus the initial temperature is 35 F.

Now remove the exponential to get the room temperature,

So,

[tex]T_{RT} = 74[/tex]

Therefore, the initial temperature of the liquid is 35 F and the room temperature is 74 F.

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Answer:

B = 34.77°

Step-by-step explanation:

For this problem you are given all three side lengths and asked to find an angle. To do this you can use the law of cosines which is written:

[tex]b^{2} =a^{2} +c^{2} -2ac Cos(B)[/tex]

This can be rearranged to find the angle B:

[tex]b^{2} -a^{2} -c^{2} /-2ac = Cos(B)[/tex]

With lowercase letters being sides and uppercase being angles.

We simply plug in the sides and solve:

[tex]4^{2} -6^{2} -7^{2}/-2*6*7= Cos(B)[/tex]

0.8214 = Cos (B)

Then you use inverse cosine to get angle B alone.

B = 34.77°

Answer:

Height of the goalpost is 9.25 m.

Step-by-step explanation:

As per the rule of reflection in physics,

Angle of incidence = Angle of reflection

As we can see in the picture attached, both the angles (θ) are equal.

m∠ACB = m∠ECD = 90° - θ

m∠ABC = m∠ADC = 90°

Therefore, both the triangles ΔABC and ΔEDC will be similar.

And by the property of similar triangles, their corresponding sides will be proportional.

[tex]\frac{AB}{ED}= \frac{CB}{CD}[/tex]

[tex]\frac{1.75}{ED}=\frac{2.6}{13.75}[/tex]

ED = [tex]\frac{1.75\times 13.75}{2.6}[/tex]

ED = 9.25 m

Height of the goalpost is 9.25 m.

Answer:

Step-by-step explanation:

if it is rotated in clockwise direction then C'(-2,-3),D'(2,-5),E'(0,-7)

if rotated in anticlockwise direction C'(2,3),D'(-2,5),E'(0,7)

Answer:

7 a⁴ b³

Step-by-step explanation:

-7 ( -a²)²( - b ³)

= -7 ( a²)² ( - b³)

= - 7 ( a²)² × b³

= (-7)( a²*² )× b³

= 7 a⁴ b³

Answer:

Solution given:

(-a²)=-a*-a=a²

-b³=-b*-b*-b=-b³

now

-7(-a²)²(-b³)=-7*a⁴*-b³=-7*-1 *a⁴b³=7a⁴b³

the product is 7a⁴b³.

so

enter"+".

Answer:

[tex]m\angle 2=122^{\circ},\\m\angle 1 = 58^{\circ}[/tex]

Step-by-step explanation:

By definition, tangent lines touch a circle at one point. This one point intersects the circle at a 90 degree angle.

In any circle, the measure of an inscribed angle is exactly half of the arc it forms. Since [tex]\angle 2[/tex] forms an arc labelled 244 degrees, the measure of angle 2 must be [tex]\frac{244}{2}=\boxed{122^{\circ}}[/tex].

Angle 1 and 2 form one side of a line. Since there are 180 degrees on each side of the line, we have:

[tex]\angle 1+\angle 2=180,\\\angle 1 + 122=180,\\\angle 1=180-122=\boxed{58^{\circ}}[/tex]

Answer:

Luis’s, because he flipped the inequality sign when he subtracted

Step-by-step explanation:

7.2b + 6.5 > 4.8b – 8.1.

Amelia started by subtracting 7.2b from both sides to get

6.5 > –2.4b – 8.1

Correct

Luis started by subtracting 4.8b from both sides to get

2.4b + 6.5 < – 8.1

Incorrect

Shauna started by subtracting 6.5 from both sides to get

7.2b > 4.8b – 14.6

Correct

Clarence started by adding 8.1 to both sides to get

7.2b + 14.6 > 4.8b

Correct

Luis’s is incorrect because he flipped the inequality sign when he subtracted