Choose the system for the graph.
y 2 2x+2
y2-x
A.
B.
C.
D.
≤ 2x - 1
yz -x + 2
y≤-2x + 2
(y 2 x
ys 2x + 2
y >- 1x

Step-by-step explanation:

Area of rectangle= length × breadth

A= a²+6a+8

= a²+4a+2a+8

= a(a+4) + 2(a+4)

= (a+4)(a+2)

length= a+4

breadth= a+2

The true statement is (c) Amal's work is incorrect because it includes a positive two instead of a negative two in the answer

The complete question is added as an attachment

From the table, we have

Divisor = x^2 - 3x + 4

Quotient = 2x + 5

Dividend = -2x^3 + 11x^2 - 23x + 20

See that the signs of the leading coefficients of the dividend and the divisor are different

This means that the leading coefficient of the quotient must be negative

From the question, we have:

Quotient = 2x + 5

The expression 2x + 5 has a positive leading coefficient

Hence, the true statement is (c) Amal's work is incorrect because it includes a positive two instead of a negative two in the answer

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Answer:

  9.08

Step-by-step explanation:

To find the predicted value of y, put the x-value where x is in the equation and do the arithmetic.

  [tex]\hat{y}=134.63-2.79x\qquad\text{given}\\\\\hat{y}=134.63-2.79(45) = 134.63-125.55\qquad\text{use 45 for x}\\\\\boxed{\hat{y}=9.08}\qquad\text{simplify}[/tex]

Answer:

The graph of g(x) has a y-intercept at (0,0) and a slope of -2.

Answer:

7

Step-by-step explanation:

Given the information from the question:

[tex]fg - f = f \times g - f[/tex]

Next we can use the order of operations to find the value of the expression.

[tex]fg - f = - 6 \times - 1 - ( - 1) \\ = 6 - ( - 1) \\ = 6 + 1 \\ = 7[/tex]

Step-by-step explanation:

we have 2 blocks, as the graphic shows.

the surface areas of both blocks are the sum of their 6 sides each.

the special thing about seeing them as "composite figure" is that 2 sides (one for each block) are partly or even completely blocking each other off from being seen, so these parts and whole side are not part of the combined surface area.

let's start with the large block :

it is 5cm × 6cm × 20cm.

its surface area is the sum of

top and bottom 5×6

front and back 20×5

left 20×6

visible right (20 - 12)×6 = 8×6

it is (20-12)cm long, because the short block

is 12cm high.

so, we have

2 times 5×6 =2×30 = 60 cm²

2 times 20×5 = 2×100 = 200 cm²

20×6 = 120 cm²

8×6 = 48 cm²

in total : 428 cm²

now the small block :

it is 4cm × 6cm × 12cm.

its surface area is the sum of

top and bottom 4×6

front and back 4×12

no left (completely covered by the large block)

right 6×12

so, we have

2 times 4×6 = 2×24 = 48 cm²

2 times 4×12 = 2×48 = 96 cm²

6×12 = 72 cm²

in total : 216 cm²

the complete surface area of the composite figure is

428 + 216 = 644 cm²

Answer:

  triangle angle sum theorem

Step-by-step explanation:

The missing statement is one that justifies the sum of the angles in a triangle being 180°.

That justification is provided by the ...

  triangle angle sum theorem

Answer:

10

Step-by-step explanation:

Every number with exponent zero is equal to 1

(7³×8)⁰ = 1

5⁰ = 1

then:

(3² + 5⁰) / (7³×8)⁰

= (3² + 1) / 1

= (9+1) / 1

= 10

3^2 = 9

3^2 = 95^0 =1

(7^3 x 8)^0 is 1

(anything to power of zero is one)

9 + 1 / 1 gives us the fraction 10/1

10/1 + 1/3 => make denominator the same, so I'll multiply 10/1 by 3

We get : 30/3 + 1/3 => 31/3

Thus answer is 31/3

Hope this helps!

Answer:

3; 1

Step-by-step explanation:

when there are six spots we can see that there are 2 eyes

so

divide both sides by 2

6:2

6 / 2 : 2 / 2

3 : 1

that is your answer

Answer:

a) $20,771.76

b) $20,817.67

c) $20,484.80

d) $20,864.52

Step-by-step explanation:

Compound Interest Formula

[tex]\large \text{$ \sf A=P\left(1+\frac{r}{n}\right)^{nt} $}[/tex]

where:

Part (a): semiannually

Given:

Substitute the given values into the formula and solve for A:

[tex]\implies \sf A=15000\left(1+\frac{0.055}{2}\right)^{2 \times 6}[/tex]

[tex]\implies \sf A=15000\left(1.0275}{2}\right)^{12}[/tex]

[tex]\implies \sf A=20771.76[/tex]

Part (b): quarterly

Given:

Substitute the given values into the formula and solve for A:

[tex]\implies \sf A=15000\left(1+\frac{0.055}{4}\right)^{4 \times 6}[/tex]

[tex]\implies \sf A=15000\left(1.01375}\right)^{24}[/tex]

[tex]\implies \sf A=20817.67[/tex]

Part (c): monthly

Given:

Substitute the given values into the formula and solve for A:

[tex]\implies \sf A=15000\left(1+\frac{0.055}{12}\right)^{12 \times 6}[/tex]

[tex]\implies \sf A=15000\left(1+\frac{0.055}{12}\right)^{72}[/tex]

[tex]\implies \sf A=20484.80[/tex]

Continuous Compounding Formula

[tex]\large \text{$ \sf A=Pe^{rt} $}[/tex]

where:

Part (d): continuous

Given:

Substitute the given values into the formula and solve for A:

[tex]\implies \sf A=15000e^{0.055 \times 6}[/tex]

[tex]\implies \sf A=20864.52[/tex]

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if there was a random selection of  cartons from each of the groups to measure grams of fat. This is an example of stratified sampling

Stratified sampling can be defined as a method of sampling that involves  division of a population into smaller groups or items, these are called strata.

This groups or strata are then arranged or organized based on the shared characteristics or attributes of the members in the group of the given population.

Stratification is the process of classifying the population into groups.

Features of  stratified sampling are;

From the information given, we can see that it is an example of stratified sampling.

Thus, if there was a random selection of cartons from each of the groups to measure grams of fat. This is an example of stratified sampling

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Answer:

Step-by-step explanation:

Equation

f(x) = (8x + 1) / (2x + 9)

Notice the brackets. They are necessary to show what comes before the division sign, and what comes after.

Behavior

The best way to state the behavior is to get something like a graphing program to show you what the curve looks like -- where it's critical points are for example. I use Desmos for  this kind of question, Just do a search for Desmos and bookmark it. You will use it quite often.

So you want to know the behavior.

Right Curve

Crosses the x axis at (-0.125, 0)

Crosses the y axis at (0,0,111)

The right curve has a domain of -∞ < x < ∞

The  right curve has a range of -∞ < x < ∞

The range is going to have to go out quite a ways before you see any dramatic decrease in the way it is drawn.

Left Curve.

The right hand curve never crosses either the x or y axis.  Nor does it just touch the x or y axis.

The domain is -∞ <x < 0

The range is 0<x<∞

The polar equation of an ellipse is [tex]r=-\frac{3}{1+2cos\theta}[/tex].

The vertices of ellipse are (−1,0) and (3,0).

The polar equation of an ellipse can be represented as

[tex]r=\frac{ep}{1+ecos\theta}[/tex]

where e is the eccentricity.

Eccentricity, e = [tex]\frac{c}{a}[/tex]

c is the distance from the center to the focus and a is the distance from the center to the vertex

[tex]c=\frac{3-(-1)}{2}[/tex]

⇒ [tex]c=\frac{4}{2}[/tex]

⇒ c = 2

[tex]a=\frac{3+(-1)}{2}[/tex]

⇒ [tex]a=\frac{2}{2}[/tex]

⇒ a = 1

Then, e = [tex]\frac{2}{1}[/tex]

⇒ e = 2

Now, the polar equation of an ellipse becomes as,

⇒ [tex]r=\frac{2p}{1+2cos\theta}[/tex] ------- (1)

Now plug in a vertex point such as (-1,0) and solve for p,

⇒ [tex]-1=\frac{2p}{1+2cos0}[/tex]

⇒ [tex]-1=\frac{2p}{1+2(1)}[/tex]               [∵ cos 0 = 1]

⇒ [tex]-1=\frac{2p}{3}[/tex]

⇒ [tex]-3=2p[/tex]

⇒ [tex]p=-\frac{3}{2}[/tex]

Thus the polar equation of an ellipse (1) becomes as,

⇒ [tex]r=\frac{2(-\frac{3}{2} )}{1+2cos\theta}[/tex]

⇒ [tex]r=-\frac{3}{1+2cos\theta}[/tex]

Hence we can conclude that the polar equation of an ellipse is [tex]r=-\frac{3}{1+2cos\theta}[/tex].

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The gallons needed to paint the silo is 10.

A cylinder is a three-dimensional object. It is a prism with a circular base. The total surface area of cylinder can be determined by adding the area of all its faces.

Total surface area of the cylinder excluding its base = 2πrh +πr²

Where:

TSA = (2 x 3.14 x 10 x 30) + (3.14 x 10²)

314 + 1884 = 2198 ft²

Number of gallons needed = 2198 / 224 = 9.81 = 10 gallons

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the vertex of the function g(x) = f(x 2) .

If a quadratic equation is expressed as the following

                          [tex]y=a(x-h)^{2}+k[/tex]

It is then said to be in vertex form. Because the vertex point (peak point) occurs on the graph of this equation, it is so named (h,k)

The parabola that the quadratic equation depicts has this point (h,k) as its vertex.

We first remove the x squared coefficient, and then inside the bracket, we strive to create a condition that resembles a perfect square.

So, this is what we have:

                         [tex]$f(x)=x^{2}+6 x+3$\\$g(x)=f(x-2)$[/tex]

Thus, we obtain:

                        [tex]\begin{aligned}&g(x)=f(x-2) \\&g(x)=(x-2)^{2}+6(x-2)+3 \\&g(x)=x^{2}-4 x+4+6 x-12+3 \\&g(x)=x^{2}+2 x-5\end{aligned}[/tex]

Vertex form transformation of g(x):

                             [tex]\begin{aligned}&g(x)=x^{2}+2 x-5 \\&g(x)=x^{2}+2 x+1-1-5 \\&g(x)=(x+1)^{2}-9 \\&g(x)=(x-(-1))^{2}-6 \\&g(x)=(x-(-1))^{2}+(-6)\end{aligned}[/tex]

By comparing this[tex]a(x-h)^{2}+k[/tex] to, we obtain the coordinates of the vertex of the graph of g(x) as (h,k) = (-1,-6), as shown below.

As a result, the vertex of the function g(x) = f(x 2) .

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The total volume of silo is  = 116.5[tex]{~m}^{3}[/tex]

The correct option is C

Any arrangement of points, lines, or planes constitutes a geometric figure. Depending on their dimensions, geometric figures can be categorized as either a space figure, a plane figure, a line, a line segment, a ray, or a point.

Any object's surface area is the space that the object's surface takes up on a specific area or region. Volume, however, refers to how much room a thing has.

Given data:

Radius =4.4/2

                   =2.2

height of cylinder = 6.2

to find :

total volume of silo =  volume of cylinder + volume of hemisphere

                                  [tex]\begin{aligned}&=\pi r^{2} h+\frac{2}{3} \pi r^{3} \\&=\pi r^{2}\left(h+\frac{2}{3} r\right) \\&=\frac{22}{7} \times(2.2)^{2}\left[6.2+\frac{2 \times 2.2}{3}\right]\end{aligned}[/tex]

                                   = 116.5[tex]m^2[/tex]

The total volume of silo is = 116.5[tex]m^2[/tex]

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I understand that the question you are looking for is:

A grain silo is composed of a cylinder and a What is the approximate total volume of the silo? Use hemisphere. The diameter is 4.4 meters. The height of  3.41 for [tex]\pi[/tex] and round the answer to the nearest tenth of its cylindrical portion is  6.2 meters. a cubic meter.

a. 37.1[tex]m^2[/tex]

b. 71.9 [tex]m^2[/tex]

c.116.5 [tex]m^2[/tex]

d. 130.8[tex]m^2[/tex]

For the given functions, the domains are:

1) All real numbers.

2) D: x≥ -3

3) D: set of all real numbers such that x ≠ 0

4) D: 7 ≥ x ≥-7

5)  All real numbers.

For any function, we assume that the domain is the set of all real numbers, and then we remove all the values of x that generate problems (like a denominator equal to zero or something like that).

1) f(x) = x^2 - 4

This is just a quadratic equation, the domain is the set of all real numbers.

2) f(x) = √(x + 3)

Remember that the argument of a square root must be equal to or larger than zero, so here the domain is defined by:

x + 3 ≥ 0

x≥ -3

The domain is:

D: x ≥ -3

3) f(x) = 1/x

We can assume that the domain is the set of all real numbers, but, we can see that when x = 0 the denominator becomes zero, then we need to remove that value from the domain.

Thus, we conclude that the domain is:

D: set of all real numbers such that x ≠ 0

4) f(x) = √(49 - x^2)

Here we must have:

49 - x^2 ≥ 0

49 ≥ x^2

√49  ≥ x ≥-√49

7 ≥ x ≥-7

The domain of this function is:

D:  7 ≥ x ≥-7

5) f(x) = √(x^2 + 1)

Notice that x^2 is always a positive number, then the argument of the above square root is always positive, then the domain of that function is the set of all real numbers.

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Answer:

Define the variables.

Step-by-step explanation:

Define the variables, then set up the equations, and finally solve the system using graphing, substitution, or elimination method.

To set up or model a linear equation to fit a real-world application, First, we have to determine the known amounts or quantities before defining the unknown quantity as a variable.

A linear equation is defined as an equation in which the highest power of the variable is always one.

To set up a model linear equation to fit real-world applications

In the first step determine known amounts or quantities.

Then, assign the unknown amount to a variable.

Now, find a method or approach to express the second unknown in terms of the first if there are many unknown quantities.

Create an equation that translates the words into mathematical functions.

Complete the equation. Make certain that the solution, including the system of measurement, can be expressed in words.

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Answer:

i think 80 copies

Step-by-step explanation:

The expression, written as the sine of an angle is sin (7π/10)

From the question, we are to write the given expression as the sine or cosine of an angle.

The given expression is

sin(π/5)cos(π/2) + sin(π/2)cos(π/5)

Let A = π/5

and

B = π/2

Thus, we get

sinA cosB + sinB cosA

From the given information, we have that

sin(A ± B) = sinA cos B ± cosA sinB

∴ sin(A + B) = sinA cos B + cosA sinB

Now,

sinA cosB + sinB cosA = sinA cosB + cosA sin B

∴ sinA cosB + sinB cosA = sin (A + B)

Put A = π/5

and

B = π/2

sinπ/5 cosπ/2 + sinπ/2 cosπ/5 = sin (π/5 + π/2)

sinπ/5 cosπ/2 + sinπ/2 cosπ/5 = sin (7π/10)

Hence, the expression, written as the sine of an angle is sin (7π/10)

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[tex]\Large\texttt{Answer}[/tex]

[tex]180^\circ=\pi\:radians}[/tex]

[tex]\overline{\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad}[/tex]

[tex]\Large\texttt{Process}[/tex]

⇨ For converting from degrees to radians, use this conversion factor:

[tex]\bf{\cfrac{\pi}{180}}[/tex]

⇨ Convert

[tex]\bf{\cfrac{180}{1}\times\cfrac{\pi}{180}}[/tex]

⇨ The 180s cancel out, and we have:

[tex]\pi[/tex]

Hence

[tex]\bf{180^\circ=\pi\:radians}[/tex]

Hope that helped

[tex]-2(-1+2w)[/tex]

distribute

[tex]2-4w[/tex]

put in standard form

[tex]-4w+2[/tex]

Using it's concept, we have that the probability that both the first digit and the last digit of the three-digit number are even numbers is 2/27.

A probability is given by the number of desired outcomes divided by the number of total outcomes.

Considering that there are six numbers, out of which 4 are odd and 2 are even, we have that:

Hence the desired probability is:

p = 1/3 x 2/3 x 1/3 = 2/27.

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Answer:

9:20

Step-by-step explanation:

1kg is 1000g grams and in order to simify we need the units to be equal . 450:1000 would simplify to

45: 100 by divinding both the number by 10 then divide both number by 5 which would give 9: 20

hopefully this helped . if you need any more explanation pls ask

pls give brainliest if you like my answer :) thanks

Answer:

9: 20

Step-by-step explanation:

      1kg × 1000 = 1000g

     450 :  1000g

     450  :  1000

        9: 20

The x-intercept is when y=0, but since [tex]\log_{3}(x-4) \neq 0 \text{ } \forall x[/tex], there is no x-intercept.

The asymptote is when the argument equals 0, which is at x=4.

[tex](k \circ p)(x)=k(p(x))=k(x-3) \\ \\ =2(x-3)^2-5 \\ \\ =2(x^2 - 6x+9)-5 \\ \\ =\boxed{2x^2 - 12x+13}[/tex]

For instance, f[g (x)] exists the composite function of f(x) and g(x). The composite function f[g (x)] exists read as “f of g of x”.

The composite function exists [tex]$k(p(x))=2 x^{2}-12 x+13$[/tex]

Therefore, the correct answer is option b. [tex]$k(p(x))=2 x^{2}-12 x+13$[/tex].

A composite function exists generally as a function that exists written inside another function. The composition of a function exists done by replacing one function with another function.

Given function exists, [tex]$k(x)=2 x^{2}-5[/tex] and p(x) = (x - 3)

To find composite function k(p(x)).

k(p(x)) = k(x-3)

[tex]$&k(p(x))=2(x-3)^{2}-5 \\[/tex]

simplifying the above equation, we get

[tex]$&k(p(x))=2\left(x^{2}+9-6 x\right)-5 \\[/tex]

[tex]$&k(p(x))=2 x^{2}+18-12 x-5 \\[/tex]

[tex]$&k(p(x))=2 x^{2}-12 x+13[/tex]

The composite function exists [tex]$k(p(x))=2 x^{2}-12 x+13$[/tex]

Therefore, the correct answer is option b. [tex]$k(p(x))=2 x^{2}-12 x+13$[/tex].

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Answer:

-4

Step-by-step explanation:

We are going to substitute 0 in for x and solve for y.  

-2(0)+ 8y = -32  Anything times zero is zero

0 + 8 y = -32  Anything plus zero is itself.

8y = -32 Divide both sides by 8

y = -4

The system of linear equations represents the situation is;

x + y = 125

x + y = 1255x + 8y = 775

Simultaneous equation is an equation in two unknown values are being solved for at the same time.

let

x + y = 125

5x + 8y = 775

From equation (1)

x = 125 - y

5x + 8y = 775

5(125 - y) + 8y = 775

625 - 5y + 8y = 775

- 5y + 8y = 775 - 625

3y = 150

y = 150/3

y = 50

x + y = 125

x + 50 = 125

x = 125 - 50

x = 75

Therefore, the number of quick washes and premium washes Monica’s school band had is 75 and 50 respectively.

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Answer:

A. 5x + 8y = 775 and x + y =125

Step-by-step explanation: