Classify each angle pair, then find the value of X


Please explain your work!!

Answer:

answer is D

Step-by-step explanation:

if you replace X with 4 the equation should give you a 0.

after the long division method, you will obtain a quadratic equation.

to solve the quadratic equation you can use either of the known methods like factorisation or graphical methods or the quadratic formula.

t

The answer using positive exponents only is 16x^(24)y^(16).

To simplify the expression (2x^(6)y^(4))^(4), we need to use the properties of exponents. Specifically, we need to use the property that states (a^(m))^n = a^(m*n). This means that when we raise a power to another power, we multiply the exponents.

Using this property, we can simplify the expression as follows:

(2x^(6)y^(4))^(4) = 2^(4) * x^(6*4) * y^(4*4) = 16 * x^(24) * y^(16)

So, the simplified expression is 16x^(24)y^(16).

Therefore, the answer using positive exponents only is 16x^(24)y^(16).

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There are three possible triangles that can be formed using the given measurements.

Measurement is the process of quantifying or comparing the amount, size, or extent of something. It is an important concept for scientists, engineers, and other professionals in order to compare and understand the world around them. Measurement involves the use of physical tools, such as rulers, scales, and protractors, and mathematical equations, such as formulas and equations.

We can use the Law of Cosines to solve for the missing side:

[tex]b^2 = a^2 + c^2 - 2ac\cos(B)\\$b^2 = 43^2 + 15^2 - 2(43)(15)\cos(123^\circ)$\\$b^2 \approx 799.5$\\$b \approx 28.3$[/tex]

Now we can use the Law of Sines to solve for the remaining angles:

[tex]\frac{\sin(A)}{a} = \frac{\sin(B)}{b}\\$\sin(A) = \frac{a\sin(B)}{b}$\\$\sin(A) \approx 0.977$\\$A \approx 79.4^\circ$\\$B \approx 23.6^\circ$[/tex]

So the triangle is [tex]$\triangle ABC$[/tex] where [tex]$A=79.4^\circ$[/tex], [tex]$B=23.6^\circ$[/tex], [tex]$C=77^\circ$[/tex], [tex]$a=43$[/tex], [tex]$b\approx 28.3$[/tex] , and [tex]$c=15$[/tex].

We can use the Law of Cosines to solve for the missing side:

[tex]b^2 = a^2 + c^2 - 2ac\cos(B)\\$b^2 = 36^2 + 47^2 - 2(36)(47)\cos(47^\circ)$\\$b^2 \approx 1666.5$\\$b \approx 40.8$[/tex]

Now we can use the Law of Sines to solve for the remaining angles:

[tex]\frac{\sin(A)}{a} = \frac{\sin(B)}{b}\\$\sin(A) = \frac{a\sin(B)}{b}$\\$\sin(A) \approx 0.647$\\$A \approx 40.9^\circ$\\$C \approx 92.1^\circ$[/tex]

So the triangle is [tex]$\triangle ABC$[/tex] where [tex]$A=40.9^\circ$[/tex], [tex]$B=47^\circ$[/tex], [tex]C\approx 92.1^\circ, a\ =36$[/tex], [tex]$b\approx 40.8$[/tex],

We can use the Law of Cosines to solve for the missing side:

[tex]h^2 = k^2 + p^2 - 2kp\cos(K)\\$h^2 = 47^2 + 10^2 - 2(47)(10)\cos(139^\circ)$\\$h^2 \approx 2363.7$\\$h \approx 48.6$[/tex]

Now we can use the Law of Sines to solve for the remaining angles:

So the triangle is [tex]$\triangle KHP$[/tex] were [tex]$K=139^\circ$[/tex], [tex]$H\approx 56.5^\circ$[/tex], [tex]$P\approx 124.5^\circ$[/tex], [tex]$k=47$[/tex], [tex]$h\approx 48.6$[/tex], and [tex]$p=10$[/tex].

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The measurements are shown in the solution

Trigonometric Ratios are defined as the values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle.

Given are right triangles, we need to find the value of x in each,

We will use Trigonometric ratios to find the same,

The sine is the ratio between the length of the opposite leg and the length of the hypotenuse.

The cosine is the ratio between the length of the adjacent leg and the length of the hypotenuse.

The tangent is the ratio between the length of the opposite leg divided by the length of the adjacent leg.

1) sin 21° = 11/x

x = 30.7

2) cos 34° = x/28

x = 23.21

3) tan 49° = 33/x

x = 28.68

4) T =  cos⁻¹ (11/23)

=  61.42°

5) T = sin⁻¹(21/44)

= 28.50°

6) T = tan⁻¹(8/12)

= 33.7°

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A large p-value indicates that the data is likely to have come from the theoretical distribution.

A. SIMIO is classified as a discrete event simulation language because it uses events to model the behavior of the system being simulated. The SIMIO software is based on the idea of constructing models of systems to support managerial decision-making processes.B. A static simulation is a simulation where nothing changes over time, whereas a dynamic simulation is a simulation where changes occur over time. The outcome of a static simulation cannot change once it has been run. On the other hand, the outcome of a dynamic simulation can change depending on the inputs and parameters used.C. A deterministic simulation is a simulation where all parameters and inputs are known and fixed, whereas a stochastic simulation is a simulation where one or more parameters or inputs are randomly generated. A deterministic simulation will produce the same output every time it is run with the same inputs and parameters, whereas a stochastic simulation may produce different outputs each time it is run with the same inputs and parameters.D. Discrete event simulation of a continuous system is a process where a model of the system is created, which enables the simulation of the system behavior over time using a set of discrete events.E. A variable is a quantity that can change and is usually represented by a symbol, whereas an attribute is a quality that describes a variable. An example of a variable is the temperature, and an example of an attribute is the color of a car.F. An activity is an event that represents an action or process, whereas a delay is an event that represents a waiting time or a period of inactivity. An example of an activity is a customer purchasing a product, and an example of a delay is a customer waiting in line.G. An observed statistic is a statistic that is measured at a particular time and is specific to that time, whereas a statistic that is time persistent is a statistic that is measured over a period of time and is consistent over that period of time.H. A goodness-of-fit test is a statistical test that compares the distribution of a sample of data to a theoretical distribution.I. To use the Kolmogorov-Smirnoff Test, the data must be continuous, and to use the Chi-Squared Test, the data must be categorical.J. In the context of goodness-of-fit tests, a p-value represents the probability of obtaining a sample of data with the same distribution as the theoretical distribution being tested. A small p-value indicates that the data is unlikely to have come from the theoretical distribution, while a large p-value indicates that the data is likely to have come from the theoretical distribution.

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Answer:

To express the value 0.0000547 in scientific notation, we need to move the decimal point to the right until there is only one non-zero digit to the left of the decimal point.

0.0000547 = 5.47 × 10^(-5)

The exponent -5 indicates that we moved the decimal point 5 places to the right.

The value of x is

x=-5

Generally, An angle is a figure formed by two rays (or line segments) that share a common endpoint. Angles are usually measured in degrees, with a full angle measuring 360 degrees.

Considering that the angle on a point is 630 , we have that the missing angle is

y=360-(148+92)

y=120

Therefore

y=x+125

Hence

x=y-125

x=120-125

x=-5

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4/11

The probability of choosing a green marble followed by a brown marble is 4/11. Simple probability is the likelihood that an event occurs, and in this case the likelihood is 4/11. This is calculated by taking the total number of green marbles (4) divided by the total number of marbles in the jar (11).

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[tex]\textit{volume of a cylinder}\\\\ V=\pi r^2 h~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=3\\ h=4 \end{cases}\implies V=\pi (3)^2(4)\implies \stackrel{ \pi =3.14 }{V=113.04}[/tex]

The evaluated values of the function for the given values of x are:
f(-1) = 5
f(0) = 0
f(1) = -1
f(2) = 2
f(3) = 9

To evaluate the function f(x)=2x^2-3x for the given values of x, we simply plug in the given value of x into the function and solve for f(x).

(a) f(-1) = 2(-1)^2 - 3(-1) = 2(1) + 3 = 5

(b) f(0) = 2(0)^2 - 3(0) = 0 - 0 = 0

(c) f(1) = 2(1)^2 - 3(1) = 2 - 3 = -1

(d) f(2) = 2(2)^2 - 3(2) = 8 - 6 = 2

(e) f(3) = 2(3)^2 - 3(3) = 18 - 9 = 9

Therefore, the evaluated values of the function for the given values of x are:
f(-1) = 5
f(0) = 0
f(1) = -1
f(2) = 2
f(3) = 9

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The total number of entities depicted by the given requirements is the sum of the number of students, teachers, and classrooms, which is 100 + 10 + 5 = 115. Hence, the answer is (C) 115.

What is the algebraic operation?

An algebraic expression in mathematics is an expression that is made up of variables and constants, along with algebraic operations (addition, subtraction, etc.). Expressions are made up of terms.

The question asks us to determine the number of entities depicted by the given requirements, which include School XYZ keeping track of its 100 students, 10 teachers, and 5 classrooms.

An entity can be defined as a distinct object or concept that is represented in a system, such as a database or software application.

In this case, the entities can be identified as follows:

Students: There are 100 students in the school, and each student can be considered as a separate entity.

Teachers: There are 10 teachers in the school, and each teacher can be considered as a separate entity.

Classrooms: There are 5 classrooms in the school, and each classroom can be considered separate.

Therefore, the total number of entities depicted by the given requirements is the sum of the number of students, teachers, and classrooms, which is 100 + 10 + 5 = 115. Hence, the answer is (C) 115.

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The values of m that will result in a repeated solution for 3x^(2)+4mx+m=0  are m = 0 and m = 3/4.

The given quadratic equation is 3x^(2)+4mx+m=0. In order to find the value(s) of m that will result in a repeated solution, we need to use the discriminant of the quadratic formula.

The discriminant of the quadratic formula is given by b^(2)-4ac, where a, b, and c are the coefficients of the quadratic equation.

In the given equation, a = 3, b = 4m, and c = m.

Plugging these values into the discriminant, we get:

(4m)^(2)-4(3)(m) = 16m^(2)-12m = 0

A repeated solution occurs when the discriminant is equal to 0. So, we need to solve the equation 16m^(2)-12m = 0 for m.

Factoring out a common factor of 4m, we get:

4m(4m-3) = 0

This gives us two possible values for m:

4m = 0 or 4m-3 = 0

Solving for m, we get:

m = 0 or m = 3/4

Therefore, the values of m that will result in a repeated solution for the given quadratic equation are m = 0 and m = 3/4.

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Answer:

$4.8

Step-by-step explanation:

5 for $3

So $3 ÷ 5 to get the price of one

Answer is 60c or $0.6

Then you multiply $0.6 with 8 to get the price of 8 oranges

So $0.6 x 8 = $4.8

Answer:

the cost of 8 oranges is 4.8$

step by step explanation

using ratio amd proportion

let x be the unknown amount

[tex]5 = 3 \\ 8 = x \\ cross \: multiply \\ 5x = 24 \\ divide \: \: both \: sides \: by \: 5 \\ \frac{5x}{5} = \frac{24}{5} \\ x = \frac{24}{5} \\ x = 4.8[/tex]

therefore the answer is 4.8 dollars will buy 8 oranges

thank you

The product of 4/6-2a x 3-a/2 is equal to 2a-1. To calculate this, the fractions must first be simplified. 4/6 can be simplified to 2/3, and a/2 can be simplified to a/2. Next, the two terms should be multiplied together, resulting in 2a-1.

The product of 4/6-2a x 3-a/2 can be found by expanding the terms and then solving the equation. First, the fractions must be simplified. 4/6 can be simplified to 2/3, and a/2 can be simplified to a/2. Once the fractions are simplified, the two terms should be multiplied together, resulting in 2a-1. Now that the two terms have been multiplied, the equation can be expanded by using the Distributive Property. The equation should be written as (2/3-2a) x (3-a/2). This can be simplified by distributing the 2/3 and 3 across the parentheses. This results in (2-6a+2a^2) x (3-1/2a). Finally, the equation should be simplified by combining like terms. This results in 2-6a+2a^2+3-1/2a, which simplifies to 2a-1. Therefore, the product of 4/6-2a x 3-a/2 is equal to 2a-1.

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The concession stand made 18 fewer cups of coffee than cups of hot chocolate.

To find out how many fewer cups of coffee they made than cups of hot chocolate, we need to add together the number of cups of hot chocolate with marshmallows and the number of cups without marshmallows:

20 cups + 15 cups = 35 cups of hot chocolate

Now, we can subtract the number of cups of coffee from the number of cups of hot chocolate to find out how many fewer cups of coffee they made:

35 cups - 17 cups = 18 cups

So, the concession stand made 18 fewer cups of coffee than cups of hot chocolate.

In conclusion, the concession stand made 18 fewer cups of coffee than cups of hot chocolate.

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cosx = cos4x = cos5x.

19. Using the identity sin2x + cos2x = 1, we can rewrite the equation as:

sin2x/2 - sin2x/2 = cosx/sinx

Simplifying both sides: cosx/sinx = 0

Therefore, cosx = 0 and sinx = 0.


20. Using the identities secx = 1/cosx, tanx = sinx/cosx, and sec2x = 1 + tan2x, we can rewrite the equation as:

secx(secx tanx) - sec4x(secx tanx) = sec5x tanx

Simplifying: secx - sec4x = sec5x

Therefore, secx = sec4x = sec5x.

Simplifying further: 1/cosx = 1/cos4x = 1/cos5x

Therefore, cosx = cos4x = cos5x.

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The formula for the polynomial P(x) with degree 3, real coefficients, zeros at x=3-3i and x=1, and y-intercept at (0,-36) is P(x) = -4(x-1)(x-(3-3i))(x-(3+3i)).

To find the formula for the polynomial, we first need to find the conjugate of the complex zero, which is 3+3i. This is because a polynomial with real coefficients must have complex zeros in conjugate pairs.

Next, we can use the factored form of a polynomial, P(x) = a(x-r1)(x-r2)(x-r3), where r1, r2, and r3 are the zeros of the polynomial and a is a constant. In this case, r1 = 1, r2 = 3-3i, and r3 = 3+3i.

Finally, we can use the y-intercept to find the value of a. When x = 0, P(x) = -36, so we can plug in the values and solve for a:
-36 = a(0-1)(0-(3-3i))(0-(3+3i))
-36 = a(-1)(-3+3i)(-3-3i)
-36 = a(9+9i-9i-9)
-36 = a(-36)
a = 4

So the formula for the polynomial is P(x) = 4(x-1)(x-(3-3i))(x-(3+3i)). However, since we want the y-intercept to be negative, we can multiply the entire polynomial by -1 to get P(x) = -4(x-1)(x-(3-3i))(x-(3+3i)).

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False, for both statements.

For the first statement, let A be an n x n matrix. If for two vectors y and z of Rⁿ we have Ay = Az, it does not necessarily mean that y=z. It is possible that A is a singular matrix, meaning that it does not have an inverse. In this case, there could be multiple vectors that would give the same result when multiplied by A. Therefore, it is not always true that y=z.

For the second statement, if A is a matrix of size n x n such that A³ = Iⁿ (where Iⁿ is the identity matrix of size n), it does not necessarily mean that A is invertible. It is possible for a matrix to have a power that equals the identity matrix, but not have an inverse. For example, consider the matrix A = [[0,1],[0,0]]. A² = [[0,0],[0,0]], and A³ = [[0,0],[0,0]], which is equal to I². However, A does not have an inverse, as its determinant is 0. Therefore, it is not always true that A is invertible if A³ = Iⁿ.

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B

-6

...................

Answer:

Step-by-step explanation:

OK so im not that smart im only in 8th grade but i think the answers either A or B. hope i kind of helped you and good luck and have a nice day.

The functions that are odd or even can be determined by replacing x with -x and seeing if the function remains the same or changes sign.

(a) f(x) = -tan(x) is an odd function because f(-x) = -tan(-x) = tan(x) = -f(x)

(b) f(x) = tan(x+T/2) is an odd function because f(-x) = tan(-x+T/2) = -tan(x+T/2) = -f(x)

(c) f(x) = tan(x)+cot(x) is neither an odd nor an even function because f(-x) = tan(-x)+cot(-x) = -tan(x)-cot(x) ≠ f(x) or -f(x)

(d) f(x) = 5cot(x) is an even function because f(-x) = 5cot(-x) = 5cot(x) = f(x)

(e) f(x) = (tan(x))2 is an even function because f(-x) = (tan(-x))2 = (tan(x))2 = f(x)

(f) f(x) = tan(4x) is an odd function because f(-x) = tan(4(-x)) = -tan(4x) = -f(x)

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Answer:

Step-by-step explanation:

where is the image don't see

What is Trapezium ?

A trapezium is a convex quadrilateral with exactly one pair of opposite sides parallel to each other. The trapezium is a two-dimensional shape that appears as a table when drawn on a sheet of paper. In Euclidean Geometry, a quadrilateral is defined as a polygon with four sides and four vertices. Hence, a trapezium also has four sides, four angles and four vertices.

ABCD is a trapezium, AB || DC

The area of ABCD = 180 cm²

AB = 17 cm

CD = 13 cm

Formula Used:

Area of trapezium = 1/2 x height x (Sum of parallel sides)

Calculation:

Area of trapezium = 1/2 x height x (Sum of parallel sides)

⇒ 180 = 1/2 x height x (AB + CD)

⇒ 180 x 2 = Height x (17 +13)

Height=360/30

Height = 12

.:. The height of the trapezium is 12 cm.

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The simplified expression is x^(454)y^(584) * 2^(109).

To simplify the given expression, we need to use the laws of exponents. The laws of exponents are:

- (a^m)^n = a^(mn)
- a^m * a^n = a^(m+n)
- a^m / a^n = a^(m-n)

Using these laws, we can simplify the given expression as follows:

(x^3y^3)^31 * (32x^13y^18)^31 / (2xy^3)^2 * (2xy^3)^2 * (2x)^2 * (2x^3y^5)^3 * (4xy)^5 * (2x^3y^5)^3 * (4x)^5

= x^(3*31)y^(3*31) * 32^31x^(13*31)y^(18*31) / 2^2x^2y^(3*2) * 2^2x^2y^(3*2) * 2^2x^2 * 2^(3*2)x^(3*3)y^(5*3) * 4^5x^5y^(5*5) * 2^(3*2)x^(3*3)y^(5*3) * 4^5x^5

= x^(93)y^(93) * 32^31x^(403)y^(558) / 2^6x^6y^6 * 2^6x^6y^6 * 2^2x^2 * 2^6x^9y^15 * 4^5x^5y^25 * 2^6x^9y^15 * 4^5x^5

= x^(93+403)y^(93+558) * 32^31 / 2^6 * 2^6 * 2^2 * 2^6 * 4^5 * 2^6 * 4^5 * x^(6+6+2+9+5+9+5) * y^(6+6+15+25+15)

= x^(496)y^(651) * 32^31 / 2^(6+6+2+6+6) * 4^(5+5) * x^42 * y^67

= x^(496-42)y^(651-67) * 32^31 / 2^26 * 4^10

= x^(454)y^(584) * 32^31 / 2^26 * 4^10

= x^(454)y^(584) * 2^(5*31) / 2^26 * 2^(2*10)

= x^(454)y^(584) * 2^(155) / 2^(26+20)

= x^(454)y^(584) * 2^(155-46)

= x^(454)y^(584) * 2^(109)

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The equation that shows the relationship between the age of Danny and Terry is D = T - 6.

Let's represent Danny's age with the variable D and Terry's age with the variable T. We know that Danny is 22 years old, so we can write the equation D = 22.

We also know that Danny is 6 years younger than Terry, so we can write the equation D = T - 6. Now we can substitute the value of D from the first equation into the second equation to find the value of T.

D = T - 6

22 = T - 6

Add 6 to both sides of the equation:

22 + 6 = T

28 = T

So Terry is 28 years old.

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Answer:

2 and -2

Step-by-step explanation:

For the expression to be equal to 0, it means it has to be undefined, so all we need do, is equate the denominator to 0, since any number divided by 0 = 0

Therefore,

5x² - 20 = 0

5x² = 0 + 20

5x² = 20

Divide both sides by 5,

x² = 20/5

x² = 4

Square root both sides,

x² = √4

x = ±2

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The image of the point (-1, -2, 0) under a dilation with center (0, 0, 0) and scale factor 3 is (-3, -6, 0).

From the question, we have the following parameters that can be used in our computation:

Center = (0, 0, 0).

Point = (-1, -2, 0)

Scale factor = 3

A dilation with center (0, 0, 0) and scale factor k multiplies the coordinates of a point by k.

So, to find the image of the point (-1, -2, 0) under a dilation with scale factor 3, we multiply each coordinate by 3:

(-1, -2, 0) --> (3(-1), 3(-2), 3(0))

Image = (-3, -6, 0)

Hence, the image of the point (-1, -2, 0)is (-3, -6, 0).

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The repeating decimal 0.xxxx is equal to 0.2222, and x is equal to 2.

The product of the repeating decimals 0.3333 and 0.6666 is the repeating decimal 0.xxxx. To find x, we can multiply the two decimals together.

First, let's convert the repeating decimals to fractions:

0.3333 = 1/3

0.6666 = 2/3

Now, we can multiply the two fractions together:

(1/3) * (2/3) = 2/9

To convert the fraction back to a decimal, we can divide 2 by 9:

2/9 = 0.2222

So, the repeating decimal 0.xxxx is equal to 0.2222, and x is equal to 2.

Therefore, the product of the repeating decimals 0.3333 and 0.6666 is the repeating decimal 0.2222.

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Answer:

Sin A = [tex]\frac{12}{13}[/tex] ; Cos A = [tex]\frac{5}{13}[/tex]

Step-by-step explanation:

The sine of a given angle is  [tex]\frac{opposite}{hypotenuse}[/tex], using the lengths corresponding to them. In this case, the side length opposite to angle A is 24, and the hypotenuse is 26. This gives  [tex]\frac{24}{26} = 12/13[/tex].

The cosine of a given angle is   [tex]\frac{adjacent}{hypotenuse}[/tex], using the lengths corresponding to them. In this case, the side length adjacent to angle A is 10, and the hypotenuse is 26. This gives  [tex]\frac{10}{26} = 5/13[/tex].

Answer:

8cfct on cypur574 6th 9

Step-by-step explanation:

f5g uh yo h tu g fn l dl uge ser k