CO2 + 6H20 + Light C6H1206+ O2 is an example of a chemical reaction. Shells of atoms divide in order to transport protons to other atoms occurring during this time.
The commonly used notation for photosynthesis is 6CO2 + 6H2O C6H12O6 + 6O2. This indicates that the photosynthesis reactants, six carbon dioxide molecules, and six water molecules, are transformed into a sugar molecule and six oxygen molecules, the products, by light energy being absorbed by chlorophyll (implied by the arrow).
Because components, or reactants, mix chemically at the molecular level to create new substances, photosynthesis is seen as a chemical reaction. This is how a chemical reaction is defined.
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The scene of Wiesel and his father approaching the inferno is particularly vivid. How is such artistry achieved? Wiesel varies the pacing throughout the book in order to emphasize certain points. Here, the pacing is quickened by use of short sentence fragments, "Ten steps still.
The artistry in the scene of Wiesel and his father approaching the inferno is achieved by the use of literary techniques such as pacing and sentence structure.
The pace of the scene is quickened by the use of short sentence fragments, which creates a sense of urgency and intensity. This helps to convey the chaos and confusion of the situation, and the reader is drawn into the scene, feeling as though they are there with Wiesel and his father.
The use of sentence fragments also contributes to the overall sense of disorientation and discomfort, as it breaks away from traditional sentence structure and grammar. This contributes to the vividness of the scene and makes it more memorable for the reader.
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Write the formula of the substance that corresponds to A-H.
(A) CH2 = CH2 + H2 ------------> CH3---CH3
(B) CH2 = CH2 polymerization 2CH2 = CH2
(D) CH2 = CH2 + H2O -----> CH3CH2OH
(E) CH2 = CH2 + 6O ------> 2CO2 + 2H2O
(F) CH2 = CH2 + H2 ------------> CH3---CH3
(G) CH2 = CH2 + Cl2 --------> C2H4Cl2
(H) CH2 = CH2 + HCl -----> CH3CH2Cl
What is polymerization reaction ?When a monomer or a monomer's molecules react, polymer chains are created. Different approaches exist to categorise the numerous types of polymerization processes.
The two main categories of polymerization reactions are condensation polymerization and addition polymerization. Along with polymerization, the monomers add to one another in a way that results in a polymer that has every atom from the beginning monomers. The molecules of ethylene are linked together in lengthy chains.
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Which of the following processes takes place upon absorption of infrared radiation? Select one: a. nuclear spin flip b. bond vibration c. electron excitation d. electron spin flip
The process that takes place upon absorption of infrared radiation is bond vibration. So the correct option is "b".
Infrared radiation has a longer wavelength than visible light and does not have enough energy to cause an electron excitation or an electron spin flip. However, it does have enough energy to cause bond vibrations, which is why it is used in spectroscopy to measure the vibrational frequencies of chemical bonds.
Bond vibration occurs when infrared radiation interacts with molecules. The radiation has enough energy to cause the vibrational frequency of the chemical bonds to increase, which can be detected in spectroscopy. This increase in vibration is caused by the conversion of the radiation energy to vibrational energy of the molecule. The vibrational energy can then cause changes in the shape of the molecule, resulting in the stretching and bending of the bonds.
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Selecting reource with reliable credential and expertie i?
A. Not important, everyone’ idea are equally valid
B. Only important when you are looking for medical advice
C. Important for cientific reearch only
D. Important for any information you look up,, on any topic
Selecting resources with reliable credentials and expertise is important for any information we look up, on any topic.
The resources can be studied as reliable and credentials if they include the information that arises from an authentic source. And also, the resource that has been verified by many reviewers that exhibit special knowledge and expertise in the linked field of the topic can be contemplated as reliable and credential. That kind of resource can be looked upon for retrieving needed information on any topic.
It is important to evaluate our sources. When we do research, surely, we want to find the best information to support our ideas. This needs careful evaluation of the information we collect.
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Why is boiling-point elevation a colligative property?
A. It does not depend on a molal boiling-point constant for each solvent.
B. It is independent of changes in vapor pressure.
C.It is directly proportional to the molal concentration of a solution.
D.it is inversely proportional to the molal concentration of a solution.
Answer:
the answer is option C
Explanation:
Boiling point elevation is a colligative property of matter, i.e. it is dependent on the solute-to-solvent ratio but not on the solute's identity. This implies that the elevation in the boiling point of a solution depends on the amount of solute added to it
Problem 2: Derivation of Transport Equation for a Sedimenting Suspension. There are many parallels among momentum, mass, and energy transport because all three are derived from similar conservation laws. In this problem we derive a microscopic balance describing the concentration distri- bution o(x, t) of a very dilute suspension of small particles suspended in an incompressible fluid undergoing unsteady flow. (Note: $(x, t) is the local vol- ume frction of particles in the fluid (ie, volume of particles/volume of Auid) and hence is dimensionless.] (a) The flux of particles is the sum of that due to convection, that due to settling q: (a vector), and that due to diffusion qp (also a vector). These fluxes have units of volume per area per time (eg, velocity). With this in mind, write an integral balance from the conservation of particles for an arbitrary control volume D. Using the divergence theorem, convert all surface integrals to volume integrals, and so obtain a microscopic equation valid at any point in the flow field. (b) For small particles of radius a, the flux that is due to settling is given by: as 2 ga? Ap oź 9 (3) and the diffusive flux by KT D VO (4) 6πμα where g is the graviational acceleration, Ap is the difference in density be- tween the particles and fluid, p is the viscosity of the fluid, and KT is the thermal energy of the fluid (k is the Boltzmann constant, T is temperature). Using these results, obtain an equation in terms of derivatives of the concentration.
The divergence theorem in vector calculus, commonly referred to as Gauss' theorem or Ostrogradsky's theorem, establishes a relationship between a vector field's flow through a closed surface and its divergence in the volume it is contained in.
The divergence theorem explains that the flux through the surface, which is the surface integral of a vector field over a closed surface, is equal to the volume integral of the divergence over the area inside the surface. It implies that the net flux out of a region is equal to the total of all the field sources in the region, with sinks being considered negative sources.
In specifically in electrostatics and fluid dynamics, the divergence theorem is a significant finding in the mathematics of physics and engineering. Typically, it is utilized in three dimensions in various fields. It can, however, apply to any number of dimensions. It is analogous to integration by parts in a single dimension. It is analogous to Green's theorem in two dimensions.
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high-resolution mass spectrometry is advantageous in determining what key feature of an unknown molecule?
Option C is correct. High-resolution mass spectrometry is advantageous in determining the key feature of an unknown molecule will be molecular formula.
High-resolution mass spectrometry (HRMS) is an analytical technique which is used to determine the atomic masses of an organic and inorganic molecules or monatomic ions which is present in different kinds of samples. High resolutions can be achieved through a variety of different mass spectrometers, yet the fundamental workings will be similar.
HRMS analysis begins by passing a sample into the spectrometer, where it will be ionized. The formed ions will travel along with the spectrometer's length, and it is separated by their relative charges and masses. Once the ions reach the end of the spectrometer, they are picked up by a detector, and the information will be logged on a computer.
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--The given question s incomplete, the complete question is
"High-resolution mass spectrometry is advantageous in determining what key feature of an unknown molecule? A) functional group B) atomic structure C) molecular formula D) carbon hydrogen structure"--
suppose you found out that i = 3.11 for some unknown acid. what could you conclude about the dissociation of the acid? how many hydrogen atoms can dissociate from the acid?
The number of hydrogen ions that have dissociated is 0.0498 moles
The ionization constant (pKa) is a measure of the strength of an acid in solution. The lower the value of pKa, the stronger the acid is, meaning it dissociates more readily and produces more hydrogen ions (H+) in solution. On the other hand, a higher value of pKa means the acid is weaker and less likely to dissociate.
In the case of the unknown acid with pKa = 3.11, this value indicates that the acid is partially dissociated in solution, meaning that a fraction of the hydrogen atoms have dissociated from the molecule to form hydrogen ions (H+) and the corresponding anion.
The dissociation reaction of an acid can be represented as follows:
HA (acid) + H2O (water) -> H3O+ (hydronium ion) + A- (anion)
Where HA represents the acid molecule and A- represents the anion. The concentration of the hydrogen ions (H+) in solution can be calculated from the ionization constant (pKa) using the equation:
[H+] = 10^-pKa
So, for the unknown acid with pKa = 3.11, the concentration of hydrogen ions in solution can be calculated as [H+] = 10^-3.11 = 0.0498 M.
This information can be used to further analyze the behavior of the unknown acid in solution, such as its behavior in different types of reactions or its effect on the pH of the solution.
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the mole is a counting unit defined as 1 mole = 6.022 × 10^23 objects. if you have a sample with 2.02 × 10^22 h2o molecules, how many moles of water would the sample contain?Enter the value using exponential notation, e.g. 1.23 × 10^4 would be entered as 1.23E4.(value ± 2%)
If you have the sample with 2.02 × 10²² H₂O molecules. The number of moles of water in the sample is 3.3 E⁻².
The one moles of the substance = 6.022 × 10²³ molecules
The number of molecules of water = 2.02 × 10²² molecules
The number of the moles of water is as follows :
The number of the moles of water = 2.02 × 10²² / 6.022 × 10²³ moles
The number of the moles of water = 3.3 × 10⁻² moles
Thus, number of moles of water is 3.3 × 10⁻² moles in 2.02 × 10²² molecules .
In the exponential notation is 3.3 E⁻² .
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the laboratory procedure calls for 50.00 ml of cuso4 solution with a concentration of 0.300 m. what mass of cuso4∙5h2o is required to prepare this solution?
The laboratory procedure is for the 50.00 ml of the CuSO₄ solution with the concentration of 0.300 M. The mass of CuSO₄.5H₂O is required to prepare this solution is 2.5 g CuSO₄.5H₂O .
The concentration of the CuSO₄ = 0.300 M
The volume = 50 mL
The moles of CuSO₄ = 0.300 × 0.050
= 0.015 mol
Mass of CuSO₄ = moles × molar mass
= 0.015 × 159.6
= 2.39 g
There are 5 moles of H₂O :
= 159.6 / ( 159.6 + 5 × 18 ) × 100 %
= 63.9 % of CuSO₄
The mass of the CuSO₄.5H₂O = 2.39 ( 100 × 5H₂O / 63.6 )
= 2.5 g CuSO₄.5H₂O
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calculate the energy of a photon and the energy per mole of photons for radiation of wavelength (i) 600 nm (red), (ii) 550 nm (yellow), (iii) 400 nm (blue).
The energy of a photon and the energy per mole of photons for radiation of wavelength 600 will be 199 kJmol-1, 550 will be 217.5 kJmol-1 and 400 will be 299 kJmol-1.
⇒E (per photon): E = hc / λ
E = (6.626 X 10-34Js) (3.0 X 108ms-1) / (600 x 10-9m)
E = 3.31 x 10-19 J
E (per mole of photon):
E (per mole) = 3.61 x 10-19 J x 6.02 x 1023 photons / 1mol photon
E = 199KJmol-1
⇒E (per photon): E = hc / λ
E = (6.626 × 10⁻³⁴Js) (3.0 × 10⁸ms⁻¹) / (550 × 10⁻⁹m)
E = 3.61 x 10⁻¹⁹ J
E (per mole of photon):
E (per mole) = 3.61 × 10⁻¹⁹ J × 6.02 × 10²³ photons / 1mol photon
E = 217.5KJmol⁻¹
⇒E (per photon): E = hc / λ
E = (6.626 × 10⁻³⁴Js) (3.0 × 10⁸ms⁻¹) / (400 × 10⁻⁹m)
E = 4.969 × 10¹⁹ J
E (per mole of photon):
E (per mole) = 4.969 × 10⁻¹⁹ J × 6.02 × 10²³ photons / 1mol photon
E = 299KJmol⁻¹
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what is the equation for the rate of formation of 1-iodobutane from the reaction of 1chlorobutane (bucl) with nai by an sn2 mechanism? a. b. c. d. rate
Option (b) is correct. The equation for the rate of formation of 1-iodobutane from the reaction of 1-chlorobutane with NaI by SN2 mechanism is K [BuCl] [NaI].
SN2 mechanism is also called bimolecular nucleophilic substitution reactions. In this reaction the nucleophile attacks and the leaving group leaves is simultaneous. so the bond making between the nucleophile and the electrophilic carbon occurs at the same time as the bond breaking between the electrophilic carbon and the halogen. It is a type of nucleophilic substitution where a lone pair of electrons on a nucleophile attacks an electron deficient electrophilic center and bonds to it resulting in the expulsion of a leaving group. This reaction is stereospecific. The rate determining step of SN2 mechanism include both the alkyl halide as well as nucleophile as both will be present in the transition step and a 5 membered unstable intermediate will be involved.
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The complete question is,
What is the equation for the rate of formation of 1-iodobutane from the reaction of 1chlorobutane with NaI by an sn2 mechanism?
a. Rate = k[BuCl]
b. Rate= k [BuCl] [NaI]
c. Rate = k[NaI]
d. Rate = K [ Bucl]2
palladium metal has a density of 12.0 . assuming the palladium atomic radius is 137 pm, is the unit cell of the element primitive cubic, body-centered cubic, or face-centered cubic?
A quantity of 6.023 x [tex]10^{23}[/tex] atoms of an element equals one gram of that element.
The mass of the element is defined as 1 g.atom of the element when its relative atomic mass is represented in grams.
Density = mass / volume.
There are 4 atoms to the unit cell in a fcc.
(4×atomic mass /6.02 x 10^23) = mass of unit cell
(4×106.42 g/mol) / (6.02 x 10^23) = 7.07 x 10^-22 g
Density = mass/volume
? V = mass / density
V = 7.07 x 10^-22 g / 12.0 g/cm³
V = 5.89 x 10^-23 cm³
For the FCC configuration, 4r = a×v2
a = 4r /v2, also V (cell) = a³
a³ = 5.89 x 10^-23 cm³
a = 3.89 x 10^-8 cm
a = 4r /v2 , where r = atomic radius
3.89 x 10^-8 cm = 4r / v2
r = 1.38 x 10-8 cm
1 cm = 1 x 10^10 pm
1.38 x 10^-8 cm × (1 x 10^10 pm / 1 cm) = 138 pm
r = 138 pm.
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A gas sample with a volume of 4.06 L at a temperature of 34.4 C is heated until it's new volume is 8.29 L. What is the new temperature of the gas?
According to Charle's law, the new temperature of the gas at constant pressure is 70.25°C.
What is Charle's law?Charles law is an experimental gas law which provides description about the behavior of gases which tend to expand on heating.It states that, at constant pressure, the temperature is in direct proportion with the volume that is,V∝T or V₁/T₁=V₂/T₂.The relation between volume and temperature is linear as the temperature increases volume also increases.
The graph of volume versus temperature is a straight line passing through the origin.On substitution, T₂=8.29×34.4/4.06=70.25°C.
Thus, the new temperature of the gas at constant pressure is 70.25°C.
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What was Rosalind Franklin, James Watson and Francis Crick's discovery, and what did it lead to? In three to five sentences, explain your answer.
Rosalind Franklin, James Watson and Francis Crick's discovery of the double-helix structure of DNA lead to the understanding of how genetic information is passed from parent to offspring, and the development of modern biotechnology.
What was Rosalind, Watson and Crick's discovery?Rosalind Franklin, James Watson, and Francis Crick's discovery was the structure of the DNA molecule. Their work led to a better understanding of the genetic code and how genes are passed on from generation to generation.
It also opened the door to further research on how genes could be manipulated to change the characteristics of living organisms. This research has led to a better understanding of how certain diseases are caused and has also allowed us to develop treatments and cures for diseases by altering the structure of DNA.
The discovery of the structure of DNA has also allowed us to better understand the evolution of life on Earth.
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20 points!!! can someone help me with this? I got all the data I am just confused on what 'state of matter' means. They give you the data, its in the pdf my assignment is the document, but I need the answers to state of matter. I will mark you brainliest if its correct!
how many faradays are needed to deposit 10.5 g of copper onto the surface of an electrode from a solution of cu2 ? (molar mass of copper = 63.55 g/mol) (3 points)
To determine how many Faradays are needed to deposit 10.5 g of copper onto the surface of an electrode from a solution of Cu2+, we can use the relationship between the amount of electric charge (Q) required for a redox reaction and the number of moles of a substance involved in the reaction (n).
One Faraday (F) of electric charge is defined as the amount of charge required to react with one mole of electrons. In this case, the reaction involves the reduction of Cu2+ ions to Cu atoms at the electrode surface, so we need to determine the number of moles of Cu2+ ions that are required to produce 10.5 g of copper.The molar mass of copper is 63.55 g/mol, so 10.5 g of copper corresponds to 10.5 g / 63.55 g/mol = 0.165 moles of copper. Since the reaction involves a 1:1 stoichiometry between Cu2+ ions and Cu atoms, we also have 0.165 moles of Cu2+ ions.
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the mass of water in a 250 ml beaker is 248.78 g. if the temperature in the lab is 18°c, what is the volume of water in the beaker? the density of water at 18°c is 0.9986g/ml.
The mass of the water is 248.78 g and the density of the water is 0.0086 g/mL , the volume of water in the beaker is 249.12 mL.
The mass of the water in the beaker = 248.78 g
The density of the water in the beaker = 0.9986 g/mL
The temperature provide = 18 °C
The density expression is given as :
Density = mass / volume
The volume = mass / density
where,
The mass = 248.78 g
The density = 0.9986 g/mL
The volume = 248.78 / 0.9986
The volume = 249.12 mL
The volume of the water in the beaker is 249.12 mL.
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biochemists often study reactions in solutions containing phosphate ion, which is commonly found in cells. how many grams of solute are in 3.06 l of 0.377 m sodium hydrogen phosphate? enter to 1 decimal place.
In 3.06 liters of 0.377 molar sodium hydrogen phosphate, there are 11.81 grams of solute. This can be calculated using the formula:
molarity x volume (in liters) x molar mass of solute = mass of solute.
In this case, 0.377 M x 3.06L x 119.98 g/mol = 11.81 g.
Sodium hydrogen phosphate is a salt composed of the ions sodium (Na+) and hydrogen phosphate (HPO4-). The molecule consists of one sodium atom covalently bonded to one hydrogen atom and four oxygen atoms, forming a tetrahedral shape. When dissolved in water, the sodium ion separates from the hydrogen phosphate ion, and the solution becomes positively charged due to the presence of the sodium cation.
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Suppose you have a neuron with the following starting concentration of K+ at 37 degrees C...
[K+]outside = 5 mM [K+]inside = 140 mM
What would happen to the membrane potential of this neuron if it were only permeable to potassium and you reduced the [K+]outside.
The membrane potential of this neuron if it were only permeable to potassium and you reduced the [K+]outside is -89 mV.
The difference in electric potential between the interior and exterior of a biological cell is known as membrane potential (also transmembrane potential or membrane voltage). That is, there is a difference in the energy necessary for electric charges to flow from the internal to the external cellular surroundings and vice versa, as long as no kinetic energy is acquired or radiation is produced.
This energy need is determined directly by the charge concentration gradients. Typical membrane potential values for the cell's exterior, generally reported in millivolts and indicated as mV, vary from -80 mV to -40 mV. A membrane made of a lipid bilayer with proteins incorporated in it surrounds all animal cells.
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25.00 ml of 0.085 mol/l aqueous sodium sulfide is added to 56.5 ml of 0.10 mol/l mercury (ii) nitrate. what mass of mercury (ii) sulfide, hgs(s), precipitates?
The approximate mass of mercury(II) sulfide which precipitates is 0.52g.
We can first calculate the number of moles of sodium sulfide and mercury(II) nitrate present in the solution:
For sodium sulfide:
n = C x V
n = 0.085 mol/L x 0.025 L = 0.002125 mol
For mercury(II) nitrate:
n = C x V
n = 0.10 mol/L x 0.0565 L = 0.00583 mol
Next, we can use the stoichiometry of the reaction between sodium sulfide and mercury(II) nitrate to determine the amount of mercury(II) sulfide precipitated:
Na2S + Hg2(NO3)2 -> HgS + 2NaNO3
1 mole of Na2S reacts with 1 mole of Hg2(NO3)2 to produce 1 mole of HgS and 2 moles of NaNO3.
Since we have 0.002125 mol of sodium sulfide, the amount of mercury(II) sulfide produced is also 0.002125 mol.
Finally, we can use the molar mass of mercury(II) sulfide to calculate its mass:
HgS has a molar mass of 247 g/mol
0.002125 mol of HgS has a mass of:
m = n x M
m = 0.002125 mol x 247 g/mol
m = 0.52 g
So, approximately 0.52 g of mercury(II) sulfide precipitates
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which product is the major product of the reaction? what would you expect the proton nmr spectre of a and b to look like?
The primary product of a reaction is determined by several parameters, including reaction circumstances, reactants, and reaction type. The proton NMR spectra of compounds “a” and “b” would be affected by the compounds' molecular structure and the surrounding environment.
It is impossible to forecast the primary product or the proton NMR spectra without particular information on the reaction and chemicals. The interpretation of Nuclear Magnetic Resonance (NMR) data is critical in molecular identification. When analysing NMR spectra, numerous criteria such as chemical shift, spin multiplicity, coupling constants, and integration can be used to assign the structure of an unknown substance as well as recognized structures. Each unique proton in the molecule will give rise to a distinct peak in the NMR spectrum with different chemical shifts, based on the magnetic environment of that proton.
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why does the liquid rise in the capillary tube when the boiling substance cools below the boiling point?
The liquid rise in the capillary tube when the boiling substance cools below the boiling point due to decrease in vapor pressure.
As the liquid cools down, its vapor pressure will decrease and when the vapor pressure drops just below atmospheric pressure, the liquid will be automatically drawn into the capillary tube (forced there by the higher atmospheric pressure).
The energy that is required for the liquid molecules to expand to the gas phase increases as the pressure applied to the liquid surface increases, requiring a greater temperature to transform the liquid to gas phase. As a result of this when pressure rises, the boiling point of a liquid rises.
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how to interpret gel electrophoresis data
Interpreting gel electrophoresis data involves analyzing the separated patterns of macromolecules in the gel.
Gel electrophoresis is a laboratory technique used to separate and analyze macromolecules, such as DNA, RNA, and proteins. To interpret gel electrophoresis data, one needs to examine the patterns of separated macromolecules in the gel.
Gel electrophoresis works by applying an electrical field to a gel matrix containing the sample of macromolecules. The macromolecules move through the gel matrix in response to the electric field, and are separated based on their size and charge. The separated macromolecules can then be visualized and analyzed.
When interpreting gel electrophoresis data, one should examine the patterns of separated macromolecules in the gel. The patterns can provide information about the size and charge of the macromolecules, and can be compared to reference patterns or standards to identify specific macromolecules. For example, in DNA gel electrophoresis, the separated DNA fragments can be compared to a size marker or reference DNA to determine the size of the fragments. The interpretation of gel electrophoresis data can also involve comparing results from multiple samples to identify differences or changes in macromolecule patterns.
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Which of the following is the electron configuration of an excited state of an oxygen atom? A) 1s22s22p4 B) 1s22s22p5 C) 1s22s22p33s1 D) 1s22s22p6 E) 1s22s22p3
C. 1s22s22p33s1. The 1s22s22p33s1 is the electron configuration of an excited state of an oxygen atom.
What is the oxygen atom's excited state's electron configuration?When an electron is stimulated and leaps into a higher orbital, the atom's excited-state configuration differs from its normal configuration. Oxygen has the excited-state electron configuration 1s22s22p33s1.
What is an atom's excited state?An atom's excited state is one in which it has more energy than its ground state. In this case, one or more electrons are not at their lowest energy state. Electrons have advanced to a higher energy level by using external energy.
What is the name of an atom's excited state?Energized-state absorption is the process of a system (such as an atom or molecule) being excited from one excited state to a higher-energy excited state by absorbing a photon (ESA). Only when an electron has already been excited from the ground state to a lower excited state is excited-state absorption conceivable.
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an emission line the hydrogen atom has a wavelength of 95.0 nm. what is the initial energy state (ni) of the electron?
The initial energy state (ni) of the electron is 3.
The energy of the electron at a specific energy level in the hydrogen atom calculation by Rydberg formula is given by:
En=−RH⋅(Z/n)²
En = energy level
R = Rydberg's constant (1.0973731568539(55) x 107 m-1)
Z = atomic number of the atom
n1 and n2 are integers where n2 > n1.
Ef = − RH⋅( Z/nf )2
Ei= −R H.( Z/ni )²
ΔE = Ef −E i
Δ E = [−RH⋅(Z/ nf )²] − [−RH⋅(Zni )² ]
take −RH⋅(Z)² as a common factor,
ΔE =−RH⋅(Z)²[1/nf²−1/ni²] (Eq. 1)
The energy of the photon emitted is given by:
ΔE=−hc/λ (Eq. 2)
Please take note that when energy is discharged, the expression of energy must now include a negative sign.
Equation 1 and equation 2 combined result in:
−hc/λ=−RH⋅(Z)²[1/nf₂−1/ni²] (Eq. 3)
Planck's constant, h, is 6.626 x 10⁻³⁴ J.
Rydberg constant (s RH) is 2.118 x10⁻¹⁸ J.
The hydrogen atom's atomic number is Z, which equals 1.
The fundamental quantum number is n.
The electron's initial quantum state is ni
Given that the emission wavelength is in the visible portion of the spectrum, nf=2 (Balmer series). All observable transitions must have a n=2 conclusion.
plugging the numbers in (Eq.3)
hc/λ=−RH⋅(Z)²[1/n²f−1/n²i]
ni =−6.626⋅10⁻³⁴J.s× .998 x10⁸m/s x 656.7×10⁻⁹m
ni= =−2.178⋅10⁻¹⁸J⋅ (1)²[1/2²−1/ni²
solve for ni,
ni=3
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calculate the grams of ethane present in a sample containing 0.1376 moles if the molar mass of ethane is 30.067 g/mol.
There are 4.17 grams of ethane present in a sample containing 0.1376 moles if the molar mass of ethane is 30.067 g/mol.
The number of grams of ethane in a sample can be calculated by multiplying the number of moles of ethane by its molar mass. The molar mass of ethane is 30.067 g/mol, so the number of grams of ethane in the sample is:
0.1376 moles * 30.067 g/mol = 4.17 g
The molar mass of a substance is defined as the mass of one mole of that substance and is usually expressed in g/mol. A mole is a unit of measurement for the amount of a substance, defined as Avogadro's number of entities (atoms, molecules, ions, etc.). One mole of a substance contains Avogadro's number of entities of that substance.
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an element has two naturally occurring isotopes. isotope 1 has a mass of 190.9606 amu and a relative abundance of 37.3 % , and isotope 2 has a mass of 192.9629 amu . find the atomoic mass
The atomic mass of this element is 192.22 amu. This is calculated by taking the weighted average of the masses of the two isotopes, which is (190.9606 x 37.3%) + (192.9629 x 62.7%) = 192.22 amu.
The atomic mass of this element is calculated by taking the weighted average of the masses of the two isotopes.
This means that you multiply the mass of each isotope by its relative abundance (the fraction of that isotope that exists in the element) to get the weighted average mass.
For example, in this case the first isotope has a mass of 190.9606 amu and a relative abundance of 37.3%. This means that the contribution of this isotope to the atomic mass is (190.9606 amu x 0.373) = 70.9043 amu. Similarly, the contribution of the second isotope is (192.9629 amu x 0.627) = 121.3179 amu. When these two contributions are added together you get the atomic mass of 192.22 amu.
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If the nucleus of an atom is represented as 2 X, the atom is
What is the best way to fill the graduated cylinder EXACTLY to the 10.0 mL marking? -By adding small amounts of water using a medicine dropper once the meniscus is near the desired volume.
The best way to fill a graduated cylinder exactly to the 10.0 mL marking is by adding small amounts of water using a medicine dropper once the meniscus is near the desired volume.
A graduated cylinder is a laboratory tool used to measure the volume of a liquid. The cylinder is marked with graduation lines at regular intervals, which allow the user to determine the volume of a liquid based on its height in the cylinder.
To fill a graduated cylinder exactly to the 10.0 mL marking, it is best to use a medicine dropper or a pipette, as this will allow you to add small amounts of liquid to the cylinder. This is especially important when filling the cylinder to an exact volume, as it is easier to be precise with small additions of liquid than it is with larger amounts.
When using a medicine dropper or a pipette, it is important to add the liquid slowly and watch the meniscus, which is the curved surface of the liquid at the top of the cylinder. The meniscus should be observed from eye level, with the graduation lines in focus. As you add the liquid, the meniscus will rise in the cylinder, and you should stop adding liquid when the meniscus reaches the 10.0 mL marking.
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