Answer
14√5
Step-by-step explanation:
8√5 + 2√45
= 8√5 + 6√5
= 14√5
Hope this helps
Answer:
[tex]\boxed {\boxed {\sf 14 \sqrt{5}}}[/tex]
Step-by-step explanation:
We are asked to combine the radicals. We have the following expression:
[tex]8 \sqrt{5} + 2 \sqrt{45}[/tex]
Currently, we cannot combine these radicals. The value under the square root is not the same for both terms.
However, we can simplify the radical 2 √45 because the value under the radical is divisible by a perfect square.
45 can be divided by 9 (the perfect square) for a quotient of 5. So, we can simplify the radical using this information.
Break the radical into 2 radicals: 9 and 5.
[tex]8 \sqrt{5}+ 2 \sqrt{9}\sqrt{5}[/tex]
Notice that a perfect square is under the radical. √9 can be simplifed to 3.
[tex]8 \sqrt{5}+ 2 *3 \sqrt{5}[/tex]
Multiply 2 and 3.
[tex]8 \sqrt{3} + 6 \sqrt{5}[/tex]
Now the value under the radical is the same for both terms, and we can add the numbers in front of the radicals.
[tex]14 \sqrt{5}[/tex]
The radicals combined is equal to 14√5
Find each product
-4 (41)
4 (-41)
-4 (-41)
Please help me!!
The salaries of 235 nurses were recorded and analyzed. The analyst later found that the highest salary was incorrectly recorded as 10 times the actual amount. After the error was corrected, the report showed that the corrected value was still higher than any other salary. Which sample statistic must have changed after the correction was made?
The sample statistic that must have changed after the correction was made is mean. Because mean is based on all the observation in the data. So changing any value in the data will impact mean.
Changing the highest salary in the data will have no impact on median because median lies at the center of data.
Changing the highest salary in the data will have no impact on mode because mode is the most frequently occurring value in the data.
Changing the highest salary in the data will have no impact on minimum because minimum is the smallest value in the data.
Hence the only statistic which will change is mean.
Answer: A-Mean
Step-by-step explanation:
A.) Mean
B.) Median
C.) Mode
D.) Minimum
If F is the function defined by F(x)=3x−1, find the solution set for F(x)=0.
The solution for set F(x) is -1
Determine if each statement is always, sometimes, or never true.
Parallel lines are
coplanar.
Perpendicular lines are
coplanar.
Distance around an unmarked circle can
be measured
Answer:
1) Parallel lines are "ALWAYS"
coplanar.
2) Perpendicular lines ARE "ALWAYS"
coplanar.
3) Distance around an unmarked circle CAN "NEVER" be measured
Step-by-step explanation:
1) Coplanar means lines that lie in the same plane. Now, for a line to be parallel to another line, it must lie in the same plane as the other line otherwise it is no longer a parallel line. Thus, parallel lines are always Coplanar.
2) similar to point 1 above, perpendicular lines are Coplanar. This is because perpendicular lines intersect each other at right angles and it means they must exist in the same plane for that to happen. Thus, they are always Coplanar.
3) to have the distance, we need to have the circle marked out. Because it is from the marked out circle that we can measure radius, diameter and find other distances around the circle. Thus, distance around an unmarked circle can never be measured.
the shorter side of a rectangle is 60% of the longer side and the perimeter of the rectangle is 96 inches. find the side lengths
Answer:
Length of the rectangle:
[tex]x = \frac{4800}{106} = \frac{2400}{53} [/tex]
Breadth of the rectangle:
[tex]60\%(x) = \frac{60}{100} \times \frac{4800}{106} \: \: \: \: \: \: \: \: \: \: \: \\ =60 \times \frac{48}{106} \\ = \frac{2880}{106} [/tex]
Step-by-step explanation:
Longer side of the rectangle(length) = x
Shorter side of the rectangle(breadth) = (60%)x
Perimeter of the rectangle = 2(l+b) = 96 inches
Hence,
[tex]96 = 2(x + 60\%(x))[/tex]
[tex]96 = 2(x + \frac{6}{100 } x)[/tex]
[tex]96 = 2( \frac{100}{1 00} x + \frac{6}{100} x)[/tex]
[tex]96 = 2( \frac{106}{100} x)[/tex]
[tex]96 = \frac{106}{50} x[/tex]
[tex]96 \div \frac{106}{50} = x[/tex]
[tex]96 \times \frac{50}{106} = x[/tex]
[tex] \frac{4800}{106} = x[/tex]
State sales tax y is directly proportional to retail price x. An item that sells for 156 dollars has a sales tax of 14.42 dollars. Find a mathematical model that gives the amount of sales tax y in terms of the retail price x .
What is the sales tax on a 320 dollars purchase.
Answer:
The sales tax on a 320 dollars purchase is of $29.6.
Step-by-step explanation:
State sales tax y is directly proportional to retail price x.
This means that:
[tex]y = cx[/tex]
In which c is the constant of proportionality.
An item that sells for 156 dollars has a sales tax of 14.42 dollars.
This means that [tex]x = 156, y = 14.42[/tex]. We use this to find c. So
[tex]y = cx[/tex]
[tex]14.42 = 156c[/tex]
[tex]c = \frac{14.42}{156}[/tex]
[tex]c = 0.0924[/tex]
Then
[tex]y = 0.0924x[/tex]
What is the sales tax on a 320 dollars purchase?
y when [tex]x = 320[/tex]. So
[tex]y = 0.0924(320) = 29.6[/tex]
The sales tax on a 320 dollars purchase is of $29.6.
The length of a rectangle is 12 m and its diagonal is 15 m. find
the breadth and area of the rectangle.
Answer:
108 square metres
Step-by-step explanation:
A=√d square - l square
here
A = area
d= diagonal
l= length
If x=3 y=5 h=9 wat is xy+h
Answer:
24
Step-by-step explanation:
3x5=15
15+9=24
What is the ninth term in the binomial expansion of (x – 2y)13?
329,472x5y8
–329,472x5y8
–41,184x8y5
41,184x8y5
Answer:
It's A
Step-by-step explanation:
On Edg
Answer pls:) I would really appreciate it
Answer:
1. C
2. B
3 A
4. A
Step-by-step explanation:
#1
Brady starts off with 12 coins
And buys 6 more coins every year
So add 6 to find number of coins he will have the next year until we've done it five times ( because we want to find how many he will have after 5 years )
12 ( 1st year )
Add 6
12 + 6 = 18 ( 2nd year )
Add 6
18 + 6 = 24 ( 3rd year )
Add 6
24 + 6 = 30 ( 4th year )
Add 6
30 + 6 = 36 ( 5th year )
By the fifth year he will have 36 coins and the sequence would be
12, 18, 24, 30, 36
Which corresponds with answer choice C
2
15, 19, 23, 27, ?
We want to find the next term
To do so we must find the common difference
We can do this by subtracting the last given term by the term before it
27 - 23 = 4
Just to clarify we can do the terms before those
19 - 15 = 4
So the common difference is 4
Now to find the next term we simply add 4 to the last given term
27 + 4 = 31
The next term would be 31
3. Cumulative property of addition states that you can add any 3 numbers in a different order and they will be the same
a + b + 2 = 2 + a + b
Same variables and numbers just different order
Therefore this is an example of cumulative property of addition
4. The GCF ( greatest common factor ) is the greatest number that the two numbers can be divided by
18a and 24ab
Factors of 18
2 , 9 , 6, 3 , 1 and 18
Factors of 24
24, 1, 2, 12, 6, 4, 3 and 8
The greatest factor that both 18 and 24 have is 6
The GCF would be 6a ( not 6 ) because both numbers share a common variable (a) ( 18a , 24ab )
What are the intercepts of the graphed function?
3
-2
Х
O x-intercept = (-1,0)
y-intercept = (-3,0)
O x-intercept = (0, -1)
y-intercept = (0, -3)
O x-intercept = (0, -1)
y-intercept = (-3,0)
x-intercept = (-1,0)
y-intercept = (0, -3)
6
Step-by-step explanation:
x intercept=(-1,0) because the graph is passing this point on the x axis
y intercept=(0,-3)
Answer:
4th option
Step-by-step explanation:
The x- intercept is where the graph crosses the x- axis.
This is at (- 1, 0 )
The y- intercept is where the graph crosses the y- axis.
This is at (0, - 3 )
Draw a line representing the "rise" and a line representing the "run" of the line. State the slope of the line in simplest form.
Answer:
Slope = 2
Step-by-step explanation:
To find the slope of the line, you need to plot two points
My own two points will be: [tex](1,2)[/tex] and [tex](2,4)[/tex]
Now use the Slope-Formula to identify the slope of the line
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
[tex]m=\frac{4-2}{2-1}[/tex]
[tex]m=\frac{2}{1}[/tex]
[tex]m=2[/tex]
so the slope of the line in simplest form will be 2.
find the rate of change of volume of a cone if dr/dt is 3 in./min. and h=4r when r = 8 inches
Answer:
[tex]v = \frac{1}{3}bh[/tex]
since base is pi r^2
[tex]v = \frac{1}{3} \pi \: r {}^{2} h[/tex]
it's given that h=4r
[tex]v = \frac{1}{3} \pi \: r^{2} (4r) = \frac{4}{3} \pi \: {r}^{3} [/tex]
now find derivative
[tex] \frac{dv}{dt} = 4\pi \: r {}^{2} [/tex] × dr/dt
r=8 , dv/dt = 3
dv/dt = 4pi (8)^2 ×3 = 768pi
Answer:
768 pi in^3/min
Step-by-step explanation:
Volume of cone=1/3 pi×r^2×h
Differentiating this gives:
dV/dt=1/3×pi×2r dr/dt×h+1/3×pi×r^2×dh/dt
We are given the following:
dr/dt = 3 in./min.
h=4r when r = 8 inches
If h=4r then dh/dt=4dr/dt=4(3 in/min)=12 in/min
If h=4r and r=8 in, then h=4(8)=32 in for that particular time.
Plug in:
dV/dt=1/3×pi×2r dr/dt×h+1/3×pi×r^2×dh/dt
dV/dt=1/3×pi×2(8)(3)×32+1/3×pi×(8)^2×12
dV/dt=pi×2(8)(32)+pi×(8)^2(4)
dV/dt=pi(256×2)+pi(64×4)
dV/dt=pi(512)+pi(256)
dV/dt=pi(768)
dV/dt=768pi
dV/dt=768/pi in^3/min
i need helpp pleaseee
(x+a)(x-a) = x² -25 then what is the value of a ?
Answer:
The value of A is 5
......
[tex]\huge{\boxed{\boxed { ⎆ Answer :- }}} \ [/tex]
[tex](x + a)(x - a) = {x}^{2} - 25[/tex]
Use, the algebraic identity ↦
[tex](a + b)(a - b) = {a}^{2} - {b}^{2} [/tex]
So,
[tex](x + a)(x - a) = {x}^{2} - 25 \\ \\ ⟹ \sqrt{25} = 5[/tex]
↦So, the value of a is 5.
ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ
꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐
3 miles in 25 minutes same rate in 20 minutes?
Step-by-step explanation:
25 minutes=3 miles
1 minute = 3/25 miles
20 minutes = 3/25 * 20 miles
= 2.4 miles
Therefore, the answer is 2.4 miles.
what is the formula for triangle
Answer:
A = 1/2 b × h
Step-by-step explanation:
hope it helps !!!!
Answer:
The formula for the area of a triangle is 1/2bh.
Question 3: Is the mean hemoglobin level of high-altitude workers different from 20 g/cm ? To investigate this, researchers examined a sample of 20 workers and found that sample mean hemoglobin level is 17 g/cm whereas sample standard deviation is 3 g/cm². Test this claim at alpha=0.10.
Answer:
Science is really connected to mathematics.Hemoglobin is the red bloodUse the appropriate reciprocal identity to find the exact value of sin for the given value of csc . Rationalize denominators when applicable. csc 27/5 sin
Answer:
[tex]\sin(\theta) = \frac{5}{27}[/tex]
Step-by-step explanation:
Given
[tex]\csc(\theta) = \frac{27}{5}[/tex]
Required
Determine [tex]\sin(\theta)[/tex]
In trigonometry identity;
[tex]\sin(\theta) = \frac{1}{\csc(\theta)}[/tex]
So, we have:
[tex]\sin(\theta) = \frac{1}{\frac{27}{5}}[/tex]
Take inverse of the fraction
[tex]\sin(\theta) = \frac{5}{27}[/tex]
A confided aquifer has a piezometric height of 30 feet before being pumped. The well is then pumped at 250 gallons/day for a very long time and results in a drawdown of 10 feet at the well. If the transmissivity in the aquifer is 10.0 ft2/day and the radius of the well is 0.5 feet, estimate the drawdown in feet for a well 50 feet away
Answer:
[tex]d_2=-8.32ft[/tex]
Step-by-step explanation:
From the question we are told that:
Height of first draw down [tex]h=30[/tex]
Pump Discharge [tex]Q=250gallons/day[/tex]
Well 1 depth [tex]d_1=10ft[/tex]
Transmissivity[tex]\=T 10.0 ft2/day[/tex]
Radius[tex]r=0.5[/tex]
Well 2 depth [tex]d_2=50ft[/tex]
Generally the Thiem's equation for Discharge is mathematically given by
[tex]Q=\frac{2\piT(h_2-h_1)}{ln(\frac{r_2}{r_1})}[/tex]
[tex]250=\frac{2*\pi 10 (10-d_2)}{ln(\frac{50}{0.5})}[/tex]
[tex]1151.293=2*\pi 10 (10-d_2)[/tex]
[tex]d_2=-8.32ft[/tex]
A farmer picks pumpkins from a large field. The farmer makes samples of 260 pumpkins and inspects them. If one in fifty pumpkins are not fit to market and will be saved for seeds, what is the standard deviation of the mean of the sampling distribution of sample proportions?
Answer:
[tex]\mu = 5.2[/tex]
[tex]\sigma = 2.257[/tex]
Step-by-step explanation:
Given
[tex]n = 260[/tex] -- samples
[tex]p = \frac{1}{50}[/tex] --- one in 50
Solving (a): The mean
This is calculated as:
[tex]\mu = np[/tex]
[tex]\mu = 260 * \frac{1}{50}[/tex]
[tex]\mu = 5.2[/tex]
Solving (b): The standard deviation
This is calculated as:
[tex]\sigma = \sqrt{\mu * (1-p)}[/tex]
[tex]\sigma = \sqrt{5.2 * (1-1/50)}[/tex]
[tex]\sigma = \sqrt{5.2 * 0.98}[/tex]
[tex]\sigma = \sqrt{5.096}[/tex]
[tex]\sigma = 2.257[/tex]
the cost of 10 oranges is $6. what is the cost of an orange ?
Answer Choices:
$0.40
$0.60
$4
$6
Answer:
$0.60
Step-by-step explanation:
To find the cost of 1 orange, divide the $6 by 10:
6/10 = 0.6
Hope it helps (●'◡'●)
Pls solve the above question
Kindly don't spam+_+
Answer:
Step-by-step explanation:
Given expressions are,
[tex]p=\frac{\sqrt{10}-\sqrt{5}}{\sqrt{10}+\sqrt{5}}[/tex] and [tex]q=\frac{\sqrt{10}+\sqrt{5}}{\sqrt{10}-\sqrt{5}}[/tex]
Remove the radicals from the denominator from both the expressions.
[tex]p=\frac{\sqrt{10}-\sqrt{5}}{\sqrt{10}+\sqrt{5}} \times \frac{\sqrt{10}-\sqrt{5}}{\sqrt{10}-\sqrt{5}}[/tex]
[tex]=\frac{(\sqrt{10}-\sqrt{5})^2}{(\sqrt{10})^2-(\sqrt{5})^2}[/tex]
[tex]=\frac{(\sqrt{10}-\sqrt{5})^2}{5}[/tex]
[tex]\sqrt{p}=\sqrt{\frac{(\sqrt{10}-\sqrt{5})^2}{5}}[/tex]
[tex]=\frac{\sqrt{10}-\sqrt{5}}{\sqrt{5}}[/tex]
[tex]q=\frac{\sqrt{10}+\sqrt{5}}{\sqrt{10}-\sqrt{5}}[/tex]
[tex]=\frac{\sqrt{10}+\sqrt{5}}{\sqrt{10}-\sqrt{5}}\times \frac{\sqrt{10}+\sqrt{5}}{\sqrt{10}+\sqrt{5}}[/tex]
[tex]=\frac{(\sqrt{10}+\sqrt{5})^2}{(\sqrt{10})^2-(\sqrt{5})^2}[/tex]
[tex]=\frac{(\sqrt{10}+\sqrt{5})^2}{5}[/tex]
[tex]\sqrt{q}=\sqrt{\frac{(\sqrt{10}+\sqrt{5})^2}{5}}[/tex]
[tex]=\frac{(\sqrt{10}+\sqrt{5})}{\sqrt{5}}[/tex]
[tex]\sqrt{q}-\sqrt{p}-2\sqrt{pq}=\frac{(\sqrt{10}+\sqrt{5})}{\sqrt{5}}-\frac{(\sqrt{10}-\sqrt{5})}{\sqrt{5}}-2(\frac{(\sqrt{10}+\sqrt{5})}{\sqrt{5}})(\frac{(\sqrt{10}-\sqrt{5})}{\sqrt{5}})[/tex]
[tex]=\frac{1}{\sqrt{5}}(\sqrt{10}+\sqrt{5}-\sqrt{10}+\sqrt{5})-\frac{2}{5}[(\sqrt{10})^2-(\sqrt{5})^2)][/tex]
[tex]=\frac{1}{\sqrt{5}}(2\sqrt{5})-\frac{2}{5}(10-5)[/tex]
[tex]=2-2[/tex]
[tex]=0[/tex]
Identify the level of measurement of the data, and explain what is wrong with the given calculation. Ina set of data, alert levels are represented as 1 for low, 2 for medium, and 3 for high. The average mean of the 522 alert levels is 1.3. The data are at the ________ level of measurement. a. Nominalb. Ordinalc. Ratiod. IntervalWhat is wrong with the given calculation?a. Such data should not be used for calculations such as an average.b. One must use a different method to take the average of such datac. The true average is 2.5d. There is nothing wrong with the given calculation.
Answer:
(1) Ordinal
(2) Such data should not be used for calculations such as an average.
Step-by-step explanation:
Given
[tex]1 \to Low[/tex]
[tex]2 \to Medium[/tex]
[tex]3 \to High[/tex]
[tex]Average = 1.3[/tex]
Solving (a): The level of measurement
When observations are presented in ranks such as:
[tex]1 \to Low[/tex]
[tex]2 \to Medium[/tex]
[tex]3 \to High[/tex]
The level of measurement of such observation is ordinal
Solving (b): What is wrong with the computation?
Ordinal level of measurement are not numerical values whose average can be calculated because they are used as ranks.
Hence, (a) is correct
Determine whether the point is on the graph of the equation 2x+7y=13
(-4,3)
Is (-4,3) on the graph of 2x+7y=13?
Yes or no?
Answer:
(I) yessssssssssssssssssssssss
Answer:
yes it is.
Step-by-step explanation:
i did this and it was correct
There are 4 routes from Danbury to Hartford and 6 routes from Hartford to Springfield. You need to drive from Danbury to Springfield for an important meeting. You don’t know it, but there are traffic jams on 2 of the 4 routes and on 3 of the 6 routes. Answer the following:
a. You will miss your meeting if you hit a traffic jam on both sections of the journey. What is the probability of this happening?
b. You will be late for your meeting if you hit a traffic jam on at least one, but not both sections of the trip. What is the probability of this?
c. What is the probability that you will hit no traffic jam?
Answer:
a. P) = 0.25
b. P) = 0.25
c. P) = 0.5
Step-by-step explanation:
a) 1/4 as 1/2 x 1/2 = 1/4 = 0.25 This becomes reduced as we are multiplying one complete probability journey by another complete probability journey.
b) see above as 1/2 x 1/4 and 1/4 x 1/2 = 2.5 = 1/4 = 0.25
or we can Set to 1 and 1 - 3/4 = 1/4. = 0.25.
c) 1/2 as half of the journeys have traffic jams so its 1 - 1/2 = 1/2 = 0.5
Last year Nancy weighted 37( 5)/(8) pounds. This year she weighed 42.7 pounds. How much did she gain?
Answer:
22.7 pounds
Step-by-step explanation:
Simply just subtract 42.7 with 37 (5/8) to get the answer. If done correctly, you should get 22.7 pounds.
So, the final answer is 22.7 pounds.
Hope this helped!
Joe bought 200 masks and each mask costs Rs.5. How much did he pay altogether?
pls write the steps how to do if you I will give 5 star
Given:
total number of masks= 200cost of 1 mask= Rs. 5so, total cost fir 200 masks=
200×5
= 1000
therefore, Joe paid Rs. 1000 altogether.
Find the value of y in the equation y=-4x+9 when x=-3
Answer:
y = 21
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightStep-by-step explanation:
Step 1: Define
Identify
y = -4x + 9
x = -3
Step 2: Evaluate
Substitute in x [Equation]: y = -4(-3) + 9Multiply: y = 12 + 9Add: y = 21The distribution of the number of children for families in the United States has mean 0.9 and standard deviation 1.1. Suppose a television network selects a random sample of 1000 families in the United States for a survey on TV viewing habits.
Required:
a. Describe (as shape, center and spread) the sampling distribution of the possible values of the average number of children per family.
b. What average numbers of children are reasonably likely in the sample?
c. What is the probability that the average number of children per family in the sample will be 0.8 or less?
d. What is the probability that the average number of children per family in the sample will be between 0.8 and 1.0?
Answer:
a) By the Central Limit Theorem, it has an approximately normal shape, with mean(center) 0.9 and standard deviation(spread) 0.035.
b) Average numbers of children between 0.83 and 0.97 are reasonably likely in the sample.
c) 0.0021 = 0.21% probability that the average number of children per family in the sample will be 0.8 or less
d) 0.9958 = 99.58% probability that the average number of children per family in the sample will be between 0.8 and 1.0
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
Mean 0.9 and standard deviation 1.1.
This means that [tex]\mu = 0.9, \sigma = 1.1[/tex]
Suppose a television network selects a random sample of 1000 families in the United States for a survey on TV viewing habits.
This means that [tex]n = 1000, s = \frac{1.1}{\sqrt{1000}} = 0.035[/tex]
a. Describe (as shape, center and spread) the sampling distribution of the possible values of the average number of children per family.
By the Central Limit Theorem, it has an approximately normal shape, with mean(center) 0.9 and standard deviation(spread) 0.035.
b. What average numbers of children are reasonably likely in the sample?
By the Empirical Rule, 95% of the sample is within 2 standard deviations of the mean, so:
0.9 - 2*0.035 = 0.83
0.9 + 2*0.035 = 0.97
Average numbers of children between 0.83 and 0.97 are reasonably likely in the sample.
c. What is the probability that the average number of children per family in the sample will be 0.8 or less?
This is the p-value of Z when X = 0.8. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{0.8 - 0.9}{0.035}[/tex]
[tex]Z = -2.86[/tex]
[tex]Z = -2.86[/tex] has a p-value of 0.0021
0.0021 = 0.21% probability that the average number of children per family in the sample will be 0.8 or less.
d. What is the probability that the average number of children per family in the sample will be between 0.8 and 1.0?
p-value of Z when X = 1 subtracted by the p-value of Z when X = 0.8.
X = 1
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{1 - 0.9}{0.035}[/tex]
[tex]Z = 2.86[/tex]
[tex]Z = 2.86[/tex] has a p-value of 0.9979
X = 0.8
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{0.8 - 0.9}{0.035}[/tex]
[tex]Z = -2.86[/tex]
[tex]Z = -2.86[/tex] has a p-value of 0.0021
0.9979 - 0.0021 = 0.9958
0.9958 = 99.58% probability that the average number of children per family in the sample will be between 0.8 and 1.0
