Complete the function table. Function: t = 5d − 2

The probability of not spinning a 3 is 8/9

From the question, the given parameters are:

Number of sections = 9

Sections = Number 1 to 9

The probability of spinning a 3 = 1/9

The above probability can be represented as

P(3) = 1/3

The probability that the number 3 is not spun is the complement of the  probability of spinning a 3

This is calculated as

P(3) + P(Not 3) = 1

Substitute the known values in the above equation So, we have the following equation

1/9 + P(Not 3) = 1

Evaluate the like terms

P(not 3) = 8/9

Hence, the probability is 8/9

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The equation that models the function is y = 8/3(x) - 5/3.

Given:

The graph of a linear function passes through the point (-2, -7).

When the input increases by 3 the value of the function increases by 8.

(x,y) = (x+3,y+8)

(-2,-7) = (-2+3,-7+8)

= (1,1)

slope between (1,1) and (-2,-7) is m = -7-1/-2-1

= -8/-3

m = 8/3.

substitute m in y = mx + c

y = 8/3(x)+c

substitute (-2,-7)

-7 = 8/3(-2) + c

-7*3 = -16 + 3c

-21+16 = 3c

-5 = 3c

c = -5/3

y = 8/3(x) - 5/3.

Therefore the equation that models the function is y = 8/3(x) - 5/3.

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Answer:

8p - 9

Step-by-step explanation:

→ Expand brackets

6p - 15 + 2p + 6

→ Collect like terms

8p - 9

Yes, you are safe to land, If the landing angle at an airport is 4° and you are two miles out and ½ mile high.

The final approach, also known as the final leg or final approach leg, is the last leg of an aircraft's approach to landing in aviation. During this leg, the aircraft is aligned with the runway and descending for a landing. In aircraft radio lingo, it is frequently abbreviated to "final".

Given,

If the landing angle at an airport is 4° and you are two miles out and ½ mile high,

Yes, you are safe to land.

A normal airport landing pattern calls for aircraft to turn from the base leg to the final within 0.5 to 2 miles of the airport when visual meteorological conditions (VMC) are present. A "straight-in" final approach, when all other legs are skipped, is frequently employed for instrument approaches as well as VFR approaches onto controlled airfields. At American non-towered airports, straight-in approaches are discouraged.

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The  dimensions of recangle is = 30 yrds.

acc to our question-

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Answer:

16x² - 18x

Step-by-step explanation:

(25x² + 4 - 30x) - (9x² + 4 - 12x) ← distribute this parenthesis by - 1

= 25x² + 4 - 30x - 9x² - 4 + 12x ← collect like terms

= (25x² - 9x²) + (4 - 4) + (- 30x + 12x)

= 16x² + 0 + (- 18x)

= 16x² - 18x

Answer:  The correct answer is Option D: h=2A/(b1+b2)

Step-by-step explanation:

Solve for h:

a=(1/2h)(b1+b2)

Step 1: Flip the equation

1/2b^2h+1/2b1h=a

Step 2: Factor out variable h

h((b2+b1)/2)=a

Step 3: Divide both sides by (b^2+b1)/2

h((b2+b1/2))/(b2+b1/2)=(a/(b2+b1)/2)

h=2a/(b2+b1)  

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The formula for the cost if the line rental is £20 and the price of calls made is £15 will be 20 + 15p.

It should be noted that an expression is used to illustrate the relationship given between the variables.

In this case, the monthly phone contract is made up of the fixed line rental and the price represented by p.

The appropriate expression to illustrate this information will be:

= Fixed cost + Calls made

= 20 + 15(p)

= 20 + 15p

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The domain of h(z) would be (-8,3).

The range of h(z) would be (2,9).

Point (4,8) would be moved to (0,8)

What are the domain and range of a function?

The domain is the set of all x-values that can be used to make the function "work" and produce actual y-values.

A function's range is the variety of conceivable y-values (minimum y-value to maximum y-value)

For the function f(x):

Domain: (-4,7)

Range: (2,9)

The function f(x+4) is equal to 1 (f(x+4)).

This shows, inputs: -4, outputs: 1

Domain of f(x+4):

add -4 to the Domain values of f(x)

Domain:(-4-4,7-4)=(-8,3)

Range of f(x+4):

Multiply the range values of f(x) by 1

Range: (1*2,1*9)= (2,9)

Find, where the point (4,8) would be moved:

add -4 to 4, and multiply 8 by 1

(4-4,8*1)

=(0,8)

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Answer:

-0.67

Step-by-step explanation:

What is the slope of the line created by this equation? Round your answer out to the two nearest decimal places. 6x + 9y = 1

_____________________________________________

Slope intercept form solves for y:

y = mx + b when m = slope and b = y-intercept

First, solve for y:

6x + 9y = 1

subtract 6x from both sides:

6x + 9y - 6x = 1 - 6x

9y = 1 - 6x

divide both sides by 9:

9y/9 = (1 - 6x)/9

y = 1/9 - 6/9x

reduce right side:

y = 1/9 - 2/3x

rearrange right side:

y =  - 2/3x + 1/9

Back to the equation: y = mx + b when m = slope and b = y-intercept

your slope is -2/3

in decimal form, rounded to two digits: -0.67

The relation accepts reflexive, symmetry, and transitive.

Recall that a relation R is reflexive if the element (x, x) belongs to R for all elements X in the domain of R.

If (x, y) belongs to R, then follows that (y, x) must likewise belong to R, making the situation symmetric.

And it is transitive if (x, y) and (y, z) belongs to R necessarily implies that (x, z) belongs to R.

Given r is a relation on the set of all nonnegative integers R(a,b)

Reflexive - YES. A given number a will always have the same remainder when divided by 5.

Symmetric - YES. If a and b have the same remainder when divided by 5, then b and a are the same pair, so again they will have the same remainder.

Transitive - YES. If a and b as well as b and c have the same remainder when divided by 5, this is possible if both a and c also have the same remainder when divided by 5.

Therefore the relation accepts reflexive, symmetry, and transitive.

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Answer:

x=21

Step-by-step explanation:

The angles of a triangle always add up to 180°

71+62+(2x+5)=180

First add 71 and 62

133+(2x+5)=180

Then you subtract 133

2x+5=47

Subtract 5 too

2x=42

Then divide by 2

x=21

We can check our answer by adding all the angles

71+62+(2*21+5)

71+62+(42+5)

71+62+47=180

sin^-1(-1/2) enter directly into a calculator and you'll find your answer

Now we have to,

→ find the required value of b.

Formula we use,

→ (AC)² = (BC)² + (AB)²

Then the value of a will be,

→ (10.5)² = b² + (3)²

→ 110.25 = b² + 9

→ b² = 110.25 - 9

→ b = √101.25

→ [ b = 10.06 in ]

Hence, value of b is 10.06 in.

Answer:

You have to place the numbers given or your left in the formula given. So for example: y= 2*(-2)^2

that's: y=2*4, so: y=8

1) y=8

2) y= 2*(-1)^2. y=2

3) y= 2*(0)^2. y=0

4) y= 2*(1)^2. y=2

5) y= 2*(2)^2. y=8

Answer:

1: [tex]2\sqrt{2}[/tex]

2: [tex]10\sqrt{55}[/tex]

Step-by-step explanation:

[tex]\sqrt{16-8}[/tex]

[tex]\sqrt{8}[/tex]

[tex]\sqrt{8}=2\sqrt{2}[/tex]

2:

[tex]\sqrt{\frac{11}{16+4}[/tex]

[tex]\sqrt{\frac{11}{20}[/tex]

[tex]\sqrt{.55}[/tex]

[tex]10\sqrt{55}[/tex]

Hopes this helps

The perimeter of Ragans new mural is 530cm.

Rectangle:

A rectangle is a type of quadrilateral, whose opposite sides are equal and parallel. It is a four-sided polygon that has four angles, equal to 90 degrees. A rectangle is a two-dimensional shape.

Here it is given that the measure of the rectangle is 238 cm and 435cm.

The Raegan creates a mural that is 27cm.

The formula to calculate the perimeter of a rectangle:

Perimeter = 2(length + breadth)

Earlier the length is 238cm and the breadth is 435cm.

Now replace the breath 435cm to 27cm.

length = 238cm

breadth = 27cm

Therefore we get the perimeter of the rectangle:

Perimeter = 2( 238 + 27)

= 2( 265)

=530cm

Therefore the perimeter is 530cm.

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Answer:

1400

Step-by-step explanation:

The equation that can be used to find the amount of electricity Jeremy used per day during the month of December is 3.8KWH per day and Jeremy used 3.8KWH per day electricity in the month of December.

Electricity Jeremy used in November = 6 kilowatt hours (KWH)

Total electricity used in the holiday season = 120KWH

He took the decorations down on December 30

Amount of electricity Jeremy used per day during the month of December =

(Total electricity used in the holiday season - Electricity Jeremy used in November) / 30 days

= (120KWH - 6KWH) / 30

= 114KWH / 30

= 3.8KWH per day

In conclusion, the amount of electricity Jeremy used per day in December is 3.8KWH per day.

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Answer:

  15 feet

Step-by-step explanation:

Given an 8' object casts a 10' shadow, you want to know the length of the shadow of a 12' object.

The shadow length is proportional to the object length:

  shadow/object = 10'/8' = s/12'

Multiplying by 12', we have ...

  s = (12')(10/8) = 15'

The shadow of a tree 12 feet tall will be 15 feet long.

Answer:

Step-by-step explanation:

We know that the area of a triangle is given by :-

Let b be the base (in feet)  of the triangle .

it is given that  , The school wants the height of the triangle to be 6 feet.

Then, the area of triangle will be :-

           (1)

The area of the logo must be at most (less than or equal to) 15 square feet.

i.e. Area ≤ 15 square feet         (2)

Now, Substitute the value of A from (1) into (2) , we get

Divide both sides by 3  , we get

The spreadsheet that shows the distances between the cities, indicates that the distances between the cities are as follows;

a) From Hereford to Chester, the distance is 95 miles

b) Chester is the town that is 99 miles from Kendal

c) Ellen will have driven 201 miles if she drives from Kendal to Hereford through Chester

A spreadsheet application is used for the storage analysis, organization, and computation of data.

The interpretation of the distances in the chart which is in the form of a spreadsheet are;

The value in the cell corresponding to the distance from Kendal to Chester that is the cell which is on the same column as Kendal and on the same row as Chester is 99

Therefore, the distance from Kendal to Chester is 99 miles

The value in the cell that directly links Chester to Hereford that is the cell which is on the same column as Chester and on the same row as Hereford is 95

Therefore, the distance from Chester to Hereford is 95 miles

The value in the cell that connects Kendal to Hereford, that is the cell which is on the same column as Kendal and which is on the same row as Hereford is 201

Therefore the distance from Kendal to Hereford is 201 miles

a) The distance from Hereford to Chester is 95 miles

b) The town that is 99 miles from Kendal is Chester

c) The distance Ellen will have driven if she drives from Kendal to Hereford via Chester is 201 miles

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Answer:

[tex] \frac{ {m}^3{} }{25} [/tex]

Step-by-step explanation:

that is the answer

Answer:

Step 6 is wrong

Answer:

7

Step-by-step explanation:

65x+9.45y=160.657 point 6 5 x plus 9 point 4 5 y is equal to 160 point 6 5

The strategy which would eliminate a variable in the system of equations is to multiply the top equation by -5 , then add the equation and is denoted as option B.

This is a mathematical term which is made up of two expressions and is connected by an equal sign.

In the example given below:

x - 2y = 11

5x + 3y = -11

We can multiply the top by -5 which will result in:

-5x + 10y = -55 after which it is added to the other to give:

-5x + 5x + 10y + 3y  = -55 + (-11)

13y = -66

y = -66/13.

From this we can notice that the variable x was eliminated which is why option B is the correct choice.

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Answer: b)

Please give brainliest thx

Answer: 2[tex]\sqrt{2}[/tex]

Step-by-step explanation: First plug in the value, which is [tex]\sqrt{8}[/tex]

Then divided to 2[tex]\sqrt{2}[/tex]

a. The relationship between time and distance is not an arithmetic sequence, as the rate of change is not constant.

b. The distance is given by: d(n) = 5n².

An arithmetic sequence happens when the change in the output is always the same when the input changes by one, that is, the rate of change is constant.

From the table, the increases when the input(time) increases by one are given as follows:

15, 15, 35, 45.

The increases are not constant, hence the relationship between time and distance is not an arithmetic sequence.

The equation for the distance is given as follows:

d(t) = 0.5gt².

The constant is:

g = 10.

Hence:

d(t) = 5t².

At a time of n seconds, the distance is found replacing the lone instance of t by n, hence:

d(n) = 5n².

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