The three main components of electrolytic cells are cathode, anode and electrolyte. The negatively charged electrolytic cells are cathode and the positively charged electrolytic cells are anode.
An electrolytic cell can be defined as the electrochemical device which uses the electrical energy to perform a non-spontaneous redox reaction. They are mainly used for the electrolysis of certain compounds.
Here the anode cell is:
3H₂O (l) + I⁻ (aq) → IO⁻₃ (aq) + 6e⁻ + 6H⁺ (aq)
cathode cell is:
14H⁺ (aq) + Cr₂O₇²⁻ (aq) + 6e⁻ → 2Cr³⁺ (aq) + 7H₂O (l)
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Write a K expression for
[CoCl4]2-(aq)(blue) + 6H2O(l) ⇌ [Co(H2O)6]2+(aq)(pink) + 4Cl-(aq)
The relationship between a reaction's products and reactants with regard to a certain unit is expressed by the equilibrium constant, K.
Thus, When a reaction is homogeneous, all of the products' and reactions' states of matter are the same (the prefix "homo" means "same"). The solvent typically controls the reaction's overall state of matter.
When a reaction is in chemical equilibrium, the concentrations of the reactants and products do not significantly fluctuate over time. A double arrow between the reactants and products denotes these reversible reactions.
As described, this reaction is endothermic, therefore when heat is added, the equilibrium constant moves to the right. In turn, this turns the solution blue. Cl- is drawn out of solution by the addition of AgNO3.
Thus, The relationship between a reaction's products and reactants with regard to a certain unit is expressed by the equilibrium constant, K.
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If 128g of a certain gas in a container with a volume of 21.5 L has a pressure of 140 kPa and a temperature of 45°C, what is the molar mass of the gas?
The molar mass of the gas contained in a container with a volume of 2.15L with a pressure of 140kPa is 112.28 g/mol.
How to calculate molar mass?The molar mass of a substance can be calculated by dividing the mass of the substance by its no of moles.
According to this question, 128g of a certain gas in a container with a volume of 21.5 L has a pressure of 140 kPa and a temperature of 45°C. The no of moles must first be calculated as follows:
PV = nRT
Where;
P = pressureV = volumen = no of molesR = gas law constantT = temperature1.38 × 21.5 = n × 0.0821 × 318
29.67 = 26.1078n
n = 1.14 moles
molar mass = 128g ÷ 1.14 moles = 112.28 g/mol
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what mass of oxygen is required to oxidise 10g of ammonia to NO? Can someone explain to me step by step on how to do this reacting mass calculation?
4 NH3 + 5 O2 = 4 NO + 6 H2O
Taking into account the reaction stoichiometry, 13.33 grams of oxygen is required to oxidise 10g of ammonia to NO.
Reaction stoichiometryIn first place, the balanced reaction is:
4 NH₃ + 5 O₂ → 4 NO + 6 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
NH₃: 4 molesO₂: 5 molesNO: 4 molesH₂O: 6 molesThe molar mass of the compounds is:
NH₃: 17 g/moleO₂: 32 g/moleNO: 30 g/moleH₂O: 18 g/moleBy reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
NH₃: 4 moles ×17 g/mole= 68 gramsO₂: 5 moles ×32 g/mole= 160 gramsNO: 4 moles ×30 g/mole= 120 gramsH₂O: 6 moles ×18 g/mole= 108 gramsMass of O₂ requiredThe following rule of three can be applied: If by reaction stoichiometry 120 grams of NO are produced by 160 grams of O₂, 10 grams of NO are produced by how much mass of O₂?
mass of O₂= (10 grams of NO ×160 grams of O₂)÷120 grams of NO
mass of O₂= 13.33 grams
Finally, 13.33 grams of O₂ is required.
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If you mix 20.0 mL of 0.010 M MgCl2with 20.0 mL of 0.0020 M Na2CO3, will magnesium carbonate, MgCO3, precipitate out from the solution? Explain. Given: Ksp(MgCO3) = 4.0 × 10-5.
If you mix 20.0 mL of 0.010 M MgCl[tex]_2[/tex] with 20.0 mL of 0.0020 M Na[tex]_2[/tex]CO[tex]_3[/tex], magnesium carbonate will not precipitate out from the solution.
The byproduct of the condensing of atmospheric water vapour that falls from clouds as a result of gravitational pull is referred to as precipitation in meteorology. Rain, sleet, slush, ice pellets, graupel, drizzle, and hail are the main types of precipitation.
When a region of the outside world becomes completely saturated with water vapour, the water condenses or "precipitates" or falls. Because the water vapour does not enough condense to precipitate, fog and mist are instead colloids rather than precipitation. magnesium carbonate will not precipitate out from the solution.
Ksp =[Mg²⁺][CO₃²⁻]
[0.010][20] = C₂×40
C₂=0.001M
Q= 0.005×0.001
= 5×10⁻⁶M
Q<Ksp
precipitation will not occur
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What is the pH of 6.00 M H2CO3 if it has 7% dissociation? SHOW YOUR WORK!!!
From the calculation, the pH of the solution can be obtained as 0.39.
What is the pH of the solution?We first have to obtain the dissociation constant of the solution;
α = √Ka/C
Ka = Cα^2
Ka = 4.9 * 10^-3 * 6
Ka = 0.0294
Then we have that;
0.0294 = [x]^2/[6 - x]
0.0294 * [6 - x] = x^2
0.1764 - 0.0294 x = x^2
x^2 + 0.0294 x - 0.1764 =0
x = 0.41 M
Thus the pH of the solution is;
pH = -log[0.41]
= 0.39
pH is an important parameter in chemistry, biology, and many other fields, as it can affect the behavior and properties of substances and reactions.
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Part D
Now predict the shape of a graph that shows velocity in the x direction (v) versus time
The shape of a graph that shows the velocity in the x direction (v) versus time when the object is accelerating in the x direction would be a curve with a non-zero slope.
What is the velocity of a body?The rate at which an object's displacement changes in relation to a frame of reference is its velocity. The direction of the movement of the body or the object is defined by its velocity.
According to the equation v = s/t, velocity (v) is a vector quantity that quantifies displacement (or change in position, s), over the change in time (t).
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Answer: I expect a horizontal line (slope 0). As time increases, the velocity in the x direction stays about the same.
Explanation: Edmentum sample answer
2.50 g of As2O3 are titrated with 38.5 mL of KMnO4 to reach the end point.
5As2O3(s)+4MnO−4(aq)+9H2O(l)+12H+(aq)⟶10H3AsO4(aq)+4Mn2+(aq)
Calculate the concentration of the KMnO4 solution.
50 g of As[tex]_2[/tex]O[tex]_3[/tex] are titrated with 38.5 mL of KMnO[tex]_4[/tex] to reach the end point. 0.26M is the concentration of the KMnO[tex]_4[/tex] solution.
Concentration in chemistry refers to the quantity of a material in a certain area. The ratio of the solute within a solution to the solvent or whole solution is another way to define concentration. In order to express concentration, mass in unit volume is typically used.
The solute concentration can, however, alternatively be stated in moles or volumetric units. Concentration may be expressed as per unit mass rather than volume.
5As[tex]_2[/tex]O[tex]_3[/tex](s)+4MnO[tex]_4[/tex]⁻(aq)+9H[tex]_2[/tex]O(l)+12H⁺(aq)⟶10H[tex]_3[/tex]AsO[tex]_4[/tex](aq)+4Mn[tex]_2[/tex]⁺(aq)
the stoichiometry ratio between As[tex]_2[/tex]O[tex]_3[/tex] and MnO[tex]_4[/tex]⁻ is 5:4
0.0126 moles of As[tex]_2[/tex]O[tex]_3[/tex] will react with 4/5×0.0126 moles = 0.01008moles
0.01008moles of MnO[tex]_4[/tex]⁻ is present in 38mL
concentration of KMnO[tex]_4[/tex]= moles×volume
= 0.010/38×1000
=0.26M
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What is the answer to this?
3. What is the percentage composition of Ba(NO3)2?
(Find the mass percent of each element.)
Ba(NO₃)₂ has the following percentage composition: 52.6% Ba, 10.7% N, and 36.7% O.
How to calculate percentage composition?The molar mass of Ba(NO₃)₂ is:
Ba: 1 x 137.33 g/mol = 137.33 g/mol
N: 2 x 14.01 g/mol = 28.02 g/mol
O: 6 x 16.00 g/mol = 96.00 g/mol
Adding these up gives us a total molar mass of 261.35 g/mol.
The mass percent of each element is then:
Ba: (137.33 g/mol / 261.35 g/mol) x 100% = 52.6%
N: (28.02 g/mol / 261.35 g/mol) x 100% = 10.7%
O: (96.00 g/mol / 261.35 g/mol) x 100% = 36.7%
Therefore, the percentage composition of Ba(NO₃)₂ is: 52.6% Ba, 10.7% N, and 36.7% O.
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If you have 155 mL solution of a 0.762 M FeCIs solution, how many grams of FeCIs are contained in this sample?
What is the mass in grams of KBr in 0.400 L of a 0.350 M solution?
1. The mass (in grams) of FeCl₂ contained in the sample is 14.96 grams
2. The mass (in grams) of KBr present in the solution is 16.66 grams
How do i determine the mass present?1. The mass of FeCl₂ contained in the sample can be obtained as shown below:
First, we shall obtain the mole
Volume = 155 mL = 155 / 1000 = 0.155 LMolarity = 0.762 MMole of FeCl₂ =?Mole = molarity × volume
Mole of FeCl₂ = 0.762 × 0.155
Mole of FeCl₂ = 0.118 mole
Finally, we shall determine the mass of FeCl₂ present in the sample. Details below:
Mole of FeCl₂ = 0.118 moleMolar mass of FeCl₂ = 126.75 g/molMass of FeCl₂ = ?Mass = Mole × molar mass
Mass of FeCl₂ = 0.118 × 126.75
Mass of FeCl₂ = 14.96 grams
2. The mass of KBr present in the solution can be obtained as shown below:
First, we shall obtain the mole
Volume = 0.4 LMolarity = 0.350 MMole of KBr =?Mole = molarity × volume
Mole of KBr = 0.350 × 0.4
Mole of KBr = 0.14 mole
Finally, we shall determine the mass of KBr in the solution. Details below:
Mole of KBr = 0.14 moleMolar mass of KBr = 119 g/molMass of KBr = ?Mass = Mole × molar mass
Mass of KBr = 0.14 × 119
Mass of KBr = 16.66 grams
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Adding 1.64 g of naphthalene to 80.00 g of cyclohexane, C.H₁2() lowers the freezing point from
5.53°C to 1.37°C. If K, for cyclohexane is 19.9°C/m, calculate the molar mass of the naphthalene.
A cycloalkane with the chemical formula C6H12 is cyclohexane. Non-polar describes cyclohexane.
Thus, Colorless and combustible, cyclohexane has a characteristic detergent-like stench that is reminiscent of cleaning products.
The industrial manufacturing of adipic acid and caprolactam, which are building blocks for nylon, uses cyclohexane primarily.
cyclohexanone and cyclohexanol that serves as the starting point for the production of adipic acid and caprolactam, which are both precursors to nylon. Annual production of cyclohexanone and cyclohexanol totals several million kilos.
Thus, A cycloalkane with the chemical formula C6H12 is cyclohexane. Non-polar describes cyclohexane.
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5. What is the mass of nitrogen in 125 g NH3? (find % composition first!)
The mass of nitrogen in 125 g NH3 is 102.9375g
Showing the calculation of mass in a chemical equationTo start by finding the percentage composition of nitrogen in NH3, we find the molar mass of NH3:
1N + 3H = 1(14) + 3(1) = 14 + 3 = 17g/mol
The percent composition of nitrogen in NH3 is:
mass of nitrogen in 1 mol NH3 / molar mass of NH3 x 100%
= (14/17 )x 100
= 82.35%
So, 82.35% of the mass of NH3 comes from nitrogen.
To find the mass of nitrogen in 125 g NH3, we can set up a proportion:
mass of nitrogen / 125 g NH3 = 82.35 / 100
mass of nitrogen = (125 g NH3) x (82.35 / 100)
mass of nitrogen = 102.9375 g
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I WILL GIVE 35 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS PLEASE
The number of mole of Ba₃(PO₄)₂ produced from 3.54 L of 0.373 M BaCl₂ is 0.44 mole
How do i determine the mole of Ba₃(PO₄)₂ produced?We'll begin our calculation by obtaining the mole of BaCl₂ in 3.54 L of 0.373 M BaCl₂. This is shown below:
Volume = 3.54 LMolarity = 0.373 MMole of BaCl₂ =?Mole = molarity × volume
Mole of BaCl₂ = 0.373 × 3.54
Mole of BaCl₂ = 1.32 mole
Finally, we can determine the number of mole of Ba₃(PO₄)₂ produced from the reaction. This is illustrated below:
Balanced equation for the reaction:
3BaCl₂ + 2H₃PO₄ -> Ba₃(PO₄)₂ + 6HCl
From the balanced equation above,
3 moles of BaCl₂ reacted to produce 1 mole of Ba₃(PO₄)₂
Therefore,
1.32 mole of BaCl₂ will react to produce = 1.32 / 3 = 0.44 mole of Ba₃(PO₄)₂
Thus, we can conclude from the calculation made above that the number of mole of Ba₃(PO₄)₂ produced is 0.44 mole
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please answer the questions in the picture
If 5.34 g of tricarbon octahydride reacts with 25.2 g of oxygen gas, the limiting reactant is tricarbon octahydride.
8.72168 grams of water is produced.
5.84 grams of excess reactant is left over after the reaction is complete.
The percent yield of water, if 6.98 g of water is actually produced in a laboratory experiment is 80.0459 %.
What is the equation of the combustion reaction?The equation of the combustion reaction is given below:
C₃H₈ + 5 O₂ -----> 3 CO₂ + 4 H₂O
molar masses:
tricarbon octahydride: 44.11 g/mol
oxygen gas: 32 g/mol
water: 18.02 g/mol
carbon dioxide: 44.01 g/mol
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consider the combustion of carbon monoxide in oxygen gas.2CO(g)+O2(g)=2CO2(g).In this reaction 10.8 moles of carbon dioxide was produced. Calculate the number of moles of carbon monoxide used in this reaction to produce such number of moles of carbon dioxide.
In this reaction 10.8 moles of carbon dioxide was produced. 10.8moles of carbon monoxide used in this reaction to produce such number of moles of carbon dioxide.
In chemistry, a mole, usually spelt mol, is a common scientific measurement unit for significant amounts of very small objects like molecules, atoms, or other predetermined particles. The mole designates 6.02214076 1023 units, which is a very large number.
For the Worldwide System of Units (SI), the mole is defined as this number as of May 20, 2019, according to the General Convention on Measurements and Weights. The total amount of atoms discovered through experimentation to be present in 12 grammes of carbon-12 was originally used to define the mole.
2CO(g)+O[tex]_2[/tex](g)=2CO[tex]_2[/tex](g)
moles of carbon dioxide= 10.8 moles
According to stoichiometry
moles of carbon monoxide= (2/2)× 10.8 =10.8moles.
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Calculate the volume in mL of 0.567 M Ca(OH)2 needed to neutralize 42.8 mL of 0.490 M H3PO4 in a titration.
The volume in mL of 0.567 M Ca(OH)₂ needed to neutralize 42.8 mL of 0.490 M H₃PO₄ in a titration is 36.98ml.
A neutralization reaction can be defined as a chemical reaction in which an acid and base quantitatively react together to form a salt and water as products.
In a reaction to water, neutralization results in excess hydrogen or hydroxide ions present in the solution. The pH of the neutralized solution depends on the strength of the acid or base involved in it.
Given,
Concentration of calcium hydroxide = 0.567M
Volume of phosphoric acid = 42.8 moles
Concentration of phosphoric acid = 0.49M
During neutralization, the number of moles of acid and base remain same,
M₁V₁ = M₂ V₂
i.e. Moles of acid = moles of base
0.49 × 42.8 = 0.567 × V₂
V₂ = 36.98 ml
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Calculate the volume in mL of 0.600 M NaCl solution that contains 0.00123 moles of NaCl
Answer:
2.05 mL
Explanation:
Hope this helps :)
In addition to pH meter, what other methods and/or experimental devices may be used to determine the Ksp values of sparingly soluble electrolytes? Please give at least three examples.
What factor(s) may change Ksp values? Please elaborate your answer.
According to the solubility of of sparingly soluble electrolytes by conductometer and potentiometer.
Solubility is defined as the ability of a substance which is basically solute to form a solution with another substance. There is an extent to which a substance is soluble in a particular solvent. This is generally measured as the concentration of a solute present in a saturated solution.
The solubility mainly depends on the composition of solute and solvent ,its pH and presence of other dissolved substance. It is also dependent on temperature and pressure which is maintained.It can also be determined for electrolytes.
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Readiness Test: Populations, Communities, and Ecosystems
The structure of an ecosystem is characterized by the organization of both biotic and abiotic components. The reduction of the resources decrease the population of a species. The correct option is A.
An ecosystem is defined as the structural and functional unit of ecology in which the living organisms interact with each other and the surrounding environment. The living components of the ecosystem are called biotic components and the non-living components are called abiotic components.
In short, raw material extraction can adversely affect the environment, biodiversity loss, damage to ecosystem functions and global warming.
Thus the correct option is A.
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will the product of KOH + FeCl3 form precipitate
Answer:
The reaction between ferric chloride and potassium hydroxide leads to the formation of ferric hydroxide and potassium. It is a precipitation reaction in which ferric and hydroxide ion on reaction with each other results in the formation of ferric hydroxide as reddish-brown precipitate.
Thank you in advance.
The rate expression is k [BF₃]²[NH₃], overall order is 3, rate constant k is 1.13 × 10⁻³ mol⁻² dm⁶ s⁻¹.
How to calculate rate expression?The rate expression for this reaction can be written as:
Rate = k [BF₃]^m[NH₃]^n
The method of initial rates can be used to calculate the values of m and n. When we compare experiments 1 and 2, notice that halving the concentration of [NH3] reduces the initial rate of reaction. This suggests that the reaction is first order in terms of [NH3], implying that n = 1.
When comparing experiments 1 and 3, notice that increasing the concentration of [BF3] by a factor of 2.5 increases the initial rate of reaction by a factor of 9.39 (i.e., 2.13/0.227). This shows that the reaction is about second order in relation to [BF3], i.e., m 2.
Therefore, the rate expression for the reaction is:
Rate = k [BF₃]²[NH₃]
The overall order of the reaction is m + n = 3.
Using the data from experiment 4, substitute the values and solve for k:
Rate = k [BF₃]²[NH₃]
1.02 × 10-¹ = k (3.00 × 10⁻¹)² (1.00 x 10⁻¹)
k = 1.02 × 10-¹ / (3.00 × 10⁻¹)² (1.00 x 10⁻¹)
k = 1.13 × 10⁻³ mol⁻² dm⁶ s⁻¹
Therefore, the rate constant k is 1.13 × 10⁻³ mol⁻² dm⁶ s⁻¹.
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Cellular respiration is a chemical process in cells that releases energy the cells need to function. What statement below is true about this reaction.
A. The process of cellular respiration releases energy because the energy that is released when the bonds are formed in CO2 and water is equal to the energy required to break the bonds of sugar and oxygen.
B. The process of cellular respiration releases energy because the energy that is released when the bonds that are formed in CO2 and water is lost when bonds of glucose and oxygen are broken.
C. The process of cellular respiration releases energy because the energy that is released when the bonds are formed in CO2 and water is less than the energy required to break the bonds of sugar and oxygen.
D. The process of cellular respiration releases energy because the energy that is released when the bonds are formed in CO2 and water is greater than the energy required to break the bonds of sugar and oxygen.
The process of cellular respiration releases energy because the energy that is released when the bonds are formed in CO[tex]_2[/tex] and water is equal to the energy required to break the bonds of sugar and oxygen. Therefore, the correct option is option A.
Cells turn sugars into energy through a process called cellular respiration. Cells need fuel or an electron acceptor to power the chemical process that converts energy into usable forms such as ATP along with additional kinds of energy that can be utilised to power cellular reactions.
All multicellular species, including eukaryotes, as well as certain single-celled organisms, generate energy by aerobic respiration. Utilising oxygen, which is the strongest electron acceptor found in nature, is called aerobic respiration. The process of cellular respiration releases energy because the energy that is released when the bonds are formed in CO[tex]_2[/tex] and water is equal to the energy required to break the bonds of sugar and oxygen.
Therefore, the correct option is option A.
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 If you mixed three plastic cup's contents containing 0,05 L of 1M Kool-Aid, 0.05 L of 2.5M Kool-Aid, and 0.05 L of 0.5M Kool-Aid, what would the molarity be of the resulting solution?
M = 1.183
Molarity is moles/Liter, so setting up some equations gives you
1) 1M = Xmol/0.05L
2) 2.5M = Xmol/0.05L
3) 0.5M = Xmol/0.05L
Solve for each X
1) X = 0.05mol
2) X = 0.125mol
3) X = 0.0025mol
Now add all the moles and Liters (separately)
XM = (0.05+0.125+0.0025)mol/(0.05+0.05+0.05)L
XM = 0.1775mol/0.15L
X = 1.183M
What mass of oxygen gas, O2, from the air is consumed in the combustion of 702 g of octane, C8H18, one of the principal components of gasoline?
Select one:
A. 13.22 g
O B. 25.0 g/mol
O C. 32.0 g
O D. 33.22 g/mol
O E. 39.0 g
The principal components of gasoline is 702 g of octane.
Thus, Crude oil and other petroleum liquids are used to create gasoline, a fuel. The majority of gasoline is utilized in car engines.
For retail sale at gas stations, finished motor gasoline is produced at petroleum refineries and blending facilities.
In order to create finished motor gasoline, petroleum refineries primarily produce gasoline blendstocks, which must be blended with other liquids. In order to create finished motor gasoline in various grades and formulas, gasoline blendstocks, finished gasoline, and fuel ethanol are combined at blending terminals.
Thus, The principal components of gasoline is 702 g of octane.
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Balance equation Pb(C2H3O2)2 + CO2 + H2O= PbCO3 + HC2H3O2
The balanced equation is: Pb(C2H3O2)2 + CO2 + H2O → PbCO3 + 2 HC2H3O2
Balancing chemical equationsIn a balanced chemical equation, the number of atoms of each element is the same on both sides of the equation. Thus, the balanced equation of the reaction is:
Pb(C2H3O2)2 + CO2 + H2O → PbCO3 + 2 HC2H3O2
The coefficients used to balance the equation are:
1 Pb(C2H3O2)2 + 1 CO2 + 1 H2O → 1 PbCO3 + 2 HC2H3O2
After balancing the equation, we can see that one molecule of lead(II) acetate reacts with one molecule of carbon dioxide and one molecule of water to produce one molecule of lead(II) carbonate and two molecules of acetic acid.
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A mixture of He , Ar , and Xe has a total pressure of 2.10 atm . The partial pressure of He is 0.250 atm , and the partial pressure of Ar is 0.300 atm . What is the partial pressure of Xe ? Express your answer to three significant figures and include the appropriate units.
The partial pressure of the gas in a mixture is the pressure that the gas would exert if present alone in the vessel at the same temperature as that of the mixture. Here the partial pressure of Xe is
The pressure exerted by a mixture of two or more non-reacting gases enclosed in a definite volume is equal to the sum of the partial pressures of the component gases.
According to Dalton's law of partial pressures, total pressure is:
P = p₁ + p₂ + ...
2.10 = 0.250 + 0.300 + p
p = 1.55
Partial pressure of Xe = 1.55
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5. How many moles of NaCl are in a 500mL solution with a concentration of 0.66M?
How many grams of SrCl₂ are in a 768mL solution with a concentration of 0.978M?
What is the volume of a solution with 500grams of CaBr, and a concentration of 0.879M?
How many molecules of MgCl₂ are in a 759mL solution with a concentration of 0.99M?
How many milligrams of LiCI are in a 999mL solution with a concentration of 0.951M?
How many kilograms of KCI are in a 1556mL solution with a concentration of 1.23M?
6.
7.
8.
9.
0.
Cacl₂?
hp
5.1 g sodium carbonate solution was dissolved in water to make 500cm³ of solution.20cm³ of this solution was tirated against 20.45 cm³ of 0.04M hydrochloric acid . Calculate the % of purity of the sodium carbonate solid
Answer:
We know that, Va= 20.45 cm³, Vs= 20 cm³, Ma= 0.04M . But molar mass of Na₂CO₃ = 106. So, concentration (g/dm³) = 0.02045 × 106 = 2.1677 g/dm³. Hence, The percentage purity of the sodium carbonate solid is 21.25%.
Four friends were playing on the playground. They began to question where
all organisms get energy from. Here are their thoughts:
Brock:
Malik:
Kira:
Sydney:
I think that the main source of energy for most life is food.
I think that the main source of energy for most life is water.
I think that the main source of energy for most life is the Sun.
I think that most organisms make their own energy.
Circle the friend you most agree with. Explain why you agree with that person.
The friend I agree with the most is Kira because all living organisms directly or indirectly depend on the sun for their energy.
Source of energy for living organismsKira is the one who is right because the main source of energy for most life on Earth is indeed the Sun.
Photosynthesis is the process by which plants, algae, and some bacteria convert sunlight into chemical energy, which is then used to fuel cellular processes.
Even organisms that do not photosynthesize directly, such as animals, ultimately rely on the Sun's energy because they consume plants or other organisms that do.
While food and water are important for sustaining life, they are ultimately derived from the energy captured by photosynthetic organisms from the Sun.
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Who has course hero?I really need the “lion king…Ecology science.” Answer key so I can print it.It wont let me print mines.
Note that the above prompt on Ecology draws it's analysis form a well known story which have been told visually called "The Lion King".
The answers are:
1) Biotic Factors, simply put are living things
2 examples of things from Lion King Introduction are:
3) Abiotic factors are Non -living things.
4) Examples from the introduction are:
MountainWaterDirt5) the symbiotic relationship is called: commensalism.
What is commensalism?Long-term biological interactions known as commensalism occur when individuals of one species benefit while those of the other species suffer neither advantages nor harm.
Ecology which is the study of the environment, allows a person to comprehend how different types of creatures coexist in various kinds of physical settings.
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Full Question:
Although part of your question is missing, you might be referring to this full question:
1) What is Biotic Factors
2) List three biotic factors from the Lion King introduction
3) What is Abiotic factors?
4) List three Abiotic factors from the Lion King introduction
5) The bird riding on the tusks of the elephant feed on insects the elephant stirs up. What kind of symbiotic relationship exists between the two?
2. Label the different layers of the atmosphere and the separating boundaries between each layer.
The layers of the atmosphere with the boundaries that are between them are shown in the image attached here.
Layers of the atmosphereThe troposphere, which rises up to an altitude of roughly 10-15 km, is the layer that is closest to the Earth's surface. The majority of the Earth's air mass is contained here, which is also where weather happens.
The tropopause marks the transition from the troposphere to the stratosphere, the next layer. It designates the altitude at which the temperature stops dropping.
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