confidence interavls for a population proportion. suppose that a random sample of 1000 mortgage loans that were defaulted within the first year reveals 410 of these loans were approved on hte basis of falsified applications. what is point estiamte of and a 95% confidence interval for p, the proportion of all first year defaults that are approved on the basis of flsified application

Answer:

32 one-dollar bills.

Step-by-step explanation:

Let x represent one-dollar bills and y represent two-dollar bills.

He has a total of 49 bills. Therefore:

[tex]x+y=49[/tex]

The total amount of money James has is 66. x is worth one dollar, while y is worth two dollars. Therefore:

[tex]1x+2y=66\\x+2y=66[/tex]

We have a system of equations. Solve by substitution:

[tex]x+2y=66\\x+y=49\\x=49-y\\(49-y)+2y=66\\y=17\\x=49-17=32[/tex]

Therefore, James has 32 one-dollar bills and 17 two-dollar bills.

Checking:

[tex]32(1)+17(2)\stackrel{?}{=}66\\32(1)+17(2)\stackrel{\checkmark}{=}66\\\\32+17\stackrel{?}{=}49\\49\stackrel{\checkmark}{=}49[/tex]

Answer:

The "square root spiral," donned the "Spiral of Theodorus" was created by Theodorus to visualize a set of 17 isosceles triangles where [tex]n[/tex] is equal to a value between one and seventeen.

I have attached an image of the Square Root spiral below.

Answer:

a

  [tex]df = 24.32[/tex]

b

 [tex]df = 30.10[/tex]

c

 [tex]df = 30.7[/tex]

d

[tex]df = 25.5[/tex]

Step-by-step explanation:

Generally degree of freedom is mathematically represented as

          [tex]df = \frac{ [\frac{ s^2_i }{m} + \frac{ s^2_j }{n} ]^2 }{ \frac{ [ \frac{s^2_i}{m} ]^2 }{m-1 } +\frac{ [ \frac{s^2_j}{n} ]^2 }{n-1 } }[/tex]

Considering a

         a) m = 12, n = 15, s1 = 4.0, s2 = 6.0

           [tex]df = \frac{ [\frac{ 4^2 }{12} + \frac{ 6^2 }{15} ]^2 }{ \frac{ [ \frac{4^2}{12} ]^2 }{12-1 } +\frac{ [ \frac{6^2}{15} ]^2 }{15-1 } }[/tex]

         [tex]df = 24.32[/tex]

Considering b

       (b) m = 12, n = 21, s1 = 4.0, s2 = 6.0

          [tex]df = \frac{ [\frac{ 4^2 }{12} + \frac{ 6^2 }{21} ]^2 }{ \frac{ [ \frac{4^4}{12} ]^2 }{12-1 } +\frac{ [ \frac{6^2}{21} ]^2 }{21-1 } }[/tex]

        [tex]df = 30.10[/tex]

Considering c

      (c) m = 12, n = 21, s1 = 3.0, s2 = 6.0

           [tex]df = \frac{ [\frac{ 3^2 }{12} + \frac{ 6^2 }{21} ]^2 }{ \frac{ [ \frac{3^4}{12} ]^2 }{12-1 } +\frac{ [ \frac{6^2}{21} ]^2 }{21-1 } }[/tex]

           [tex]df = 30.7[/tex]

Considering c

        (d) m = 10, n = 24, s1 = 4.0, s2 = 6.0

                [tex]df = \frac{ [\frac{ 4^2 }{10} + \frac{ 6^2 }{24} ]^2 }{ \frac{ [ \frac{4^2}{10} ]^2 }{10-1 } +\frac{ [ \frac{6^2}{24} ]^2 }{24-1 } }[/tex]

               [tex]df = 25.5[/tex]

Answer:

Step-by-step explanation:

[tex]12-8x=5\\\\Collect\:like\:terms\\\\-8x =5-12\\\\-8x = -7\\\\Divide\:both\:sides\:by -8\\\frac{-8x}{-8} \\=\frac{-7}{-8} \\\\x = 0.875\\\\x = 0.88[/tex]

Answer:

14 mi

Step-by-step explanation:

Cedarburg is 22 13/16 miles from Allenville and 8 13/16 miles from Lakeside.  You have to solve for the distance from Lakeside to Allenville.

8 13/16  +  x  =  22 13/16

(8 13/16  +  x)  -  8 13/16  =  22 13/16  -  8 13/16

x  =  14

The distance from Lakeside to Allenville is 14 miles.

Answer:

The value of x is 30°

Step-by-step explanation:

We are given that the outer angle of the parallelogram is 60 degrees. Therefore it's respective inner angle will be 180 - 60 = 120 degrees. And, by properties of a parallelogram, the angle opposite to this angle will be 120 degrees as well.

If we draw extend the line creating angle 2x, then we will make ( 1 ) a vertical angle to 2x, ( 2 ) a 90 degree angle, and ( 3 ) and angle that we can let be y. Therefore, 2x + y = 90, and 3x + y = 120.

[tex]\begin{bmatrix}2x+y=90\\ 3x+y=120\end{bmatrix}[/tex] ,

[tex]\begin{bmatrix}6x+3y=270\\ 6x+2y=240\end{bmatrix}[/tex] ,

[tex]6x+2y=240\\-\\\underline{6x+3y=270}\\y=30[/tex],  

[tex]2x + (30) = 90,\\2x = 60,\\x = 30[/tex]

Solution : x = 30°

Answer:

x = 30

Step-by-step explanation:

a+ 60 = 180

a = 120

3x+b = 120  because opposite angles in a parallelogram are equal

2x+90+b = 180 since it forms a line

2x+b = 90

We have 2 equations and 2 unknowns

3x+b = 120

2x+b = 90

Subtracting

3x+b = 120

-2x-b = -90

---------------------

x = 30

Answer:

13

Step-by-step explanation:

A)5+5=10

B)5+7=12

C) impossible

D)7+7=14

E)5+5+5=15

Answer:

vol = 17,148 cu. in.

Step-by-step explanation:

vol = 4 / 3 * pi * r³

vol = 4 / 3 *3.14 * 16³

vol = 17,148 cu. in.

Answer:

The answer is

Step-by-step explanation:

Volume of a sphere is given by

[tex]V = \frac{4}{3} \pi {r}^{3} [/tex]

where r is the radius of the sphere

π = 3.14

From the question

r = 16 inches

Volume of the sphere is

[tex]V = \frac{4}{3} (3.14) {16}^{3} [/tex]

V = 17148.586

We have the final answer as

V = 17149 cubic inches to the nearest cubic inch

Hope this helps you

Answer:

(0,2)

Step-by-step explanation:

the point where Oy intercepts the graph has x=0 and y= f(0)

so this is (0,2)

━━━━━━━☆☆━━━━━━━

▹ Answer

80%

▹ Step-by-Step Explanation

20/25 = 0.8 → 80%

Hope this helps!

CloutAnswers ❁

━━━━━━━☆☆━━━━━━━

Answer:

2.7 in²

Step-by-step explanation:

Since ∆BAC and ∆EDF are similar, therefore, the ratio of their area = square of the ratio of their corresponding side lengths.

Thus, if area of ∆EDF = x, area of ∆BAC = 6 in², EF = 2 in, BC = 3 in, therefore:

[tex] \frac{6}{x} = (\frac{3}{2})^2 [/tex]

[tex] \frac{6}{x} = (1.5)^2 [/tex]

[tex] \frac{6}{x} = 2.25 [/tex]

[tex] \frac{6}{x}*x = 2.25*x [/tex]

[tex] 6 = 2.25x [/tex]

[tex] \frac{6}{2.25} = \frac{2.25x}{2.25} [/tex]

[tex] 2.67 = x [/tex]

[tex] x = 2.7 in^2 [/tex] (nearest tenth)

Answer:

(-1,-4)

Step-by-step explanation:

The equation of a parabola os written as: ax^2+bx+c

This parabola's equation is x^2+2x-3

● a= 1

● b= 2

● c = -3

The coordinates of the parabola are: ( (-b/2a) ; f(-b/2a) )

● -b/2a = -2/2 = -1

● f(-b/2a) = (-1)^2+2×(-1)-3=1-2-3= -4

So the vertex coordinates are (-1,-4)

Answer:

-1+2X

Step-by-step explanation:

Answer:

well all of these look like a way so we have to use elimination method

A : random number tables : well it has random numbers so X out

B: PHONE NUMBERS: well phone numbers are random so X out

C: USing the internet : totally X out

D: books of random numbers: X out

so none of the above i guess

The only way that might not be used in generating random numbers is : (B). using phone numbers selected at random in a local phone book

Random numbers are numbers that occurs randomly without prediction. these numbers are impossible to predict using past values.

Random numbers are important for computer encryption and lotteries.

In conclusion, The only way that might not be used in generating random numbers is using phone numbers selected at random in a local phone book

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Answer:

The correct option is B.

Step-by-step explanation:

The hypothesis to determine whether the vending machines are properly dispensing 12 ounces of coffee is:

H₀: [tex]\mu_{A}=\mu_{B}=\mu_{C}[/tex]

Hₐ: Not all means are equal.

The ANOVA output is as follows:

One-way ANOVA: Machine A, Machine B, Machine C

Source           DF              SS                MS              F              P

Factor              2            8.363           4.182         31.73       0.000

Error               15             1.977            0.132

Total               17           10.340

The significance level is α = 0.05.

The p-value of the model is:

p-value = 0.000

Decision rule:

If the p-value of the test is less than the significance level then the null hypothesis will be rejected.

p-value = 0.000 < α = 0.05

The null hypothesis will be rejected.

Conclusion:

There is a significant difference between the means.

Thus, the correct option is B.

Answer:

Graph 2

Step-by-step explanation:

The equation x = t² - 3 is represented by exponential growth, ( t² ) so it's graph will be similar to the first graph, graph 1, in our options. Then again we have to consider the equation y = √t - 2, which will be similar to graph 4, but with a greater slope. This leaves us with a solution of graph b.

Answer:

  2700 years

Step-by-step explanation:

The exponential function for the fraction remaining is ...

  r(t) = (1/2)^(t/5730)

where r is the remaining fraction and t is the time in years. We can solve for t to get ...

  log(r) = (t/5730)log(1/2)

  t = 5730·log(r)/log(1/2)

For the given r=0.72, the age of the artifact is estimated to be ...

  t = 5730·log(0.72)/log(0.5) ≈ 2700 . . . years

Answer:

The correct answer is:

c. Joe will go running, biking and hunting

Step-by-step explanation:

Parallel construction or parallelism or parallel structure is a style used in writing a sentence, where there is a balance in phrases or clauses within one or more sentences by them having the same grammatical structure. parallelism adds elegance, clarity and symmetry to sentences. It essentially has to so with a repetition of a chosen grammatical form within a sentence.

In our example:

a.  Jim likes to hunt, bike, and throwing darts. (not parallel)

    Jim likes to hunt, bike, and throw darts (parallel)

The verbs, hunt, bike and throw must be in the same form (present continuous) to be parallel

b. Mimie has to study, drive her sister to the store, and enjoy herself in the garden. (not parallel).

The sentence in option b is not parallel because the other actions apart from "study" have a place where they took place; drive her sister to the store, enjoy herself in the garden, however, "study" doesn't have a place where the action occurs.

c. Jane will throw a ball, then she will mow the lawn. (not parallel)

the sentence is not parallel because there is an inconsistency in the pattern of the construct. a parallel version is:

Jane will first throw a ball, then she will mow the lawn, or

jane will throw a ball and mow the lawn.

d. Joe will go running, biking, and hunting. (parallel)

all the verbs are in the present continuous form.

Here is the complete question:

a. Statistically significant at 0.01

b. Not statistically significant

Answer:

The test is significant

Step-by-step explanation:

When a p value is smaller than or less than alpha we say it is statistically significant.

We are testing the p value or likelihood of 0005 against a significant level of 0.01

P value = 0.005 < 0.01

0.005 is less than 0.01 which shows the test to be significant.

The decision rule would be to reject the null hypothesis and say the result is statistically significant.

Answer:

I dont Know

Step-by-step explanation:

Answer:

54°

Step-by-step explanation:

Let ∠CYX=x

AB║CD

∠AXE=∠CYX  (corresponding angles)

∠AXE=3∠CYX-108

x=3x-108

3x-x=108

2x=108

x=108/2=54°

∠AXE=∠CYX=x=54°

∠BXY=∠AXE=54° (Vertically opposite angles)

Answer:

Diameter of wheel in millimetres is 660.4

Step-by-step explanation:

Diameter of wheel in inches = 26

given

1 inch = 25.4 millimeters

multiplying RHS and LHS by 26

26*1 inch = 26*25.4 millimeters

=>26 inch = 660.4 mm.

Thus, diameter of wheel in millimetres is 660.4

An old campfire is uncovered during an archaeological dig. Its charcoal is found to contain less than 1/1000 the normal amount of [tex]^{14}\text{C}[/tex] ​. Estimate the minimum age of the charcoal, noting that  [tex]2^{10} = 1024[/tex]

Answer:

57300 years

Step-by-step explanation:

Using the relation of an half-life time in relation to fraction which can be  expressed as:

[tex]\dfrac{N}{N_o} = (\dfrac{1}{2})^{\frac{t}{t_{1/2}}[/tex]

here;

N represents the present atom

[tex]N_o[/tex] represents the  initial atom

t represents the time

[tex]t_{1/2}[/tex] represents the half - life

Given that:

Its charcoal is found to contain less than 1/1000 the normal amount of [tex]^{14}\text{C}[/tex] ​.

Then ;

[tex]\dfrac{N}{N_o} = \dfrac{1}{1000}[/tex]

However; we are to  estimate the minimum age of the charcoal, noting that  [tex]2^{10} = 1024[/tex]

so noting that [tex]2^{10} = 1024[/tex], then:

[tex]\dfrac{1}{1000}> \dfrac{1}{1024}[/tex]

[tex]\dfrac{1}{1000}> \dfrac{1}{2^{10}}[/tex]

[tex]\dfrac{1}{1000}> (\dfrac{1}{2})^{10}[/tex]

If

[tex]\dfrac{N}{N_o} = \dfrac{1}{1000}[/tex]

Then

[tex]\dfrac{N}{N_o} > (\dfrac{1}{2})^{10}[/tex]

Therefore, the estimate of the minimum time needed is 10 half-life time.

For [tex]^{14}\text{C}[/tex] , the normal half-life time = 5730 years

As such , the estimate of the minimum age of the charcoal =  5730 years × 10

= 57300 years

Step-by-step explanation:

First we need to find out what they all 3 equal, with multiplication.

5×5=25

10×5=50

20×5=100

In each of these problems, the answer is multiplying itself by 2 in order to get to the next answer. So this is how they are related

Answer:

12 units

Step-by-step explanation:

Since all of the sides of a rhombus are congruent, JK = JM which means:

2x + 4 = 3x

-x = -4

x = 4 so 3x = 3 * 4 = 12

Answer:

There is no sufficient evidence to support the claim

Step-by-step explanation:

From the question we are told that

     The level of significance is  [tex]\alpha = 0.05[/tex]

     The  sample proportion is  [tex]\r p = 0.08[/tex]

     The  sample size is  [tex]n = 250[/tex]

Generally for normal sampling distribution can  be used

     [tex]n * p > 5[/tex]

So  

     [tex]n* p = 250 * 0.12 = 30[/tex]

Since  

     [tex]n * p > 5[/tex] then  normal sampling distribution can  be used

The null hypothesis is  [tex]H_o : p = 0.12[/tex]

  The alternative hypothesis is  [tex]H_a : p > 0.12[/tex]

The  test statistic is evaluated as

            [tex]t = \frac{\r p - p }{ \sqrt{ \frac{p(1- p)}{n} } }[/tex]

substituting values

            [tex]t = \frac{0.08 - 0.12 }{ \sqrt{ \frac{0.12 (1- 0.12)}{250 } } }[/tex]

            [tex]t = -1.946[/tex]

The  p-value is obtained from the z  table and the value is

        [tex]p-value = P(t > -1.9462) =0.97512[/tex]

Since the [tex]p-value > \alpha[/tex]

    Then we fail to reject the null hypothesis

Hence it means there is no sufficient evidence to support the claim

Answer: It's B

Step-by-step explanation:

The table that represents the double number line is (b)

On the double number line, we have the following points

x: 0    1

y: 0    25

This means that as x increases by 1, y increases by 25.

So, we have:

x: 0  1    2    3   4

y: 0 25  50 75 100

The above is represented by the second table

Hence, the table that represents the double number line is (b)

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By the fundamental theorem of calculus,

[tex]E(t)=E(1)+\displaystyle\int_1^t E'(u)\,\mathrm du[/tex]

So we have

[tex]E(t)=92+\displaystyle\int_1^t(75-6u)\,\mathrm du[/tex]

[tex]E(t)=92+(75u-3u^2)\bigg|_1^t[/tex]

[tex]E(t)=20 + 75 t - 3 t^2[/tex]

Hector outperformed the challenge rate as he exercised 2.88 hours a week.

It is best to convert the mixed fraction to decimals for easier calculation.

The students are encouraged to exercise 2¹/₂ hours per week. In decimals this is:

= 2 + ¹/₂

= 2 + 0.5

= 2.5 hours per week

In the 4 week period, Hector exercised 11¹/₂ hours which is:

= 11 + ¹/₂

= 11 + 0.5

= 11.5 hours

The number of hours he exercised per week is:

= Number of hours in total / Number of weeks

= 11.5 / 4

= 2.88 hours per week

When compared to the fitness challenge rate, we can conclude that Hector outperformed the challenge rate

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Answer:

The answer is 2 7/8