Consider a classroom of 25 students:
(a) What is the probability that at least 2 students have the same birthday? (consider a year of 365
days, i.e., no leap year)
(b) Given that no students were born in January, recalculate the probability in the previous question.
(c) What is the probability that there is at least one student who shares the same birthday as you?

a. The mean of the sampling distribution of [tex]\bar{X}[/tex] is 75 and the standard deviation is 0.4.

b. The chance that the average score of this group of students is more than 76 is 0.0062.

c. The probability that the sample mean deviates from the population mean by less than 2 is 1.

d. The 98% confidence interval for µ is (74.07, 75.93).

(a) Mean of  [tex]\bar{X}[/tex] = μ = 75

Standard deviation of [tex]\bar{X}[/tex] = σ/√n = 4/√100 = 0.4

Therefore, the mean of the sampling distribution of [tex]\bar{X}[/tex] is 75 and the standard deviation is 0.4.

(b) z = ([tex]\bar{X}[/tex] - μ) / (σ/√n)

where [tex]\bar{X}[/tex] = 76, μ = 75, σ = 4, and n = 100.

Substituting the values, we get:

z = (76 - 75) / (4/√100) = 2.5

Using a standard normal distribution table, we can find the probability that a z-score is greater than 2.5. This probability is approximately 0.0062. As a result, the chance that the average score of this group of students is more than 76 is 0.0062.

(c) We need to calculate the z-scores for [tex]\bar{X}[/tex] = 75 + 2 = 77 and [tex]\bar{X}[/tex] = 75 - 2 = 73 using the formula:

z = ([tex]\bar{X}[/tex] - μ) / (σ/√n)

Substituting the values, we get:

z1 = (77 - 75) / (4/√100) = 5

z2 = (73 - 75) / (4/√100) = -5

Using a standard normal distribution table, we can find the probability that a z-score is between -5 and 5. This probability is approximately 1. Therefore, the probability that the sample mean deviates from the population mean by less than 2 is 1.

(d) To construct a 98% confidence interval for µ, we can use the formula:

[tex]\bar{X}[/tex] ± zα/2 (σ/√n)

where [tex]\bar{X}[/tex] = 75, σ = 4, n = 100, and zα/2 is the z-score corresponding to the 98% confidence level, which can be found using a standard normal distribution table. For a 98% confidence level, zα/2 = 2.33.

Substituting the values, we get:

75 ± 2.33 (4/√100)

Simplifying, we get:

75 ± 0.93

Therefore, the 98% confidence interval for µ is (74.07, 75.93).

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Considering a number of 100 trials, the experimental probability of heads should be close to the theoretical probability of 1/2 = 50%.

A probability is calculated as the division of the desired number of outcomes by the total number of outcomes in the context of a problem/experiment.

A fair coin is equally as likely to come up heads or tails, hence the theoretical probability of heads is given as follows:

1/2 = 0.5 = 50%.

For a large number of trials, such as 100 trials, the experimental probability is expected to be close to the theoretical probability, hence it should also be close to 50%.

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Step-by-step explanation:

The product of the form method is a technique used to factorize a quadratic expression of the form ax^2 + bx + c. Here are the steps to follow:

1. Write down the quadratic expression in the standard form ax^2 + bx + c, where a, b, and c are constants.

2. Multiply the coefficient a by the constant c to get the product ac.

3. Find two factors of ac that add up to the coefficient b. In other words, find two numbers p and q such that pq = ac and p + q = b.

4. Rewrite the quadratic expression by replacing the middle term bx with the two terms px and qx. This is done by splitting the middle term of the quadratic expression using the two numbers p and q found in step 3. So the quadratic expression becomes ax^2 + px + qx + c.

5. Factor the first two terms of the expression ax^2 + px using the greatest common factor (GCF). This gives us a(x + p/a)x + qx + c.

6. Factor the last two terms qx + c using the GCF. This gives us a(x + p/a)(x + c/q).

7. Simplify the expression by combining any like terms and check that the factors obtained in step 6 can be expanded back into the original quadratic expression.

8. Write down the factored form of the quadratic expression, which is (x + p/a)(x + c/q).

These are the steps of the product of the form method.

Since 23² is less than 12² + 20², we can conclude that the values 12, 20, and 23 do not create a right triangle.

To determine if the values 12, 20, and 23 create a right triangle, we can use the Pythagorean theorem, which states that for any right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.

So, we can calculate:

12² + 20² = 144 + 400 = 544

23² = 529

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The integral that gives the length of the parametric curve x(t) = 2t², y(t) = t, 0 ≤ t ≤ 8 is: ∫₀⁸ √(16t² + 1) dt

To find the length of the parametric curve

[tex]x(t) = 2t^2, y(t) = t, 0 ≤ t ≤ 8[/tex]

, we need to evaluate the integral:

[tex]∫√[(dx/dt)² + (dy/dt)²]dt[/tex]

where dx/dt and dy/dt are the first derivatives of x(t) and y(t) with respect to t, respectively.

Step 1: Compute dx/dt ,

[tex] dx/dt = d(2t^2)/dt = 4t dy/dt = d(t)/dt =1[/tex]

Step 2: Compute the square of the derivatives and sum them

(4t)² + (1)² = 16t² + 1

Step 3: Find the square root of the sum √(16t² + 1) Step 4: Set up the integral and evaluate it over the given interval [0, 8] Length = ∫₀⁸ √(16t² + 1) dt

Thus, the integral that gives the length of the parametric curve x(t) = 2t², y(t) = t, 0 ≤ t ≤ 8 is: ∫₀⁸ √(16t² + 1) dt

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Correct answer is "Examine the following integral gives the length of the parametric curve or not x(t) = 2t², y(t) = t, 0 ≤t≤8"

According to the question the length of arc BC is approximately 1.69 feet.

The measurement of the circle's boundaries is called as the circumference or perimeter of the circle. whereas the circumference of a circle determines the space it occupies. The circumference of a circle is its length when it is opened up and drawn as a straight line. Units like cm or unit m are typically used to measure it. The circle's radius is considered while calculating the circumference of the circle using the formula. As a result, in order to calculate the circle's perimeter, we must know the radius or diameter value.

The circumference of a circle is given by the formula[tex]$C = 2\pi r$[/tex], where $r$ is the radius of the circle. In this case, the radius is 8 feet, so the circumference of the circle is: C=16π feet.

Since the angle BAC is one-third of a radian, we know that angle BOC (the angle at the center of the circle) is twice as large, or approximately $38.2^\circ$. This is because the angle at the center of the circle is twice as large as the angle on the circumference that it intercepts.

Now we can use this angle to find the length of arc BC. The formula for the length of an arc is: L = Ф/360 *C

L = 38.2/350 * 16π = 1.69 feet.

So the length of arc BC is approximately 1.69 feet.

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a) For a one-tail test with Zx = 1.46 and a = 0.10, the area in the tail to the right of 1.46 is 0.0735. Since this is greater than 0.10, we fail to reject the null hypothesis.

b) For a one-tail test with Zx = -2.48 and a = 0.01, the area in the tail to the left of -2.48 is 0.0066. Since this is less than 0.01, we reject the null hypothesis.

c) For a two-tail test with Zx = -1.92 and a = 0.01, the area in each tail is 0.025. The total area in the tails is 0.050. Since this is greater than 0.01, we fail to reject the null hypothesis.

d) For a two-tail test with Zx = 2.76 and a = 0.02, the area in each tail is 0.01. The total area in the tails is 0.02. Since this is less than 0.02, we reject the null hypothesis.

Followings are the answers of 9.3 :

a) Since the test is for the alternative hypothesis that ? > 50, and the sample mean is 52, which is greater than 50, we reject the null hypothesis.

b) The test statistic is Z = (52 - 50) / (12 / sqrt(36)) = 1.5. The area in the tail to the right of 1.5 is 0.0668. Therefore, the p-value for the test is 0.0668.

Followings are the answers of 9.4 :

a) Since the test is for the alternative hypothesis that ? < 120, and the sample mean is 111, which is less than 120, we reject the null hypothesis.

b) The test statistic is Z = (111 - 120) / (26 / sqrt(40)) = -2.3038. The area in the tail to the left of -2.3038 is 0.0104. Therefore, the p-value for the test is 0.0104.

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K-fold cross-validation generally produces an estimate with lower bias compared to leave-one-out cross-validation.(option b).

Cross-validation is a popular technique used in machine learning to estimate the performance of a model on unseen data. There are different methods of cross-validation, including leave-one-out and K-fold. In leave-one-out, only one data point is left out for testing, while in K-fold, a Kth portion of the data is held out.

Now, to answer the question of which method generally produces an estimate with higher bias, we need to look at the formula for bias in cross-validation. The bias is given by the difference between the expected value of the cross-validation estimate and the true performance of the model.

For K-fold cross-validation, the expected value of the estimate is computed as the average of the estimates obtained in each of the K folds. This means that the bias is dependent on the number of folds used. The more folds used, the lower the bias is likely to be.

Hence the correct option is (b).

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We can see here that completing the frequency table, we have:

Interval               Frequency

0 - 2                           6

3 - 5                           6

6 - 8                           1

9 - 11                          2  

Frequency in mathematics and statistics describes how frequently a specific occurrence, value, or data point appears in a given dataset or sample.

It is frequently used when explaining how data is distributed, such as the frequency of test scores or the prevalence of particular behaviors or qualities in a group.

A fundamental idea in statistics, frequency is used to analyze and understand data in a variety of domains, including the social sciences, business, and science.

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Answer:  H

Step-by-step explanation:

The rule for a graph to be a function is if there are not 2 points that have the same x.

You can do a vertical line test. If you held up a vertical line(line that goes straight up and down) to both of these curves, across the entire curves(everywhere).  The curves do not hit that vertical line 2 or more times.  

Since both curves pass the vertical line test.  They are both functions.

As we have proven both directions of the statement X = Y if and only if Xy = (X + Y)²/4.

Let's start with the "if" direction. This means we need to prove that if Xy = (X + Y)²/4, then X = Y. To do this, we can start by multiplying both sides of the equation by 4 to get rid of the fraction:

4Xy = (X + Y)²

Expanding the right-hand side of the equation gives:

4Xy = X² + 2XY + Y²

We can rearrange this equation by subtracting 2XY and Y² from both sides:

4Xy - 2XY - Y² = X²

Next, we can factor out X on the left-hand side:

X(4y - 2Y) = X² - Y²

If we assume X ≠ 0, we can divide both sides by X to get:

4y - 2Y = X - Y

Simplifying this expression gives:

2y = X + Y

Finally, we can substitute this equation back into the original equation Xy = (X + Y)²/4 to get:

Xy = (2y)²/4

Simplifying this expression gives:

Xy = y²

Since X ≠ 0 (as we assumed earlier), we can divide both sides by X to get:

y = X

Therefore, we have shown that if Xy = (X + Y)²/4, then X = Y.

Now, let's move on to the "only if" direction. This means we need to prove that if X = Y, then Xy = (X + Y)²/4. To do this, we can start with the equation X = Y and substitute Y for X in the equation Xy = (X + Y)²/4:

Yy = (Y + Y)²/4

Simplifying this expression gives:

Yy = Y²

Dividing both sides by Y (since Y ≠ 0), we get:

y = Y/1

Therefore, we have shown that if X = Y, then Xy = (X + Y)²/4.

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In this scenario, a computer software magazine compares the rates of malware infection for computers protected by security software A and B.

To construct a 98% confidence interval for the difference between the proportions of infection for the two types of security software packages, follow these steps:

1. Calculate the proportions of infection for each security software (pA and pB):
  pA = 80/800 = 0.1
  pB = 45/900 = 0.05

2. Calculate the combined proportion (pC) and the standard error (SE) for the difference between proportions:
  pC = (80 + 45) / (800 + 900) = 125/1700 = 0.0735
  SE = sqrt((pC * (1 - pC)) * ((1/800) + (1/900))) = 0.0204

3. Find the z-score for a 98% confidence interval (z = 2.33 for a 98% CI).

4. Calculate the margin of error (ME) using the z-score and standard error:
  ME = z * SE = 2.33 * 0.0204 = 0.0475

5. Calculate the confidence interval for the difference between proportions:
  CI = (pA - pB) ± ME = (0.1 - 0.05) ± 0.0475 = 0.05 ± 0.0475 = (0.0025, 0.0975)

The 98% confidence interval is (0.0025, 0.0975), which can be rounded to (0.002, 0.098). This interval does not contain zero, which means it contradicts the claim that the proportion of infections is the same for the two types of security software. Therefore, the answer is (0.02, 0.098); yes.

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The fraction of people on the band's mailing list who have seen the band play at least once is 3/4.

To find the fraction of people who have seen the band play at least once, we need to add the fraction of people who have seen the band exactly once to the fraction of people who have seen the band more than once.

Fraction of people who have seen the band exactly once = 3/10

Fraction of people who have seen the band more than once = 9/20

To find the fraction of people who have seen the band play at least once, we need to add these two fractions

Fraction of people who have seen the band at least once = 3/10 + 9/20

We need to find a common denominator to add these two fractions. The common denominator of 10 and 20 is 20.

Fraction of people who have seen the band at least once = (3/10) * (2/2) + (9/20) * (1/1)

= 6/20 + 9/20

= 15/20

= 3/4

Therefore, 3/4 of the people on the band's mailing list have seen the band play at least once.

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The degree of the expression 12x+5x²-99x⁵ is

The degree of an algebraic expression is the highest power of the variable in the expression. An expression can have a variable or more.

For example, the degree of the expression 5y⁷+ 6y⁴+ 3y² is 7 because 7 is the highest exponent of the variable y in the expression.

Similarly the expression 12x+5x²-99x⁵ has 3 terms with x has the variable. The highest power of x in the expression is 5. Therefore the degree of the expression is 5.

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There are 1440 possible seating arrangements for eight people with X and Y sitting next to each other around the table.

To find the number of possible seating arrangements for eight people with X and Y sitting next to each other, follow these steps:

1. Treat X and Y as a single unit since they are seated next to each other. This means we now have 7 "units" to arrange (6 individual people and 1 unit of X and Y together).

2. Determine the number of arrangements for these 7 units around the table. Since the chairs don't matter and right and left are different, we use the formula for circular permutations: (n-1)! = (7-1)! = 6! = 720 possible arrangements.

3. Within the X and Y unit, there are 2 possible arrangements: X can be on the left of Y or on the right. So, we need to multiply the number of arrangements by the arrangements within the X and Y unit: 720 * 2 = 1440.

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The curve of the equation x³ + 9x² = 0 is sketched.

To begin, we can start by finding the x-intercepts of the function. The x-intercepts occur when F(x) = 0, so we can set the equation equal to zero and solve for x:

x³ + 9x² = 0

x²(x + 9) = 0

This equation has two solutions: x = 0 and x = -9. These values correspond to the x-intercepts of the function.

Next, we can find the y-intercept by evaluating the function at x = 0:

F(0) = 0³ + 9(0)² = 0

So the y-intercept is 0.

We can also analyze the behavior of the function as x approaches positive or negative infinity. As x becomes very large (either positive or negative), the x³ term in the equation will dominate and the function will behave like x³. This means that the function will increase without bound as x approaches infinity, and decrease without bound as x approaches negative infinity.

To sketch the curve, we can use these points and information to plot the general shape of the function. We know that the function has two x-intercepts, at x = 0 and x = -9, and a y-intercept at the origin. We also know that the function behaves like x³ as x becomes very large (either positive or negative).

Then we get the graph like the following.

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To calculate the probability that the club will win at least 1 of the 3 matches, we need to calculate the probability that they will lose all 3 matches and then subtract that from 1.

The probability of losing all 3 matches would be (0.7)^3 = 0.343. So the probability of winning at least 1 of the 3 matches would be 1 - 0.343 = 0.657, or approximately 66 percent.
To find the probability that the club will win at least 1 of the next 3 matches with a 30 percent probability of winning each match, we can use the complementary probability method. This involves finding the probability of the opposite event occurring (i.e., the club losing all 3 matches) and then subtracting that probability from 1.
Step 1: Determine the probability of losing each match. Since the club has a 30 percent probability of winning each match, the probability of losing each match is 1 - 0.30 = 0.70.
Step 2: Find the probability of losing all 3 matches. Since the matches are independent events, you can multiply the probability of losing each match together: 0.70 * 0.70 * 0.70 = 0.343.
Step 3: Calculate the complementary probability. To find the probability of winning at least 1 match, subtract the probability of losing all 3 matches from 1: 1 - 0.343 = 0.657.
So, the probability that the club will win at least 1 of the next 3 matches with a 30 percent probability of winning each match is 0.657 or 65.7%.

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there are 33 pleasing ordered triples.

We are given a set {1, 2, 3, 4, 5, 6}. We need to count the number of pleasing ordered triples (a, b, c), where a < b < c, and a, b, c are elements of the set.

Condition (b) requires that both b and c be greater than a. Since a can take any value from 1 to 4, the number of possibilities for (a, b, c) is:

For a = 1, there are 4 choices for b (2, 3, 4, 5) and 5 choices for c (3, 4, 5, 6, 5). However, we must exclude the case where b = c = 5, since both b and c must be greater than a. Therefore, there are 4 × 4 - 1 = 15 pleasing triples with a = 1.

For a = 2, there are 3 choices for b (3, 4, 5) and 4 choices for c (4, 5, 6, 5). However, we must exclude the case where b = c = 5, since both b and c must be greater than a. Therefore, there are 3 × 4 - 1 = 11 pleasing triples with a = 2.

For a = 3, there are 2 choices for b (4, 5) and 3 choices for c (5, 6, 5). However, we must exclude the case where b = c = 5, since both b and c must be greater than a. Therefore, there are 2 × 3 - 1 = 5 pleasing triples with a = 3.

For a = 4, there is only 1 choice for b (5) and 2 choices for c (6, 5). Therefore, there is only 1 × 2 = 2 pleasing triples with a = 4.

The total number of pleasing ordered triples is:

15 + 11 + 5 + 2 = 33

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The yards of ribbon purchased by Susan using amount on the debit card is equal to 32 yards.

Amount on prepaid debit card  = $20

Price of the ribbon  = 16 cents per yard

Amount left on the card after purchasing ribbon = $14.88  

Amount used to purchase ribbon

= Amount on initial amount debit card  - Amount left after purchasing ribbon

= $20.00 - $14.88 =$5.12

So Susan spent $5.12 on the ribbon.

Now ,use the price per yard to figure out how many yards she bought,

= Amount spent to buy ribbon / price of the ribbon per yard

= $5.12 ÷ $0.16 per yard

= 32 yards

Therefore, Susan bought 32 yards of ribbon with her prepaid debit card.

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To find a parametrization of the surface 3x^2 + 8xy, we can use two parameters u and v, such that x = u and y = v.

Substituting these values into the equation gives us z = 3u^2 + 8uv. Therefore, a parametrization of the surface is (u, v, 3u^2 + 8uv).

To find the tangent plane at x = 1, y = 0, z = 3, we need to first find the partial derivatives of the parametric equation with respect to u and v. These are:

∂/∂u (u, v, 3u^2 + 8uv) = (1, 0, 6u + 8v)
∂/∂v (u, v, 3u^2 + 8uv) = (0, 1, 8u)

Evaluating these partial derivatives at the point (1, 0, 3), we get:

∂/∂u (1, 0, 3) = (1, 0, 6)
∂/∂v (1, 0, 3) = (0, 1, 8)

Using the cross product of these two vectors, we can find the normal vector to the tangent plane:

(1, 0, 6) x (0, 1, 8) = (-6, -8, 1)

Therefore, the equation of the tangent plane is:

-6(x-1) - 8y + (z-3) = 0

To compare this with the graph, we can plot the surface using a software such as WolframAlpha, and then plot the tangent plane at the given point.

The tangent plane should appear as a flat surface tangent to the original surface at that point.

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The clay used by Samuel to create two triangular pyramids and three rectangular pyramids is 140 cm³

Volume of  rectangular pyramid = 1/3 × base area × height

Volume of  rectangular pyramid = 1/3 × 14 ×6

The volume of  rectangular pyramid = 28 cm³

Volume of  triangular pyramid = 1/3 × base area ×height

Volume of  triangular pyramid = 1/3 ×12×7

The volume of  triangular pyramid = 28 cm³

He made two triangular pyramids and three rectangular pyramids

= 2 × 28 + 3 × 28

= 140 cm³

The clay used to make two triangular pyramids and three rectangular pyramids is 140 cm³

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The question is incomplete the complete question is :

Samuel used clay to make a diorama of the pyramids in Ancient Egypt. He made two triangular pyramids and three rectangular pyramids. How much clay did he us to create all the pyramids?

A 28 cm3

B 84 cm3

C110 cm3

D 140 cm3

the probability that a randomly selected customer uses coupons but did not bring their own bags is 0.13.

What is probability?

The probability formula enables us to determine the likelihood of an event by dividing the number of favorable outcomes by the total number of possible outcomes. The probability of an event can range from 0 to 1 because the number of favorable outcomes cannot exceed the total number of outcomes.

From the Venn diagram, we can see that the probability of using coupons but not bringing their own bags is the area inside circle C but outside the overlapping region. Therefore, the probability is:

P(C and not B) = P(C) - P(C and B) = 0.25 - 0.12 = 0.13

So, the probability that a randomly selected customer uses coupons but did not bring their own bags is 0.13.

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Answer:

B) 175

Step-by-step explanation:

Same thing as before:

To get from 1.4 to 7 and to get from 7 to 35, you have to multiply by 5.

To get from 35 to the next sequence, you also have to multiply by 5.

35·5

=175

Hope this helps! :)

Answer:

7=1.4n

n=7÷1.4

n=5

next term =35×5

=175 B

The slope represents the predicted change in sales price for each additional square foot of a home. Using this slope, you can then create the regression line equation, which will help you predict the sales price based on square footage for homes in the subdivision.

To predict the sales price based on square footage for homes in this subdivision using the least squares regression line, you would need to follow these steps:

1. Collect data: Gather data on the sales prices and square footages of homes in the subdivision. This data will be used to calculate the regression line.

2. Calculate the mean: Find the average (mean) sales price and average square footage for the homes in your data set.

3. Calculate deviations: For each home, calculate the deviation of its sales price from the mean sales price and the deviation of its square footage from the mean square footage.

4. Calculate products: Multiply the deviations of sales price and square footage for each home, and then sum the products.

5. Calculate squared deviations: Square the deviations of square footage for each home, and then sum the squared deviations.

6. Calculate the slope: Divide the sum of products by the sum of squared deviations. This will give you the slope of the least squares regression line.

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Our confidence interval is only representative of the sample that we selected, and there could be variation in the true population proportion.

To construct a confidence interval for the population proportion of all pregnant women who gave birth the week of their due date

the following steps can be taken:

1. Determine the sample size: The sample size can be determined based on the desired level of confidence and margin of error. Let's say we want a 95% confidence level and a margin of error of 5%, which means we want to be 95% confident that the true proportion falls within 5% of the sample proportion. Using a confidence interval calculator, the required sample size would be 385.

2. Select a random sample of women who have recently given birth: The sample should be selected randomly to ensure that it is representative of the population of all pregnant women.

3. Calculate the sample proportion: Determine the proportion of women in the sample who gave birth the week of their due date.

4. Calculate the standard error: The standard error can be calculated using the formula SE = √((p*(1-p))/n), where p is the sample proportion and n is the sample size.

5. Calculate the confidence interval: Using a confidence interval calculator, the confidence interval for the population proportion can be calculated. For our example, the confidence interval would be 0.404 to 0.556.

The confidence interval we constructed (0.404 to 0.556) does not contradict the study's claim that a certain proportion of pregnant women give birth the week of their due date, as the interval includes the possibility of this proportion being within the range of 0.40 to 0.56.

Our confidence interval is only representative of the sample that we selected, and there could be variation in the true population proportion.

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Answer:

31 and 4 ninths square yards.

Step-by-step explanation:

The surface area of a right rectangular prism is the amount of wrapping paper you need to cover it up. To find it, you need to measure the length, width, and height of the prism. Then you can use this magic spell:

Surface area = 2 (lw + wh + lh) square units

where l is the length, w is the width, and h is the height.

For example, you have a right rectangular prism with length 3 yards, width 1 and 1 third yard, and height 2 and 2 thirds yards. That's a big gift! Using the magic spell, we get:

Surface area = 2 ((3 x 1 1/3) + (1 1/3 x 2 2/3) + (3 x 2 2/3)) yd² Surface area = 2 ((4 + 3 7/9 + 8)) yd² Surface area = 2 (15 7/9) yd² Surface area = 31 4/9 yd²

So the surface area of the right rectangular prism is 31 and 4 ninths square yards. That's a lot of wrapping paper! I hope you have enough tape!

The value of P(not yellow) if the spinner is spun once is 75%

From the question, we have the following parameters that can be used in our computation:

Spinner with repeated colors numbered from 1 to 8

The sample space of a eight-sided number cube is

S = {8 colors}

Where, the sections that are not yellow are

not yellow = 6 sections

Using the above as a guide, we have the following:

P(not yellow) = n(not yellow)/n(S)

So, we have

P(not yellow) = 6/8

Evaluate

P(not yellow) = 75%

Hence, the value of P(not yellow) is 75%

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The perimeter of shape B would be = 173.5in

To calculate the perimeter, the formula for scale factor should be used and it's given as follows;

Scale factor = perimeter a/perimeter b

The perimeter of shape a = 144 in

The perimeter of shape b = ?

The scale factor used for both shapes = 5/6 = 0.83

That is; 0.83 = 144/b

make b the subject of formula;

b = 144/0.83

= 173.5 in

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The image and the net that represents the solid figure is attached

From the question, we have the following parameters that can be used in our computation:

rectangular prism

When the rectangular prism is splitted into nets, we have the following shapes

Shapes = 6 rectangular faces

This means that the net that represents the solid figure has 6 rectangular faces

Using the above as a guide, we have the following:

The net of the solid figure is the image 4

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