Taking into account the reaction stoichiometry, 2.95 grams of MgO from 1.78 g of Mg and 2.36 g of O₂.
Reaction stoichiometryIn first place, the balanced reaction is:
2 Mg + O₂ → 2 MgO
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
Mg: 2 molesO₂: 1 moleMgO: 2 molesThe molar mass of the compounds is:
Mg: 24.31 g/moleO₂: 32 g/moleMgO: 40.31 g/moleThen, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
Mg: 2 moles ×24.31 g/mole= 48.62 gramsO₂: 1 mole ×32 g/mole= 32 gramsMgO: 2 moles ×40.31 g/mole= 80.62 gramsLimiting reagentThe limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.
Limiting reagent in this caseTo determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 32 grams of O₂ reacts with 48.62 grams of Mg, 2.36 grams of O₂ reacts with how much mass of Mg?
mass of Mg= (2.36 grams of O₂× 48.62 grams of Mg)÷ 32 grams of O₂
mass of Mg= 3.586 grams
But 3.586 grams of Mg are not available, 1.78 grams are available. Since you have less mass than you need to react with 2.36 grams of O₂, Mg will be the limiting reagent.
Mass of Mg formedConsidering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 48.62 grams of Mg form 80.62 grams of MgO, 1.78 grams of Mg form how much mass of MgO?
mass of MgO= (1.78 grams of Mg× 80.62 grams of MgO)÷ 48.62 grams of Mg
mass of MgO= 2.95 grams
Finally, 2.95 grams of MgO can be produced.
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Read the text about an animal in motion.
A prairie dog was resting underground in its burrow when it heard other prairie
dogs running around above ground. The prairie dog left its burrow and ran
around on a flat field with the others. After a few minutes, it got hungry. So, it
stopped in a patch of grass to feed.
When was the least gravitational potential energy stored between the prairie dog and Earth?
Assume that the prairie dog's mass did not change.
when the prairie dog was resting in its burrow
when the prairie dog got hungry
when the prarie dog stopped in the grass
The of life on Earth is defined by gravity. It influences plant and animal growth and development by regulating the proliferation of their cmorphologyonstituent cells1. Gravity is also important in cellular function.
when the prairie dog stopped in the grass.
What are the motion of the animal?Translational motion (such as the movement of an animal's center of gravity) and rotational motion are both important for animals (like the swinging of a leg). Most animals have flexible bodies with articulated arms and legs that are joined to the body via joints.The morphology of life on Earth is defined by gravity. It influences plant and animal growth and development by regulating the proliferation of their constituent cells1. Gravity is also important in cellular function.On Earth, Newton's laws define the weight of a body (or any other object) as mass times gravitational acceleration (w = m * g). That is, the weight of an object is determined by the gravitational pull on it.To learn more about : morphology
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A 9.96 g-sample of lithium chloride was dissolved in 100.0 mL of water at 22.2°C. When the salt was dissolved, the temperature of the solution was 41.3°C. Given the specific heat of solution of 4.18 J g^-1 °C-1 calculate the molar enthalpy of solution of lithium chloride. The density of water is 1.0 g/mL. Answer: -37.4 kJ/mol
The molar enthalpy of a lithium chloride solution containing 9.96 grams of lithium chloride dissolved in 100.0 milliliters of water at 22.2 degrees Celsius, rising to 41.3 degrees Celsius, is 34.0 kilojoules/mole.
The mass of water:
Density(D) = Mass(m) ÷ Volume(v)
1.00 g/ml = m÷100ml
m = 1.00g/ml × 100.0 ml
m = 100g
The amount of energy absorbed by water:
q = m × C × ΔT
q = 100g × 4.189J/g.°C × (41.3°C - 22.3°C)
q = 418 J/°C × 19.1°C
q = 7984J
q = 7.984kJ
The amount of energy absorbed by water is 7.984 kJ. The number of moles of lithium chloride has to be calculated. Then, the lithium chloride solution's molar enthalpy is calculated by dividing the energy absorbed by the lithium chloride solution by the number of moles of lithium chloride.
The molar mass of lithium chloride:
(Molar mass of lithium) + (Molar mass of chlorine)
(6.94g/mol) + (35.5g/mol)
42.4g/mol
The number of moles of lithium chloride:
Number of moles(n) = Mass(m) ÷ Molar Mass(M)
n = 9.96g ÷ (42.4g/mol)
n = 0.235 mol
The molar enthalpy of the lithium chloride solution:
Molar enthalpy = Energy absorbed(q) ÷ Moles of substances(n)
Molar enthalpy = 7.984kJ ÷ 0.235mol
Molar enthalpy = 34.0kJ/mol
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Liquid CleanersUV lightFumigationHeat/pressureVery effective, kills on allsurfaces. Expensive,V cannot be present whenthere, often requires someclean up.Easy to use, Cheap, greatfor flat surfaces, effective.Does not work well onvertical surfaces, can besmelly and require cleanup.Very Effective, Kills on allsurfaces, no clean upneeded. However, it takesa lot of time and cannotbe used on large objects.Easy, Cheap, great for flatsurfaces, no clean up. Noteffective in shadows,doesn't kill all microbes
Answer:
• Liquid cleaners,: Easy to use, Cheap, great for flat surfaces, effective. Does not work well on vertical surfaces, can be smelly and require clean up.
• UV light,: Very Effective, Kills on all surfaces, no clean up needed. However, it takes a lot of time and cannot be used on large objects.
• Fumigation,: Very effective, kills on all surfaces. Expensive, V cannot be present when there, often requires some clean up.
• Heat/pressure,: Easy, Cheap, great for flat surfaces, no clean up. Not effective in shadows, doesn't kill all microbes.
Explanation:
• Liquid cleaners,: it can slip down vertical surfaces and not have enough contact time to be able to fulfill its function.
,• UV light,: as UV light cleaning is normally done in closed chambers, it is not useful for large objects.
,• Fumigation,: in this case, concentrated chemicals are usually used, so it is very important not to be present during the fumigation.
,• Heat/pressure,: it is an economical method, because normally, pressurized hot water is used.
Enter your answer in the provided box.
Calculate the following quantity: volume of 1.96 M calcium chloride that must be diluted with water to
prepare 761 mL of a 2.79 x 102 M chloride ion solution.
mL
The volume of a 1.96 M calcium chloride that must be diluted with water to prepare 761 mL of a 2.79 x 102 M chloride ion solution is 108,326.02mL.
How to calculate volume?The volume of a solution can be calculated using the following formula:
C₁V₁ = C₂V₂
Where;
C₁ = initial concentrationV₁ = initial volumeC₂ = final concentrationV₂ = final volumeAccording to this question, 1.96 M calcium chloride must be diluted with water to prepare 761 mL of a 2.79 x 10² M chloride ion solution. The initial volume can be calculated as follows:
1.96 × V = 279 × 761
1.96V = 212,319
V = 108,326.02mL
Therefore, 108,326.02mL is the volume of the solution.
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Which statement could be used as a testable hypothesis for a scientificexperiment?A. If you put a cricket in water, it will be too scared to chirp.B. Does humidity affect how rapidly crickets chirp?C. Crickets are more annoying at night than during the day.OD. If the temperature decreases, then crickets will chirp less.
Answer
D. If the temperature decreases, then crickets will chirp less.
Explanation
A hypothesis is a testable guess about the relationship between two or more variables. As the temperature rises, it becomes easier to reach a certain activation energy, thereby allowing chemical reactions, such as the ones that allow a cricket to chirp, to occur more rapidly. Conversely, as the temperature falls, the reaction rates slow, causing the chirping to diminish along with it. Therefore the above statem
balance the equation for redox reaction in basic solution: HS^- (AQ.) + CLO3^- (AQ.) = S8 (S) +CL^- (AQ.)
The balancing of the given reaction can be: [tex]8HS^-_{(aq)}+4ClO^{3-}_{(aq)}---- > S_8+4Cl^-+4H_2O[/tex]
What is balancing equation?A balanced chemical equation is one that has the same number of atoms of each type in the reaction on both the reactant and product sides. In a balanced chemical equation, both the mass and the change are equal.
When using constants, a balanced equation is critical because the coefficients become the powers of the concentrations of products and reactants. The constant is incorrect if the equation is not balanced.
To balance a chemical equation, add coefficients to the symbols or formulas as needed so that the same number of each type of atom occurs in both reactants and products.
To balance the given reaction, it can be written as:
[tex]8HS^-_{(aq)}+4ClO^{3-}_{(aq)}---- > S_8+4Cl^-+4H_2O[/tex]
Thus, the above mentioned is the balanced equation.
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The Federal Reserve Bank of the United States is also known as the
people’s bank.
central bank.
world bank.
retail bank.
Answer:
The Federal Reserve System (sometimes refered to as "The Fed") is the central bank of the United States. It is the name given to a country's primary monetary authority.
Explanation:
Answer:
central bank
Explanation:
2023
HELP ME ASAP ALCHEMY CHEMISTRY: pray:
The symbol, name, atomic number, mass number, charge, number of protons, number of neutrons, and number of electrons of the given atoms are as follows:
2.
symbol: ⁶⁰₂₉Cuname: Copper-60atomic number: 29mass number: 60charge: 0number of protons: 29number of neutrons: 31number of electrons: 293.
symbol: ¹⁹⁸₇₉Auname: Gold-198atomic number: 79mass number: 198charge: +1number of protons: 79number of neutrons: 119number of electrons: 784.
symbol: ¹⁹₉Fname: Fluorine-19atomic number: 9mass number: 19charge: -1number of protons: 9number of neutrons: 10number of electrons: 105.
symbol: ²³⁸₉₂Uname: uranium-238atomic number: 92mass number: 238charge: 0number of protons: 92number of neutrons: 146number of electrons: 926.
symbol: ¹⁴₆Cname: Carbon-14atomic number: 6mass number: 14charge: 0number of protons: 6number of neutrons: 8number of electrons: 6What is the atomic number of an element?The atomic number of an element is the number of protons in the nucleus of an atom.
For a neutral atom, the number of protons is equal to the number of electrons.
For a negatively-charged atom, the number of electrons is greater than the proton number by the size of the charge on the atom.
For a positively-charged atom, the number of electrons is less than the proton number by the size of the charge on the atom.
The mass number is the sum of the proton and neutron in the nucleus. Hence, the neutron number is the difference between the mass number and the atomic number.
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Which equation is balanced?
Responses
2Mg+O2→2MgO
Na+F2→2NaF
2Al+3O2→Al2O3
Al+3F2→AlF3
five ways through which plant diseases are spread
An aqueous solution is 28.0% by mass potassium bromide, KBr, and has a density of 1.24 g/mL.
The molality of potassium bromide in the solution is
Molarity depends on the temperature and molality is independent of temperature. The molality of the given potassium bromide solution is 3.19mol/kg.
What is molality?Molality can be defined as the “total moles of a solute in a kilogram of a solvent.” SI unit of molality is mol/kg.
Mathematically,
Molality= number of moles of potassium bromide ÷mass of solvent in kg
number of moles of potassium bromide = given mass ÷molar mass of potassium bromide
28% means in 100 gram of solution 28g of potassium bromide is present, so mass of solvent= 100-28=72g
number of moles of potassium bromide=28g÷119 g/mol
= 0.23mol
Molality=(0.23×1000)÷72
Molality=3.19mol/kg
Therefore, the molality of solution is 3.19mol/kg.
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circle the meaning of the word in italics.
1. damp - (very wet, slightly wet, soaked, dripping.)
2. stain - ( embroidery, smear, mend, hole)
3. scrub - ( bleach, fold, sprinkle rub)
4. rust - stain form (plastic, leaf, iron, wood)
5. bleach - expose under the ( sun, fire, lamp, iron)
Answer:
1- damp
meaning: slightly wet
2-stain
meaning: smear
3-scrub
meaning: rub
4-rust
meaning: stain form iron
5-bleach
meaning: expose under the sun
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How many grams of NO are obtained from 16.1 g NO2 ?
Question: How many grams of NO are obtained from 16.1 g NO2 ?
Explanation: Goodmorning: ) i'm gonna say 2ɴᴏ2 --> 2ɴᴏ + ᴏ2
ᴍᴏʟᴇᴄᴜʟᴀʀ ᴡᴇɪɢʜᴛ ᴏꜰ ɴᴏ2 = 46.0ɢ
ᴍᴏʟᴇᴄᴜʟᴀʀ ᴡᴇɪɢʜᴛ ᴏꜰ ɴᴏ = 30.0ɢ
16ɢ ɴᴏ2 / 46ɢ (ᴍᴡ ᴏꜰ ɴᴏ2)=.3478 ᴍᴏʟ ᴏꜰ 2ɴᴏ2
= .3478 ᴍᴏʟ ᴏꜰ 2ɴᴏ✨
I’m struggling with determining the results of some of these problems.
Chemistry => Measurements => Dimensional Analysis
In order to do a division, the units must be congruent.
We can divide units of different properties, that is, units of mass by units of volume, but we cannot divide or multiply units of the same property that are on different scales, that is, we cannot divide nor multiply milligrams by grams, there must be a conversion before division. Therefore we will have to:
[tex](3.0mg^2)\cdot(0.023g)\text{ = No}[/tex][tex](4.0g)\cdot(1.0cm^3)=Yes=4.0g.cm^3[/tex][tex]\frac{20.mg^2}{0.010g}=No[/tex]7. When solid carbon reacts with oxygen gas to produce carbon dioxide gas, woul the triangle H value be on the reactant or product side of the equation?
When solid carbon reacts with oxygen gas to produce carbon dioxide gas. the deltaH (enthalpy change ) value is negative .DeltaH would be on the product side of the equation.
What is enthalpy change?In a thermodynamic system, energy is measured by enthalpy. Enthalpy is a measure of a system's overall heat content and is equal to the system's internal energy plus the sum of its volume and pressure.
Knowing whether q is endothermic or exothermic allows one to characterise the relationship between q and H. An endothermic reaction is one that absorbs heat and demonstrates that heat from the environment is used in the reaction, hence q>0 (positive). For the aforementioned equation, under constant pressure and temperature, if q is positive, then H will also be positive. In a similar manner, heat is transferred to the environment when it is released during an exothermic reaction. Thus, q=0 (negative). Therefore, if q is negative, H will also be negative.
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How many moles of sucroseare in 5.25x1029 sucrosemolecules?[?]x10[?]Enter your answer with the correctnumber of significant figures and be surethe prefix is a number between 1 and 10!Prefix (green)Exponent (yellow)Enter
To calculate the number of moles we will use Avogadro's number, which relates the number of molecules contained in a mole of any substance, the relationship between moles and molecules is as follows:
[tex]\begin{gathered} \text{Moles of a subtances=Molecules}\times\frac{1mol}{6.02\times10^{23}molecules} \\ \text{Moles of sucrose=}5.25\times10^{29}molecules\times\frac{1mol}{6.02\times10^{23}molecules} \\ \text{Moles of sucrose=}8.72\times10^5mol \end{gathered}[/tex]In the statement we are given the molecules with 3 significant figures, therefore the answer must also have 3 significant figures. So the answer will be: In 5.25x10^29molecules are 8.72x10^5 mol of sucrose
how to find number of moles of hydrogen gas collected for trial one?
We can consider the hydrogen gas of the first trial like an ideal gas and use the ideal gas law.
P * V = n * R * T
Where P is the pressure of the gas, V is the volume, n is the number of moles, R is the ideal gas constant and T is the temperature. We already have those values.
P = 753.8 mmHg (Pressure of Dry Hydrogen Gas)
760 mmHg = 1 atm
P = 753.8 mmHg * 1 atm/(760 mmHg)
P = 0.9918 atm
V = 40.3 mL (Volume of Hydrogen Gas Collected)
1000 mL = 1 L
V = 40.3 mL * 1 L/(1000 mL)
V = 0.0403 L
R = 0.082 atm*L/(mol*K) (ideal gas constant)
T = 295.6 K (Temperature in K)
Finally we can replace these values into the formula and solve it for n.
P * V = n * R * T
n = P * V /(R * T)
n = (0.9918 atm * 0.0403 L)/(0.082 atm*L/(mol*K) * 295.6 K)
n = 0.00165 moles
Answer: the number of moles of Hydrogen gas collected in trial 1 is 0.00165 mol.
If we use R = 62.358 L-torr/mol-K we need:
T = 295.6 K
V = 0.0403 L
P = 753.8 mmHg = 753.8 torr
n = P * V /(R * T)
n = (753.8 torr * 0.0403 L)/(62.358 torr*L/(mol*K) * 295.6 K)
n = 0.00165 moles
Write the balanced, nuclear equation for the positron emission from the Thallium-201 radioisotope.
The balanced nuclear equation for the positron emission from the Thallium-201 radioisotope is given below as:
²⁰¹₈₁Tl ---> ⁰₊₁e + ²⁰¹₈₂HgWhat is positron emission?Positron emission is a form of nuclear reaction in which a proton inside the nucleus of a radioactive element is converted into a neutron.
Positron emission is also known as beta plus decay, or β⁺ decay.
Positron emission does not result in changes in the mass number of the new atomic nucleus, but the atomic number of the new atomic nucleus is less than that of the original element by 1.
Nuclear reactions are reactions that involve changes occurring in the nucleus of an atom.
Radioactive elements are elements that spontaneously decay and release nuclear particles as well as radiation.
In the positron emission from the Thallium-201 radioisotope, the new atom formed will have one less proton than the original element.
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What is formed when a sodium atom and chlorine atom react chemically?
1- an element
2- a compound
3- an electron
4- a neutron
PLEASE ANSWER i am begging
How many milliliters of a stock solution of 7.00 M HNO3 would you have to use to prepare 0.120 L of 0.480 M HNO3 ? If you dilute 20.0 mL of the stock solution to a final volume of 0.270 L , what will be the concentration of the diluted solution?
1. The volume of the stock solution needed is 0.008 L
2. The concentration of the diluted solution is 0.52 M
1. How to determine the volume of the stock solution
We can obtain the volume of the stock solution as follow:
Molarity of stock solution (M₁) = 7Volume of diluted solution (V₂) = 0.120 L Molarity of diluted solution (M₂) = 0.480 M Volume of stock solution (V₁) =?M₁V₁ = M₂V₂
7 × V₁ = 0.480 × 0.120
5 × V₁ = 0.0576
Divide both side by 7
V₁ = 0.0576 / 7
V₁ = 0.008 L
Thus, the volume needed is 0.008 L
2. How to determine the concentration of the diluted solution
We can obtain the concentration of the diluted solution as follow:
Volume of stock solution (V₁) = 20 mLConcentration of stock solution (C₁) = 7 MVolume of diluted solution (V₂) = 0.270 L = 0.270 × 1000 = 270 mL Concentration of diluted solution (C₂) =?C₁V₁ = C₂V₂
7 × 20 = M₂ × 270
140 = M₂ × 270
Divide both side by 270
C₂ = 140 / 270
C₂ = 0.52 M
Thus, the concentration is 0.52 M
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What mass of glycerin (C3H8O3) must be dissolved in 169.8 g water to give a solution with a freezing point of -3.81°C? Kf for water = 1.86°C*kg/mol.
Please give explanation...
It is necessary to add 2.67 grams of glycerin to 169.8 grams of water in order to produce a solution that has a freezing point that is 3.81 degrees below zero.
This is further explained below.
What is glycerin?Generally, The freezing point of water will drop as a result of the addition of glycerin to the water.
The term "Depression in Freezing Point" has been given to describe this phenomenon. This kind of attribute is known as a colligative property.
By using the formula, we are able to calculate the decrease in the freezing point,
dT = i.m.K
dT = 0-(-3.81) °C
dT = 3.81 °C.
Generally, the equation for the Molarity is mathematically given as
m = W/92 x 0.1698
Therefore
[tex]3.81 = \frac{1.86 x W}{(92 x 0.1698}\\\\W = \frac{3.81 x 92 x .01698 }{1.86}[/tex]
W = 2.67 grams.
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What is the name of the chemical formula Cl3N8?
A. chlorine nonanitrogen
B. trichlorine octanitride
C. chlorine nitride
D. tetrachlorine octanitride
The name of the chemical formula; Cl₃N₈ is trichlorine octanitride (option B).
What is IUPAC?IUPAC is the acronym for international Union of pure and applied chemistry. IUPAC nomenclature of organic chemistry is a method of naming organic chemical compounds as recommended by the International Union of Pure and Applied Chemistry.
According to this IUPAC nomenclatural rules, the following applies:
Mono means oneDi means twoTri means threeTetra means fourPenta means fiveHexa means sixHepta means sevenOcta means eightAccording to this question, a compound with the following chemical formula is given; Cl₃N₈. This suggests that the name will be trichlorine octanitride.
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Write a balanced nuclear equation for the beta decay of Pb-212
Answer:
Explanations:
Beta decay is a type of radioactive decay in which a beta particle is emitted from the nucleus. A beta particle is written as:
[tex]^0_{-1}\beta[/tex]The required balanced nuclear equation for the beta decay of Pb-212 will be expressed as:
[tex]^{212}_{82}Pb\rightarrow^0_{-1}\beta+^{212}_{83}Bi[/tex]From the reaction, you can see that the beta decay of Pb-212 produces the Bismuth element with atomic number 83 and mass number 212.
Which action is the best example of direct observation?
Answer:
meaning
Explanation:
repeat yourself please and be specific
A solution of an unknown compound has a concentration of 36.2% by mass. How many moles are present in 3.644 kg of solution if the solute has a molar mass pf 89.6 g/mol?
First part)
36.2% by mass means:
36.2 g of solute ------- 100 g of solution
Second part)
We want to know how many moles are present in 3.644 kg of solutions.
3.644 kg = 3644 g of solution
Now,
36.2 g of solute -------- 100 g of solution
x --------- 3644 g of solution
x = 1319 g of solute = 1320 g (3 significant figures)
Therefore 1320 g are diluted in 3644 g
Third part)
Number of moles = mass /molar mass
Number of moles = 1320 g of solute/ 89.6 g/mol of solute= 14.7 moles
Answer: 14.7 moles of solute
what is the molarity of h3po4 solution if 0.05 M ba(oh)2 is needed to neutralize 20.00 ml of h3po4
The molarity of h3po4 solution if 0.05 M ba(oh)2 is needed to neutralize 20.00 ml of h3po4 is 0.25 M.
Given,
M₁ =?
valance factor H₃PO₄ (n)₁ = 3
M₂ = 0.05 M
V1 = V2 = 20 m or 0.02 L
valance factor Ba(OH)₂(n)₂ = 2
M₁n₁V₁ = M₂n₂V₂
M₁ = (M₂n₂V₂) / n₁V₁
= 0.05 × 2 × 3
= 0.25 M
Molarity is the number of moles of a substance in keeping with the liter of answer. solutions labeled with the molar awareness are denoted with a capital M; a 1. zero M answer incorporates 1 mole of solute according to the liter of answer. Molality is the variety of moles of solute in step with a kilogram of solvent.
Molarity (M) is the amount of a substance in a positive volume of solution. Molarity is described because the moles of a solute in step with liters of an answer. Molarity is also known as the molar attention of an answer.
Molarity is very crucial in chemistry for one big purpose. it's far the measurement of concentration in any mixture. The molarity of any solution is a way to know the unique factors or compounds which are found in any solution.
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By using carbon-14, scientists were able to determine that 436 half-lifes have occurred since this specimen died. How old is this fossil? The half-life of carbon-14 is 5730 years. **TWO PART QUESTION** Please explain all your steps for part b!!
In this question, we have to calculate the age of a fossil after the decay of Carbon-14 436 times, with a half-life of 5730 years, and in order to do that, we can multiply both values, one example to understand this step better is:
Let's say we have a 2 times decay of a certain amount of Carbon-14, we can say that 11,460 years have passed by, and we can check it:
x grams of C 14 = 0 years
x/2 grams of C 14 = 5730 years, 1st decay
x/4 grams of C 14 = 11460 years, 2nd decay
Therefore with 436 decays
5730 * 436 = 2,498,280 years this is the age of this fossil
Part B:
For this part, we will need to use the Half-Life formula, which is the following:
N(t) = N0(1/2)^t/t1/2
Where:
N(t) = quantity of the substance remaining, 2.2*10^-78
N0 = initial quantity of the substance
t = time elapsed, 2,498,280 years
t1/2 = half life of the substance, 5730 years
Now we add these values into the formula:
2.2*10^-78 = N0(1/2)2,498,280/5730
2.2*10^-78 = N0(1/2)^436
2.2*10^-78 = 5.63*10^-132N0
N0 = 2.2*10^-78/5.63*10^-132
N0 = 3.91*10^53 was the initial quantity
What is the name of a substance that contains a useful element which can be extracted from it?
The name of a substance that contains a useful element which can be extracted from it is ore.
ore can be defined as the mineral from which useful substance can be extracted and it contains more valuable substances. ore is deposited of one or more precious mineral in earth crust. examples of ore is iron ore : hematite , magnetite , copper ore : pyrite , borntite, zinc ore : sphalerite, zinc blende, calamite.
The Four types of ore are given as follows :
Ore oxideOre halidesOre carbonatessulphide oreThus, The name of a substance that contains a useful element which can be extracted from it is ore.
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A 60.5 mL sample of a 0.116 M potassium sulfate solution is mixed with 40.0 mL of a 0.102 M lead (II) acetate solution and the following precipitation reaction occurs: K2SO4(aq)+Pb(C2H3O2)2(aq)→2KC2H3O2(aq)+PbSO4(s) The solid PbSO4 is collected, dried, and found to have a mass of 1.00 g . Determine the limiting reactant, the theoretical yield, and the percent yield.
The limiting reactant is lead acetate as in absence of it reaction will not occur. Theoretical and percent yield are 2.1092 g and 49.52% respectively.
What is percent yield?Percent yield is defined as the ratio of actual yield to the theoretical yield multiplied by 100. If the actual and theoretical yield are same then the percent yield is 100%.If actual yield is less than the theoretical yield then the percent yield is less than 100%.Reason of this condition arising is the incompletion of reaction or loss of sample during recovery process.
In cases where percent yield is over 100% it indicates that more sample is recovered than the predicted amount.This condition arises when there are other simultaneous reactions taking place leading to the formation of product. It can also arise if there is incomplete removal of impurities from the sample .
To calculate percent yield, it is necessary to know theoretical yield which for the given reaction is found out as, mass of potassium sulfate is found from molarity which is 1.212 g .If,174.259 g potassium sulfate produces 303.26 lead sulfate then 1.212 g potassium sulfate will produce 1.212×303.26/174.259=2.1092 g of lead sulfate which is the theoretical yield.
The percent yield is calculated as follows, 1/2.1092×100=49.52%.
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1. Consider the titration of 0.250 M of 50.0 mL nitric acid (HNO) by 0.350 M NH,. Kb for NH, is 1.8 x 10°. Calculate the pH of the resulting solution after the following volumes of NH, have been added. a. 0.0 mL b. 50.0 mL c. Half-way equivalence point d. At equivalence point e. 150.0 mL
Answer:I got pH = 4.98
Explanation:. This agrees with the fact that strong acid + weak base = acidic pH.
If you notice, the volume and concentration of both
NH
3
and
HNO
3
are identical, and
HNO
3
only has one
H
+
. Therefore, you should convince yourself that these neutralize each other exactly because the number of mols of each are equal.
This leaves the same number of mols of
NH
+
4
as
NH
3
, in TWICE the volume (i.e. don't forget to account for dilution!):
