The primary key in the Employee Database schema is "person_id" in the Employee table. There are two foreign keys: "person_id" in the Works table referencing the Employee table, and "company_name" in the Works table referencing the Company table.
What are the primary keys and foreign keys in the Employee Database schema?a. Primary Keys: person_id (in Employee), company_name (in Company)
Foreign Keys: person_id (in Works), company_name (in Works)
b. π(person_id, person_name, street, city)(σ(city = "Bahrain")(Employee))
c. π(person_name)(σ(city = "Miami")(Employee))
d. π(person_name)(σ(salary > 10000)(Employee))
e. π(person_name)(σ(city = "Miami" ∧ salary > 10000)(Employee))
f. π(person_id, person_name)(Employee - σ(company_name = "BigBank")(Works))
g. π(person_id, person_name, city)(σ(company_name = "BigBank")(Employee ⨝ Works))
h. π(person_id, person_name)(σ(city = Company.city)(Employee ⨝ Works ⨝ Company))
i. π(person_id, person_name, street, city)(σ(company_name = "BigBank" ∧ salary > 10000)(Employee ⨝ Works ⨝ Company))
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Write a c++ program to merge two arrays. Your output shall be like below (You can choose the array size and elements of your choice).
Enter the size of the first array: 5
Enter the 5 elements of the first array: 1, 2, 3, 4, 5
Enter the size of the second array: 5
Enter the 5 elements for the second array: 6, 7, 8, 9, 10
The NEW MERGED ARRAY: 1 2 3 4 5 6 7 8 9 10
This C++ program prompts the user to enter the size and elements of two arrays. It then creates a new array with a size equal to the sum of the sizes of the two input arrays.
```cpp
#include <iostream>
using namespace std;
int main() {
int size1, size2;
cout << "Enter the size of the first array: ";
cin >> size1;
int arr1[size1];
cout << "Enter the elements of the first array: ";
for (int i = 0; i < size1; i++) {
cin >> arr1[i];
}
cout << "Enter the size of the second array: ";
cin >> size2;
int arr2[size2];
cout << "Enter the elements of the second array: ";
for (int i = 0; i < size2; i++) {
cin >> arr2[i];
}
int mergedSize = size1 + size2;
int mergedArray[mergedSize];
for (int i = 0; i < size1; i++) {
mergedArray[i] = arr1[i];
}
for (int i = 0; i < size2; i++) {
mergedArray[size1 + i] = arr2[i];
}
cout << "The NEW MERGED ARRAY: ";
for (int i = 0; i < mergedSize; i++) {
cout << mergedArray[i] << " ";
}
cout << endl;
return 0;
}
```
The elements of the first array are copied into the merged array first, followed by the elements of the second array. Finally, the program outputs the merged array.
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What would be the output of the following code: numbers = [1, 1, 2, 3] for number in numbers: if number % 2 == 0: break print(number) 1 -- ~ M 1 2 3 2 1 1 3
The output of the following code: numbers = [1, 1, 2, 3] for number in numbers: if number % 2 == 0: break print(number).
Then, it uses an if statement to check whether each element is even or not. If an element is even, the code uses a break statement to stop the iteration immediately and exits the loop.
Therefore, only the first even number in the list will be printed. If none of the numbers in the list is even, the loop will finish normally without executing the break statement. Then, it will print the last value of the variable "number", which is the last element of the list "numbers".Since the list "numbers" has four elements: [1, 1, 2, 3], and the first even number is 2, the output of the code will be "1 -- ~ M".
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Question 6 Convert the following infix expressions into their corresponding prefix forms. (a + b) * c/d [Choose] (a + b) * (c / d) [ Choose] a + b*c/d [Choose ] a + b* (c/d) ✓ [Choose ] +a/*bcd *+ab/cd +ab*/cd /*+abcd +a*b/cd +ab*c/d < Previous
The prefix form of the infix expression (a + b) * (c / d) is + * / d c b a. By converting the expression to prefix form.
The given infix expression is: a + b * (c / d)
To convert it to prefix form, we follow the following steps:
Reverse the expression.
Original: a + b * (c / d)
Reversed: d / c * b + a
Determine the precedence of operators and enclose them in parentheses accordingly.
Reversed: ((d / c) * b) + a
Write down the final prefix expression.
Prefix form: + * / d c b a
To convert the given infix expression to prefix form, we follow the steps mentioned above. In the first step, we reverse the expression to get d / c * b + a. Then, in the second step, we enclose the expressions (d / c) and (d / c) * b in parentheses to indicate their precedence. Finally, in the third step, we write down the reversed expression as the prefix form, which is + * / d c b a.
The prefix form of the infix expression (a + b) * (c / d) is + * / d c b a. By converting the expression to prefix form, we ensure that the order of operations is explicitly defined, making it easier to evaluate the expression programmatically.
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find the id, first name, and last name of each customer that currently has an invoice on file for wild bird food (25 lb)
To provide the ID, first name, and last name of each customer who currently has an invoice on file for wild bird food (25 lb), the specific data from the database or system needs to be accessed. Without access to the specific data source, it is not possible to provide the direct answer.
To find the required information, you would typically need to query a database or system that stores customer and invoice data. The query would involve joining tables related to customers and invoices, filtering for invoices with the specified product (wild bird food, 25 lb). The specific database schema and structure would determine the tables and fields involved in the query.
Here's an example SQL query that demonstrates the concept, assuming a simplified database schema:
```sql
SELECT c.id, c.first_name, c.last_name
FROM customers c
JOIN invoices i ON c.id = i.customer_id
JOIN invoice_items ii ON i.id = ii.invoice_id
JOIN products p ON ii.product_id = p.id
WHERE p.name = 'wild bird food' AND p.weight = 25;
```
In this example, the query joins the `customers`, `invoices`, `invoice_items`, and `products` tables, filtering for the specified product name ('wild bird food') and weight (25 lb). The result would include the ID, first name, and last name of each customer who has an invoice on file for that particular product.
Please note that the actual query may vary depending on the specific database schema and structure, and the query language being used.
Without access to the specific data and database structure, it is not possible to provide the direct answer to the query. However, the explanation and example query provided should give you an understanding of the process involved in retrieving the required information from a database or system.
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You wish to know what devices are out of date and need to be
refreshed (replace). We also wish to know the employee who
currently has the device. Write a single Access SQL statement that
will return a
The solution to this query using SQL is:SELECT Device_Name, Employee_NameFROM Devices INNER JOIN Employees ON Devices.Employee_ID = Employees.Employee_IDWHERE Devices.Date_Purchased < DATEADD("yyyy", -3, DATE());
We can see that in the code above, we first select the name of the device and the employee to whom the device belongs to. We also join the table Employees with table Devices to get the employee name for the device ID. The WHERE clause determines which devices should be refreshed by checking if the date the device was purchased is older than three years. If the purchase date is older than three years, the device needs to be replaced. We can use the DATEADD function to subtract 3 years from the current date. This code ensures that only devices older than three years will be shown in the result.
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What would be the resulting color from the following RGB color code? (255,0,255) Select one: O a. Black O b. White O c. Green O d. Magenta O e. Red O f. Yellow O g. Cyan Oh. Blue O i. Grey
The resulting color from the following RGB color code (255, 0, 255) is Magenta. The RGB color model is an additive model, which is used to generate colors on displays like computer screens and televisions.
The RGB code is used to represent the color in the RGB model. RGB stands for Red, Green, and Blue, and it specifies the amount of each color that is required to generate the color we see.Color is an important part of our daily life. It has an impact on our emotions, behaviors, and moods.
A variety of colors exist, each with its own significance. Magenta is a bright, vivid color that can be produced by mixing blue and red. It is a mixture of red and violet. It is also known as Fuchsia and Hot Pink, and it is frequently associated with femininity.In a full RGB model, each color component ranges from 0 to 255. This range implies that there are 256 colors available for each color component.
As a result, there are 16,777,216 possible colors that can be generated in an RGB color model. When all three colors are mixed in equal proportions, the resulting color is white. Black is the absence of color. To produce black, all three color components must be set to 0, such as (0, 0, 0). So, the correct answer is option d. Magenta.
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1. Which of the following is not true?
Select one:
a. When management outsources their organization’s IT functions, they also outsource responsibility for internal control.
b. Once a client firm has outsourced specific IT assets, its performance becomes linked to the vendor’s performance.
c. IT outsourcing may affect incongruence between a firm’s IT strategic planning and its business planning functions.
d. The financial justification for IT outsourcing depends upon the vendor achieving economies of scale.
a). a. When management outsources their organization’s IT functions, they also outsource responsibility for internal control. is the correct option.
The following statement that is not true from the given options is:When management outsources their organization’s IT functions, they also outsource responsibility for internal control. This statement is false.What is outsourcing?Outsourcing is an activity in which an organization or company employs a third-party service provider to perform specific tasks, operate its IT infrastructure, or provide a service. Outsourcing may include several components of a company's operations, such as human resources, accounting, customer care, and, of course, IT functions.
The organization that outsources may also outsource responsibility for internal control.Therefore, option a) is incorrect in this case.What is IT Outsourcing?IT outsourcing is a process by which a company's IT functions are transferred to a third-party provider. The third-party provider takes responsibility for the infrastructure, software, and IT operations, and the client organization pays a monthly or annual fee for those services. The vendor will be responsible for maintaining the IT infrastructure, applications, and services, and the client will have access to support, maintenance, and assistance whenever required.
Therefore, options b) c) and d) are correct, and the answer is: Option a).
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How easily an authorized person can move data from one place to
another is an example of:
a) intentional mobility.
b) unintentional mobility.
c) authorized access.
d) autonomous mobility.
The ease with which authorized persons can move data from one location to another is an example of authorized access. The authorized person is given permission to access and transfer data between systems and applications. The response to this inquiry would be: option c) authorized access.
Here is an explanation of authorized access:Authorized access refers to the use of logins, passwords, keys, or other security mechanisms that have been approved by data security administrators to restrict access to confidential or sensitive data. As a result, only authorized personnel with appropriate credentials can access data or applications that have been restricted to specific users.
The opposite of authorized access is unauthorized access, which refers to unauthorized access to information by individuals who are not authorized to access it. Unauthorized access is often the result of hacking, viruses, malware, or other forms of cybercrime.
The main goal of authorized access is to restrict the ability of unauthorized persons or software to access confidential information. As a result, it assists to maintain data security and to prevent data breaches, which might lead to the release of confidential data to outsiders.
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MCQ: Which of the following are application scenarios of TensorFlow? Select one or more: Artistic style transfer Facial recognition O AlphaGo Self-driving
The following are some of the application scenarios of TensorFlow:
Artistic Style TransferFacial RecognitionAlphaGoSelf-driving CarsTensorFlow is an open-source platform designed to create and build complex deep learning models. It is a widely used platform in the field of data science, artificial intelligence, and machine learning.
Artistic style transfer refers to the practice of merging two images, one being the content and the other being the style, into one output image. This application of TensorFlow is extensively used in the domain of art and design.
Facial recognition involves identifying an individual's face in a given image or video footage. TensorFlow's accuracy and robustness make it an ideal tool for this application.
AlphaGo is a computer program that plays the game Go and won against the world champion of Go. AlphaGo was created using TensorFlow and deep learning algorithms.
TensorFlow is widely used in the development of self-driving cars. It is used for tasks such as image and video recognition, speech recognition, and other cognitive abilities that are required for autonomous driving.
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The regions are expanding. Americas will now be called North America, and Middle East and Africa will now be called Middle East. Write the update statements to change these regions. ( Please make sure it runs)
Here are the tables
CONSULTANTS
- CONSULTANT_ID
- FIRST_NAME
- LAST_NAME
- EMAIL
- PHONE_NUMBER
- HIRE_DATE
- JOB_ID
- SALARY
- COMMISSION_PCT
- MANAGER_ID
- DEPARTMENT_ID
.
COUNTRIES
- COUNTRY_ID
- COUNTRY_NAME
-REGION_ID
.
CUSTOMERS
- CUST_ID
CUST_EMAIL
CUST_FNAME
CUST_LNAME
CUST_ADDRESS
CUST_CITY
CUST_STATE_PROVINCE
CUST_POSTAL_CODE
CUST_COUNTRY
CUST_PHONE
CUST_CREDIT_LIMIT
.
DEPARTMENTS
- DEPARTMENT_ID
DEPARTMENT_NAME
MANAGER_ID
LOCATION_ID
.
EMPLOYEES
- EMPLOYEE_ID
FIRST_NAME
LAST_NAME
EMAIL
PHONE_NUMBER
HIRE_DATE
JOB_ID
SALARY
COMMISSION_PCT
MANAGER_ID
DEPARTMENT_ID
.
JOB_HISTORY
- EMPLOYEE_ID
START_DATE
END_DATE
JOB_ID
DEPARTMENT_ID
.
JOBS
- JOB_ID
JOB_TITLE
MIN_SALARY
MAX_SALARY
.
LOCATIONS
- LOCATION_ID
STREET_ADDRESS
POSTAL_CODE
CITY
STATE_PROVINCE
COUNTRY_ID
.
REGIONS
- REGION_ID
REGION_NAME
.
SAL_GRADES
- GRADE_LEVEL
LOWEST_SAL
HIGHEST_SAL
.
SALES
- SALES_ID
SALES_TIMESTAMP
SALES_AMT
SALES_CUST_ID
SALES_REP_ID
UPDATE REGIONS SET REGION_NAME = 'North America' WHERE REGION_NAME = 'Americas';
UPDATE REGIONS SET REGION_NAME = 'Middle East' WHERE REGION_NAME = 'Middle East and Africa';
To update the region names, we use the UPDATE statement in SQL. The first statement updates the region name 'Americas' to 'North America', and the second statement updates the region name 'Middle East and Africa' to 'Middle East'.
In the UPDATE statement, we specify the table name followed by the SET keyword. Within the SET clause, we provide the column name to be updated ('REGION_NAME') and the new value we want to set ('North America' or 'Middle East'). We use the WHERE clause to specify the condition for updating only the rows that match the given region names.
By executing these two update statements, the region names will be changed as desired in the REGIONS table.
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3
and 4 are together
2. What's the wild card mask for subnet mask of ? I 3. What's the wild card mask for subnet prefix of /20? 4. Which OSPF wildcard mask would be appropriate to use for the given network pref
To determine the wild card mask for a subnet mask or prefix, we need to understand the concept of subnetting and how the wild card mask works.
A wild card mask is the inverse of a subnet mask. It is used to define the range of IP addresses that should be matched or ignored in various networking configurations.
To find the wild card mask for a given subnet mask, we simply need to flip the bits of the subnet mask. For example, if the subnet mask is 255.255.0.0, the wild card mask would be 0.0.255.255.
For a subnet prefix of /20, we need to convert it into a subnet mask to find the corresponding wild card mask. The subnet mask for /20 is 255.255.240.0. To get the wild card mask, we flip the bits, resulting in 0.0.15.255.
The appropriate OSPF wildcard mask for a given network prefix depends on the desired routing configuration. Wildcard masks are used in OSPF (Open Shortest Path First) to define network addresses or ranges. The choice of wildcard mask would depend on the specific network addresses or ranges you want to include or exclude in the OSPF configuration. It is important to carefully analyze the network topology and requirements to select the appropriate wildcard mask for OSPF
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Draw a data dependency graph for the program. void simple(int a, int b, int c, int d){ int i, j, k, m; m = 20; k = 2; i= b + a; j= d; k = k + 5; while ((c + d) > i) { i=i+2; j=i+c-d+a; } if (i > i + 5){ k=j+i; } return; }
In the given program, there are several data dependencies that can be visualized using a data dependency graph. The dependencies include read-after-write (RAW), write-after-read (WAR), and write-after-write (WAW) dependencies.
The data dependency graph for the program is as follows:
m = 20
k = 2
i = b + a
j = d
k = k + 5
while ((c + d) > i) {
i = i + 2
j = i + c - d + a
}
if (i > i + 5) {
k = j + i
}
The variables a, b, c, d, i, j, k, m are represented as nodes in the graph, and the dependencies between them are represented by directed edges. For example, the calculation of "i" depends on the values of "a" and "b" (i = b + a), so there is a data dependency edge from "a" and "b" to "i".
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3. 15 points - Special Bit Instructions - Perform the following tasks using only a single line of assembly code. Assume for these problems that register X contains $2050. a. Set bits 1, 2, and 6 of $2
A single line of assembly code was used to set bits 1, 2, and 6 of $2 to 1 by performing a logical OR operation with the immediate value 0x46. This ensured that only those bits were set to 1, and all other bits remained unchanged.
To set bits 1, 2, and 6 of $2, a single line of assembly code can be used. Assume for this problem that register X contains $2050. The binary representation of 2050 is 100000000010. To set bits 1, 2, and 6 of $2 to 1, we need to use a logical OR operation using the immediate value 0x46, which has the binary representation 01000110.The value 0x46 is added to the contents of register $2 using a logical OR operation. By doing this, bits 1, 2, and 6 are set to 1, and all other bits remain unchanged.The single line of assembly code for setting bits 1, 2, and 6 of $2 is:ori $2, $2, 0x46Explanation: The logical OR operation compares each bit of the two operands and returns a value of 1 if either or both bits are 1. By using the immediate value 0x46, which has bits 1, 2, and 6 set to 1, we ensure that only those bits will be set to 1, while all other bits remain unchanged.
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Performing the given task with only a single line of assembly code would give us BSF $2030, #1 | #2 | #6.
How to find the assembly code ?The BSF instruction stands for "Bit Set Field". It sets the specified bits in the operand to 1. In this case, the operand is $2030, and the specified bits are 1, 2, and 6. The | symbol is used to perform a bitwise OR operation. The bitwise OR operation will set the specified bits in the operand to 1, if they are already 1, or to 1, if they are 0.
The BSF instruction will only set the specified bits to 1 if the value in register X is greater than or equal to the value of the specified bits. In this case, the value in register X is $2050, which is greater than or equal to the value of the specified bits (1, 2, and 6). Therefore, the BSF instruction will set bits 1, 2, and 6 of $2030 to 1.
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10 8 12 37 24 21 18 18 14 17 H2 23 26 (33 H erge these two Skew Heaps H1 and H2, show the result.
Given, H1: 10 8 12 37 24 21 18 18 14 17 and H2: H2: 23 26 (33 H Let us find the Skew Heap for the given two Skew Heaps:
Insert the nodes of H2 into H1, following Skew Heap merge algorithm, we get: The steps followed to merge two Skew Heaps are: We merge two heaps H1 and H2 by taking the root of the heap with the greater root and attaching the entire heap to the smaller root as its child.
We swap the left and right children of all nodes in the merged heap, obtaining the final Skew Heap. The merge of Skew Heaps H1 and H2 gives us the following Skew Heap:10 8 12 37 24 21 18 18 14 17 23 26 33 H Hence, the resultant Skew Heap after merging H1 and H2 is: 10 8 12 37 24 21 18 18 14 17 23 26 33 H. The above answer includes more than 100 words, I hope this helps.
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Suppose you use the simple division hash function, h (k)=k%n and quadratic probing to insert a sequence of elements: 4,5,8,10, one by one to an array (Suppose the length of array: n=6). What would be the array position (or index) to store 10? A. 0 B. 1 C. 3 D. 4
The array position to store 10 using the simple division hash function and quadratic probing would be C. 3.because of collision resolution through quadratic probing.
The simple division hash function, h(k) = k % n, calculates the array position by taking the remainder of the key (k) divided by the length of the array (n). In this case, n is 6.
Let's go through the steps of inserting the elements using quadratic probing:
Inserting 4:
The hash value for 4 is 4 % 6 = 4. Since the array position 4 is empty, we can directly store 4 there.
Inserting 5:
The hash value for 5 is 5 % 6 = 5. The array position 5 is empty, so we can store 5 there.
Inserting 8:
The hash value for 8 is 8 % 6 = 2. However, the array position 2 is already occupied by 4. With quadratic probing, we probe the next positions using quadratic increments. The next position to check is (2 + 1^2) % 6 = 3. Since the array position 3 is empty, we store 8 there.
Inserting 10:
The hash value for 10 is 10 % 6 = 4. However, the array position 4 is already occupied by 4. We continue quadratic probing, and the next position to check is
(4 + 1^2) % 6 = 5.
But position 5 is also occupied by 5. We continue probing:
(4 + 2^2) % 6 = 2.
Position 2 is still occupied. We probe again:
(4 + 3^2) % 6 = 1.
Position 1 is empty, so we can store 10 there.
Therefore, the array position to store 10 is C. 3.
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For the following features:
- Admin can add article types, number of available items, prices
-Admin adds articles to categories
- User can select desired number of items (up to available maximum) to add to cart
- Cart calculates the amount user needs to pay
- User can remove articles from cart
- User can do the online payment
- There should be discounts for 3rd and every next transaction in a month, with the payment amount greater than 60BAM.
- Every user profile has a history of their purchases. There is also a report tab that shows the statistics regarding the amounts spent, number of transactions, items a user buys (how many per selected period, etc.). Reports are generated on a yearly basis by default, but a user can select any date range to see the relevant reports.
- Based on the reports the system suggests items to buy to a user whenever they login.
Give a brief system overview, which includes the product’s perspective, scope, constraints and risks, and success criteria. Moreover, it should provide a quick glance into the primary system actors and key system features. Afterwards, it should present a feasibility and requirements analysis (functional and nonfunctional requirements). Not all of these sections are mandatory, but you should, at the very least, provide a functional and nonfunctional requirements analysis.
Also, briefly write system maintainability, data integrity and security concerns relating to the implementation of the above mentioned features. You can discuss the administrative part of the application, features and their maintenance, data maintenance and backup, restoring the data when application crashes, application security, future developments and data integrity, etc.
System OverviewThe system is an e-commerce platform that enables users to purchase articles of different types. It allows the admin to manage the platform by adding new article types, set prices, available items, and add articles to categories.
A user can select the desired items to add to their cart, remove articles from the cart, do the online payment, and view their purchase history.Key System Features
Admin Management - This feature allows the admin to manage the platform by adding new article types, set prices, and available items.
Cart Management - This feature enables users to select the desired items to add to their cart, remove articles from the cart, and do the online payment.
Purchase History - This feature enables users to view their purchase history. Reports are generated on a yearly basis by default, but a user can select any date range to see the relevant reports.System ActorsThe primary system actors are admin and users.
Functional Requirements- The system should allow the admin to add new article types, set prices, available items, and add articles to categories.-
The system should allow users to select the desired items to add to their cart, remove articles from the cart, do the online payment, and view their purchase history.- Discounts should be offered for the 3rd and every next transaction in a month, with the payment amount greater than 60BAM.
Nonfunctional Requirements- The system should be scalable and able to handle a large number of users.- The system should be available 24/7.- The system should be secure, and user data should be protected from unauthorized access.
Maintainability, Data Integrity, and Security ConcernsRelating to the implementation of the above mentioned features, the following concerns are identified:-
Administrative Part of the Application:
Regular system maintenance should be performed, which includes updating the system with the latest security patches and making sure that the system is running smoothly.-
Features and Their Maintenance:
The system features should be regularly updated based on user feedback and market demand.-
Data Maintenance and Backup:
Regular data backups should be performed to prevent data loss in case of system failure.-
Restoring the Data When Application Crashes:
The system should be able to restore data in case of system failure.-
Application Security:
The system should be secure, and user data should be protected from unauthorized access.-
Future Developments and Data Integrity:
The system should be designed to allow for future developments, and data integrity should be maintained throughout the system.
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identify the functional and non-functional requirement development activities associated with the following scenario: "GJU transportation department is creating an online survey questionnaire for requesting students' feedback on the desired features to develop an online trans application".
The scenario states that GJU (German Jordanian University) transportation department wants to create an online survey questionnaire for requesting students' feedback on the desired features to develop an online trans application.
Functional requirement development activities: Functional requirements specify what the system should do. In the given scenario, the following functional requirement development activities are associated with creating an online survey questionnaire: Identify the target audience: One of the essential activities for the functional requirement development of the survey questionnaire is identifying the target audience. It involves identifying the group of students who will be surveyed.
Develop relevant survey questions: After identifying the target audience, the transportation department should develop relevant survey questions. Relevant survey questions are questions that are significant to the target audience. The department should develop survey questions that are easy to understand, and students should not have to spend more time reading or understanding the question.Prioritize student needs: The transportation department should prioritize student needs when creating the survey questionnaire.
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Computer Science, Language C++.
Please see my below code. I need to overload the operator ==, but I can't figure how to make it work when my compiler is only allowing me to pass two parameters since == is binary operator. Line 216 is the line of the == operator to be overloaded. Each object has a vector "initial list". The goal of the overload is for the overlaoded operator to return true if obj5 and obj6 are equal to eachother and false if they're not. In this case I initialized the objects so that they are equal to eachother so the overloaded == operator should return true. It's not the prettiest code right now, let me know if you need any clarification, but the operator to be overloaded is in line 216. The code does run if 216 is commented out.
#include
#include
#include
#include
#include
using namespace std;
class StringSet {
private:
vector initialList;
friend ostream& operator << (ostream& COUT, StringSet& obj);
friend istream& operator >> (istream& IN, StringSet& obj);
public:
StringSet(){}
StringSet(string InitialArray[], int Size)
{
for(int i=0; i < Size ; i++) // user inputting elements
{
initialList.push_back(InitialArray[i]);
}
}
StringSet(const StringSet &other) // use const because "other" object is not being manipulated
{
cout <<"copy constructor\n";
for (int i = 0; i < other.initialList.size();i++)
{
initialList.push_back(other.initialList[i]);
}
}
void AddString()
{
initialList.push_back(" added ");
cout <<"test add element\n";
}
void RemoveString()
{
initialList.erase (initialList.begin());
}
int SetSize()
{
return initialList.size();
}
bool SearchSet()
{
for(int i=0; i < initialList.size(); i++) // user inputting elements
{
if (find(initialList.begin(), initialList.end(), "search") != initialList.end())
return true;
else
return false;
}
return false;
}
void DisplaySet()
{
for(int i=0; i < initialList.size(); i++)
{
cout << initialList[i]<< " ";
}
}
void WriteFile()
{
fstream myFile;
myFile.open("assntwo.txt", ios::out);
if (myFile.is_open())
{
myFile << "Blueberry\n";
myFile << "Kiwi\n";
}
}
void ReadFromFile()
{
fstream myFile;
myFile.open("assntwo.txt", ios::in);
if (myFile.is_open())
{
string line;
while (getline(myFile, line))
{
cout << line << endl;
}
myFile.close();
}
}
void ClearSet()
{
initialList.clear();
}
StringSet operator+(StringSet const &obj){
// creating new object of StringSet class to return
StringSet my_union;
// adding all the elements of the list to the new object's list
for(string str : this->initialList){
my_union.initialList.push_back(str);
}
// checking if any element of other object is present in the list already or not, if not then add it to the list
for(string str : obj.initialList){
if(find(my_union.initialList.begin(), my_union.initialList.end(), str) == my_union.initialList.end()){
my_union.initialList.push_back(str);
}
}
// return my_union
return my_union;
}
StringSet operator *(const StringSet& Obj)
{
cout <<"intersection\n";
StringSet temp;
StringSet my_intersection;
for(string n: Obj.initialList)
{
temp.initialList.push_back(n);
}
vector::iterator it;
for (int i = 0; i < Obj.initialList.size(); i++)
{
it = find (temp.initialList.begin(), temp.initialList.end(), Obj.initialList[i]);
if (it != temp.initialList.end())
{
my_intersection.initialList.push_back(Obj.initialList[i]);
}}
cout<<"hi\n";
for(string a: my_intersection.initialList)
{
cout << a;
}
return my_intersection;
}
};
ostream& operator << (ostream& COUT, StringSet& obj) // Goal of the overload is to make it print the info about
{
for(int i=0; i < obj.initialList.size(); i++)
{
COUT << obj.initialList[i]<< " ";
}
return COUT;
}
istream& operator >> (istream& IN, StringSet& obj)
{
string a;
cout << "Please enter a string\n";
IN >> a;
obj.initialList.push_back(a);
return IN;
}
int main()
{
string initialArray[] = {"apple", "orange"};
StringSet obj1(initialArray, 2);
StringSet obj2 (obj1);
cout << "Constructor for initial values, copy constructor, and copy destructor done\n";
obj1.AddString();
cout<<"search result: " << obj1.SearchSet()<< endl; // 1 means true 0 means false, works
obj1.RemoveString();
obj1.SetSize();
obj1.DisplaySet();
obj2.DisplaySet();
//obj1.ClearSet();
obj1.WriteFile();
obj1.ReadFromFile();
// tester code for + operator overloading
string initialArray2[] = {"apple", "orange"};
StringSet obj4(initialArray2, 2);
StringSet obj3 = obj1 + obj4; // overload +
cout<< "Displaying after taking union of obj1 and obj4\n";
obj3.DisplaySet();
cout<
// intersections
cout <<"where we at\n";
cout <<"obj1\n";
obj1.DisplaySet();
cout <<"obj4\n";
obj4.DisplaySet();
cout <<"thats where\n";
obj3.DisplaySet();
obj3 = obj1*obj4;
obj3.DisplaySet();
cout <<"overload\n";
cout << obj1;
StringSet obj5;
cin >> obj5;
obj5.DisplaySet();
StringSet obj6(obj5);
obj6 == obj5; // this is the line that needs to be overloaded operator ==
}
To overload the `==` operator, you can define it as a member function inside the `StringSet` class. Here's how you can implement it.
```cpp
bool operator==(const StringSet& obj) {
if (initialList.size() != obj.initialList.size())
return false;
for (int i = 0; i < initialList.size(); i++) {
if (initialList[i] != obj.initialList[i])
return false;
}
return true;
}
```
Place the above code inside the `StringSet` class, preferably before the closing curly brace of the class definition. This implementation checks if the sizes of the `initialList` vectors in both objects are equal. If not, it immediately returns false. Then it compares each element of the vectors to see if they are equal. If any pair of elements is not equal, it returns false. Otherwise, if all elements are equal, it returns true.
By overloading the `==` operator in this way, you can compare `StringSet` objects for equality using the `==` operator. For example, in your code, `obj6 == obj5` will return true if `obj5` and `obj6` have the same elements in their `initialList` vectors, and false otherwise.
Note: It's also worth mentioning that you have a comment on the line `cout<// intersectionscout <<"where we at\n";`. Please make sure to fix the comment by adding the missing `<<` before the comment text to avoid a compilation error.
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If front = 0, year = 4, correntsize=4 and max Queue Size = s, then dequexe () number from the index removes D • Select After dequeue, front (0,114,5) D 3 0,4,5 1208 currentsize and (3,4,5). Camlin
Based on the given information, let's assume we have a queue with a front index of 0, a year value of 4, a current size of 4, and a maximum queue size of s.
To dequeue an element from the queue, we need to follow these steps:
1. Remove the element at the front index from the queue.
2. Update the front index to the next position.
3. Decrement the current size of the queue.
Let's apply these steps:
1. Dequeue the element at the front index (0): D
2. Update the front index to the next position (front = front + 1): front = 1
3. Decrement the current size of the queue (currentsize = currentsize - 1): currentsize = 3
After dequeueing, the front index becomes 1, and the current size of the queue decreases to 3.
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need Cryptographic protocol Shape Analyser Code
For the following descriptions, M is the message, K is a freshly chosen symmetric key, PubK(N) is the public key of N, and PrivK(N) is the private key of N. {}K stands for encryption with key K. Hash(X) is hashing of message X.
1)Sign then encrypt:
A -> B: {M, A, {Hash(M)}PrivK(A)}K, {K}PubK(B)
2)Encrypt then sign:
A -> B: {M}K, A, {Hash({M}K)}Privk(A), {K}PubK(B)
To implement the cryptographic protocols described, you will need a combination of signing and encrypting techniques. The first protocol involves signing the message before encrypting it, while the second protocol involves encrypting the message before signing it.
1) Sign then encrypt:
In this protocol, A signs the message M using their private key PrivK(A), ensuring the authenticity and integrity of the message. The signed message is then encrypted using a symmetric key K.
The encrypted message, along with A's identity and the hash of the message, encrypted with A's private key, is sent to B. Additionally, A encrypts the symmetric key K with B's public key PubK(B) to ensure confidentiality during transmission.
2) Encrypt then sign:
In this protocol, A encrypts the message M using a symmetric key K. The encrypted message is then sent to B.
A also computes the hash of the encrypted message and signs it using their private key PrivK(A), ensuring the authenticity and integrity of the encrypted message.
A's identity and the encrypted symmetric key K are also included in the message.
These protocols provide a secure way to exchange messages between A and B, ensuring that the messages cannot be tampered with and that only the intended recipients can access the content.
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Discuss the design phase of an enterprise architecture for a
university (education sector) using TOGAF framework. Focus on the
first six stages of TOGAF ADM. (800
The design phase of an enterprise architecture for a university (education sector) using TOGAF framework is discussed below:TOGAF (The Open Group Architecture Framework) is a comprehensive framework for enterprise architecture that provides an approach for designing, planning, implementing, and managing enterprise IT architecture.
It can be used to design the architecture of an enterprise in a systematic manner.In the first six stages of the TOGAF ADM, the design phase takes place.
This phase entails creating and designing the architecture that meets the enterprise's business objectives. It also entails the creation of a baseline architecture and a target architecture.
The design phase of an enterprise architecture for a university (education sector) using TOGAF framework is discussed below:
1. Architecture Vision: The first phase is to define the organization's architecture vision, which includes identifying its business objectives, drivers, and constraints.
2. Business Architecture: The second phase entails developing the business architecture by defining the organization's business strategy, goals, and objectives. This stage establishes the relationship between business goals and IT objectives.
3. Information Systems Architecture: This phase involves defining the information systems architecture that supports the business objectives and aligns with the business architecture. It also includes developing a technology architecture that supports the organization's information systems.
4. Technology Architecture: The fourth phase is to develop a technology architecture that defines the technical infrastructure, platforms, and application components necessary to support the information systems architecture. It includes the specification of hardware, software, networks, and communication infrastructure.
5. Opportunities and Solutions: In this phase, the enterprise's IT architecture is analyzed, and opportunities and solutions for improvement are identified.
6. Migration Planning: This phase entails developing a migration plan for implementing the target architecture. It involves defining the transition architecture and identifying the steps required to implement the target architecture.
In conclusion, the design phase of an enterprise architecture for a university (education sector) using the TOGAF framework includes creating an architecture vision, developing the business architecture, defining the information systems architecture, developing a technology architecture, identifying opportunities and solutions, and developing a migration plan.
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PLEASE READ QUESTIONS CAREFULLY AND ANSWER
Write a C program that perform the following:
1. Create three threads, Thread A, ThreadB, and Thread C.
2. Create a shared variable and initialize it b
The provided C program creates three threads and initializes a shared variable. Each thread accesses and modifies the shared variable, and the final value is displayed at the end.
Here's an example of a C program that creates three threads (Thread A, Thread B, and Thread C) and initializes a shared variable:
```c
#include <stdio.h>
#include <stdlib.h>
#include <pthread.h>
int sharedVariable;
void* threadFunction(void* arg) {
int threadId = *(int*)arg;
// Access the shared variable
printf("Thread %c: The shared variable is %d\n", threadId, sharedVariable);
// Modify the shared variable
sharedVariable += threadId;
// Display the modified shared variable
printf("Thread %c: The modified shared variable is %d\n", threadId, sharedVariable);
pthread_exit(NULL);
}
int main() {
pthread_t threadA, threadB, threadC;
int threadIdA = 'A', threadIdB = 'B', threadIdC = 'C';
// Initialize the shared variable
sharedVariable = 0;
// Create threads
pthread_create(&threadA, NULL, threadFunction, &threadIdA);
pthread_create(&threadB, NULL, threadFunction, &threadIdB);
pthread_create(&threadC, NULL, threadFunction, &threadIdC);
// Wait for threads to finish
pthread_join(threadA, NULL);
pthread_join(threadB, NULL);
pthread_join(threadC, NULL);
// Display the final value of the shared variable
printf("The final value of the shared variable is %d\n", sharedVariable);
return 0;
}
```
In this program, three threads are created using the `pthread_create()` function. Each thread executes the `threadFunction()` function, which accesses and modifies the shared variable. The `pthread_join()` function is used to wait for the threads to finish their execution. Finally, the program displays the final value of the shared variable.
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The remove method in the queue class, removes the element from the a. front of the list b. middle of the list c. any where in the list depending on the index d. end of the list
The remove method in the queue class removes the element from the a) front of the list.
Queues are an abstract data type that follows a First-In-First-Out (FIFO) principle. It means that the element that is inserted first is the first element that gets removed from the list. Therefore, the remove method deletes the element that was first added to the queue.The remove method pops the front element from the queue. It also shifts the remaining elements in the queue. If there are no elements in the queue, it raises an error that notifies the user that the queue is empty.
It is essential to ensure that the queue has elements before calling the remove method to avoid the raised error. Overall, the remove method is a vital method in the queue class that helps to maintain the FIFO principle by removing the front element in the queue.
Therefore, the correct answer is a) front of the list.
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Discuss Byzantine fault problem in relation to blockchain.(15
marks)
Byzantine fault tolerance denotes a network's or system's capacity to continue operating even when certain components are problematic or have failed. With a BFT system, blockchain networks continue to function or carry out planned tasks as long as the majority of network participants are trustworthy and real.
This means that a transaction must be validated and included to the block by more than half or two-thirds for the nodes on the blockchain network.
Compromise nodes must be in the majority in order to induce malice in a Byzantine fault-tolerant blockchain. Malice can manifest itself as double spending, a 51% assault, a Sybil attack, and so on.
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You have just taken a role as data scientist in a start-up called TEXTMOOD, founded by a team of psychologists. These psychologists have conducted research whose conclusion is that traditional notions of sentiment applied to text in sentiment analysis (with values ‘positive' or negative') are less helpful to humans in understanding textual intention than a different kind of categorisation that they call MOOD (with specific values 'critical', ‘grateful', 'bored', 'excited'). For instance, a comment "I'm really not a fan of #thebieb's new haircut" would be regarded as critical of Justin Bieber. The company has collected a large dataset of social media comments and had them labelled with this four-way mood categorisation scheme. They have asked you to build a high-performing classifier that will identify the mood from some new social media comment. Explain the extent to which pretrained models would be appropriate for a solution here. In doing so, focus on: • the kind of existing pretrained models that would be suitable; • how these pretrained models should be used in the transfer learning: how the new model is built on top of the pretrained model, and what new layers are needed; and • how the new model is trained.
Using pretrained models would be appropriate for building a high-performing classifier for mood classification in social media comments. Models such as BERT, GPT, or RoBERTa, which are pretrained on large text corpora, can be suitable for this task. Transfer learning can be employed by building a new model on top of the pretrained model. This involves adding additional layers specific to the mood classification task and fine-tuning the pretrained model on the labeled dataset.
Pretrained models, such as BERT (Bidirectional Encoder Representations from Transformers), GPT (Generative Pre-trained Transformer), or RoBERTa (Robustly Optimized BERT approach), have been trained on large-scale text datasets and have learned valuable representations of language. These models capture contextual relationships and semantic information, making them well-suited for text classification tasks.
To adapt a pretrained model for mood classification, a new model can be built on top of the pretrained model. The new layers are typically added on the top of the pretrained model, including an output layer with four units corresponding to the four mood categories: critical, grateful, bored, and excited. These new layers are randomly initialized, while the weights of the pretrained layers are frozen or fine-tuned to prevent overfitting.
The new model is trained by feeding the labeled dataset of social media comments through the network. During training, the parameters of the new layers and, optionally, some of the pretrained layers are updated using backpropagation and gradient-based optimization techniques like stochastic gradient descent. The objective is to minimize a suitable loss function, such as categorical cross-entropy, to improve the model's ability to classify the mood of new social media comments accurately.
By leveraging pretrained models and employing transfer learning, the startup can benefit from the learned representations of language while adapting the model specifically for mood classification in social media comments. This approach can help in building a high-performing classifier with reduced training time and better generalization capabilities.
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What would be the output of the following program: public class Test \{ public static void main(String] args) \{ KWLinkedList \( < \) Integer \( > \) list \( = \) new KWLinkedList \( < \) Integer> \(
The original program will execute successfully but will not produce any output.
The provided Java program is a valid code that creates a linked list of integers using the KWLinkedList class. The KWLinkedList class is a custom implementation of a linked list data structure in Java, allowing for the storage and manipulation of integer values.
However, it is important to note that the given program lacks any code to print the linked list or its contents. Consequently, when the program is executed, it will run without encountering any errors or issues. Nevertheless, it will not generate any output or display the elements stored within the linked list.
To rectify this and observe the contents of the linked list, you can modify the program by incorporating a loop that iterates through each element of the linked list. Within the loop, you can add code to print or display the individual values, enabling you to visualize the data stored in the linked list.
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Most Web pages today are written in a ____— a coding system used to define the structure, layout, and general appearance of the content of a Web page.
Most Web pages today are written in a markup language— a coding system used to define the structure, layout, and general appearance of the content of a Web page.
One popular markup language is HTML (Hypertext Markup Language), which is used to structure the content and define the elements of a webpage. The simplification process mentioned involves applying Boolean algebra rules to logical expressions. Boolean algebra is a mathematical system that deals with binary variables and logical operations such as AND, OR, and NOT.
By applying rules like distribution, De Morgan's laws, and complementation, the expressions can be simplified to their most concise forms. Simplification helps in analyzing and implementing logical circuits or systems by reducing complexity and improving efficiency. These simplified forms are easier to understand, manipulate, and translate into practical implementations in various applications, including digital logic design and programming
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The parts in this question belong to the same mini project. Your answers should consider the information given in all parts of the question. (a) There are a lot of interesting factors about streets in Hong Kong. For example, is Short Street really short? Why some streets are named after vegetables? Chris is interested in street names and their length and collect a data file named streets_hk.csv. The first line contains header information. Each of the remaining lines contains the name, the district and the length (in kilometres) of one street. The first few lines of the file are shown below. Name, District, Length Short Street, Kowloon, 0.06 Kowloon Road, Kowloon, 0.21 Rednaxela Terrace, HK Island, 0.23 Tuen Mun Road, NT, 16.28 Tolo Highway, NT, 11.33 Sha Tin Road, NT, 3.42 Complete the following program, with the tasks divided in parts, that performs analysis on the file. The program should first read the data in a data structure, which is a list of dictionaries with each dictionary contains the data of a street. [6] street_list = [] with open('streets_hk.csv', 'r') as infile: firstline = True while True: line = infile.readline () if line: if firstline: firstline = False continue # # PART (i) # else: break print (street_list) # PART (ii) # PART (iii) # PART (iv) Submit all the following parts as one whole program. (i) Add code (in the specified place) in the above program skeleton so that the list of dictionaries (i.e. the variable street_list) contains the data from the CSV file. (ii) Add code to find out how many streets have a length of 1.0 kilometre or below. Print the result with a suitable output message. (iii) Add code to find out the shortest street. The program should print the name, the district and the length of the shortest street. (iv) Add code to find out the 3 longest street in the Kowloon district, and print them out from the longest first. Use any method. The name and the length of the streets should be printed.
The program reads data from a CSV file named 'streets_hk.csv' and performs analysis on the street data. It creates a list of dictionaries, `street_list`, to store the street information.
(i) To read the data from the CSV file and store it in `street_list`, the program uses a `with` statement to open the file and reads each line using a loop. It skips the first line (header) and appends the street information as a dictionary to `street_list` for each subsequent line.
(ii) To find the number of streets with a length of 1.0 kilometer or below, the program iterates through `street_list` and checks the length value for each street. If the length is less than or equal to 1.0, a counter is incremented. Finally, the program prints the count with a suitable output message.
(iii) To determine the shortest street, the program iterates through `street_list` and compares the length of each street with the current shortest length. It updates the shortest length and stores the corresponding street information. After iterating through all streets, the program prints the name, district, and length of the shortest street.
(iv) To find the three longest streets in the Kowloon district, the program creates an empty list, `kowloon_streets`, to store the streets in the Kowloon district. It iterates through `street_list`, checks if the district is "Kowloon," and appends the street information to `kowloon_streets`. Then, it sorts `kowloon_streets` based on the length of the streets in descending order. Finally, the program prints the names and lengths of the top three streets in `kowloon_streets`.
By implementing these parts, the program successfully reads and analyzes the street data, providing information about the number of short streets, the shortest street, and the three longest streets in the Kowloon district.
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In class Student, a variable is needed to hold the student’s major, the value can only be one of the majors that theuniversity offers. Explain and justify with an example (Student and driver class) in JAVA, the type you would choose for major variable.
In the given scenario, if a variable is needed to hold the student's major, the value can only be one of the majors that the university offers. In Java programming language, the type to choose for major variable would be Enumeration. Enumeration is a special class in Java that defines a group of values that are known at compile time.
Enumerations can be thought of as a sort of named integer constants which increases the code readability and reduces the errors. Enumerations are often used where there are fixed, predefined sets of values that have meaning within the program.
The above declaration creates an enumeration type called "Major" with five values (Computer Science, Biology, Psychology, Mechanical Engineering, and Electrical Engineering). Now, this enumeration can be used as the data type for the major variable in the Student and Driver classes.
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PostgreSQL Question:
Write a short description in English explaining what this SQL query is doing:
SELECT emp_no,
title,
CASE WHEN title LIKE 'Senior%' THEN 'Senior' ELSE 'Junior'
END AS seniority
FROM titles
LIMIT 20;
The above-mentioned SQL query is selecting employee number (emp_no), their job title (title), and the category of job seniority (seniority) and limiting the result set to only 20 records.
The select statement is used to specify the columns that need to be returned from the table titles. The employee number is being selected which is stored in the emp_no column and the job title which is stored in the title column of the titles table.
The CASE expression is being used to determine whether the job title of an employee starts with "Senior" and if yes then the employee is assigned the "Senior" category of job seniority, otherwise, the employee is assigned the "Junior" category of job seniority.Furthermore, the results set is limited to only 20 records which will be returned by the LIMIT clause. This query will help in analyzing the job titles of the employees by categorizing them into senior and junior employees.
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