a)The 95% confidence interval are
0-44,44-88
b))Yes, we can claim significant reduction in the rate of intrusion attempts
The p-value is 0.067No, the given assumption does not make a difference.We have firewall change of 14 people.
We need to compute total sum before firewall change which can be done by
(56+47+49+37+38+60+50+43+59+50+56+54+58)/14
=657/14
=46.92
Now, similarly, after firewall change total sum is
(53+21+32+49+45+38+44+33+32+43+53+46+36+48+39+35+37+36+39+45)/20
=756/20
=37.8
Now the difference between average number of intrusion attempts before and after firewall change is
(46.92-37.8)
=9.12
Now, we need to make confidence interval to only 95% of this difference=
(95×9.12)/100
=44.196=44(approx)
It means our interval range varies from 0-44,44-88 with a difference of 44.
b)Yes, we can easily claim that rate of intrusion attempts decreases.
Before firewall change, we can see average number of intrusion attempt is =46.92
After firewall change, we can see average number of intrusion attempt is
37.8
So, we can see rate of intrusion decreases on increasing the number of blocked intrusions.
For computing z-value, we just need to take square root of the difference of average number of intrusions attempst
=>Z-value= √9.12=3.01
Using the z-table, we get that for the above z-value, corresponding p-value is 0.067
Hence, the interval range is 0-44,44-88 and b)Yes we can claim, p-value is 0.067.No, this assumption does not make a difference.
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toilet rolls come in packs of 4 and 9
the 4 packed one is priced £2.04
the 9 packed one is priced £4.68
By calculating the price per roll, determine which roll is better value
The roll with a better value, that is, cheap price is 9 packed toilet roll.
How to find the roll with a better value?In order to determine the roll with a better value, we will consider the unit price of each roll and make comparison.
Unit price refers to the price of a commodity per each unit.
Cost of 4 packed toilet roll = £2.04Unit price = Cost / units
= £2.04 / 4
= £0.51 per unit
Cost of 9 packed toilet roll = £4.68Unit price = Cost / units
= £4.68 / 9
= £0.52 per unit
Therefore, it can be concluded that the the roll which has a better value is the 9 packed toilet roll.
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Solve 2x + b = c for x.
2x + b - b = c - b subtract b from both sides
2x = c - b combine like terms/simplify
2x - 2 = c - b - 2 subtract 2 from both sides to get x isolated
x = c - b - 2 simplify/final answer
The above process has an error. What is the mistake?
What is the correct final answer?
The value of x from the given equation is x=(c-b)/2. Therefore, in the given steps, the person has done mistake in step 3.
The given equation is 2x+b=c.
What is an equation?In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.
The given equation cab solved as follows
Subtract b from both sides
2x+b-b=c-b
Combine like terms/simplify
2x=c-b
Divide 2 from both sides to get x isolated
x=(c-b)/2
The value of x from the given equation is x=(c-b)/2. Therefore, in the given steps, the person has done mistake in step 3.
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3. Verify that PQ is twice the length of ST.
How to do this please help
The length of the PQ is twice of the Length of the ST .
How to find the Length between two points?The length of the line segment connecting two points in a plane is defined as distance between two points. The method for calculating the distance between two points is typically written as
d=√((x_2-x_1)²+(y_2-y_1)²)
This formula is used to calculate the distance between two locations on a coordinate plane or an x-y plane.
from the graph
P(2,4), Q(-4,-6), S (7,2) and T (4, -3)
Find the Length of the PQ = √((x_2-x_1)²+(y_2-y_1)²)
= [tex]\sqrt{ (-4-2)^2 + (-6-4)^2}[/tex]
= [tex]\sqrt{136} =11.66[/tex]
ST = [tex]\sqrt{ (4-7)^2 + (-3-2)^2}[/tex] =[tex]\sqrt{34}[/tex] = 5.83
hence verified
The length of the PQ is twice of the Length of the ST .
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What is the line of x =- 2?.
Precalculus is an example here, since x=−2 is a vertical type line, there is no y-intercept as well as the slope is undefined.
The slope is undefined and all of the factors on the road have an x-coordinate of that (a few number). For example, if x = -2, then all factors alongside this line can have an x-coordinate of -2, making it a vertical line. y=−2 is a flat line crossing the factor at (0,−2) consequently the gradient is 0 and the the y intercept is -2.
A terrible slope approach that variables are negatively related; that is, whilst x increases, y decreases, and whilst x decreases, y increases. Graphically, a terrible slope approach that as the road on the road graph movements from left to right, the road falls. The x-coordinate -2 is represented throughout. This is NOT a function.
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Mariam is going to invest $3,000 and leave it in an account for 13 years. Assuming the interest is compounded monthly, what interest rate, to the nearest hundredth of a percent, would be required in order for Mariam to end up with $6,200?
Answer:
8.21%
Step-by-step explanation:
r = (1/t)(A/P - 1)
t = 13
A = 6200
P = 3000
1 6200
r = (-------) ((------------) - 1))
13 3000
1 31
r = (-------) ( ------ - 1)
13 15
1 16
r = (-------) ( ------ )
13 15
16
r = -------- = 0.0820512
195
r = 0.0820512 x 100 = 8.20512
r ≈ 8.21%
I hope this helps!
Answer:
Step-by-step explanation:
Compounded Monthly:
Use A=P(1+r/n)^nt
A=6200
P=3000
t=13
n=12
Plug in and simplify:
1. Multiply 12 times 13
2. Divide out the 3000
3. Raise both sides to the 1/156 power to cancel out the exponent
4. Subtract 1 from both sides
5. Multiply by 12 on both sides
R should equal 0.0559716
That is about 5.60%
5.60%
How do u get 6.75 into a fraction
Answer:
[tex]\frac{27}{4}[/tex] or [tex]6\frac{3}{4}[/tex]
Step-by-step explanation:
6.75 = [tex]6\frac{3}{4}[/tex] = [tex]\frac{27}{4}[/tex]
Because 0.75 = [tex]\frac{3}{4}[/tex]
I would appreciate it if you mark my answer as brainliest.
Answer:
6 3/4
Step-by-step explanation:
so first 1/4 equals to 0.25
so if 1/4 is 0.25 than 3/4 would be 0.75
6 in this equation represents 24/4
so it would be (24+3)/4
which is 27/4
after simplifying you would get 6 3/4
50% of 25% of x is 96 what is the number
Answer:
the answer is 768
Step-by-step explanation:
because we should first do cross division multiply the denominator with 96 then get the answer
helppppppppppp plsssss
Answer: The zero of a function is the value of y when x equals zero.
Step-by-step explanation: The zero of a function is the value of y when x equals zero. It is also known as an x-intercept. In this case, I believe there is a mistake in this question, as when x equals 0, it shows on the table that it is 6. The zero of the function should be (0,6). They say that the zero is -2, but that is not possible as that would be the y-intercept, where y is zero.
For your homework, I would ask the teacher about the question as it seems to be an error. You can use the response above, since it is correct, but make sure to check with your teacher for review.
sketch the region of integration for the integral z 3 0 z 9 9x2 z 9y 0 f(x, y, z) dz dy dx. rewrite this integral as an equivalent iterated integral in three of the five possible other orders
The integral that is an equivalent iterated integral in three of the five possible other orders is
I= [tex]\int\limits^9_0[/tex] [tex]\int\limits^{9-z}_0[/tex][tex]\int\limits^3_{\sqrt{9-y}[/tex] f(x, y, z)dzdydx
What is meant by integration?An integral in mathematics assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that come from merging infinitesimal data. The process of determining integrals is known as integration.
Consider the integral,
I= [tex]\int\limits^3_0[/tex] [tex]\int\limits^9_{9-x^{2}}[/tex] [tex]\int\limits^{9-y}_0[/tex]f(x, y, z)dzdydx
This implies that the solid is bounded by
0≤z≤9-y
9-x²≤y≤9
0≤x≤3
Therefore, y+z=9, z=0
y=9-x², y=9
x=0, x=3
Now, the region is given by,
y=9-x², y=9, x=3, x=0
The shaded region is the required region of the figure region.
For the next integral,
√9-y≤x≤3
0≤y≤9
I= [tex]\int\limits^9_0[/tex] [tex]\int\limits^3_{\sqrt{9-y}[/tex] [tex]\int\limits^{9-y}_0[/tex]f(x, y, z)dzdydx
Here we have,
y+z =9, z=0
y=9-x², y=9
x=0, x=3
So, √9-y≤x≤3
The projection on the yz plane is,
y+z=0, z=0
y=9
0≤z≤9-y
0≤y≤9
I= [tex]\int\limits^9_0[/tex] [tex]\int\limits^{9-y}_0[/tex][tex]\int\limits^3_{\sqrt{9-y}[/tex] f(x, y, z)dzdydx
Again, 0≤y≤9-z
0≤z≤9
I= [tex]\int\limits^9_0[/tex] [tex]\int\limits^{9-z}_0[/tex][tex]\int\limits^3_{\sqrt{9-y}[/tex] f(x, y, z)dzdydx
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Two time the maller of two number added with nine time the larger i 215. While, ix time the larger added with even time the maller give -89. Find the number
By solving a system of two simultaneous linear equation, it can be calculated that
There are 6 1p coin, 8 2p coin, 5 5p coin and 1 10p coins in the pot
What is simultaneous linear equation?
At first it is important to know about linear equation
Equation shows the equality between two algebraic expressions by connecting the two algebraic expressions by an equal to sign.
A one degree equation is known as linear equation.
Two or more linear equations, which can be solved together to obtain common solution are known as simultaneous linear equation.
Here a system of two simultaneous linear equation needs to be solved
Let the larger number be x and the smaller number be y
Two times the smaller of two number added with nine time the larger is 215.
9x + 2y = 215 ... (1)
Six time the larger added with seven time the smaller give -89.
6x + 7y = -89
Multiplying (1) by 2
18x + 4y = 430 ..... (3)
Multiplying (2) by 3
18x + 21y = -267 ... (4)
Subtracting (4) from (3)
-17y = 697
y = [tex]-\frac{697}{17}[/tex]
y = -41
Putting the value of y in (1)
9x + 2 [tex]\times[/tex] (-41) = 215
9x = 215 + 82
9x = 297
x = [tex]\frac{297}{9}[/tex]
x = 33
The two numbers are 33 and -41
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A researcher wants to do an analysis with an independent variable that is categorical and has three classes. The dependent variable is continuous. Which is test is appropriate?
ANOVA
ANOVA is appropriate because the independent variable is categorical and has three classes. The dependent variable is continuous, so ANOVA can be used to determine if there is a significant difference between the means of the three groups.
ANOVA and appropriate test for analysis of varianceThe appropriate test is an analysis of variance (ANOVA).There are many different types of statistical tests that can be used to analyze data. When choosing a statistical test, it is important to consider the type of data that is being analyzed. In this case, the researcher is looking at an independent variable that is categorical and has three classes. The dependent variable is continuous. In this situation, the best test to use is an analysis of variance (ANOVA).
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Brenda measured the middle school and made a scale drawing. The gym, which is 90 feet long in real life, is 18 inches long in the drawing. What scale did Brenda use for the drawing?
1 inch = 5 feet
The scale used but Brenda is 1 inch = 5 feet
A scale is used to give context to the user about the size of the area that map covers. It is made by converting real-life measurements into physical measurements for quick calculations.
Brenda measured the middle school and made a scale drawing.
The actual length of the gym = 90 ft.
The length she used in her drawing = 18 inches.
So we will now find the scale used for this drawing,
18 inches = 90 ft.
therefore, 1 inch = 90/18 ft.
i.e. 1 inch = 5 ft.
Hence, The scale used but Brenda is 1 inch = 5 feet.
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The total time it will take for one person to complete a task from beginning to end without taking into account holidays, time off, or other project work is known as this.
A. Duration estimate
B. Work effort estimate
C. Bottom-up estimate
D. Parametric estimate
B. Work effort estimate
As per the required total time taken by one person to complete a task from beginning to end without taking into any account holidays, time off, or any other project work is known as Work effort estimate.
As given in the question,
Total time taken by one person to complete the task with conditions:
-: From beginning to end no holiday.
-: No time off
-: no other project work
A. Duration estimate represents the time taken to complete any project.
Incorrect option.
B. Work effort estimate represents the point clearly mentioned to what is required to complete the task.
Here clearly mentioned all the points .
Correct option.
C . Bottom-up estimate represents estimates for individual components of work that are designed to rolled up into the overall estimate.
Incorrect option.
D. Parametric estimate represents the different parameters like total cost , time and resources required for the project.
Incorrect option.
Therefore, for the required total time taken by one person to complete a task from beginning to end without taking into any account holidays, time off, or any other project work is known as Work effort estimate.
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For all values of x, f(x)=2x 1 and g(x)=x^2 solve fg(x)=gf(x)
After solving the values of x are 0,-2.
Given:
f(x)=2x+1 and g(x)=x^2 and f(g(x))=g(f(x))
f(x^2) = g(2x+1)
2(x^2) + 1 = (2x+1)^2
2x^2 + 1 = (2x)^2 + 1^2 + 2*2x*1
2x^2 + 1 = 4x^2 + 1 + 4x
4x^2 - 2x^2 + 4x = 1-1
2x^2 + 4x = 0
2x(x+2) = 0
2x = 0 and x+2 = 0
x = 0 and x = -2
Therefore After solving the values of x are 0,-2.
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The accompanying graph shows the elevation of a
certain region in New York State as a hiker travels
along a trail.
Elevation (ft)
y
1600-
1500
1400-
1300-
1200-
1100-
1000-
900-
5
10
Distance Hiker Travels (mi)
0
State the domain and range in context of the situation
X
Answer: 10 and X and 0
Step-by-step explanation:
Tyler leaves his house to meet a friend at 2:25 p.m. He comes back at 3:10 p.m.
How long was he gone?
Tyler was gone for 45 minutes
Answer: 45 minutes
Step-by-step explanation: First, do 60-25 to find how much time there is till 3. (60-25=35) Then, add 10 because he came back at 3:10, not 3:00.
hope this helps!
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1. Determine where the graph of the function is concave upward and where it is concave downward. (Enter your answers using interval notation. If the answer cannot be expressed as an interval, enter EMPTY or ?.)
g(x) = 5x3 ? 8x
concave upward =
concave downward =
g''(x) > 0 and hence the graph is concave up where x belong to zero to infinity and concave down when x belong to negative infinity to zero
How to find the intervals where a function is concave up and concave down?
In determining intervals where a function is concave upward or concave downward, you first find domain values where f″(x) = 0 or f″(x) does not exist. Then test all intervals around these values in the second derivative of the function. If f″(x) changes sign, then ( x, f(x)) is a point of inflection of the function.
g(x) =5x^3+8x
g'(x) = 15x^2+8
g''(x)= 30x
g''(x)= 0
this implies that
g''(x) > 0 and hence the graph is concave up where x belong to zero to infinity
and concave down when x belong to negative infinity to zero
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TRUE/FALSE: there is a basis of rn consisting of eigenvectors of a, then a is diagonalizable. TRUE/FALSE: if a is diagonalizable, then a is invertible.
If Rn has a basis of eigenvectors of A, then A is diagonalizable.
This statement is true.
If A is diagonalizable, then A is invertible.
This statement is false.
What is diagonalizable matrix?
If there is an invertible matrix P and a diagonal matrix D such that P^-1AP=D, or alternatively A=PDP^-1, then the square matrix A is said to be diagonalizable or non-defective in linear algebra.
If Rn has a basis of eigenvectors of A, then A is diagonalizable.
This statement is true.
In this case we can construct an invertible matrix P.
If A is diagonalizable, then A is invertible.
This statement is false.
It’s invertible if it doesn’t have a zero as eigen value but this doesn’t affect diagonalizabilty.
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What is the diameter of the inscribed circle of the triangle?
The diameter of the inscribed circle of the triangle is
(Type a whole number.)
x+2
2x-7
The value of diameter for the given triangle inscribed in a circle will be 22.
What is a circle?A circle is a geometrical figure which becomes by plotting a point around a fixed point by keeping a constant distance.
In our daily life, we always see circular objects for example our bike wheel.
The longest line which can be drawn inside the circle will be the diameter.
As per the given triangle inscribed a circle.
The length x +2 and 2x - 7 will be the radius of the circle and the sides of the triangle will be the tangent of the circle.
x + 2 = 2x - 7
2 = 2x - x - 7
x = 9
Thus, radius = 9 + 2 = 11
Diameter = 11 x 2 = 22 units.
Hence "The value of diameter for the given triangle inscribed in a circle will be 22".
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The diagram shows a triangle.
All the measurements are in cm.
3x-1
4x + 1
3x
The perimeter of the triangle is 70 cm.
The area of the triangle is A cm².
Work out the value of A.
The area of triangle (A) is 210 cm².
What is the area of the triangle and perimeter of the triangle?
If a, b, and c are the sides of the triangle, then
Perimeter of the triangle = (a + b + c) units.
Area of the triangle = [tex]\sqrt{(s(s - a) (s - b) (s - c)) }[/tex]
The semi-perimeter of the triangle, s = (a + b + c)/2
Let the triangle is ABC,
and AB = 3x - 1, BC = 4x + 1 and AC = 3x.
Perimeter = 70
AB + BC + AC = 70
3x-1 + 4x + 1 +3x = 70
10x = 70
x = 7
AB = a = 3x - 1 = 20
BC = b = 4x + 1 = 29
AC = c = 3x = 21
Now semi-perimeter = s = 70/2
s = 35
Area of the triangle = [tex]\sqrt{(s(s - a) (s - b) (s - c)) }[/tex]
[tex]=\sqrt{35(35-20)(35-29)(35-21)}\\\\\\=\sqrt{35(15)(6)(14)}\\\\=\sqrt{44100}\\\\=210[/tex]
Area of the triangle = 210 square cm.
Hence, the area of triangle (A) is 210 cm².
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PLEASE HELP ASAP ............................
Answer:
There’s no restrictions if I’m not mistaken.
Step-by-step explanation:
You’re correct
Select the correct answer.
Which graph corresponds to the following inequality?
-2x - 3y < 6
The graph that correspond to the inequality is the graph in option D
How to know the corresponding graphsome interpretation on the information from the question include
shading above a line is greater than and shading below is less thandashed lines mean the inequality do not have "equal to"With the equation: -2x - 3y < 6. Bearing less than, using the guide above, we lookout for graph that have dotted line and shaded above the line
The quality described makes the 4th graph the correct option
other consideration is the intercept
the first equation at x= 0, -2x - 3y < 6 y < -2 (0, -2)
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suppose x ~ n(15, 3). between what x values does 68.27% of the data lie? the range of x values is centered at the mean of the distribution (i.e., 15).
For provide normal distribution such that
x ~ n(15, 3), 68.27% of the data lie between the values of x as x= 12 to x= 18 .The range of x-values is centered around the mean of the distribution (that is, 15).
Normal Probability:
This problem uses the Z-score formula to calculate the range such that 68.27% of the data falls within the range. Z-scores are normal scores, plotted on a normal curve with mean 0 and variance 1. The Excel function NORM.S.INV() is used to get the score value.
We have given that
Mean, μ = 15
Standard deviation, σ = 3
P( a <X<b) = 0.6827
P( (a − μ)/(σ < X − μ )/σ <(b− μ)σ) = 0.6827
P ( a- 15) /3 < Z < (b- 15)/3) = 0.6827
P( Z< (b-15)/3) - P( Z< ( a - 15)/3) = 0.6827
1 - P( Z > (b-15)/3) - P( Z< ( a - 15)/3) = 0.6827
(Symmetrical Property)
We know that,
P( Z> (b-15)/3) = P( Z< ( a - 15)/3) ( symmetric)
2 × P( Z< ( a - 15)/3) = 0.3173
P( Z< ( a - 15)/3) = 0.15865
Now,
Excel function for the value of z score:
=NORM.S.INV(0.15865)
(a − 15)/3 = -1.00
=> a-15 = -3
=> a = 12 and b = 15 + 3 = 18
Hence, the values of x are 12 and 18 where 68.27% data lie.
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What do you do when an expression has a negative exponent?.
Answer:
Below
Step-by-step explanation:
Move it to the other side of the fraction ( make it an inverse to change it to a + exponent)
Examples 5^-2 = 1/ ( 5^2)
1 / (x^-23) = x ^23
x^2 y^-3 = x^2 / y^3 etc
How do you write an equation that passes through a point and has a slope?.
Answer:
Use y = mx + b form.
Substitute x, y and m.
Solve for b.
Now you have m, and b.
Use the form again, substitute m and b.
That will give you the generalized equation. You can use it to describe every point on the line.
Wildhorse Company had the following transactions involving notes payable. July 1, 2022 Nov. 1, 2022 Dec. 31, 2022 Feb. 1, 2023 Apr. 1, 2023 Borrows $98,000 from First National Bank by signing a 9-month, 8% note. Borrows $101,000 from Lyon County State Bank by signing a 3-month, 6% note. Prepares adjusting entries. Pays principal and interest to Lyon County State Bank. Pays principal and interest to First National Bank. Prepare journal entries for each of the transactions. (Credit account titles are automatically indented when amount is entered. Do not indent manually. Record journal entries in the order presented in the problem.) Date Account Titles and Explanation Debit Credit (To record accrual of interest from First National Bank) (To record accrual of interest from Lyon County State Bank)
1. The preparation of the journal entries for Wildhorse Company is as follows:
Date Account Titles and Explanation Debit Credit
July 1, 2022: Cash $98,000
Notes Payable $98,000
(To record the issuance of a 9-month, 8% note.)Nov. 1, 2022: Cash $101,000
Notes Payable $101,000
(To record the issuance of a 3-month, 6% note.)2. The preparation of the adjusting entries for Wildhorse Company is as follows:
Date Account Titles and Explanation Debit Credit
Dec. 31, 2022: Interest Expenses $3,920
Interest Payable $3,920
(To record the accrual of interest expense on the 9-month note.)Dec. 31, 2022: Interest Expense $1,010
Interest Payable $1,010
(To record the accrual of interest expense on the 3-month note.)3. The preparation of the journal entries for Wildhorse Company is as follows:
Date Account Titles and Explanation Debit Credit
Feb. 1, 2023: Interest Expense $505
Interest Payable $1,010
Notes Payable $101,000
Cash $102,515
(To record the payment of cash for both interest and the note.)Apr. 1, 2023: Interest Expense $1,960
Interest Payable $3,920
Notes Payable $98,000
Cash $103,880
(To record the payment of cash for both interest and the note.)How are adjusting entries different from other journal entries?Adjusting journal entries are made at the end of the financial period to agree with the accounting records according to the accrual concept of generally accepted accounting principles.
Other journal entries are made to recognize the business transactions in the accounting records as they occur.
Transactions Analysis:July 1, 2022: Cash $98,000 Notes Payable $98,000 (9-month, 8% note)
Nov. 1, 2022: Cash $101,000 Notes Payable $101,000 (3-month, 6%)
Dec. 31, 2022: Interest Expenses $3,920 Interest Payable $3,920
Dec. 31, 2022: Interest Expense $1,010 Interest Payable $1,010.
Feb. 1, 2023: Interest Expense $505 Interest Payable $1,010 Notes Payable $101,000 Cash $102,515
Apr. 1, 2023:Interest Expense $1,960 Interest Payable $3,920 Notes Payable $98,000 Cash $103,880
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Write an equation in slope-intercept form for the line that passes through the given point and is perpendicular to the graph of the equation.
(9, 12); y=13x−4
Answer:
[tex]\sf y = \dfrac{-1}{13}x+ \dfrac{165}{13}[/tex]
Step-by-step explanation:
Equation of line in slope-intercept form: y = mx + bHere m is the slope and b is the y-intercept.
y = 13x - 4
m₁ = 13
Product of slope of the Perpendicular line m * m₁ = -1
[tex]\sf m = \dfrac{-1}{m_1}\\\\m = \dfrac{-1}{13}[/tex]
Equation of the line:
[tex]\sf y = \dfrac{-1}{13}x+b[/tex]
The point (9,12) passes through the line. Substitute the coordinates in the above equation and find the value of 'b'.
[tex]\sf 12 = \dfrac{-1}{13}*9+b\\\\[/tex]
[tex]\sf 12 + \dfrac{9}{13}=b\\\\ \dfrac{156}{13}+ \dfrac{9}{13}=b\\\\\boxed{b= \dfrac{165}{13}}[/tex]
Equation of line:
[tex]\sf y = \dfrac{-1}{13}x+ \dfrac{165}{13}[/tex]
Let X Be A Random Variable That Follows The Normal Distribution With Mean 33 And Variance 10. Answer The Following, Rounding Your Answers To two decimal places(a) What is the probability that X is greater than 39, P (X>39)?(b) What is P (34
The probability that X is greater than 39, P (X>39) is 0.03.
Define probability.A probability is a numerical representation of the likelihood or chance that a specific event will take place. Both proportions ranging from 0 to 1 and percentages ranging from 0% to 100% can be used to describe probabilities.
Given,
Mean = 33
Variance = 10
Standard deviation = 3.16
Z score,
= x - mean/standard deviation
= 39 - 33/3.16
= 1.89
P value from Z table,
P( x< 39) = 0.9712
P( x > 39) = 1 - P(x <39)
P( x > 39) = 1 - 0.9712
P(x > 39) = 0.0288
The probability that X is greater than 39, P (X>39) is 0.03.
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this is built in excel and allows you to perform calculations; you just put the arguments in that the calculation needs.
The correct answer is Option D which is function.
Given that,
You can make computations using this Excel feature by simply entering the necessary inputs.
Range
Syntax
Formula
Function
Answer is Option D
Using the necessary arguments in the right sequence, a function is a predetermined formula that conducts calculations. SUM, AVERAGE, COUNT, etc. are some built-in functions. the arguments in that the calculation needs function and it is selected over Range, Syntax, Formula
So, The correct answer is Option D which is function.
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A sample of 32 observations is selected from a normal population. The sample mean is 66, and the population standard deviation is 5. Conduct the following test of hypothesis using the 0.10 significance level. H0: μ = 68 H1: μ ≠ 68 rev: 10_12_2016_QC_CS-65155 12. value: 1.00 points Required information
a. Is this a one- or two-tailed test?
b. What is the decision rule?
Reject H0 if z < -1.645 or z > 1.645
Reject H0 if -1.645 < z < 1.645
c. What is the value of the test statistic? (Negative amount should be indicated by a minus sign. Round your answer to 2 decimal places.)
Value of the test statistic
d. What is your decision regarding H0?
Reject H0
Fail to reject H0
e. What is the p-value? (Round z value to 2 decimal places and final answer to 4 decimal places.)
p-value
The alternate includes inequality, this is a two-tailed test.
Given:
A sample of 32 observations is selected from a normal population. The sample mean is 66, and the population standard deviation is 5. Conduct the following test of hypothesis using the 0.10 significance level. H0: μ = 68 H1: μ ≠ 68 rev: 10_12_2016_QC_CS-65155 12. value: 1.00 points Required information.
Number of sample observations:
n = 32
Sample mean:
x = 66
Population standard deviation:
σ = 5
Significance level:
α = 0.10
The hypothesis is stated as,
[tex]H_0[/tex] : μ = 68
[tex]H_1[/tex] : μ ≠ 68
Since The alternate includes inequality, this is a two-tailed test.
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