The two example plots of potential energy as a function of position will be Simple Harmonic Oscillator Potential and Potential Well.
Potentials of the following kind can limit a particle to a certain region of space:
1) Simple Harmonic Oscillator Potential: This potential restricts the motion of an attached mass on a spring and restricts the vibration of a heterogeneous molecule about its mean location.
Consequently, an upward parabola will represent the plot for this function. The weak force that this potential energy represents is that. (In this case, the Restoring Force is in charge of changing the particle's potential energy.)
2) Potential Well: Particles are imprisoned in an area with less energy than the potential energy surrounding it, and as a result, they require energy to leave the system. Consequently, a particle Outside of this area of high potential, no assistance is possible.
Protons and neutrons are held within the boundaries of the nucleus by the Strong Nuclear Force, which has an exceptionally high potential. These subatomic particles are imprisoned inside this potential and are therefore unable to leave without assistance.
Potential will be in the form of
V(x)=0 for -L<x<L
V(x)=V for x<-L and x>L
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a 300 g ball with a speed v of 6.0 m/s strikes a wall at an angle of 30o and then rebounds with the same speed and angle. it is in contact with the wall for 10 ms. (a) calculate the impulse experienced by the ball. (b) calculate the average force exerted by the ball on the wall.
a) The impulse experienced by the ball is 1.8 kg·m/s
b) The average force exerted by the ball on the wall is 180 N.
What is Velocity ?
Velocity is a vector quantity that describes the rate of change of an object's position. It is equal to the displacement of an object divided by the time interval over which the displacement occurred. Velocity has both magnitude and direction, and its units are typically meters per second (m/s). The velocity of an object can change over time due to acceleration, and if an object is moving in a circular path, it also has a component of velocity perpendicular to its direction of motion, known as centripetal velocity.
a)
Impulse = change in momentum = mv sin (30) - ( -mv sin30)
= 2mv sin 30
= mv = 0.3 × 6
= 1.8 kg·m/s
b) average force = Impulse/period of application
= 1.8/0.01
= 180 N
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When wind blows, stationary waves can be formed on the aerial wire. Explain how stationary waves are produced and why only waves of specific frequencies can form on the aerial wire
1. Wind produces a disturbance that travels along the wire
2. Wave is reflected at each end
3. Waves interfere
4. Only certain frequencies since fixed ends have to be nodes
Stationary waves are produced when wind produces a disturbance that travels along the wire. This wave is reflected at each end. Then the waves interfere and only certain frequencies since fixed ends have to be nodes.
A wave that maintains its location throughout time is said to be stationary. It can develop in a stationary medium as a result of interference between two waves that have equal wavelengths and are moving in opposite directions but along the same path. They should have almost same amplitude.
Standing waves only occur at certain frequencies as you can only get a stable pattern if there is a whole number of half wavelengths along the length of the oscillator.
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A nurse pushes a 152 kg gurney. What is the normal force acting on the bed?
Type your answer...
Answer:
1489.6 N
Explanation:
The Normal Force (N) is the force of the floor acting up on the gurney, which is equal in magnitude and opposite in direction to the force of the weight (W) of the gurney.
N = W = mg = (152 kg)(9.8 m/s²) = 1489.6 N
7. A 50 kg bicyclist on a 10 kg bicycle speeds up from 5.0 m/s to 10 m/s.
Given:
(a) What was the total kinetic energy before accelerating?
(b) What was the total kinetic energy after accelerating?
(c) How much work was done to increase the kinetic energy of the bicyclist? (Hint : Work = Δ KE = KEf - KEi)
Answer:
a)-750J ; b)-3000J ; c)-2
Explanation:
a)- (K.E.1)=mu²/2=60×25/2=750J
b)-(K.E.2)=mv²/2=60×100/2=3000J
c)-Work done= (K.E.2)-(K.E.1)=2250J
a firefighting crew uses a water cannon that shoots water at at a fixed angle of above the horizontal. the firefighters want to direct the water at a blaze that is 10.0 m above ground level. how far from the building should they position their cannon? there are two possibilities; can you get them both? (hint: start with a sketch showing the trajectory of the water.)
Projectile motion is the motion of an object that has been launched or thrown and is subject to only the acceleration of gravity.
How far from the building should they position their cannon?The two possibilities are:A distance of 10.0 m from the building, with the cannon aimed at an angle of 45° above the horizontal.A distance of 14.1 m from the building, with the cannon aimed at an angle of 60° above the horizontal.This is a problem in projectile motion. The two possible solutions to this problem involve calculating the angle of the cannon relative to the horizontal and the distance the cannon needs to be from the building.A good way to start is to sketch a diagram of the situation. Draw a line representing the trajectory of the water coming from the cannon, and label the horizontal and vertical distances. The horizontal distance is the distance the cannon needs to be from the building and the vertical distance is the height of the blaze.Using trigonometry, the angle of the cannon relative to the horizontal can be found using the vertical and horizontal distances. The angle of the cannon relative to the horizontal is equal to the inverse tangent of the ratio of the vertical and horizontal distances.The distance the cannon needs to be from the building can then be found by using the Pythagorean theorem. The distance from the cannon to the building is equal to the square root of the sum of the squares of the vertical and horizontal distances.Therefore, the two possible solutions to this problem are the angle of the cannon relative to the horizontal and the distance the cannon needs to be from the building.To learn more about Projectile motion refer to:
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A car manufacturer reduces the mass of a car by 250 kg. If the new design is otherwise identical to the old design, how will the new car compare to the old car?
f It will require more fuel to operate.
g It will have a greater gravitational attraction to the road.
h It will need less force to move.
j It will release more gas emissions.
Answer:
h. It will need less force to move.
Explanation:
The reduction in mass of the car means that the car will have less inertia, or resistance to motion. This means that less force will be required to accelerate or maintain motion for the new car design compared to the old car design. Lowering the weight of the car will improve its power-to-weight ratio and thus will be more efficient in terms of fuel consumption and acceleration but this is not directly related to the question.
saturn is 95 times the mass of earth. its volume is about 765 times that of earth. why?
Saturn is 95 times the mass of earth. its volume is about 765 times that of earth because Saturn has a lower density than Earth.
The second-largest planet in the Solar System after Jupiter, Saturn is located six planets from the Sun. With a typical radius of almost nine and a half times that of Earth, it is a gas giant. Despite being nearly 95 times more massive, it barely possesses an eighth of Earth's average density. Saturn's interior is most likely made up of a rocky core, a layer of deep metallic hydrogen, a layer of liquid hydrogen and helium in the middle, and a layer of gaseous material on the outside. Saturn's upper atmosphere contains ammonia crystals, which give the planet a faint yellow tint.The radius of the planet is just as important to the planet's gravity as is the planet's mass. It is inversely related to the square of the radius and immediately relates to the planet's mass. Saturn's radius is 9.5 times that of Earth, despite its mass being 95 times that of Earth.
Therefore, gravity is 95 /(9.5) ²= 1.053 times greater than that of the Earth.
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what is the range of the input voltages that will be coded as: (0011 1011 1011 0001)2.
When given the input code 1111, a 4 bit Digital to Analog converter (DAC) produces an output value of 5 V.
A 10-bit ADC has a maximum range of 1024. (2 to the power of 10). The range's actual numbers are 0 to 1023, but what matters for this discussion is that there are 1024 distinct integers. A pin will detect the presence of a voltage level that is either "high" or "low" on a digital input. These voltage levels are provided to you as the boolean values true for high and false for low when you read a digital pin in your program. Since the resolution of a Flash type ADC equals V/(2N), it has a resolution of V/16 for a 4 bit Flash type ADC.
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the frequency 100 mhz (100 million cycles per second) is right in the middle of the fm dial on your radio. what is the wavelength of these waves?
The wavelength of radio waves with a frequency of 100 MHz is approximately 3 meters.
What is wavelength of radio waves?
Radio waves have a wavelength range from about 1 millimeter to 100 kilometers. The wavelength of an electromagnetic wave can be calculated using the formula:
wavelength (λ) = speed of light (c) / frequency (f)
where the speed of light in a vacuum is approximately 299,792,458 meters per second (c = 3 x 10^8 m/s). So, for a frequency of 100 MHz (100 million cycles per second), the wavelength can be calculated as:
[tex]λ = c / f = 3 x 10^8 m/s / 100 x 10^6 Hz = 3 m[/tex]
So the wavelength of radio waves with a frequency of 100 MHz is approximately 3 meters.
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joe and tom are competing in a 100 m race. partway through the race, joe is 50 m from the finish line and moving at 10 m/s and tom is 51 m from the finish line and moving at 9.75 m/s. if joe maintains his speed and tom begins accelerating, what magnitude of constant acceleration must tom have so that they finish the race in a dead heat
Tom must accelerate at a constant rate of 0.25 m/s2 in order to finish the race in a dead heat with Joe.
What is accelerate?Accelerate is an action or process of speeding up or increasing in rate or amount. It is commonly used to describe an increase in the rate of change of velocity, or the rate of change of a variable such as time, speed, or distance. Acceleration can be generated by a variety of forces and factors, such as gravity, electrical current, centrifugal force, friction, and aerodynamic drag.
Tom must have a constant acceleration of 0.25 m/s2 in order to finish the race in a dead heat with Joe. This can be calculated using the equation for average velocity, vavg = (v1 + v2)/2, where v1 is Joe's velocity and v2 is Tom's velocity. If Joe and Tom both have the same final velocity, then their average velocity must be equal.
50 m / 10 m/s + 51 m / (9.75 m/s + a) = (10 m/s + a)
Solving for a, we get a = 0.25 m/s2. Therefore, Tom must accelerate at a constant rate of 0.25 m/s2 in order to finish the race in a dead heat with Joe.
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A spring of force constant k = 3000 N/m launches 1-kg marbles upward
into a 20-kg block, as shown at right. The spring is compressed 0.2 m from
its natural length and then released. The marble travels upward 0.2 m as
the spring pushes it and then travels upward an additional 0.8 m to strike
the bottom of the block. The block then flies upward into the air.
106) What is the speed of the marble when it strikes the bottom of the
block?
Answer:
The speed of the marble can be found using the equation for kinetic energy, KE = (1/2)mv^2, where m is the mass of the marble and v is its velocity. Since the marble is being launched by the spring, we can use the equation for potential energy, PE = (1/2)kx^2, to find its velocity.
The potential energy of the spring is (1/2)kx^2 = (1/2)(3000 N/m)(0.2 m)^2 = 600 J
The kinetic energy of the marble is KE = (1/2)mv^2, where m = 1kg, so KE = (1/2)(1 kg)(v^2).
So 600 J = (1/2)(1 kg)(v^2)
Solving for v, we get:
v = sqrt(1200 J/ 1kg)
v = sqrt(1200 m^2/s^2/ 1kg)
v = 34.64 m/s.
Explanation:
Explained above
A 100 Watt light bulb has an average life of 2000 hours. How much energy does it consume over its lifetime? Give
your answer in Joules.
The energy it consume over its lifetime as per the given values is [tex]7.20X10^6[/tex] joules.
What is electrical power?When an electrical equipment is used, some electrical energy is consumed in order for it to function.
For instance, an electrical bulb uses electrical energy in order to transform it into light energy. Electric power, then, is the pace at which an electrical equipment uses energy or performs its function.
Here, it is given that,
P = 100 W
t = 2000 h = 2000 x 60 x 60 = [tex]7.20X10^6[/tex]
We know that,
Electric power = E/t.
E = P x t
E = [tex]100X7.2X10^6[/tex]
E = [tex]7.20X10^6[/tex] joules
Thus, the energy will be [tex]7.20X10^6[/tex] joules.
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Darcel runs the simulation for the large version of each object. What can he say in general about the energies of the objects in the simulation as they roll down the incline? (Select all that apply.)"The total energy of the system remains constant and is equal to the gravitational potential energy of the object at the top of the incline.""The total kinetic energy of a rolling object is the sum of the rotational kinetic energy about the center of mass and the translational kinetic energy of the center of mass.""The translational kinetic energy is always greater than the rotational kinetic energy.""The potential energy of the system remains constant, and is equal to the total energy."
12 mvCM2 is the translational kinetic energy. Rotational kinetic energy is equal to 12 I2. The combined translational and rotational kinetic energies of an object in motion determine its total kinetic energy.
A rolling object's combined linear and rotational kinetic energies make up its total kinetic energy: The second equation clearly shows that a rolling item has kinetic energy that is greater than its kinetic energy during translation. Yes, the kinetic energies of rotation and translation are same. The coordinated (non-random) movement of mass with respect to a certain reference frame involves both of them as the energy of motion. 12 mvCM2 is the translational kinetic energy. Rotational kinetic energy is equal to 12 I2.
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Two different rivers have drops that are the same height. In river A, this section of the river is a waterfall. In river B, this section has a hydroelectric dam. In what way does the energy differ between the drops in the two rivers?
The potential energy of the water would be less at the top of the drop in river A than in river B.
The kinetic energy of the water would be less at the bottom of the drop in river A than in river B.
The potential energy of the water would be greater at the top of the drop in river A than in river B.
The kinetic energy of the water would be greater at the bottom of the drop in river A than in river B.
Answer:
The kinetic energy of the same amount of water would be greater at the bottom of the drop of river A (waterfall) than in river B (hydroelectric dam.)
Explanation:
In a uniform gravitational field, the gravitational potential energy of an object is proportional to height relative to the ground. It is given that the top of the two drops are of the same height. As a result, the same amount of water at the top of the drops would have the same amount of gravitational potential energy.
When water moves from the top of the drop to the bottom, gravitational potential energy is converted into kinetic energy.
In the waterfall of river A, the change in potential energy is nearly entirely converted into kinetic energy. However, in river B, some of that potential energy is converted into the mechanical energy of the hydroelectric generators. Since energy is conserved, the same amount water at the bottom of the river B drop would have less kinetic energy.
For the situation described in the previous question, which cart experiences the greater change in kinetic energy? It's impossible to tell without knowing the initial velocities.
Cart 1 experiences the bigger change in kinetic energy, and this change is independent of the cart's beginning velocity.
An object's kinetic energy is the energy it has as a result of motion. Applying force is necessary if we wish to accelerate an object. We have to put forth work to apply a force. After the job is finished, the object will be travelling at a new, constant speed because energy has been transferred to it. The energy of motion, or kinetic energy, can be seen in the movement of an item or subatomic particle. Kinetic energy is present in every moving object and particle.The formula for kinetic energy is stated as K E = 1 2 m v 2. Where m is the body's mass, v is its velocity, and KE is its kinetic energy.
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what type of relationship (direct or inverse) exists between wavelength, frequency, and photon energy? what does a photon energy unit of a joule equal?
The photon energy is directly proportional to the photon's frequency. Similarly, the photon energy is inversely proportional to the wavelength of the photon.
A photon is mainly a packet of light from which many radiations emerge. The energy of the photon is given as E=h.f, E=hc/λ. So the energy E is directly proportional to frequency,f and also to 1/λ. Therefore the energy is directly proportional to frequency and inversely proportional to wavelength.
The photon energy unit of one Joule, Using Planck's equation, the energy of a photon can be determined from its wavelength. The energy of a photon is related to its wavelength by Planck's Equation, E=hc/λ. Inspection of this equation shows that as the wavelength decreases the energy increases, which explains why gamma rays having very small wavelengths are dangerous because of their high energy while radio waves having lengths on the order of meters are relatively harmless.
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when a charged ruler attracts small pieces of (originally uncharged) paper, sometimes a piece jumps quickly away after touching the ruler. why?
When a charged ruler attracts small pieces of paper sometime a piece gems quickly away after touching the ruler because that piece gets neutral after getting touched with ruler.
When we use a charged ruler to attract the small pieces of paper which for originally uncharged, we see that the pieces of paper gets attracted by the ruler but sometime we say that some of the pieces gets quickly away from the ruler after touching it.
This is simply because after touching the charged ruler the electrical neutrality comes into play between the charged particles.
As we know that the neutral objects do not attract each other the pieces of paper gets quickly away.
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Suppose all charges are now doubled (i.e., q1 = -7.8 μC, q2 = 13.6 μC, q3 = 4.6 μC), how will the electric field at P change?Â
Its magnitude will increase by less than a factor of two and its direction will remain the same
Its magnitude will increase by less than a factor of two and its direction will change
Its magnitude will double and its direction will remain the same
Its magnitude will double and its direction will change
If all charges are doubled, the electric field at point P will change such that, Its magnitude will double and its direction will remain the same. Hence, the correct option is (c).
The electric field at a point is proportional to the charge that creates it. If all charges are doubled, the electric field will also be doubled. This means that the magnitude of the electric field will double, but its direction will remain the same since the charges that create the electric field and the distances between them are unchanged. The electric field is a field that exists in space around charged particles, such as electrons and protons. The electric field represents the influence of the charged particles on other charged particles within the field. The electric field can be thought of as a collection of lines of force that originate from the positive charges and end at the negative charges. Therefore, the correct answer is (c) - its magnitude will double and its direction will remain the same.
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Question - Suppose all charges are now doubled (i.e., q1 = -7.8 μC, q2 = 13.6 μC, q3 = 4.6 μC), how will the electric field at P change? choose the correct option.
(a) Its magnitude will increase by less than a factor of two and its direction will remain the same.
(b) Its magnitude will increase by less than a factor of two and its direction will change.
(c) Its magnitude will double and its direction will remain the same.
(d) Its magnitude will double and its direction will change.
if you have a 2 kg object and a 3 kg object separated by a distance of 4 meters, what is the gravitational force drawing them together?
The gravitational force drawing them together is 2.5 × 10⁻¹² N, if the masses of objects are 2 kg and 3 kg and they are separated by 4 meter distance.
Mass of the first object, m₁ = 2 kg
Mass of the second object, m₂ = 3 kg
The distance between them, d = 4 m
Universal gravitational constant, G = 6.67 × 10⁻¹¹ Nm²/kg²
The gravitational force is formulated as, F = Gm₁m₂/d²
F = (6.67 × 10⁻¹¹)(2 × 3)/4²
F = 2.5 × 10⁻¹¹ N
This force is an attractive force and it will be experienced by both the object.
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Please help! Due tonight
How does the thermodynamic laws (0th, 1st, 2nd, 3rd) describe boiling water?
The zeroth, first and second laws of thermodynamics can be applied to a boiling water.
What is thermodynamics?We know that the study of thermodynamics would have to do with the transfer of heat form one object to the other.
In this case, we know that water is boiling, it is going to attain a thermal equilibrium in line with the zeroth law of thermodynamics. Then the transfer of heat between the water and the environment can be accounted for by the first and the second laws of thermodynamics. We can not be able to apply the third laws of thermodynamics to the system of a boiling water.
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A particular car engine provides a force of 700n when a car is moving at its top speed of 40 ms-1
a. Calculate how much work is done by the car’s engine in one second. b. State the output power of the engine.
The car's engine provides a force of 700 N and does 28000 joules of work in one second, with an output power of 28000 W. We can calculate this using work = f.s and power = work/time
a. Work is calculated as the force applied multiplied by the distance traveled in the direction of the force. In the case of the car's engine, the work done in one second can be calculated as follows:
work = force x distance
distance = speed x time (t = 1 second)
work = 700 N x (40 m/s x 1 s)
work = 28000 J
b. Power at what rate work is being performed. It can be calculated as the work done divided by the time taken. In this case, the output power of the engine can be calculated as follows:
power = work/time
power = 28000 J / 1 s
power = 28000 W
So, the engine provides an output power of 28000 watts. This means that in one second, the engine does 28000 joules of work, which is equivalent to 28 kilowatts of power.
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you have a ct circuit connected to a relay. you know the following: the ct resistance is 0.800 ohms total the wires from the ct to relay are 100 ft each and have a resistance of 0.001 ohms/ft the relay has a resistance 0.020 ohms the worst-case fault occurs for a 1lg fault. what is the total resistance you need to consider when evaluating the cts? a. 1.020 ohms b. 0.920 ohms c. 1.000 ohms d. 0.900 ohms
When evaluating the CTS you need to consider the total resistance of 1.020 ohms. Here option A is the correct answer.
The total resistance to consider when evaluating the CTs is given by the sum of the resistance of the CT, the wires, and the relay.
The resistance of the wires can be calculated using the formula R = r * L, where r is the resistance per unit length (0.001 ohms/ft) and L is the total length of the wires (100 ft * 2 = 200 ft).
Plugging in the values, we get:
Rwires = 0.001 ohms/ft * 200 ft = 0.200 ohms
The total resistance to consider is then:
Rtotal = RCT + Rwires + Rrelay
Rtotal = 0.800 ohms + 0.200 ohms + 0.020 ohms
Rtotal = 1.020 ohms
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if you measured vab as 12.0 v, what is the vba?
The required value of Vba, when the value of Vab is given is calculated to be - 12 v.
Vab voltage drop from the node a to b is measured as 12 v.
So, Vba = ?
Vab can be written as Va - Vb. This value is given as 12 v.
Vab = Va - Vb = 12 v ---(1)
Vba voltage drop from the node b to a can be written as Vb - Va. This value is to be found out.
Vba = Vb - Va = -( Va - Vb) = - 12 v ---(2)
Thus, the value of Vba is calculated to be - 12 v.
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at its highest point, what fraction of the initial kinetic energy has been converted to potential energy?
At its highest point, all of the initial kinetic energy has been converted to potential energy.
What is kinetic energy?
Kinetic energy is a form of energy related to the motion of an object. It is the energy associated with the movement of an object, and is calculated by multiplying the mass of the object by the square of its velocity. Kinetic energy is a scalar quantity, meaning that it only has magnitude and does not have a direction. It is often represented by the letter K. When an object is at rest, it has no kinetic energy. However, when it starts to move, it gains kinetic energy. Kinetic energy can be transferred from one object to another in collisions or by the application of a force. In addition, kinetic energy can be converted into other forms of energy, such as thermal energy. Kinetic energy is an important concept in many fields of physics, such as mechanics and thermodynamics.
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How many moons and rings does Uranus have?
The Uranus have 13 faint rings and 27 small moons in the solar system.
What is Uranus all about?Uranus, the third-largest planet in our solar system and the seventh from the Sun, is incredibly chilly and windy. The ice giant spins at a nearly 90-degree angle from the axis of its orbit, encircled by 13 foggy rings and 27 tiny moons. One of the two frost giants in the outer solar system is Uranus (the other is Neptune). A heated, dense fluid comprised of the "icy" substances water, methane, and ammonia made up the vast majority (80% or more) of the planet's mass.
Why is Uranus ringed in 13 places?The age of Uranus' rings is predicted to be less than 600 million years, considering them extremely juvenile. The collisional fragmentation of several former moons that ringed the planets resulted to the Uranian ring system.
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what tire pressures does ford reccommend fo a 2019 ford fusion energi titamium with 18 inch wheels reccommend?
For a Ford Fusion, the suggested tire pressure for the front and rear tires on a set of 18-inch wheels for 2019 Ford Fusion Energi Titanium tires is 32 psi (PSI).
The recommended pressure is typically displayed on a sticker inside the driver's door of newer vehicles. In most cases, the owner's handbook contains the specifications if there isn't a sticker on the door. When the tires are cold, most passenger cars advise 32 to 35 pressures in the tires.
In addition to hybrid ratings of 104 city MPGe and 91 highway MPGe, the 2019 Fusion Energi has gas mileage estimates of 43 city MPG and 41 highway MPG.
In the Ford Fusion Hybrid, the gasoline engine and braking are both used to partially replenish the battery. That entails filling the tank with fuel and starting the car. You can actually plug the Ford Fusion Energi into a power source.
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if the force on the ball increases linearly for 4.00 ms, holds constant for 20.0 ms, and then decreases linearly to zero in another 4.00 ms, what is the maximum force (in n) on the ball?
The maximum force on the ball is 280 N if the force on the ball increases linearly for 4.00 ms
The maximum force on the ball will be the average of the initial and final forces, which is half of the total force applied. The total force applied over the 28.0 ms time period is the area of the triangle formed by the linear increase, constant force, and linear decrease.
The area of the triangle can be found by calculating its height and width, and then multiplying them together. The height of the triangle is the maximum force applied over the 20.0 ms period, and the width of the triangle is 28.0 ms.
Therefore, the maximum force on the ball is (20.0 ms)(28.0 ms)/2 = 280 N.
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how many watts will be radiated from a spherical black body 1115cm in diameter at a temperature of 800c
A spherical black body 1115 cm in diameter at a temperature of 800 K will radiate approximately 5085798.666 W.
The total power radiated from a black body can be calculated using the Stefan-Boltzmann law, which states that the power per unit area (P) emitted from a black body at temperature T is given by:
P = σ x T^4
where σ is the Stefan-Boltzmann constant (5.67 x 10^-8 W/m^2K^4).
The total power radiated from a sphere with diameter D can be calculated as:
P = 4 x π x (D/2)^2 x σ x T^4
Plugging in the values D = 1115 cm, T = 800 K, we get:
P = 4 x π x (1115/2 cm)^2 x 5.67 x 10^-8 W/m^2K^4 x (800 K)^4
P = (4 x π x (1115/2 cm)^2) x (5.67 x 10^-8 W/m^2K^4) x (800^4 K^4)
P = (4 x π x (0.1115 m)^2) x (5.67 x 10^-8 W/m^2K^4) x (800^4 K^4)
Converting the units to watts, we get:
P = 4 x π x (0.1115 m)^2 x 5.67 x 10^-8 W/m^2K^4 x 800^4 K^4
P = 4 x π x 0.0126225 m^2 x 5.67 x 10^-8 W/m^2K^4 x 64000000 K^4
P = 4 x π x 0.0126225 m^2 x 5.67 x 10^-8 x 64000000 W
P = 4 x 3.14 x 0.0126225 m^2 x 5.67 x 10^-8 x 64000000 W
P = 5085798.666 W
So, a spherical black body 1115 cm in diameter at a temperature of 800 K will radiate approximately 5085798.666 W.
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Draw lines to match the wave terms with the correct description.
Amplitude - Highest line
Trough - Lowest point
Crest - Distance between top and rest position
Oscillate - Back and forth motion
Amplitude - Distance between top of crest and rest position
Frequency - Number of waves per second
Wavelength - Distance between two crest or troughs
Compression - Where particles are close together
Rarefaction - Where particles are farthest apart
Incident wave - The wave that moves towards an object
Reflected wave - The wave that moves off an object
Superpose - When waves add or cancel out
Reflect - When a wave bounces off an object
What are the terms that describe waves?A wave is a disturbance that travels through a medium, carrying energy from one place to another without the permanent transfer of matter.
The terms that are used to describe a wave are;
Amplitude
Wavelength
Frequency
Period
Velocity
Crest
Trough
Polarization
Interference
Diffraction.
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correct answer issss ??
Answer:
Bbbbbbbb 12 b/c
Explanation:
i1=6A
i2=v/R
i2=24/4=6A
i1+i2=6+6=12A
