Consider this quadratic equation. x2 3 = 4x which expression correctly sets up the quadratic formula to solve the equation?

Answer:

6

Step-by-step explanation:

Original Equation

(n-1)!

Plug in 4 as n

(4-1)!

Subtract

(3)!

Rewrite using definition of factorial: [tex]a! = a*(a-1)*(a-2)....*1[/tex]

3! = 3*2*1

You don't really have to write the 1, since it doesn't change the value

6

Answer: C

Step-by-step explanation:

[tex]\frac{3x+1}{x+8} \div \frac{x-7}{5x}\\\\=\frac{3x+1}{x+8} \times \frac{5x}{x-7}\\\\=\frac{5x(3x+1)}{(x+8)(x-7)}\\\\=\frac{15x^2 +5x}{x^2 +x-56}[/tex]

Answer:

The coordinates of D is (7, 10)

Explanation:

Let the coordinates of endpoint D be (x, y)

Mid-point formula:

[tex]\sf (x_m, y_m) = (\dfrac{x_1+x_2}{2}, \dfrac{y_1+y_2}{2})[/tex]

Applying formula:

[tex]\sf (-1, \:4) = (\dfrac{-9+ x}{2},\: \dfrac{-2+y}{2} )[/tex]

Comparing found:

[tex]\sf -1 =\dfrac{-9+ x}{2} \quad and \quad \: 4 = \dfrac{-2+y}{2}[/tex]

[tex]\sf 2(-1)+9 =x \quad and \quad \: 2(4)+2 =y[/tex]

[tex]\sf x = 7 \quad and \quad \: y = 10[/tex]

So, coordinates of D is (7, 10)

The answer is (7, 10).

Remember the midpoint formula : [tex]\boxed {M = (\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})}[/tex]

Finding the x coordinate of D

Finding the y coordinate at D

The range of possible values should be (7,34), i.e 7 < x < 34.

The answer must be more noteworthy than 7, else the two sides are less than or rise to to the third. That triangle is outlandish. The reply must moreover be less than 34, since at that point the two other sides would rise to the third, making an impossible triangle.

By the property of triangle, Sum of the lengths of any two sides of a triangle is always greater than the length of the third side.

To prove above propert, let us assume a  ΔABC

extend AB to D in such a way that AD=AC.

In ΔDBC, as the angles opposite to equal sides are always equal, so,

∠ADC=∠ACD

so,

∠BCD>∠BDC

As the sides opposite to the greater angle is longer, so,

BD>BC

AB+AD>BC

Since AD=AC, then,

AB+AC>BC

Hence, sum of two sides of a triangle is always greater than the third side.

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Answer:

7 < x < 34

Step-by-step explanation:

The point that is a solution to the system of inequalities is (5, 0)

The system of inequalities is given as:

y ≤ 2x + 2

y ≥ -5x + 4

Next, we test the given options.

From the list of options, we have

(x, y) = (5, 0)

Substitute (x, y) = (5, 0) in y ≤ 2x + 2 and y ≥ -5x + 4

y ≤ 2x + 2

0 ≤ 2 * 5 + 2

0 ≤ 12 -- this is true

y ≥ -5x + 4

0 ≥ -5 * 5 + 4

0 ≥ -21 -- this is true

Since both results are true, then it means that the point that is a solution to the system of inequalities is (5, 0)

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Complete question

Which point is a solution to the system of inequalities graphed here? y ≤ 2x + 2

y ≥ -5x + 4

A. (1,6)

B. (-6,0)

C. (0,5)

D. (5,0)

The equation of the ellipse having foci  (±2,0) and vertices (±5,0) is [tex]x^{2} /4+y^{2} /21=1[/tex].

Given the foci of ellipse is (±2,0) and vertices (±5,0).

We are required to find the equation of ellipse having foci (±2,0) and vertices (±5,0).

Equation is the relationship between two or more variables that are expressed in equal to form. Equation of two variables looks like ax+by=c.

Equation of ellipse is as under:

[tex]x^{2} /a^{2} +y^{2} /b^{2} =1[/tex],where a is the semi major axis.

We have been given that a=5, c=2.

We know that [tex]c^{2} =a^{2} -b^{2}[/tex]

We have to find the value of b.

b=[tex]\sqrt{a^{2} -c^{2} }[/tex]

=[tex]\sqrt{5^{2} -2^{2} }[/tex]

=[tex]\sqrt{25-4}[/tex]

=[tex]\sqrt{21}[/tex]

Using the values of a and b in the equation [tex]x^{2} /a^{2} +y^{2} /b^{2} =1[/tex]

[tex]x^{2} /(2)^{2} +y^{2}/\sqrt{21} ^{2} =1[/tex]

[tex]x^{2} /4+y^{2} /21=1[/tex]

Hence the equation of the ellipse having foci  (±2,0) and vertices (±5,0) is [tex]x^{2} /4+y^{2} /21=1[/tex].

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Answer: Your answers are

A. 1, 287 ways

B. 154,440 ways

Hope this helped :D

Please mark me brainliest

Answer:

13cm

Step-by-step explanation:

Given the map scale:

1cm on the map : 4km actual distance

4km actual distance : 1cm on the map

1km actual distance : [tex]\frac{1}{4} =0.25cm[/tex] on the map

Therefore,

52km actual distance = 0.25 * 52 = 13cm

Answer:

The answer is x=2 and y=0.

Step-by-step explanation:

The given Equations are:

                    5x-2y=10      ----------------- (i)
                    4y+20=10x   ----------------- (ii)

From equation find the value of x, that is:

         5x=10+2y         (Obtained By adding 2y on both side of Equation (i))

Next divide with 5 on both side to get x:

          x=(10+2y)/5           ------------------ (iii)

Put this value of x in equation (ii):

        4y+20=10((10+2y)/5)

Simplifying the above equation:

         4y+20=2(10+2y)

         4y+20=20+4y

From the above equation the solution of y is not possible.

We can make it 0. So,
         y=0

Put this value of y in equation (iii), to get value of x:

        x=(10+2(0))/5

        x=(10+0)/5

        x=10/5

        x=2

Answer:

11

Step-by-step explanation:

for this question we can look at the whole answer for the square root of 120 which equals 10.9544511501

[tex]\sqrt{120} = 10.9544511501[/tex]

now looking at our answer (10.9544511501) we want to find the nearest WHOLE NUMBER. in the current answer the whole number is 10, followed by many decimals.

10.9544511501

but to find the nearest whole number we have to round the place value BEFORE our whole number. (in this case the 9)

10.9544511501

we can now look at this highlighted section of our equation and think... is 10.9  closer to 11 or 10. well logically, to get to 11 from 10.9 we only have to go up by 0.1, rather than to get to 10, where you have to subtract 0.9.

10.9 + 0.1 = 11

10.9 - 0.9 = 10

But to make it easier, remember the rule:

the place value one place to the RIGHT of what you're rounding to, is what determines the new number. (in this case the .9)

and as any number 5 or above rounds up, we can say that our new number, rounded to the nearest whole number equals 11

10.9 rounded to the nearest whole number = 11

Answer:

x = -1

y = 1

Step-by-step explanation:

Given expressions

1) 2x + 3y - 1 = 0

2) 5x + 2y + 3 = 0

Add 1 on both sides of the 1) equation:

2x + 3y - 1 + 1 = 0 + 1

2x + 3y = 1

Subtract 3 on both sides of the 2) equation:

5x + 2y + 3 - 3 = 0 - 3

5x + 2y = -3

Current System

1) 2x + 3y = 1

2) 5x + 2y = -3

Multiply 2.5 on both sides of the 1) equation

(2.5) 2x + (2.5) 3y = (2.5) 1

5x + 7.5y = 2.5

Current System

1) 5x + 7.5y = 2.5

2) 5x + 2y = -3

Subtract 2) equation from 1) equation

(5x + 7.5y) - (5x + 2y) = 2.5 - (-3)

Get rid of the parenthesis

5x + 7.5y - 5x - 2y = 2.5 + 3

Combine like terms

5x - 5x + 7.5y - 2y = 5.5

0 + 5.5y = 5.5

5.5y = 5.5

Divide 5.5 on both sides

5.5y / 5.5 = 5.5 / 5.5

[tex]\boxed{y=1}[/tex]

Substitute the y-value back to one of the equations to find the x-value

2x + 3y - 1 = 0

2x + 3(1) - 1 = 0

Combine like terms

2x + 3 - 1 = 0

2x + 2 = 0

Subtract 2 on both sides

2x + 2 - 2 = 0 - 2

2x = -2

Divide 2 on both sides

2x / 2 = -2 / 2

[tex]\boxed{x=-1}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

The correct answers to the sample space illustrated will be:

S = {I, L, L, M, P, T, U, Y}.

S = {g, r, b, y, o}.

S = {W, X, Y, Z}.

Flipping a fair, two-sided coin.

Sample space = lemon-lime, lemon-lime, watermelon, watermelon, watermelon, grape, grape, grape, grape, grape.

S = {Joy, Bob, Ben, Peter, John}

A paper bag has five colored marbles. The marbles are red, green, blue, yellow, and orange. The sample space when choosing one marble will be S = {g, r, b, y, o}.

A four-part spinner is spun once and the spinner with four parts labeled W, X, Y, and Z. The sample space for the experiment is S = {W, X, Y, Z}.

The event will have a sample space of S = {h, t} is the flipping a fair, two-sided coin.

The correct sample space for the gumballs in her bag will be sample space = lemon-lime, lemon-lime, watermelon, watermelon, watermelon, grape, grape, grape, grape, grape.

My experiment with 5 or more possible outcomes will be that a teacher wants to randomly give one of his give students a pack of chocolate.

The sample space for the experiment will be based on their names. This will be S = (Joy, Bob, Ben, Peter, John).

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The amount of cash needed to retire baldwin's bond early based on the brokerage will be $5427896.

It should be noted that from the information given, we are to calculate the amount of cash needed to retire baldwin's bond early based on the brokerage.

This will be:

= 6000 + (5756951 × 94.18/100)

= 6000 + 5421896.45

= 5427896

Therefore, the amount of cash needed to retire baldwin's bond early based on the brokerage will be $5427896.

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[tex]\huge\boxed{18\ \text{points}}[/tex]

We'll represent Louise's, Tammy's, Delores's, and Sheryl's point values with [tex]x[/tex], [tex]x+1[/tex], [tex]x+2[/tex], and [tex]x+3[/tex] respectively since each one is 1 point more than the last.

Add all of these values up and set it all equal to [tex]78[/tex].

[tex]x+x+1+x+2+x+3=78[/tex]

Now, simplify.

[tex]4x+6=78[/tex]

Subtract [tex]6[/tex] on both sides.

[tex]\begin{aligned}4x+6-6&=78-6\\4x&=72\end{aligned}[/tex]

Divide both sides by [tex]4[/tex].

[tex]\begin{aligned}\frac{4x}{4}&=\frac{72}{4}\\x&=\boxed{18}\end{aligned}[/tex]

Since Louise's score is [tex]x[/tex], the answer is [tex]18[/tex].

To verify our answer, add the point totals [tex]18[/tex], [tex]19[/tex], [tex]20[/tex], and [tex]21[/tex].

This equals [tex]78[/tex], so we can be sure the answer is correct.

The correct option is: (b)

                                =432.

By employing multiple processes, simplification refers to reducing the expression to a simpler form. Approximation is the process of making something less complicated and hence easier to accomplish or understand, or the object that arises from this process. The mathematical formula is simplified to its nearest value but is not exactly correct.

Therefore, we must follow the order listed above when simplifying expressions. In the example before, we divide 8 by 4 and then add the result to 12 because, according to BODMAS, division (D) comes before multiples (M).

[tex]$3 \cdot 2^{3} \cdot 2 \cdot 3^{2}Calculate exponents $2^{3}: 8$$$=3 \cdot 8 \cdot 2 \cdot 3^{2}$$Calculate exponents $3^{2}: 9$$$=3 \cdot 8 \cdot 2 \cdot 9$$ $3 \cdot 8 \cdot 2 \cdot 9= 432$$$=432$$[/tex]

So. the value will be = 432

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I understand that the question you are looking for is :

Simplify the expression to a single numerical value.

3*2^3*2*3^2

(a)144

(b)432

(c)900

(d)5,184

The given series is diverges according to the P Test.

According to the statement

we have given that the a series and we have to find that the those series is a converges or diverges.

So, For this purpose, we know that the

P-series test to say whether or not the series converges.

So, The given series is

[tex]1 + 1/\sqrt{32} + 1/\sqrt[3]{243 } + 1/\sqrt[4]{1024} + 1/\sqrt[5]{3125}[/tex]

And then

The value of  P becomes P = 5/6 < 1  when we find it using the p series test.

Hence, the p-series diverges

Because according to the p series test, The series converges if, and only if, the power satisfies p>1.

And diverges if, and only if, the power satisfies p<1.

So, The given series is diverges according to the P Test.

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Question:

Use Theorem 9.11 to determine the convergence or divergence of the p-series. 1 + 1/32 squareroot + 1/243 squareroot 3 + 1/1024 squareroot 4 + 1/3125 squareroot 5.

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The number of combinations of balloons that can be chosen is 1716.

Selections and combinations are synonyms. Combinations represent the choosing of items from a predetermined group of items. We're not trying to arrange anything here. We're going to pick them.

Utilizing the combinations formula, it is simple to determine how many distinct groups of r objects each may be created from the provided n unique objects.

Number of red balloons = 12

Number of blue balloons = 8

First, we figure out how to choose from 13 red and 9 blue balloons.

There are 7 balloons left out of the 29 total (i.e. 29 - 13 - 9)

So, n = 7+7-1

n = 13

r = 7

Number of combinations of balloons = [tex]_{13} C_{7}[/tex]

                                                               = 13!/(13-7)!7!

                                                               = 13!/6!7!

                                                               = 1716

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The equation of the given parabola is y2=−20(x+3)

A parabola is a symmetrical open plane curve formed by the intersection of a cone with a plane parallel to its side. The path of a projectile under the influence of gravity ideally follows a curve of this shape.

In general in a parabola, if we have

(y−n)2=4p(x−m),

then the vertex is (m,n)

The axis of symmetry is y=m

The focus is (p+m,n)

The directrix is x=m−p.

Hence, for the given case

p+m=−8

n=0

m−p=2

⇒n=0

m=−3

p=−5

So, the answer will be y2=−20(x+3)

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    Let's say you want to go on a vacation this summer because you finally saved enough money for it. While at the store to buy more hairbands (you just can't seem to figure out where they all went) you see something that you have been wanting for ages. The item is a bit on the more expensive side but you don't know when you will see it again. You decide to buy the item but you had to use some of the money planned for your trip to pay for it. But because you bought the item you now can't do all the activities you wanted on your trip.

The choice of buying the item affected your choices available on your trip.  

Answer:

dependent events

Step-by-step explanation:

Answer:

800÷100 = 8

65×8=520

[tex]\frac{520}{800}[/tex]

another way:

100%-65%=35%

35% = 0.35

800×0.35= 280

800-280=520

another way:

65% = 0.65

0.65×800=520

Hope it helped! :)

Answer:

Step-by-step explanation:

a. d^2 - 7d + 6 = 0

(d - 1)(d - 6) = 0

d - 1 = 0,  d - 6 = 0 therefore:

d = 1,  6.

b, x^2 + 18x + 81 = 0

(x + 9)(x + 9) = 0

x = -9  multiplicity 2.

c   u^2 + 7u - 60 = 0

(u + 12)(u - 5) = 0

u = -12, 5.

The inequality to describe the possible temperature in Bismarck, North Dakota given that t represent temperature is t < 4°F

The inequality signs are;

Let

So

t < 4°F in Bismarck, North Dakota

This means, temperature in Bismarck, North Dakota is less than 4°F

Therefore, t < 4°F is the inequality to represent temperature in Bismarck, North Dakota.

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We've got a negative slope, but it doesn't look steep enough to go through 6 on the y-axis.

So, it's the last option:

y = - 1.25x + 5.75

Hope this helps!

The statements that are true regarding the angles formed by the transversal and parallel lines are:

A. m∠1 = 70°.

B. m∠2 = 110°

C. m∠6 = 70°.

E. m∠9 = 50°

H. m∠16 = 130°

Given the following angle measures formed when two parallel lines ( being cut by two transversals:

Using relevant theorems, let's determine which of the statements are true:

Angles 4 and 1 are vertical angles, therefore they are congruent based on the vertical angles theorem.

m∠4 = m∠1

m∠1 = 70°.

m∠2 = 180 - m∠4 [linear angles theorem]

m∠2 = 180 - 70

m∠2 = 110°

m∠6 = m∠4 [base on the alternate interior angles theorem]

m∠6 = 70°.

m∠9 = 180 - m∠12 [based on the linear angles theorem]

m∠9 = 180 - 130

m∠9 = 50°

m∠16 = m∠12 [based on the corresponding angles theorem]

m∠16 = 130°

The statements that are true are:

A. m∠1 = 70°.

B. m∠2 = 110°

C. m∠6 = 70°.

E. m∠9 = 50°

H. m∠16 = 130°

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Magnitude of the momentum of this system just after the collision = 19.2Kgm/s

Law of conservation of momentum states that the total momentum after the collision must be equal to the total momentum before the collision.

The momentum of each ball is given by:

p = mv

where m is the mass of the ball and v its velocity.

The momentum of ball 1 is:

p = mv

= (3.0 kg)(4.0 m/s)

= 12.0 kg m/s in the eastward direction

The momentum of ball 2 is:

p = mv

= (5.0 kg)(3.0 m/s)

= 15.0 kg m/s in the northward direction

The two momenta are in perpendicular directions, so the magnitude of the total momentum can be found as:

[tex]p = \sqrt{p1^{2} +p2^{2} }[/tex]

[tex]p = \sqrt{12^{2} +15^{2} }\\p = \sqrt{144 + 225} \\p = \sqrt{369}\\ p = 19.2 kgm/s[/tex]

and due to the law of conservation of the momentum, this is also equal to the total momentum after the collision.

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It will take 585 billion years to solve the puzzle tower of Hanoi puzzle.

What is hanoi of tower?

The Tower of Hanoi is a mathematical game or puzzle that uses three rods and a number of disks that can slide onto any rod. It is also known as The Problem of the Benares Temple, the Tower of Brahma, Lucas' Tower, or simply the pyramid puzzle. The disks are stacked on one rod at the start of the problem, the smallest at the top and roughly forming a conical shape.

Using the Tower of Hanoi as little as possible

In one version of the problem, 64 golden disks are being used by Brahmin priests to solve it.

Minimum moves required if you had 64 golden disks [tex]=2^{64}-1[/tex]

The problem would take around 585 billion years to solve if every move took a single second.

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Answer:

Step-by-step explanation:

Opposite angles in a cyclic quadrilateral are supplementary.

  x° = 180° -105°

  x° = 75°

__

The value of the other angle is similarly found:

  w° = 180° -80°

  w° = 100°

__

Additional comment

This result comes from the inscribed angle theorem. That theorem tells you the measure of the inscribed angle is half the measure of the intercepted arc.

The opposite angles of a cyclic quadrilateral intercept the circle at the same two points, dividing the total 360° circle into two parts. Each angle has a measure equal to half its corresponding arc, so the total of the two angles is half the total of the two arcs: 360°/2 = 180°. The angles are supplementary.

The probability of getting exactly one face card is 0.72.

According to the questions two cards are drawn from a deck.

Since, we know that

Total number of cards in a deck = 52

Total number of face cards =  3 × 4 = 12

So, the number of ways of selecting 2 cards from a deck = [tex]^{52} C_{2}[/tex]

And, the total number of ways of  getting exactly one face cards

= [tex]^{12} C_{1} \times ^{40} C_{1}[/tex]  + [tex]^{40} C_{1} \times ^{12} C_{1}[/tex]

= 2[tex]^{40} C_{1} \times ^{12} C_{1}[/tex]

Therefore, the probability of getting exactly one face card

= [tex]\frac{2(^{40} C_{1} \times ^{12} C_{1})}{^{52C_{2} } }[/tex]

[tex]= \frac{2(\frac{40 \times 39!}{1!\times 39!} \frac{12\times 11!}{11!}) }{\frac{52\times 51\times 50!}{2!\times50!} }[/tex]

[tex]= \frac{2(40\times 12)}{26\times 51}[/tex]

[tex]=\frac{2\times 480}{1326}[/tex]

= 0.72

Hence, the probability of getting exactly one face card is 0.72.

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The unit rate of 1/4 book 1/3 hour in books per hour is 3/4 books per hour.

Unit rate is the rate of a quantity in terms of another quantity per unit.

Unit rate(books per hour) = Number of books / Number of hours

= 1/4 ÷ 1/3

= 1/4 × 3/1

= (1×3) / (4×1)

= 3/4 books per hour

Therefore, the unit rate of 1/4 book 1/3 hour in books per hour is 3/4 books per hour.

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Answer: The answer is 87. when you look at the picture each number is one number apart from each other like look at

86, 87, 88, 89, 90, 91

85 + 1  = 86

86 + 1 = 87

87 + 1 = 88

89 + 1 = 90

90 + 1 = 91

Step-by-step explanation: