Consider two point charges, a and b, separated by a distance, d. The total electric potential energy is kab/d.
Given,
The charges of two-point objects are a, and b
The separation distance between them is 'd'.
The total electric potential energy is defined as:
[tex]E = \frac{kq_1q_2}{d}[/tex]
where k = coulomb's constant
= 1/(4πε₀)
= 9 × 10⁹ Nm²C⁻²
As
q₁ = a,
q₂ = b and
d = d
E = (kab)/d
And as there are no other interactions we can conclude E is the total electric potential energy.
Therefore, the total electric potential energy is kab/d.
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a 190 kg hoop rolls along a horizontal floor so that the hoop's center of mass has a speed of 0.140 m/s. how much work must be done on the hoop to stop it?
To stop a 190 kg hoop moving at 0.140 m/s, you need to do work on it equal to the kinetic energy of the hoop.
This can be calculated using the equation KE = 0.5 x m x v2, where m is the mass of the hoop and v is its velocity. In this case, the kinetic energy of the hoop is 0.5 x 190 x (0.140)2 = 11.9 J. Therefore, 11.9 J of work must be done on the hoop to stop it.
To stop the 190 kg hoop, an external force must act on it to reduce its kinetic energy. This can be done by applying friction to the surface of the hoop or by applying an opposing force to the hoop such as a wind resistance force. When the kinetic energy is reduced to zero, the hoop will be at rest.
The amount of work done is equal to the change in kinetic energy of the hoop; that is, the difference between the initial kinetic energy and the final kinetic energy. Since the initial kinetic energy is 11.9 J and the final kinetic energy is 0, the amount of work done on the hoop is 11.9 J.
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a gnat takes off from one end of a pencil and flies around erratically for 31.6 s before landing on the other end of the same pencil. if the gnat flew a total distance of 2.15 m, and the pencil is 0.0563 m long, find the gnat's average speed and the magnitude of the gnat's average velocity.
Average speed is s_avg = v_avg = 0.068 m/s; and magnitude of average velocity is v_avg = 2.15 m / 31.6 s = 0.068 m/s.
To find the gnat's average speed and average velocity, we first need to find the magnitude of the velocity. The average velocity is defined as the total distance traveled divided by the total time spent traveling. In this case, the total distance is 2.15 m, and the total time is 31.6 s.
Magnitude of average velocity:
v_avg = 2.15 m / 31.6 s = 0.068 m/s
The average speed is defined as the total distance traveled divided by the total time spent traveling, regardless of direction. In this case, since the gnat traveled from one end of the pencil to the other, its average speed will be equal to its average velocity, since velocity takes into account direction.
Average speed:
s_avg = v_avg = 0.068 m/s
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A certain spring elongates 9 mm when it is suspended vertically anda block of mass M is hung on it. The natural frequency ofthis mass-spring system is?
A certain spring elongates 9 mm when it is suspended vertically and a block of mass M is hung on it. The natural frequency of the mass-spring system obtained is [tex]5.25\ Hz[/tex].
Given:
Elongation of the spring is given by [tex](x) = 9\ mm = 9 \times 10^{-3}\ m[/tex]
Acceleration due to gravity [tex](g) = 9.8 m/s^2[/tex]
Find the natural frequency (f) of the mass-spring system the steps are given below.
The spring constant (k) is given by:
[tex]k = (M \times g) / x\\k = (M \times 9.8) / (9 \times 10^{-3}) \\k= 1088.89 \times M\ N/m[/tex]
The natural frequency formula is given by:
[tex]f = (1 / 2\pi) \times \sqrt\(k / M)[/tex]
Substitute the value of k as follows:
[tex]f = (1 / 2\pi) \times \sqrt\(1088.89 * M / M\)\\f = (1 / 2\pi) \times \sqrt\(1088.89\)[/tex]
Calculate the square root and the value of frequency is obtained:
[tex]f = (1 / 2\pi) \times 32.995 \\f = 5.25\ Hz[/tex]
Hence, the natural frequency of the mass-spring system is obtained approximately [tex]5.25\ Hz[/tex].
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how do you produce a standing wave in any material?
Standing waves are produced whenever two waves of identical frequency interfere with one another while traveling opposite directions along the same medium.
Standing surge patterns are characterized by certain fixed points along the medium which suffer no relegation.
standing surge patterns are produced as the result of the repeated hindrance of two swells of identical frequence while moving in contrary directions along the same medium. All standing surge patterns correspond of bumps and antinodes. The bumps are points of no relegation caused by the destructive hindrance of the two swells. The antinodes affect from the formative hindrance of the two swells and therefore suffer maximum relegation from the rest position.
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2. a particle starts at at the origin of a coordinate system with a velocity of 1.32 m/s in the negative direction. the particle is acceleration at 1.95 m/s2 in the direction 35 degrees above the axis. (a) at what time does the component of the particle's position equal 3.38 m?
We will have two solutions for t, but we are only interested in the positive one, which is the time that it takes for the particle to reach the x = 3.38 m position. The negative solution corresponds to the time before the particle starts moving.
To find the time at which the component of the particle's position equals 3.38 m, we need to use the kinematic equation for one-dimensional motion with constant acceleration.
The kinematic equation for one-dimensional motion with constant acceleration is:
[tex]x = v0t + 1/2at^2[/tex]
where x is the position of the particle,
v0 is the initial velocity,
t is the time, and
a is the acceleration.
In this problem, the component of the particle's position that we're interested in is in the direction 35 degrees above the x-axis.
We can find the component of the acceleration in that direction by using trigonometry:
[tex]a_x = a \times cos(35)[/tex]
The initial velocity of the particle is v0 = -1.32 m/s in the negative direction, so the component of the initial velocity in the x direction is
[tex]v0_x = -1.32 \times cos(35).[/tex]
We are looking for the time t at which x = 3.38 m.
Plugging in the values, we get:
[tex]3.38 = -1.32 \times cos(35) t + 1/2 \times a_x \times t^2[/tex]
[tex]3.38 = -1.32 \times cos(35) t + 1/2 \times a \times cos(35) \times t^2[/tex]
Solving for t, we can use the quadratic formula:
[tex]t = (-b \pm\sqrt{(b^2 - 4ac)) / 2a[/tex]
where [tex]a = 1/2 \times a \times cos(35)[/tex], b = [tex]-1.32 \times cos(35)[/tex], and c = -3.38.
Plugging in the values, we get:
[tex]t = (-(-1.32 \times cos(35)) ± \sqrt((-1.32 \times cos(35))^2 - 4 \times 1/2 \times a \times cos(35) \times -3.38)) / (2 \times 1/2 \times a \times cos(35))[/tex]
[tex]t = (1.32 \times cos(35) ± \sqrt((1.32 \times cos(35))^2 + 4 \times 1/2 \times 1.95 \times cos(35) \times 3.38)) / (2 \times 1/2 \times 1.95 \times cos(35))[/tex]
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in annealing, cite three sources of internal residual stresses in metal components. what are two possible adverse consequences of these stresses?
Internal residual stresses in metal components can arise from several sources during the annealing process. These sources are non uniform heating and cooling, phase transformations and plastic deformation.
Sources of internal residual stress are:
Non-uniform heating and cooling: During annealing, the rate of heating and cooling can vary across the metal component, leading to residual stresses caused by thermal expansion and contraction.Phase transformations: When a metal undergoes phase changes, such as solid-state transformations, the volume of the material can change, leading to residual stresses within the component.Plastic deformation: Plastic deformation can occur during the annealing process, leading to residual stresses caused by the redistribution of the material's internal structure.Adverse consequences of these residual stresses include:
Distortion or warping: Residual stresses can cause the metal component to deform, resulting in distorted or warped parts that are no longer suitable for their intended use.Reduced fatigue life: Residual stresses can increase the risk of fatigue failure, particularly in components that are subjected to cyclic loading. This can reduce the overall life of the component, leading to unexpected failure.Learn more about residual stresses here:
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a constant torque of 4 nm is applied to an inertial load of 0.05 kg m2. what is the angular acceleration rate?
The angular acceleration rate of the load is found to be 80
The inertia load of the constant torque of 4Nm is 0.05 Kgm².
We know, the relation between the torque, the angular acceleration and the moment of inertia is given as,
T = IA
Where,
T is the torque applied on the load,
I is the moment of inertia of the load,
A is the angular acceleration of the load,
Putting all the values of the respective terms is,
We get,
4 = 0.05A
A = 80 rad/s²
So, the angular acceleration rate of the load is 80 rad/s².
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. rationalize the following observations. a. aerosol cans will explode if heated. b. you can drink through a soda straw. c. a thin-walled can will collapse when the air inside is removed by a vacuum pump. d. manufacturers produce different types of tennis balls for high and low elevations.
a. Aerosol cans contain a mixture of a volatile liquid and a compressed gas, usually a propellant. When heated, the pressure inside the can increases, leading to a risk of explosion.
b. A soda straw works by creating a partial vacuum, which draws the liquid up the straw and into your mouth. The straw acts as a tube to convey the liquid from one place to another.
c. Thin-walled cans are not designed to withstand a vacuum. When the air inside is removed, the pressure outside the can becomes greater than the pressure inside, causing the can to collapse.
d. Different types of tennis balls are produced for different elevations because the air pressure at high elevations is lower than the air pressure at low elevations. This affects the bounce of the ball and requires manufacturers to produce different types of tennis balls to ensure the ball performs consistently at different elevations.
What is meant by Rationalizing Observations?Rationalizing observations refers to explaining and interpreting observations in a logical and systematic way, based on scientific knowledge and principles. It involves understanding the underlying mechanisms, causes, and relationships between the observations and the physical phenomena being studied.
The goal of rationalizing observations is to provide a coherent explanation that can help to make predictions and understand the observations in a deeper and more meaningful way.
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creep occurs when you subject a part to a constant load, producing an initial deflection followed by a slow increase in strain with time. T/F
The statement stands for, True i.e. creep occurs when you subject a part to a constant load, producing an initial deflection followed by a slow increase in strain with time.
Creep is a phenomenon that occurs when a material is subjected to a constant load, causing an initial deflection followed by a slow increase in strain with time. This slow increase in strain can result from the material's internal structural changes and the motion of dislocations within the material's lattice structure. Creep is commonly observed in materials that are subjected to high stresses over an extended period of time, such as in the case of mechanical components in high-temperature applications, such as engines and turbines. The rate of creep can be influenced by factors such as temperature, stress, and the type of material.
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You observe a ball that moves (34.5 + 0.1) cm in (19.84 +0.01) s. What is the observed speed of the ball (best estimate and most probable uncertainty)? (speed = distance / time) Oa. (1.62 +0.01) cm/s b. (1.74 +0.01) cm/s c. (2.09 + 0.01) cm/s d. (1.739 + 0.005) cm/s d. (2.094 +0.008) cm/s
The required speed of the ball when distance and time are given is calculated to be (1.74 ± 0.01) cm/s.
The formula for speed is speed = distance/time. Using the given values, we can calculate the observed speed of the ball as follows:
Distance is given as (34.5 ± 0.1) cm.
Time is given as (19.84 ± 0.01) s.
Speed = distance / time = (34.5 ± 0.1)/(19.84 ± 0.01)
Using the most probable uncertainty (±0.5 times the smallest uncertainty), we can estimate the uncertainty in the speed calculation as follows:
Uncertainty in distance = 0.1 cm
Uncertainty in time = 0.01 s
Uncertainty in speed = (uncertainty in distance) / (time) ± 0.5 × (smallest uncertainty)
= (0.1) / (19.84) ± 0.5 × (0.01)
= 0.0051 ± 0.005 cm/s
Therefore, the observed speed of the ball is (1.74 ± 0.01) cm/s.
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A bicyclist accelerates from her initial velocity at a rate
of 0.50 meters per second squared for 4.0 seconds.
During this time, she covers a distance of 44 meters.
What is the bicyclist's initial velocity?
Answer:
We can use the equation:
distance = initial velocity * time + (1/2) * acceleration * time^2
We know that the distance is 44 meters, the acceleration is 0.50 meters per second squared and the time is 4.0 seconds.
By substituting these values into the equation:
44 = initial velocity * 4.0 + (1/2) * 0.50 * 4.0^2
Solving for initial velocity, we get:
initial velocity = (44 - 2) / 4 = 42 / 4 = 10.5 meters per second.
So, the bicyclist's initial velocity is 10.5 meters per second.
How much force is required to stop a 0.25 Kg ball moving at 5 m/s during a time of 0.01
seconds?
The force required to stop a 0.25 Kg ball moving at 5 m/s during a time of 0.01 seconds is 2.5 Newtons.
How much force is required to stop a 0.25 Kg ball moving at 5 m/s during a time of 0.01 seconds?This can be calculated using the equation F = m*a, where m is the mass of the object (0.25 Kg) and a is the acceleration (5 m/s/0.01 seconds).Thus, F = 0.25 * 5 = 2.5 N.The force required to stop a 0.25 Kg ball moving at 5 m/s during a time of 0.01 seconds is 12.5 N. This is a type of impulse force, which is a force that acts over a period of time rather than a single instantaneous force. Impulse forces are typically used to change momentum. In this case, the impulse force is being used to reduce the momentum of the ball from 5 kgm/s to 0 kgm/s in the space of 0.01 seconds.This is achieved by applying a force of 12.5 N over the 0.01 second period. This is known as an impulse force because it is applied over a period of time, rather than in a single instantaneous action. This type of force is often used in physics problems to determine the momentum of a moving object, as it allows for the calculation of the force needed to stop the object in a certain amount of time.To learn more about impulse force refer to:
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what is the total mechanical energy of a satellite of mass m orbiting the earth at a distance equal to 2 times the earth's g
The total mechanical energy of a satellite of mass m orbiting the earth at a distance equal to 2 times the radius of the earth is -GMm/4R.
Let the mass of the Earth = M
Mass of the satellite = m
Let the velocity of the satellite around the Earth, = v
Distance from the Earth's = 2R
We know that centrifugal force is balanced by the gravitational force for orbiting motion of an object
mv²/2R = GMm/(2R)²
v² = GM/2R
So kinetic energy of the satellite will be. K.E = 0.5mv² = GMm/4R
Potential energy of an object in space is formulated as P.E = -GMm/2R
Mechanical energy = K.E + P.E
Mechanical energy = GMm/4R + -GMm/2R
= -GMm/4R
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How is it possible for an object that experiences no net magnetic force to experience a net magnetic torque?
a. If equal but opposite magnetic forces act at separate points on an object, and do not lie along the same line, then the forces will sum to zero but the torques generated by them will not. b. Only circular currents, such as current loops, experience magnetic torques without a net magnetic force. The circular geometry ensures that the magnetic forces always cancel, whereas the torques generated by them always add. c. It is not possible. A net torque requires a net force. d. If the object can carry current in opposite directions, like a coaxial cable, it can experience a net magnetic torque without a net magnetic force.
The answer is A because equal but opposite magnetic forces that apply at different points on an item and do not lie along the same line will result in equal but opposite torques that will not cancel out.
The item will spin even when the center of mass does not accelerate if all the forces acting on it combine to create a net torque if they do not act at the same spot. A non-uniform magnetic field causes various forces to arise at various spots on the needle, resulting in a net force. Additionally, net torque results from this. If the magnetic field is uniform, there is no net force acting on a loop as a result of the magnetic field. However, the net force is not zero if the field is not uniform. Near a magnet or a coil or loop carrying electricity, the magnetized substance feels net force.
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A city of 6000 population has an average water use of 110 gallons per person per day. Compute the average total rate of use in cubie feet per second and in gallons per minute. (1 eu ft- 7.48 gal.)
The average total rate of water use in the city is 6.23 cubic feet per second and 583.33 gallons per minute, which can be calculated using simple arithmetic operations and unitary method.
To compute the average total rate of use in cubic feet per second and in gallons per minute, we need to first find the total amount of water used per day in the city. This can be done by multiplying the population by the average water use per person:
6000 * 110 gallons/person/day = 660000 gallons/day
To find the average total rate of use in cubic feet per second, we need to convert the daily usage to cubic feet and divide it by the number of seconds in a day:
660000 gallons/day * (1 cubic foot/7.48 gallons) = 87809.6 cubic feet/day
87809.6 cubic feet/day / (24 hours/day * 3600 seconds/hour) = 6.23 cubic feet/second
To find the average total rate of use in gallons per minute, we simply divide the daily usage by the number of minutes in a day:
660000 gallons/day / (24 hours/day * 60 minutes/hour) = 583.33 gallons/minute
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What is the magnitude and direction of the net force?
The net force is the vector sum of all forces exerted on an object. The net force, or, to put it another way, the sum of all the forces, is the outcome of the fact that a force is a vector and that two forces of equal size and opposite direction cancel each other out.
What are the net force's directions?The net force always mirrors the acceleration's direction. The net force acting on an object traveling in a circle at a constant speed is pointed in the direction of the circle's center. Such a direction is referred to as centripetal.
What is the net force's strength?The formula below demonstrates how the mass of an item multiplied by its acceleration determines the size of the net force acting on it. An object is not speeding and is in a state known as equilibrium if the net force acting on it is zero.
Why is net force important?The total force acting on an object is referred to as the net force. Mass can be accelerated by a net force. A body, whether it is at rest or in motion, is subject to another force. The term "net force" is used to describe a system that is under the influence of numerous forces.
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what is the electric potential difference between two points a distance d apart in a uniform electric field e?
A continuous electric field can be created by aligning two sizable, flat, conducting plates in a straight line. V = E d represents the electrical potential difference in an even electric field.
What might separate these two points, if at all?It takes work to move a unit positive charge from one location to the other, hence the potential difference between two points is equivalent to that amount of labor.
What does class 10th mean by a probable difference between two points?Possibly existing variation between any two points The amount of labor required to move a unit positive charge along any path between two places in the electric field is defined as the distance that can be traveled by the charge without accelerating.
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what will cause the mass displayed on a digital scale to fluctuate
Instability of the surface, external vibrations, and electromagnetic interference can cause the mass displayed on a digital scale to fluctuate.
Instability of the surface, external vibrations, and electromagnetic interference are factors that can impact the accuracy of a digital scale's readings. If the surface the scale is placed on is not stable, the reading may fluctuate even if the weight of the object being measured does not change.
Similarly, vibrations from external sources such as foot traffic or machinery can cause the scale to vibrate, leading to fluctuating readings. Electromagnetic interference from electronic devices such as cell phones or computers can also impact the accuracy of the scale's readings.
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Which tatement accurately decribe the flow of heat in each example• Heat will flow from Object 1 to Object 2 in example 2 and 4, and heat will flow from Object 2 to Object 1 in example 1 and 3. • Heat will flow from Object 1 to Object 2 in example 1 and 3, and heat will flow from Object 2 to Object 1 in example 2 and 4. O- Heat will flow from Object 1 to Object 2 in Example 3, and heat will flow from Object 2 to Object 1 in example 1, 2, and 4. • Heat will flow from Object 1 to Object 2 in example 1, 2, and 4, and heat will flow from Object 2 to Object 1 in Example 3
Option 4 is correct, which is heat will flow from Object 1 to Object 2 in example 1, 2, and 4, and heat will flow from Object 2 to Object 1 in Example 3.
Alternative solutions go against the fundamental rule of thermodynamics.
What is heat?Heat is one of the vital sources of energy for the continued existence of life on earth, according to the definition of heat. According to thermodynamics, heat is transferred between bodies as a result of temperature differences.
For many purposes, including cooking, ironing, transportation, leisure, etc., we use heat energy. This kind of energy is essential to nature as well. The gradient produced by the uneven heating of various regions determines the occurrence of the wind, rain, seasons changing, etc.
Heat is energy that is transferred into or out of a thermodynamic system via a mechanism involving microscopic atomic modes of motion or the corresponding macroscopic properties.
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Solar energy, in the form of electromagnetic waves, travels into Earth's atmosphere by radiation. One type of wave that reaches Earth's atmosphere can damage our skin and potentially cause skin cancer. What is this type of wave?
A. ultraviolet
B. radio
C. infrared
D. gamma
The type of radiation that reaches Earth's atmosphere can damage our skin and potentially cause skin cancer is Ultraviolet radiation.
option A.
What is ultraviolet ray?Ultraviolet radiation is a form of non-ionizing radiation that is emitted by the sun and artificial sources, such as tanning beds.
Solar energy, in the form of electromagnetic waves, travels into Earth's atmosphere by radiation. One type of wave that reaches Earth's atmosphere can damage our skin and potentially cause skin cancer is Ultraviolet radiation.
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If an aluminum crimp connector were used to connect a copper wire to a battery, what would you expect to happen? A. Only the copper wire will corrode. B. Only the aluminum connector will corrode. C. Both will corrode. D. Nothing
It offers an excellent mechanical and electrical connection crimping. so, only the copper wire will corrode
The general rule for crimping all kinds of connectors is to remove a small amount of wire insulation. Then, insert the wire and crimp the connector into an appropriately sized opening in the jaws. It is advised that the connector be re-crimped with the next-smallest hole in the jaws of non-ratcheting pliers.
The term "cold weld" is occasionally used to describe a good crimp connection because it is gas tight and won't wick. It offers an excellent mechanical and electrical connection so, only the copper wire will corrode and, like the solder method, can be used on solid or stranded conductors.
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tiger woods hit a golf ball at a velocity of 80 m/s. the head of his club was in contact with the 50 g ball for 0.40 ms. what is the average force acting on the golf ball during impact?
The average force acting on the golf ball during impact is 200,000 Newtons.
The average force acting on the golf ball during impact can be calculated using Newton's second law of motion. The equation is F = ma, where F is the force, m is the mass of the object, and a is the acceleration. Since the mass of the golf ball is 50g (0.05 kg), and the acceleration is determined by the velocity of the ball and the time it is in contact with the club (80 m/s divided by 0.0004 s), the average force acting on the golf ball during impact is 200,000 Newtons.
F = ma
m = 50g or 0.05kg
a = v/t
a = 80/0.0004 ( as velocity "v" = 80 m/s and time "t" = 0.40ms which is equal to 0.0004 s ).
Put the values of "a" and "m" in equation F = ma
therefore, F = 0.05 ( 80/0.0004 )
F = 200,000 N
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a landscape engineer has 200 feet of border to enclose a rectangular pond. what dimensions will result in the largest pond?
The required dimensions which will result in the largest pond are calculated to be l = 50 feet, b = 50 feet.
The perimeter of the rectangular pond is given as 200 feet.
Mathematically, we know perimeter = 2( l + b)
So, 2( l + b) = 200
( l + b) = 100
Breadth = 100 - length
The area of rectangle = l b
A = l (100 - l) = -l² + 100 l
The function has a maximum and the parabola opens down if the x² coefficient is negative.
A = -x² + 100 x
We have a < 0, so f(x) has a maximum,
we know that, f(-b/2a) = maximum
l = -b/2a = -100/2(-1) = 50
b = 100 - l = 100 - 50 = 50
The dimensions for maximum area is given as, l = 50 feet, b = 50 feet.
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A person is playing a carnival game where they throw a 0.50 kg ball forward, with
a velocity of 21.0 m/s, to hit a 0.20 kg bottle sitting on a shelf. When the ball
makes contact with the bottle, it bounces back causing the bottle to fly off at 3.0
m/s. What is the velocity of the ball after it hits the bottle?
The velocity of the ball after it hits the bottle is 19.8 m/s.
What is the final velocity of the bottle?The final velocity of the bottle after the collision is determined by applying the principle of conservation of linear momentum as follows;
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
where;
m₁ is the mass of the ballm₂ is the mass of the bottle u₁ is the initial velocity of the ballu₂ is the initial velocity of the bottlev₁ is the final velocity of the ballv₂ is the final velocity of the bottle( 0.5 x 21 ) + ( 0.2 x 0 ) = 0.5v₁ + (3 x 0.2 )
10.5 = 0.6 + 0.5v₁
0.5v₁ = 9.9
v₁ = 9.9 / 0.5
v₁ = 19.8 m/s
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a cylindrical object has a uniform rectangular cross section of bx2b and density of p/3 where p is the density of water
The volume and mass of a cylindrical object with a uniform rectangular cross section of b x 2b and a density of p/3, where p is the density of water, may be computed.
as follows: r2 * h = volume where r denotes the cylinder's radius and h its height. r2 * h * (p/3) = Mass = Volume * Density Because the cylinder's cross section is a rectangle with dimensions b x 2b, the radius of the cylinder may be determined as r = (b / 2). Substituting this into the volume equation yields: Volume = * (b/2)2 * (h) And the mass equation is as follows: * (b/2)2 * h * (p/3) = mass We may use these equations to compute the volume and mass of the cylindrical object. Given the size of its cross section and its density in relation to water.
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orbiting in a potential dominated by the mass of a central black hole, what is the mass of the black hole?
.The supermassive black hole at the center of the Milky Way, Sagittarius A*, is 4.3 million solar masses.
what is the mass of the black hole?
A typical stellar-class of black hole has a mass between about 3 and 10 solar masses. Supermassive black holes exist in the center of most galaxies, including our own Milky Way Galaxy. They are astonishingly heavy, with masses ranging from millions to billions of solar masses.The matter density needed to form such a black hole is extremely high – about 2 x 1019 kg per cubic metre. That's more extreme than the density of an atomic nucleus.Well, even though black holes are extreme in many ways, they don't have infinite mass and it's mass that determines the force of their gravity. Some black holes known as stellar black holes. have about the amount of mass that very massive stars do.To learn more about black hole refers to:
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where will the proton signal appear, in hertz, if the sample is analyzed with a 200.0 ‑mhz instrument?
The proton signal will show at 200.0 MHz if the sample is evaluated using a 200.0 MHz equipment. The instrument's frequency is the same as the frequency of the proton signal.
Hertz (Hz) is the standard unit of measurement for expressing frequency, which is the number of cycles of a periodic signal per second. The proton signal is visible as a resonance peak at a certain frequency that is proportional to the magnetic field experienced by the protons in the sample in Nuclear Magnetic Resonance (NMR) spectroscopy. A conventional NMR experiment involves placing the sample in a magnetic field and exposing it to a radiofrequency (RF) pulse with the same frequency as the proton signal. When the RF pulse is removed, the protons return to their original state, and the energy absorbed during the RF pulse is released and recorded by the NMR equipment In general, the proton signal emerges at a frequency proportionate to the intensity of the magnetic field. Higher proton frequencies arise from stronger magnetic fields.
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Suppose you conduct one experiment and find that the E = mc3, rather than the historically accepted formula, E = mc2. What should you do next?
a. Test a new variable
b. Share your findings
c. Apply your results to a new experiment
d. Repeat the exact same procedure
Suppose you conduct one experiment and find that the E = mc3, rather than the historically accepted formula, E = mc2. Then you have to repeat the exact same procedure
E = mc2. The most well-known equation in the world, but what does it actually mean? "Mass times the square of the speed of light equals energy." The equation's most fundamental claim is that energy and mass (matter) are interchangeable; they are just different manifestations of the same thing.
The answer to the question "Why does E=mc2?" is thus straightforward and elegant: "Because everything is always traveling through spacetime." By seeing the situation correctly, we can understand that the rest energy that we weren't expecting is simply a result of the time component of that motion.
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describe what happens when you bring your hand close to the tape. does it matter which side of the tape you approach?
When you bring your hand close to tape, an attractive force called the van der Waals force is generated between your hand and the tape. The van der Waals force is a result of the temporary dipole moments that occur when electrons in the hand and electrons in the tape interact with one another.
It does not matter which side of the tape you approach. The van der Waals force is a result of the temporary dipole moments that occur between the electrons in your hand and the electrons in the tape, regardless of the orientation of your hand or the tape. The strength of the van der Waals force will depend on the distance between your hand and the tape, as well as the type of materials and the properties of the surfaces involved. The closer your hand is to the tape, the stronger the van der Waals force will be.
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If you heat a thin, circular ring so its temperature is twice what it was originally, the ring's hole a. becomes four times smaller.
b. becomes smaller by an unknown amount.
c. becomes two times smaller.
d. remains the same size.
e. becomes larger.
When temperature increases its area also increases because of thermal expansion as the total size of the ring increases its hole size will also increase and it becomes larger. Therefore option E is correct.
When a thin, circular ring is heated and its temperature increases, thermal expansion occurs. The expansion of the ring is a result of the increased kinetic energy of its molecules, causing them to move apart and the ring to expand.
Since the hole is part of the ring, it will also undergo thermal expansion. As the ring expands, both its circumference and diameter increase. Consequently, the hole in the ring will also expand in size.
Therefore, when the temperature of a thin, circular ring is doubled, the hole in the ring becomes larger.
This is because the increase in temperature leads to thermal expansion, causing both the ring and its hole to increase in size.
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If you heat a thin, circular ring so its temperature is twice what it was originally, the ring's hole it becomes larger.
Thus, The hole in a thin, round ring does not shrink four times if its temperature doubles when heated. The material's characteristics and thermal expansion coefficient affect how much the hole changes in size.
Due to the particles' increased kinetic energy when a substance is heated, it usually expands. The diameter of the hole and the ring's circumference are both impacted by this expansion.
It is impossible to accurately estimate the change in hole size based only on the temperature doubling without that knowledge.
Thus, If you heat a thin, circular ring so its temperature is twice what it was originally, the ring's hole it becomes larger.
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