constraints aregroup of answer choicesquantities to be minimized in a linear programming model.restrictions that limit the settings of the decision variables.input variables that can be controlled during optimization.quantities to be maximized in a linear programming model.

The solution to the equation −18 − 6k = 6(1 + 3k) in terms of k is k = -3/4.

A statement that affirms the equivalence of two expressions joined by the equals symbol "=" is known as an equation.

Your steps are correct, and here's the solution to the equation:

−18 − 6k = 6(1 + 3k)

To solve for k, we first use the distributive property to remove the parentheses:

−18 − 6k = 6 + 18k

Then, we simplify the equation by combining like terms:

−18 − 6k + 6k = 6 + 18k + 6k

-18 = 24k

Finally, we isolate k by dividing both sides by 24:

-18/24 = 24k/24

-3/4 = k

Therefore, the solution to the equation −18 − 6k = 6(1 + 3k) in terms of k is k = -3/4.

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The complete question is:

Solve for the value of k in the equation:

-18 - 6k = 6(1 + 3k)

where k is an unknown constant.

After using the formula: z = (x - μ) / σ , the z-score for Allison's weight is 0.5.So, the z-score for Allison's weight is 0.5.

To find the z-score for Allison's weight, we use the formula:
z = (x - μ) / σ

where x is Allison's weight (145 lbs), μ is the mean weight of females (135 lbs), and σ is the standard deviation (20 lbs).

Substituting the values, we get:

z = (145 - 135) / 20
z = 0.5

Therefore, the z-score for Allison's weight is 0.5.

To calculate the z-score for Allison's weight, we can use the following formula:

z-score = (Allison's weight - mean weight) / standard deviation

Plugging in the given values:
z-score = (145 lbs - 135 lbs) / 20 lbs = 10 lbs / 20 lbs = 0.5

So, the z-score for Allison's weight is 0.5.

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The hypothesis test is a one-tailed test, since we are testing for a specific direction (greater than 72%).

An assumption is said to as a hypothesis when it is supported by evidence. Any investigation that turns the research questions into predictions must start here. Variables, the population, and the relationships between the variables are among its constituent parts.

The hypotheses for the test are:

H0: p = 0.72 (null hypothesis)

Ha: p > 0.72 (alternative hypothesis)

The claim is that the proportion of college students who recycle is greater than 72%, which corresponds to the alternative hypothesis.

The hypothesis test is a one-tailed test, since we are testing for a specific direction (greater than 72%).

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The curve f(x) is f(x) = -2x + 3.

Given that dy/dx = -2, we can integrate both sides with respect to x to obtain:

dy/dx = -2

dy = -2 dx

Integrating both sides, we get:

y = -2x + C

where C is the constant of integration. To find the value of C, we use the initial condition f(0) = 3:

y = -2x + C

f(0) = 3

-2(0) + C = 3

C = 3

Thus, the equation of the curve is:

y = -2x + 3

Therefore f(x) is -2x + 3

We can sketch the curve by plotting a few points. For example, when x = 0, y = 3 (as required by the initial condition). When x = 1, y = 1. When x = -1, y = 5. We can also note that the slope of the curve is always -2, meaning that the curve is a straight line with a negative slope.

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As x approaches infinity, the limit of function [(2x-1)(3-x)]/[(x-1)(x+3)] is equal to -2.

What is function?

In mathematics, a function is a relation between a set of inputs (called the domain) and a set of possible outputs (called the codomain) with the property that each input is related to exactly one output.

To find the limit of [(2x-1)(3-x)]/[(x-1)(x+3)] as x approaches infinity, we need to consider the highest power of x in the numerator and the denominator.

In the numerator, the highest power of x is [tex]x^2[/tex], which comes from the product of (2x)(3). In the denominator, the highest power of x is also [tex]x^2[/tex], which comes from the product of (x)(x).

Thus, we can use the rule that when the highest powers of x in the numerator and denominator are equal, the limit is the ratio of the coefficients of these highest powers. Therefore:

lim [(2x-1)(3-x)]/[(x-1)(x+3)]

= lim [([tex]-2x^2[/tex] + 7x - 3)/([tex]x^2[/tex] + 2x - 3)]

= lim [-2 + (7/x) - (3/[tex]x^2[/tex])] / [1 + (2/x) - (3/[tex]x^2[/tex])]

= -2/1

= -2

Therefore, as x approaches infinity, the limit of [(2x-1)(3-x)]/[(x-1)(x+3)] is equal to -2.

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Answer:

a) multiply

b) 16

Step-by-step explanation:

a) To convert a smaller unit of measurement into a larger unit, multiply because more of a smaller unit is required to cover up a larger measurement.

b) We know that there are 16 ounces in a pound, which is the unit rate.

If "3 marks" are awarded for each "correct-answer" and "-1 marks" for each "incorrect-answer", then the total score of Varun in quiz is 47.

Out of the 25 questions in the quiz, Varun attempted all of them, which means he has answered 25 questions in total.

Out of the 25 questions, Varun answered only 18 correctly, which means he answered 7 questions incorrectly.

Therefore, the total score for his correct answers would be : 18 × 3;

⇒ 54 marks,

The total score for his incorrect answers would be : 7 × (-1) = -7;

Varun did not leave any question "un-attempted", so he did not gain or lose any marks for those questions.

Varun's total score in the quiz would be : (Score for correct answers) + (Score for incorrect answers)

⇒ Total Score = 54 + (-7) = 47 marks,

Therefore, Varun's total score in quiz is 47 marks.

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The given question is incomplete, the complete question is

In a Mathematics quiz, the total number of questions are 25. According to the marking scheme, 3 marks are given for every correct answer and -1 marks for every incorrect answer, and 0 for questions not attempted.

Varun attempts all questions but only 18 of his answers are correct. What is his total score in the quiz?

It is true that every invertible square matrix can be written as a product of elementary matrices. because, it depends on whether you are talking about invertible square matrices or all square matrices.

An elementary matrix is a matrix that can be obtained from the identity matrix by performing a single elementary row operation (such as swapping two rows, multiplying a row by a scalar, or adding a multiple of one row to another).

Moreover, any matrix that can be expressed as a product of elementary matrices is invertible.

However, not every square matrix is invertible, and so not every square matrix can be written as a product of elementary matrices. For example, the zero matrix cannot be written as a product of elementary matrices since it is not invertible.

So, it depends on whether you are talking about invertible square matrices or all square matrices.

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Answer:

24 coins

Step-by-step explanation:

We give the dimes a unknown number like y since the nickels are twice as much we give it 2y we multiply the numbers with their value and form an equation like 2y×5+y×10=160 find the value of y then get value of 2y+y to get the number of coins

the probability of choosing exactly 5 red marbles when 12 marbles are chosen at random is approximately 0.028.

This is a hypergeometric probability problem .

The total number of ways to choose 12 marbles from 27 is:

${{27}\choose{12}} = \frac{27!}{12!15!} = 10,!626,!766$

The number of ways to choose 5 red marbles and 7 blue marbles is:

$ {{15}\choose{5}}\cdot{{12}\choose{7}} = \frac{15!}{5!10!}\cdot\frac{12!}{7!5!} = 300,!450$

So the probability of choosing exactly 5 red marbles is:

$P(\text{5 red}) = \frac{300,!450}{10,!626,!766} \approx 0.028$

what is probability?

Probability is the measure of the likelihood or chance of an event occurring. It is a quantitative measure that ranges from 0 to 1, where 0 indicates an impossible event and 1 indicates a certain event.

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If the point (3, -2) were reflected across the y-axis what would be the new y-coordinate is same as before, which is -2.

If a point (x, y) is reflected across the y-axis, its x-coordinate becomes its opposite (-x), while its y-coordinate remains the same.

In this case, the point is (3, -2). If we reflect this point across the y-axis, its x-coordinate will become its opposite, which is -3. The new coordinates of the reflected point will be (-3, -2).

Therefore, the new y-coordinate is still -2, as the point is only being reflected across the y-axis and not moving up or down in the y-direction. The change is only in the x-coordinate, which becomes its opposite.

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Radioactive particles 2000  the sample have 80 years from today.

We have the information:

There is 2000 radioactive particles in a sample.

and,  your grandmother measured 4000 radioactive particles in it 80 years ago.

We have to find the samples of radioactive particles present it in 80 years from today.

By the definition of Half line,  The half line of the item is 80 years.

=> 80 years from now, means that another half life is achieved means, 2000 will reduced to half on decay.

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Answer:

Step-by-step explanation:

To match each term to the corresponding probability of it snowing tomorrow, we can use the following definitions:

Likely means that the event has a high chance of happening, so the probability is close to 1. For example, P(snow) = 0.9 means that it is very likely to snow tomorrow.

Unlikely means that the event has a low chance of happening, so the probability is close to 0. For example, P(snow) = 0.1 means that it is very unlikely to snow tomorrow.

Certain means that the event will definitely happen, so the probability is exactly 1. For example, P(snow) = 1 means that it will surely snow tomorrow.

Impossible means that the event will never happen, so the probability is exactly 0. For example, P(snow) = 0 means that it will not snow tomorrow at all.

Using these definitions, we can match each term to the corresponding probability as follows:

Likely: P(snow) > 0.5

Unlikely: P(snow) < 0.5

Certain: P(snow) = 1

Impossible: P(snow) = 0

The total cost for all the foam and vinyl needed to build the play structure would be $419.91

Let's say the play structure is a cube with each side measuring 36 inches. The total volume of the foam needed to build this cube would be:

V = (36 in)³ = 46,656 in³

Since the structure is a cube, the surface area would be:

A = 6 × (36 in)² = 7,776 in²

The cost for the foam would be:

46,656 in³ × $0.008/in³ = $373.25

The cost for the vinyl would be:

7,776 in² × $0.006/in² = $46.66

Total cost will be:

$373.25 + $46.66 = $419.91

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When it comes to printing full-color pictures, it usually involves using the CMYK color model which stands for cyan, magenta, yellow, and black.

These colors are combined in different amounts to create a wide range of colors and shades. Therefore, the answer to your question is three plus black. The colors cyan, magenta, and yellow are combined to produce a wide range of colors, while the black is added to enhance contrast and to create darker tones.

This combination of colors provides a more accurate and vibrant representation of the original picture. It is important to note that there are other color models used for printing such as RGB (red, green, and blue) which is used for digital displays, but for printing purposes, CMYK is the most common.

In conclusion, full-color pictures are printed using three colors (cyan, magenta, and yellow) plus black to enhance contrast and create darker tones. This combination of colors provides a more accurate and vibrant representation of the original picture.

This model consists of four ink colors: cyan (C), magenta (M), yellow (Y), and key (black, K). These four inks are combined in various proportions to produce a wide range of colors in the final print. Therefore, the correct answer would be four colors (CMYK), including black.

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This method of completing the square can be used to solve any quadratic equation, even if the coefficients a, b, and c are not whole numbers.

Completing the square is a method used to solve quadratic equations in the form of ax^2 + bx + c = 0, where a, b, and c are constants. To use this method, follow these steps:

1. Move the constant term (c) to the other side of the equation, so that you have ax^2 + bx = -c.

2. Divide both sides of the equation by the coefficient of the x^2 term (a), so that you have x^2 + (b/a)x = -c/a.

3. Take half of the coefficient of the x term (b/a), square it, and add it to both sides of the equation, so that you have x^2 + (b/a)x + (b/2a)^2 = (b/2a)^2 - c/a.

4. Simplify the left side of the equation by factoring it as (x + b/2a)^2.

5. Take the square root of both sides of the equation, remembering to include both the positive and negative square roots.

6. Solve for x by subtracting b/2a from each side of the equation.

This method of completing the square can be used to solve any quadratic equation, even if the coefficients a, b, and c are not whole numbers. It is a useful tool to have in your mathematical toolbox, as it can simplify complicated equations and help you find the solutions you need.

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For this function, A is -2/3, B is 0 and C is 2/3.

To find the critical numbers of the function f(x) = 9x + 4[tex]x^{-1}[/tex] , we need to find the values of x where the derivative of the function is equal to zero or undefined.

The derivative of f(x) is:

f'(x) = 9 - 4[tex]x^{-2}[/tex] = 9 - 4/[tex]x^{2}[/tex]

To find where the derivative is equal to zero, we set f'(x) = 0 and solve for x:

9 - 4/[tex]x^{2}[/tex]  = 0

4/[tex]x^{2}[/tex]  = 9

[tex]x^{2}[/tex] = 4/9

x = ±2/3

Therefore, the critical numbers of f(x) are x = 2/3 and x = -2/3.

To find the intervals where the function is not defined, we need to look for values of x that make the denominator of the expression 4[tex]x^{-1}[/tex]  equal to zero. In this case, the function is not defined at x = 0.

Now we need to determine the sign of the derivative in each of the intervals (−∞,A], [A,B), (B,C], and [C,∞).

For x < -2/3, f'(x) is negative because 4/[tex]x^{2}[/tex]  is positive and 9 is greater than 4/[tex]x^{2}[/tex] . Therefore, the function is decreasing on the interval (−∞,−2/3).

For −2/3 < x < 0, f'(x) is still negative because 4/[tex]x^{2}[/tex]  is positive and 9 is still greater than 4/[tex]x^{2}[/tex] . Therefore, the function is decreasing on the interval (−2/3,0).

For 0 < x < 2/3, f'(x) is positive because 4/[tex]x^{2}[/tex]  is positive and 9 is less than 4/[tex]x^{2}[/tex] . Therefore, the function is increasing on the interval (0,2/3).

For x > 2/3, f'(x) is still positive because 4/[tex]x^{2}[/tex]  is positive and 9 is still less than 4/[tex]x^{2}[/tex] . Therefore, the function is increasing on the interval (2/3,∞).

Finally, the function is not defined at x = 0, so the interval [A,B) is (−∞,0) and the interval (B,C] is (0,∞).

Therefore, we have:

A = -2/3

B = 0

C = 2/3

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The confidence interval for proportion of adults who liked video game is (0.575091,0.8915756 ) from sample. It has a parameter 65%.

Number of enrolled students in STAT during year 2020 = 70

The population of adults that is 18 or above in 2020 = 258.3 million

Number of students are classmates= 30

Out of 30, number of students who like video game = 22

level of significance = 0.95

Let p denote the proportion of students in sample who liked video games. it is p = 22/30 = 0.733.

Using the distribution table, value of z for 95% is equals to the 1.96. From the formula of confidence interval, [tex]CI = p ± z\sqrt{ \frac{ p( 1 - p)}{n}}[/tex]

[tex]= 0.733 ± \sqrt{ \frac{0.733( 1 - 0.733)}{30}}[/tex]

= (0.575091, 0.8915756), the lower limit and upper limit of interval. This interval contains 65% which is population parameter. Hence, required value is (0.575091, 0.8915756).

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To find the probability of rolling a sum of either 3 or 7, we need to find the number of ways we can get each sum and divide by the total number of possible outcomes. For a sum of 3, the only way to get this is by rolling a 1 and a 2. There are two ways to arrange this: 1-2 and 2-1.


Probability = (Number of desired outcomes) / (Total number of possible outcomes)
Probability = 8 / 36

We can simplify the fraction by dividing both numerator and denominator by their greatest common divisor, which is 4:

Probability = (8/4) / (36/4)
Probability = 2/9

So, the probability of rolling a sum of 3 or 7 with two dice is 2/9, or approximately 0.222222 as a decimal rounded to the nearest millionth.

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The probability that more boys than girls are chosen is approximately 39.67%.

To determine the probability that more boys than girls are chosen from a classroom with 10 boys and 12 girls, we need to consider the possible ways this can happen. There are two scenarios:

1. 3 boys and 2 girls are chosen.
2. 4 boys and 1 girl are chosen.

First, calculate the total number of ways to choose 5 students from 22 (10 boys + 12 girls) using the combination formula: C(n, k) = n! / (k! * (n-k)!)

C(22, 5) = 22! / (5! * 17!) = 26,334

Now, calculate the probabilities for the two scenarios:

1. 3 boys and 2 girls are chosen:
C(10, 3) = 10! / (3! * 7!) = 120
C(12, 2) = 12! / (2! * 10!) = 66
Total combinations: 120 * 66 = 7,920

2. 4 boys and 1 girl are chosen:
C(10, 4) = 10! / (4! * 6!) = 210
C(12, 1) = 12! / (1! * 11!) = 12
Total combinations: 210 * 12 = 2,520

Add the combinations for both scenarios: 7,920 + 2,520 = 10,440

Now, calculate the probability:

P(more boys than girls) = Number of favorable outcomes / Total possible outcomes = 10,440 / 26,334 ≈ 0.3967 or 39.67%

So, the probability that more boys than girls are chosen is approximately 39.67%.

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Using the amplitude of the motion, After approximately 0.89 seconds, the bobber will be at the midpoint between its high point and low point for the first time.

The bobber will be at the midpoint between its high point and low point for the first time after 1.5/4 seconds.

To find the answer, we need to first find the amplitude of the motion, which is half of the total distance the bobber travels, so amplitude = 1.5/2 = 0.75 inches.

Next, we can use the formula for the period of a simple harmonic motion: T = 2π√(m/k), where T is the period, m is the mass, and k is the spring constant. In this case, we can use the formula T = 3 seconds.

Solving for k, we get k = (4π²)m/T². Since we don't know the mass of the bobber, we can assume it's negligible and use k = 4π²/T². Plugging in T = 3 seconds, we get k = 4π ²/⁹.

Now we can use the formula for the displacement of a simple harmonic motion at time t: x = Acos(ωt), where A is the amplitude and ω is the angular frequency (ω = 2π/T). We want to find when the displacement x = 0.5A (i.e. the midpoint between the high and low points), so we can solve for t:

0.5A = Acos(ωt)

0.5 = cos(2πt/3)

2πt/3 = arccos(0.5)

t = 3arccos(0.5)/2π

t ≈ 0.89 seconds

So after approximately 0.89 seconds, the bobber will be at the midpoint between its high point and low point for the first time.

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Therefore, the 90% confidence interval for Student 1 is (89.61, 105.19). Therefore, the 90% confidence interval for Student 2 is (84.96, 131.24).

To calculate the 90% confidence interval for the mean number of customers served within 5 minutes for each student, we need to use the formula:

CI = X ± (tα/2 * s/√n)

where X is the sample mean, s is the sample standard deviation, n is the sample size, and tα/2 is the critical value from the t-distribution with (n-1) degrees of freedom at the desired confidence level (in this case, 90%).

For Student 1:

X = (102 + 86 + 98 + 109 + 92)/5

= 97.4

s = √([(102-97.4)² + (86-97.4)² + (98-97.4)² + (109-97.4)² + (92-97.4)²]/(5-1))

= 7.94

n = 5

tα/2 = 1.895 (from t-distribution table with 4 degrees of freedom at 90% confidence level)

CI = 97.4 ± (1.895 * 7.94/√5)

= 97.4 ± 7.79

= (89.61, 105.19)

For Student 2:

X = (81 + 165 + 97 + 134 + 92 + 87 + 114)/7

= 108.1

s = √([(81-108.1)² + (165-108.1)² + (97-108.1)² + (134-108.1)² + (92-108.1)² + (87-108.1)² + (114-108.1)²]/(7-1))

= 30.18

n = 7

tα/2 = 1.895 (from t-distribution table with 6 degrees of freedom at 90% confidence level)

CI = 108.1 ± (1.895 * 30.18/√7)

= 108.1 ± 23.14

= (84.96, 131.24)

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The horizontal asymptote is y = 0 and the vertical asymptotes are x = -1 and x = -5. The graph of g(x) can be sketched as given in the picture.

Asymptotes are lines that a curve approaches but never touches. There are two types of asymptotes:

Horizontal asymptote: A horizontal asymptote is a horizontal line that a curve approaches as the value of x becomes very large or very small. In other words, if the curve approaches a specific y-value as x approaches infinity or negative infinity, then that y-value is the horizontal asymptote.

Vertical asymptote: A vertical asymptote is a vertical line that a curve approaches but never touches. A vertical asymptote occurs when the denominator of a function becomes zero and the numerator does not.

Here we have

The horizontal and vertical asymptotes of the reciprocal squared function that has been shifted left 3 units and down 4 units.

The reciprocal squared function is given by:

=> f(x) = 1/(x²)

To shift this function left 3 units and down 4 units, we need to modify the equation as follows:

=> g(x) = 1/((x+3)²) - 4

=> g(x) = 1/x² + 6x + 9 - 4

=> g(x) = 1/x²+6x+5

To find the horizontal asymptotes, consider what happens to the function as x approaches infinity and negative infinity.

As x approaches infinity, the x² term dominates the denominator, so we can approximate g(x) as 1/x².

Thus, the horizontal asymptote is y = 0.

As x approaches negative infinity, the x² term still dominates the denominator, and so g(x) also approaches 0.

Thus, the horizontal asymptote is also y = 0.

To find the vertical asymptotes, we need to look for values of x that make the denominator of g(x) equal to zero. We can factor the denominator as (x + 1)(x + 5),

so the vertical asymptotes occur at x = -1 and x = -5.

Therefore,

The horizontal asymptote is y = 0 and the vertical asymptotes are x = -1 and x = -5. The graph of g(x) can be sketched as given in the picture.

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Answer:

$391.2 per owner

Step-by-step explanation:

find the total price of the items and divide it by five

For a computer software store, the estimate the probability that a person who walks into the store will buy something is equals to the 0.22. So, option(c) is right one.

Probability is the chances of occurrence of an event. It is calculated by dividing the favourable outcomes to the total possible outcomes.

We have, John runs a computer software store. Number of people walked by his store = 120/ day

Number of people came in his store = 53

Number of people who buy something from the store = 26

We have to determine the estimate the probability that a person who walks into the store will buy something. Let E be an event such that a person walk and buying something from store. Here, total possible outcomes for occurrence an event = 120

Favourable outcomes for event E = 26

So, probability that a person who walks into the store will buy something, P(E) =

[tex] \frac{ 26}{120}[/tex] = 0.21666 ~ 0.22

Hence, required value is 0.22.

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Complete question:

john runs a computer software store. he counted 120 people who walked by his store in a day, 53 of whom came into the store. of the 53, only 26 bought something in the store. estimate the probability that a person who walks into the store will buy something. round your answer to the nearest hundredth. group of answer choices

a) 0.66

b) 0.49

c) 0.22

d) 0.44

e) none of these choices

Answer:

see explanation

Step-by-step explanation:

ratio of sides = 8 : 5 : 7 = 8x : 5x : 7x ( x is a multiplier )

given the perimeter = 480 , then

8x + 5x + 7x = 480

20x = 480 ( divide both sides by 20 )

x = 24

then

8x = 8 × 24 = 192

5x = 5 × 24 = 120

7x = 7 × 24 = 168

the sides of the triangle are 192 inches, 120 inches, 168 inches

-------------------------------------------------------------------------------------------

ratio of angles = 8 : 15 : 17 = 8x : 15x : 17x ( x is a multiplier )

the sum of the angles in a triangle = 180° , then

8x + 15x + 17x = 180

40x = 180 ( divide both sides by 40 )

x = 4.5

Then

8x = 8 × 4.5 = 36

15x = 15 × 4.5 = 67.5

17x = 17 × 4.5 = 76.5

the angles in the triangle are 36°, 67.5°, 76.5°

Answer:

2, 3, 1, 3, 5, 4---->1, 2, 3, 3, 4, 5

The median is 3.

The value of y in the right triangle is 27.3 cm.

A right angle triangle is a triangle that has one of its angle as 90 degrees.

The sum of angles in a triangle is 180 degrees.

Therefore, let's apply Pythagoras's theorem to find the sides of the right triangle as follows:

c² = a² + b²

where

Therefore,

20.2² - 16.4² = h²

408.04 - 268.96 = h²

h = √677

h = 26.0192236625

h = 26.0 cm

Let's find y as follows:

y² = 26² + 8.2²

y = √676 + 67.24

y = √743.24

y = 27.2624283585

y = 27.3 cm

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Answer:

Part A:

The price of product A is determined by the function f(x) = 12500(0.82)^x. To determine whether the price is increasing or decreasing, we can look at the behavior of the function as x increases.

When x increases by 1 year, the value of the function is:

f(x+1) = 12500(0.82)^(x+1) = 10250(0.82)^x

To find the percentage change in price per year, we can calculate:

[(f(x+1) - f(x)) / f(x)] * 100%

= [(10250(0.82)^x - 12500(0.82)^x) / 12500(0.82)^x] * 100%

= -0.16 * 100%

= -16%

Therefore, the price of product A is decreasing by 16% per year.

Part B:

To determine which product recorded a greater percentage change in price over the previous year, we need to calculate the percentage change in price for each product from year to year.

For product B, the percentage change in price from year to year is:

   From year 1 to year 2: [(f(2) - f(1)) / f(1)] * 100% = [(3136 - 5600) / 5600] * 100% = -43.14%

   From year 2 to year 3: [(f(3) - f(2)) / f(2)] * 100% = [(1756.16 - 3136) / 3136] * 100% = -44.06%

   From year 3 to year 4: [(f(4) - f(3)) / f(3)] * 100% = [(983.45 - 1756.16) / 1756.16] * 100% = -43.99%

For product A, we already determined that the percentage change in price per year is -16%.

Therefore, product A recorded a smaller percentage change in price over the previous year compared to product B.

Step-by-step explanation:

there are two values of x in the interval where the instantaneous rate of change of is equal to the average rate of change of over the interval.

To find the average rate of change of over the interval , we need to calculate the slope of the line passing through the two endpoints of the interval.

The slope of the line passing through the points and is given by:

( - )/( - ) = ( -3 - 3)/(1 - (-1)) = -6/2 = -3

Therefore, the average rate of change of over the interval is -3.

To find how many values of in the interval have instantaneous rate of change equal to the average rate of change, we need to find the derivative of :

f'(x) = 3x^2 - 3x - 3

Setting f'(x) equal to the average rate of change, we get:

3x^2 - 3x - 3 = -3

Simplifying the equation, we get:

3x^2 - 3x = 0

Factoring out 3x, we get:

3x(x - 1) = 0

Therefore, the solutions are x = 0 and x = 1.

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