Answer:
Age Frequency Cumulative Frequency
Less than 30 28 28
Less than 40 37 28 + 37 = 65
Less than 50 1 4 65 + 14 = 79
Less than 60 3 79 + 3 = 82
Less than 70 4 82 + 4 = 86
Less than 80 1 86 + 1 = 87
Less than 90 1 87 + 1 = 88
Step-by-step explanation:
Given:
The Frequency Distribution table of ages of best actresses when award was won
To find:
Construct the cumulative frequency distribution
Solution:
In order to construct cumulative frequency distribution for the given data, each frequency from above table is added to the sum of the previous frequencies. For example, frequency for Less than 40 is 37 and the previous frequency (less than 30) is 28 so in order to calculate cumulative frequency 28 i.e. previous frequency is added to 37 (frequency of less than 30) and the cumulative frequency is 65. The complete table is given above.
You can use both the t statistic and the z statistic to test hypotheses about the mean of population. The test that uses the t statistic is typically referred to as a t test, while the test that uses z statistic is commonly called a z test.
Which of the following statements are true of the t statistic? Check all that apply.
a. If you know the population standard deviation, you should use the t statistic.
b. The t statistic could be considered as an estimated z statistic.
c. The t statistic provides a relatively poor estimate of z with small sample sizes.
d. The formula for the t statistic is t = (M - s) / SM.
Answer:
An apple a day keeps the doctor away
Step-by-step explanation:
Type in the answer
Its gonna be right
if the probability of drawing a red card from a box is 3/8, what are the odds against drawing a red card from the box
Answer: 5/8
Step-by-step explanation:
Simply do 8/8(1)-3/8 to get 5/8
Hope it helps <3
There were 3 squirrels and 18 acorns on Josh’s back porch. What was the ratio of squirrels to acorns? Enter your answer in reduced form. (100 points!!)
Answer:
1:6
Step-by-step explanation:
Answer:
Step-by-step explanation:
1:6
Which of the following equations are identities? Check all that apply.
A. sec x=
CSC X
1
B. CSCX=
sinx
1
C. tanx=
secx
D. tanx=
sin x
COS
Answer:
B. CSCX= sinx / 1
D. tanx= sin x / COS x
Step-by-step explanation:
A. sec x= 1/cos(x)
CSC X / 1 = sin(x)
B. CSCX
sinx / 1 = csc(x)
C. tanx= sin(x) / cos(x)
secx = 1 / cos(x)
D. tanx= sin(x) / cos (x)
sin (x) / cos(x)
The correct option is (D). tanx = sinx/cosx
Option (D). is correct.
What is Trigonometry?The trigonometric function, which comprises the sine, cosine, tangent, cotangent, secant, and cosecant. Can be used for practical applications.
As per the given data:
We are given some trigonometric identities, and we have to find out which of the given identities in the options are correct.
(A). secx = cscx/1
This is incorrect, as secx = 1/cosx
(B). cscx = sinx/1
This is incorrect, as cscx = 1/sinx
(C). tanx= secx
This is incorrect, as tanx = sinx.secx
(D). tanx = sinx/cosx
This is correct as, tanx = sinx/cosx
The correct option is (D). tanx = sinx/cosx
Hence, The correct option is (D). tanx = sinx/cosx
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X/h + 1 = -2
The value of x is terms of h is __.
Type the correct answer in the box. Use numerals instead of words.
Answer:
x = - 3h
Step-by-step explanation:
Given
[tex]\frac{x}{h}[/tex] + 1 = - 2 ( subtract 1 from both sides )
[tex]\frac{x}{h}[/tex] = - 3 ( multiply both sides by h )
x = - 3h
Step-by-step explanation:
[tex] \frac{x}{h + 1} = - 2[/tex]
Cross multiply
We have
-2(h + 1) = x
Expand the terms in the bracket
We have the final answer as
x = -2h - 2
Hope this helps you
Rent for a 3 bedroom apartment is regularly $936 per month. Apartment management is now offering one month free for a 12 month lease. If you sign a one year lease and apply the free month equally across months, how much is your monthly lease amount?
Answer:
$858
Step-by-step explanation:
Monthly lease amount is ⇒ $936
Considering one moth free, yearly rental would be
⇒ 11*$936= $10296The monthly lease amount :
⇒ $10296 / 12 = $858The test statistic of z=1.92 is obtained when testing the claim that p≠0.767. a. Identify the hypothesis test as being two-tailed, left-tailed, or right-tailed. b. Find the P-value. c. Using a significance level of α=0.10, should we reject H0 or should we fail to reject H0?
Answer:
it is a two tailed test
The p - value for z=1.92 is 0.9726
Using a significance level of α=0.10, We fail to reject H0. The calculated z value lies out side the Zα value.
Step-by-step explanation:
For p≠0.767
Taking null hypothesis as p≠0.767 and alternate hypothesis as p =0.767
H0 :p≠0.767 Ha :p≠0.767 it is a two tailed test
The p - value for z=1.92 is 0.9726 from the table.
Using a significance level of α=0.10
z value for 0.10 for two tailed test is ± 1.645
Z >zα
1.92> ± 1.645
Using a significance level of α=0.10, We fail to reject H0. The calculated z value lies out side the Zα value.
What is the range of the function f(x)=3/4|x|-3
Range is [tex]y\in[-3,+\infty)[/tex].
Hope this helps.
The exact heights of different elephants Choose the correct answer below. A. The data are continuous because the data can only take on specific values. B. The data are discrete because the data can take on any value in an interval. C. The data are discrete because the data can only take on specific values. D. The data are continuous because the data can take on any value in an interval.
Answer:
Option d: The data are continuous because the data can take on any value in an interval.
Step-by-step explanation:
The data are continuous if they can take on any value within a range. In this case study, there are different elephants including small/young ones and big ones/old ones.
Thus, their heights will vary and can take on any value within a particular range.
James determined that these two expressions were equivalent expressions using the values of x - 4 and x-6.
Which statements are true? Check all that apply.
7x+4 and 3x+5+4x-1
When x-2, both expressions have a value of 18.
The expressions are only equivalent for x = 4 and x-6.
The expressions are only equivalent when evaluated with even values.
The expressions have equivalent values for any value of x.
The expressions should have been evaluated with one odd value and one even value.
When x-0, the first expression has a value of 4 and the second expression has a value of 5.
The expressions have equivalent values if x - 8.
Answer:
1 - Correct
2 - incorrect
3- incorrect
4 - incorrect
5 - Correct
Step-by-step explanation:
Notice that
3x + 5 + 4x -1 = 3x + 4x + 5 -1 = 7x + 4
therefore the two expressions are equivalent for ANY number, specially x = 4 and x = 6 therefore
1 - Correct
Since that is true for all numbers
2 - incorrect
3- incorrect
4 - incorrect
The expressions are equivalent for all numbers therefore
5 - Correct
In order to estimate the difference between the average Miles per Gallon of two different models of automobiles, samples are taken, and the following information is collected. Model A Model B Sample Size 50 55 Sample Mean 32 35 Sample Variance 9 10 a) At 95% confidence develop an interval estimate for the difference between the average Miles per Gallon for the two models. b) Is there conclusive evidence to indicate that one model gets a higher MPG than the other
Answer:
At 95% confidence limits for the true difference between the average Miles per Gallon for the two models is -1.8210 to 4.1789
Yes 95 % confidence means that there's conclusive evidence to indicate that one model gets a higher MPG than the other.
Step-by-step explanation:
Model A Model B
Sample Size 50 55
Sample Mean x` 32 35
Sample Variance s² 9 10
At 95 % confidence limits are given by
x1`-x2` ± 1.96 [tex]\sqrt{\frac{s^{2} }{n1} +\frac{s^{2}}{n2} }[/tex]
Putting the values
32-35 ± 1.96 [tex]\sqrt\frac{9}{50}+\frac{10}{55}[/tex] ( the variance is the square of standard deviation)
-3 ± 1.96 [tex]\sqrt{ \frac{495+500}{2750}[/tex]
-3 ± 1.96( 0.6015)
-3 ± 1.17896
-1.8210; 4.1789
Thus the 95% confidence limits for the true difference between the average Miles per Gallon for the two models is -1.8210 to 4.1789.
Yes 95 % confidence means that there's conclusive evidence to indicate that one model gets a higher MPG than the other.
The owner of a shoe store wanted to determine whether the average customer bought more than $100 worth of shoes. She randomly selected 10 receipts and identified the total spent by each customer. The totals (rounded to the nearest dollar) are given below.
Use a TI-83, TI-83 Plus, or TI-84 calculator to test whether the mean is greater than $100 and then draw a conclusion in the context of the problem. Use α=0.05.
125 99 219 65 109 89 79 119 95 135
Select the correct answer below:
A) Reject the null hypothesis. There is sufficient evidence to conclude that the mean is greater than $100.
B) Reject the null hypothesis. There is insufficient evidence to conclude that the mean is greater than $100.
C) Fail to reject the null hypothesis. There is sufficient evidence to conclude that the mean is greater than $100.
D) Fail to reject the null hypothesis. There is insufficient evidence to conclude that the mean is greater than $100.
Answer:
D) Fail to reject the null hypothesis. There is insufficient evidence to conclude that the mean is greater than $100.
Step-by-step explanation:
We are given that the owner of a shoe store randomly selected 10 receipts and identified the total spent by each customer. The totals (rounded to the nearest dollar) are given below;
X: 125, 99, 219, 65, 109, 89, 79, 119, 95, 135.
Let [tex]\mu[/tex] = average customer bought worth of shoes.
So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu \leq[/tex] $100 {means that the mean is smaller than or equal to $100}
Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu[/tex] > $100 {means that the mean is greater than $100}
The test statistics that will be used here is One-sample t-test statistics because we don't know about population standard deviation;
T.S. = [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex] ~ [tex]t_n_-_1[/tex]
where, [tex]\bar X[/tex] = sample mean = [tex]\frac{\sum X}{n}[/tex] = $113.4
s = sample standard deviation = [tex]\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }[/tex] = $42.78
n = sample of receipts = 10
So, the test statistics = [tex]\frac{113.4-100}{\frac{42.78}{\sqrt{10} } }[/tex] ~ [tex]t_9[/tex]
= 0.991
The value of t-test statistics is 0.991.
Now, at a 0.05 level of significance, the t table gives a critical value of 1.833 at 9 degrees of freedom for the right-tailed test.
Since the value of our test statistics is less than the critical value of t as 0.991 < 1.833, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.
Therefore, we conclude that the mean is smaller than or equal to $100.
a three dimensional figure with a circular base and a smooth face that diminishes to a single point
Answer:
I believe that the answer is a cone
Step-by-step explanation:
A cone is a three dimensional figure that has a circular base and a smooth face that goes up into a single point.
Various studies indicate that approximately 11% of the world's population is left handed. You think this number is actually higher. You take an SRS of 225 people and find that 31 of them are left handed. Test your claim at the 5% significance level.
A. State your null and alternative hypotheses.
B. Sketch the rejection region.
C. Calculate the test statistic.
D. Determine the P-value for your test.
Answer:
a. H0 : p ≤ 0.11 Ha : p >0.11 ( one tailed test )
d. z= 1.3322
Step-by-step explanation:
We formulate our hypothesis as
a. H0 : p ≤ 0.11 Ha : p >0.11 ( one tailed test )
According to the given conditions
p`= 31/225= 0.1378
np`= 225 > 5
n q` = n (1-p`) = 225 ( 1- 31/225)= 193.995> 5
p = 0.4 x= 31 and n 225
c. Using the test statistic
z= p`- p / √pq/n
d. Putting the values
z= 0.1378- 0.11/ √0.11*0.89/225
z= 0.1378- 0.11/ √0.0979/225
z= 0.1378- 0.11/ 0.02085
z= 1.3322
at 5% significance level the z- value is ± 1.645 for one tailed test
The calculated value falls in the critical region so we reject our null hypothesis H0 : p ≤ 0.11 and accept Ha : p >0.11 and conclude that the data indicates that the 11% of the world's population is left-handed.
The rejection region is attached.
The P- value is calculated by finding the corresponding value of the probability of z from the z - table and subtracting it from 1.
which appears to be 0.95 and subtracting from 1 gives 0.04998
A national survey of 1000 adult citizens of a nation found that 25% dreaded Valentine's Day. The margin of error for the survey was 3.6 percentage points with 90% confidence. Explain what this means.
Answer:
There is 90% confidence that the proportion of the adult citizens of the nation that dreaded Valentine’s Day is between 0.214 and 0.286.
Step-by-step explanation:
The summary of the statistics from the information given is ;
At 90% confidence interval, 25% dreaded Valentine's Day and the margin of error for the survey was 3.6 percentage points
SO;
[tex]C.I = \hat p \pm M.O.E[/tex]
[tex]C.I = 0.25 \pm 0.036[/tex]
C.I = (0.25-0.036 , 0.25+0.036)
C.I = (0.214, 0.286)
The 90% confidence interval for the proportion of the adult citizens of the nation that dreaded Valentine’s day is 0.214 and 0.286.
There is 90% confidence that the proportion of the adult citizens of the nation that dreaded Valentine’s Day is between 0.214 and 0.286.
Syrus is buying a tent with the dimensions shown below. The volume inside the tent is 4.5 m34.5\text{ m}^34.5 m34, point, 5, start text, space, m, end text, cubed. Syrus isn't sure if the tent will be tall enough for him to stand inside. What is the height of the tent?
Answer:
2 meters
Step-by-step explanation:
The volume is 4.5
⋅1.5⋅h⋅3
=2.25h
=h
The height of the tent is 2 meters.
Hope this helps :)
Answer:
2 meters
Step-by-step explanation:
Calculate the pay for the following day of a
weekly time card given a wage of $14/hr.
Morning:
In 08:00
Out 12:00
Afternoon:
In 12:45
Out 17:30
pay = $[?]
Answer: $122.50
Step-by-step explanation:
In Out
8:00 12:00 = 4 hours
12:45 17:30 = 4.75 hours
Total 8.75 hours
8.75 hours x $14/hr = $122.50
Note: to subtract 12:45 from 17:30, borrow 1 hour from 17 and add 60 minutes to 30:
17:30 → 16:90
- 12:45 - 12:45
4: 45
4 hours 45 minutes = [tex]4\frac{3}{4}[/tex] = 4.75 hours
Need help with this, I don’t need an explanation.
the answer is x=-2
and y=12
Laura wants to place one flower every 3/4 meters along the path from the gate to the main entrance of her home. The path is 12 meters long. How many flowerpots will she need?
Answer:
16 flowerpots
Step-by-step explanation:
12 divided by 3/4=16
Share £1200 in the ratio 3:5.
so you have the amount.
amount: 1200
then you have the ratio
ratio: 3:5
you have the count.
count: 2
and then you have the shares
shares: 8
and the amount per share is 150.00
so the total amount of shares is the sum of each person's ratio so,
so 1:5:2:3:9 = 1 + 5 + 2 + 3 +9 = 20 shares. hope that helps you..
An architect needs to consider the pitch, or steepness, of a roof in order to ensure precipitation runoff. The graph below shows
the vertical height, y, versus the horizontal distance, x, as measured from the roof peak's support beam.
Roof Steepness
y
14
12
10
8
Vertical Height (feet)
4
2
+X
10 12 14
0
2
4
6
8
Horizontal Distance (feet)
Determine the equation that could be used to represent this situation.
Answer:
The third answer (C).
Step-by-step explanation:
This graph starts at 10. So it needs the +10 at the end.
Also the slope is -1/2 because the graph goes down one, right two. Rise/run.
Answer:
y= -1/2x+10
Step-by-step explanation:
The slope-intercept form of a linear equation is y = mx + b, where m represents the slope and b represents the y-intercept.
For the the given graph, the y-intercept is 10. The slope can be determined by finding the rate of change between any two points on the graph, such as (2,9) and (8,6).
If 5e^x=300, x
I need help fast
Answer:
ln(60)
Step-by-step explanation:
We have the equation [tex]5e^x=300[/tex]. We can divide both sides of the equation by 5, getting [tex]e^x=60[/tex]. Finally, we can take the natural log of both sides, getting that x is equal to [tex]\ln(60)[/tex].
Solve the quadratic equation by factoring 9x^2 -16 = 0
Answer: x= - 4/3 and x = 4/3
Step-by-step explanation:
(3x-4) times (3x+4) = 0
Given that is both the median and altitude of , congruence postulate SAS is used to prove that is what type of triangle?
A.
equilateral
B.
scalene obtuse
C.
isosceles
D.
scalene acute
Answer:isosceles is the correct
Step-by-step explanation:
According to the given conditions the triangle ABC is an isosceles triangle.
What is an isosceles triangle?An isosceles triangle is a triangle that has any two sides equal in length and angles opposite to equal sides are equal in measure.
Given that, BD is median and altitude in the triangle ABC, and we are asked to find that what type of the triangle ABC will be if we prove triangles ADB and CBD congruent by SAS rule,
So, the proof is as follows,
AD = CD [definition of median]
∠ ADB = ∠ CDB [definition of altitude]
BD = BD [reflexive property]
∴ Δ ADB ≅ Δ CBD by SAS rule
AB = BC by CPCT
According to the definition of an isosceles triangle we can say that, ABC is an isosceles triangle.
Hence, according to the given conditions the triangle ABC is an isosceles triangle.
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The true average diameter of ball bearings of a certain type is supposed to be 0.5 in. A one-sample t test will be carried out to see whether this is the case. What conclusion is appropriate in each of the following situations?
(a) n 15 t 1.66 a 0.05
A. Reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in
B. Reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
C. Do not reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in
D. Do not reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
(b) n 15 t 1.66 a 0.05
Reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in
Reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
Do not reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in
Do not reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
(c) n 26, t 2.55 a 0.01
A. Reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in
B. Reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
C. Do not reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in
D. Do not reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
(d) n 26, t 3.95
A. Reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in
B. Reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
C. Do not reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
D. Do not reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in
Complete Question
The complete question is shown on the first uploaded image
Answer:
a
C
b
C
c
C
d
A
Step-by-step explanation:
From the question we are told that
The population mean is [tex]\mu = 0.5 \ in[/tex]
Generally the Null hypothesis is [tex]H_o : \mu = 0. 5 \ in[/tex]
The Alternative hypothesis is [tex]H_a : \mu \ne 0.5 \ in[/tex]
Considering the parameter given for part a
The sample size is n = 15
The test statistics is t = 1.66
The level of significance [tex]\alpha = 0.05[/tex]
The degree of freedom is evaluated as
[tex]df = n- 1[/tex]
[tex]df = 15- 1[/tex]
[tex]df = 14[/tex]
Using the critical value calculator at (social science statistics web site )
[tex]t_{\frac{\alpha}{2} ,df } = t_{\frac{0.05 }{2} ,14} = 2.145[/tex]
We are making use of this [tex]t_{\frac{\alpha }{2} }[/tex] because it is a one-tail test
Looking at the value of t and [tex]t_{\frac{\alpha }{2} }[/tex] the we see that [tex]t < t_{\frac{\alpha }{2} }[/tex] so the null hypothesis would not be rejected
Considering the parameter given for part b
The sample size is n = 15
The test statistics is t = -1.66
The level of significance [tex]\alpha = 0.05[/tex]
The degree of freedom is evaluated as
[tex]df = n- 1[/tex]
[tex]df = 15- 1[/tex]
[tex]df = 14[/tex]
Using the critical value calculator at (social science statistics web site )
[tex]t_{\frac{\alpha}{2} ,df } = t_{\frac{0.05 }{2} ,14} = -2.145[/tex]
Looking at the value of t and [tex]t_{\frac{\alpha}{2} ,df }[/tex] the we see that t does not lie in the area covered by [tex]t_{\frac{\alpha}{2} , df }[/tex] (i.e the area from -2.145 downwards on the normal distribution curve ) hence we fail to reject the null hypothesis
Considering the parameter given for part c
The sample size is n = 26
The test statistics is t = -2.55
The level of significance [tex]\alpha = 0.01[/tex]
The degree of freedom is evaluated as
[tex]df = n- 1[/tex]
[tex]df = 26- 1[/tex]
[tex]df = 25[/tex]
Using the critical value calculator at (social science statistics web site )
[tex]t_{\frac{\alpha}{2} ,df } = t_{\frac{0.01 }{2} ,25} = 2.787[/tex]
Looking at the value of t and [tex]t_{\frac{\alpha }{2} }[/tex] the we see that t does not lie in the area covered by [tex]t_{\alpha , df }[/tex] (i.e the area from -2.787 downwards on the normal distribution curve ) hence we fail to reject the null hypothesis
Considering the parameter given for part d
The sample size is n = 26
The test statistics is t = -3.95
The level of significance [tex]\alpha = 0.01[/tex]
The degree of freedom is evaluated as
[tex]df = n- 1[/tex]
[tex]df = 26- 1[/tex]
[tex]df = 25[/tex]
Using the critical value calculator at (social science statistics web site )
[tex]t_{\frac{\alpha}{2} ,df } = t_{\frac{0.01 }{2} ,25} = -2.787[/tex]
Looking at the value of t and [tex]t_{\frac{\alpha}{2} }[/tex] the we see that t lies in the area covered by [tex]t_{\alpha , df }[/tex] (i.e the area from -2.787 downwards on the normal distribution curve ) hence we reject the null hypothesis
please answer asap. there are two pics :)
Answer:
[tex]\boxed{\sf A. \ 0.34}[/tex]
Step-by-step explanation:
The first triangle is a right triangle and it has one acute angle of 70 degrees.
We can approximate [tex]\sf \frac{WY}{WX}[/tex] from right triangle 1.
The side adjacent to 70 degrees is WY. The side or hypotenuse is WX.
The side adjacent to 70 degrees in right triangle 1 is 3.4. The side or hypotenuse is 10.
[tex]\sf \frac{3.4}{10} =0.34[/tex]
Bubba Bulldog and all of his dog friends love to hide bones! Bubba hid 4 bones, Barry hid 5 bones, Larry hid 10 bones, and Goby hid 13 bones.
Find the mean number of dog bones.
_______dog bones
Answer:8
Step-by-step explanation:
You find the average which is adding them all together then dividing by how many numbers you added.
Which linear inequality is represented by the graph?
y > 2x + 2
y ≥ One-halfx + 1
y > 2x + 1
y ≥ One-halfx + 2
Answer: y > 2x + 1
Step-by-step explanation:
In the graph first, we can see two things:
The line is not solid (so the values in the line are not included), and the shaded part is above, so we will be using the symbol:
y > f(x)
Now, in the line we can see that when x = 0, y = 1.
So the linear equation must be something like:
f(x) = a*x + 1
The only one that has an y-intercept equal to 1 is y > 2x + 1
Answer:
C or y>2x +1
Step-by-step explanation:
edge
PLEASE HELP Which ordered pair is a solution to the system of inequalities?
y< 3x
y< 5
Answer:
I am pretty sure that it is C
Step-by-step explanation:
A 1,3 so 3 < 3 no not true
x,y
B -12,50 50< -36 Also not true
x , y
C 9 , 4 4<27 Yes 4< 5 YEPPP
D 4,10 10<12 Yes 10<5 NOOPPPPPEEEE
A line with a slope of 5 passes through the point (2,10). What is its equation in slope intercept form
Answer:
The answer is
y = 5xStep-by-step explanation:
Equation of a line is y = mx + c
where
m is the slope
c is the y intercept
From the question
Slope / m = 5
Equation of the line passing through point (2 , 10) is
y - 10 = 5(x - 2)
y - 10 = 5x - 10
y = 5x - 10 + 10
y = 5xHope this helps you
