Construct the cumulative frequency distribution for the given data.
Age​ (years) of Best Actress when award was won Frequency ​
20-29 28 ​
30-39 37
​40-49 14 ​
50-59 3
​60-69 4
​70-79 1
​80-89 1
Age​ (years) of Best Actress when award was won Cumulative Frequency
Less than 30
Less than 40
Less than 50
Less than 60
Less than 70
Less than 80
Less than 90

Answers

Answer 1

Answer:

 Age                               Frequency                   Cumulative Frequency

 Less than 30                             28                                       28

 Less than 40                             37                                28 + 37  =  65

 Less than 50                              1 4                                 65 + 14   =  79

 Less than 60                               3                                  79 + 3   =  82

 Less than 70                                4                                 82 + 4   =  86

 Less than 80                                1                                     86 + 1  =  87

 Less than 90                                1                                    87 + 1  =  88

Step-by-step explanation:

Given:

The Frequency Distribution table of ages of best actresses when award was won

To find:

Construct the cumulative frequency distribution

Solution:

In order to construct cumulative frequency distribution for the given data, each frequency from above table is added to the sum of the previous frequencies. For example, frequency for Less than 40  is 37 and the previous frequency (less than 30) is 28 so in order to calculate cumulative frequency 28 i.e. previous frequency is added to 37 (frequency of less than 30) and the cumulative frequency is 65. The complete table is given above.


Related Questions

Need help with this, I don’t need an explanation.

Answers

the answer is x=-2

and y=12

The exact heights of different elephants Choose the correct answer below. A. The data are continuous because the data can only take on specific values. B. The data are discrete because the data can take on any value in an interval. C. The data are discrete because the data can only take on specific values. D. The data are continuous because the data can take on any value in an interval.

Answers

Answer:

Option d: The data are continuous because the data can take on any value in an interval.

Step-by-step explanation:

The data are continuous if they can take on any value within a range. In this case study, there are different elephants including small/young ones and big ones/old ones.

Thus, their heights will vary and can take on any value within a particular range.

Which of the following equations are identities? Check all that apply.
A. sec x=
CSC X
1
B. CSCX=
sinx
1
C. tanx=
secx
D. tanx=
sin x
COS

Answers

Answer:

B. CSCX=  sinx  / 1

D. tanx= sin x  / COS x

Step-by-step explanation:

A. sec x=  1/cos(x)

CSC X  / 1 = sin(x)

B. CSCX

sinx  / 1  = csc(x)

C. tanx=   sin(x) / cos(x)

secx  = 1 / cos(x)

D. tanx=  sin(x) / cos (x)

sin (x)  / cos(x)

The correct option is (D). tanx = sinx/cosx

Option (D). is correct.

What is Trigonometry?

The trigonometric function, which comprises the sine, cosine, tangent, cotangent, secant, and cosecant. Can be used for practical applications.

As per the given data:

We are given some trigonometric identities, and we have to find out which of the given identities in the options are correct.

(A). secx = cscx/1

This is incorrect, as secx = 1/cosx

(B). cscx = sinx/1

This is incorrect, as cscx = 1/sinx

(C). tanx= secx

This is incorrect, as tanx = sinx.secx

(D). tanx = sinx/cosx

This is correct as, tanx = sinx/cosx

The correct option is (D). tanx = sinx/cosx

Hence, The correct option is (D). tanx = sinx/cosx

To learn more about Trigonometry, click:

brainly.com/question/29002217

#SPJ7

a three dimensional figure with a circular base and a smooth face that diminishes to a single point

Answers

Answer:

I believe that the answer is a cone

Step-by-step explanation:

A cone is a three dimensional figure that has a circular base and a smooth face that goes up into a single point.

James determined that these two expressions were equivalent expressions using the values of x - 4 and x-6.
Which statements are true? Check all that apply.
7x+4 and 3x+5+4x-1
When x-2, both expressions have a value of 18.
The expressions are only equivalent for x = 4 and x-6.
The expressions are only equivalent when evaluated with even values.
The expressions have equivalent values for any value of x.
The expressions should have been evaluated with one odd value and one even value.
When x-0, the first expression has a value of 4 and the second expression has a value of 5.
The expressions have equivalent values if x - 8.

Answers

Answer:

1 - Correct

2 - incorrect

3- incorrect

4 - incorrect

5 - Correct

Step-by-step explanation:

Notice that

3x  + 5 + 4x -1  =    3x + 4x + 5 -1 = 7x  + 4

therefore the two expressions are equivalent for ANY number, specially x = 4 and x = 6 therefore

1 - Correct

Since that is true for all numbers  

2 - incorrect

3- incorrect

4 - incorrect

The expressions are equivalent for all numbers therefore

5 - Correct

Syrus is buying a tent with the dimensions shown below. The volume inside the tent is 4.5 m34.5\text{ m}^34.5 m34, point, 5, start text, space, m, end text, cubed. Syrus isn't sure if the tent will be tall enough for him to stand inside. What is the height of the tent?

Answers

Answer:

2 meters

Step-by-step explanation:

The volume is 4.5

⋅1.5⋅h⋅3

=2.25h

=h

The height of the tent is 2 meters.

Hope this helps :)

Answer:

2 meters

Step-by-step explanation:

Calculate the pay for the following day of a
weekly time card given a wage of $14/hr.

Morning:
In 08:00
Out 12:00
Afternoon:
In 12:45
Out 17:30

pay = $[?]​

Answers

Answer:  $122.50

Step-by-step explanation:

In          Out

8:00    12:00    = 4 hours

12:45    17:30   = 4.75 hours  

          Total        8.75 hours

8.75 hours x $14/hr = $122.50

Note: to subtract 12:45 from 17:30, borrow 1 hour from 17 and add 60 minutes to 30:

 17:30       →         16:90

- 12:45                - 12:45

                            4: 45

4 hours 45 minutes = [tex]4\frac{3}{4}[/tex] = 4.75 hours

In order to estimate the difference between the average Miles per Gallon of two different models of automobiles, samples are taken, and the following information is collected. Model A Model B Sample Size 50 55 Sample Mean 32 35 Sample Variance 9 10 a) At 95% confidence develop an interval estimate for the difference between the average Miles per Gallon for the two models. b) Is there conclusive evidence to indicate that one model gets a higher MPG than the other

Answers

Answer:

At 95% confidence limits for the true difference between the  average Miles per Gallon for the two models is -1.8210  to  4.1789

Yes 95 % confidence means  that there's conclusive evidence to indicate that one model gets a higher MPG than the other.

Step-by-step explanation:

                              Model A              Model B

Sample Size              50                          55

Sample Mean  x`         32                           35

Sample Variance  s²    9                            10

At 95 % confidence limits are given by

x1`-x2` ± 1.96 [tex]\sqrt{\frac{s^{2} }{n1} +\frac{s^{2}}{n2} }[/tex]

Putting the values

32-35  ± 1.96  [tex]\sqrt\frac{9}{50}+\frac{10}{55}[/tex]        ( the variance is the square of  standard deviation)

-3 ± 1.96 [tex]\sqrt{ \frac{495+500}{2750}[/tex]

-3 ± 1.96( 0.6015)

-3 ± 1.17896

-1.8210; 4.1789

Thus the 95% confidence limits for the true difference between the  average Miles per Gallon for the two models is -1.8210  to  4.1789.

Yes 95 % confidence means  that there's conclusive evidence to indicate that one model gets a higher MPG than the other.

You can use both the t statistic and the z statistic to test hypotheses about the mean of population. The test that uses the t statistic is typically referred to as a t test, while the test that uses z statistic is commonly called a z test.

Which of the following statements are true of the t statistic? Check all that apply.

a. If you know the population standard deviation, you should use the t statistic.
b. The t statistic could be considered as an estimated z statistic.
c. The t statistic provides a relatively poor estimate of z with small sample sizes.
d. The formula for the t statistic is t = (M - s) / SM.

Answers

Answer:

An apple a day keeps the doctor away

Step-by-step explanation:

Type in the answer

Its gonna be right

The test statistic of z=1.92 is obtained when testing the claim that p≠0.767. a. Identify the hypothesis test as being​ two-tailed, left-tailed, or​ right-tailed. b. Find the​ P-value. c. Using a significance level of α=0.10​, should we reject H0 or should we fail to reject H0​?

Answers

Answer:

it is a two tailed test

The p - value for z=1.92  is 0.9726

Using a significance level of α=0.10, We fail to reject H0. The calculated z value lies out side the Zα value.

Step-by-step explanation:

For p≠0.767

Taking  null hypothesis as p≠0.767 and alternate hypothesis as p =0.767

H0 :p≠0.767  Ha :p≠0.767  it is a two tailed test

The p - value for z=1.92  is 0.9726 from the table.

Using a significance level of α=0.10

z value for 0.10 for two tailed test is ± 1.645

Z >zα

1.92> ± 1.645

Using a significance level of α=0.10, We fail to reject H0. The calculated z value lies out side the Zα value.

The true average diameter of ball bearings of a certain type is supposed to be 0.5 in. A one-sample t test will be carried out to see whether this is the case. What conclusion is appropriate in each of the following situations?
(a) n 15 t 1.66 a 0.05
A. Reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in
B. Reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
C. Do not reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in
D. Do not reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
(b) n 15 t 1.66 a 0.05
Reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in
Reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
Do not reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in
Do not reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
(c) n 26, t 2.55 a 0.01
A. Reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in
B. Reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
C. Do not reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in
D. Do not reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
(d) n 26, t 3.95
A. Reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in
B. Reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
C. Do not reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
D. Do not reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in

Answers

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

   C

b

    C

c

    C

d  

     A

Step-by-step explanation:

From the question we are told that

    The population mean is  [tex]\mu = 0.5 \ in[/tex]

     

Generally the Null hypothesis is  [tex]H_o : \mu = 0. 5 \ in[/tex]

                The Alternative hypothesis is  [tex]H_a : \mu \ne 0.5 \ in[/tex]

Considering the parameter given for part a  

       The sample size is  n =  15  

        The  test statistics is  t =  1.66

        The level of significance [tex]\alpha = 0.05[/tex]

The degree of freedom is evaluated as

            [tex]df = n- 1[/tex]

           [tex]df = 15- 1[/tex]

           [tex]df = 14[/tex]

Using the critical value calculator at (social science statistics web site )  

           [tex]t_{\frac{\alpha}{2} ,df } = t_{\frac{0.05 }{2} ,14} = 2.145[/tex]

We are making use of this  [tex]t_{\frac{\alpha }{2} }[/tex] because it is a one-tail test

Looking at the value of  t and [tex]t_{\frac{\alpha }{2} }[/tex] the we see that  [tex]t < t_{\frac{\alpha }{2} }[/tex] so the null hypothesis would not be rejected

Considering the parameter given for part b  

       The sample size is  n =  15  

        The  test statistics is  t =  -1.66

        The level of significance [tex]\alpha = 0.05[/tex]

The degree of freedom is evaluated as

            [tex]df = n- 1[/tex]

           [tex]df = 15- 1[/tex]

           [tex]df = 14[/tex]

Using the critical value calculator at (social science statistics web site )  

           [tex]t_{\frac{\alpha}{2} ,df } = t_{\frac{0.05 }{2} ,14} = -2.145[/tex]

Looking at the value of  t and [tex]t_{\frac{\alpha}{2} ,df }[/tex] the we see that t does not lie in the area covered by  [tex]t_{\frac{\alpha}{2} , df }[/tex] (i.e the area from -2.145 downwards on the normal distribution curve ) hence we fail to reject the null hypothesis

 

Considering the parameter given for part  c

       The sample size is  n =  26  

        The  test statistics is  t =  -2.55

        The level of significance [tex]\alpha = 0.01[/tex]

The degree of freedom is evaluated as

            [tex]df = n- 1[/tex]

           [tex]df = 26- 1[/tex]

           [tex]df = 25[/tex]

Using the critical value calculator at (social science statistics web site )  

           [tex]t_{\frac{\alpha}{2} ,df } = t_{\frac{0.01 }{2} ,25} = 2.787[/tex]

Looking at the value of  t and [tex]t_{\frac{\alpha }{2} }[/tex] the we see that t does not lie in the area covered by  [tex]t_{\alpha , df }[/tex] (i.e the area from -2.787 downwards on the normal distribution curve ) hence we fail to reject the null hypothesis

Considering the parameter given for part  d

       The sample size is  n =  26  

        The  test statistics is  t =  -3.95

        The level of significance [tex]\alpha = 0.01[/tex]

The degree of freedom is evaluated as

            [tex]df = n- 1[/tex]

           [tex]df = 26- 1[/tex]

           [tex]df = 25[/tex]

Using the critical value calculator at (social science statistics web site )  

           [tex]t_{\frac{\alpha}{2} ,df } = t_{\frac{0.01 }{2} ,25} = -2.787[/tex]

Looking at the value of  t and [tex]t_{\frac{\alpha}{2} }[/tex] the we see that  t  lies in the area covered by  [tex]t_{\alpha , df }[/tex] (i.e the area from -2.787 downwards on the normal distribution curve ) hence we  reject the null hypothesis

A line with a slope of 5 passes through the point (2,10). What is its equation in slope intercept form

Answers

Answer:

The answer is

y = 5x

Step-by-step explanation:

Equation of a line is y = mx + c

where

m is the slope

c is the y intercept

From the question

Slope / m = 5

Equation of the line passing through point (2 , 10) is

y - 10 = 5(x - 2)

y - 10 = 5x - 10

y = 5x - 10 + 10

y = 5x

Hope this helps you

If 5e^x=300, x
I need help fast

Answers

Answer:

ln(60)

Step-by-step explanation:

We have the equation [tex]5e^x=300[/tex]. We can divide both sides of the equation by 5, getting [tex]e^x=60[/tex]. Finally, we can take the natural log of both sides, getting that x is equal to [tex]\ln(60)[/tex].

Laura wants to place one flower every 3/4 meters along the path from the gate to the main entrance of her home. The path is 12 meters long. How many flowerpots will she need?

Answers

Answer:

16 flowerpots

Step-by-step explanation:

12 divided by 3/4=16

There were 3 squirrels and 18 acorns on Josh’s back porch. What was the ratio of squirrels to acorns? Enter your answer in reduced form. (100 points!!)

Answers

Answer:

1:6

Step-by-step explanation:

Answer:

Step-by-step explanation:

1:6

Which linear inequality is represented by the graph?

y > 2x + 2
y ≥ One-halfx + 1
y > 2x + 1
y ≥ One-halfx + 2

Answers

Answer: y > 2x + 1

Step-by-step explanation:

In the graph first, we can see two things:

The line is not solid (so the values in the line are not included), and the shaded part is above, so we will be using the symbol:

y > f(x)

Now, in the line we can see that when x = 0, y = 1.

So the linear equation must be something like:

f(x) = a*x + 1

The only one that has an y-intercept equal to 1 is y > 2x + 1

Answer:

C or y>2x +1

Step-by-step explanation:

edge

if the probability of drawing a red card from a box is 3/8, what are the odds against drawing a red card from the box

Answers

Answer: 5/8

Step-by-step explanation:

Simply do 8/8(1)-3/8 to get 5/8

Hope it helps <3

Rent for a 3 bedroom apartment is regularly $936 per month. Apartment management is now offering one month free for a 12 month lease. If you sign a one year lease and apply the free month equally across months, how much is your monthly lease amount?

Answers

Answer:

$858

Step-by-step explanation:

Monthly lease amount is ⇒ $936

Considering one moth free, yearly rental would be

⇒ 11*$936= $10296

The monthly lease amount :

⇒ $10296 / 12 = $858

PLEASE HELP Which ordered pair is a solution to the system of inequalities?
y< 3x
y< 5

Answers

Answer:

I am pretty sure that it is  C

Step-by-step explanation:

A 1,3 so 3 < 3 no not true

   x,y

B -12,50   50< -36 Also not true

    x  ,  y

C  9  ,  4   4<27 Yes    4< 5 YEPPP

D 4,10   10<12 Yes          10<5 NOOPPPPPEEEE

A national survey of 1000 adult citizens of a nation found that 25​% dreaded​ Valentine's Day. The margin of error for the survey was 3.6 percentage points with 90​% confidence. Explain what this means.

Answers

Answer:

There is 90% confidence that the proportion of the adult citizens of the nation that dreaded Valentine’s Day is between 0.214 and 0.286.

Step-by-step explanation:

The summary of the statistics from the information given is ;

At 90% confidence interval, 25​% dreaded​ Valentine's Day and the margin of error for the survey was 3.6 percentage points

SO;

[tex]C.I = \hat p \pm M.O.E[/tex]

[tex]C.I = 0.25 \pm 0.036[/tex]

C.I = (0.25-0.036 , 0.25+0.036)

C.I = (0.214, 0.286)

The 90% confidence interval for the proportion of the adult citizens of the nation that dreaded Valentine’s day is 0.214 and 0.286.

There is 90% confidence that the proportion of the adult citizens of the nation that dreaded Valentine’s Day is between 0.214 and 0.286.

An architect needs to consider the pitch, or steepness, of a roof in order to ensure precipitation runoff. The graph below shows
the vertical height, y, versus the horizontal distance, x, as measured from the roof peak's support beam.
Roof Steepness
y
14
12
10
8
Vertical Height (feet)
4
2
+X
10 12 14
0
2
4
6
8
Horizontal Distance (feet)
Determine the equation that could be used to represent this situation.

Answers

Answer:

The third answer (C).

Step-by-step explanation:

This graph starts at 10. So it needs the +10 at the end.

Also the slope is -1/2 because the graph goes down one, right two. Rise/run.

Answer:

y= -1/2x+10

Step-by-step explanation:

The slope-intercept form of a linear equation is y = mx + b, where m represents the slope and b represents the y-intercept.

For the the given graph, the y-intercept is 10. The slope can be determined by finding the rate of change between any two points on the graph, such as (2,9) and (8,6).

Various studies indicate that approximately 11% of the world's population is left handed. You think this number is actually higher. You take an SRS of 225 people and find that 31 of them are left handed. Test your claim at the 5% significance level.
A. State your null and alternative hypotheses.
B. Sketch the rejection region.
C. Calculate the test statistic.
D. Determine the P-value for your test.

Answers

Answer:

a. H0 : p ≤ 0.11 Ha : p >0.11 ( one tailed test )

d. z= 1.3322

Step-by-step explanation:

We formulate our hypothesis as

a. H0 : p ≤ 0.11 Ha : p >0.11 ( one tailed test )

According to the given conditions

p`= 31/225= 0.1378

np`= 225 > 5

n q` = n (1-p`) = 225 ( 1- 31/225)= 193.995> 5

p = 0.4 x= 31 and n 225

c. Using the test statistic

z=  p`- p / √pq/n

d. Putting the values

z= 0.1378- 0.11/ √0.11*0.89/225

z= 0.1378- 0.11/ √0.0979/225

z= 0.1378- 0.11/ 0.02085

z= 1.3322

at 5% significance level the z- value is ± 1.645 for one tailed test

The calculated value falls in the critical region so we reject our null hypothesis H0 : p ≤ 0.11 and accept  Ha : p >0.11 and  conclude that the data indicates that the 11% of the world's population is left-handed.

The rejection region is attached.

The P- value is calculated by finding the corresponding value of the probability of z from the z - table and subtracting it from 1.

which appears to be 0.95 and subtracting from 1 gives 0.04998

Bubba Bulldog and all of his dog friends love to hide bones! Bubba hid 4 bones, Barry hid 5 bones, Larry hid 10 bones, and Goby hid 13 bones.
Find the mean number of dog bones.
_______dog bones

Answers

Answer:8

Step-by-step explanation:

You find the average which is adding them all together then dividing by how many numbers you added.

Share £1200 in the ratio 3:5. ​

Answers

so you have the amount.

amount: 1200

then you have the ratio

ratio: 3:5

you have the count.

count: 2

and then you have the shares

shares: 8

and the amount per share is 150.00

so the total amount of shares is the sum of each person's ratio so,

so 1:5:2:3:9 = 1 + 5 + 2 + 3 +9 = 20 shares.  hope that helps you..

The owner of a shoe store wanted to determine whether the average customer bought more than $100 worth of shoes. She randomly selected 10 receipts and identified the total spent by each customer. The totals (rounded to the nearest dollar) are given below.
Use a TI-83, TI-83 Plus, or TI-84 calculator to test whether the mean is greater than $100 and then draw a conclusion in the context of the problem. Use α=0.05.
125 99 219 65 109 89 79 119 95 135
Select the correct answer below:
A) Reject the null hypothesis. There is sufficient evidence to conclude that the mean is greater than $100.
B) Reject the null hypothesis. There is insufficient evidence to conclude that the mean is greater than $100.
C) Fail to reject the null hypothesis. There is sufficient evidence to conclude that the mean is greater than $100.
D) Fail to reject the null hypothesis. There is insufficient evidence to conclude that the mean is greater than $100.

Answers

Answer:

D) Fail to reject the null hypothesis. There is insufficient evidence to conclude that the mean is greater than $100.

Step-by-step explanation:

We are given that the owner of a shoe store randomly selected 10 receipts and identified the total spent by each customer. The totals (rounded to the nearest dollar) are given below;

X: 125, 99, 219, 65, 109, 89, 79, 119, 95, 135.

Let [tex]\mu[/tex] = average customer bought worth of shoes.

So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu \leq[/tex] $100      {means that the mean is smaller than or equal to $100}

Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu[/tex] > $100      {means that the mean is greater than $100}

The test statistics that will be used here is One-sample t-test statistics because we don't know about population standard deviation;

                            T.S.  =  [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex]  ~ [tex]t_n_-_1[/tex]

where, [tex]\bar X[/tex] = sample mean = [tex]\frac{\sum X}{n}[/tex] = $113.4

             s = sample standard deviation = [tex]\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }[/tex] = $42.78

             n = sample of receipts = 10

So, the test statistics =  [tex]\frac{113.4-100}{\frac{42.78}{\sqrt{10} } }[/tex]  ~  [tex]t_9[/tex]

                                    =  0.991

The value of t-test statistics is 0.991.

Now, at a 0.05 level of significance, the t table gives a critical value of 1.833 at 9 degrees of freedom for the right-tailed test.

Since the value of our test statistics is less than the critical value of t as 0.991 < 1.833, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

Therefore, we conclude that the mean is smaller than or equal to $100.

Given that is both the median and altitude of , congruence postulate SAS is used to prove that is what type of triangle?



A.
equilateral

B.
scalene obtuse

C.
isosceles

D.
scalene acute

Answers

Answer:isosceles is the correct

Step-by-step explanation:

According to the given conditions the triangle ABC is an isosceles triangle.

What is an isosceles triangle?

An isosceles triangle is a triangle that has any two sides equal in length and angles opposite to equal sides are equal in measure.

Given that, BD is median and altitude in the triangle ABC, and we are asked to find that what type of the triangle ABC will be if we prove triangles  ADB and CBD congruent by SAS rule,

So, the proof is as follows,

AD = CD [definition of median]

∠ ADB = ∠ CDB [definition of altitude]

BD = BD [reflexive property]

∴ Δ ADB ≅ Δ CBD by SAS rule

AB = BC by CPCT

According to the definition of an isosceles triangle we can say that, ABC is an isosceles triangle.

Hence, according to the given conditions the triangle ABC is an isosceles triangle.

Learn more about isosceles triangles, click;

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X/h + 1 = -2

The value of x is terms of h is __.

Type the correct answer in the box. Use numerals instead of words.

Answers

Answer:

x = - 3h

Step-by-step explanation:

Given

[tex]\frac{x}{h}[/tex] + 1 = - 2 ( subtract 1 from both sides )

[tex]\frac{x}{h}[/tex] = - 3 ( multiply both sides by h )

x = - 3h

Step-by-step explanation:

[tex] \frac{x}{h + 1} = - 2[/tex]

Cross multiply

We have

-2(h + 1) = x

Expand the terms in the bracket

We have the final answer as

x = -2h - 2

Hope this helps you

Solve the quadratic equation by factoring 9x^2 -16 = 0

Answers

Answer: x= - 4/3 and x = 4/3

Step-by-step explanation:

(3x-4) times (3x+4) = 0

What is the range of the function f(x)=3/4|x|-3

Answers

Range is [tex]y\in[-3,+\infty)[/tex].

Hope this helps.

please answer asap. there are two pics :)

Answers

Answer:

[tex]\boxed{\sf A. \ 0.34}[/tex]

Step-by-step explanation:

The first triangle is a right triangle and it has one acute angle of 70 degrees.

We can approximate [tex]\sf \frac{WY}{WX}[/tex] from right triangle 1.

The side adjacent to 70 degrees is WY. The side or hypotenuse is WX.

The side adjacent to 70 degrees in right triangle 1 is 3.4. The side or hypotenuse is 10.

[tex]\sf \frac{3.4}{10} =0.34[/tex]

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