Convert the following in to SI units without changing its values
a. 4000 g
b. 2.4 km​

Answer:

m1 v1 = x-component of momentum   (towards origin)

m2 v2 = y-component of momentum  (towards origin where they collide)

m3 V cos 37 = m1 v1

m3 V sin 37 = m2 v2    components of momentum after collision

sin 37 / cos 37 = 2 v2/ v1

v2/ v1  = 1/2 * tan 37 = 1/2 * .754 = .377   for the ratio of speeds

Using m3 V cos 37 = m1 v1

3 * 2 cos 37 = 1 * v1

v1 = 4.79 m/s

m3 V sin 37 = m2 v2

v2 = 6 * sin 37 / 2 = 1.81 m/2

v2 / v1 = 1.81 / 4.79 = .378      same as ratio found above

Answer:

to sell and to buy

Explanation:

measurement is a comparison between unknown quantity with a known quantity

Las leyes de la óptica geométrica, permite encontrar los enunciados verdaderos son:

 1. Un rayo es una línea perpendicular a los frentes de onda.

 2. La onda incidente y reflejada van en el mismo medio

 3. La normal es perpendicular a la superficie que divide el medio.

 4. El espejo el ángulo de incidencia y refracción son iguales

Se le pide que diga si la afirmación es verdadera o falsa.

1) Un rayo de luz es una línea imaginaria que se dibuja perpendicular a la onda.

La luz está compuesta por infinitos frentes de onda, para simplificar la notación se dibuja un plano a través de todos los frentes de onda con la misma fase y la línea normal a esta se llama rayo; es el equivalente matemático de la norma definida para un plano

la declaración es verdadera

2) Una onda reflejada es aquella que viaja por el mismo medio que la onda incidente después de alcanzar el límite entre dos medios.  

Cuando la onda interactúa con el medio a medida que se refleja o se transmite, la onda reflejada está en el mismo medio de incidencia.

la declaración es verdadera

3) La normal es una línea perpendicular a la línea que divide las dos medias.

En óptica es habitual describir los fenómenos con respecto a una línea perpendicular al plano de incidencia de la onda electromagnética, esta línea se denomina Normal.

La afirmación es verdadera

4) En espejos planos, el ángulo de incidencia es igual al ángulo de reflexión.

La ley de la reflexión establece que el ángulo de incidencia es igual al ángulo de reflexión. En los espejos cumplen esta ley

la declaración es verdadera

5) En los espejos convexos la luz incide en el interior de la superficie esférica.

En un espejo convexo, el radio de curvatura va hacia la parte interior de la esfera, los rayos incidentes comienzan en la parte exterior del espejo.

la afirmación es falsa

          [tex]\frac{1}{f} = \frac{1}{p} + \frac{1}{q}[/tex]

Donde f es la distancia focal, p y q son la distancia al objeto y la imagen, respectivamente

En este caso la distancia al objeto es infinita,  por lo cual  la distancia focal es igual a la distancia a la imagen

          f = q

El foco está a una distancia igual al mitad radio de curvatura de un espejo esférico.

La distancia focal es la distancia donde se forma la imagen cuando el objeto está en el infinito, si usamos la ecuación del constructor

        f = q = R / 2

donde la distancia focal es el radio de curvatura sobre dos

la afirmación es falsa

7) En un espejo esférico, una imagen derecha es aquella que está por encima del eje óptico.

En óptica, la imagen puede ser vertical o invertida. Por convención el objeto se dibuja hacia arriba con respecto al eje óptico, si la imagen también está hacia arriba se llama derecha y si está hacia abajo se llama invertida

En un espejo esférico es invertida

la afirmación es Falsa

Usando las leyes de la óptica geométrica podemos encontrar si los enunciados son verdaderos o no.

las afirmaciones verdaderas son: 1,2,3,4

las declaraciones falsas son: 4,6,7

Obtenga más información sobre la óptica geométrica aquí: brainly.com/question/15850239

Answer:

A fertilized human egg cannot grow into a crocodile, duck or fish specifically because of: genetic code. is a stage in reproduction whereby an egg and a sperm fuse to create a single cell.

Explanation:

Because of ; Genetic Code

Answer:

The average setting for a gas-powered hot water boiler is 180°F. This provides the appropriate level needed for most cold weather temperatures. If you can raise the temperature manually, do not set it any higher than 210°F (which is often the limit), and try to remain down at 190°F if you need the extra heat.

Given the particle's acceleration is

[tex]\vec a(t) = \left(3\dfrac{\rm m}{\mathrm s^2}\right)\vec\jmath[/tex]

with initial velocity

[tex]\vec v(0) = \left(5\dfrac{\rm m}{\rm s}\right)\,\vec\imath[/tex]

and starting at the origin, so that

[tex]\vec r(0) = \vec 0[/tex]

you can compute the velocity and position functions by applying the fundamental theorem of calculus:

[tex]\vec v(t) = \vec v(0) + \displaystyle \int_0^t \vec a(u)\,\mathrm du[/tex]

[tex]\vec r(t) = \vec r(0) + \displaystyle \int_0^t \vec v(u)\,\mathrm du[/tex]

We have

• velocity at time t :

[tex]\vec v(t) = \left(5\dfrac{\rm m}{\rm s}\right)\,\vec\imath + \displaystyle \int_0^t \left(3\dfrac{\rm m}{\mathrm s^2}\right)\,\vec\jmath\,\mathrm du \\\\ \vec v(t) = \left(5\dfrac{\rm m}{\rm s}\right)\,\vec\imath + \left(3\dfrac{\rm m}{\mathrm s^2}\right)t\,\vec\jmath \\\\ \boxed{\vec v(t) = \left(5\dfrac{\rm m}{\rm s}\right)\,\vec\imath + \left(3\dfrac{\rm m}{\mathrm s^2}\right)t\,\vec\jmath}[/tex]

• position at time t :

[tex]\vec r(t) = \displaystyle \int_0^t \left(\left(5\dfrac{\rm m}{\rm s}\right)\,\vec\imath + \left(3\dfrac{\rm m}{\mathrm s^2}\right)u\,\vec\jmath\right) \,\mathrm du \\\\ \boxed{\vec r(t) = \left(5\dfrac{\rm m}{\rm s}\right)t\,\vec\imath + \frac12 \left(3\frac{\rm m}{\mathrm s^2}\right)t^2\,\vec\jmath}[/tex]

Force applied will be equal to 40 Newtons .

Answer:

F=40N

Explanation:

As

P=[tex]\frac{F}{A}[/tex]   and

F=P*A

Putting the values

F=200*0.2

Displacement = (14-20) Km = -6 Km

The displacement of a car is -6 Km South

How ??

Force:-

We know

According to newtons second law

[tex]\boxed{\sf Force=Mass\times Acceleration}[/tex]

[tex]\\ \sf\longmapsto Force=kgm/s^2[/tex]

We don't use it

[tex]\\ \sf\longmapsto Force=Newton(N)[/tex]

Hence its a derived unit.

Pressure:-

[tex]\\ \sf\longmapsto Pressure=\dfrac{Force}{Area}[/tex]

[tex]\\ \sf\longmapsto Pressure=\dfrac{N}{m^2}[/tex]

[tex]\\ \sf\longmapsto Pressure=Pascal(Pa)[/tex]

Hence its a derived unit

Answer:

[tex]{ \boxed{ \sf{F = Bev}}}[/tex]

Explanation:

F » Force

B » Magnetic flux density

e » magnitude of charge

v » voltage

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Answer:

972.5 mm

Explanation:

Since there are 10 millimeters in one centimeter, we move the decimal place to the right once to convert from cm to mm.

Explanation:

If an equation is dimensionally correct, it does not mean that the equation must be true. On the other hand, when the equation is dimensionally correct, the equation cannot be true. Dimensional analysis is a technique used to check whether a relationship is correct

The direction of a magnetic field can be accurately described as flowing from the north pole to the south pole,

When considering the idea of a magnetic dipole, it involves having two magnetic poles that possess equal strength but differ in polarity. This particular configuration results in the creation of a magnetic field that flows from the north to south pole. The magnitude of this field is determined by the size of the magnetic dipole moment, which serves as a distinctive quality of the magnet.

The idea of a magnetic field pertains to a specific region in space that can exert magnetic force on either a magnet or a charged particle in motion. The orientation of the magnetic field lines indicates the direction of the force that would affect any magnetic object within the field. It's important to note that these lines always form closed loops, originating from the north pole of the magnet and extending through surrounding space before ultimately returning to enter at its south pole. This implies that without fail, magnetic field lines travel from north to south pole, with this directional flow being reliant on the magnet's magnetic dipole moment.

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Answer:

5000 Pa

Explanation:

First collect the data you've been given already and make sure to convert into the right units;

Density = 1 g/cm³ ...... 1000 Kg/ m³

acceleration due to gravity = 10 m/s²

Height = 50 cm......0.5 m

after collecting the data, use the formula to solve

pressure = pgh

= 1000 × 10 × 0.5

= 5000 Pa

hope this helps

According to 1st equation of motion :

[tex]\boxed{ \boxed{v = u + at}}[/tex]

where,

let's solve for t

[tex] \hookrightarrow \: 17.63 = 0 + 2.13t[/tex]

[tex] \hookrightarrow \: t = \dfrac{17.63}{2.13} [/tex]

[tex] \hookrightarrow \: t = 8.276 \approx 8.28\: \: sec[/tex]

The area of the plate is 167.78 centimeters.

The area of the plate can be calculated with the equation of the area of a rectangle:

[tex] A = l*w [/tex]   (1)      

Where:

l: is the length = 24.74 cm

w: is the width = 6.78 cm

By entering the above values into equation (1) we can find the area.

[tex] A = 24.74 cm*6.78 cm = 167.74 cm [/tex]

Therefore, the area of the plate is 167.78 centimeters.

You can see another example of the area of a rectangle here: https://brainly.com/question/17673166?referrer=searchResults

I hope it helps you!

Answer:

If it measurement system were not established ,then there may create lots of problem such as: unequal measure ,anyone can get more ,or anyone can get less mass ,so on .

Answer:

Explanation:

In the four hours before 13:00 the train traveled 4(80) = 320 km.

It needs to travel another 4(320) = 1280 km in the next 21:00 - 13:00 = 8 hrs.

1280 / 8 = 160 km/hr

We can define average speed as:

s = (distance traveled)/(time it takes)

Using this, we will find that the average speed at which the train must travel the rest of the journey is 160km/h.

Here the given information is:

The train starts its journey at 9:00

The average speed between 9:00 and 13:00 was 80km/h, and it travels 1/5 of the journey by 13:00.

Then, if we define D as the total distance of the whole journey, in that lapse of 4 hours the train traveled 1/5 of D, or just D/5.

Then we can write the average speed as:

[tex]80km/h = \frac{(D/5)}{4h}[/tex]

[tex]80km/h*4h = D/5[/tex]

[tex]320km = D/5[/tex]

[tex]5*320km = D = 1,600km[/tex]

This means that the total distance of the journey is 1,600km

And at this time (13:00) the train already traveled 320km, so the distance left is:

[tex]d = 1,600km - 320km = 1,280km[/tex]

And we know that the train needs to finish the journey at 21:00

The time between 13:00 and 21:00 is 8 hours.

So the train needs to travel a distance of 1,280km in 8 hours, then the average speed that the train needs is:

[tex]s = (1,280km)/8h = 160 km/h[/tex]

s = 160km/h

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Answer:

Volume of wood is 68-50 = 18 cm³

Explanation:

Answer:

poopybutt pickle juice????? baa?

Explanation:

Answer:

what you need help on exactly?

Explanation:

Answer:

A stretched rubber band has potential energy

Answer:

elastic potential energy

Explanation:

Answer:

340 Newtons of friction force

Explanation:

4.50 m/s² = 520N of Fn - ?N of Ff ÷ 40 Kg or [tex]\frac{520-x}{40}[/tex] = 4.50

40* 520 - x/40 = 4.50 *40

520-x = 180

520-x/520 = 180/520

x=340 N of Ff

Answer:

12

cause the is no longer erra

Nothing accelerates a Projectile Horizontally during Motion...

Consequently

Horizontal Acceleration is Always Zero.

The Horizontal Velocity is always Constant too.

Only the vertical Velocity changes by -9.8ms-².

If this is so...

∆x = v'∆t + ½(0)(∆t)²

∆x = v't.

I'd go with Option D.

Dimentional analysis is very important in physics, because it allows finding errors in equations. We find that the following true equations

a) F= m a

b) x = 2 a t²

c) E = [tex]\frac{1}{2} }\ m \ a \ x[/tex]

d) E = m a x

The fundamental units in mechanics are;

the length [L] whose unit is the meter

The time [T] that has the second as a unit

The mass [M] with fundamental unit the kilogram (kg)

all other quantities are derived from these three fundamental units, for example velocity is

     v = x / t

we replace the units

     [v] = [L] / [T]

so the units of velocity are the distance between time.

This exercise uses the units of various quantities and asks to find if the equations are dimensionally correct.

Let's substitute the units in each expression

a) F = m a

    [M] [L] / [[T] ² = [M] [L] / [T] ²

the two sides of the expression are equal therefore the equation is correct

b) x = 2 a t²

scalar quantities have no units

    [L] = [L] / [T] ² [T] ²

    [L] = [L]

the two sides are equal, therefore the equation is correct

c) E = ½ m a x

    [M] [L] ² [T] ² = [M] [L] [T] ² [L]

    [M] [L] ² [T] ² = [M] [L] ² [T] ²

the two sides are equal the equation is correct

d) E = m a x

since scalar quantities have no units, this expression is equivalent to the expression in part c, therefore it is correct

e) F = F x / m

    [M] [L] / [T] ² = [M] [L] / [T] ² [L] / [M]

    [M] [L] / [T] ² = [L] ² / [T] ²

the two sides are different so the equation is false

In the dimensional analysis we find that expressions are true a, b, c, d  and we see that the expression e is false

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[tex] \large \mathfrak{Answer : }[/tex]

Velocity of the body traveling 600 m in 5 min = 300 seconds is :

Answer:

48

Explanation:

because teachers hand will be bigger than a student's hand. That's why teacher's hand acquire less surface area