Answer:
A) 5.2 A
Explanation:
formula = watts ÷ volts
1200 ÷ 230 = 5.217
a pulse has a 3 cycles each with a wavelength of .25 mm. what is the spatial pulse length in mm
The spatial pulse length is 0.75 mm, if the pulse has 3 cycles each with a wavelength of 0.25 mm.
Spatial pulse length in ultrasound imaging is used to determine for how much time an ultrasound wave exists in space. It is equal to the number of cycle times the wavelength of the pulse. A higher axial resolution is due to the shorter spatial length. Spatial pulse length can be decreased by using the higher frequency transducer or by heavier damping.
Spatial pulse length(SPL) = Number of cycle in each pulse × wavelength
Spatial pulse length(SPL) = 3 × 0.25 = 0.75 mm
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would a special (speci) observation be made if the ceiling decreased from 1,000 ft to 900 ft agl?
A special (speci) observation would be made if the ceiling decreased from 1,000 ft to 900 ft agl.
The global standard code for hourly and unique surface weather measurements is SPECI.
A SPECI message is the same as a METAR but is broadcast only when necessary. It is a unique observation message that draws attention to any noteworthy change that has occurred since the last METAR or SPECI was published.
Aeronautical decision making is a systematic approach to the mental process used by aircraft pilots to consistently to determine the best course of action in response to a given set of circumstances.
Inflight briefing should be requested in those cases where an update to a previous briefing needs to be obtained over an aircraft's radio.
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if a positive test charge is placed in an electric fiield, what is the direction of the force on the test charge?
If a positive test charge is placed in an electric field, direction of the force is in positive direction.
A positive test charge will experience force in the positive direction of an axis if it is placed in an electric field.
Each point in space has an electric property known as an electric field when charge of any kind is present.
Electric field E can be defined as. [tex]E=\frac{F}{q}[/tex] or, [tex]E=K\frac{Qq}{r^2}[/tex]. This is the electric field that charge Q is exposed to as a result of charge q. This formula for the electric field intensity is based on Coulomb's law.
An electric field can be found using a test charge, which is a little positive charge.
The test charge is kept generally positive because, as we all know, electrons, which are negatively charged, are the major charge carriers in current flow.
Force is the push or pull that an object experiences that causes it to alter its velocity. As a vector quantity with both magnitude and direction, force has both. The newton (sign N) is the SI unit of force.
Three types of forces are:-
Gravitational force, Electrical force and Magnetic forces.
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When Galileo observed Venus, he saw something that didn't fit with the Ptolemaic model for the SolarSystem. What was it?a. Venus shows phases, instead of always looking nearly full at times.b. Venus looks brighter at certain times than at others.c. Venus sometimes shows a crescent phase, and not just a constant, nearly-fullphase.d. Venus sometimes shows a nearly full phase, and not just a crescent.
When Galileo observed Venus, he saw something that didn't fit with the Ptolemaic model for the Solar System and it was option a. Venus shows phases, instead of always looking nearly full at times.
In October 1610, Galileo made his first telescopic views of Venus. He was eager to find out if Venus has phases like the Moon did. Before the telescope was created, Venus and the other planets appeared to be blazing stars. Galileo was able to determine that Venus circled the Sun, not the Earth, by observing the phases of the planet.
The centuries-old notion that the sun and planets rotated around Earth were disproved by Galileo Galilei's observation that Venus appeared in our sky in phases that were comparable to those of the Earth's Moon. This proved that Venus orbited the sun.
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Question: Consider three spheres all caring charge Q uniformly distributed over the volume. Sphere #1 is of radius R/2; Sphere #2 is of radius R; sphere #3 is of radius 2R. 1. Rank electric field created by these spheres at distance R/2 from the center, greatest first: a. 1; 2; 3 b. 3; 2; 1 c. 2; 1;3 d. 1=2; 3 e. Electric field is the same for all. Rank electric field created by these spheres at distance R from the center, greatest first: a. 1; 2; 3 b. 3; 2; 1 c. 2; 1;3 d. 1=2; 3 e. Electric field is the same for all. 3. Rank electric field created by these spheres at distance 2R from the center, greatest first: a. 1; 2; 3 b. 3; 2; 1 c. 2; 1;3 d. 1=2; 3 e. Electric field is the same for all.
The electric field formed by a charged sphere at a distance R/2 from the center is proportional to the charge on the sphere and inversely proportional to the square of the radius of the sphere.
As a result, at R/2 distance from the center, the electric field produced by sphere #1 (of radius R/2) will be bigger than the electric field produced by sphere #2 (of radius R), which will be greater than the electric field produced by sphere #3. (of radius 2R). As a result, the correct answer is: b. 3; 2; 1 The electric field formed by a charged sphere at a distance R from the center is proportional to the charge on the sphere and inversely proportional to the square of the radius of the sphere. As a result, at distance R from the center, the electric field produced by sphere #3 (of radius 2R) will be smaller than that produced by sphere #2 (of radius R), which will be less than that produced by sphere #1 (of radius R/2). As a result, the correct answer is: a. 1; 2; 3 The electric field formed by a charged sphere at a distance of 2R from the center is proportional to the charge on the sphere and inversely proportional to the square of the radius of the sphere. As a result, at a distance of 2R from the center, the electric field formed by sphere #3 (of radius 2R) will be less than the electric field created by sphere #2 (of radius R), which will be less than the electric field created by sphere #1 (of radius R). greater than the electric field produced by sphere #1 (of radius R/2). As a result, the correct answer is: a. 1; 2; 3.
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A uniform resistance wire leng th till is stretched its becomes four times. Does its resistance in crease or decrease?
A pumpkin is launched from the ground at an angle of 60° above the horizontal. The pumpkin strikes the center of a large target that is 80 ft from the pumpkin launcher and 48 ft above the ground. (g = 32 ft/s2)What is the magnitude pumpkin’s initial velocity in [ft/s]?What is the magnitude pumpkin’s velocity just before it strikes the target in [ft/s]? What is the angle, in [o], of the pumpkin’s velocity just before it strikes the target?
Where y=48ft, the first equation to be used is y=v0sin60ot - 16t2. You should use the second equation, x=v0cos60ot, where x=80ft.
Therefore, 80=v0t/2 and t=160/v0. In order to obtain t2= (160/v0)2, enter these expressions into the equations.To find v0, solve for 48=v0(.867)160/v0 -16(160/v0)2. As a result, v0 becomes =67.25ft/s. So t=160/v0 =160/67.25=2.38s. To determine the velocity, v, locate vy and vx. In other words, vy = v0y -gt, and vy= 67.25(.867) - 32(2.38), yielding vy = -18.397ft/s, vx = v0(1/2), which equals 33.625ft/s, and v=(vx2 + vy2)1/2, which equals 75.187ft/s. The velocity vector's angle with the target is now tan-1(18.397/33.625) and equal to 28.68° below horizontal.At a 60° angle above the horizontal, a pumpkin is thrown from the ground. At a distance of 80 feet and an altitude of 48 feet above the earth, the pumpkin lands in the center of a sizable target. (g = 32 ft/s2)
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it has been suggested that rotating cylinders about 19.5 mi long and 5.38 mi in diameter be placed in space and used as colonies. what angular speed must such a cylinder have so that the centripetal acceleration at its surface equals the free-fall acceleration on earth?
The angular speed required so that the angular acceleration is equal to the free fall acceleration on earth is 0.047 rad/s².
The centripetal acceleration of a is given by,
a = w²r
r is the radius,
r = D/2
a = w²D/2
D is the diameter of cylinder.
Also,
The free-fall acceleration has to be equal to the angular acceleration,
g = angular acceleration
a = g
w²D/2 = g
w = √(2g/D)
Putting values,
w = √(2x9.8/D)
D = 5.38 miles.
1 mile = 1609m
5 miles = 8931.4 m
So, we get,
w = √(2x9.8/8931.4)
w = 0.047 rad/s²
So, the angular speed that is required is 0.047 rad/s².
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a sample of gas is heated frtom 35 c to 70 c correctly describe what happens to the vo;lme
In accordance with gas laws, when a sample of gas is heated frtom 35 c to 70 c , its volume increases.
Gas Laws are laws that govern how a gas's pressure, volume, and temperature are related. According to Charles' Law (one of the gas laws), at constant temperature, for a fixed amount of gas, its volume is directly proportional to its temperature.
Ideal gas law equation : PV=nRT
According to Charles's gas law, V ∝ T
V1/V2 = T1/T2
According to given question, T1 (in kelvin) = 35+273 = 308K
T2 (in kelvin) = 70+273 = 343K
Hence, V1/V2 = 308/343 = >1
Thus, we can infer that when temperature rises, an ideal gas' volume increases.
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if a car is moving at 60 mph, how fast is the tire spinning phsyics
If a car is moving at 60 mph, 361 RPM as fast the tire spinning if the diameter of the wheel is 80 cm.
To find the speed of the spinning tire, you need to convert the car speed from mph to a linear velocity (units of length per time), and then divide by the wheel's circumference.
First, convert the wheel diameter from cm to inches: 80 cm x 0.3937 inches/cm = 31.5 inches
Next, calculate the wheel's circumference: C = π x D = 3.14 x 31.5 inches = 99 inches
Now convert 60 mph to inches per minute: 60 mph x 5280 ft/mile x 12 inches/ft = 35,840 inches/minute
Finally, divide the linear velocity by the wheel's circumference to find the tire speed in RPM: 35,840 inches/minute / 99 inches = 361.64 RPM.
So the tire is spinning at approximately 361 RPM.
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If a car is moving at 60 mph, how fast is the tire spinning if the diameter of the wheel is 80 cm?
How would increasing the magnetic force of a magnet change the pattern of magnetic field lines between its poles?
The increase in the strength of the magnetic field will make the magnetic filed lines more closer to each other at the magnetic poles.
What are magnetic field lines ?The magnetic field lines show how powerful the magnet is. This magnetic field will have a wider region of coverage for a powerful magnet. The magnetic field lines appear to all diverge or converge at the poles, as shown in the illustration above. This indicates that the region where a magnet's external magnetic field is highest.
The magnetic south pole is the point at which all magnetic field lines converge for all magnets, while the magnetic north pole is the point at which all magnetic field lines diverge.
The magnet's north pole is where magnetic lines of force begin, and its south pole is where they terminate. At the poles, magnetic field lines are closest to one another, and the distance at which they are separated from the magnet changes.
Magnetic force lines never cross one another. But they come closer when the field strength is increased.
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what quantity is determined by the change in potential energy of a particle which is acted on by a force?
The change in kinetic energy of the particle is determined by the change in potential energy of the particle which is acted on by a force.
What is force?
Force is a physical quantity that is a measurement of an interaction that occurs between two objects or systems. It is a vector quantity, meaning it has magnitude and direction. Force can cause an object to accelerate, decelerate, or remain at a constant speed. Examples of forces include gravitational force, electrostatic force, and electromagnetic force. Force is a key concept in classical mechanics, and is fundamental to understanding how objects interact in the physical world. Force is also used to describe energy, momentum, and torque. Understanding force can help us better understand how the physical world works.
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which conversion ratio would convert a measurement in millimeters to a value expressed in meters?
The following conversion factor is used to convert between millimeters and meters: footnote size rm "1 millimeter is one thousandth of a meter, or 0.001 m." 1/1000 of a meter is one millimeter, or 0.001 m.
It is typically applied to measure an object's length or to express the distance between two places.
The units of meter, centimetre, millimeter, and inch are used to measure the length of any object. Thousandth of a metre is what the word millimetre signifies. To further appreciate the idea, let's study more about this metric unit, the conversions, and work through a few examples.
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What would be true of a thermometer that always reads three degrees off?
a. It is valid but not reliable.
b. It is both reliable and valid.
c. It is neither reliable nor valid.
d. It is not valid, but you cannot determine if it is reliable from the information given.
e. It is reliable but not valid
A thermometer that always reads three degrees off, is reliable but not valid.
Reliability of a measuring instrument refers to the consistency of the measurement. It always give the same reading for the same temperature, however it is not correct as it is reads three degrees off. So we can say it is reliable, we can use it by calibrating it.
On the other hand it is not valid, as it gives the incorrect value of the temperature by reading the three degrees off. It does not give the reading that is suppose to. So it is not valid, or we can say the reading of this thermometer is not valid. Hence the correct option is E.
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A gas at and atmospheric pressure fills a cylinder. The gas is transferred to a new cylinder with three times the volume, after which the pressure is half the original pressure. What is the new temperature of the gas?
The new temperature of gas is 3/2 times of old temperature when a gas at and atmospheric pressure fills a cylinder.
Given the initial volume of cylinder = V1
The initial pressure of gas = P1
The initial temperature of gas = T1
Let the volume of new cylinder = V2
It is given that V2 = 3V1
Let the pressure of new cylinder = P2
It is given that P2 = 1/2P1
Let the new temperature of cylinder = T2
We know that from thermodynamic gas laws that PV = nRT where R is gas constant and n is the number of moles.
Then, P1V1/T1 = P2V2/T2 keeping n constant.
P1V1/T1 = 1/2P1 x 3V1/T2
T2/T1 = 3/2 = 1.5
Then T2 = 3/2T1
Hence the new temperature of gas is 3/2 times of old temperature.
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what mass of bromine will be produced if a potassium bromide solution reacts with 50.0ml of a 1.20 mol/l solution of acidified naclo4(aq)
Around 9.588 g of bromine will be produced when 50.0 ml of 1.20 mol/L potassium bromide solution reacts with 50.0 ml of a 1.20 mol/L solution of acidified NaClO.
The reaction between potassium bromide (KBr) and sodium hypochlorite (NaClO) in the presence of acid is a redox reaction, which results in the formation of bromine (Br2) and sodium chloride (NaCl). The amount of bromine produced can be calculated using the stoichiometry of the reaction.
First, the number of moles of potassium bromide (KBr) can be calculated using the molarity and volume of the KBr solution:
Moles of KBr = Molarity x volume
= 1.20 mol/L x (50.0 ml / 1000 ml/L)
= 0.0600 mol
Since the reaction is 1:1 between KBr and NaClO, the same number of moles of bromine will be produced. The mass of bromine can be calculated using the moles and molar mass of bromine:
Mass of Br2 = Moles of Br2 x Molar mass of Br2
= 0.0600 mol x 159.80 g/mol
= 9.588 g
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Joanne walks 0.4 km south to Macy’s then she gets hungry and walks 0.5 km north to the food court she then remember she needs a new outfit and walk 0.7 km to forever 21 she walks for a total of 1.75 hours . find her speed and velocity
Answer: 0.914 km/hour or 914 meters/hour
Explanation:
To calculate Joanne's speed, we need to divide the distance she traveled by the time it took her to travel that distance. In this case, she walked a total distance of 0.4 km south + 0.5 km north + 0.7 km = 1.6 km. To find her speed, we divide the distance traveled by the time it took:
Speed = 1.6 km / 1.75 hours
= 0.914 km/hour or 914 meters/hour
Velocity, on the other hand, is a vector quantity that describes an object's speed and direction. In this case, Joanne walked 0.4 km south and then 0.5 km north and then 0.7km to forever 21 so her direction is not constant. Therefore, her velocity would be zero, because her displacement is zero.
what is the weight of a 80-kg astronaut at the surface of mars? what is the pull of gravity on the same astronaut if he is in orbit at 3400 km above the surface?
When we do this, we find that , the acceleration due to gravity at the surface of Mars, is equal to 296 newtons, which is the weight force exerted by the astronaut on Mars's surface, divided by 80 kilograms, which is the astronaut's mass .
what is the weight of a 80-kg astronaut at the surface of mars?
The mass of the astronaut is the same everywhere, that is, on all planets and in space. Therefore his mass will still be 80 kg.So an object or person on Mars would weigh 37.83% its weight on earth.We would take the mass given, 80 kg, and multiply it times the acceleration of Earth's downward pull on that mass, 9.8 m/s/s. So the weight on Earth is 784 newtons. So the weight of the same 80 kg mass on the moon is 133.28 N.Objects on the moon weigh 1/6 of the weight on earth. Hence, the weight of an object on earth is that on the moon.To learn more about mars refers to:
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Please help meeee i’m very confused
The amount of force is referred to as the magnitude of a force. Hence, option B is correct.
What is Force?A force is an action that has the ability to alter an object's motion. An object can be caused by a force, which can also accelerate an item. To describe force, a push or a pull, makes intuitive sense. Forces have had both direction and magnitude, since they are vector quantities. It is measured in newtons that use the SI system (N). The symbol for force is the letter F.An entity's net force equals the rate at which its momentum is changing over time, according to the original formulation of Newton's second law.Objects' velocities can be changed by the concepts of push, drag, and torque. Thrust causes an item to move faster, whereas torque allows an object to move slower. Each part of an extended body typically exerts forces on its adjacent sections; the internal mechanical stress in the body is the result of the distribution of these forces.To learn more about force refer
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the lowest note on a grand piano has a frequency of 27.5 hz . the entire string is 2.00 m long and has a mass of 400 g . the vibrating section of the string is 1.90 m long. part a what tension is needed to tune this string properly? express your answer in newtons.
The tension needed to properly tune a grand piano string can be calculated using the equation T = (μL2f2)/(4L2), which is 130.31N.
μ is the mass per unit length of the string, L is the length of the string's vibrating section, and f is the string's frequency. Therefore, to calculate the tension, we need to first calculate the mass per unit length, which is equal to the mass of the string divided by the length of the vibrating section.
In this case, the mass per unit length is 400g divided by 1.90m, which equals 210.53 g/m.
Now we can calculate the tension.
Plugging in the values to the equation, the tension is (210.53g/m×1.90m2×275Hz2)/(4×1.90m2)
=130.31N.
Therefore, the tension needed to tune this string properly is 130.31 N.
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a motorcyclist initially traveling at 70 m/s accelerates at a constant acceleration to a speed of 130 m/s in 10 seconds. how far did he travel?
Answer:
a motorcyclist initially traveling at 70 m/s accelerates at a constant acceleration to a speed of 130 m/s in 10 seconds. how far did he travel?
Explanation:
a motorcyclist initially traveling at 70 m/s accelerates at a constant acceleration to a speed of 130 m/s in 10 seconds. how far did he travel?
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Two identical carts are released on tracks of equal height as shown. Neglect loss.
- In which case does the cart have a greater initial gravitational potential energy ?
- in which cause does the cart reach the bottom of the track in a shorter time ?
- in which case does the cart have a greater final speed?
Potential answers; Cart A , Cart B, or ‘equal’
Answer:
Drop down 1,2, & 3 all are Equal
Explanation:
- Both carts have the same initial gravitational potential energy, as they are released from the same height on tracks of equal height.
- Both carts will reach the bottom of the track in the same time, as they are both subject to the same gravitational force and start at the same height.
- Both carts will have the same final speed, as they are both subject to the same gravitational force and experience the same amount of friction over the same distance.
Consider the hypothetical thermochemical equation 3 A + B 2 C for which AH = 63.3 kJ/ mol. = a) If you have 5.30 moles of A, what quantity of heat, in kJ, would be absorbed? b) If the reaction absorbs 345 kJ of heat, What quantity in moles of C would be produced? c) What would AH, in kJ/mol, be for the reaction 2 C →3 A + B? 13 III > d) What would AH, in kJ/mol, be for the reaction 9 A + 3 B →6 C? e) Which one of the following reactions would have an enthalpy change of -2xAH? Here, AH refers to the enthalpy change of the original reaction.
Enthalpy are given as a)334.99 kJ; b)5.46 moles; c)63.3 kJ/mol;
d)189.9 kJ/mol; e)The reaction that would have an enthalpy change of -2xAH is:
6 C →9 A + 3 B.
a) If you have 5.30 moles of A, the quantity of heat absorbed can be calculated as follows:
AH = 63.3 kJ/mol
moles of A = 5.30 moles
Heat absorbed = moles of A * AH
Heat absorbed = 5.30 moles * 63.3 kJ/mol = 334.99 kJ
b) If the reaction absorbs 345 kJ of heat, the quantity of moles of C produced can be calculated as follows:
Heat absorbed = 345 kJ
AH = 63.3 kJ/mol
Moles of C = Heat absorbed / AH
Moles of C = 345 kJ / 63.3 kJ/mol = 5.46 moles
c) For the reaction 2 C →3 A + B, the enthalpy change can be calculated using the equation:
AH = -AH(reversed reaction)
AH = -63.3 kJ/mol
AH = 63.3 kJ/mol
d) For the reaction 9 A + 3 B →6 C, the enthalpy change can be calculated as follows:
Enthalpy change for the reaction = 9 * AH(3 A + B 2 C) / 3 = 9 * 63.3 kJ/mol / 3 = 189.9 kJ/mol
e) The reaction that would have an enthalpy change of -2xAH is:
6 C →9 A + 3 B
Enthalpy change for the reaction = 9 * 63.3 kJ/mol / 6 = 189.9 kJ/mol * -2 = -379.8 kJ/mol.
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how do all the organisms in an ecosystem get the resources they need to release energy?
Answer: Energy is transferred between organisms in food webs from producers to consumers. The energy is used by organisms to carry out complex tasks. The vast majority of energy that exists in food webs originates from the sun and is converted (transformed) into chemical energy by the process of photosynthesis in plants.
a multiple-piston hydraulic jack has two output pistons, each with an area of 250 cm2. the input piston, whose area is 25 cm2, is connected to a lever that has a mechanical advantage of 9:1. if a 50 n force is exerted on the lever, how much pressure (kn/m2 or kpa) is developed in the system? how much force (kn) will be exerted by each output piston?
The pressure developed in the system is 180 Kn/m² and force that will be exerted by each output piston is 2.25 KN.
What is pressure?A physical force applied to an object is referred to as pressure. The force applied is perpendicular to the surface of the objects per unit area. F/A is the fundamental formula for pressure (Force per unit area). Pascals are a unit of pressure (Pa). Absolute, atmospheric, differential, and gauge pressures are different types of pressure. Have you ever noticed that when using a straw to drink something, you actually suck the air out of the straw? While taking a drink, you are actually exerting "Pressure."
a) Actual force applied F' = 50 x 9 = 450 N
so,
Pressure
= 450 / (25 x 10⁻⁴)
= 180000 N/m²
= 180 Kn/m²
b) force at each output = 180 x 250 x 10⁻⁴/2 =2.25 KN
Thus, The pressure developed in the system is 180 Kn/m² and force that will be exerted by each output piston is 2.25 KN.
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a 0.15 kg baseball is thrown with a speed of 46 m/s. it is hit striaght back at the pitcher with a speed of 78 m/s. what is the magnitude of the impulse exerted on the ball by the bat?
The impulse exerted on the ball by the bat is 4.8 Ns. The result is obtained by using the Impulse-Momentum Theorem.
What is Impulse-Momentum Theorem?The Impulse-Momentum Theorem states that impulse of an object equals to the change of the momentum. It can be expressed as
I = Δp
I = mΔv
Where
I = Impuls (Ns or kg m/s)Δp = change of momentum (Ns or kg m/s)m = mass of an object (kg)Δv = change of velocity (m/s)A baseball is thrown with
m = 0.15 kgv₀ = 46 m/sv₁ = 78 m/sFind the magnitude of the impulse exerted on the ball by the bat!
The impulse exerted by the bat is
I = mΔv
I = m(v₁ - v₀)
I = 0.15(78 - 46)
I = 0.15(32)
I = 4.8 Ns
Hence, the bat exerts the impulse of 4.8 Ns.
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IP Silver pellet with a ma of 1. 2 g
g
and a temperature of 88 ∘C
∘
C
are added to 270 g
g
of water at 18 ∘C
∘
C
Hence, the value of Tfinal will be =18.01786 C
The temperature of the final mixture can be calculated using the law of conservation of energy, which states that the total energy of a system remains constant.
The change in energy of the water is equal to the heat absorbed by the water from the silver pellet.
Q = mcΔT
where Q is the heat absorbed,
m is the mass of the water,
c is the specific heat capacity of water,
and ΔT is the change in temperature.
The heat absorbed by the water can be calculated as follows:
Q = mcΔT = 270 g * 4.18 J/g°C * (Tfinal - 18°C) = mcΔT
The heat absorbed by the water can be calculated as follows:
Q = mcΔT = 1.2 g * 0.24 J/g°C * (88°C - Tfinal) = mcΔT
Solving for Tfinal, we get:
Tfinal = 18°C + (Q / mc)
= 18°C + [1.2 g * 0.24 J/g°C * (88°C - Tfinal)] / [270 g * 4.18 J/g°C]
=18 + [1.2*0.24*(88-18)]/[270*4.18]
=18+(20.16/1128.6)
=18+0.01786
=18.01786 C
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does acceleration depend on the speed of an object? why or why not? give an example of a slow object having a larger acceleration than a fast object. try to use a different example than those given by your classmates. can anyone think of an example of an object moving in such a way so that it is accelerating while having zero velocity?
acceleration depends on the change in velocity
Is acceleration affected by speed or velocity?Acceleration is a vector quantity because it is affected by changes in velocity. This indicates that acceleration has a magnitude as well as a direction. Meters per second squared, or m/s2, are the conventional units of acceleration. These units are derived from velocity units, meters per second, and time units, seconds.
Without zero velocity, a bode can have acceleration. For example, when an object is hurled upwards, the velocity at the body is zero at that point, yet it experiences acceleration owing to gravity. It is feasible that when an item is hurled upward, its velocity is zero at the highest point and it has a finite acceleration owing to gravity.
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A stuntman drives a car of mass 885 kg east with a speed of 40 m/s.
a. If the car accelerates at a rate of –3 m/s2, how long will it take the car to go 200 m? (3 points)
b. The stuntman drives the car off a 120 m cliff while going 40 m/s. How long will it take the car to land? (3 points)
c. How far horizontally from the cliff will the car land? (4 points)
PLSSS I NEED THIS ASAP!!
It will take 13.33 s for the stuntman's car to reach 200 m. The car will land in 4.48 s and the car will land 178.72 m from the cliff horizontally.
How to calculate time and distance?a. To find the time it takes the car to go 200 m, we need to find the final velocity of the car, which can be calculated using the formula vf = vi + at, where vi is the initial velocity, a is the acceleration, and t is the time.
Since the car is slowing down, the acceleration is negative, so we can use the formula:
t = (vf - vi) / a = (0 - 40) / -3 = 13.33 s
b. To find the time it takes the car to land, we need to find the time it takes for the car to fall the 120 m height. This can be found using the formula:
t = √(2d / g), where d is the distance fallen and g is the acceleration due to gravity (9.8 m/s²).
t = √(2 x 120 / 9.8) = 4.48 s
c. To find the horizontal distance the car lands from the cliff, we need to find the horizontal distance the car travels during the time it falls. This can be found using the formula:
d = vi x t = 40 x 4.48 = 178.72 m.
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A 100kg is rolling down a hill with 129000J of energy, how fast is it going
In order to calculate the speed of an object, we need to use the formula:
Speed = (2 x Energy) / Mass
So, using the information given in the question:
Speed = (2 x 129000 J) / 100 kg
To find the speed, we need to divide the energy by the mass and then multiply by 2.
Speed = 2580 m/s
So, the 100kg object is rolling down the hill at a speed of 2580 m/s (or approximately 5800 mph)