Could someone show me a step by step process on how to do this problem? Calculus 2

Could Someone Show Me A Step By Step Process On How To Do This Problem? Calculus 2

Answers

Answer 1

The arc length is given by the definite integral

[tex]\displaystyle \int_1^3 \sqrt{1 + \left(y'\right)^2} \, dx = \int_1^3 \sqrt{1+9x} \, dx[/tex]

since by the power rule for differentiation,

[tex]y = 2x^{3/2} \implies y' = \dfrac32 \cdot 2x^{3/2-1} = 3x^{1/2} \implies \left(y'\right)^2 = 9x[/tex]

To compute the integral, substitute

[tex]u = 1+9x \implies du = 9\,dx[/tex]

so that by the power rule for integration and the fundamental theorem of calculus,

[tex]\displaystyle \int_{x=1}^{x=3} \sqrt{1+9x} \, dx = \frac19 \int_{u=10}^{u=28} u^{1/2} \, du = \frac19\times\frac23 u^{1/2+1} \bigg|_{10}^{28} = \boxed{\frac2{27}\left(28^{3/2} - 10^{3/2}\right)}[/tex]


Related Questions

4.) Determine the missing side of a rectangle with an area of 480 cm² and a length of 32 cm. Please show your work.​

Answers

Answer:

w = 15 cm

Step-by-step explanation:

We want to find the width, as the area of a rectangle is length (l) * width (w).

Since we know the area and the length, we have 480 = 32w

Isolating w by dividing both sides by 32 gives us w = 15 cm

INDUSTRIES IS CONSIDERING PURCHASING A CERTAIN STOCK. AFTER
CONSIDERABLE RESEARCH, THE BOARD MEMBERS DETERMINE THAT THERE IS A 60% CHANCE OF MAKING $8000, A 10% CHANCE OF BREAKING EVEN, AND A 30% CHANCE
OF LOSING $6200. FIND THE EXPECTATION OF THIS PURCHASE

Answers

0.6(8000) + 0.1(0) + 0.3(-6200)
4800 + 0 - 1860
$2140

Solve the equation

7/4x-2=-5x+1

Answers

[tex]\large{\mathcal{ANSWER}}[/tex]Problem:

[tex]\frac{7}{4}[/tex] [tex]x\:-\:2\:=\:-5x\:+\:1[/tex]

Solution:

[tex]\frac{7}{4}[/tex] [tex]x\:-\:2\:=\:-5x\:+\:1[/tex]

[tex]7x\: - \:8 \:=\: -20x\: + \:4 [/tex]

[tex]7x \:- \:8 \:+ \:20x \:= \:4[/tex]

[tex]7x\: + \:20x \:= \:4 \:+ \:8 [/tex]

[tex]27x\: = \:4\: + \:8[/tex]

Answer:

[tex]x\:= [/tex] [tex]\frac{4}{9}[/tex]

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Answer:

x = 4/9

Step-by-step explanation:

Solve for x

7/4 x -2  = -5x +1

Add 5x to each side

7/4 x -2+5x  = -5x +1+5x

7/4 x  + 5x -2  = 1

Get a common denominator for the x terms

7/4x  +20/4x -2 = 1

Add 2 to each side

27/4 x -2+2 = 1+2

27/4 x = 3

Multiply each side by 4

27/4 x *4 = 3*4

27x = 12

Divide each side by 27

27x/27 = 12/27

x = 12/27

Simplify

x = 4/9

solve the simultaneous equation 2x+y=22 =12, x + 24+2 = 18, 2x -y +22=16 ​

Answers

The solution for the simultaneous equations 2x + y - 2z = 12, x + 2y +z =18 and 2x - y + 2z =16 are x = 7, y = 4 and z = 3

What are linear equations?

Linear equations are equations that have constant average rates of change, slope or gradient

How to determine the solution to the simultaneous equations?

A system of linear equations is a collection of at least two linear equations.

In this case, the system of equations is given as

2x + y - 2z = 12,

x + 2y +z =18

2x - y + 2z =16

Eliminate y and z in the equations by adding the first and the third equation together

This gives

2x + y - 2z = 12,

+

2x - y + 2z =16

--------------------------

4x = 28

Divide both sides by 4

x = 7

Substitute x = 7 in x + 2y +z =18 and 2x - y + 2z =16

7 + 2y +z =18

2(7) - y + 2z =16

This gives

2y + z = 11

-y + 2z= 2

Multiply -y + 2z= 2 by 2

-2y + 4z= 4

Add -2y + 4z= 4 and 2y + z = 11

5z = 15

Divide by 5

z = 3

Substitute z = 3 in -y + 2z= 2

-y + 2*3= 2

Evaluate

y = 4

Hence, the solution for the simultaneous equations 2x + y - 2z = 12, x + 2y +z =18 and 2x - y + 2z =16 are x = 7, y = 4 and z = 3

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SOLVE THE FOLLOWING PROBLEMS.
A) IN HOW MANY WAYS CAN THE LETTERS OF THE WORD “TRACK” BE ARRANGED?
B) A STUDENT MUST SELECT AND ANSWER SIX OUT OF TEN QUESTIONS ON AN EXAM. IN HOW MANY WAYS CAN THIS BE DONE?
C) A TEACHER DECIDES TO GIVE SIX IDENTICAL PRIZES TO 6 OF THE 20 STUDENTS IN HIS CLASS. IN HOW MANY WAYS CAN THIS BE DONE

Answers

The answers to the question are:

12021038760

How to solve for permutations and combinations

1. The letters of the word track can be arranged in 5! ways

These are  5 x 4 x 3 x 2 x1

= 120

2. The way that the student would be able to select 6 out of 10 questions would be by 10C6

= 210 ways

C)This teacher would be able to make the decision of the prices to the students using =20C6= n!(n-r!r!)

= 38760

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Using a numberline, find both the intersection and the union of the following intervals:
(-∞,6) and (-∞,9)

Answers

By critically observing the number lines, the intersection of both (-∞, 6) and (-∞, 9) is (6, 9) because this is the point where they overlap. Also, the union of both (-∞, 6) and (-∞, 9) on a number line is (-∞, 9).

What is a number line?

A number line can be defined as a type of graph with a graduated straight line which contains both positive and negative numerical values that are placed at equal intervals along its length.

Given the following intervals:

First interval = (-∞, 6).Second interval = (-∞, 9).

On a number line, the first interval would comprise the following numerical values -∞,..........-6, -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6.

On a number line, the second interval would comprise the following numerical values -∞,..........-6, -5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9.

By critically observing the number lines, we can logically deduce that intersection of both (-∞, 6) and (-∞, 9) is (6, 9) because this is the point where they overlap.

Also, the union of both (-∞, 6) and (-∞, 9) on a number line is (-∞, 9).

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Joyce paid $108.00 for an item at the store that was 40 percent off the original price. What was the original price?

Answers

The original price of the item is $180

The values given in the question are;

Actual cost of the item Joyce bought= $108
The item was sold 40 percent off the original price

The original price can be calculated as follows


The first step is to subtract 40% from 100%

100%- 40%

= 60%

Let x represent the original price of the item

60/100x= 108

0.6x= 108

Divide both sides by the coefficient of x which is 0.6

0.6x/0.6= 108/0.6

x= 180


Thus, the original price of the item is $180


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Round 229.371to the nearest one tenth and hundredths

Answers

Answer:

229.37, 229.4

Step-by-step explanation:

1. Hundredths
2. Tenths

229.37 and 229.4
explanation:

The figure below is a scale drawing of an office courtyard using the scale 1 centimeter = 4 feet.



Which figure is a scale drawing of the same courtyard using the scale 1 centimeter = 3 feet?

Answers

Using proportions, it is found that option A gives a figure that is a scale drawing of the same courtyard using the scale 1 centimeter = 3 feet.

What is a proportion?

A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.

Researching this problem on the internet, the figure with a scale of 1 cm = 4 feet has the dimensions of:

51 cm, 75 cm, 30 cm and 72cm.

For a scale of 1 centimeter = 3 feet, these measures will be multiplied by 4/3, hence the figure is given in option A, as:

51 x 4/3 = 68 cm.75 x 4/3 = 100 cm.30 x 4/3 = 40 cm.72 x 4/3 = 96 cm.

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A store is having a 20% off sale. The sale price of an item with price p is p - 0.2p. What is an equivalent expression.

Answers

Answer:

An equivalent expression would be the sale price of an item with price p is 0.8p

s(sale price) = 0.8p

An isosceles trapezoid has a perimeter of 108 metres. Its shorter base measures 11.5 metres and its longer base measures 28.1 metres. The two remaining sides have the same length; what is that length?

Answers

The length of one of the remaining sides is 34.20 meters.

What is the length?

A trapezoid is a convex quadrilateral. A trapezoid has at least on pair of parallel sides. the parallel sides are called bases while the non parallel sides are called legs

Perimeter of an isosceles trapezoid =  sum of lengths of sides of a trapezoid

length of shorter base + length of longer base + (2 x legs)

108 = 11.5 + 28.1 + (2 x legs)

108 = 39.60 + (2 x legs)

108 - 39.60 =  (2 x legs)

68.40 =  (2 x legs)

leg = 68.40 / 2

= 34.20 meters

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A satellite orbits the Earth at a height of 343 kilometers. If the satellite makes 8 revolutions around the Earth, how many kilometers does it travel? (Earth's diameter is 6371 kilometers.) Use 3.14 as the approximate value of pi .

Answers

The number of kilometres travelled by the satellite in discuss in which case, the satellite makes 8 revolutions around the earth is; C = 177,271.8 km.

What is the distance in kilometres covered by the satellite after 8 revolutions?

Given from the task content, the earth's diameter is; 6371 km and since, the height at which the satellite orbits the earth is; 343km, it follows that the diameter of orbit if the satellite in discuss is;

D = 6371 + (343)×2

Hence, we have; diameter, D = 7057 km.

Hence, the distance travelled after 8 revolutions is;

C = 8 × πd

C = 8 × 3.14 × 7057

C = 177,271.8 km.

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Solve using the distributive property -5(-3u-3x+4)

Answers

Answer:

15u+15x-20

Step-by-step explanation:

* = multiply or times

We have to multiply everything in the parenthesis by -5, meaning:

-5*-3u = 15u

-5*-3x = 15x

-5*4 = -20

Put it all together: 15u+15x-20

[tex]\huge\text{Hey there!}[/tex]


[tex]\huge\textbf{What is the distributive formula?}[/tex]

[tex]\mathsf{a(b + c)}\\\\\mathsf{= a(b) + a(c)}\\\\\mathsf{= ab + ac}[/tex]

[tex]\large\textbf{Extended distributive property formula:}[/tex]

[tex]\mathsf{a(b + c + d)}\\\\\mathsf{= a(b) + a(c) + a(d)}\\\\\mathsf{= ab + ac + ad}[/tex]

[tex]\huge\textbf{What are we solving for?}[/tex]

[tex]\large\textbf{It seems like you have the extended distributive property}[/tex]

[tex]\mathsf{-5(-3u - 3x + 4)}[/tex]

[tex]\huge\textbf{What are the steps to solving for the}\\\\\huge\textbf{given equation?}[/tex]

[tex]\mathsf{-5(-3u - 3x + 4)}\\\\\mathsf{= -5(-3u) - 5(-3x) - 5(4)}\\\\\mathsf{= 15u + 15x - 20}[/tex]

[tex]\huge\textbf{What is the answer to the equation?}[/tex]

[tex]\huge\boxed{\frak{{= 15\mathsf{u} + 15\mathsf{x} - 20}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Throughout this course, you have examined how real-world scenarios can be modelled using quadratic functions, exponential functions, trigonometric ratios sinusoidal functions, and sequences and series. Part A:- In this task, you will be creating unique real-world problems that can be modelled using the functions that we have learned. You may use real-world scenarios that we have examined throughout the course, but your problem should be created by you and have a unique description. Choose three (3) of the five (5) topics below and create a real-world scenario related to each of the three. 1. Exploring Quadratic Functions to Find Zeros or the Vertex; 2. Exponential Growth or Decay; 3. Using Trigonometric Ratios to Solve Three Dimensional Problems; 4. Representing Periodic Behaviour with Sinusoidal Functions: 5. Solving Financial Problems using Sequences & Series.

PLEASE SOLVE WITHOUT USING RADINAS

Answers

The exponential function is illustrated below.

How to illustrate the example?

An exponential function has a growth factor or 3.76. What is the percentage growth rate?

The growth factor (b) is given as:

b = 3.76

So, the percentage growth rate (r) is calculated as:

r = b - 1

Substitute known values

r = 3.76 - 1

Evaluate the difference

r = 276%

The way to solve Financial Problems using Sequences & Series will be:

The first salary that Mr James earn is 10000 and there is a yearly increase of 2000. Find his salary in the 5th year. This will be:

= a + (n - 1)d

= 1000 + (5 - 1)2000

= 10000 + (4 × 2000)

= 10000 + 8000.

= 18000

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pls help me!!! #18-19

Answers

Answer:

18. Sqrt40 goes between 6 and 7.

19. Sqrt83 ~= 9

Step-by-step explanation:

For both of these problems, it's really useful to be very familiar with the perfect squares on the times table. 1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144, 169, 196, 225...



On #18, we're looking at the sqrt40. This will be between sqrt36 and sqrt49, because 40 is between 36 and 49. But sqrt36 is 6 and sqrt49 is 7. So sqrt40 is between 6 and 7.

For #19, the sqrt83 is far closer to sqrt81 than it is to sqrt100. Sqrt81 = 9. So sqrt83 is very close to 9, it would round to 9 and not 10.

Using a number line, find both the intersection and the union of the following
intervals:
(-∞, 6) and (-∞, 9)

Answers

The intersection of the two intervals in the number line will be = 4, 5,  6,.......+∞ = (-∞,6).

The union of the two intervals = -3, -2, -1, 0, 1, 2, 3, 4, 5,.....,+∞ = (-∞),9)

How to illustrate the information?

The given intervals are;

First interval  = (-∞, 6)

Second interval  = (-∞, 9)

Using the number line, we therefore, the first interval includes, -3, -2, -1, 0, 1, 2, 3, 4, 5,.....,+∞

The second interval includes, 4, 5,.....,+∞

Which gives the intersection as 4, 5, 6,7, 8,9......+∞

The union is the interval that combines the two sets of intervals which is given as follows;

The union of the two intervals = -3, -2, -1, 0, 1, 2, 3, 4, 5,.....,+∞

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14. A photograph measures eight inches wide and ten inches long. The picture is enlarged to fit on a wall. If the new larger picture is 208 inches wide, how long is it?​

Answers

Answer:

The file contains the solution to the question

In the derivation of the formula for the volume of a cone, the volume of the cone is calculated to be StartFraction pi Over 4 EndFraction times the volume of the pyramid that it fits inside. A cone is inside of a pyramid with a square base. The cone has a height of h and a radius r. The pyramid has a base edge length of 2 r. Which statement best describes where the StartFraction pi Over 4 EndFraction comes from in the formula derivation? It is the ratio of the area of the square to the area of the circle from a cross section. It is the ratio of the area of the circle to the area of the square from a cross section. It is the difference of the area of the square and the area of the circle from a cross section. It is the sum of the area of the square and the area of the circle from a cross section.

Answers

In the derivation of the formula for the volume of a cone, the volume of the cone is calculated to be D. the the sum of the area of the square and the area of the circle from a cross section.

How to illustrate the information?

It should be noted that a volume simply means the amount of three dimensional space that's enclosed by a closed surface.

It is typically meaured on cubic units.

In this case, in the derivation of the formula for the volume of a cone, the volume of the cone is calculated to be the the sum of the area of the square and the area of the circle from a cross section.

In conclusion, the correct option is D.

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Answer:

B. It is the ratio of the area of the circle to the area of the square from a cross section.

Step-by-step explanation:

[tex]\lim _{x\to \infty }\left(\frac{tanx-sinx}{x^2}\right)[/tex]

Answers

The limit does not exist. There are infinitely many infinite discontinuities at [tex]x=n\pi[/tex], where [tex]n\in\Bbb N[/tex]. The function oscillates wildly between negative and positive infinity.

See a picture, please

Answers

Due to length restrictions, we kindly invite to check the explanation herein for further details of the hyperbola.

How to analyze an hyperbola

Herein we have an hyperbola whose axis of symmetry is parallel to the y-axis and the major semiaxis length is in the y-direction. By analytical geometry, we know that eccentricities of hyperbolae are greater than 1.

a) The formula for eccentricity is:

e = √(a² + b²) / a      (1)

Where:

a - Major semiaxis lengthb - Minor semiaxis length

If we know that a = 4 and b = 3, then the eccentricity of the hyperbola is:

e = √(4² + 3²) / 4

e = 5 / 4

b) The coordinates of the two vertices of the hyperbola are:

V(x, y) = (h, k ± a)      (2)

Where (h, k) are the coordinates of the center of the hyperbola.

V₁ (x, y) = (0, 4), V₂ (x, y) = (0, - 4)

The coordinates of the foci of the hyperbola are:

F(x, y) = (h, k ± c), where c = √(a² + b²).     (3)

c = √(4² + 3²)

c = 5

F₁ (x, y) = (0, 5), F₂ (x, y) = (0, - 5)

The equations of the asymptotes of the hyperbola are:

y = ± (a / b) · x

y = ± (4 / 3) · x      (4)

And the equations of the directrices of the hyperbola are:

y = k ± (2 · a - c)

y = 0 ± (8 - 5)

y = ± 3     (5)

The graph is presented in the image attached below.

c) The parametric equations for the hyperbola are the following formulae:

y = ± a · cosh t   →   y = ± 4 · cosh t      (6)

x = b · sinh t   →   x = 3 · sinh t     (7)

d) First, we determine the slopes of the two tangent lines by implicit differentiation:

m = (16 · x) / (9 · y)

m = (16 · 2.3) / [9 · (± 4.807)]

m = ± 0.851

Second, we find the intercept of each tangent line:

(x, y) = (2, 4.807)

b = 4.807 - 0.851 · 2

b = 3.105

y = 0.851 · x + 3.105      (8)

(x, y) = (2, - 4.807)

b = - 4.807 - (- 0.851) · 2

b = - 3.105

y = - 0.851 · x - 3.105      (9)

e) The definite integral of the arc length of the hyperbola is presented below:

[tex]s = \int\limits^{2}_{1} {\sqrt{\left(\frac{dx}{dt} \right)^{2}+\left(\frac{dy}{dt} \right)^{2}}} \, dt[/tex]

If we know that dx / dt = a² · sinh² t and dy / dt = b² · cosh² t, then the definite integral for the arc length is:

[tex]s = \int\limits^2_1 {\sqrt{a^{2}\cdot \sinh ^{2}t +b^{2}\cdot \cosh^{2}t}} \, dt[/tex]      (10)

f) We apply the following substitutions on (1): x = r · cos θ, y = r · sin θ. Then, we have the polar form by algebraic handling:

r(θ) = (a · b) / (b² · sin² θ - a² · cos² θ)     (11)

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A kite is flying 95 ft off the ground, and its string is pulled taut. The angle of elevation of the kite is 59 degrees. Find the length of the string. Round your answer to the nearest tenth.

Answers

If a kite is flying 95 ft. off the ground, and its string is pulled taut. The angle of elevation of the kite is 59 degrees. Then the length of the string will be 110.8 ft.

Given information constitutes the following,

The distance of the flying kite from the ground, length AB (refer the figure) = 95 ft.

The angle of elevation of the kite, ∠ACB = 59°

We have to find the length of the string, that is the length AC. For that, we can apply Trigonometry as shown in the next steps of the solution.

In ΔABC, as shown in the attached figure,

sin (∠ACB ) = AB / AC

⇒ sin (59°) = 95 / AC

0.8572 = 95 / AC

AC = 95 / 0.8572

AC = 110.814

AC ≈ 110.8 ft.                [After rounding off to the nearest tenth]

Hence, the length of the string comes out to be 110.8 ft.

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Ke'o went shopping and spent $114 on clothes
and bought 5 pocket squares for the same price and one pairs
of $14 shorts. Write an equation for this story
problem, then solve for the price of the shirts.
Select two answers.

A. equation: 5[x+(1)(14)] = 114

B. price of each pocket square: $28

C. price of each pocket square: $25

D.equation: [(1)(14) - 5] = 114

E. price of each pocket square: $20

F. price of each pocket square: $19

G. equation: [5+ (1)(14)] = 114

H. equation: 5x+(1)(14) = 114

Answers

Equation H and answer E are correct

5x + 14 = 114
5x = 100
x = 20

Someone please help me with this question asap!

Answers

[tex] \qquad \qquad \bf \huge\star \: \: \large{ \underline{Answer} } \huge \: \: \star[/tex]

Correct choice = B

[tex]\textsf{ \underline{\underline{Steps to solve the problem} }:}[/tex]

Take HJ = a, GH = b and GJ = c

a = b + 2

c = a + b - 17

a + b + c = 73

put the value of a from equation 1 in equation 2

[tex]\qquad❖ \: \sf \:c = (b + 2) + b - 17[/tex]

[tex]\qquad❖ \: \sf \:c = 2b - 15[/tex]

now, put the value of a and c in equation 3

[tex]\qquad❖ \: \sf \:b + 2 + b + 2b - 15 = 73[/tex]

[tex]\qquad❖ \: \sf \:4b - 13 = 73[/tex]

[tex]\qquad❖ \: \sf \:4b = 86[/tex]

[tex]\qquad❖ \: \sf \:b = 21.5 \: \: in[/tex]

Now, we need to find HJ (a)

[tex]\qquad❖ \: \sf \:a = b + 2[/tex]

[tex]\qquad❖ \: \sf \:a = 21.5 + 2[/tex]

[tex]\qquad❖ \: \sf \:23.5 \: \: in[/tex]

[tex] \qquad \large \sf {Conclusion} : [/tex]

Option B is correct

Answer:

23.5 in

Step-by-step explanation:

To find the length of HJ in triangle GHJ, create three equations using the given information, then solve simultaneously.

Equation 1

HJ is two inches longer than GH:

⇒ HJ = GH + 2

Equation 2

GJ is 17 inches shorter than the sum of HJ and GH:

⇒ GJ + 17 = HJ + GH

Equation 3

The perimeter of ΔGHJ is 73 inches:

⇒ HJ + GH + GJ = 73

Substitute Equation 1 into Equation 2 and isolate GJ:

⇒ GJ + 17 = GH + 2 + GH

⇒ GJ + 17 = 2GH + 2

⇒ GJ = 2GH - 15

Substitute Equation 1 into Equation 3 and isolate GJ:

⇒ GH + 2 + GH + GJ = 73

⇒ 2GH + GJ = 71

⇒ GJ = 71 - 2GH

Equate the two equations where GJ is the subject and solve for GH:

⇒ 2GH - 15 = 71 - 2GH

⇒ 4GH = 86

⇒ GH = 21.5

Substitute the found value of GH into Equation 1 and solve for HJ:

⇒ HJ = 21.5 + 2

HJ = 23.5

Need some help with macroeconomics !

Answers

The monetary policy that the Central Bank is using to address the downturn in the economy is the reduction of the reserve requirement from 17% t 14%.

What is monetary policy?

It should be noted that the monetary policy is the set of actions to control money supply in the economy.

The macroeconomic issues resulting from the pandemic on Trinidad and Tobago are that there are less money in circulation and there's a reduction in the standard of living.

The reduction of the reserve requirement will impact the money supply as it will lead to more money in circulation.

Complete question:

1. What form of monetary policy can the Central Bank use to address the downturn in the economy resulting from the pandemic?

2. Identity and explain two macroeconomic issues resulting from the pandemic on Trinidad and Tobago.

3. Identify how the reserve requirement will impact the money supply.

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How do I graph the following set {x is an even number, -1≤x<12}

Answers

Step-by-step explanation:

Use this sort of layout, but where x will be an odd number, do not shade it. there should be a pattern of shaded segments followed by unshaded segments repeating

1) The following scatterplot shows the percentage of the vote a candidate received in the 2016 senatorial elections

according to the voter's income level based on an exit poll of voters conducted by a news agency. The income

levels 1-8 correspond to the following income classes:

1 = Under $15,000; 2 = $15-30,000; 3 = $30-50,000; 4 = $50-75,000; 5 = $75-100,000;

6 = $100-150,000; 7 = $150-200,000; 8 = $200,000 or more.

Use the election scatterplot to determine whether there is a correlation between percentage of vote and income

level at the 0.01 significance level with a null hypothesis of ρs = 0.

A) The test statistic is between the critical values, so we fail to reject the null hypothesis. There is no

evidence to support a claim of correlation between percentage of vote and income level.

B) The test statistic is not between the critical values, so we fail to reject the null hypothesis. There is no

evidence to support a claim of correlation between percentage of vote and income level.

C) The test statistic is between the critical values, so we reject the null hypothesis. There is sufficient

evidence to support a claim of correlation between percentage of vote and income level.

D) The test statistic is not between the critical values, so we reject the null hypothesis. There is sufficient

evidence to support a claim of correlation between percentage of vote and income level

Answers

Option C is correct. The test statistic is not between the critical values, so we reject the null hypothesis. There is sufficient evidence to support a claim of correlation between percentage of vote and income level.

How to find the correlation

The scatter plot is the plot that is used to show the correlation that is known to exist between the given data sets that is of interests. It helps by showing the existing relationship between the x values and the y values in the question.

When we look at the graph properly, if we are to rule a line we would find out that most of the data points in the equation fall under the line in the data set. This shows that there is high correlation between these two variables.

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1. Assuming that the company sells all that it produces, what is the profit function?

2. What is the domain of P(x) ?

3. The company can choose to produce either 50 or 60 items. What is their profit for each case, and which level of production should they choose? Profit when producing 50 items? Profit when producing 60 items?

4. Can you explain, from our model, why the company makes less profit when producing 10 more units?

Answers

The  profit function is R(x) = -0.5 (x - 50²) + 1150

The domain of P(x)  is:  0 ≤ x ≤ 150 Profit when producing 50 items = 1150 Profit when producing 60 items =  1100 What is the profit function about?

Note that:

1. Profit  = Revenue - cost

P (x) =  0.5 ( x - 90²) + 4050 - 40x - 100  

= 0.5 ( x² - 180 + 8100 + 4050 - 40x - 100  

=0.5 x² - 50x - 100  

=0.5( x² - 100x) - 100  

=  -0.5 (x - 50²) + 1150

2.  Since the minimum unit is 50.

Then   x ≤ 150

X = describe the item so it need to be a negative number

x ≥ 0

Hence the domain of P(x)  is:  0 ≤ x ≤ 150

3. Assume x = 50 , 60

R(50) = 1150 , R (60 ) = -0.5 (60-50)² + 1150 = 1100

4. R (x) = -0.5 (x-50)² + 1150  then 50 more unit is removed hence, Profit when producing 60 items =  1100

Therefore, The  profit function is R(x) = -0.5 (x - 50²) + 1150

The domain of P(x)  is:  0 ≤ x ≤ 150 Profit when producing 50 items = 1150 Profit when producing 60 items =  1100

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need help please...

Answers

Answer:

[tex]\sf 28 \frac{1}{3} \:ft=28.3\:ft\:(nearest\:tenth)[/tex]

Step-by-step explanation:

Given information:

It takes Mr Kelly 6 strides to walk 20 ft.It takes Mr Kelly 8.5 strides to walk the other side of his house.

Let x be the unknown length of the other side of Mr Kelly's house.

To solve, set up a ratio with the given information and the defined unknown, then solve for x:

[tex]\textsf{20 ft : 6 strides = x ft : 8.5 strides}[/tex]

[tex]\implies \sf 20:6 = x:8.5[/tex]

[tex]\implies \sf \dfrac{20}{6}=\dfrac{x}{8.5}[/tex]

[tex]\implies \sf x=\dfrac{20 \cdot 8.5}{6}[/tex]

[tex]\implies \sf x=\dfrac{170}{6}[/tex]

[tex]\implies \sf x=28 \frac{1}{3} \:ft[/tex]

[tex]\implies \sf x=28.3\:ft\:(nearest\:tenth)[/tex]

Therefore, the length of the other side of Mr Kelly's house that takes him 8.5 strides to walk is 28.3 ft (nearest tenth).

Let that be x

20:x=6:8.520/x=6/8.520/x=12/1712x=17(20)12x=340x=340/12x=28.3ft

95 m
b =
b
57 m
What is the length of the missing leg? If necessary, round to the nearest tenth.
meters

Answers

If the length of hypotenuse is 95 m ,perpendicular is 57 m then the length of missing leg is 76m.

Given that the length of hypotenuse is 95 m ,the length of perpendicular is 57 m.

We are required to find the length of base or missing leg.

The given triangle is a right angled triangle. We can easily find out the length of the base of the triangle by using pythagoras theorem.

Pythagoras theorem says that the square of hypotenuse of a right angled triangle is equal to the sum of squares of the base and perpendicular of that triangle.

[tex]H^{2} =P^{2} +B^{2}[/tex]

We have to find the base of the triangle.

B=[tex]\sqrt{H^{2} -P^{2} }[/tex]

=[tex]\sqrt{(95)^{2} -(57)^{2} }[/tex]

=[tex]\sqrt{9025-3249}[/tex]

=[tex]\sqrt{5776}[/tex]

=76 m.

Hence if the length of hypotenuse is 95 m ,perpendicular is 57 m then the length of missing leg is 76m.

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What is the General form of the zero of a first degree polynomial? Explained answered please​

Answers

Answer:

for normalian is a function of the form FX is equal to a and x n + a n - 1 x n - 1 + ax2 into X + A1 is equal to A2 is degree per normal highest power of X is

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