Addition of a catalyst, at 15 °C, a certain reaction is able to produce 0.80 moles of product per minute at 25 °C it will produce at a rate of 0.40 moles per minute. The correct option to this question is C.
Effect of temperatureAs the concentration of an enzyme rises, so does the rate of an enzyme-catalyzed reaction. An enzyme-catalyzed process moves more quickly at higher temperatures than it does at lower ones. The protein gets denatured at higher temperatures, which also noticeably slows down the rate of the reaction.With a reduced activation energy, a catalyst offers the reaction a different pathway. The rate will rise since there are more particles with activation energy today. The activation energy does not change as the temperature rises.The amount of energy that can be transformed into activation energy in a collision increases with temperature, which will speed up the reaction rate. The opposite would happen if the temperature dropped.For more information on catalyst kindly visit to
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A balloon holds 60.0 kg of helium. What is the volume of the balloon if the final pressure is 1.20 atm and the temperature is 22°C?
Answer:
Explanation:
Use the formula PV=nRT
P is pressure in atm
V is volume in whatever unit you're working in as long as everything is in that unit (anything volume related)
n is the number of moles
R is the constant so 0.08206
and T is temperature and this MUST be in Kelvin which is 173.15 + C
the equation can be shifted depending on what you need to solve
.
In which polymer does the monomer include a benzene ring?
The polymer that includes a monomer with a benzene ring is called a phenolic polymer.
What is a polymer ?A polymer is a large molecule made up of repeating subunits called monomers. These monomers can be identical or different, and they are linked together through chemical bonds to form a long chain. Polymers can be natural, such as proteins, cellulose, and DNA, or they can be synthetic, such as plastics, synthetic rubber, and fibers.
Polymers have a wide range of properties and can be tailored to meet specific requirements for various applications. For example, some polymers are strong and tough, making them suitable for use in structural materials, while others are flexible and elastic, making them useful in materials such as rubber and elastomers.
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25.0 mL of 0.40 mol L-1 sodium hydroxide solution was placed in a well cleaned conical flask. Some phenolphthalein indicator was added to it. A pilot titration was carried out which indicated that about 17 mL of hydrochloric acid (HCl) was required for neutralisation. Three more titrations gave the titre readings as: 14.96 mL, 15.02 mL and 15.00 mL. (a) Write a balanced equation for this reaction. (b) Calculate the average titre volume in L. (c) Calculate the amount (in mol) of hydroxide ions used in the titration. (d) Calculate the concentration of the hydrochloric acid.
a) The balanced equation is NaOH + HCl → NaCl + H2O
b) The concentration of the hydrochloric acid is 0.655 mol L-1.
c) The amount of hydroxide ions used is 0.010 mol.
d) The concentration of the hydrochloric acid is 0.655 mol L-1.
The equation and the concentration(a) The balanced chemical equation for the reaction between sodium hydroxide and hydrochloric acid is:
NaOH + HCl → NaCl + H2O
(b) To find the average titre volume, we need to add up the four readings and divide by the number of readings:
Average titre volume = (17.00 mL + 14.96 mL + 15.02 mL + 15.00 mL) / 4 = 15.25 mL
However, it is important to convert this volume to liters (L) before using it in any calculations:
Average titre volume = 15.25 mL = 0.01525 L
(c) The amount of hydroxide ions used in the titration can be calculated using the balanced chemical equation and the volume and concentration of the sodium hydroxide solution:
Amount of NaOH used = concentration × volume
= 0.40 mol L-1 × 0.0250 L
= 0.010 mol
Since the balanced chemical equation shows that one mole of NaOH reacts with one mole of HCl, the amount of hydroxide ions used is also 0.010 mol.
(d) To calculate the concentration of the hydrochloric acid, we need to use the amount of hydrochloric acid used and the volume of the average titre reading:
Amount of HCl used = concentration × volume
= concentration × 0.01525 L
Since one mole of HCl reacts with one mole of NaOH, the amount of HCl used is equal to the amount of NaOH used, which we calculated in part (c):
Amount of HCl used = 0.010 mol
Substituting this value into the above equation gives:
0.010 mol = concentration × 0.01525 L
Solving for concentration gives:
concentration = 0.010 mol / 0.01525 L = 0.655 mol L-1
Therefore, the concentration of the hydrochloric acid is 0.655 mol L-1.
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6. What is the pH of a 0.25 M solution of NH4Cl? [Kb(NH3) = 1.8 10–5
The Ammonium Chloride solution at 0.25 M has a pH of 2.67.
Why is the pH of Ammonium Chloride below 7?As a result, the weak basic (Chlorine) in the solution is overpowered by the conjugate acid (Ammonium cation), making the solution mildly acidic. According to the equation pH =log[Hydrogen ion], an acidic solution has a pH lower than 7. Aqueous ammonium chloride solution has a pH that is less than 7.
Ammonium cation + Water ⇌ Nitrogen trihydride + Hydronium ion
Kb = [Nitrogen trihydride][Hydronium ion] / [Ammonium cation]
[Nitrogen trihydride] = [Hydronium ion] = x
[Ammonium cation] = 0.25 - x
Kb = [Nitrogen trihydride][Hydronium ion] / [Ammonium cation]
1.8 × 10–5 = x² / (0.25 - x)
1.8 × 10–5 = x² / 0.25
x² = 4.5 × 10–6
x = 2.12 × 10–3
pH = -log[Hydronium ion] = -log(2.12 × 10–3) = 2.67
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8. Balance the following equation:
NH3(g) + F2(g) → N₂F4(g) + HF(g)
a. How many moles of each reactant are needed to produce 4.00 moles of HF?
b. How many grams of F2 are required to react with 1.50 moles of NH3?
c. How many grams of N₂F4 can be produced when 3.40 grams of NH3 reacts?
The balanced equation for the given chemical reaction is:2 NH3(g) + 5 F2(g) → N2F4(g) + 6 HF(g)
What is the balanced chemical equation?a. To produce 4.00 moles of HF, we can use the stoichiometry of the balanced equation.
From the balanced equation, we can see that the mole ratio of NH3 to HF is 2:6 or 1:3.
This means that for every 1 mole of NH3, we will get 3 moles of HF.
So, to produce 4.00 moles of HF, we will need 4.00 moles / 3 moles per mole of NH3 = 1.33 moles of NH3.
b. To calculate the grams of F2 required to react with 1.50 moles of NH3, we can use the stoichiometry of the balanced equation.
From the balanced equation, we can see that the mole ratio of NH3 to F2 is 2:5.
This means that for every 2 moles of NH3, we will need 5 moles of F2.
So, for 1.50 moles of NH3, we will need 5 moles F2 / 2 moles NH3 * 1.50 moles NH3 = 3.75 moles of F2.
To convert moles of F2 to grams, we need to know the molar mass of F2, which is 2 x 19.00 g/mol = 38.00 g/mol.
So, the grams of F2 required to react with 1.50 moles of NH3 is 3.75 moles of F2 * 38.00 g/mol = 142.50 g of F2.
c. To calculate the grams of N2F4 that can be produced from 3.40 grams of NH3, we can use the stoichiometry of the balanced equation.
From the balanced equation, we can see that the mole ratio of NH3 to N2F4 is 2:1.
This means that for every 2 moles of NH3, we will produce 1 mole of N2F4.
First, let's convert 3.40 grams of NH3 to moles. The molar mass of NH3 is 1 x 14.01 g/mol + 3 x 1.01 g/mol = 17.03 g/mol.
So, 3.40 g of NH3 / 17.03 g/mol = 0.20 moles of NH3.
Now, using the mole ratio of NH3 to N2F4, we have 0.20 moles of NH3 * 1 mole of N2F4 / 2 moles of NH3 = 0.10 moles of N2F4.
To convert moles of N2F4 to grams, we need to know the molar mass of N2F4, which is 2 x 14.01 g/mol + 4 x 19.00 g/mol = 104.00 g/mol.
So, the grams of N2F4 that can be produced from 3.40 grams of NH3 is 0.10 moles of N2F4 * 104.00 g/mol = 10.40 g of N2F4.
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Why would the calculations of hydrogen peroxide be lower them the actual number in the bottle?
Which sub atomic particles are similar in size
Answer:
Neutrons and Protons
Explanation:
Different elements can have subatomic particles of varying sizes. The size of an atom is defined by the size of its electron cloud, which is composed of electrons, and the size of its nucleus, which is composed of protons and neutrons. The atomic number and subsequently the identity of an element are determined by the number of protons in the nucleus. The quantity of protons and neutrons in the nucleus determines its size. The quantity of electrons in the electron cloud and the energy levels they are located at define its size. The size of atoms can differ depending on the element due to differences in the amount of protons, neutrons, and electrons.
The heat of combustion of liquid ethylene glycol, C2H6O2 is -1189.2 kJ/mol. In an experiment 4.34 g of this compound was burnt completely and the heat evolved raised the temperature of y gram of water from 27.5 °C to 45.5 °C. Calculate the value of y (mass of water used).
The value of y is 1141 g if 4.34 g of this compound were totally burned, and the heat released caused a gram of water to warm up from 27.5 °C to 45.5 °C.
How can you figure out how much water was used?1 mole of ethylene glycol burns with a heat output of -1189.2 kJ/mol. The following formula can be used to determine the amount of heat released during the burning of 4.34 g of ethylene glycol:
Ethylene glycol's ([tex]C_{2}H_{6}O_{2}[/tex]) molar mass is calculated as follows: 2(12.01 g/mol) + 6(1.01 g/mol) + 2(16.00 g/mol) = 62.07 g/mol
Burned ethylene glycol is calculated as follows: 4.34 g / 62.07 g/mol = 0.0699 mol
4.34 g of ethylene glycol burned, releasing the following amount of heat:
-83.1 kJ = 0.0699 mol x -1189.2 kJ/mol
The water used in the experiment absorbs this heat. Water has a specific heat capacity of 4.18 J/g°C. The following formula can be used to determine how much water was utilized in the experiment:
The amount of heat the water absorbs is: -83.1 kJ = -83,100 J
The water's temperature changed from 45.5 °C to 27.5 °C, which equals 18 °C.
The mass of water employed in the experiment is 1,141 g, which is equal to -83,100 J / (4.18 J/g°C 18 °C).
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Which of the following is true for a volatic cell constructed in the first part of the experiment?
B, Electrons flow from the anode to the cathode is true for a voltaic cell constructed in the first part of the experiment.
What is a voltaic cell?A voltaic cell, also known as a galvanic cell, is an electrochemical cell that converts chemical energy into electrical energy. It consists of two half-cells, each with an electrode and an electrolyte solution. The two half-cells are connected by a wire and a salt bridge.
During operation, the electrons flow from the anode (the electrode where oxidation occurs) to the cathode (the electrode where reduction occurs) through the wire, while ions flow through the salt bridge to balance the charges in the two half-cells. This generates an electric current that can be used to power electrical devices.
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Complete question:
Which of the following is true for a voltaic cell constructed in the first part of the experiment?
Electrons flow from higher potential energy to lower potential energy.
Electrons flow from the anode to the cathode.
Electrons flow from the more negatively charged electrode to the more positively charged electrode.
All of the above
Calculate The PH After 15.0 ML Of 0.210 KOH Is Added In The Titration Of 55.0 ML Of .210 M HClOThe Ka Of HClO Is 4.0x10^-8
The pH after 15.0 mL of 0.210 KOH is added in the titration of 55.0 mL of 0.210 M HClO is 4.56.
To solve this problem, we need to use the balanced chemical equation for the reaction between KOH and HClO:
HClO + KOH → KClO + H2O
We can see that for every mole of KOH added, one mole of HClO will react. Therefore, the number of moles of HClO in 55.0 mL of 0.210 M HClO is:
n(HClO) = M(HClO) x V(HClO) = 0.210 mol/L x 0.0550 L = 0.0116 mol
When 15.0 mL of 0.210 M KOH is added, the number of moles of KOH added is:
n(KOH) = M(KOH) x V(KOH) = 0.210 mol/L x 0.0150 L = 0.00315 mol
Since the reaction is a neutralization reaction, the moles of HClO left after the reaction will be:
n(HClO) = n(HClO)initial - n(KOH) = 0.0116 mol - 0.00315 mol = 0.00845 mol
We can now use the equilibrium expression for the ionization of HClO in water to calculate the pH of the solution:
HClO + H2O ⇌ H3O+ + ClO-
Ka = [H3O+][ClO-]/[HClO]
At equilibrium, the concentrations of H3O+ and ClO- can be assumed to be equal to the concentration of HClO that remains unreacted, since HClO is a weak acid and does not dissociate completely in water. Therefore:
[H3O+] = [ClO-] = [HClO] = 0.00845 mol / (0.0550 L + 0.0150 L) = 0.105 M
Substituting these values into the equilibrium expression for Ka:
Ka = [H3O+][ClO-]/[HClO] = (0.105 M)² / 0.00845 M = 1.31 x 10⁻⁶
pKa = -log(Ka) = -log(1.31 x 10⁻⁶) = 5.88
pH = 1/2(pKw - pKa) = 1/2(14.00 - 5.88) = 4.56
Therefore, the pH after 15.0 mL of 0.210 KOH is added in the titration of 55.0 mL of 0.210 M HClO is 4.56.
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When ΔH > 0, the reaction is considered to be ________.
endothermic
combustion
exothermic
expansion
Endothermic since it requires heat from the surrounding
A mixture that contains large particles that are uniformly dispersed is called a _____.
solvent
emulsion
alloy
colloid
Answer:
colloid
Explanation:
there's no explanation
Que símbolo tiene 25 protones,25 electrones y 27 neutrones
How do you think the electrons, and the way the electrons are bonded or transfered,
affect how the two compounds dissolve?
Answer:
the electron will be drawn more toward the atom with the higher e lectronegativity resulting in a polar covalent bond.
Explanation:
When atoms of different elements share electrons through covalent bonding, the electron will be drawn more toward the atom with the higher e lectronegativity resulting in a polar covalent bond. When compared to ionic compounds, covalent compounds usually have a lower melting and boiling point, and have less of a tendency to dissolve in water.
In order to estimate the population size of the woodlice in her garden, Jessica used the mark-recapture method: she trapped, marked and released 20 woodlice. Three days later, she trapped 15 woodlice and observed that 10 had marks. Use the following formula to estimate the woodlice population size: population size = 1st sample × 2nd sample ÷ 2nd sample that had been marked.
NEED HELP ASAP!!!!!!
To determine the size of the entire population: In the equation N = M, replace the variables of M solutions, R (number all marked recaptured), with T (total recaptured during second visit). T R = frac M T R N = RMT.
What is the mark-recapture method's formula?In order for the mark-recapture method to function, it must be assumed that the proportion the marked organisms that are recaptured inside the second sample corresponds to that of the original marked in the entire population. This equation R(recaptured)/C(captured in second sample)=M(marked initially)/N) illustrates this (total number in population).
Why do people employ the capture-recapture technique?It has been suggested that capture-recapture techniques be used to gauge a register's degree of completeness. These techniques were initially created to determine how big a confined animal colony was. The process aims to capture, tag, and release as many animals is possible in a given region all at once. This is known as the "capture" stage.
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What does X represent for this transmutation? 9 4Be + 4₂He X+ ¹on ?
The result of the transformation, denoted by the symbol X, is 12 6C.
What does the radioactive decay symbol X stand for?The chemical symbol for the unstable nucleus, X, is represented by the nuclear equation, where the letter a stands for the particle's mass number and the letter b for the number of protons.
What is atom transmutation?the process of changing one chemical element into another. Since a transmutation involves a change to the atomic nuclei's structure, it can either be produced via a nuclear reaction (q.v. ), like neutron capture, or it can happen naturally due to radioactive decay, like alpha and beta decay (qq. v.).
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The isotope Tl-208 undergoes β decay with a half-life of 3.1 min.
What is the decay constant for this process?
a.)
4.47 min⁻¹
b.)
2.15 min⁻¹
c.)
0.224 min⁻¹
d.)
0.031 min⁻¹
The decay constant for this process is
c.) 0.224 min⁻¹How to find the decay constantThe decay constant (λ) is related to the half-life (t1/2) by the following equation:
λ = ln(2) / t1/2
where
ln(2) is the natural logarithm of 2, which is approximately 0.693.
Substituting the given half-life of 3.1 min into the equation, we get:
λ = ln(2) / (3.1 min) ≈ 0.223 min^(-1)
Therefore, the decay constant for the β decay of Tl-208 is approximately 0.223 min^(-1).
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Can someone help me with this I am too lazy to work it out
Answer:
acid +metal ----->salt +hydrogen
How many grams of Aluminum Sulfate are produced when 4 g of Aluminum Nitrate react with 3 g of Sodium Sulfate?
Al(NO3)3 + Na2SO4 ---------> Al2(SO4)3 + NaNO3
3.21 grams of Aluminum Sulfate are got when 4 g of Aluminum Nitrate reacts chemcially with 3 g of Sodium Sulfate.
WHat is the balanced equation for this reaction? How many grams of Aluminum Sulfate are produced?The equation given is not balanced. Thus, when balanced the equation becomes:
2 Al(NO₃)₃ + 3 Na₂SO₄ → Al₂(SO₄)₃ + 6 NaNO₃
The molar mass of Al(NO₃)₃ is:
Al(NO₃)₃ = 1(Al) + 3(N) + 9(O) = 213 g/mol
The molar mass of Na₂SO₄ is:
Na₂SO₄ = 2(Na) + 1(S) + 4(O) = 142 g/mol
From the balanced equation, we can see that 2 moles of Al(NO₃)₃ react with 3 moles of Na2SO4 to produce 1 mole of Al₂(SO₄)₃. Therefore, we can calculate the number of moles of Al(NO₃)₃ and Na₂SO₄ that react:
Number of moles of Al(NO₃)₃ = 4 g / 213 g/mol = 0.0188 mol
Number of moles of Na₂SO₄ = 3 g / 142 g/mol = 0.0211 mol
From the balanced equation, we can see that 2 moles of Al(NO₃)₃ produce 1 mole of Al₂(SO₄)₃. Therefore, the number of moles of Al₂(SO₄)₃ produced is:
Number of moles of Al₂(SO₄)₃ = 0.0188 mol / 2 * 1 = 0.0094 mol
The molar mass of Aluminum Sulfate (Al₂(SO₄)₃) is:
Al₂(SO₄)₃ = 2(Al) + 3(S) + 12(O) = 342 g/mol
Therefore, the mass of Aluminum Sulfate produced is:
Mass of Al₂(SO₄)₃ = Number of moles of Al₂(SO₄)₃ * Molar mass of Al₂(SO₄)₃
= 0.0094 mol * 342 g/mol
= 3.21 g
Hence, 3.21 grams of Aluminum Sulfate are liberated when 4 g of Aluminum Nitrate change state with 3 g of Sodium Sulfate.
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What is eutectic temperature
The eutectic point is the lowest temperature at which the liquid phase is constant at a particular pressure.
What does the word "eutectic" mean?A melting composition known as a eutectic consists of at least two components that melt and freeze at the same rates. The components combine during the crystallisation phase, operating as a single component as a result.
What are eutectic pressure and temperature?The eutectic is the system's lowest melting point under its own pressure; it has a matching temperature called the eutectic temperature and produces the eutectic liquid as a result. In terms of composition, eutectic liquids are located between the system's solid phases.
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At 25 ∘C
, the equilibrium partial pressures for the reaction
A(g)+2B(g)↽−−⇀C(g)+D(g)
were found to be A=5.63
atm, B=5.00
atm, C=5.47
atm, and D=5.63
atm.
What is the standard change in Gibbs free energy of this reaction at 25 ∘C ?
Δ∘rxn= ? kJmol
The reaction's equilibrium partial pressures are at 25 °C. The calculated PA value for 3A(g)+4B(g)2C(g)+3D(g) is 5.56 atm.
Explanation:
For elements within their standard condition, G0f G f 0 is taken to be zero. As a result, the reaction's standard modification of Gibb's free energy around 25 degrees Celsius becomes 98.746 kJ.
What do you mean by equilibrium?
It is a situation in which opposite forces or behaviors are in equilibrium and can be either static (like when forces act on a body and the resultant is zero) of dynamic. (as in a reversible chemical reaction when the rates of reaction in both directions are equal)
What is equilibrium, and what is its equation?
This static as well as dynamic equilibrium of every one of the the external and internal variables in the system is described by the equilibrium equation. The equilibrium equation in the static situation is. [6.23] K denotes the stiffness matrix of the system, u is the vector carrying nodal displacements, where F denotes outside forces.
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In an experiment, 5 g of Copper was heated with excess Sulfur to yield 4 g of Copper(I)Sulfide. What is the % yield?
The percent yield of copper(I) sulfide in this experiment is 31.83%.
What is percent yield?
To calculate the percent yield, we need to compare the actual yield (the amount of product that was obtained in the experiment) with the theoretical yield (the amount of product that should have been obtained if the reaction had gone to completion).
The balanced chemical equation for the reaction between copper and sulfur to form copper(I) sulfide is:
Cu + S → [tex]Cu_{2}S[/tex]
The molar mass of Cu is 63.55 g/mol, and the molar mass of S is 32.06 g/mol. The molar mass of [tex]Cu_{2}S[/tex] is 159.17 g/mol.
First, we need to calculate the theoretical yield of copper(I) sulfide using the amount of copper used in the experiment:
5 g Cu × (1 mol Cu / 63.55 g Cu) × (1 mol [tex]Cu_{2}S[/tex] / 1 mol Cu) × (159.17 g [tex]Cu_{2}S[/tex] / 1 mol [tex]Cu_{2}S[/tex] ) = 12.57 g [tex]Cu_{2}S[/tex]
So the theoretical yield of copper(I) sulfide is 12.57 g.
The actual yield obtained in the experiment is 4 g.
The percent yield is then:
percent yield = (actual yield / theoretical yield) × 100%
percent yield = (4 g / 12.57 g) × 100%
percent yield = 31.83%
Therefore, the percent yield of copper(I) sulfide in this experiment is 31.83%.
What is theoretical yield ?
The theoretical yield is the amount of product that would be obtained in a chemical reaction if it went to completion, meaning that all the limiting reactant was used up and no product was lost. It is calculated using stoichiometry, which involves balancing the chemical equation for the reaction and using the coefficients to determine the mole ratio between the reactants and products.
Theoretical yield is often used as a reference value to compare with the actual yield obtained in an experiment, which is the amount of product actually obtained from the reaction. The percent yield can then be calculated by dividing the actual yield by the theoretical yield and multiplying by 100%.
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The combustion of 136 g of methane (CH₄) in the presence of excess oxygen gas produces 353 g of carbon dioxide. [CH₄ + 2O₂ --> CO₂ + 2H₂O; C = 12.01 g/mol, H = 1.01 g/mol, O = 16.0 g/mol]
What is the percent yield?
a.)
0.385
b.)
0.026
c.)
0.947
d.)
0.00946
Taking into account definition of percent yield, the correct answer is option c): the percent yield for the reaction is 0.947.
Reaction stoichiometryIn first place, the balanced reaction is:
CH₄ + 2 O₂ → CO₂ + 2 H₂O
By reaction stoichiometry, the following amounts of moles of each compound participate in the reaction:
CH₄: 1 moleO₂: 2 molesCO₂: 1 moleH₂O: 2 molesThe molar mass of the compounds is:
CH₄: 16.05 g/moleO₂: 32 g/moleCO₂: 44.01 g/moleH₂O: 18.02 g/moleBy reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
CH₄: 1 mole ×16.05 g/mole= 16.05 gramsO₂: 2 moles ×32 g/mole= 64 gramsCO₂: 1 mole ×44.01 g/mole= 44.01 gramsH₂O: 2 moles×18.02 g/mole= 36.04 gramsMass of CO₂ formedThe following rule of three can be applied: if by reaction stoichiometry 16.05 grams of CH₄ form 44.01 grams of CO₂, 136 grams of CH₄ form how much mass of CO₂?
mass of CO₂= (136 grams of CH₄× 44.01 grams of CO₂)÷16.05 grams of CH₄
mass of CO₂= 372.92 grams
Then, 372.92 grams of CO₂ can be produced from 136 grams of CH₄.
Percent yieldThe percent yield is the ratio of the actual return to the theoretical return expressed as a percentage and this is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:
percent yield= (actual yield÷ theoretical yield)× 100%
where the theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product.
Percent yield for the reaction in this caseIn this case, you know:
actual yield= 353 gramstheorical yield= 372.92 gramsReplacing in the definition of percent yield:
percent yield= (353 grams÷ 372.92 grams)× 100%
Solving:
percent yield= 94.7%= 0.947
Finally, the percent yield for the reaction is 0.947.
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help pls!!! how many moles of H3PO4 form from 8.0 moles of H2O?
The number of mole of H₃PO₄ that can be formed from the reaction of 2 moles of P₄O₁₀ and 8 moles of H₂O is 5.33 moles
How do i determine the mole of H₃PO₄ formed?First, we shall determine the limiting reactant. Details below
P₄O₁₀ + 6H₂O -> 4H₃PO₄
From the balanced equation above,
1 mole of P₄O₁₀ reacted with 6 moles of H₂O
Therefore,
2 moles of P₄O₁₀ will react with = 2 × 6 = 12 moles of H₂O
From the above calculation, we can see that a higher amount of H₂O is needed to react completely with 2 moles of P₄O₁₀
Thus, H₂O is the limiting reactant.
Now, we shall determine the mole of H₃PO₄ formed from the reaction. Details below:
P₄O₁₀ + 6H₂O -> 4H₃PO₄
From the balanced equation above,
6 moles of H₂O reacted with 4 moles of H₃PO₄
Therefore,
8 moles of H₂O will react with = (8 × 4) / 6 = 5.33 moles of H₃PO₄
Thus, the mole of H₃PO₄ formed is 5.33 moles
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A gaseous mixture contains O₂ and another unknown gas in he molar
ratio of 4:1 effuses through a hole in 245 sec. Under similar conditions,
same volume of O, takes 220 sec to effuse. Find the molar mass of the
gas. (in g/mol)
The molar mass of the unknown gas is 28 g/mol.
What is Graham's law of effusion?Graham's law of effusion states that the rate of effusion (the escape of gas molecules through a tiny hole) of a gas is inversely proportional to the square root of its molar mass, at constant temperature and pressure. This means that lighter gases effuse (escape through a hole) faster than heavier gases, all other factors being equal.
We can use Graham's law of effusion to solve this problem:
Rate of effusion is inversely proportional to the square root of molar mass.
Thus, we can write:
(rate of effusion of O₂) / (rate of effusion of the unknown gas) =
sqrt(molar mass of the unknown gas) / sqrt(molar mass of O₂)
Let's call the molar mass of the unknown gas "M". We can set up the following system of equations using the information given in the problem:
4/1 = (rate of effusion of O₂) / (rate of effusion of the unknown gas)
(rate of effusion of O₂) = 1/220
(rate of effusion of the unknown gas) = 1/245
Plugging in these values, we get:
4/1 = (1/220) / (1/245)
4/1 = 49/44
Solving for the rate of effusion of the unknown gas, we get:
(rate of effusion of the unknown gas) = (1/245) / (49/44) = 4/539
Now we can use Graham's law of effusion to find the molar mass of the unknown gas:
(rate of effusion of O₂) / (rate of effusion of the unknown gas) =
sqrt(molar mass of the unknown gas) / sqrt(molar mass of O₂)
(1/220) / (4/539) = sqrt(M) / sqrt(32)
Solving for M, we get:
M = 28 g/mol
Therefore, the molar mass of the unknown gas is 28 g/mol.
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A balloon ascends at a constant rate V in an atmosphere that is exponentially stratified so that the variation of temperature with altitude is given by T(z) -Toe". The balloon carries a thermocouple temperature sensor having a time constant t. Determine the sensor temperature as a function of time. Sketch the sensor temperature and the actual temperature versus time
We can plug them into the equation above and plot the temperature of the sensor and the actual temperature against time on a graph to visualize how they change over time during the ascent of the balloon.
What is Temperature?
Temperature is a measure of the average kinetic energy of the particles in a substance, such as a solid, liquid, or gas. It is a scalar quantity that reflects the hotness or coldness of a substance. In other words, temperature indicates how much thermal energy is present in a substance.
This equation describes an exponential decay of the temperature with time. As time goes on, the temperature of the sensor decreases exponentially towards zero.
To sketch the sensor temperature and the actual temperature versus time, we would need additional information, such as the initial temperature T0, the time constant tc, and the rate of ascent V of the balloon.
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The speed of sound in diamond, 12,000 meters/sec, is roughly four times the
speed in air. What is the speed of sound in diamond in feet per hour (ft/hr)?
Answer:
The speed of sound in diamond is about **12,000 metres per second (39,000 ft/s)** which is about **35 times** its speed in air³. To convert this to feet per hour (ft/hr), we can use the following conversion factors:
1 meter = 3.28084 feet
1 second = 3600 hours
Therefore, the speed of sound in diamond in feet per hour (ft/hr) is:
12,000 m/s x 3.28084 ft/m x 3600 s/hr = 141,732,480 ft/hr
What happens when a solid is dissolved into a liquid?
.
True or false: the saturation level, or maximum amount that we could dissolve, for each solute in the lab changed as we changed the temperature
True as solubility usually increases as temperature increases
pls help!!!
a compound is found to be 51.39% carbon, 8.64% hydrogen, and 39.97% nitrogen. it has a molecular molar mass of 140.22 g/mol. what is the molecular formula.
show work pls!!
The molecular formula of the compound, given that it contains 51.39% carbon, 8.64% hydrogen, and 39.97% nitrogen is C₆H₁₂N₄
How do i determine the molecular formula?To obtain the molecular formula, we must first determine the empirical formula. Details on how to obtain the empirical formula is given beloww:
Carbon (C) = 51.39%Hydrogen (H) = 8.64%Nitrogen (N) = 39.97%Empirical formula =?Divide by their molar mass
C = 51.39 / 12 = 4.283
H = 8.64 / 1 = 8.64
N = 39.97 / 14 = 2.855
Divide by the smallest
C = 4.283 / 2.855 = 1.5
H = 8.64 / 2.855 = 3
N = 2.855 / 2.855 = 1
Multiply through by 2 to express in whole number
C = 1.5 × 2 = 3
H = 3 × 2 = 6
N = 1 × 2 = 2
Thus, we can conclude that the empirical formula is C₃H₆N₂
Finally, we shall determine the molecular formula. Details below
Empirical formula = C₃H₆N₂Molar mass of compound = 140.22 g/molMolecular formula =?Molecular formula = empirical × n = mass number
[C₃H₆N₂]n = 140.22
[(12×3) + (1×6) + (14×2)]n = 140.22
70n = 140.22
Divide both sides by 70
n = 140.22 / 70
n = 2
Molecular formula = [C₃H₆N₂]n
Molecular formula = [C₃H₆N₂]₂
Molecular formula = C₆H₁₂N₄
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