Determine the maximum possible number of turning points for the graph of the function. any help??

Determine The Maximum Possible Number Of Turning Points For The Graph Of The Function. Any Help??

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Answer 1

The maximum possible number of turning points on the graph of the given function is; 2.

What is the maximum possible number of turning points for f(x)?

It follows from the task content that the maximum number of turning points for the graph of the function; f(x) = (x + 1) (x + 1) (4x - 6) is to be determined.

By observation, it follows that the function is of degree 3.

Recall, the maximum possible number of turning points for a function of degree n is; (n - 1).

Consequently, since the degree of f(x) is 3; the maximum possible number of turning points is; 2.

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I have a 10% off coupon that i would like to apply to my purchase today, you have two $20. 00 items here, and one $5. 00 item what will the total be

Answers

The total price after applying the 10% discount of two $10 items and one $5 item is $40.50.

Let's calculate the original price of our items,

Two $20.00 items,

$20.00 x 2 = $40.00,

One $5.00 item, $5.00,

The total original price of our items is,

$40.00 + $5.00 = $45.00,

For finding the amount of the discount that we have to make, we just do the product of the percentage of the discount to total original amount of the items,

$45.00 x 10% = $4.50

So, the amount discounted is $4.50.

To find the amount after the discount, we subtract the discounted price from the original amount.

$45.00 - $4.50 = $40.50

Hence, the total price of the items will be $40.50.

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y=x-8/x^2+4x-5 find any points of discontinuity for the rational function

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Answer:

The rational function has a point of discontinuity at any value of x that makes the denominator equal to zero, as division by zero is undefined.

To find such values, we need to solve the equation x^2 + 4x - 5 = 0 for x:

x^2 + 4x - 5 = 0

(x + 5)(x - 1) = 0

x = -5 or x = 1

Therefore, the rational function has points of discontinuity at x = -5 and x = 1.

refer to the following frequency distribution of days absent during a calendar year by employees of a manufacturing company. days absent number of employees 0 up to 3 2 3 up to 6 25 6 up to 9 14 9 up to 12 19 12 up to 15 42 how many employees were absent six or more days? multiple choice 61 75 17 25

Answers

75 employees were absent for six or more days.

To determine how many employees were absent for six or more days, we need to refer to the given frequency distribution of days absent:

- 0 up to 3 days: 2 employees

- 3 up to 6 days: 25 employees

- 6 up to 9 days: 14 employees

- 9 up to 12 days: 19 employees

- 12 up to 15 days: 42 employees

To find the number of employees absent for six or more days, we need to add the number of employees in the last three categories:

14 (6 up to 9 days) + 19 (9 up to 12 days) + 42 (12 up to 15 days) = 75 employees

Therefore, 75 employees were absent for six or more days.

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can we predict blood pressure based on a person's gender? a random sample of 500 people was selected to determine the relationship between the two variables.what is the simplest type of statistical analysis that would be appropriate to use to analyze this data?

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The simplest type of statistical analysis that would be appropriate to analyze this data is a two-sample t-test or a chi-square test of probability.

These tests can help determine if there is a significant difference in blood pressure between males and females in the sample population. However, it is important to note that correlation does not necessarily imply causation, and other factors such as age, lifestyle, and genetics may also influence blood pressure. The tests mentioned can provide statistical evidence to determine if there is a significant difference in blood pressure between males and females in the sample population. If the p-value of the test is less than the significance level (usually 0.05), we can conclude that there is a significant difference in blood pressure between males and females.

However, it is important to keep in mind that correlation does not necessarily imply causation. Just because there is a significant difference in blood pressure between males and females does not necessarily mean that being male or female is the cause of the difference in blood pressure. Other factors such as age, lifestyle, and genetics may also play a role in determining blood pressure levels.

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a survey organization polls 500 registered voters and one of the pieces of information they collect is the voters' incomes. the average income in the sample is $65,000 per year and the sd is $35,000. the histogram of the sampled incomes is skewed to the right, and 110 (22%) of the sampled voters saying they have an income of $150,000 or more. calculate a 95%-confidence interval for the percentage of all voters in the population who have an income of $150,000 or more. group of answer choices

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The 95% confidence interval for the percentage of all voters in the population who have an income of $150,000 or more is approximately (18.38%, 25.62%).

To calculate the 95% confidence interval for the percentage of all voters in the population who have an income of $150,000 or more, we can use the following formula:
CI = p ± z*sqrt((p*(1-p))/n)
Where:
p = proportion of voters in the sample who have an income of $150,000 or more = 110/500 = 0.22
z* = z-score corresponding to 95% confidence level = 1.96 (from standard normal distribution)
n = sample size = 500
Plugging in these values, we get:
CI = 0.22 ± 1.96*sqrt((0.22*(1-0.22))/500)
CI = 0.22 ± 0.049
CI = (0.171, 0.269)
Therefore, we can be 95% confident that the percentage of all voters in the population who have an income of $150,000 or more is between 17.1% and 26.9%.
To calculate a 95% confidence interval for the percentage of all voters in the population who have an income of $150,000 or more, we will use the following formula:
CI = p-hat ± Z * √(p-hat * (1 - p-hat) / n)
Where:
- CI represents the confidence interval
- p-hat is the sample proportion (110/500 = 0.22)
- Z is the Z-score for a 95% confidence interval (1.96)
- n is the sample size (500)
Plugging the values into the formula:
CI = 0.22 ± 1.96 * √(0.22 * (1 - 0.22) / 500)
CI = 0.22 ± 1.96 * √(0.1716 / 500)
CI = 0.22 ± 1.96 * 0.01845
CI = 0.22 ± 0.03612

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class of 30 students with 14 boys and 16 girls must select 4 leaders. how many ways are there to select the 4 leaders so that at least one girl is selected?

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To solve this problem, we can use the concept of combinations. We want to select 4 leaders from a group of 30 students, so the total number of ways to select 4 leaders is:

30C4 = (30*29*28*27)/(4*3*2*1) = 27,405

Now, let's consider the number of ways to select 4 leaders where no girls are selected. Since there are 16 girls in the class, we must select all 4 leaders from the group of 14 boys. The number of ways to do this is:

14C4 = (14*13*12*11)/(4*3*2*1) = 10,626

Therefore, the number of ways to select 4 leaders where at least one girl is selected is:

27,405 - 10,626 = 16,779

So there are 16,779 ways to select the 4 leaders so that at least one girl is selected.

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Which is equivalent to the complex fraction

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The expression that is equivalent to the complex fraction is given as follows:

(-2y + 5x)/(3x - 2y)

How to simplify the fraction?

The fraction for this problem is defined as follows:

(-2/x + 5/y)/(3/y - 2/x).

The numerator is simplified as follows:

-2/x + 5/y = (-2y + 5x)/xy

The denominator is simplified as follows:

3/y - 2/x = (3x - 2y)/xy

Hence:

(-2/x + 5/y)/(3/y - 2/x) = [(-2y + 5x)/xy]/[(3x - 2y)/xy]

When two fractions are divided, we multiply the numerator by the inverse of the denominator, hence:

(-2y + 5x)/xy x xy/(3x - 2y) = (-2y + 5x)/(3x - 2y).

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Express the definite integral as an infinite series in the form ∑=0[infinity]an. ∫ 0 1 ,3 tan-1 (x²) dx (Express numbers in exact form. Use symbolic notation and fractions where needed.)

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To express the definite integral ∫ 0 1 ,3 tan-1 (x²) dx as an infinite series in the form ∑=0[infinity]an, we can use the Taylor series expansion of the arctangent function:

arctan(x) = ∑n=0[infinity] (-1)ⁿ x^(2n+1) / (2n+1)

Substituting x² for x and multiplying by 3, we get:

3 arctan(x²) = 3 ∑n=0[infinity] (-1)ⁿ (x²)^(2n+1) / (2n+1)

= 3 ∑n=0[infinity] (-1)ⁿ x^(4n+2) / (2n+1)

Integrating this series with respect to x from 0 to 1, we get:

∫ 0 1 ,3 tan-1 (x²) dx = ∫ 0 1 3 ∑n=0[infinity] (-1)ⁿ x^(4n+2) / (2n+1) dx

= 3 ∑n=0[infinity] (-1)ⁿ ∫ 0 1 x^(4n+2) / (2n+1) dx

= 3 ∑n=0[infinity] (-1)ⁿ (1/(4n+3)) / (2n+1)

= 3 ∑n=0[infinity] (-1)ⁿ / [(4n+3)(2n+1)]

Therefore, the infinite series representation of the definite integral ∫ 0 1 ,3 tan-1 (x²) dx in the form ∑=0[infinity]an is:

∑n=0[infinity] (-1)ⁿ / [(4n+3)(2n+1)]

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here is net of a right rectangular prism. the area of prism

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The surface area of rectangular prism is 48 square units

The surface area of rectangular prism is 2(lw+wh+hl)

From the figure the height is 2 units

width is 2 units

length is 5 units

Plug in these values in formula

Surface area = 2(5×2 + 2×2 + 2×5)

=2(10+4+10)

=2(24)

=48

Hence, the surface area of rectangular prism is 48 square units

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Help me pleaseee!!!!!!!!!!!!!!!!!!

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Answer:

5 units

Step-by-step explanation:

Helping in the name of Jesus.

A hot air balloon travels 18 miles in 3 hours. At this rate, how many miles will the hot air balloon travel in 3/4 hour?

Answers

Answer:

At the given rate, the hot air balloon can travel 9/2 or 4.5 miles in 3/4 of an hour

Step-by-step explanation:

We can solve this problem one of two ways:  

We can either make a proportion between the first distance (18 mi) and time (3 hr) and the second distance (d) and time (3/4 hr), where we'll need to solve for the second distance, or We can use the distance-rate-time formula to find how fast it took the hot air balloon to travel 18 miles in 3 hours.  Then, we can use this rate to find the distance it can travel in 3/4 hours.

The first ways seems the most straight forward, while the second ways helps you confirm your answer, as I'll show at the end:

[tex]\frac{18}{3}=\frac{d}{3/4} \\\\27/2=3d\\9/2=d\\4.5=d[/tex]

We can check our answer by first finding the rate at which the hot air balloon travelled 18 miles using the distance-rate-time formula, which is

d = rt, where d is the distance, r is the rate, and t is the time:

18 = 3r

6 = r

Now, we can check whether the product of the rate (6 mph) and the second time (3/4 hr) equals the second distance (9/2 mi)

9/2 = 6 * 3/4

9/2 = 9/4

9/2 = 9/2

Increase 380 by 143%

Answers

The Correct Answer is:

923.4

a fair coin is flipped 10 times. a) (b) what is the probability the first three flips are heads? what is the probability that there are an equal number of head and tails? (c) what is the probability that there are an equal number of heads and tails and the first three flips are heads?

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(a) The probability of getting heads or tails on a fair coin flip is both 1/2. Therefore, the probability of getting three heads in a row is (1/2)^3 = 1/8.

(b) The probability of getting an equal number of heads and tails in 10 coin flips is the sum of the probability of getting 5 heads and 5 tails, 4 heads and 6 tails, 6 heads and 4 tails, and so on. This can be calculated using the binomial distribution, with n=10 and p=0.5. The formula for the binomial distribution is P(X=k) = (n choose k) * p^k * (1-p)^(n-k), where (n choose k) is the number of ways to choose k items from a set of n items. Using this formula, we get P(X=5) + P(X=6) + P(X=7) + P(X=8) + P(X=9) + P(X=10) = 0.623.

(c) The probability of getting three heads in a row and an equal number of heads and tails in 10 coin flips can be calculated by multiplying the probabilities of each event. Using the result from part (a), we get P(three heads in a row and X=5) = (1/8) * P(X=5) = (1/8) * 0.246 = 0.031. Therefore, the probability of getting three heads in a row and an equal number of heads and tails in 10 coin flips is 0.031.

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Plot the points A(-7,1), B(-3, -6), C(2, -4) on the coordinate axes below. State the
coordinates of point D such that A, B, C, and D would form a parallelogram.
(Plotting point D is optional.)

Answers

(-2, 3) are the coordinates of point D of parallelogram.

A(-7,1), B(-3, -6), C(2, -4)

Let the 4th point D = (x , y)

In a parallelogram, diagonals bisect each other.

midpoint of BD = midpoint of AC

If two points are (x₁ , y₁) and (x₂,y₂)

then midpoint = {(x₁+x₂)/2 , (y₁+y₂)/2}

midpoint of AC = {(-7 + 2)/2 , (1-4)/2}

= {-5/2 , -3/2}

midpoint of BD = {(-3 + x)/2 , (-6 + y)/2}

Now,

midpoint of BD = midpoint of AC

{-5/2 , -3/2} =  {(-3 + x)/2 , (-6 + y)/2}

Comparing both sides

(-3 + x)/2 = -5/2

-3+x=-5

x=-2

taking y -coordinate

(-6+ y)/2 = -3/2

-6 + y = -3

y = 3

Point D (x , y) = (-2, 3)

Hence,  (-2, 3) are the coordinates of point D of parallelogram.

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2. Determine whether the following sequence converges, and if so, find its limit. cos() (a) »* b){uče on(0) {cx*(n + 1}} n-2n} c nn n2

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The sequence is of the form a_n / b_n, where b_n goes to negative infinity and a_n is bounded. By the ratio test, we can conclude that the sequence converges to 0. Hence, the limit of the sequence is 0.


However, I can still explain the terms "sequence", "limit", and "converges" for you:

1. Sequence: A sequence is an ordered list of elements, usually numbers, which are connected by a specific rule or pattern. For example, an arithmetic sequence is defined by the common difference between consecutive terms.

2. Limit: The limit of a sequence is a value that the terms of the sequence get arbitrarily close to as the sequence progresses. If a sequence has a limit, it means that as the number of terms (n) increases, the value of the sequence approaches a specific value.

3. Converges: A sequence is said to converge if it has a limit. In other words, as the number of terms (n) goes to infinity, the terms of the sequence approach a specific value. If a sequence does not have a limit or does not approach a specific value, it is said to diverge.
Let's first look at the denominator, (n - 2n^2). As n approaches infinity, the second term dominates and the denominator goes to negative infinity.

Now let's look at the numerator, cos((n+1)/n). As n approaches infinity, the argument of cos approaches 1, and cos(1) is a fixed value.

Therefore, the sequence is of the form a_n / b_n, where b_n goes to negative infinity and a_n is bounded. By the ratio test, we can conclude that the sequence converges to 0

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A map has a scale of 1:200 000.
Find the area, in square kilometres, of a lake that has an area of 12.4 cm² on the map.

Answers

The area of the lake on the map scale of  1:200000 is found to be 0.496 km²

To find out the size of the lake, we have to find the area of the map and then we will use the scaling.

We know that the scale of the map is 1:200000. This means that 1 centimeter on the map represents 200,000 centimeters on the ground. Now, converting the values. So, the area of the lake on the ground is,

(12.4cm²/10,000,000)(200,000cm/1cm)² = 0.496 km²

Therefore, the area of the lake is 0.496 square kilometers (rounded to three decimal places).

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Find the dircetional derivative of f(x. y, z) = xy + z^3 at the point P = (3, -2, -1) in the direction pointing to the origin.

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The directional derivative of f(x, y, z) at the point P in the direction pointing to the origin is 3√(14)/14.

To find the directional derivative of f(x, y, z) = xy + z^3 at P = (3, -2, -1) in the direction pointing to the origin, we need to first find the gradient of f at P.

Gradient of f(x, y, z) = ∇f(x, y, z) = (fx, fy, fz) = (y, x, 3z^2)

At P = (3, -2, -1), the gradient of f is:

∇f(3, -2, -1) = (-2, 3, 3)

The direction vector pointing from P to the origin is:

d = <-3, 2, 1>

To find the directional derivative of f at P in the direction of d, we need to take the dot product of the gradient of f at P and the unit vector in the direction of d:

|d| = √((-3)^2 + 2^2 + 1^2) = √(14)

u = d/|d| = <-3/√(14), 2/√(14), 1/√(14)>

Directional derivative of f at P in the direction of d is:

Duf(P) = ∇f(3, -2, -1) · u

Duf(P) = (-2, 3, 3) · <-3/√(14), 2/√(14), 1/√(14)>

Duf(P) = (-6/√(14)) + (6/√(14)) + (3/√(14))

Duf(P) = 3√(14)/14

Therefore, the directional derivative of f(x, y, z) = xy + z^3 at the point P = (3, -2, -1) in the direction pointing to the origin is 3√(14)/14.

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Suppose that g^a ≣ 1 (mod m) and that g^b ≣ 1 (mod m).

Prove that g^gcd(a,b) ≣ 1 (mod m)

Answers

To prove that g^gcd(a,b) ≣ 1 (mod m), we can use the fact that for any integers a and b, there exist integers x and y such that gcd(a,b) = ax + by (known as Bezout's identity).

Let d = gcd(a,b) and write a = dx and b = dy for some integers x and y.

Then we have:

g^d = g^(ax+by) = (g^a)^x * (g^b)^y ≣ 1^x * 1^y ≣ 1 (mod m)

since g^a ≣ 1 (mod m) and g^b ≣ 1 (mod m) by assumption.

Therefore, g^gcd(a,b) ≣ 1 (mod m) is desired.

HENCE, PROVED

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A local college recorded the number of students who registered for each class offered during the first summer session. The data is presented in the box-and-whisker plot shown. Which is the range of the number of students per class for the top 25% of the classes?

Answers

To find the range of the number of students per class for the top 25% of the classes, we need to determine the range of the upper quartile of the data.

The upper quartile (Q3) is represented by the top of the box in the box-and-whisker plot. We can see that the top of the box is at approximately 32 students.

To determine the range of the upper quartile, we need to find the value of the data point that represents the 75th percentile (Q3) and subtract it from the maximum value (the top whisker).

The range of the upper quartile is:

Range = Maximum - Q3

The maximum value is represented by the top whisker, which appears to be at approximately 48 students.

To find the value of Q3, we can use the median of the upper half of the data. The median of the upper half of the data is represented by the bottom of the box in the box-and-whisker plot, which appears to be at approximately 28 students.

Therefore, the range of the upper quartile is:

Range = Maximum - Q3 = 48 - 28 = 20

So the range of the number of students per class for the top 25% of the classes is 20.

what is a residual? for a given set of data (paired observations of x and y), how many residuals are there?

Answers

A residual is the difference between the observed value of y and the predicted value of y (y-hat) based on the regression equation.

In other words, it is the amount of variation in the data that is not explained by the regression model. For a given set of data with paired observations of x and y, there is one residual for each observation. These residuals are used to assess the accuracy of the regression model and can help identify outliers or areas where the model may need to be improved.


A residual is the difference between an observed value of a dependent variable (y) and its predicted value, based on a regression model. In a given set of data with paired observations of x and y, the number of residuals will be equal to the number of observations. So, if you have n paired observations, there will be n residuals.

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Write the following power series in sigma notation 2x 1 + + + + + √5.5 9.52 V13.53 717.54 4x2 8x3 16x4

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The power series can be written in sigma notation as: ∑(n=0 to ∞) [ (2x)^n / (n! * √(5.5 + n)) + (4x^2)^n / (n! * 9.52) + (8x^3)^n / (n! * 13.53) + (16x^4)^n / (n! * 717.54) ]

the given power series in sigma notation. The power series you provided is:

2x^1 + 4x^2 + 8x^3 + 16x^4 + ...

First, let's identify the pattern in the series. We can see that the coefficient of each term is a power of 2, and the exponent of x is increasing by 1 for each term.

To write this in sigma notation, we can use the following formula:

∑(2^n * x^(n+1))

where the summation is from n=0 to infinity.

So, the sigma notation for the given power series is:

∑(2^n * x^(n+1)) from n=0 to ∞

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if 1 cm on a map equals 1 km on earth, the fractional scale would be written as

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The fractional scale for a map where 1 cm represents 1 km on Earth would be written as 1:100,000. This means that one unit of measurement on the map (1 cm) represents 100,000 units of measurement in the real world (1 km).

A fractional scale on a map represents the relationship between distances on the map and the corresponding distances on the Earth's surface. In this case, where 1 cm on the map represents 1 km on Earth, the fractional scale is determined by comparing the two distances.

The numerator of the fraction represents the map distance (1 cm), and the denominator represents the equivalent Earth distance (1 km). To convert the numerator and denominator into the same units, both are typically expressed in the same unit of measurement, such as centimeters or kilometers. Therefore, the fractional scale for this scenario would be written as 1:100,000, indicating that one unit of measurement on the map corresponds to 100,000 units of measurement on Earth.

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TRAINGLE ABC IS A EQILATERAL TRIANGLE SEE QUESTION IN ATTACHED DOCUMENT AND SOLVE

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According to the given triangle, the value of ∠AFE = 48 degrees. (option b).

Let's start by looking at the given figure. We have an equilateral triangle ABC, which means all its sides are equal, and all its angles are 60 degrees. We are also given a point D outside the triangle and an angle CAD of 18 degrees. This means that the angle CAD and the angle BAC are supplementary (they add up to 180 degrees), since they both share the side AC.

Now, we can apply the angle bisector theorem to the triangle AEB. This tells us that AE/EB = AD/DB. Since CD = BE and triangle ADE is congruent to triangle BDC, we can say that

AD/DB = AE/EC = (AE + EC)/EC = AC/EC.

Therefore,

=> AE/EC = AC/EC - 1 = (2 cos 18 - 1)/sin 18.

Solving for sin ∠AFE, we get sin

∠AFE = (sin 12)(sin (42 - x))/sin (126 - x)(sin (60 - x)).

Taking the inverse sine of this value, we get

∠AFE = 48 degrees.

Therefore, the answer is option B, 48 degrees.

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calculate the average rate of change of f (x )equals cube root of x plus 5 end root on the interval [-4, 3].

Answers

Answer:

average rate of change = [tex]\frac{1}{7}[/tex]

Step-by-step explanation:

the average rate of change of f(x) in the closed interval [ a, b ] is

[tex]\frac{f(b)-f(a)}{b-a}[/tex]

here [ a, b ] = [ - 4, 3 ] , then

f(b) = f(3) = [tex]\sqrt[3]{3+5}[/tex] = [tex]\sqrt[3]{8}[/tex] = 2

f(a) = f(- 4) = [tex]\sqrt[3]{-4+5}[/tex] = [tex]\sqrt[3]{1}[/tex] = 1

average rate of change = [tex]\frac{2-1}{3-(-4)}[/tex] = [tex]\frac{1}{3+4}[/tex] = [tex]\frac{1}{7}[/tex]

using the given measures of the non-right triangle, solve for the remaining three measures. the triangle is not drawn to scale. a = 20, c = 22, and angle c = 18 degrees. find b =

Angle A =

Angle B =

Answers

The remaining three measures are b ≈ 2.3, A ≈ 41.4 degrees, B ≈ 9 degrees. solve for the remaining three measures of the non-right triangle, we can use the Law of Cosines. The formula is: c^2 = a^2 + b^2 - 2abcos(C).

Using the given measures, we can plug them into the formula and solve for b:
22^2 = 20^2 + b^2 - 2(20)(b)cos(18)
484 = 400 + b^2 - 40bcos(18)
84 = b^2 - 40bcos(18)
We can use the Law of Sines to solve for angles A and angle B. The formula is:
a/sin(A) = b/sin(B) = c/sin(C)
Plugging in the given measures:
20/sin(A) = b/sin(B) = 22/sin(18)
Solving for sin(A):
sin(A) = (20*sin(18))/22
sin(A) ≈ 0.65

Taking the inverse sine:
A ≈ 41.4 degrees
Solving for sin(B):
sin(B) = (b*sin(18))/22
sin(B) ≈ 0.766b
Substituting sin(A) and sin(B) into the equation for b:
84 = b^2 - 40(sin(A)/sin(B))(b)
84 = b^2 - (57.5)b
b^2 - (57.5)b - 84 = 0
Using the quadratic formula:
b ≈ 55.2 or b ≈ 2.3
Since b must be shorter than c (22), the solution is b ≈ 2.3.

Therefore, angle B can be found using the Law of Sines:
20/sin(41.4) = 2.3/sin(B)
sin(B) ≈ 0.154
Taking the inverse sine:
B ≈ 9 degrees
Therefore, the remaining three measures are:
b ≈ 2.3
A ≈ 41.4 degrees
B ≈ 9 degrees

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Can someone help wit this question

Answers

The volume of the rectangular prism is 28 cm³.

The volume of the triangular prism is 720 cm³.

How to find the volume of a figure?

The figures are rectangular prism and a triangular prism. The volume of the prism can be found as follows:

volume of the rectangular prism = lwh

where

l = lengthw = widthh = height

Therefore,

volume of the rectangular prism = 2 × 7 × 2

volume of the rectangular prism = 4 × 7

volume of the rectangular prism = 28 cm³

Therefore,

volume of the triangular prism = 1 / 2 bhl

where

h = height of the triangleb = base of the triangular basel = height of the prism

Hence,

volume of the triangular prism = 1 / 2 × 8 × 15 × 12

volume of the triangular prism = 1440  /2

volume of the triangular prism = 720 cm³

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what is the null hypothesis? group of answer choices the mean driving times for the three routes are different the mean driving times for the three routes are the same the mean driving times for the three routes are independent

Answers

The null hypothesis is a statement that assumes there is no significant relationship between two variables or that there is no difference between two groups. In the context of the given question, the null hypothesis would be that the mean driving times for the three routes are the same.

This means that there is no significant difference in the average driving times for the three routes being compared. The null hypothesis is often used in statistical hypothesis testing, where it is compared against the alternative hypothesis to determine if the observed data provides enough evidence to reject the null hypothesis.

In this case, the alternative hypothesis could be that the mean driving times for the three routes are different, indicating that there is a significant difference in the average driving times for the three routes. By testing the null hypothesis, researchers can determine whether or not there is a significant difference in the data being analyzed.

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find the measure of x in p.​

Answers

The measure of x in the circle in the image above is calculated as:

x = 62.

How to Find the Measure of x in the Circle?

To find the measure of x, recall that the measure of a full circle is equal to 360 degrees, and also, a central angle is equal to the measure of the arc of a circle.

Therefore, we have:

65 + 2x - 19 + 3x + 4 = 360

Combine like terms:

50 + 5x = 360

5x = 360 - 50

5x = 310

5x/5 = 310/5

x = 62

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The boys football team is selling game tickets for a football game. Adult admission is $8 and student admission is $6 there are usually twice as many students than adults at the game. If the goal is to make $3000. Write 2 equations. Solve the system of equations, how many student and adult tickets must be sold? Let a = the number of adults and b = the number of students

Answers

To make $3000 selling game tickets, the boys football team needs to sell a combination of adult and student tickets. Solving the system of equations gives the number of adult and student tickets that must be sold 150 adult tickets and 300 student tickets.

The first equation relates the number of adults and students: since there are twice as many students as adults, we can write

b = 2a

where b is the number of students and a is the number of adults.

The second equation relates the revenue from ticket sales to the number of adults and students

8a + 6b = 3000

where 8a is the revenue from adult tickets and 6b is the revenue from student tickets.

Now we can substitute the first equation into the second equation to get

8a + 6(2a) = 3000

Simplifying, we get

20a = 3000

Dividing by 20, we get

a = 150

This means we need to sell 150 adult tickets. Using the first equation, we can find the number of student tickets

b = 2a = 2(150) = 300

So we need to sell 300 student tickets.

Therefore, the boys football team must sell 150 adult tickets and 300 student tickets to reach their goal of making $3000.

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If VI + Vy=9 and y(64) = 1, find y(64) by implicit differentiation. (64) =

Answers

The y is a constant function, since its derivative is 0, Therefore, y(64) = 1

To solve this problem, we need to use implicit differentiation. First, we differentiate both sides of the equation VI + Vy = 9 with respect to x (since y is a function of x) using the chain rule:

d/dx(VI) + d/dx(Vy) = d/dx(9)

Since VI is a constant, its derivative is 0, and we can simplify to:

V d/dx(y) = 0

Now we can solve for d/dx(y):

d/dx(y) = 0/V = 0

This tells us that y is a constant function, since its derivative is 0. Therefore, y(64) = 1 is the only possible value for y(64), since it is given in the problem.

So, to answer the question, y(64) = 1.


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