Determine the point on the graph of the linear equation 2x + 5y = 19, whose ordinate is 1 1/2 times its abscissa.

Answer: is it y - 1 = 1/2(x -5) ?

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

Answer:

the answer is b

Step-by-step explanation:

because If you go over -3 to the left and up 5 then you get to b

You would expect approximately 136 numbers in the data set to be between 56 and 74.

To determine the number of numbers you would expect to be between 56 and 74 in a normally distributed data set with a mean of 65 and a standard deviation of 9, we can utilize the properties of the standard normal distribution.

First, we need to standardize the values of 56 and 74 by converting them to z-scores. The z-score formula is:

z = (x - μ) / σ

where z is the z-score, x is the data value, μ is the mean, and σ is the standard deviation.

For 56:

z = (56 - 65) / 9

z = -1

For 74:

z = (74 - 65) / 9

z = 1

Next, we need to find the area under the standard normal curve between the z-scores -1 and 1. We can use a standard normal distribution table or a calculator to find this probability.

Using a standard normal distribution table, the area between -1 and 1 is approximately 0.6826. This represents the proportion of the data that falls within one standard deviation of the mean.

To find the number of numbers expected to be between 56 and 74, we multiply the proportion by the total number of data points:

Expected number = Proportion * Total number of data points

Expected number = 0.6826 * 200

Expected number ≈ 136.52

As a result, you would anticipate that roughly 136 of the data set's numbers would fall between 56 and 74.

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Answer:

Algebraic Expression?

Answer:

-6

Step-by-step explanation:

To find the slope the the formula is y=mx+b

m means slope so -6 is the slope

Answer:

Step-by-step explanation:

To find the acceleration of an object given it's mass and the force acting on it can be found by using the formula

[tex]acceleration = \frac{force}{mass} \\ [/tex]

From the question

force = 5 N

mass = 10 kg

So we have

[tex]acceleration = \frac{5}{10 } = \frac{1}{2} \\ [/tex]

We have the final answer as

Hope this helps you

The Acceleration of 10kg Maas's pushed by a 5n force:

0.5 m/s²

Answer: 4.The equation has no solutions.

The equation 2+3x=4x+1-X has no solutions.

To solve for x, we can combine like terms and then factor the equation.

2+3x=4x+1-X

-X+3x=1-2

2x=-1

x=-1/2

However, this value of x does not satisfy the original equation. When we substitute x=-1/2 into the original equation, we get

2+3(-1/2)=4(-1/2)+1-(-1/2)

-1=-3

This is a contradiction, so the equation has no solutions.

Therefore, the correct answer is 4. The equation has no solutions.

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Answer:

the answe its the light blue/green the y=3x+3

Step-by-step explanation:

To compute a weighted average forecast for the given demand data, we assign weights to each period based on their relative importance. The most recent period has a weight of 0.4, the next most recent period has a weight of 0.3, and the remaining periods have weights of 0.2 each. By multiplying each demand value with its corresponding weight and summing the results, we can calculate the weighted average forecast.

To compute the weighted average forecast, we multiply each demand value by its corresponding weight and sum the results. Given the demand data:

Period 1: Demand = 44

Period 2: Demand = 42

Period 3: Demand = 44

Period 4: Demand = 42

Period 5: Demand = 47

Using the provided weights, we assign the following weights to each period:

Period 1: Weight = 0.4

Period 2: Weight = 0.3

Period 3: Weight = 0.2

Period 4: Weight = 0.2

Period 5: Weight = 0.2

Now, we multiply each demand value by its corresponding weight:

Weighted Demand for Period 1: 44 * 0.4 = 17.6

Weighted Demand for Period 2: 42 * 0.3 = 12.6

Weighted Demand for Period 3: 44 * 0.2 = 8.8

Weighted Demand for Period 4: 42 * 0.2 = 8.4

Weighted Demand for Period 5: 47 * 0.2 = 9.4

Finally, we sum up the weighted demand values:

Weighted Average Forecast = 17.6 + 12.6 + 8.8 + 8.4 + 9.4 = 56.8

Therefore, the weighted average forecast for the given demand data is 56.8.

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Answer:

Questions no 1

Answer : width of the parking lot is 88m

Questions no 2

Answer : length of the pool is 79m

Answer:

(a):88m (b):79m BE sure to look at step so you learned :)

Step-by-step explanation:

p=374m

l=99,

BRUH

so

2(99+w)=374

198+2w=374

2w=176

w=88

for B:

a=4898m^2

w=62

let l me the lenth of the pool

use a=lw

4898=62l

L=79

The equation in slope-intercept form of the line that passes through (6, −1) and (3, −7) is:y = 2x − 13.

To write an equation in slope-intercept form of the line that passes through (6, −1) and (3, −7), you will use the point-slope form, as follows:

y − y1 = m(x − x1),

where:

m = slope (or gradient) of the line, and

(x1, y1) = the coordinates of a point on the line.

Let us calculate the slope (gradient) of the line using the given points:

(6, −1) and (3, −7).

m = (y2 − y1)/(x2 − x1)

m = (−7 − (−1))/(3 − 6)

= −6/−3

= 2

Thus, the slope of the line is 2.

Using the coordinates of one of the points, say (6, −1), in the point-slope form, we obtain:

y − y1 = m(x − x1)y − (−1)

= 2(x − 6)y + 1

= 2x − 12

Subtracting 1 from both sides, we get:

y = 2x − 13

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A work of art can be considered anything someone made. Someone took the time and energy into making the car and clothes. The car is like a sculpture and the clothes and like painting on a shirt.

Answer:

  KL = 3

Step-by-step explanation:

It appears we are to assume that K lies between J and L, so we have ...

  JK +KL = JL

  (2x+3) +(x) = (4x)

  3x +3 = 4x

  3 = x . . . . . . . subtract 3x

KL = 3

Answer:

4

Step-by-step explanation:

JL  =  JK + KL Additive Property of Length

4x + 5  =  (5x − 1) + 2x Plug in JL = 4x + 5, JK = 5x − 1, and KL = 2x

4x + 5  =  7x − 1 Add

4x + 6  =  7x Add 1 to both sides

6  =  3x Subtract 4x from both sides

2  =  x Divide both sides by 3

Now, use the value of x to find KL.

KL  =  2x Given

KL  =  2(2) Pluginx = 2

KL  =  4 Multiply

The value of x is approximately 0.019.

To solve the equation a = b * (c - d) + d + x for x, we can substitute the given values of a, b, c, and d into the equation and solve for x.

Given:

a = 0.16

b = 0.2

c = 0.14

d = 0.01

Substituting these values into the equation, we have:

0.16 = 0.2 * (0.14 - 0.01) + 0.01 + x

Simplifying the equation, we get:

0.16 = 0.2 * 0.13 + 0.01 + x

0.16 = 0.026 + 0.01 + x

0.16 = 0.036 + x

Subtracting 0.036 from both sides of the equation, we have:

0.16 - 0.036 = x

0.124 = x

Therefore, the value of x is approximately 0.124 (rounded to three decimal places).

Please note that there was a discrepancy in the given equation provided. The correct equation should be a = b * (c - d) + d + x, not a=b∗(c−d)+d+x​.

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Answer: number three the answer is 0.15 And for number four the answer is 0.49, 0.5, 3/5, 17/20

Step-by-step explanation:

Answer:

30?

Step-by-step explanation:

divide 20 by 8 and then times the answer by 12

Answer:

10:45 - they started watching the film at this time

Step-by-step explanation:

Given that James saw exactly one of these types of animal, the probability that he saw a crocodile is given as follows:

1/3.

The parameters that are needed to calculate a probability are listed as follows:

Then the probability is calculated as the division of the number of desired outcomes by the number of total outcomes.

The probability of seeing exactly one type of animal is given as follows:

2/5 x 1/6 + 3/5 x 2/9 = 1/15 + 6/45 = 3/45 + 6/45 = 9/45.

The probability of seeing exactly one type of animal and being a crocodile is given as follows:

2/5 x 1/6 = 1/15 = 3/45.

Hence the conditional probability is given as follow:

(3/45)/(9/45) = 3/9 = 1/3.

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12.1 T(-v) = -T(v) for a linear transformation T from V to W.

12.2 T: M22 → M22 defined by T(A) = A + AT is a linear transformation by verifying the additivity and homogeneity properties.

12.1 To prove that T(-v) = -T(v), let's consider a vector v in V. Since T is a linear transformation, it satisfies the property T(u + v) = T(u) + T(v) for any vectors u and v in V.

Now, let's consider -v, the negative of v. By the properties of vector spaces, -v can be expressed as -v = (-1)v. Applying the linearity property, we have T(-v) = T((-1)v) = (-1)T(v) = -T(v). Thus, T(-v) is indeed equal to -T(v), as required.

12.2 To show that T: M22 → M22 defined by T(A) = A + AT is a linear transformation, we need to verify two properties: additivity and homogeneity.

Additivity: For any matrices A and B in M22, we need to show that T(A + B) = T(A) + T(B). Let's consider A and B. Applying the transformation T, we have T(A + B) = (A + B) + (A + B)T. Simplifying, we get T(A + B) = A + B + AT + BT = (A + AT) + (B + BT) = T(A) + T(B).

Homogeneity: For any scalar c and matrix A in M22, we need to show that T(cA) = cT(A). Let's consider cA. Applying the transformation T, we have T(cA) = cA + c(AT). Simplifying, we get T(cA) = c(A + AT) = cT(A).

Since T satisfies both the additivity and homogeneity properties, it is a linear transformation.

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Answer:

0.875

Step by step explanation:

Answer:

y=-1/2x+7/2

Step-by-step explanation:

we already know the slope of the line is -1/2

so right now it's: y=-1/2x+b (b is a placeholder for the y intercept)

however, we need the y intercept.

Find that by plugging in the point (-5,6)

6=-1/2(-5)+b

6=5/2+b

7/2=b

therefore the line should be y=-1/2x+7/2

Hope this helps!

The given matrix A has singular values σ₁ = 8, σ₂ = 0, and σ₃ = 0. An orthogonal matrix V can be found such that VTAV = Σ, where Σ is a diagonal matrix with singular values on the diagonal.

Similarly, an orthogonal matrix U can be found such that for each nonzero singular value σᵢ of A, the corresponding columns of U and V satisfy uᵢ = Avᵢ. The singular value decomposition of A is given by A = UΣVT.

To find the singular values of A, we need to calculate the eigenvalues of the matrix AᵀA. First, we calculate AᵀA:

AᵀA = [[0, 1, 0], [-3, 0, 0], [0, 1, 0]][[0, -3, 0], [1, 0, 1], [0, 0, 0]] = [[1, 0, 1], [0, 1, 0], [0, 0, 0]].

The eigenvalues of AᵀA are the singular values squared. The eigenvalues of AᵀA are λ₁ = 2, λ₂ = 1, and λ₃ = 0. Therefore, the singular values of A are σ₁ = √(λ₁) = √2, σ₂ = √(λ₂) = 1, and σ₃ = √(λ₃) = 0.

To find an orthogonal matrix V, we need to calculate the eigenvectors corresponding to the nonzero eigenvalues of AᵀA. The eigenvectors corresponding to λ₁ = 2 and λ₂ = 1 are v₁ = [1, 0, 1] and v₂ = [0, 1, 0], respectively. We normalize these eigenvectors to obtain unit vectors: v₁' = [1/√2, 0, 1/√2] and v₂' = [0, 1, 0].

An orthogonal matrix V can be constructed by using these unit eigenvectors as its columns: V = [[1/√2, 0, 1/√2], [0, 1, 0], [1/√2, 0, -1/√2]].

To find an orthogonal matrix U, we can calculate the columns of U using the equation uᵢ = Avᵢ for each nonzero singular value σᵢ. Since σ₂ = σ₃ = 0, we do not need to calculate the corresponding columns of U.

The singular value decomposition of A is given by A = UΣVT, where U = [[1/√2, 1/√2], [0, 0]], Σ = [[√2, 0], [0, 0]], and VT = [[1/√2, 0, 1/√2], [0, 1, 0]].

Therefore, the singular value decomposition of A is A = UΣVT = [[1/√2, 1/√2], [0, 0]][[√2, 0], [0, 0]][[1/√2, 0, 1/√2], [0, 1, 0]].

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The solution is as follows: The amount paid by Kendall will be $250 per month if she chooses self-employment at The Centerville Salon and gives 50 haircuts per month.  The amount paid by Kendall will be $200 per month if she chooses to work at the franchise and gives 50 haircuts per month.

To write a system of equations and graph them, we first need to define our variables.

Let x be the number of haircuts Kendall gives in a month. The two options for Kendall are:

Self-employment at The Centerville Salon. In this case, Kendall will pay $300 per month to rent a station and keep all of her earnings. So, if she performed x haircuts, then the total amount she earns is x dollars. However, she has to pay $300 to the salon.

So, her net earnings for the month will be x – 300.The franchise option. In this case, Kendall will have to pay the salon $6 for every haircut. So, the total amount she pays the salon will be 6x.

Therefore, Kendall's net earnings for the month will be x – 6x = –5x

We know that the amount paid to either salon would be the same if Kendall gives a certain number of haircuts every month. So, we can equate the net earnings for both the options and solve for x.

–5x = x – 300–6x

= –300x

= 50

Now that we have the value of x, we can find Kendall's net earnings for both the options. When Kendall gives 50 haircuts in a month, her net earnings from self-employment will be 50 – 300

= –250 dollars.

This means she will actually have to pay the salon $250.

When Kendall gives 50 haircuts in a month, her net earnings from the franchise will be

50 – 6(50) = –200 dollars.

This means she will actually have to pay the salon $200.

Hence, the solution is as follows: The amount paid by Kendall will be $250 per month if she chooses self-employment at The Centerville Salon and gives 50 haircuts per month.

The amount paid by Kendall will be $200 per month if she chooses to work at the franchise and gives 50 haircuts per month.

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Answer:

40 pounds is x% of 75 pounds.

Answer:

you need 13

Step-by-step explanation:

because you need at least 5 and a 8 water bottles and 8+5 is 13

The null hypothesis for the test would be that there is no difference between the ratings for the existing coffee flavors and the newly introduced holiday flavor. The alternative hypothesis would be that there is a significant difference between the ratings.If the p-value of the test is less than the level of significance, the company can reject the null hypothesis and conclude that there is a significant difference between the ratings for the two sets of flavors. This would indicate that the holiday flavor is preferred more than the existing flavors and the company can introduce it as a new flavor for the holiday season.

The coffee company can use a hypothesis test for matched pairs in a situation where they want to compare the preferences of their customers for the existing coffee flavors with the newly introduced holiday flavor. By conducting a matched-pairs hypothesis test, the company can determine whether the holiday flavor is preferred more than the existing flavors.Matched-pairs hypothesis test is a statistical test used to determine the difference between two related variables. In this case, the related variables are the preferences of the customers for existing coffee flavors and the newly introduced holiday flavor. The test involves measuring the differences between the paired variables and determining whether the differences are significant enough to indicate a preference for one flavor over the other.
For instance, the coffee company can conduct a survey among its customers to determine their preferences for the different coffee flavors. The survey can involve asking the customers to rate the existing coffee flavors and the newly introduced holiday flavor on a scale of 1 to 10. The company can then compare the ratings for each customer to determine whether the holiday flavor is preferred more than the existing flavors.After collecting the data, the company can use a paired t-test to determine whether the differences in the ratings are significant.

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A. To obtain the Cartesian and polar forms of the function f(z) = z², we square the complex number z and express it in both forms.

B. To verify if u(x, y) = (x y³ -x³y) is a harmonic function, we check if it satisfies Laplace's equation. We can then construct the analytic function w = f(z) = u(x, y) + iv(x, y) by introducing a harmonic conjugate.

C. To find the poles and classify their orders for the given functions, we analyze the denominators and determine the values of z for which the functions become singular.

A. The function f(z) = z² can be expressed in Cartesian form as f(z) = (x + iy)² = x² - y² + 2ixy. In polar form, we write z as z = re^(iθ), where r represents the magnitude and θ is the argument. Squaring z gives f(z) = r²e^(2iθ).

B. To verify if u(x, y) = (x y³ - x³y) is harmonic, we calculate its second-order partial derivatives with respect to x and y. If Laplace's equation (∂²u/∂x² + ∂²u/∂y² = 0) holds true, then u is harmonic.

Next, we introduce a harmonic conjugate v(x, y) such that vₓ = -uₓ and vᵧ = -uᵧ. Solving these partial differential equations gives us v(x, y) = -(x³ + 3xy²) + C, where C is a constant.

Thus, the analytic function w = f(z) = u(x, y) + iv(x, y) is given by w = (x y³ - x³y) - i(x³ + 3xy²) + C.

C. To find the poles and classify their orders for the given functions:

f(z) = ²1: There is no denominator, so the function has no poles.

f(z) = z¹ + 2z² + 1: The denominator is z² + z + 1, which can be factored as (z - ω)(z - ω²), where ω is a complex cube root of unity. The function has simple poles at z = ω and z = ω², with orders 1.

f(z) = z² + z + 1: The denominator is z² + z + 1, which does not factor further. The function has no poles.

By analyzing the denominators of the functions, we determine the poles and classify their orders accordingly.

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Answer:

so the  awnsers would be 1 3 4

Step-by-step explanation:

The geometric value sequence are given by

a) -2.7 , 9 , -30 , -100 ...

b) -1 , 2.5 , -6.25 , 15.625 ...

c) 8 , 0.8 , 0.08 , 0.008 ...

A geometric progression is a sequence in which each term is derived by multiplying or dividing the preceding term by a fixed number called the common ratio.

The nth term of a GP is aₙ = arⁿ⁻¹

The general form of a GP is a, ar, ar2, ar3 and so on

Sum of first n terms of a GP is Sₙ = a(rⁿ-1) / ( r - 1 )

Given data ,

Let the geometric progression be represented as A

Now , the value of A is

a)

A = -2.7 , 9 , -30 , -100 ..

The common ratio of the GP is r = second term / first term

On simplifying , we get

r = 9 / -2.7

r = 10/3

So , the progression is geometric

b)

A = -1 , 2.5 , -6.25 , 15.625 ...

The common ratio of the GP is r = second term / first term

On simplifying , we get

r = 2.5 / -1

r = -2.5

So , the progression is geometric

c)

A = 8 , 0.8 , 0.08 , 0.008 ...

The common ratio of the GP is r = second term / first term

On simplifying , we get

r = 0.8 / 8

r = 1/10

So , the progression is geometric

Hence , the GP is solved

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