Determine the resultant internal loadings in the beam at cross sections through points D and E. Point E is just to the right of the 16-kN load.Shear ForceShear force is the total effective force or resultant force vertical to the shaft or beam. Normal force is perpendicular to the shear force. The magnitude of the shear force depends on the vertical load applied to the beam.

Answers

Answer 1

The resultant internal loadings in the beam at cross sections through point D and E are 15.12 kN upwards and 34.88 kN upwards respectively.

To calculate the internal loading at point D and E, first we need to calculate the support reaction at A and C, by taking the moment about reaction A.

R₁ + R₂ = 25×4 + 15 = 115 kN

R₂ × 7 = 15 × 5.5 + 100 × (4×2/3)

R₂ = 349.167/7 = 49.88

R₁ = 115 - 49.88 = 65.12 kN

Internal loading at D = 65.12 - 25×2 = 15.12 kN upwards

Internal loading at E = 49.88 - 15 = 34.88 kN upwards

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--The given question is incomplete, the complete question is:

"Determine the resultant internal loadings in the beam at cross sections through points D and E in the given figure. Point E is just to the right of the 15-kN load."--

Determine The Resultant Internal Loadings In The Beam At Cross Sections Through Points D And E. Point

Related Questions

a river flows with a uniform velocity v. a person in a motorboat travels 1.42 km upstream, at which time a log is seen floating by. the person continues to travel upstream for 75 min at the same speed and then returns downstream to the starting point, where the same log is seen again. find the flow velocity of the river. assume the speed of the boat with respect to the water is constant throughout the entire trip.

Answers

Let's assume the speed of the boat relative to the water is s.

The time taken for the boat to travel 1.42 km upstream is t1.

The time taken for the boat to travel 1.42 km downstream is t2.

The velocity of the river is v.

Since the speed of the boat relative to the water is constant, we have:

Upstream:

v + s = s + (1.42 km) / t1 = (1.42 km) / t1 km/hr

Downstream:

v - s = (1.42 km) / t2 km/hr

Since the boat takes 75 min for the round trip, we have:

t1 + t2 = 75 min = 1.25 hours

Rearranging the above equations, we have:

v = (1.42 km / t1 - 1.42 km / t2) / 2 km/hr

Substituting t1 + t2 = 1.25 hours, we have:

v = (1.42 km / (1.25 hours - t2) - 1.42 km / t2) / 2 km/hr

Since t2 = 1.25 hours - t1, we have:

v = (1.42 km / (1.25 hours - (1.25 hours - t1)) - 1.42 km / (1.25 hours - t1)) / 2 km/hr

v = (1.42 km / (1.25 hours) - 1.42 km / (2.5 hours - t1)) / 2 km/hr

Finally, solving for t1, we have:

t1 = (1.42 km / v) * 2 km/hr / (1 + (1.42 km / (1.25 hours * v))) hours

So, the flow velocity of the river is v.

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The energy given off as heat by 500 g of an alloy as it cools by 25°C raises the
temperature of 250 g of water from 20°C to 28°C. Calculate the specific heat
of the alloy (in J/kg K). Remember that the specific heat of water is 4180 J/kg-K.
Upload a copy of your calculations and your answer.

Answers

Answer:

Below

Explanation:

The heat the water gains is the heat lost by the metal ...

  Hw = .25 kg * (28- 20 C) * 4180 J/(kg K) = 8360 J

So the metal gains 8360 J and cools by 25 °C

500g = .5 kg

                        8360 /(.5kg* 25 C) = 668.8 J /(kg K)

Note: Remember that a degree C = one K)  

A lead ball is dropped in a lake from a diving board 6.31 m above the water. It hits the water with a certain velocity and then sinks to the bottom with the same constant velocity. It reaches the bottom 5.05 s after it is dropped. (a) How deep is the lake? (b) What is the magnitude of the average velocity of the ball for the entire fall? (c) Suppose the water is drained from the lake. The ball is now thrown from the diving board so that it again reaches the bottom in 5.05 s. What is the magnitude of the initial velocity of the ball?

Answers

Answer:

a) To find the depth of the lake, we can use the following equation:

distance = initial velocity x time + (1/2) x acceleration x time^2

As the ball sinks to the bottom with the same constant velocity, we can assume that the acceleration is due to gravity, which is 9.8 m/s^2 (going downward)

We know that the time it takes for the ball to hit the bottom is 5.05 seconds, so we can substitute these values into the equation:

distance = 0 x 5.05 s + (1/2) x 9.8 m/s^2 x (5.05 s)^2

distance = 12.6125 m

So the lake is 12.6125 m deep

b) To find the magnitude of the average velocity of the ball for the entire fall, we can use the equation:

average velocity = distance / time

We know that the distance is the depth of the lake, which is 12.6125 m, and the time is 5.05 s, so we can substitute these values into the equation:

average velocity = 12.6125 m / 5.05 s

average velocity = 2.49 m/s

c) To find the magnitude of the initial velocity of the ball when it is thrown, we can use the following equation:

initial velocity = final velocity^2 + 2 x acceleration x distance

As the ball reaches the bottom in the same time as when it was dropped, 5.05 s, we can assume that the final velocity is 0 m/s. We know that the acceleration is 9.8 m/s^2 (going downward), and the distance is the depth of the lake, which is 12.6125 m. So we can substitute these values into the equation:

initial velocity = 0^2 + 2 x 9.8 m/s^2 x 12.6125 m

initial velocity = 24.6 m/s

Note that the magnitude of initial velocity is 24.6 m/s, which is a scalar value, it doesn't have any direction.

Distance to Epicenter (km) using equation

Answers

The distance to the epicenter by using the equation D = ΔT 8.4 is 16.8 kilometers.

What is the epicenter?

In an earthquake, the epicenter can be defined as the location on the earth's surface that is aligned with the location in which the earthquake originated.

How to calculate the distance to the epicenter?

The equation that is commonly used to calculate the distance to the epicenter in an earthquake is D =ΔT 8.4. In this equation T represents the difference in time between the P and the S wave, while 8.4 represents a constant.

Based on this, let's calculate the distance:

D =ΔT 8.4

D = 2 x 8.4

D = 16.8 km

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The spring stiffness is
130 N/cm
. Find the stretch of the spring (in centimeters) and the tension in the cord (in N) AB for a 10-kg ball. Units have been provided.

Answers

The acceleration due to gravity is 9.8 m/s2, the tension in the cord is equal to 98 N.

What is acceleration?

Acceleration is the rate of change of velocity over time. It is a vector quantity, meaning it has both direction and magnitude. It is typically measured in meters per second squared (m/s2), and is the rate at which the speed or velocity of an object changes.

The stretch of the spring can be calculated using the equation F = kx, where F is the applied force,
k is the spring stiffness, and x is the stretch of the spring.
In this case, the applied force is the weight of the 10-kg ball, which is equal to 98 N.
Plugging this into the equation,
we have 98 = 130x,
which can be solved for x to get x = 0.75 cm.

The tension in the cord can be calculated using the equation F = ma,
where F is the force,
m is the mass,
and a is the acceleration.
Since the acceleration due to gravity is 9.8 m/s2, the tension in the cord is equal to 98 N.

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a system is composed of two blocks. the blocks, sliding on a horizontal frictionless surface, collide and stick together. which of the following statements are correct regarding the system? there are two correct answers.(4 points) this is an open system. this is a closed system. friction is an external force on this system. there is no net external force on this system.

Answers

A closed system is a system in which the total energy of the system is conserved.

Which of the following statements are correct regarding the system?This system is an example of a closed system. In this system, two blocks are sliding on a horizontal frictionless surface and collide and stick together.Since there is no friction present, the external forces on the system are zero, meaning that there is no net external force on this system.This means that the total energy of the system is conserved, as no energy is being added or taken away. This makes it a closed system.The system in question is a closed system, meaning that no energy or matter can enter or leave the system. This is because the two blocks are stuck together after the collision, and thus the system is completely isolated from its environment. Friction, however, is an external force on this system, since it acts on the blocks when they collide. At the same time, there is no net external force on this system. This is because the forces that are acting on the system are balanced out and thus there is no net force on the system as a whole.In conclusion, the system in question is a closed system, and friction is an external force acting on it. However, since the forces acting on the system are balanced out, there is no net external force on the system.

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The equation of motion of particle is s = 8t² + 3t - 10 ,s being in meters and t in seconds. Compute the initial velocity and also the velocity when the displacement is zero.

Answers

Answer:

the velocity when the displacement is zero is 17.95 m/s.

Explanation:

The initial velocity can be found by taking the first derivative of the position function (s) with respect to time (t). The velocity function v = ds/dt is given by:

v = 8 * 2t + 3

The initial velocity, v0, at t = 0, is:

v0 = 8 * 2 * 0 + 3 = 3 m/s

The velocity when the displacement is zero can be found by setting s = 0 in the position function and solving for t:

0 = 8t² + 3t - 10

Using the quadratic formula, we find that:

t = (-3 ± √(3² - 4 * 8 * -10)) / (2 * 8)

t = (-3 ± √(9 + 320)) / 16

t = (-3 ± √329) / 16

t = (-3 ± 18.12) / 16

t = (15.12 / 16) or (-21.12 / 16)

Since time cannot be negative, we take the positive value:

t = (15.12 / 16) = 0.9475 s

At t = 0.9475 s, the velocity can be found using the velocity function:

v = 8 * 2 * 0.9475 + 3 = 17.95 m/s

So, the velocity when the displacement is zero is 17.95 m/s.

Two orareind me with a mass of 4.00 kg and other with a mass of 6.00 kg, sit on a
frictionless surface. A worker pulls horizontally on the 6.00 kg crate with a force that gives the crate
an acceleration of 2.5 ms.
a. What is the acceleration of the 4.00 kg crate? (1 mark)
b. Draw a free-body diagram for the 4.00 kg crate and use it together with Newton's second
law to find the tension T in the rope that connects the two crates. (2 marks)
C. Calculate the magnitude and direction of the force the worker applies. (2 marks)
Foma
4.00 kg
T
6.00 kg

Answers

a.  The acceleration of the 4.00 kg crate is 3.75 m/s^2.

b.  A free-body diagram for the 4.00 kg crate is shown below:

4.00 kg

T

c. The direction of the force is to the right, since the crate is moving to the right. The magnitude of the force is 15 N.

What is acceleration?

Acceleration can be described as  the rate of change of the velocity of an object with respect to time.

We use  Newton's second law of motion, which states that the net force on an object is equal to its mass times its acceleration

(F_ = m * a).

The total force on each crate is equal to the force applied on it. If the force applied on the 6.00 kg crate produces an acceleration of 2.5 m/s^2, the  total force on the 6.00 kg crate is 6.00 kg * 2.5 m/s^2 = 15 N.

Therefore, the total  force on the 4.00 kg crate is 4.00 kg * a = 15 N,

a = 15 N / 4.00 kg

a = 3.75 m/s^2.

The tension T in the rope that connects the two crates can be found using Newton's second law of motion.

b.  (F = m * a), so we can put out the  the equation as :

T - 4.00 kg * 3.75 m/s^2 = 0

T = 4.00 kg * 3.75 m/s^2 = 15 N

c.

F - 6.00 kg * 2.5 m/s^2 = 0

F = 6.00 kg * 2.5 m/s^2 = 15 N

The direction of the force is to the right, since the crate is moving to the right. The magnitude of the force is 15 N.

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How much work is done in lifting a 60.0 kg crate a vertical distance of 10.0 m at a
constant velocity?

Answers

Formula for work:

[tex]w=Fd[/tex]

work(measured in joules) = force(measured in newtons) * distance(measured in meters)

Formula for force:

[tex]F=ma[/tex]

force(measured in newtons) = mass(measured in kilograms) * acceleration(measured in m/s^2)

__________________________________________________________

Given:

[tex]m=60kg[/tex]

[tex]d=10m[/tex]

[tex]a=9.8m/s^2[/tex]

[tex]w=?[/tex]

__________________________________________________________

Finding force:

[tex]F=ma[/tex]

[tex]F=60\times9.8[/tex]

[tex]F=588N[/tex]

__________________________________________________________

Finding work:

[tex]w=Fd[/tex]

[tex]w=588\times10[/tex]

__________________________________________________________

Answer:

[tex]\fbox{w = 5880 Joules}[/tex]

recall that means: for all there is a such that for all satisfying we have that . what if the limit does not equal ? think about what the means in language. consider the following phrases: 1. 2. 3. 4. 5. but 6. such that for all 7. there is some 8. there is some such that order these statements so that they form a rigorous assertion that and enter their reference numbers in the appropriate sequence in these boxes:

Answers

The correct sequence is 5, 1, 3, 8, 4, 6, 7, 2. The statement that is being discussed is:

"For all > 0 there exists a > 0 such that for all satisfying we have that ."

To explain the statement further, it means that for any given real number > 0, there exists a real number > 0 such that for all real numbers satisfying , we have that . In other words, if is sufficiently close to (i.e. if is less than ), then must also be close to (i.e. must be less than ).

This idea is essential to understanding limits. The statement can be written more formally as:

[tex]$$\lim_{x \to c} f(x) = L \iff \forall \epsilon > 0, \exists \delta > 0 \text{ such that } \forall x \in \mathbb{R}, 0 < |x - c| < \delta \Rightarrow |f(x) - L| < \epsilon$$[/tex]

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a pendulum on planet x, where the value of gg is unknown, oscillates with a period of 2 ss.part apart completewhat is the period of this pendulum if its mass is doubled? note that you do not know the value of mm, ll, or gg, so do not assume any specific values. the required analysis involves thinking about ratios.express your answer with the appropriate units.tt

Answers

The time period of simple pendulum in which g is constant l is length of pendulum is T=2pirootl/g which oscillates with a period of 2 ss.

a- for a simple pendulum force constant or spring factor k is proportional to mass m therefore m cancels out in denominator as well as in numerator.

b-in case of a simple pendulum the restoring force acting on the bob of the pendulum is given as:-

F=-mgsing theta

m=mass of bob

g= acceleration due to gravity

theta=angle of displacement

for small theta sintheta =theta

hence time period T=2pirootL/g.

A simple pendulum is a point mass suspended by a weightless and inextensible string fixed rigidly to support, the supported string and mass is called pendulumn.

T = 2π√(l/g)

l is the length of the pendulum.

g is the acceleration due to gravity.

Examples of simple pendulums are found in clocks, swing sets, and even the natural mechanics of swinging legs all are on the basis of simple pendulum. Tetherballs are examples of spherical pendulums.

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HURRYYYYYY 20 pointsssss
Which of the following statements is true?
Group of answer choices

A correlation of -.50 is weaker than a correlation of .50.

A correlation of 1.33 is stronger than a correlation of .33.

A correlation of .56 is better than a correlation of .55.

A correlation of .33 is just as strong as a correlation of -.33.

Answers

The following statement which is true is :  A correlation of .33 is just as strong as a correlation of -.33.

What is meant by correlation?

The tendency of two or more systems that independently exhibit simple behavior to show complex and novel behavior together because of their interaction is called correlation.

Correlation is a statistical measure that expresses extent to which two variables are linearly related implying that they change together at a constant rate. It is common tool for describing simple relationships without making statement about cause and effect.

Correlation between variables does not mean that the change in one variable is the cause of the change in the values of other variable.

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A ball is thrown upwards and returns to the same position. Compared with its original speed after release, its speed when it returns is about _____. Free Fall: If the air resistance is ignored, then the acceleration of an object moving upward or falling towards the ground is numerically equal to the acceleration due to gravity. Energy Conservation: Energy cannot be created or destroyed, but it can flow from one form to another. This is a powerful and wide-ranging principle that can help us solve many problems. In situations where friction and thermal energy are insignificant, we can apply the conservation of mechanical energy. Mechanical energy includes kinetic energy and potential energy. A common application of this is projectile motion, in which the sum of kinetic energy and gravitational potential energy is constant. We can state this as follows: K E 1 + P E 1 = K E 2 + P E 2 Here, K E represents kinetic energy (J), and P E represents the potential energy (J). Also, the subscript 1 represents some particular point in the path of the projectile, and the subscript 2 represents another point. For most situations, the kinetic energy basically only depends on the speed of the projectile: K E = 1 2 m v 2 . The gravitational potential energy depends on the height: P E = m g h . Here, m is the mass (kg), v is the speed (m/s), g is the acceleration of gravity (9.8 m/ s 2 ), and h is the height (m).

Answers

A ball is thrown upwards and returns to the same position. Compared with its original speed after relase, its speed when it returns is about the same.

To solve this case, we will use energy conservation and free fall concepts.

Energy conservation defines that the energy in a system will remains the same as long as no other external force working in the system. Energy in a system will not be created or destroyed, but only change its form from one to another.

We will use the energy conservation concepts in this case under the kinetic and potential energies approach.

When the ball is thrown upwards, the ball has its kinetic energy and zero potential energy. As the ball goes higher, it will reach its highest peak once all of its kinetic energy has change into potential energy. The potential energy then will change into kinetic energy directly as the ball falls into its initial position. We can formulazid these moments as:

E1 = E2 = E3

where:

E1 = total energy when the ball is thrown upwards

E2 = total energy when the ball just stop at its highest peak

E3 = total energy when the ball starts to drop into its initial position

E1 = E2 = E3

Ek1 + Ep1 = Ek2 + Ep2 = Ek3 + Ep3

1/2 mv1² + mgh1 = 1/2mv2² + mgh2 = 1/2mv3² + mgh3

1/2mv1² + mg(0) = 1/2m(0)² +mgh = 1/2mv3² + mg(0)

1/2v1² = gh = 1/2v3²

v1² = v3² =2gh

v1 = v3 = √2gh

The ball will falls with the same speed as the speed when it was thrown upwards.

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how hard is it easy to be a killer

Answers

Answer:very hard

Explanation:

i feel like its very easy hard to be a killer

9. If two objects begin at rest, what is the total momentum of the system before they push off from one
another? What is the momentum of the system after they push off from one another?
10. If two objects are moving but the total momentum of the system is zero, what do you know about
the momentum of the two objects?
11. Two people stand facing each other at a roller skating rink then push off each other.
a. What is the momentum of the system before they push off each other?
b. What must be the momentum of the system after they push off each other?
c. If the girl skater has a mass of 30 kg and moves backward at 5 m/s, what is the velocity of the boy
skater if his mass is 50 kg?
d. If the force applied between the two skaters occurs over 2.5 seconds, what is the force exerted on
each of the skaters?

Answers

Answer:

10. If two objects are moving but the total momentum of the system is zero, the momentum of the two objects are equal in magnitude but opposite in direction.

11.

a. The momentum of the system before they push off each other is zero as they both start at rest.

b. The total momentum of the system after they push off each other must be zero, as the law of conservation of momentum states that the total momentum of a closed system remains constant.

c. If the girl skater has a mass of 30 kg and moves backward at 5 m/s, the velocity of the boy skater would be in the opposite direction at 5 m/s. This can be found using the equation p = mv, where p is momentum, m is mass, and v is velocity. Since the total momentum of the system is zero, the momentum of the girl skater (30 kg * -5 m/s) must be equal in magnitude but opposite in direction to the momentum of the boy skater (50 kg * v). So, v = (30 kg * -5 m/s) / 50 kg = -5/50 m/s = -0.1 m/s.

d. The force exerted on each skater can be found using the equation F = Δp/Δt, where F is force, Δp is the change in momentum, and Δt is the time over which the force is exerted. Using the known values, F = Δp/Δt = (0 - 0) / 2.5 s = 0 N. This means that the force exerted on each skater is zero.

Two stones are separated by a vertical distance y (in meters) from each other. One stone is thrown down with an initial velocity v01 = -23 m/s and the other is thrown up from the ground with an initial v02 = 5 m/s at the same time the other is thrown.
How far, in meters, must they be separated so they hit the ground at the same time?

Answers

The formula y = - 1 2 g t 2 y = - frac 1 2 g t 2 y=-21gt2 describes the vertical distance from the ground, where g is the acceleration of gravity and h is a height.

When you throw two stones of an equal sizes do they hit the ground at the same time why?It took both stones two hours and twenty minutes to fall to the ground. As a result, since height is constant for both particles, time is solely dependent on height. Both will fall to the ground simultaneously since the forces and height are equal.Things with various masses will nevertheless strike the ground at the same time if they are dropped from the same height because Earth provides them the exact same acceleration.The formula t=g2h provides the free fall time. Both stones hit the ground at the same time because t is independent of mass and h and g are equal.

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What happens after we die on earth?

Answers

Your heart stops beating, your breathing stops, and your brain stops working. According to research, brain activity may continue for several minutes after a person is declared dead.

What do people see when they die?

Visual or auditory hallucinations are common during the dying process. The reappearance of deceased family members or loved ones is common. These visions are thought to be normal.

The dying may shift their focus to "another world," where they may converse with people or see things that others do not.

Thus, brain activity is not synonymous with consciousness or awareness. It does not imply that the individual is aware that they have died.

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Kepler's second law states that as a planet orbits the Sun, itsweeps out equal areas in equal times. Which of the followingstatements describe a characteristic of the solar system that isexplained by Kepler's second law?
Check all that apply
a) Venus orbits the Sun faster than Earth orbits the Sun.
b) Inner planets orbit the Sun at higher speed than outerplanets
c) The Sun is located slightly off-center from the middle ofeach planet's orbit.
d) All the planets orbit the Sun in nearly the same plane
e) Earth is slightly closer to the Sun on one side of itsorbit than on the other side
f) Pluto moves faster when it is closer to the Sun thanwhen it is farther from the Sun

Answers

Kepler's second law states that as a planet orbits the Sun, it sweeps out equal areas in equal times. the options are b) Inner planets orbit the Sun at higher speed than outer planets, d) All the planets orbit the Sun in nearly the same plane, f) Pluto moves faster when it is closer to the Sun than when it is farther from the Sun.

Kepler's second law states that as a planet orbits the Sun, it sweeps out equal areas in equal times. The following statements describe characteristics of the solar system that are explained by Kepler's second law:

The correct options are option b, d and f.

These statements are consistent with the idea that a planet sweeps out equal areas in equal times as it orbits the Sun, because a planet moving faster would be able to sweep out a larger area in a given amount of time. Kepler law is made to find the distance, motion, trajectory of the celestial bodies that are moving in he solar system and we can use it to prove many theories and we are making the proportionality in the many ways.

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o a swimmer under water, objects look blurry. When goggles are worn, however, the images are sharp. Why is this so? Contact with water makes the focal length of the eye change. The goggles have a focal length that corrects the vision of the swimmer. The swimmer's eyes are adapted to refraction that takes place as light passes from the air into the cornea. The goggles maintain this. The blurriness is caused by the water irritating the swimmers eyes. The goggles protect the swimmers eyes.

Answers

The images sharpen when the goggles are worn because the focal length of goggles maintains the refraction of light into cornea and corrects the vision of the swimmer.

What is Refraction?

Refraction is the redirection of a wave as it travels through one medium and into another in physics. The wave's alteration in speed or a change in the medium might both result in the redirection. Although light refraction is the most frequently seen phenomena, refraction can also occur with other waves, including sound and water waves.

The angle between the original direction of wave propagation and the direction of speed change affects how much a wave is refracted. Light slows down and somewhat changes direction as it moves from the air into the water. Refraction describes this shift in direction.

Why are Goggles Used While Swimming?

The focal length of the eye alters upon contact with water. The goggles have a focal length that enhances the swimmer's vision. The eyes of a swimmer are shaped to refract light as it enters the cornea from the air. This is upheld by the goggles. The water's irritation of the swimmers' eyes is what causes the blurriness. Swimmers' eyes are protected with goggles.

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A uniform rod of mass M is in the shape of a semicircle of radius R (Fig. P14.45). Calculate the force on a point mass m placed at the center of the semicircle.

Answers

To calculate the force on the point mass m placed at the center of the semicircle, we need to consider the gravitational force acting on the mass m due to the uniform rod.

The gravitational force acting on the point mass m can be calculated using the equation:

F = G * (m * M) / R^2

where G is the gravitational constant, m is the mass of the point mass, M is the mass of the uniform rod, and R is the radius of the semicircle.

The uniform rod can be considered as a point mass located at the center of the semicircle, so the force on the point mass m can be simplified as:

F = G * (m * M) / R^2 = G * m * M / R^2

In conclusion, the force on the point mass m placed at the center of the semicircle is equal to the gravitational force between the point mass and the uniform rod, which is given by the equation F = G * m * M / R^2.

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a piece of copper block of mass 24grams and 230 degrees Celsius is placed in a copper calorimeter of mass 60 gram containing 54 grams of water at 31° Celsius assuming heat losses are negligible calculate the final steady temperature of the mixture specific heat capacity of water is 4200 joule per kilogram Kelvin specific heat capacity of copper is 400 joules per kilogram Kelvin. I need this ASAP.I'll mark brainliest

Answers

Answer:

31.37 degree Celcius

Explanation:

To calculate the final steady temperature of the mixture, we need to use the conservation of energy principle, which states that the total energy before and after the process must be the same. The heat lost by the copper block will be equal to the heat gained by the water and the copper calorimeter.

We can start by finding the heat lost by the copper block. We know that the mass of the copper block is 24 grams, and the specific heat capacity of copper is 400 J/kg·K.

The change in temperature of the copper block is 230°C - 31°C = 199°C. Therefore, the heat lost by the copper block can be calculated as:

Q_copper = mass x specific heat capacity x change in temperature

Q_copper = (24 g) x (400 J/kg·K) x (199°C)

Q_copper = 150336 J

Next, we'll find the heat gained by the water and the calorimeter. We know that the mass of the water is 54 grams, and the specific heat capacity of water is 4200 J/kg·K.

The change in temperature of the water is T_final - 31°C = T_final - 31. Therefore, the heat gained by the water can be calculated as:

Q_water = mass x specific heat capacity x change in temperature

Q_water = (54 g) x (4200 J/kg·K) x (T_final - 31)

We also know that the mass of the calorimeter is 60 grams, and the specific heat capacity of copper is 400 J/kg·K.

The change in temperature of the calorimeter is T_final - 31°C = T_final - 31.

Therefore, the heat gained by the calorimeter can be calculated as:

Q_calorimeter = mass x specific heat capacity x change in temperature

Q_calorimeter = (60 g) x (400 J/kg·K) x (T_final - 31)

Now we can use the conservation of energy principle to find the final steady temperature. Since the heat lost by the copper block is equal to the heat gained by the water and the calorimeter, we can set up the following equation:

Q_copper = Q_water + Q_calorimeter

150336 J = (54 g) x (4200 J/kg·K) x (T_final - 31) + (60 g) x (400 J/kg·K) x (T_final - 31)

Solving for T_final, we get

T_final = (150336 J + 31*(544200 + 60400))/(544200+60400)

= (150336+31*266400)/266400

= (150336+828240)/266400

= 98576/266400

= 0.37°C

Therefore, the final steady temperature of the mixture is T_final = 31°C + 0.37°C

= 31.37°C

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A tennis player tosses a tennis ball straight up and then catches it after 1.57 s at the same height as the point of release.

Answers

PART A:

-9.8 m/s^2 (S)

PART B:

0 meters (N)

PART C:

≈ 7.7 (ROUNDED)
Accurate: 7.69300

PART D:

4.9 m (Δy)

Transcribed Text:
A tennis player tosses a tennis ball straight up and then catches it after 1.57 seconds at the same height as the point of release.

Required:

Acceleration of the ball while in flightVelocity of the ball at maximum heightInitial velocityMaximum height reached

Use the following kinematic equations:


[tex]v=v_o+at[/tex]

Final velocity = Initial Velocity + Acceleration × Time

Δ[tex]x=v_ot+\frac{1}{2}at^2[/tex]

Change in position (displacement) = Initial velocity × time + (0.5) (acceleration × final time)²

[tex]v^2=v_o2+2a[/tex]Δ[tex]x[/tex]

Final velocity (squared) = Initial velocity (two times) + (two times) acceleration * change in position

*A illustration shall be provided for better understanding*

Part A:

Once the tennis player releases the ball, the only force acting on that ball is the gravitational force which exerts an acceleration of -9.8 m/s^2.

Part B:

At that maximum height (as seen in the attached picture) would have a velocity of 0 for just a split moment making this the answer.

PART C: *Be aware that the PART A and B are just conceptual type questions and now we have actual calculations to figure out*.

Reviewing what we know,

Acceleration = -9.8 m/s^2

Time = 2.00 seconds

Now we have to find the initial velocity.

Reviewing the picture and the final velocity, it should turn out this way:

[tex]Vi=V_i,V=-V_o[/tex]

Looking at the kinematic equations we would use:
[tex]V_f=V_i+at[/tex]

Current equation:

[tex]-V_o=V_o+(-9.8)(1.57)[/tex]

* MULTIPLY -9.8 and 1.57!!!

Now we must subtract the V(naught) from both sides.

The left and right side would become:

[tex]-2v_o=-15.38600[/tex]

Divide -2 from both sides.

Initial velocity = 7.69300

Rounded

≈ 7.7 m/s

This would make the initial velocity equal to 7.7 m/s

PART D:
In order to solve for maximum height, we must use some values we would need to find this answer.

Initial velocity = 7.69300 m/s

Acceleration = -9.8m/s^2

Final velocity (or velocity at max height) = 0 m/s

Δy = ...

The kinematic equation we would be using is:

[tex]v^2=v_o2+2a[/tex]Δ[tex]x[/tex]

Because the situation is in the vertical dimension, the 'delta x' will be changed to:

[tex]v^2=v_o2+2a[/tex]Δ[tex]y[/tex]

Subtract the initial velocity squared from both sides of the equation.

This would give us:
[tex]v^2-v_0^2=2a[/tex]Δ[tex]y[/tex]

Divide both sides by 2a.

By finding this we can find the vertical displacement.

[tex]\frac{v^2-u^2}{2a}[/tex]=Δ[tex]y[/tex]

Let plug in the known values

[tex]\frac{(0)^2-(9.8)^2}{2(-9.8^2)} = 4.9m[/tex]

Done

provide an explanation on why motor vehicles use what is called a multigrade viscosity oil and explain what is meant by an oil viscosity rating such as 5W30.

Answers

Motor vehicles use multigrade viscosity oil because it can perform well in a wide range of temperatures. In cold temperatures, a low viscosity oil is needed for the engine to start easily and for the oil to circulate quickly to lubricate moving parts. In hot temperatures, a higher viscosity oil is needed to prevent the oil from thinning out and losing its lubricating properties.

A viscosity rating, such as 5W30, is a way to measure the oil's thickness or resistance to flow. The first number, 5 in this case, represents the oil's viscosity rating at low temperatures (usually measured at -25°C or -13°F). The "W" stands for "Winter" and it indicates that the oil has been tested at low temperatures. The second number, 30, represents the oil's viscosity rating at high temperatures (usually measured at 100°C or 212°F). The higher the second number, the thicker the oil will be at high temperatures. Therefore, 5W30 oil has a low viscosity at low temperatures, making it easier to start the engine, but it has a higher viscosity at high temperatures, providing better protection for the engine.

A straight line drawn anywhere on a Mercator projection is a line of true compass direction, called a _____ line.
Rhumb

Answers

A straight line drawn anywhere on a Mercator projection is a line of true compass direction, called a loxodrome line.

A loxodrome is a line of true compass direction on a Mercator projection map. Here are some key points to keep in mind:

Mercator projection: This type of map projection was created in 1569 by Gerardus Mercator, and it is widely used for nautical and aeronautical charts. It is also a popular choice for world maps due to its ability to show areas near the poles in their correct proportions.

True compass direction: A loxodrome represents a line of constant compass bearing, meaning that it maintains a constant angle relative to true north. This is in contrast to a great circle, which represents the shortest path between two points on the surface of a sphere.

Straight line appearance: On a Mercator projection map, a loxodrome appears as a straight line that intersects all meridians (lines of longitude) at the same angle. This makes it a useful tool for navigators, as they can simply steer a constant compass course and follow the loxodrome line to their destination.

Limitations: While a loxodrome may appear as a straight line on a Mercator projection map, it is actually a curve in reality. This is because the Mercator projection distorts the shape of the earth's surface, especially near the poles. In addition, a loxodrome is not the shortest distance between two points, so it may not be the best route to follow in all cases.

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Calculate the kinetic energy of an object of mass 10kg when it is moving with a velocity 2ms-1

Answers

The kinetic energy of an object of mass 10kg when it is moving with a velocity 2ms⁻¹ is  20 joule.

What is kinetic energy?

The energy an object has as a result of motion is known as kinetic energy in physics. It is described as the effort required to move a mass-determined body from rest to the indicated velocity.

The body holds onto the kinetic energy it acquired during its acceleration until its speed changes.

Mass of the object: M = 10 kg.

Velocity of the object: v = 2 m/s.

Hence, the kinetic energy of the object = 1/2×Mv²

= 1/2 × 10 × 2² joule

= 20 joule.

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A rock is dropped from a high tower and falls freely under the influence of gravity.
Which one of the following statements concerning the rock as it falls is true? Neglect
the effects of air resistance.
A) The rock will gain an equal amount of momentum during each second.
B) The rock will gain an equal amount of kinetic energy during each second.
C) The rock will gain an equal amount of speed for each meter through which it falls.
D) The rock will gain an equal amount of momentum for each meter through which it
falls.
E) The amount of momentum the rock gains will be proportional to the amount of
potential energy that it loses.

Answers

Neglecting the effects of air resistance, the statement that is true about a freely falling rock is the one that says "the rock will gain an equal amount of momentum during each second (of its fall)." Therefore, the correct answer is option A.

According to the question, a rock is dropped from a tower. It falls freely, meaning that there is no initial force that was applied to it and that the falling is purely under the influence of gravity. In cases like this, the primary force that is working on the rock, besides gravity, is the friction that it experiences with the air (air resistance).

Falling objects get faster the longer they are in the air because of the momentum it gains. Air resistance slightly slows the speed, but since we're instructed to ignore the air resistance, only the acceleration of gravity would affect the object.

The formula you can use to calculate a falling object is:

  v = g * t

  v = 2 * g * h

  h = 0.5 * g * t²

h = height traveled.v = final velocity.g = gravity acceleration.t = time taken.

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A person pushes a 15.5-kg shopping cart at a constant velocity for a distance of 28.5 mon a flat horizontal surface. She pushes in a direction 32.2 below the horizontal. A 30.4-N frictional force opposes the motion of the cart. (a) What is the magnitude of the force that the shopper exerts? Determine the work done by (b) the pushing force, (c) the frictional force, and (d) the gravitational force.

Answers

a) The magnitude of the force that the shopper exerts is equal to the force of friction plus the force needed to overcome gravity. This can be calculated using the following formula:

F = ma = (15.5 kg)(9.8 m/s^2)sin(32.2) + 30.4 N

b) The work done by the pushing force is equal to the force multiplied by the distance moved in the direction of the force. This can be calculated using the following formula:

W = Fdcos(theta) = (F)(28.5 m)cos(32.2)

c) The work done by the frictional force is equal to the force of friction multiplied by the distance moved in the direction of the force. This can be calculated using the following formula:

W = Fdcos(theta) = (30.4 N)(28.5 m)cos(32.2)

d) The work done by the gravitational force is equal to the force of gravity multiplied by the distance moved in the direction of the force. This can be calculated using the following formula:

W = Fdcos(theta) = (15.5 kg)(9.8 m/s^2)sin(32.2)(28.5 m)cos(32.2)

Note that work done by force is negative when force opposes the motion.

2
Select all the correct answers.
Which two statements are true about a system?
A system is a group of objects analyzed as one unit.
Energy that moves across system boundaries is conserved.
There's only one way to define the boundaries of a system.
All systems are made by humans.

Answers

Answer: a AND B

Explanation:1, IS TRUE AND 2 AIS TRUE

The things that are true about a system are :

A system is a group of objects analyzed as one unit

Energy that moves across the system boundaries is conserved.

What is a System ?

System is nothing more than a group of identifiable items (or smaller systems), as it is defined in physics or chemistry. The word "system" often refers to a collection that makes it easier to think about an issue. Everything else outside of what the system defines is considered the surrounds.

The collection of elements and energy under study is referred to as a system. For instance, everything within a jar in which reactions are taking place is the system, while everything outside the jar is the environment. Everything outside of the system, or the rest of the cosmos, is considered the surrounds.

The things that are true about a system are :

A system is a group of objects analyzed as one unit

Energy that moves across the system boundaries is conserved.

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Assume that a typical driver has 1 sec reaction time (i.e., it takes 1 second before a typical driver starts reacting to changes in traffic light, e.g., after the light turns yellow, the driver starts slowing down after 1 sec). assume that 0.3g deceleration is a comfortable rate of slowing down (g is the gravitational acceleration)

Answers

between the moment the driver sights an obstacle and the moment he applies the brakes

What is a driver’s response time?

A driver’s reaction time is the amount of time it takes between seeing an obstruction and applying the brakes. During this period, the automobile maintains a steady speed while he drives closer to the obstruction. The reaction time is the amount of time it takes to respond to a situation by shifting your foot from the accelerator to the brake pedal. A typical reaction time is ¾ of a second. The reaction distance is the distance traveled by a vehicle within this period.

Method that is more exact.D = (s * r) / 3.6 d = response distance in meters (to be calculated). S denotes the speed in kilometers per hour. R denotes the response time in seconds. 3.6 = fixed conversion figure

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A red cart is moving rightward with a momentum of 60 kg*cm/s when it collides
with a blue cart that is also moving rightward with a momentum of 30 kg*cm/s.
The collision causes the red cart to slow down and the blue cart to increase its
momentum to 50 kg*cm/s.
Enter the momentum values of each individual cart and of the system of two carts
before and after the collision. Also indicate the change in momentum of the carts
and of the system.

Answers

The momentum of the red cart before and after the collision is 60 kgm/s and 40 kgm/s respectively.

The momentum of the blue cart before and after the collision is 30 kgm/s and 50 kgm/s respectively.

What is the final momentum of the carts after the collision?

The final momentum of the carts after the collision is determined by applying the principle of conservation of linear momentum.

Sum of initial momentum = sum of final momentum

60 kgm/s  +  30 kg m/s  = 50 kgm/s  + Pr

where;

Pr is the final momentum of the red cart

90 kgm/s - 50 kgm/s = Pr

40 kgm/s = Pr

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