Determine the sample type.
A student is researching if people like to study at the city library. The student stands by the door of the city library and surveys people walking in.

The graph of y=-3x-1 is given in the attachment.

Graph is a mathematical representation of a network and it describes the relationship between lines and points.

The given equation is  y=-3x-1

The slope intercept form of a line is y=mx+b, where m is slope and b is the y intercept.

In the given equation slope is -3.

Let us find few values of x and y.

x    0    1    2     3    4

y    -1   -4   -7    -10  -13

Hence, the graph of y=-3x-1 is given in the attachment.

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Answer:

Below

Step-by-step explanation:

1cm on the map is  500 m  

1 cm on the map is 50000 cm

1:50000

[tex](4.8 \times 10^7) + 6,500,500[/tex]

[tex]48,000,000+6,500,500[/tex]

[tex]=\boxed{54,500,500}[/tex]

Answer:

Below

Step-by-step explanation:

The zeroes are given as x = 0   and x = - 4

then the factorization would be   ( x - 0 )( x - - 4)   =   x (x+4) = f(x)

El nuevo sueldo, luego de un incremento del 25%, será $29,678.50

Recordar que si tenemos un número A, y lo incrementamos en un porcentaje X, entonces el nuevo número será:

A' = A*(1 + X/100%)

En este caso el valor inicial is $23,750, y lo incrementamos en un 25%, entonces el nuevo sueldo esta dado por la expresion de abajo.

A' = $23,750*(1 + 25%/100%)

A' = $23,750*(1.25) = $29,678.50

El núevo sueldo del empleado, luego del aumento, será $29,678.50.

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I Hope you got the answer right?

I'm guessing it's A or B

A, Because 125 Average Salary of each employee
B, Because 600 is how much he spends everyday.

I'm going to say
B, $600 spent in a day/daily expenses

If I'm right your welcome.
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Answer:

A and B

Answer:

Without additional information, it is impossible to answer this question as there is no information about the "she" or "record time" referred to in the question.

Suppose the real number x is greater than 0. Then for any natural number n, the reciprocal of n, 1/n, is less than x if and only if n > 1/x.

Since 1/x is a positive real number, it is always less than a sufficiently large natural number, say N. Hence, 1/N < x.

Therefore, there exists a natural number for which the reciprocal is less than x.

The solution is based on the properties of real numbers and the notion that there is always a natural number greater than any positive real number.

For a given positive real number x, if we take a natural number n that is larger than 1/x, then the reciprocal of n, 1/n, will be less than x. This is because 1/n = n^(-1), which means the value of n^(-1) becomes smaller as n increases.

So, if we choose a sufficiently large natural number, its reciprocal will always be less than any positive real number x. This means that for any positive real number x, there is always a real number greater than 0 (1/n) for which the reciprocal of a natural number (n) is less than it (x).

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Answer: D

Step-by-step explanation:

since she must sell at least 40 mugs to meet her goal, y must be greater than or equal to 40

The statements that are FALSE about the Outliners are

(b) all outliers are influential points  ,   and

(d) outliers should usually be removed from a data  .

The statement "(b) all outliers are influential points"  is false because not all outliers are influential points, meaning that they do not have a significant effect on the results of a statistical analysis.

Whether or not an outlier is influential depends on the specific situation and the type of analysis being performed.

The statement "(d) outliers should usually be removed from a data " is false because removing all outliers from a data set is not always appropriate.

Outliers can provide important information and removing them can sometimes lead to the loss of valuable information. In some cases, outliers can be valid observations and should be kept in the data.

The given question is incomplete , the complete question is

Which of the following statements are false? (select all responses that apply) group of answer choices

(a) Outliers can not be leverage points

(b) all outliers are influential points

(c) all outliers are leverage points

(d) outliers should usually be removed from a data  .

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Answer: 176 miles

First, multiply the fraction 44/100 by 400. After cross simplifying, you should get 176. 44% is nothing but 44 out of 100, which is why we multiplied by 44/100

(1) The Linearity Property for sums states that the sum of two sums is equal to the sum of the individual terms. That is, if a and b are two sums, then a + b = Σ(a + b).

(2) The Telescoping Property for sums states that the sum of a sequence of terms can be expressed as the difference between two terms. That is, if a1, a2, …, an are terms of a sequence, then Σai = a1 - an.

(3) The Geometric Property for sums states that the sum of the first n terms of a geometric sequence is equal to the product of the first term and the sum of the common ratio raised to the nth power. That is, if a is the first term and r is the common ratio, then Σa_i = ar^(n-1).

(4) The Associativity Property for sums states that changing the order of terms in a sum does not affect the result. That is, if a is a sum, then a = Σa = Σ(Σa).

(5) Σk = ∑k = the sum of the first k terms of a sequence.

(6) Σk^-2 = ∑k^-2 = the sum of the inverse of the first k terms of a sequence.

(7) Σk^-3 = ∑k^-3 = the sum of the inverse of the cube of the first k terms of a sequence.

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Answer:

it is 16

Step-by-step explanation:

do 2x2x2x2 which will give you 16

Both the second and the induction hypothesis result from the first inequality.

You established its validity for n=5. Let's now assume that it is true for some number n5. Its validity for n+1 is to be demonstrated. But

2n+1=2×2n>2×n2>(n+1)2.

The first discrepancy is a result of induction, and we are aware of the second (n−1)2≥42>2, since n≥5

We can widen this disparity  (n−1)2>2 as follows:

n2−2n+1>n2−2n−1>2n2−2n−1>2n2>20n2n2+2n+1=(n+1)2,

which is the second inequality claimed in (♠)

2n+1=2n∗2>2n2=n2+n2>n2+2n+1=(n+1)2

2n+1>(n+1)2

Base case: n=5

(the problem states "n

greater than 4

choose the first matching integer, then.

25>52⟹32>25

Now, the Inductive Step:

2n+1>(n+1)2

now expanding

2∗2n>n2+2n+1

now we proved for the n+1 case

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The rectangle's length is equal to the circumference of the circle, while the the rectangle's width is equal to radius of the circle. So, the area of the circle is one half of the area of the rectangle.

Mathematically, the circumference of a circle can be calculated by using this mathematical expression:

C = 2πr or C = πD

Where:

Note: Radius = diameter/2 = 10/2 = 5 cm.

Mathematically, the area of a circle can be calculated by using this formula:

Area of a circle = πr²

Area of a circle = 25π cm².

Mathematically, the area of a rectangle can be calculated by using this formula:

Area of a rectangle = LW

Where:

Area of a rectangle = 10π × 5

Area of a rectangle = 50π cm².

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The length of each piece of yarn in mixed fraction form if total length is 18 feet, is 2(4/7) feet each for 7 pieces.

What is fraction?

In mathematics, a fraction is used to denote a portion or component of the whole. It stands for the proportionate pieces of the whole. Numerator and denominator are the two components that make up a fraction. The numerator is the number at the top, and the denominator is the number at the bottom.

The number of pieces of yarn Cody has = 3

Length of 1 piece of yarn = 6 feet

The number of pieces Cody needs to cut is = 7

The total length of yarn = Number of pieces of yarn × Length of 1 piece of yarn

Apply the arithmetic operation of multiplication.

Substitute the values into the equation -

The total length of yarn = 3 × 6

The total length of yarn = 18 feet

The length of each yarn piece = Total length of yarn / Number of pieces Cody needs to cut

Apply the arithmetic operation of division.

Substitute the values into the equation -

The length of each yarn piece = 18 / 7

The result is obtained in a fractional form -

The length of each yarn piece = 2(4/7)

Therefore, the length of each piece is 2(4/7) feet.

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The fractional form of the given percentage is 79/100.

Fraction is a comparison between two mathematical quantities or numbers in general.

The number which is being compared is called Numerator and the with whom it is compared is called Denominator.

In mathematical words, if a fraction is look like A/B where A and B are two numbers then A is called Numerator and B is called Denominator.

Percentage is the comparison of a quantity with respect to the number in  100.

Here given the percentage is 79 percent.

So 79 in 100

So the fractional form of the given percentage is = 79/100.

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The parametric equations are therefore: x is t, y is 1/3 * t, and z is t.

Response: x = t; y = 1/3; t; z = t

Given

At t = 0, r(t) equals f(t) * I + g(t) * j + h(t) * k.

(F (t0), G (t0), and H (t0))

r(t) = ln (t - 1) + (t + 2) * j + t * ln(tk) t * t * 0 = 1 Required Information is Missing

Calculate the parametric equations.

j + t * ln + (t - 1)/(t + 2) * ln + r(t) = ln(ti) (tk)

With regard to t, differentiate (t) = 1/t * I + 3/((t + 2) 2) * j + (ln(t) + 1) Let t=1 (i.e., e * t * t * 0 = 1)

r = 1/1 for prime (1). * I + 3/((1 + 2) ^ 2) * j + (ln(1) + 1) I + 3/(3 2) * k r prime (1) * j + (0 + 1) Prime (1) = I + 3/9 * K R * j + (1) (1) Prime (1) = I + 1/3 * j + * k r (1) I + 1/3 * j + k = * k r prime (1)

To find x, y, and z.

We utilise the following methods to find x, y, and z: r(t) = f(t) (t) * j + h (t) * k + I + g (t)

This suggests that:

prime r (1) * T = xi, yj, and zk

We therefore have:

I + 1/3 * j + k) = xi + yj + zk * t

it + 1/3 * jt + kt = xi + yj + zk.

In contrast:

xi = it

Divide by I x, y, and j to get 1/3 * jt.

Divide by j y = 3/9 * t zk = kt

Divided by k, z equals t.

The parametric equations are therefore: x = t, y = 1/3 * t, and z = t.

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The answers are: (a) 0.2224, (b) 0.7776, (c) 0.3545, (d) 0.5785

Probability is a branch of mathematics that deals with the likelihood or chance of an event happening. It is a number between 0 and 1 that indicates the likelihood of an event occurring, with 0 meaning that an event is impossible and 1 meaning that an event is certain to occur.

Probability is used to model and make predictions about real-world situations such as the outcome of a coin flip, the results of a survey, or the success of a marketing campaign. It is also used in many fields including statistics, finance, engineering, and sciences to make decisions based on uncertain data.

The problem requires the use of the normal approximation to the binomial distribution to estimate the probabilities. Let X be the number of flights that arrive on time out of 186 flights. Then X follows a binomial distribution with parameters n = 186 and p = 0.88.

We can use the normal approximation to estimate the probability of X taking different values. Let's denote the mean and standard deviation of X as mu and sigma respectively:

mu = np = 186 × 0.88 = 163.68

sigma = √(np(1-p)) = √(186 × 0.88 × 0.12) = 5.55

(a) P(159) = P(X = 159) can be estimated using the normal distribution using the Z-score:

Z = (159 - mu) / sigma = (159 - 163.68) / 5.55 = -0.77

P(159) ≈ P(Z < -0.77) ≈ 0.2224 (using a standard normal table)

(b) P(X ≥ 159) can be estimated using the cumulative distribution function:

Z = (159 - mu) / sigma = (159 - 163.68) / 5.55 = -0.77

P(X ≥ 159) = P(Z ≥ -0.77) = 1 - P(Z < -0.77) = 1 - 0.2224 = 0.7776

(c) P(X < 161) can be estimated using the cumulative distribution function:

Z = (161 - mu) / sigma = (161 - 163.68) / 5.55 = -0.36

P(X < 161) = P(Z < -0.36) = 0.3545 (using a standard normal table)

(d) P(161 ≤ X ≤ 174) can be estimated using the cumulative distribution function:

Z1 = (161 - mu) / sigma = (161 - 163.68) / 5.55 = -0.36

Z2 = (174 - mu) / sigma = (174 - 163.68) / 5.55 = 1.51

P(161 ≤ X ≤ 174) = P(Z1 < Z < Z2) = P(Z < 1.51) - P(Z < -0.36) = 0.9330 - 0.3545 = 0.5785

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At the end of the year there will be 356 rabbit.

Fibonacci sequence is a sequence, in which each number is the sum of the two preceding ones. The numbers in the Fibonacci sequence is the Fibonacci numbers.

Suppose a newly-born pair of rabbits, one male and one female, are put in a field.

Let [tex]f_{1},f_{2},f_{3} ,........f_{12}[/tex] represents the number of rabbit in the month 1, month2,....month12.

i.e., [tex]f_{1} =2, f_{2} =2[/tex]

At the end of its second month a female can produce another pair of

rabbits. i.e., [tex]f_{3}=4[/tex].

At the end of third month a parent female produce one pair and the daughter female produce one pair. i.e., [tex]f_{4} = 8.[/tex]

Similarly it goes on for 12 months.

Using fibonacii sequence, the general term is,

[tex]f_{n} =f_{n-1}+f_{n-2}[/tex]

for 5th month

[tex]f_{5} =f_{4} +f_{3} =8+4=12[/tex]

[tex]f_{6} =f_{5} +f_{4} =12+8=20[/tex]

[tex]f_{7} =f_{6} +f_{5} =20+12=32[/tex]

[tex]f_{8} =f_{7} +f_{6} =32+20=52[/tex]

[tex]f_{9} =f_{8} +f_{7} =52+32=84[/tex]

[tex]f_{10} =f_{9} +f_{8} =84+52=136[/tex]

[tex]f_{11} =f_{10} +f_{9} =136+84=220[/tex]

[tex]f_{12} =f_{11} +f_{10} =220+136=356.[/tex]

Hence, at the end of the year there will be 356 rabbit.

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In Old English (OE), endian-endode-endod (end/ended/ended in ModE) is an example of a base form of verb inflection.

The base form of the verb "end" in Old English is "endian." This form is used as the root or base form from which other forms of the verb are derived. In this case, "endian" is inflected to "endode" to indicate a past participle form, and to "endod" to indicate a simple past form.

This is an example of a base form of verb inflection, where the base form of a verb is altered to indicate tense, aspect, or voice. This type of inflection is common in older languages like Old English, but has since declined in use in modern English, where auxiliary verbs and word order are used to convey tense and aspect.

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Step-by-step explanation:

Here is a graph of the given piecewise function:

Graph of f(x)={(1/3 x-1" if " x≤0 -1/2 x+6" if " 0<x≤6

The graph of the given piecewise function is a straight line with two segments. The first segment, which lies between x = 0 and x = 6, has a slope of -1/2 and a y-intercept of 6. The second segment, which lies between x = 0 and x = -∞, has a slope of 1/3 and a y-intercept of -1.

Answer:y=4+2√(2)i  and y=4-2√(2)i

Step-by-step explanation:

y= 1/4(x-4)^2 +2

y=1/4(x²-8x+16)+2

y=(1/4)x²-2x+4+2

y=(1/4)x²-2x+6

using the Quadratic Equation

y=(-b±√(b²-4ac))/(2a)

Where a=1/4, b=-2, c=6

y=(-(-2)±√((-2)²-4(1/4)(6)))/(2(1/4))

y=(2±√(4-6))/(1/2)

y=4±2√(-2)

y=4±2√(2)i

y=4+2√(2)i  and y=4-2√(2)i

The sampling which represents the format of the morning show where a radio station asks its listeners to call and give their opinion is given by option B. Simple random sampling.

Therefore, the sampling which is used to decide the format of the show is option B . Simple random sampling.

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Answer:

below

Step-by-step explanation:

Just put 25 where 'n' is and calculate = 1441 rabbits

Answer:

Step-by-step explanation:

The area of square 1 is 13mm*26mm=338mm^2

The area of the second rectangle is 15mm*32mm=480mm^2

The are of both rectangles = 338mm^2+480mm^2=818mm^2

1.The probability of a driver having a conversation while driving only is 1/2

2. the probability that the student choose will have a dog but not a cat is 3/8

A probability is a number that reflects the chance or likelihood that a particular event will occur. Probabilities can be expressed as proportions that range from 0 to 1, and they can also be expressed as percentages ranging from 0% to 100%.

Probability = sample space / total outcome

1. Probability of looking at and making conversation = probability of looking at phone × making conversation

= 3/10 = 6/10 × x

x = 3/10 ÷ 6/10

x = 3/10 × 10/6

x = 3/6 = 1/2

therefore the probability of making conversation while driving is 1/2

2. The total number of students = (18-6)+ (16-6)+6 + 4 = 12+10+6+4 = 32

The number of students that have dog alone = 18-6 = 12

therefore the probability of choosing a student with a dog but not a cat = 12/32

= 3/8

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The number of peaks, symmetry, tendency to skew, and homogeneity of a distribution are all indicators of its shape.

Explain about the shape of the distribution?

There are two types of data item distributions: symmetric and asymmetric. The "normal distribution" and the "skewed distribution" are two prevalent illustrations of both symmetry and asymmetry. The distribution's two halves are mirror images of one another in a symmetrical distribution.

The number of peaks, the presence of symmetry, the propensity to skew, and the homogeneity of a distribution all help to explain its shape. (Graphs with skewed distributions show a greater number of points on one side than the other.) PEAKS: Graphs frequently show maximums or peaks in a certain area.

Either a normal distribution or a normal curve. When dealing with such a distribution, the mean should be reported.

Simple Frequency Distribution:

A simple frequency distribution is a table that lists each unique score in the data set and the number of times that score appears.

Score Frequency:

1.0 3

1.1 3

1.2 1

1.3 1

1.5 1

2.0 1

2.2 2

2.3 2

2.5 1

3.0 2

3.2 1

3.4 2

3.5 2

3.7 1

3.8 1

4.0 5

Grouped Frequency Distribution:

A grouped frequency distribution is a table that groups the scores into ranges (also known as bins) and lists the number of scores that fall into each range.

Score Range Frequency

1.0-1.9 9

2.0-2.9 7

3.0-3.9 10

4.0-4.9 4

Frequency Polygon:

A frequency polygon is a graph that is created by connecting the midpoints of the top of the bars in a histogram. The x-axis represents the scores and the y-axis represents the frequency.

Histogram:

A histogram is a graph that represents the frequency distribution of a set of continuous data. It is similar to a bar graph, but the bars are adjacent to each other and there are no spaces between the bars.

Shape of the distribution:

The shape of the distribution is right-skewed, which means that the majority of the data is concentrated on the left side of the distribution and there is a long tail of data points on the right side. This is indicated by the fact that the majority of the scores are between 1 and 3, while only a few scores are at 4.0 or above.

Bar Graph:

 __________

Male:  |__|__|__|__|

      10

      ____________________

Female: |__|__|__|__|__|__|

      20

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The distance between A and B is 575.21

In mathematics, trigonometric functions are real functions that relate an angle of a right-angled triangle to ratios of two side lengths. The six trigonometric functions are Sine, Cosine, Tangent, Secant, Cosecant, and Cotangent.

Given that, A boat is heading towards a lighthouse, whose beacon-light is 111 feet above the water. From point AA, the boat’s crew measures the angle of elevation to the beacon, 6°, before they draw closer. They measure the angle of elevation a second time from point BB at some later time to be 13°

tan 6° = 111/base

base = 1056

tan 13°= 111/base-AB

base - AB = 480.79

AB = 575.21

Hence, the distance between A and B is 575.21

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