We know that the hypotenuse is 6.5 units long, and x is the opposite leg to angle 50.
To find the value of x, use the sine trigonometric reason.
[tex]\begin{gathered} \sin 50=\frac{x}{6.5} \\ x=6.5\cdot\sin 50 \\ x\approx4.98 \end{gathered}[/tex]Therefore, the answer is A) 4.98.What is the LCM of 3, 16, 24
The LCM of 3, 16, and 24 = 48
Explanation:The LCM of 3, 16, and 24 is found below
The LCM = 3 x 2 x 2 x 2 x 2
The LCM = 48
Therefore, the LCM of 3, 16, and 24 = 48
Evaluate this exponential expression.8.(2+ 3)^2 – 4^2
We are given the following expression:
[tex]8.\mleft(2+3\mright)^2-4^2[/tex]To solve the expression we will add the numbers inside the parenthesis:
[tex]8.(2+3)^2-4^2=8(5^2)-4^2[/tex]Now we solve the squares:
[tex]8(5^2)-4^2=8(25)-16[/tex]Now we solve the product:
[tex]8(25)-16=200-16[/tex]Now we solve the operation:
[tex]200-16=184[/tex]Therefore, the expression is equivalent to 184.
Could anyone help me on this geometry question
Using the properties of parallel lines, The value of Y is 6.
The parallel lines are what?In a given three-dimensional space, any parallel planes are those that never cross. A line that crosses two or more other lines is said to be transversal. Two distinct angles are created when a line crosses two parallel lines.
According to the listed characteristics of parallel lines, these various forms of angles are used to demonstrate if two lines are parallel to one another.
Given,
Lines l and m must be parallel for the assertion to be true.
4x =(11x-8) - 90 (linear angle
11x - 4x = 98
7x = 98
x = 14
4x = 9y+2
4(14) = 9y + 2
56 - 2 = 9y
y = 6
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Triangle ABC has the vertices A(-3,4), B(0, 2), and C(-2, 1) in the coordinate plane. What will the coordinates of Triangle A'B'C' be after a reflection over the y axis? a. A'(3,-4), B'(0, -2), and C' (2, -1) b. A(3,4), B'(0,2), and C'(2, 1) C. A'(-4, 3), B'(-2, 0), and C'(-1,2) dd. A'(-4,3), B' (2,0), and C'(-1,2)
B
1) Since it is a reflection across the y-axis we can write the following rule:
Pre-image Image
(x, y) (-x,y)
2) Plugging the vertices of ABC we have
Pre-image Image
(x, y) (-x,y)
A(-3,4) A' (3,4)
B(0,2) B' (0, 2)
C(-2,1) C' (2,1)
3) Examining the options, the answer is B
View question below. Write your answer as a decimal(not a percentage)
Solution
We draw a venn diagram to illustrate the information
Without the loss of generality
From the question we have that
[tex]\begin{gathered} n(C\cup Ch)=78 \\ \\ 58-x+x+57-x=78 \\ \\ 115-x=78 \\ \\ x=115-78 \\ \\ x=37 \end{gathered}[/tex]Therefore, the probability that a chosen customer carries both cash and checks is
[tex]\begin{gathered} p=\frac{37}{100} \\ \\ p=0.37 \end{gathered}[/tex]The answer is
[tex]0.37[/tex]PLEASE HELP!! If m4=35 find m2
[tex]m < 4 = m < 2[/tex]
(The angles mentioned above are alternative angles since AB || CD)
[tex]m < 2 = m < 4 \\ m < 2 = 35[/tex]
OPTION D IS THE ANSWER.
Answer:
D is correct
Step-by-step explanation:
Angles 2 and 4 are alternate interior angles. Because angle 2 is 35 degrees, a line travels through two parallel lines to form that angle, likewise for angle 2, except for that it is alternate interior. Hope this helps.
A triangle has sides of lengths :x,12, and 34. What are the possible side lengths for x?
The length of the hypotenuse x is 36 units.
What is the hypotenuse?The longest side of a right-angled triangle, or the side opposite the right angle, is known as the hypotenuse in geometry. The Pythagorean theorem, which states that the square of the length of the hypotenuse equals the sum of the squares of the lengths of the other two sides, can be used to determine the length of the hypotenuse. The longest side of a right triangle in mathematics is called the hypotenuse. In other words, the hypotenuse is the side that faces the right angle.So, let us assume that side x is the hypotenuse of the triangle:
Formula for hypotenuse: c=√a²+b²Now, substitute values in the formula as follows:
x =√a²+b²x =√12²+34²x = √144 + 1,156x = √1,300x = 36.05551Rounding off: 36
Therefore, the length of the hypotenuse x is 36 units.
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Answer:
36 units
Step-by-step explanation:
Question 2: In comparison to the graph of y=x^2,in what direction will the graph of y=7/4x^2 be stretched
The plot that represents
[tex]y=\frac{7}{4}x^2[/tex]Is the one in Option A.
Now, in comparison to the graph of
[tex]y=x^2[/tex]The graph of
[tex]y=\frac{7}{4}x^2[/tex]Is horizontally compressed by a factor of 4/7
There are between 50 and 100 books on a shelf. Exactly 20% of them are textbooks. Exactly 1/7 of them are novels. How many books are on the shelf?
There are 70 books on the shelf
How to determine the number of books on the shelf?The given parameters are
Textbook = 20% = 1/5
Novel = 1/7
Let the number of books on the shelf be x
This means that
Textbook = 1/5 * x
Novel = 1/7 * x
The above means that:
The number of books is a multiple of 7 and 5
This is so because the number of books must be whole number
The multiples of 5 and 7 between 50 and 100 is 70
Hence, the number of books is 70
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Is there something special about 40 degrees? Will any 2 lines cut by a
transversal with congruent alternate interior angles, be parallel?
Vertical angles are always congruent - they always have the same angle measure. If one angle is 40 degrees, the vertical angle across from it will also be 40 degrees.
The angles that occupy the same relative location when a transversal cuts two or more lines are known as corresponding angles.
The figure's matching angle pairings are:
∠1 and ∠5 and ∠2 and ∠6 and ∠7 and ∠8
The matching angles are equivalent when the lines are parallel.
The pairs of angles on one side of the transversal and inside the two lines that make up a transversal that cuts two lines are known as the successive internal angles.
The further internal angles in the illustration above are:
∠3, ∠6, ∠4, and ∠5.
When a transversal cuts two parallel lines, supplemental pairs of subsequent interior angles result.
Pairs of angles on one line are generated when two parallel lines are sliced by a transversal, and these alternate internal angles are congruent.
The pairs of angles outside the two lines and on either side of a transversal that cuts two lines are referred to as the alternate external angles
∠1 and ∠7; ∠2 and ∠8;
When a transversal divides two parallel lines, the resulting alternate exterior angles are congruent.
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If the volume of a rectangular prism is 24yd cubed what is the missing measurement for Z.
The missing measurement for z would be 6 yds.
What is the volume of a rectangular prism?The volume of the rectangular prism is the product of the base area and the height.
Given the volume of a rectangular prism is 24 yds cubed
Length of prism = z
Width of prism = 1 yds
Height of prism = 4 yds
The volume of the rectangular prism would be :
volume of the rectangular prism = Base Area × Height
volume of the rectangular prism = Length × Width × Height
Substitute the values in the above formula,
24 yds cubed = z × 1 × 4
Apply the multiplication operation, and we get
24 = 4 z
z = 24/4
z = 6 yds
Therefore, the missing measurement for z would be 6 yds.
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Number 10 but I only need help finding the area.
Given:
We are given this figure.
To find:
The area of the given figure.
Step-by-step solution:
As per the question, It is a trapezoid:
Area of trapezoid = 1/2 × (a + b) × h
Here a and b are lengths of parallel sides.
Area = 1/2 × (a + b) × h
Area = 1/2 × (8 + 27) × 6
Area = 1/2 × 35 × 6
Area = 35 × 3
Area = 105 cm²
Final answer:
The final area of the trapezoid = 105 cm²
Use the given information in the figure to determine whether or not BD || AE.
Let the lines BD || AE
So, the triangle ACE is similar to triangle BCD
Then from the properties of similar triangle
The ratio of corresponding sides are always equal:
[tex]\frac{BC}{AC}=\frac{CD}{CE}=\frac{EA}{DB}[/tex]Substitute the value :
[tex]\begin{gathered} \frac{BC}{AC}=\frac{CD}{CE}=\frac{EA}{DB} \\ \frac{9}{9+6}=\frac{11}{11+3}=\frac{EA}{DB} \\ \frac{9}{12}=\frac{11}{14}=\frac{EA}{DB} \\ \text{ Since the ratio are not equal} \end{gathered}[/tex]So, the triangles are not similar thus, the lines BD is not parallel to AE
Answer : D
What is the solution to the equation below? Round your answer to two decimal places.3x = 21A.x = 2.77B.x = 1.32C.x = 0.36D.x = 3.04
Given: The equation below
[tex]3^x=21[/tex]To Determine: The value of x
Solution
Let us apply the exponent rule
[tex]\begin{gathered} 3^x=21 \\ xln3=ln21 \end{gathered}[/tex][tex]\begin{gathered} xln3=ln21 \\ x=\frac{ln21}{ln3} \end{gathered}[/tex][tex]\begin{gathered} x=\frac{3.0445}{1.0986} \\ x=2.7712 \\ x\approx2.77 \end{gathered}[/tex]Hence, the approximate value of x is 2.77, OPTION A
Use mathematical induction to prove the statement is true for all positive integers n, or show why it is false. Picture attached.
True
1) There are three steps, to using mathematical induction.
2) The first one is to check for n=1
[tex]\begin{gathered} \left(3n-2\right)^2=\frac{n\left(6n^2-3n-1\right)}{2} \\ \\ \left(3\cdot \:1-2\right)^2=\frac{1\cdot \left(6\cdot \:1^2-3\cdot \:1-1\right)}{2} \\ \\ (3-2)^2=\frac{1(6-3-1)}{2} \\ \\ 1^2=\frac{2}{2} \\ \\ 1=1\:\:True \end{gathered}[/tex]3) Secondly, let's prove it for n=k:
[tex]\sum _{k=1}^k\left(3k-2\right)^2=\frac{k\left(6k^2-3k-1\right)}{2}[/tex]4) And finally, for n=k+1
[tex]\begin{gathered} \sum _{n=1}^n\left(3n-2\right)^2=\frac{n\left(6n^2-3n-1\right)}{2} \\ \\ \sum _{\left(k+1\right)=1}^{k+1}\left(3\left(k+1\right)-2\right)^2=\frac{\left(k+1\right)\left(6\left(k+1\right)^2-3\left(k+1\right)-1\right)}{2} \\ \\ \left(3\left(k+1\right)-2\right)^2+\frac{k\left(6k^2-3k-1\right)}{2}=\frac{\left(k+1\right)\left(6\left(k+1\right)^2-3\left(k+1\right)-1\right)}{2} \\ \\ 2\left(3\left(k+1\right)-2\right)^2+k\left(6k^2-3k-1\right)=\left(k+1\right)\left(6\left(k+1\right)^2-3\left(k+1\right)-1\right) \\ \\ 6k^3+15k^2+11k+2=6k^3+15k^2+11k+2 \\ \\ 6k^3+15k^2+11k+2-2=6k^3+15k^2+11k+2-2 \\ \\ 6k^3+15k^2+11k=6k^3+15k^2+11k \\ \\ 6k^3+15k^2+11k-\left(6k^3+15k^2+11k\right)=6k^3+15k^2+11k-\left(6k^3+15k^2+11k\right) \\ \\ 0=0 \\ \\ True. \end{gathered}[/tex]As all of those 3 steps were true. Then we can tell, that this is true.
Graph the inequality on the axes below.please shade what sidex−5y<20
In the graph y will always be smaller than 1/5(x) - 4 in the inequality x−5y<20.
What is inequality?Mathematical expressions with inequalities on both sides are known as inequalities. In an inequality, we compare two values as opposed to equations. In between, the equal sign is changed to a less than (or less than or equal to), greater than (or greater than or equal to), or not equal to sign.
Olivia is chosen for the 12U softball team. What age is Olivia? Because it doesn't say "equals," you are unaware of Olivia's age. But since you already know Olivia's age should be below or equal to 12, you can write it as Olivia's Age 12. This scenario relates to inequalities in the real world.
First we will write the equation in the y-intercept form
y = mx + b
So,
⇒ x−5y<20
⇒ x -5y - 20 < 20 - 20
⇒ x -5y - 20 < 0
⇒ x -5y - 20 - x +20 < - x +20
⇒ -5y < - x +20
⇒ 5y < x - 20
⇒ y < 1/5(x) - 4
Here slope is 1/5
So the graph is give below ↓↓↓
Thus, In the graph y will always be smaller than 1/5(x) - 4 in the inequality x−5y<20.
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Match each equation with an equivalent equation 3x+5=4x+8
Each equation 3x + 5 and 4x + 8 which is equivalent to each other is matched giving the value 4.
What is equivalent equations?Equations with identical solutions or answers are said to be equivalent. It's common to compare linear equations to one another. When graphed, linear equations result in lines that are straight, have a slope, and have a y-intercept.
The characteristics that make linear equations linear are crucial in determining whether or not the equations will be equivalent when comparing linear equations. There are mathematical ways to determine whether the solutions to the equivalent equations are the same even though it may not initially appear that way.
To match the equation we need to find x first
3x + 5 = 4x + 8
⇒ 5 - 8= 4x - 3x
⇒ x = -3
Putting the value of x in respective equations
⇒ 3(-3) + 5 = 4(-3) + 8
⇒ -9 + 5 = -12 + 8
⇒ 4 = 4
Thus, each equation 3x + 5 and 4x + 8 which is equivalent to each other is matched giving the value 4.
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Find the length of segment AB. Round to 1 decimal place
Distance Between Two Points
The length of a segment that connects two points can be calculated as the distance between those points (x1,y1) (x2,y2) with the formula:
[tex]d=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]The endpoints of segment AB are A(-5, 2) and B(4, -3). Calculating the distance:
[tex]d=\sqrt[]{(4+5)^2+(-3-2)^2}[/tex]Calculate:
[tex]\begin{gathered} d=\sqrt[]{9^2+(-5)^2} \\ d=\sqrt[]{81+25} \\ d=\sqrt[]{106} \end{gathered}[/tex]Calculating and rounding to one decimal place:
d = 10.3
The length of segment AB is 10.3 units
Question 4 of 9Which of the following is the quotient of the rational expressions shownbelow?3x + 2X +52x - 1
SOLUTION
From
[tex]\begin{gathered} \frac{4x}{2x-1}\text{ divided by }\frac{3x+2}{x+5} \\ \\ \frac{4x}{2x-1}\times\frac{x+5}{3x+2} \\ \\ \frac{4x^2+20x}{6x^2+4x-3x-2} \\ \\ \frac{4x^2+20x}{6x^2+x-2} \end{gathered}[/tex]The quotient is the answer gotten after a division is made. Therefore, the answer above is the quotient. Option C is the correct answer
i need help this is kinda hard
Perform the following mathematical operation and report the answer round to the correct number of significant figures
Solution
Step 1:
Write the expression
[tex]143.6\text{ }\div\text{ 21.2}[/tex]Step 2
[tex]\begin{gathered} 143.6\text{ }\div\text{ 21.2 } \\ =\text{ 6.773584906} \end{gathered}[/tex]Answer
6.8 ( 2 significant figure)
The area of Canada is 17 times the area
of France.
The area of Canada is 3,851,809 square
miles.
What is the area of France?
plsss help
Answer:
A(Canada) / factor = A(France)
3,851,809/17 = A(France)
226,577 sqmi = A(France)
Hope that helps
NOTE: This answer is a bit off from the actual calculation but it is fine because the original value of Canada's area was given about 5,000 sqmi off.
help me please
thank you
If the ordered pair (x,y) is in the relation and the object x is from the first set and the object y is from the second set, the objects are said to be related. A relation is a type of function.
For The Realation { X | X < -4}
The Graph a is correct solution
In interval notation ( - ∞ , -4 ).
What is the definition of relation ? A relation between two sets is a collection of ordered pairs that each contain one object from the other set. If the ordered pair (x,y) is in the relation and the object x is from the first set and the object y is from the second set, the objects are said to be related. A relation is a type of function.The distinction between a relation and a function is that a relationship can have multiple outputs for a single input, whereas a function only has one input and one output. This is the fundamental distinction between relation and function. Relations are used to form those model concepts.To learn more about : Relations
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Can you find the value of n, please!
After solving for x, we get the value of n as an improper fraction:
(-3).(-1)/2
Given, the expression is:
1/8÷√2=2ⁿ
convert the expression to exponential form.
1/8 ÷ 2¹/² = 2ⁿ
1/2³ ÷ 2¹/² = 2ⁿ
convert both sides of the equation into terms with same base.
2⁻³ ÷ 2¹/² = 2ⁿ
Simplify using exponent rule with same base.
aⁿ.aˣ=aⁿ⁺ˣ
2⁻³⁻¹/²=2ⁿ
Based on the given conditions, corresponding exponents are equal.
n=-3-1/2
Rewrite the fraction using the least common denominator.
n = -6-1/2
calculate the difference.
n = -7/2
improper fraction is : (-3).(-1)/2
Hence we get the value for n as (-3).(-1)/2
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In a random sample of 30 young bears, the average weight at the age of breeding is 312 pounds. Assuming the population ages are normally distributed with a population standard deviation is 30 pounds, use the Empirical Rule to construct a 68% confidence interval for the population average of young bears at the age of breeding. Do not round intermediate calculations. Round only the final answer to the nearest pound. Remember to enter the smaller value first, then the larger number.
We have that the empirical rule to construct a 68% confidence interval can be expressed with the following general rule:
[tex](\mu-\sigma,\mu+\sigma)[/tex]in this case, we have the following information:
[tex]\begin{gathered} \mu=312 \\ \sigma=30 \end{gathered}[/tex]then, the confidence interval with 68% of confidence is:
[tex](312-30,312+30)=(282,342)[/tex]therefore, the confidence interval with 68% of confidence is (282,342)
Answer: (307,317)
Step-by-step explanation:
The population standard deviation is known (and is assumed to be normally distributed). Using the Empirical Rule, we know that approximately 68% of the data lies within one standard deviation of the mean. So, the confidence coefficient is zα2=1, approximately.The point estimate for the population mean, μ, is the sample mean, x¯=312. The standard error for the sampling distribution is σx¯=σn√, where σ is the population standard deviation and n is the sample size. So, the standard error is σx¯=30n√. We did not list a decimal approximation because the instructions stated that only the final answer should be rounded. The error bound for the mean (EBM) is given by the formula EBM=zα2(σn√)=1(3030√). Again, we did not list a decimal approximation because the instructions stated that only the final answer should be rounded. Finally, we can calculate the confidence interval at the desired level of significance using the formula (point estimate−EBM , point estimate+EBM)(312−1(3030‾‾‾√),312+1(3030‾‾‾√))(307,317)
World class marathon runners are known to run that distance (26.2 miles) in an average of 143 minutes with a standard deviation of 13 minutes.If we sampled a group of world class runners from a particular race, find the probability of the following:**(use 4 decimal places)**a.) The probability that one runner chosen at random finishes the race in less than 137 minutes. b.) The probability that 10 runners chosen at random have an average finish time of less than 137 minutes. c.) The probability that 50 runners chosen at random have an average finish time of less than 137 minutes.
EXPLANATION
We have μ = 144 and sd = 13
Computing the needed probabilities:
a) P(x < 137 ) =
[tex]=P(\frac{X-\mu}{\sigma}<\frac{137-\mu}{\sigma})[/tex][tex]=P({Z}\lt\frac{137-143}{13})[/tex][tex]=P(z<-0.4615[/tex][tex]=0.3228[/tex]a) The probability is 0.3228
b) Number of runners ---> n=10
P(x < 137 ) =
[tex]=P(\frac{X-\mu}{\frac{\sigma}{\sqrt{n}}}<\frac{137-\mu}{\frac{\sigma}{\sqrt{n}}})[/tex][tex]=P({Z}\lt\frac{137-143}{\frac{13}{\sqrt{10}}})[/tex][tex]=P(z<-1.4595)[/tex][tex]=0.0735[/tex]b) The probability is 0.0735
c) Number of runners ---> n=50
P(x < 137 ) =
[tex]=P(\frac{X-\mu}{\frac{\sigma}{\sqrt{n}}}<\frac{137-\mu}{\frac{\sigma}{\sqrt{n}}})[/tex][tex]=P({Z}\lt\frac{137-143}{\frac{13}{\sqrt{50}}})[/tex][tex]=P(z<-3.2635)[/tex][tex]\approx0.0006[/tex]b) The probability is approximately 0.0006
Suppose that the function h is defined, for all real numbers, as follows.
Find h (1), h (2), and h (4).
The function h is defined, for all real numbers , answer is as follows -
h(1) = - 2
h(2) = 3
h(4) = 3.
function, an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable
We have been given that
h(x) = 1/4(x) - 1 if x < -2
h(x) = -(x + 1)² + 2 if -2 ≤ x < 2
h(x) = 3 if x ≥ 2
Find h (1), h (2), and h (4)
For h (1) -
Value of h(1) for h(x) = -(x + 1)² + 2 as if -2 ≤ x < 2
So put x = 1
h(x) = -(x + 1)² + 2
h(1) = -(1 + 1)² + 2
h(1) = -4 + 2
h(1) = - 2
For h (2) -
Value of h(2) for h(x) = 3 as if x ≥ 2
h(x) = 3
h(2) = 3
For h (4) -
Value of h(4) for h(x) = 3 as if x ≥ 2
h(x) = 3
h(4) = 3
Hence , the value for given functions - h(1) = - 2 , h(2) = 3 and h(4) = 3.
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Ryan is 93 years younger than Stacy.9 years ago , Stacy's age was 4 times Ryan's age. How old is Ryan now.
Answer:
40 years old
Step-by-step explanation:
Define the variables:
Let r be Ryan's age (in years).Let s be Stacy's age (in years).Given Ryan is 93 years younger than Stacy:
⇒ r = s - 93
Given 9 years ago, Stacy's age was 4 times Ryan's age:
⇒ 4(r - 9) = (s - 9)
Substitute the first equation into the second equation and solve for s:
⇒ 4(s - 93 - 9) = (s - 9)
⇒ 4(s - 102) = s - 9
⇒ 4s - 408 = s - 9
⇒ 3s = 399
⇒ s = 133
Substitute the found value of s into the second equation and solve for r:
⇒ r = 133 - 93
⇒ r = 40
Therefore, Ryan is 40 years old now.
please help me out quickly
A⁻¹ = [1/19] [tex]\left[\begin{array}{ccc}7&-8\\5&-3\end{array}\right][/tex]
x = [1/19] [tex]\left[\begin{array}{ccc}18\\2\end{array}\right][/tex]
Given matrix A is:
[tex]\left[\begin{array}{ccc}-3&8\\-5&7\end{array}\right][/tex]
The inverse of a matrix is given by A⁻¹ = (1/|A|) × Adj A.
The formula gives the inverse of a 2×2 matrix [tex]\left[\begin{array}{ccc}a&b\\c&d\end{array}\right][/tex] ,
A⁻¹ = [1/(ad - bc)] [tex]\left[\begin{array}{ccc}d&-b\\-c&a\end{array}\right][/tex]
If ad - bc is not equal to 0 then only the inverse of the matrix exists.
So, in the given matrix A the determinant (ad -bc) is calculated as,
= (-3)×7 - 8×(-5) = -21 + 40 = 19 ≠ 0
Hence, the inverse of the given matrix exists, which is
A⁻¹ = [1/19] [tex]\left[\begin{array}{ccc}7&-8\\5&-3\end{array}\right][/tex]
Given [tex]b = \left[\begin{array}{ccc}-2\\-4\end{array}\right][/tex] we have to solve Ax = b
The equation can be written for x as, x = A⁻¹ b
Substituting A⁻¹ and b matrix in the equation,we have
x = [1/19] [tex]\left[\begin{array}{ccc}7&-8\\5&-3\end{array}\right][/tex] [tex]\left[\begin{array}{ccc}-2\\-4\end{array}\right][/tex]
The matrix x is,
x = [1/19] [tex]\left[\begin{array}{ccc}18\\2\end{array}\right][/tex]
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Susie receives an employee discount of 8% on all items purchased in the retail store where she works. If she purchases two blouses at $24.99 each and three skirts for $48.00, how much was her bill, including a 7% tax?A. $190.95B. $189.96C. $190.96
First, let's calculate the total price without discount or taxes:
[tex]\begin{gathered} C=2\cdot24.99+3\cdot48\\ \\ C=193.98 \end{gathered}[/tex]Now, to apply a discount of 8%, we can multiply the cost by 92%, that is, 0.92:
[tex]\begin{gathered} C^{\prime}=0.92C\\ \\ C^{\prime}=0.92\cdot193.98\\ \\ C^{\prime}=178.46 \end{gathered}[/tex]And then, to apply a tax of 7%, we can multiply the cost by 107%, that is, 1.07:
[tex]\begin{gathered} C_{final}=1.07C^{\prime}\\ \\ C_{final}=1.07\cdot178.46\\ \\ C_{final}=190.95 \end{gathered}[/tex]Therefore the correct option is A.