Determine the values of a such that the following vectors are i
linearly independent. V1 = {1,2,0}, v2= {1,0 .,1}, v3 ={1,a,4}.

Answers

Answer 1

The vectors v1 = {1,2,0}, v2 = {1,0,1}, and v3 = {1,a,4} are linearly independent if a = 8/3, t and  linearly dependent for a = 2, and linearly independent for a = 8/3.

For the vectors to be linearly independent, we need to check if the following system of equations has a unique solution:

c1v1 + c2v2 + c3v3 = 0

where c1, c2, c3 are constants, and 0 is the zero vector.

Substituting the given vectors, we get the following system of equations:

c1 + c2 + c3 = 0 (1)

2c1 + ac3 = 0 (2)

c2 + 4c3 = 0 (3)

If we can find values of a for which this system of equations has a non-trivial solution, then the vectors are linearly dependent. Otherwise, they are linearly independent.

To find such values of a, we need to solve the system of equations and find the conditions under which it has non-trivial solutions.

From equations (2) and (3), we get:

c2 = -4c3 (4)

2c1 + ac3 = 0 (5)

Substituting equations (1) and (4) into equation (5), we get:

2(-c2 - c3) + ac3 = 0

Simplifying, we get:

(-2 + a)c3 - 2c2 = 0

Substituting equation (4), we get:

(-2 + a)c3 + 8c3 = 0

Solving for c3, we get:

c3 = 0 if a = 2

c3 = 0 if a = 8/3

For a = 2, the system reduces to:

c1 + c2 = 0

2c1 = 0

c2 + 4c3 = 0

This system has a non-trivial solution: c1 = 0, c2 = 1, c3 = -1/4.

Therefore, the vectors are linearly dependent for a = 2.

For a = 8/3, the system reduces to:

c1 + c2 + c3 = 0

(8/3)c3 = 0

c2 + 4c3 = 0

This system has only the trivial solution: c1 = c2 = c3 = 0.

Therefore, the vectors are linearly independent for a = 8/3.

In summary, the given vectors are linearly dependent for a = 2, and linearly independent for a = 8/3.

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Related Questions

Use the confidence interval to find the margin of error and the sample mean

(12.0, 14.8)

Answers

Answers:

Margin of error = 1.4

Sample mean = 13.4

=============================================================

Explanation:

To find the margin of error, we subtract the endpoints and divide by 2.

(b-a)/2 = (14.8-12.0)/2 = 1.4 is the margin of error

The b-a portion calculates the width of the confidence interval. It's the distance from one endpoint to the other. Splitting that in half gives the "radius" so to speak of this interval.

----------

The sample mean is at the midpoint of those given confidence interval endpoints.

The midpoint formula will have us add up the values and divide by 2

(a+b)/2 = (12.0+14.8)/2 = 13.4 is the sample mean

The a+b portion is the same as b+a, meaning we could have written that formula as (b+a)/2 as indicated in the next section.

-----------

Take note how similar each formula is:

margin of error = (b-a)/2sample mean = (b+a)/2

The only difference is one has a minus sign and the other has a plus sign.

Can someone please tell me what x=

Answers

Answer: It is and answer that is not known yet

Step-by-step explanation: so 5x5=x x would be 25

Find the mean, median and mode of the data choose the measure. That best represents the data. Explain your reasoning

Answers

For the given observations 48, 12, 11, 45, 48, 48, 43, 32, the values are -

Mean = 37.5 , Median = 44, and Mode = 48

The median is the best measure for the data.

What is mean?

In statistics, in addition to the mode and median, the mean is one of the metrics of central tendency. Simply put, the mean is the average of the values in the given collection. It indicates that values in a particular data collection are distributed equally. The three most frequently employed metrics of central tendency are the mean, median, and mode.

To find the measure that best represents the given data, we can calculate the mean, median, and mode and choose the measure that gives us the most representative value.

Mean -

To find the mean of the data, we add up all the values and divide by the total number of values -

Mean = (48 + 12 + 11 + 45 + 48 + 48 + 43 + 32) / 8 = 37.5

Median -

To find the median of the data, we arrange the values in order from smallest to largest and then find the middle value.

If there are an even number of values, we take the average of the two middle values.

11, 12, 32, 43, 45, 48, 48, 48

There are eight values in the data set, so the median is -

(43 + 45) / 2

88 / 2

44

Mode -

To find the mode of the data, we look for the value that occurs most frequently.

In this case, 48 occurs three times, which is more than any other value, so the mode is 48.

Conclusion:

In this data set, the mean is 37.5, the median is 44, and the mode is 48. Since the data set has some values that are higher than the others, such as 48 occurring three times, the mean may be influenced by these outliers.

In this case, the median is a better measure of central tendency because it is not influenced by outliers.

Therefore, the median is the measure that best represents the data.

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Rewrite the set U by listing its elements. Make sure to use the appropriate set notation. U={z|z is an integer and -3<=z<=-1}

Answers

The answer of set U by listing its elements is {-3, -2, -1}

To rewrite the set U by listing its elements, we need to identify the integers that fall within the given range of -3<=z<=-1.

The appropriate set notation for listing the elements of a set is {element1, element2, element3, ...}.

So, the integers that fall within the given range are -3, -2, and -1.

Therefore, we can rewrite the set U as:

U = {-3, -2, -1}

This is the answer in the appropriate set notation, listing the elements of the set U.

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AB-> (2;3) AB = ?
les coordonées de mon vecteur AB-> sont ( 2;3 ) est ce que AB= racine de( 2 au carre + 3 au carée)

Answers

Answer:

Réponse :Explications étape par étapea) Le vecteur AC(xc-xa;yc-ya)vecteur AC(-6;-3

Step-by-step explanation:

Les coordonnées d'un vecteur dans un r.o.n. décrivent le déplacement qu'il représente. Ainsi, un déplacement de « 3 ...

Will a line passes through (2,2)if it is intersects the axes (2,0)and (0,2)

Answers

A line intersecting at the axes (2,0)and (0,2) will not pass through (2,2).

Given, a line intersects at the axis (2,0)and (0,2)

let the line intercept be expressed as

[tex]ax+by=1[/tex] where a and b are the x & y intercept.

since the intercept points are the axis (2,0)and (0,2)

a=2 and b=2

[tex]2x+2y=1[/tex]

when the point (2,2) is considered and put in equation

2(2)+2(2)=4≠1

Therefore, point (2,2) doesn't satisfy the equation and line doesn't pass through (2,2).

From the graph also, we can say that the line passing through (2,0) and (0,2) intersecting the axes do not pass through the point (2,2).

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Comment résoudre une équation ?
Ex: 3x + 4= 2x + 9

Answers

Given:-

[tex] \tt \: 3x + 4 = 2x + 9[/tex]

[tex] \: [/tex]

Solution:-

[tex] \tt \: 3x + 4 = 2x + 9[/tex]

[tex] \: [/tex]

[tex] \tt \: 3x - 2x = 9 - 4[/tex]

[tex] \: [/tex]

[tex] \tt \: 1x = 5[/tex]

[tex] \: [/tex]

[tex] \tt \: x = \cancel\frac{5}{1} [/tex]

[tex] \: [/tex]

[tex] \underline{ \underline{ \color{black}{ \tt \: x = 5}}}[/tex]

[tex] \: [/tex]

hope it helps!:)

Bonjour !

Il faut isoler x.

3x + 4 = 2x + 9

3x - 2x = 9 - 4

x = 5

There are 12 boys and 13 girls in my 3rd period class. How many pairs can I make if I choose
one boy and one girl?

Answers

I would think 12 because there are less boys than girls so because of that we take the number of pairing possible which would only be up to 12?

The volume of a cylinder is 180 pi cubic inches and the radius of the cylinder is 3 inches. what is the height of the cylinder 

Answers

Using the formula of the cylinder we know that the height of the given cylinder is 6.36 inches.

What is a cylinder?

One of the most fundamental curvilinear geometric shapes, a cylinder has historically been a three-dimensional solid.

It is regarded as a prism with a circle as its base in basic geometry.

In several contemporary fields of geometry and topology, a cylinder can alternatively be characterized as an infinitely curved surface.

So, the cylinder formula for the volume is:

V = πr²h

Now, substitute the values as follows:

V = πr²h

180 = 3.14*3²h

180 =  28.26h

180/28.26 = h

6.36 = h

Therefore, using the formula of the cylinder we know that the height of the given cylinder is 6.36 inches.

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1. (7 points) Find the minima and maxima of the following function at a given interval:y=x4−32​x3−2x2+2xin the interval[0,3]. Hints: You may want to use conditional statement to gatekeep the values. However, do not use solveset () function.

Answers

The minima and minima of the function y=x^4-(32/3)x^3-2x^2+2x in the interval [0,3] are:
Maxima: x=2

Minima: None

The minima and maxima of a function are the lowest and highest points on the function within a given interval. To find these points, we need to take the derivative of the function and set it equal to zero to find the critical points. The critical points are where the function changes direction, and are potential minima or maxima. We can then use a conditional statement to determine if the critical points are within the given interval and if they are minima or maxima.

The derivative of the function is:
y'=4x^3-3(32/3)x^2-4x+2

Setting the derivative equal to zero, we get:
4x^3-32x^2-4x+2=0

We can use the Rational Root Theorem to find the potential rational roots of this equation. The potential rational roots are ±1, ±2, ±1/2, and ±1/4. Using synthetic division, we find that x=2 is a root. This gives us the factor (x-2), and we can use synthetic division again to find the other factors. The factored form of the equation is:
(x-2)(4x^2-12x+1)=0

Using the quadratic formula, we can find the other two roots:
x=3±√(3^2-4(4)(1))/2(4)
x=3±√(9-16)/8
x=3±√(-7)/8
x=3±i√7/8

The only real root is x=2, so this is the only critical point. We can use a conditional statement to determine if this critical point is within the given interval and if it is a minima or maxima. The critical point x=2 is within the interval [0,3], so we need to determine if it is a minima or maxima. We can do this by taking the second derivative of the function and plugging in the critical point:
y''=12x^2-6(32/3)x-4
y''(2)=12(2^2)-6(32/3)(2)-4
y''(2)=48-64-4
y''(2)=-20

Since the second derivative is negative at the critical point, this means that the critical point is a maxima. Therefore, the maxima of the function is at x=2.

In conclusion, the minima and maxima of the function y=x^4-(32/3)x^3-2x^2+2x in the interval [0,3] are:
- Maxima: x=2
- Minima: None

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Identify the highlighted part of circle O shown below. ​

Answers

The highlighted part of circle shown below is known as segment.

What is the segment of a circle?

A segment of a circle is a region of the circle that is bounded by a chord and the arc that it intersects. More specifically, a segment is the region between a chord and a minor or major arc of a circle.

The chord is the straight line that connects two points on the circumference of the circle, and the arc is the curved part of the circumference that lies between these two points. A segment is named according to its chord, for example, the segment determined by the chord AB is referred to as segment AB. The area of a segment of a circle can be calculated using the formula A = (1/2)r^2(θ-sinθ), where r is the radius of the circle, and θ is the central angle of the segment in radians.

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Q1: What percent of males drive sports cars?

Q2: What percent of all drivers are male?

Q3: What percent of sports car drivers are male?

Q4: are question 1 and question 3 the same? (yes or no)

Answers

(1) The percentage of males that drive sports cars is 46.43 %.

(2) The percentage of all drivers that are male is 25 %.

(3) The percentage of sports car drivers that are male is 46.43 %.

(4) Yes, question 1 and question 3 are the same.

What percent of males drive sports cars?

The percentage of males that drive sports cars is calculated as follows;

= 39 / 84  x 100%

= 46.43 %

The percentage of all drivers that are male is calculated as follows;

= 60 / 240  x 100%

= 25%

The percentage of sports car drivers that are male is calculated as;

= 39 / 84  x  100%

= 46.43 %

Thus, question 1 and question 3 are the same.

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a 20
b 15
c 5
d 10
i need sum help on this real quick

Answers

Answer:

C

Step-by-step explanation:

6x° and 60° form a right angle and sum to 90° , that is

6x + 60 = 90 ( subtract 60 from both sides )

6x = 30 ( divide both sides by 6 )

x = 5

3x - 3 = root^2 of 3x^2 + 177 What is the sum of all the solutions to the above equation? A - 11 B) -3
C) 3
D) 7

Answers

We start by isolating the square root on one side of the equation:

3x - 3 = sqrt(3x^2 + 177)

Squaring both sides of the equation gives:

(3x - 3)^2 = 3x^2 + 177

Expanding the left-hand side gives:

9x^2 - 18x + 9 = 3x^2 + 177

Simplifying gives:

6x^2 - 18x - 168 = 0

Dividing both sides by 6 gives:

x^2 - 3x - 28 = 0

We can now solve for x using the quadratic formula:

x = (3 ± sqrt(3^2 + 4128)) / 2

x = (3 ± 7) / 2

Therefore, the solutions are x = -2 and x = 5, and their sum is -2 + 5 = 3.

Thus, the answer is (C) 3.

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Find 2 famous structures/ inventions showing angles formed by secants and tangents

Answers

Two famous structures/ inventions showing angles formed by secants and tangents are: The London Eye and The Eiffel Tower.

1. The London Eye: The London Eye is a giant Ferris wheel located on the South Bank of the River Thames in London. It is a popular tourist attraction and an iconic symbol of London. The London Eye has 32 oval-shaped capsules, each of which can carry up to 25 people. The structure is made up of several secants and tangents, which form angles at various points along the wheel.

2. The Eiffel Tower: The Eiffel Tower is a wrought-iron lattice tower located on the Champ de Mars in Paris, France. It is one of the most recognizable structures in the world and a symbol of France. The Eiffel Tower is made up of several secants and tangents, which form angles at various points along the structure.

Both of these structures are examples of how secants and tangents can be used in the design of famous structures and inventions. These angles play a crucial role in the stability and strength of the structures, allowing them to withstand the weight of the people and objects they hold.

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If 3x-y=12, what is the value of 8x over 2y?

A.) 2^12
B.) 4^4
C.) 8^2
D.) The value cannot be determined from the information given.

Answers

Step-by-step explanation:

We can solve for x in terms of y from the equation 3x - y = 12 as follows:

3x - y = 12

3x = y + 12

x = (y + 12)/3

Similarly, we can solve for y in terms of x:

3x - y = 12

-y = -3x + 12

y = 3x - 12

Now, we can substitute these expressions for x and y into the expression 8x/2y to get:

8x/2y = 4x/y

Substituting (y + 12)/3 for x, we get:

4x/y = 4((y + 12)/3)/y = 4(y + 12)/3y

Simplifying the numerator, we get:

4(y + 12) = 4y + 48

Substituting 3x - 12 for y, we get:

4y + 48 = 4(3x - 12) + 48 = 12x

Therefore, 8x/2y = 4x/y = 12x/4y = 12x/(3x - 12)

We cannot simplify this expression further without additional information. Therefore, the answer is (D) The value cannot be determined from the information given.

For the functionf(x)=(8−2x)^2, find f−1. Determine whetherf−1is a function.f−1(x)=±28+x​​;f−1is not a function.f−1(x)=28±x​​;f−1is not a function.f−1(x)=±28+x​​;f−1is a function.f−1(x)=28±x​​,f−1is a function.

Answers

The correct answer is f^-1(x) = (8-√x)/2; f^-1 is a function.

To find the inverse of the function f(x) = (8-2x)^2, we need to switch the x and y variables and solve for y. This will give us f^-1(x).

So, we start with:

x = (8-2y)^2

Next, we take the square root of both sides:

√x = 8-2y

Then, we isolate the y variable:

2y = 8-√x

y = (8-√x)/2

So, the inverse of the function is:

f^-1(x) = (8-√x)/2

Now, we need to determine whether f^-1(x) is a function. To do this, we can use the horizontal line test. If a horizontal line intersects the graph of f^-1(x) at more than one point, then f^-1(x) is not a function.

In this case, a horizontal line will only intersect the graph of f^-1(x) at one point, so f^-1(x) is a function.

Therefore, the correct answer is f^-1(x) = (8-√x)/2; f^-1 is a function.

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please help, I legit am not sure what I'm supposed to do ​

Answers

Recall definitions:

cosine = adjacent/hypotenusesine = opposite/hypotenusetangent = opposite/adjacent

Use the triangle to define each ratio.

Use Pythagorean theorem:

a² + b² = c²

Question 1(sin B)² + (cos B)² = (b/c)² + (a/c)² = b²/c² + a²/c² = (a² + b²)/c² = c²/c² = 1

Proved

Question 21/(cos A)² - (tan A)² = 1/(b/c)² - (a/b)² = c²/b² - a²/b² = (c² - a²)/b² = b²/b² = 1

Proved

Which side lengths form a triangle? (Choose all that apply.)


1


2


3


4

5

6

7

8

Answers

Answer:

djdjdhdudjdhxnfbxi94949495959584748474748494949585858595959585858585858585859696969485858589484748487474747383392929२९३9999४४६५८४९२84८३4६३०२०८४७४94८८४७४९8४८४८४८४८४८48484८5८५८५८४८३९2९२919९२9३76४७४7७४७४7४5959999393939393939494949449494949494998595859303099

(3,-6) is an endpoint coordinate on a line segment, where the midpoint is given to us as (1, -2). What is the coordinate of the other endpoint of the line segment? Fill in the blanks below.



( , )

Answers

The coordinate of the other endpoint of the line segment is (-1, 2).

Describe Line Segment?

In geometry, a line segment is a part of a line that has two endpoints. It is the shortest distance between two points on a line. A line segment can be straight or curved, and can be vertical, horizontal, or diagonal.

The length of a line segment can be measured using units such as centimeters, inches, or feet. The midpoint of a line segment is the point that is exactly halfway between its endpoints, and it is located at the average of the x-coordinates and the y-coordinates of the endpoints.

Let (x, y) be the coordinate of the other endpoint of the line segment. Then, we know that the midpoint of the line segment is given by the formula:

midpoint = ((x1 + x2)/2, (y1 + y2)/2)

Substituting the given values, we have:

(1, -2) = ((3 + x)/2, (-6 + y)/2)

Multiplying both sides by 2, we get:

(2, -4) = (3 + x, -6 + y)

Separating the x and y terms, we have:

2 = 3 + x -> x = -1

-4 = -6 + y -> y = 2

Therefore, the coordinate of the other endpoint of the line segment is (-1, 2).

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I need help with question 10. I need to find the value of x

Answers

The solution is, the value of x is, x = 12.

What is triangle?

A triangle is a polygon with three edges and three vertices. It is one of the basic shapes in geometry. A triangle with vertices A, B, and C is denoted \triangle ABC. In Euclidean geometry, any three points, when non-collinear, determine a unique triangle and simultaneously, a unique plane.

here, we have,

from the given figure, we get,

the triangles are similar,

so, we know that, the sides are proportional to each other.

i.e. 8:4 = x: 6

or, x = 8 * 6 / 4

or, x  = 2 * 6

or, x = 12

Hence, The solution is, the value of x is, x = 12.

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So I’ve been stuck on this for a very long time it’s so annoying please hellpppp me

Answers

ANSWER - 8p + 1 and p + (3p - 5) + (4p + 6)

hope this helps!

Do number 9 please thank you.

Answers

Answer:

x=6x³-5x²-66x-40

Step-by-step explanation:

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let ABC be a triangle. Determine the exact values of
the three angles A, B, C. if we know that A = 5x, B = 6x, and C =
7x

Answers

For the given triangle ABC, the exact values of the three angles are: A = 50°, B = 60°, and C = 70°.

Let ABC be a triangle. The angles A, B, and C can be determined using the fact that the sum of the angles in any triangle is 180°.

We know that

A = 5x, B = 6x, and C = 7x, so:


A + B + C = 5x + 6x + 7x = 18x

Since the sum of the angles in a triangle is 180°, we can set

18x = 180°

and solve for x:

18x = 180°, x = 10°

Therefore, A = 50°, B = 60°, and C = 70°.


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if 23% of all patients with high blood pressure have had side effects from a certain kind of medicin, so the normal approximation to the binomial to find the probability that among 120 this medicino more 32 will have had side effects.

Answers

The probability that no more than 32 patients out of 120 will have had side effects from the medicine is 0.8289.

The probability that a patient has side effects from the medicine is 23%, or 0.23. We can use the normal approximation to the binomial to find the probability that among 120 patients, no more than 32 will have had side effects.

First, we need to find the mean and standard deviation of the binomial distribution. The mean is np, where n is the number of trials (120 patients) and p is the probability of success (0.23). The mean is 120*0.23 = 27.6.

The standard deviation is sqrt(np(1-p)), or sqrt(120*0.23*(1-0.23)) = 4.65.

Now we can use the normal approximation to find the probability that no more than 32 patients will have had side effects. We need to find the z-score for 32, which is (32-27.6)/4.65 = 0.95. Using a z-table, we find that the probability of getting a z-score less than or equal to 0.95 is 0.8289.

Therefore, the probability that no more than 32 patients out of 120 will have had side effects from the medicine is 0.8289.

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Given the matrices A = [3/4 0] and B = [-4 0]
[0 ¾] [0 -4] 2a) Compute AB 2b) Compute BA.
2c) How did your answer in part (a) and part (b) compare? 2d) Will this be true, in general, for any two matrices when you multiply them (assuming their dimensions line up so that they may be multiplied)? If so, explain your reasoning If not, show an example of two matrices C and such that CD+DC.

Answers

The matrices A and B are given as:

A = [3/4 0]
[0 3/4]

B = [-4 0]
[0 -4]

2a) Compute AB:

AB = [3/4 0] * [-4 0]
[0 3/4] [0 -4]

= [3/4 * -4 + 0 * 0 3/4 * 0 + 0 * -4]
[0 * -4 + 3/4 * 0 0 * 0 + 3/4 * -4]

= [-3 0]
[0 -3]

2b) Compute BA:

BA = [-4 0] * [3/4 0]
[0 -4] [0 3/4]

= [-4 * 3/4 + 0 * 0 -4 * 0 + 0 * -4]
[0 * 3/4 + -4 * 0 0 * 0 + -4 * 3/4]

= [-3 0]
[0 -3]

2c) How did your answer in part (a) and (b) compare?

The answers in part (a) and (b) are the same. Both AB and BA resulted in the matrix [-3 0] [0 -3].

2d) Will this be true, in general, for any two matrices when you multiply them (assuming their dimensions line up so that they may be multiplied)? If so, explain your reasoning. If not, show an example of two matrices C and D such that CD≠DC.

No, this will not be true in general for any two matrices when you multiply them. The order in which matrices are multiplied matters, and in most cases, AB≠BA. Here is an example of two matrices C and D such that CD≠DC:

C = [1 2]
[3 4]

D = [5 6]
[7 8]

CD = [1 * 5 + 2 * 7 1 * 6 + 2 * 8]
[3 * 5 + 4 * 7 3 * 6 + 4 * 8]

= [19 22]
[43 50]

DC = [5 * 1 + 6 * 3 5 * 2 + 6 * 4]
[7 * 1 + 8 * 3 7 * 2 + 8 * 4]

= [23 34]
[31 50]

As you can see, CD≠DC.

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A line passes through the points (-2,7) and (0,-3). What is its equation in slope intercept form

Answers

The equation of the line passing through the points (-2,7) and (0,-3) in slope-intercept form is y = -5x + 7.

Let's first find the slope of the line using the two given points:

slope = (y2 - y1)/(x2 - x1)

slope = (-3 - 7)/(0 - (-2))

slope = (-3 - 7)/(0 + 2)

slope = -10/2

slope = -5

Now that we have the slope, we can use the point-slope form of a line to find its equation:

Where m is the slope and (x1,y1) is any point on the line, y - y1 = m(x - x1).

Let's use the point (-2,7) as (x1,y1):

y - 7 = -5(x - (-2))

y - 7 = -5(x + 2)

y - 7 = -5x - 10

y = -5x + 7

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Find the equation of a line, in Slope Intercept Form, that has a slope of 3 and passes through the point (-4, 2).

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[tex](\stackrel{x_1}{-4}~,~\stackrel{y_1}{2})\hspace{10em} \stackrel{slope}{m} ~=~ 3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{2}=\stackrel{m}{ 3}(x-\stackrel{x_1}{(-4)}) \implies y -2= 3 (x +4) \\\\\\ y-2=3x+12\implies {\Large \begin{array}{llll} y=3x+14 \end{array}}[/tex]

Answer: y = 3x + 14

Step-by-step explanation:

The slope-intercept form is y=mx+b

We will plug in -4 for the x, 2 for the y, and 3 for the m, and leave b alone to solve for it.

2 = 3(-4) + b

2 = -12 + b

b = 14

The final equation is y = 3x + 14.

Hope this helps!

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Answers

Answer: D, 912

Step-by-step explanation:

g(21) = 24 (21 + 17)

g(21) = 24 x 38

g(21) = 912 (Use your calculator for this part)

find from the first principle, the derivative with respect to x of the function.y=2x^2-x+3​

Answers

Answer:

[tex]\dfrac{\text{d}y}{\text{d}x}=4x-1[/tex]

Step-by-step explanation:

Differentiating from First Principles is a technique to find an algebraic expression for the gradient at a particular point on the curve.

[tex]\boxed{\begin{minipage}{5.6 cm}\underline{Differentiating from First Principles}\\\\\\$\text{f}\:'(x)=\displaystyle \lim_{h \to 0} \left[\dfrac{\text{f}(x+h)-\text{f}(x)}{(x+h)-x}\right]$\\\\\end{minipage}}[/tex]

The point (x + h, f(x + h)) is a small distance along the curve from (x, f(x)).

As h gets smaller, the distance between the two points gets smaller.

The closer the points, the closer the line joining them will be to the tangent line.

To differentiate y = 2x² - x + 3 using first principles, substitute f(x + h) and f(x) into the formula:

[tex]\implies \displaystyle \dfrac{\text{d}y}{\text{d}x}=\lim_{h \to 0} \left[\dfrac{2(x+h)^2-(x+h)+3-(2x^2-x+3)}{(x+h)-x}\right][/tex]

Simplify the numerator:

[tex]\implies \displaystyle \dfrac{\text{d}y}{\text{d}x}=\lim_{h \to 0} \left[\dfrac{2x^2+4xh+2h^2-x-h+3-2x^2+x-3)}{x+h-x}\right][/tex]

[tex]\implies \displaystyle \dfrac{\text{d}y}{\text{d}x}=\lim_{h \to 0} \left[\dfrac{2x^2-2x^2+x-x+3-3+4xh+2h^2-h)}{h}\right][/tex]

[tex]\implies \displaystyle \dfrac{\text{d}y}{\text{d}x}=\lim_{h \to 0} \left[\dfrac{4xh+2h^2-h)}{h}\right][/tex]

Separate into three fractions:

[tex]\implies \displaystyle \dfrac{\text{d}y}{\text{d}x}=\lim_{h \to 0} \left[\dfrac{4xh}{h}+\dfrac{2h^2}{h}-\dfrac{h}{h}\right][/tex]

Cancel the common factor, h:

[tex]\implies \displaystyle \dfrac{\text{d}y}{\text{d}x}=\lim_{h \to 0} \left[4x+2h-1\right][/tex]

As h → 0, the second term → 0:

[tex]\implies \displaystyle \dfrac{\text{d}y}{\text{d}x}=4x-1[/tex]

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