Determine what type of model best fits the given situation: principal p is invested at an annual interest of rate r, compounded k times a year for t years.

Answer:

-3/(b-6) = 3/(-b+6) = 3/(6-b)

Step-by-step explanation:

7/(b-6) + 10/(6-b)

= 7/(b-6) + 10/(-b+6)

= 7-10/(b-6)

= -3/(b-6) = 3/(-b+6) = 3/(6-b)

[tex] {\qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Let's solve ~

[tex]\qquad \sf  \dashrightarrow \: \cfrac{7}{b - 6} + \cfrac{10}{6 - b} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \cfrac{7}{b - 6} + \cfrac{10}{ - (b - 6)} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \cfrac{7}{b - 6} - \cfrac{10}{ b - 6} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \cfrac{ - 3}{ b - 6}\:\:\: or \:\:\: \dfrac{3}{6-b} [/tex]

Answer:

if X is the angle degree like I think it is, then X = 56 degrees

Step-by-step explanation:

isosceles triangles will have 2 equal base angles.

90 degree angle - 28 = 62°

62 is now each base angle.

62 times 2 angles equals 124

the final angle, x, is 180 - 124 = 56°

The equation 2^x = 128 as a logarithmic equation is log₂(128) = x

The equation is given as:

2^x = 128

Take the logarithm of both sides

log(2^x) = log(128)

Rewrite as:

x * log(2) = log(128)

Divide both sides of the equation by log(2)

x = log(128)/log(2)

Apply the change of base rule

x = log₂(128)

Hence, the equation 2^x = 128 as a logarithmic equation is log₂(128) = x

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Considering the dot plot, it is found that the tallest conifer is 3.25 inches taller than the shortest conifer.

It shows, with dots, the number of times that each of the measures appears in a data-set.

Researching this problem on the internet, and finding the dot plot, we have that:

The difference is:

9.5 - 6.25 = 3.25 inches.

Hence the tallest conifer is 3.25 inches taller than the shortest conifer.

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Answer:

If I'm not mistaken that is the answer

Answer:

A

Step-by-step explanation:

the means is less than the median

Answer:

Find the interval of convergence of the following series

Possible Answers:

(4,6)

[4,6)

(4,6)

[4,6]

Correct answer:

(4,6)

Explanation:

Step-by-step explanation:

Find the interval of convergence of the following series

Possible Answers:

(4,6)

[4,6)

(4,6)

[4,6]

Correct answer:

(4,6)

Explanation:

Answer:

4368 ways

Step-by-step explanation:

Use nCk for this. 16C5. This is [tex]\frac{n!}{(n-k)!(k!)}[/tex]. This becomes[tex]\frac{16!}{(11!)(5!)}[/tex]. This is [tex]\frac{16*15*14*13*12}{5*4*3*2*1}[/tex] due to 16! and 5! canceling out. This becomes 4368.

The general expression is 130 x - 600 and total points scored by the player is 1220

A) Let the number of correctly answered questions be x.

∴ Number of incorrectly answered questions will be 20 - x.

+ 100 points is awarded for each question answered correctly while -30 points is awarded for each question answered incorrectly.

Thus, the general equation becomes

= 100x - (20 - x)(-30)

= 100x +30x - 600

= 130x - 600

Thus the general expression becomes 130 x - 600

B)  The player answers 14 questions correctly, thus x = 14

Substituting the value of x =14 in the general equation we get,

= 130(14) - 600

= 1820 - 600

= 1220.

Thus the total points scored by the player will be 1220

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From the given sample data in the table on the backpack weight, we have;

(a) The means of the samples are;

(b) The range is 0.25

(c) The true statements are;

(a) The sample means of each of each of the three samples are found as follows;

[tex]Mean = \frac{ \sum \: x}{n} [/tex]

Where;

x = The value of a data point

[tex] \sum \: x = Sum of the data [/tex]

n = Sample size

The mean of the first sample, S1, data is therefore;

[tex]Mean \: S1 = \frac{3 + 7 + 8 + 3 + 7 + 9 + 6 + 8}{8} [/tex]

3+7+8+3+7+9+6+8 = 51

Which gives

[tex]Mean \: S1 = \frac{51}{8} = \mathbf{6.375\[/tex]

Similarly, we have;

[tex]Mean \: S2 = \frac{8 + 6 + 4 + 7 + 9 + 4 + 6 + 7}{8} [/tex]

8 +6+4+7+9+4+6+7 = 51

Which gives;

[tex]Mean \: S2 = \mathbf{\frac{51}{8}} = 6.375 [/tex]

Mean of the second sample = 6.375

[tex]Mean \: S3 = \frac{9 + 4 + 5 + 8 + 7 + 5 + 9 + 6}{8} [/tex]

9+4+5+8+7+5+9+6 = 53

Which gives;

[tex]Mean \: S3 = \frac{53}{8} = \mathbf{6.625} [/tex]

(b) The range of the means of the sample means is found as follows;

Range = Largest value - Smallest value

Which gives;

(c) The population mean is given by the mean of the sample means. That is, a very good estimate of the sample mean is given by the mean of the sample means.

The true statements are therefore;

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Based on the fact that the road sign's distance to Beaston is rounded to the nearest unit, the actual range of possible miles to Beaston is 9.50 ≤ x ≤ 10.49.

Based on the fact that the miles to Beaston are rounded to the nearest mile, the first thing to do is to find the lowest and highest numbers that can be rounded to 10 miles.

The lowest number that you can round to 10 miles is:

= 9.5 miles

Because of the 0.5 attached to the 9 miles, you will round up to 10 instead of down to 9.

The highest number that you can round to 10 miles at two decimal places is 10.49 miles.

The reason this is the highest is that the 0.4 is the tenths number just before 0.5. This means that you round the whole number down to 10.

Assuming the distance to Beaston is x, the interval would then be:

9.50 ≤ x ≤ 10.49.

In conclusion, the range of miles of Beaston is  9.50 ≤ x ≤ 10.49.

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The area under the curve y = x² + 4 on the interval [-3, 2] exists [tex]$\frac{95}{3}[/tex].

The area under a curve between two points exists seen by accomplishing a definite integral between the two points. To estimate the area under the curve y = f(x) between x = a and x = b, integrate y = f(x) between the limits of a and b. This area can be estimated by utilizing integration with given limits.

The equation that represents the curve exists

y = x² + 4

To estimate the area under the curve in the interval of [-3, 2] will be

[tex]$&\text { area }=\int_{-3}^{2} x^{2}+4 d x \\[/tex]

[tex]$&=\left[\frac{x^{3}}{3}+4 x\right]_{-3}^{2} \\[/tex]

[tex]$&=\frac{1}{3}\left[x^{3}\right]_{-3}^{2}+4[x]_{-}^{2} _{3} \\[/tex]

simplifying the above equation, we get

[tex]$&=\frac{1}{3}\left[(2)^{3}(-3)^{3}\right]+4[(2)-(-3)] \\[/tex]

[tex]$&=\frac{1}{3}[8+27]+4[2+3] \\[/tex]

[tex]$&=\frac{1}{3}(35)+20 \\[/tex]

[tex]$&=\left(\frac{95}{3}\right)[/tex]

Therefore, the area under the curve y = x² + 4 on the interval [-3, 2] exists [tex]$\frac{95}{3}[/tex].

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u need first to understand the thing

So, the value of x is 1.19

The question is an exponential equation

An exponential equation is a mathematical expression between two quantities in which one variable is raised to a power of the other variable.

Since [tex]4^{x} + 6^{x} = 9^{x}[/tex],

Dividing through by 4ˣ, we have

[tex]\frac{4^{x} }{4^{x} } + \frac{6^{x} }{4^{x} } = \frac{9^{x} }{4^{x} } \\1 + (\frac{6}{4})^{x} } = (\frac{9}{4})^{x} } \\1 + (\frac{3}{2})^{x} } = (\frac{3^{2} }{2^{2} })^{x} } \\1 + (\frac{3}{2})^{x} } = (\frac{3}{2})^{2x} }[/tex]

Let y = (3/2)ˣ

So,

1 + y = y²

y² - y - 1 = 0

Using the quadratic formula to find y,

[tex]y = \frac{-b +/- \sqrt{b^{2} - 4ac} }{2a}[/tex]

where a = 1 b = -1 and c = -1

Substituting the values of the variables into the equation, we have

[tex]y = \frac{-(-1) +/- \sqrt{(-1)^{2} - 4\times 1 \times (-1)} }{2\times 1}\\= \frac{1 +/- \sqrt{1 + 4} }{2}\\= \frac{1 +/- \sqrt{5} }{2}\\= \frac{1 - \sqrt{5} }{2} or \frac{1 + \sqrt{5} }{2}\\= \frac{1 - 2.236}{2} or \frac{1 + 2.236}{2}\\= \frac{- 1.236}{2} or \frac{3.236}{2}\\= -0.618 or 1.618[/tex]

Since y = (3/2)ˣ

Takung logarithm of both sides, we have

㏒y = ㏒(3/2)ˣ

㏒y = x㏒(3/2)

x = ㏒y/㏒(3/2)

x = ㏒y/㏒1.5

Since we do not have logarithm of a negative number, we use y = 1.618.

So, x = ㏒y/㏒1.5

x = ㏒1.618/㏒1.5

x = 0.2090/0.1761

x = 1.19

So, the value of x is 1.19

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The expression that represent the given statement is p/q - m²

From the question, we are to write an expression for the word problem

We are to write an expression for the statement

"Subtract the square of m from the ratio of p and q"

Square of m = m²

Ratio of p and q = p/q

Thus,

subtract the square of m from the ratio of p and q, becomes

p/q - m²

Hence, the expression that represent the given statement is p/q - m²

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Answer:

x = 0, x = 5

Step-by-step explanation:

x² - 5x = 0 ← factor out x from each term

x(x - 5) = 0

equate each factor to zero and solve for x

x = 0

x - 5 = 0 ⇒ x = 5

See below for the description of the figure

The equation is given as:

36 + 27 = 9 * (4 + 3)

Open the bracket

36 + 27 = 9 * 4 + 9 * 3

The above when represented on a figure is represented by the given figure.

From the figure, we have the following highlights:

This means that the figure has 7 columns and 9 rows where the partitions on the figure are the product of the rows and column in each partition

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Step-by-step explanation:

sin(0) = 0.

sin^2(0) = sin(0) × sin(0) = 0 × 0 = 0.

∴ sin(0) / 1 - sin^2(0) = 0 / 1 - 0

= 0 / 1

= 0.

Answer:

1) x=4, y=7

2) x=1, y=2

3) x=-3, y=2

4) x=1, y=1

word problem) 5g of nutmeg and 20g of cinnamon

Step-by-step explanation:

1)

2x-9y=-55

2(x+2y) = 2x+4y = 36

(2x+4y)-(2x-9y)=36-(-55)

13y = 91

y = 7 so x = 4

2)

2(3x+2y) = 6x+4y = 14

6x-6y=-6

(6x+4y)-(6x-6y) = 14-(-6)

10y = 20

y = 2 so x = 1

3)

2(6x+10y) = 12x+20y = 4

5(7x+4y) = 35x+20y = -65

(35x+20y) - (12x+20y) = -65-4

23x = -69

x = -3 so y = 2

4)

just add them

(3x+2y)+(x-2y) = 5+(-1)

4x = 4

x = 1 so y= 1

last)

c+n = 25

9c + 12.5n = 25*9.7 = 242.5

9(c+n) = 9*25

9c+9n=225

9c+12.5n - 9c-9n = 242.5-225

3.5n = 17.5

n = 5 so c = 20

5g of nutmeg and 20g of cinnamon

Answer:

Discount =40\%

Selling price of headphone =\$36

Solution --

we know that,

MP=SP * 100/(100-D\%)

putting values now we get,

MP = 36 * 100 / 60=60$

so, initial price of Headphone was =$60

The SEC routinely require public companies to include their review reports in their 10-Q filings because it is said to be made up of fewer details and the financial statements inclusive that are known to be unaudited.

Form 10-Q is known to be a type of a report  that is often needed by the Securities and Exchange Commission (SEC)  and it is one that all public company need to file on quarterly basis.

Note also that The SEC is known to have made and need the form in accord to the pursuant of  the Securities Exchange Act of 1934  and this form helps them to keep investors well  informed about the state of their financial health and all that is taking place at  the companies they have invest in or will choose to invest in.

Hence,  Form 10-Q is asked for because it is often used to make comparison of a company’s previous financial quarter to that of its current financial quarter.

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The domain of f(x) = √(x - 7) +9 is x ≥ 7 and the range of f(x) = √(x - 7) +9 is y ≥ 9

The function is given as:

f(x) = √(x - 7) +9

Set the radicand greater than or equal to 0

x - 7 ≥ 0

Add 7 to both sides

x ≥ 7

The above represents the domain

Set the radicand to 0

f(x) = 0 +9

So, we have

f(x) = 9

This represents the minimum value of the range.

So, the range is y ≥ 9

Hence, the domain of f(x) = √(x - 7) +9 is x ≥ 7 and the range of f(x) = √(x - 7) +9 is y ≥ 9

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Answer:

Step-by-step explanation:

Its A

The type of numbers which -560 and 114 are include the following:

B. Integer.

C. Rational.

A numerical data is also referred to as a quantitative data and it can be defined as a data set that is primarily expressed in numbers only. This ultimately implies that, a numerical data refers to a data set consisting of numbers rather than words.

In Mathematics, there are six (6) common types of numbers and these include the following:

In this context, we can infer and logically deduce that -560 and 114 are both an integer and a rational number.

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Complete Question:

What type of number is -560, 114? Choose all answers that apply:

A. Whole number

B. Integer

C. Rational

D. Irrational

The value of a particular trigonometric expression that is cos 2θ under the third quadrant is -119/169

Given:

sin θ = -⁵/₁₃

This can be seen from the trigonometric identity.

cos 2θ = 1 - 2sin²θ

From trigonometric identities, we know that;

cos 2θ = 1 - 2sin²θ

Thus;

cos 2θ = 1 - 2(-⁵/₁₃)²

cos 2θ = 1 - 2(25/169)

cos 2θ = 119/169

since cos θ is negative in the third quadrant, then we have;

cos 2θ = -119/169

so; cos θ is negative in the third quadrant, so ;

cos 2θ = -119/169

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Answer:

To find the biggest 4-digit number which is a perfect square, we have to take the square of biggest 2-digit number. ∴ The biggest 4-digit number which is a perfect square = 9801.

Step-by-step explanation:

Answer:

9801

Step-by-step explanation:

well we know 100 squared is the first 5 digit square number so it must be 99 squared, which is 9801

The vertex coefficient of the parabola with vertex (- 5, - 2) and the point (- 4, 2) is equal to 1.

In this question we must find the vertex coefficient of the equation of the parabola, which is the vertex form of the quadratic equation:

y - k = C · (x - h)²

If we know that (h, k) = (- 5, - 2) and (x, y) = (- 4, 2), then the vertex coefficient is:

2 - (- 2) = C · [- 4 - (- 2)]²

4 = C · (- 2)²

C = 1

The vertex coefficient of the parabola with vertex (- 5, - 2) and the point (- 4, 2) is equal to 1.

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The maximum possible profit = $7068

For given question,

One Microsoft July $72 put contract for a premium of $1.32

The payoff arise from put option is max (K - S, 0) - P

Now it would be maximum at S = 0

And, the maximum payoff is

K - 0 - P

= K - P

= 72 - 1.32

= $70.68

We assume that for each and every contract the number of shares is 100

So, the maximum profit gained from this strategy is

= $70.68 × 100 shares

= $7068

The maximum profit that will be gained from this strategy is $7068

Therefore, the maximum possible profit = $7068

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Answer: ||||||| n=41° |||||| m=59° IIIII p=260° IIII

Step-by-step explanation:

Alternate angle:

<m=<59°

m=59°

<n=<41°

n=41°

______________

p+41°+59°= 360°

p+100°=360°

p=360°-100°

p=260°

Answer:

n = 49

m= 31

p= 280

Step-by-step explanation:

41 + n = 90

n= 90 -41 = 49

59 + m = 90

m = 90 - 59 = 31

Hope this helps!

p + n + m = 360

p = 360 - 49 - 31 = 280

[tex] \rm log_{5}(125) \\ \rm log_{5}( {5}^{3} ) \\ \rm1 \cdot3 \\ 3 \\ \therefore \tt log_{5}(125) = 3[/tex]